\/ \ i 1. \ I I / 4\ I I1 I. Chapter 7 Review: Quadratics Textbook p Summary: p , p Practice Questions p.398,p.

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Chapter 7 Review: Quadratics Textbook p.358-444 Summary: p.396-397, p.441-442 Practice Questions p.398,p.443-444 Key Concepts: Quadratic Analysis, Different Forms of Quadratics, Solving Quadratics, Factoring, Quadratic Formula, Modeling with Quadratics. -7 Definition: A quadratic is any equation with anz in it. (and nox3,x, 1, 1j, X) The graph of a quadratic equation is in the shape of a 1 ; Quadratic Analysis 1) The X is where the parabola changes direction (either a maximum or a minimum) 2) The /c X ci for a parabola is a vertical line that goes through the vertex (about which the graph is symmetrical) 3) The domain for all quadratics (that aren t restricted in some way by a word problem) is &i i S 4) The range for a quadratic is always fl9+ c4ed by either the maximum or minimum point. 5) occur when the graph crosses the x or y axis. 6) The x-intercepts always correspond to the cc h (S of the equation, and are also called,or Et:c. Different Forms of the quadratic Vertex Form Factored Form Standard Form y = a(x p) 2 +g y = a(xt)(x I) = ax2 + bx+ c 5 -\ \ 4\ I I1 I 411 I \ I I /..!_,! \ 4 f \/ \ i 1. \ -2/ \ 1 yx -X-6 \ -4 Vertex = (p. q) Factors = x-intercepts c = y-intercept p = horizontal shift q = vertical shift a = stretch factor S You should also be able to find points on a quadratic graph using your calculator. Input the equation in Y=, and use the CALC menu.

Method #1: Factor Method #2: Formula Example: Solve x2 = x + 6-1 15_- (23)( -5) (/ 3Yx-) (2,15). Write the equation for this quadratic Example #2: A parabola has x-intercepts of-3 and 5 and goes through the point % )Ct:j q : C O-3) equation for this quadratic a{p)z q Example #1: A parabola has a y-intercept of -4 and a vertex at (3,-7). Write the using information from a question to write a quadratic. Many real-life problems can be modeled using quadratic equations. This involves Quadratic Modeling ç X e2( 2;- (Q CAL C C! - i,- x x f :: XL CAjC Method #3: Graph the Zeros Method #4: Graph the Intersections -7 ---- 3. - --------- I ()(x3)>o )< Z_)< 0 - - Solving = finding solutions/roots/zeros/x-intercepts (all the same thing) Solving Quadratics /

3)(x Chapter 7 Review: Quadratics Practice #1: Graph the equation y = (x 1 2 3) 4 without a calculator. p = q a = F vertex= max or mm? / 1 I/V --- - -- --- -- - - I,35 s; i,2,5 x 3 :::: : : : : : : : ---- -- ---- - - * * - * - - - S 6 z / C) -3c cc Domain: Range: q Practice #2: Graph the equation y = 2(x 2- x-ints = ) a= -Z max or mm? /4A X Axis of Symmetry? x / 3 0 0 y I L + 1) without a calculator. I / \ - 4. -1 ::: I :::c:::: * L L - Domain: 2 1/ Range: IA /24 IS

Practice #3: Graph the equation y = x(x 4) without a calculator. x-ints = a= / I maxormin? Axis of Symmetry? - - I Domain: 11 Range: L4 i I I : :1: / ---- Practice #4: Analyze the graph and write an equation to match: i) Vertex: (1, Axis of Symmetry: 1 - Y-Intercept: X-Intercepts: 3 Domain: [Pt Range: Pattern: I) 3 Equation: ; or (j)2

Practice #5: Solve by graphing: 3x2 + 4x 2 = 2x2 2x 7 Method #1 - Zeros xx- 2Zx -(_) Method #2 - Intersections Practice #6: Solve by factoring a) 2 16x= 24 b)2x (g)4-) x-/x Z 0 x- I 2( 2)(-) c)x 2 2x 8=O (x#2 2+5x 12=O d)2x (3 Yi-o

Quadratic Formula: x 2a b±jb2_4ac --4.-. 4 5,.------- -s s a V 2 x. - I)( )) Practice #9: Write a ciuadratic equation in factored form for this parabola: ay-interceptof5o. Practice #8: Write an equation for a parabola that has x-intercepts of-4 and 6 with y 4 /,. 2 -) ±Ji-) c)x 2=x+6 d)x 2+4x+4=O 2(i) ) ±J2(I)(-) )< -5-7i5-5 -c--zo x - 2 ( 2+5x 3 =0 b)x a)x 2 5x=2 SIMPLIFY ifpossible Practice #7: Use the quadratic formula to solve. Show all answers in EXACTform and

Practice #10: David dives from a spring board. His height, h metres, above the water t seconds after release is given by h = 4.9t 2 + 8.8t + S a) What is the domain and range for this word problem? / 11 ; O b) How high is the diving board? ) - c) What is David maximum height? d) How long is David in the air for? Practice #11: Bonnie launches a model rocket from the ground with an initial velocity of 68 m/s. The following function, h(t), can be used to model the height of the rocket, in metres, over time, t, in seconds: h(t) = 4.9t 2 + 68t Bonnie s friend Sasha is watching from a lookout point at a safe distance. Sasha s eye level is 72m above the ground. At what time during the flight will the rocket be at Sasha s eye level? 4ç IZII

Practice #11: A store rents an average of 750 video games each month at the of $4.50. The owners of the to raise rental to increase to $6000 know 30 fewer games each month because some people won t be willing to pay higher prices. What should they set for video game rentals? current rate the revenue that they will rent the rate per month. However, for every $1 increase, they rate store want (750 -(o. /L / ILl Practice #12: 1 second theball. the ty N, ft9 f 1vi e h Johnny kicks a rugby ball in air and it lands after 4 seconds. After ball was 20 feet high. Write an equation to model the time vs. height of the.2o- -3 Practice #13: Gary is competing the National Diving Championships. He does a triple-back flip off the lom tower. If Gary s maximum height of 10.85m occurred just 0.42s after jumping, how long will it take him to hit the water? then /(t/lo. (- 1z)1o. -(,2)/. /0-3 a1j) Practice #14: The length of a is 4m more Determine the dimensions of the garden if the area is 117 m2.,i / / rectangular garden than its width. 12 5 0i45 2 13