Topological Insulators and Ferromagnets: appearance of flat surface bands

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Topological Insulators and Ferromagnets: appearance of flat surface bands Thomas Dahm University of Bielefeld T. Paananen and T. Dahm, PRB 87, 195447 (2013) T. Paananen et al, New J. Phys. 16, 033019 (2014)

Overview Introduction: topological insulator Modification of surface states by a ferromagnetic exchange field Surface flat bands Summary

Introduction: topological insulators

What is a topological insulator? In a topological insulator we have an insulating bulk, but metallic surface states with a linear dispersion. E E F k Insulating (2D) metallic bound states (1D) The existence of the surface states is guaranteed by a topological quantum number

Properties of the surface states Spin-orbit coupling leads to a spin-momentum locking of the surface states. Vacuum down spin 2D topological insulator down spin Vacuum up spin Backscattering between these two channels is forbidden as long as time-reversal symmetry is preserved. Interesting for spintronics

Properties of the surface states In a 3D topological insulator the surface states form a massless 2D electron system. The dispersion forms a Dirac cone, like relativistic fermions. (In graphene we have two Dirac cones).

Topological insulators and ferromagnets

When time-reversal symmetry is respected, the surface states are topologically protected. What happens, if we break time-reversal symmetry? Can we control the surface states by a ferromagnet? Consider a topological insulator with a Zeeman field

How could this be done? FM-TI A ferromagnetic topological insulator? TI Doping by magnetic impurities Y.L.Chen et al, Science 2010 Mg doped Bi 2 Se 3 FM TI Induction by magnetic proximity effect P. Wei et al, PRL 2013 EuS on Bi 2 Se 3 thin films

What happens to the surface states in a Zeeman field? R.L. Chu et al, PRB 84, 085312 (2011) Perpendicular polarization E FM-TI k Surface states become gapped Parallel polarization E FM-TI Surface states are shifted, but survive. k

Surface flat bands

What happens to the surface states in a Zeeman field? T. Paananen and T. Dahm, PRB 87, 195447 (2013) FM TI Standard Hamiltonian for Bi 2 Se 3, 2 orbital and 2 spin degrees of freedom: H m k V 3 ( ) i =ε k14 4+ i Γ+ ασα 12 2 i= 0 α,, { xyz} ( ) = 2 ( 1 cos ) 2 ( 1 cos ) 2 ( 1 cos ) m k M B k B k B k 0 2 x 2 y 1 z ( ) m1 k 2A2sin k x = ( ) m k 2A sin k y = ( ) 2 2 In the following we set ε k =0. m3 k = 2A1sin k z

What happens to the surface states in a Zeeman field? T. Paananen and T. Dahm, PRB 87, 195447 (2013) FM TI E V=0 k

What happens to the surface states in a Zeeman field? T. Paananen and T. Dahm, PRB 87, 195447 (2013) FM TI E V=0.25 M k

What happens to the surface states in a Zeeman field? T. Paananen and T. Dahm, PRB 87, 195447 (2013) FM TI E V=0.5 M k

What happens to the surface states in a Zeeman field? T. Paananen and T. Dahm, PRB 87, 195447 (2013) FM TI E V=0.75 M k

What happens to the surface states in a Zeeman field? T. Paananen and T. Dahm, PRB 87, 195447 (2013) FM TI E V=1.0 M V=bulk gap Semi-metal k

What happens to the surface states in a Zeeman field? T. Paananen and T. Dahm, PRB 87, 195447 (2013) FM TI E V=1.25 M k

What happens to the surface states in a Zeeman field? T. Paananen and T. Dahm, PRB 87, 195447 (2013) FM TI E V=1.5 M k

What happens to the surface states in a Zeeman field? T. Paananen and T. Dahm, PRB 87, 195447 (2013) FM TI E V=1.75 M k

What happens to the surface states in a Zeeman field? T. Paananen and T. Dahm, PRB 87, 195447 (2013) FM TI E V=2.0 M k

What happens to the surface states in a Zeeman field? T. Paananen and T. Dahm, PRB 87, 195447 (2013) FM TI No splitting of the surface states Group velocity can be tuned by the Zeeman field No gap Appearance of a flat band at zero energy when V>M Seems to contradict Chu et al.

3D Topological Insulator

Consider a three dimensional system T. Paananen, H. Gerber, M. Götte, and T.Dahm, New J. Phys. (2014) y z x FM-TI Layered, anisotropic materials Surfaces are inequivalent

On the top surface we find agreement with Chu et al V z =0.5 M V x =0.5 M k y k y E E k x k x The Dirac cone is gapped The Dirac cone is shifted No flat band appears

Front surface: Zeeman field in x-direction y z x FM-TI

On the front surface the behavior is different V x =0.7 M V x =1.5 M k x k x E E k z k z The Dirac cone is isotropically suppressed, tuning of the velocity, no gap A 2D flat band appears

Front surface: Zeeman field in z-direction y z x FM-TI

On the front surface the behavior is different V z =0.7 M V z =1.5 M k x k x E E k z k z The Dirac cone is anisotropically suppressed, tuning of the velocity, no gap A 1D flat band appears

On the front surface the behavior is different y z x FM-TI No gap Isotropic suppression and 2D flat band for V x Anisotropic suppression and 1D flat band for V z

How can we understand the appearance of flat surface bands?

Bulk-boundary correspondence Classification of surface states in gapless systems: S. Matsuura et al, New J. Phys. 15, 065001 (2013) If the Hamiltonian possesses a chiral symmetry S, i.e. { H, S } = 0 a winding number can be defined that tells, if a zero energy surface state exists or not. We have checked that for all our flat band cases such a chiral symmetry exists and the winding number correctly reproduces the position of the flat bands in momentum space.

According to Matsuura et al, boundaries of the flat bands are the projection of the Fermi surface onto the surface Brillouin zone. The dimension of the flat band is the dimension of the Fermi surface plus one. Let s check this.

Fermi surface for V>M: semimetal V z =0 V z 0 k z k y k x 1D Fermi surface Projection onto k y plane yields 2D flat band Two Fermi points Projection onto k y plane yields 1D flat band, extended along k z

Weyl semimetal 3D generalization of graphene Just two bands touch at the Weyl nodes Has recently been proposed for pyrochlore iridates Possesses open Fermi arcs at the surface BZ

V z 0 The bulk is a Weyl semimetal for nonzero V z The flat bands are Fermi arcs Only visible at the side surfaces

Realistic parameters H m k V 3 ( ) i =ε k14 4+ i Γ+ ασα 12 2 i= 0 α,, { xyz} The ε k term breaks the chiral symmetry S. What are the consequences for Bi 2 Se 3?

Realistic parameters for Bi 2 Se 3 The flat band gets dispersive, but still exists and remains separated from the bulk. The system for V z 0 is still a Weyl semimetal. M=280 mev

Summary In the presence of a TRS breaking Zeeman field the surface states are not necessarily removed. Topologically protected flat bands appear at the side surfaces if V>M. The TI in a Zeeman field becomes a Weyl semimetal for V>M. The surface flat bands create Fermi arcs. The unconventional nature of this phase cannot be seen on the top surface. Flat bands at room temperature Combination of TIs and ferromagnets promises interesting spintronics applications, as the surface states can be tuned.