Page 2. Q1.Water dissociates slightly according to the equation: H 2 O(I) The ionic product of water, K w, is given by the expression

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Transcription:

Q1.Water dissociates slightly according to the equation: H 2 O(I) H + (aq) + OH (aq) The ionic product of water, K w, is given by the expression K w = [H + ][OH ] K w varies with temperature as shown in the table. Temperature / C K w / mol 2 dm 6 25 1.00 10 14 50 5.48 10 14 (a) Explain why the expression for K w does not include the concentration of water. (2) (b) Explain why the value of K w increases as the temperature increases. (2) (c) Calculate the ph of pure water at 50 C. Page 2

(d) Calculate the ph of 0.12 mol dm 3 aqueous NaOH at 50 C. (Total 10 marks) Q2.This question is about alkalis and carboxylic acids. In this question, all data are quoted at 25 C. (a) Carboxylic acids are weak acids. State the meaning of the term weak as applied to carboxylic acids. Page 3

(b) Write an equation for the reaction of propanoic acid with sodium carbonate. (c) Calculate the ph of a 0.0120 mol dm 3 solution of calcium hydroxide. The ionic product of water K w = 1.00 10 14 mol 2 dm 6. (Extra space)... (d) The value of the acid dissociation constant K a for benzenecarboxylic acid (C 6H 5COOH) is 6.31 10 5 mol dm 3. (i) Write an expression for the acid dissociation constant K a for benzenecarboxylic acid..... (ii) Calculate the ph of a 0.0120 mol dm 3 solution of benzenecarboxylic acid..... Page 4

............ (Extra space)....... (iii) A buffer solution with a ph of 4.00 is made using benzenecarboxylic acid and sodium benzenecarboxylate. Calculate the mass of sodium benzenecarboxylate (M r = 144.0) that should be dissolved in 1.00 dm 3 of a 0.0120 mol dm 3 solution of benzenecarboxylic acid to produce a buffer solution with a ph of 4.00 The value of the acid dissociation constant K a for benzenecarboxylic acid (C 6H 5COOH) is 6.31 10 5 mol dm 3................... (Extra space)......... Page 5

(5) (e) Two solutions, one with a ph of 4.00 and the other with a ph of 9.00, were left open to the air. The ph of the ph 9.00 solution changed more than that of the other solution. Suggest what substance might be present in the air to cause the ph to change. Explain how and why the ph of the ph 9.00 solution changes. Substance present in air... Explanation... (Total 17 marks) Q3.This question involves calculations about two strong acids and one weak acid. All measurements were carried out at 25 C. (a) A 25.0 cm 3 sample of 0.0850 mol dm 3 hydrochloric acid was placed in a beaker and 100 cm 3 of distilled water were added. Calculate the ph of the new solution formed. (Extra space)... (2) (b) HX is a weak monobasic acid. Page 6

(i) Write an expression for the acid dissociation constant, K a, for HX..... (ii) The ph of a 0.0850 mol dm 3 solution of HX is 2.79 Calculate a value for the acid dissociation constant, K a, of this acid. Give your answer to 3 significant figures............. (Extra space)......... (c) A 25.0 cm 3 sample of 0.620 mol dm 3 nitric acid was placed in a beaker and 38.2 cm 3 of 0.550 mol dm 3 aqueous sodium hydroxide were added. Calculate the ph of the solution formed. The ionic product of water K w = 1.00 10 14 mol 2 dm 6 at 25 C. Page 7

(Extra space)... (6) (Total 12 marks) Q4. This question is about the ph of some solutions containing potassium hydroxide and ethanoic acid. Give all values of ph to 2 decimal places. (a) (i) Write an expression for ph. (ii) Write an expression for the ionic product of water, K w (iii) At 10 C, a 0.154 mol dm 3 solution of potassium hydroxide has a ph of 13.72. Calculate the value of K w at 10 C. Page 8

(Extra space)... (2) (b) At 25 C, the acid dissociation constant K a for ethanoic acid has the value 1.75 10 5 mol dm 3. (i) Write an expression for K a for ethanoic acid. (ii) Calculate the ph of a 0.154 mol dm 3 solution of ethanoic acid at 25 C. (Extra space)... (c) At 25 C, the acid dissociation constant K a for ethanoic acid has the value 1.75 10 5 mol dm 3. Page 9

(i) Calculate the ph of the solution formed when 10.0 cm 3 of 0.154 mol dm 3 potassium hydroxide are added to 20.0 cm 3 of 0.154 mol dm 3 ethanoic acid at 25 C. (Extra space)... (4) (ii) Calculate the ph of the solution formed when 40.0 cm 3 of 0.154 mol dm 3 potassium hydroxide are added to 20.0 cm 3 of 0.154 mol dm 3 ethanoic acid at 25 C. At 25 C, K w has the value 1.00 10 14 mol 2 dm 6. (Extra space)... Page 10

(4) (Total 16 marks) Page 11