Lecture Ch. 6. Condensed (Liquid) Water. Cloud in a Jar Demonstration. How does saturation occur? Saturation of Moist Air. Saturation of Moist Air

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Lecture Ch. 6 Saturation of moist air Relationship between humidity and dewpoint Clausius-Clapeyron equation Dewpoint Temperature Depression Isobaric cooling Moist adiabatic ascent of air Equivalent temperature Aerological diagrams Condensed (Liquid) Water Ch. 4: Will H 2 O condense? Clausius-Clapeyron describes e sat (T) Ch. 5: What will H 2 O condense on? Kohler describes droplet formation Ch. 6: How much H 2 O will condense? Dew point temperature provides metric Ch. 7: How does condensed H 2 O affect stability? Conditional stability is affected by moist adiabats Ch. 8: What happens to condensed H 2 O? Precipitation processes How does saturation occur? Cloud in a Jar Demonstration By increasing water vapor Evaporation of water at surface Evaporation of falling rain http://www.youtube.com/ By cooling watch?v=xh_m4jitikw Isobaric Radiative cooling of rising air By mixing of two unsaturated air parcels http://groups.physics.umn.edu/demo/old_page/demo_gifs/4b70_20.gif Saturation of Moist Air Dew point temperature Saturation of Moist Air Clausius-Clapeyron equation at dew point v v = T p dp p = L lv T 2 dt d ln p = L lv T 2 dt d ln p dt = L lv T 2 1

Clausius Clapeyron Recall by integration between two temperatures we had Dewpoint and Humidity Integrating from ambient to saturation Dew point depression (T-T D ) INCORRECT! Figure is wrong. 1.0 0.8 T=2C T=24C T=46C Relative Humidity 0.6 0.4 0.2 0.0 0 5 10 15 20 Dewpoint Depression (T-Td) Start with measured T and T d with altitude, then overlay w s (T). Equivalent Potential Temperature 2

Equivalent Potential Temperature Accounts for liquid water heating Although approximate, (6.48) retains the condensation of water vapor provides energy to the moist air and increases its temperature relative to what the temperature would have been in dry adiabatic ascent. Temperature Metrics Virtual Temperature: The temperature air would have at the given pressure and density if there were no water vapor in it Potential Temperature: The temperature a parcel would have if it were brought adiabatically and reversibly to p 0 (usually 1 atm) Virtual Potential Temperature: The temperature a parcel would have if there were no water vapor in it (only condensed water) and if it were brought adiabatically and reversibly to p 0 (usually 1 atm) Equivalent Temperature: The temperature that an air parcel would have if all of the water vapor were to condense in an adiabatic isobaric process Equivalent Potential Temperature: The temperature a parcel would have if all of the water were condensed in an adiabatic isobaric process and if it were brought adiabatically and reversibly to p 0 (usually 1 atm) T vs. ln(p) Emagram (T is vertical; thetas slant left) {1884} Tephigram (T slants right; thetas slants left) {1915} Stuve diagram (T is vertical) {1927} areas contained by the curves have equal energies for equal areas, leading to better comparisons of CAPE and hence convective systems 3

Skew-T Log P (T slants right) {1947} All temperatures are equal at the horizontal 1000 mb level near the bottom. red lines are isotherms, dashed green lines are the equivalent potential temperature; solid green lines are the potential temperature Blue lines are the isobars (scale on the left side) Dashed purple lines are the saturated humidity mixing ratio (w s (T), i.e. nearly parallel to T) 1000hPa ws~4 g/kg wv=w-ws=11 g/kg T d Then follow theta-e adiabat to 400hPa Follow theta to saturation (T=Td=30C) How to find dew point and frost point? Cool isobarically until reaching saturation. Dew point: e=e s (T D ) Frost point: e=e s (T F ) Td=20C wv~15 g/kg T=30C Mixing Line Parcel 1 (subsaturated) Enthalpy Change for Phase+Temperature Change Parcel 2 (subsaturated) Clausius-Clapeyron (with exagerated curvature) N.B. For mixture to be supersaturated, need two parcels very close to saturation at two somewhat different temperatures. Enthalpy Change for Phase+Temperature Change Wet-Bulb Temperature 4

Radiation Transport in the Atmosphere Latent Heat accounts for 78 W/m 2! What did we learn in Ch. 6? Cloud formation what causes saturation? Cooling to decrease e s (T) Increasing water vapor to increase e Mixing of two nearly-saturated parcels Enthalpy balance: How much H 2 O will condense? Latent heat from evaporation causes cooling Latent heat from condensation causes warming Dew point (T D ) and frost point (T F ) temperatures Cool isobarically until saturation is reached RH scales with dewpoint depression (T-T D ) L lv affects energy balance (Kiehl+Trenberth, 1997) 5