What is a receptive field? Why a sensory neuron has such particular RF How a RF was developed?
x 1 x 2 x 3 y f w 1 w 2 w 3 T x y = f (wx i i T ) i y
The receptive field of a receptor is simply the area of the visual field from which light strikes that receptor. For any other cell in the visual system, the receptive field is determined by which receptors connect to the cell in question.
!
The solid black curve represents the amount of light being reflected from the figure at the top. The red curve represents the brightness of this figure as it is usually perceived. To the left of the point where the figure just starts to get lighter people usually see a dark bar that is slightly darker that the area to the left of it. At the point where the brightness just stops increasing, people usually perceive a bright bar. This phenomenon was discovered by the famous physicist, Ernst Mach and it is in his honor that these dark and bright bars are called Mach Bands. These Mach Bands can be explaind by center-surround receptive field interactions. " #
The receptive fields are represented as a disk (+) and annulus (-). The center disk is an excitatory area and the annulus an inhibitory area. The receptive fields in the uniformly white and uniformly black areas receive about the same stimulation in their excitatory centers and inhibitory surrounds. Therefore the center excitations are in balance with the surround inhibitions. The receptive field over the bright Mach Band gives a stronger response in the center because part of the surround is in the darker area. Therefore it receives less inhibition from the surround than did the center at the extreme left and right ends. The receptive field over the dark band receives more surround inhibition because part of the surround is in the brighter area. Therefore, the excitatory response is less and this results in our seeing that the area as darker. " #
You undoubtedly saw a square figure which had a small rather light square area in the center and increasingly darker perimetric strips extending to the edge. You probably also saw bright arms radiating diagonally out from the center. This figure was adapted from a chromatic version designed by V. Vasarely (Arcturus (1970) as reported in Hurvich, 1981. $ These brighter diagonal areas are physically not in the figure. That is to say, if you were to use a light measuring instrument (a photometer) and measure the amount of light coming from any of the concentric perimetric strips you would find that the same amount of light is reflected from all points along any one strip. Yes, that includes that part of the strip along the diagonal where it appears brighter. Consequently, that must mean that this brightness illusion is generated in the visual system.
$ These curves represent the amount of light reflected from the identified areas. The amount of light is constant around each perimetric strip. These curves represent the perceived brightness. Note that near the diagonal the apparent amount of light increases.
Notice in the receptive field on the left that although a small part of the inhibitory surround lies in the white center a small part of it also lies in the darkest part of the figure. With the receptive field placed as it is one might expect that the size of the surround inhibitory response would be about the same as the size of the center excitatory response. Now look at the receptive field on the right. Clearly more of the inhibitory surround lies in either the same gray as the center or in darker areas. Only a small portion lies in a brighter area than the excitatory center. Consequently, one would expect that the excitatory center would have a larger response on the diagonal than for a receptive field not on a diagonal. Hence there appears a brightness enhancement on the diagonals of this diagram. You, of course, noticed that there is no brightness on the diagonals in this figure. $
%
%
" &%
What is a receptive field? Why a sensory neuron has such particular RF How a RF was developed?
Image Analysis?
Image Analysis
'
" " 2 2 1 x + y G x, y) = (2 4 2 2πσ σ 2 x + y )exp( 2σ ( 2 2 2 ) DOG( e, i ) = [ 1 2 x 2 exp( )] [ 2 2 e 1 2 e x 2 exp( )] 2 2 i
( )* + Computer Vision:,)** - "., Retina: 1,000 MIPS! = 3*5*.../0)1 2 3 4
= 75,000 # )65& *6*3 #,)** ". = 75,000
/ 7%8 78 σ σ f F 1 2 7%8 78 σ F σ f
9 : ; & )+< H Environment 9 -
Relative amplitude Relative amplitude 1 * Spatial frequency Spatial frequency 6
8.51 2.34-0.94 = 2.34-0.94 + 8.51
8.51 2.34-0.94
y e e= y -x =' >?,>,>@A y e x e= y x X e x x
y x 1 =' >?,>,>@A x i x 2 y = a 1 x 1 + a 2 x 2 + a 3 x 3 + a 4 x 4 a i = x 1 *y
y e x i y = a 1 x 1 + a 2 x 2 + a 3 x 3 + a 4 x 4 x 1 y=xa 9 %,B% ) % 3 % C % D E,B ) 3 C D E ' x 2 $ F G a=(x t x) -1 x t y
y e x 1 How to choose basis functions? y = a 1 x 1 + a 2 x 2 + a 3 x 3 + a 4 x 4 x 2 1 -
2.34 8.51-0.94 2.34-0.94 + 8.51 =
%
1!
"
1!
.
What is a receptive field? Why a sensory neuron has such particular RF How a RF was developed?
$
$
/$
2 x y '=! 7%08, 7%8H 78I.7%08 9.7%08 2G '! % 2 " % 2 7%08.7%08.7%08,* 0%0 7%08,7%878.,.