Similar documents
3472/2 Additional Mathematics Paper 2 [Lihat sebelah SULIT

UNTUK KEGUNAAN PEMERIKSA SAHAJA

SEKOLAH MENENGAH ZON A KUCHING LEMBAGA PEPERIKSAAN PEPERIKSAAN PERCUBAAN SPM 2008


2. A die is rolled 3 times, the probability of getting a number larger than the previous number each time is

Sec 4 Maths. SET A PAPER 2 Question

National Quali cations

Express g(x) in the form f(x) + ln a, where a (4)

Sec 4 Maths SET D PAPER 2

Express g(x) in the form f(x) + ln a, where a (4)

Further Mathematics Summer work booklet

Mathematics SL. Mock Exam 2014 PAPER 2. Instructions: The use of graphing calculator is allowed.

*2500/405* 2500/405 MATHEMATICS. STANDARD GRADE Credit Level Paper 1 (Non-calculator) NATIONAL QUALIFICATIONS 2010 WEDNESDAY, 5 MAY 1.30 PM 2.

Vectors Practice [296 marks]

Part (1) Second : Trigonometry. Tan

10 th MATHS SPECIAL TEST I. Geometry, Graph and One Mark (Unit: 2,3,5,6,7) , then the 13th term of the A.P is A) = 3 2 C) 0 D) 1

3301/1H. General Certificate of Secondary Education November MATHEMATICS (SPECIFICATION A) 3301/1H Higher Tier Paper 1 Non-Calculator

Thursday 11 June 2015 Afternoon

1.30 pm 2.30 pm. Mathematics Module M4 Paper 1 (Non-calculator) Higher Tier [GMM41] 1 hour.

Mathematics Preliminary Course FINAL EXAMINATION Friday, September 6. General Instructions

SUMMATIVE ASSESSMENT I, IX / Class IX

(b) g(x) = 4 + 6(x 3) (x 3) 2 (= x x 2 ) M1A1 Note: Accept any alternative form that is correct. Award M1A0 for a substitution of (x + 3).

National Quali cations

IB Math SL 1: Trig Practice Problems: MarkScheme Circular Functions and Trig - Practice Problems (to 07) MarkScheme

GCSE Mathematics (Linear) Formulae: Higher Tier

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education

Cambridge International Examinations CambridgeOrdinaryLevel

International General Certificate of Secondary Education CAMBRIDGE INTERNATIONAL EXAMINATIONS PAPER 1 MAY/JUNE SESSION 2002

2017 HSC Mathematics Marking Guidelines

2001 Higher Maths Non-Calculator PAPER 1 ( Non-Calc. )

Here is a link to the formula booklet:

MATHEMATICS AS/P1/D17 AS PAPER 1

MATHEMATICAL METHODS

Mathematics Extension 2

TABLE OF CONTENTS 2 CHAPTER 1

Paper: 03 Class-X-Math: Summative Assessment - I

Correct substitution. cos = (A1) For substituting correctly sin 55.8 A1

CO-ORDINATE GEOMETRY. 1. Find the points on the y axis whose distances from the points (6, 7) and (4,-3) are in the. ratio 1:2.

Add Math (4047/02) Year t years $P

Sample Question Paper Mathematics First Term (SA - I) Class X. Time: 3 to 3 ½ hours

Answer all the questions

Calculus I Sample Exam #01

Written examination 2

SURA's Guides for 3rd to 12th Std for all Subjects in TM & EM Available. MARCH Public Exam Question Paper with Answers MATHEMATICS

National Quali cations

Solutions to O Level Add Math paper

Mathematics AS/P1/D17 AS PAPER 1

REQUIRED MATHEMATICAL SKILLS FOR ENTERING CADETS

Level 2 Certificate in Further Mathematics FURTHER MATHEMATICS

Methods in Mathematics Unit 2: Methods 2

MATHEMATICS UNIT 2: CALCULATOR-ALLOWED HIGHER TIER

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education

International GCSE Mathematics Formulae sheet Higher Tier. In any triangle ABC. Sine Rule = = Cosine Rule a 2 = b 2 + c 2 2bccos A

C accurately drawn. Calculate the upper bound for the area of triangle ABC. .. mm 2 (2)

Trig Practice 08 and Specimen Papers

Cambridge Assessment International Education Cambridge International General Certificate of Secondary Education. Published

SULIT 47/ The following formulae may be helpful in answering the questions. The symbols given are the ones commonly used. x b ± b 4ac a ALGEBRA 8 log

Topic 3 Part 1 [449 marks]

17.2 Nonhomogeneous Linear Equations. 27 September 2007

STRAIGHT LINES EXERCISE - 3

*P59022A0228* International GCSE Mathematics Formulae sheet Higher Tier DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA

Cambridge International Examinations Cambridge Ordinary Level

CBSE QUESTION PAPER CLASS-X MATHS

SPM Past Year Questions : AM Form 5 Chapter 5 Trigonometric Functions

Prerna Tower, Road No 2, Contractors Area, Bistupur, Jamshedpur , Tel (0657) , PART III MATHEMATICS

Paper collated from year 2007 Content Pure Chapters 1-13 Marks 100 Time 2 hours

DO NOT OPEN THIS TEST BOOKLET UNTIL YOU ARE ASKED TO DO SO

8. Quadrilaterals. If AC = 21 cm, BC = 29 cm and AB = 30 cm, find the perimeter of the quadrilateral ARPQ.

DEPARTMENT OF MATHEMATICS

2013 Bored of Studies Trial Examinations. Mathematics SOLUTIONS

Mathematics (Modular) 43055/2H (Specification B) Module 5

PLC Papers Created For:

2016 SEC 4 ADDITIONAL MATHEMATICS CW & HW

9 11 Solve the initial-value problem Evaluate the integral. 1. y sin 3 x cos 2 x dx. calculation. 1 + i i23

CAPS Mathematics GRADE 11. Sine, Cosine and Area Rules

1. SETS AND FUNCTIONS

The equation 8(9x + 7) 7(6x 5) = 1 has the solution x = k, where k is a positive integer. Pass on the value of k.

So, eqn. to the bisector containing (-1, 4) is = x + 27y = 0

Time: 1 hour 30 minutes

SEKOLAH MENENGAH ZON A KUCHING LEMBAGA PEPERIKSAAN PEPERIKSAAN PERCUBAAN SPM 2008

184/09 MATHEMATICS HIGHER TIER PAPER 1. P.M. MONDAY, 4 June (2 Hours) CALCULATORS ARE NOT TO BE USED FOR THIS PAPER

Paper: 02 Class-X-Math: Summative Assessment - I

ANSWER KEY & SOLUTIONS

Add Math (4047) Paper 2

OC = $ 3cos. 1 (5.4) 2 θ = (= radians) (M1) θ = 1. Note: Award (M1) for identifying the largest angle.

x y

6. Show appropriate working in its correct place. Full marks will not necessarily be given for answers only.

'R'nze Allowed : 3 to 3% Hours] LMaximum Marks : 80

Version 1.0. Level 2 Certificate in Further Mathematics Practice Paper Set 1. Paper /2. Mark Scheme

PhysicsAndMathsTutor.com

SEC Mathematics May 2016

Mathematics Higher Level

Mathematics A Paper 3HR

AP Calculus BC Chapter 4 AP Exam Problems. Answers

Candidate Number. General Certificate of Secondary Education Higher Tier June 2013

METHODS IN MATHEMATICS B392/02 Methods in Mathematics 2 (Higher Tier)

43005/1H. General Certificate of Secondary Education June 2008

H I G H E R S T I L L. Extended Unit Tests Higher Still Higher Mathematics. (more demanding tests covering all levels)

5.5 Special Rights. A Solidify Understanding Task

Possible C4 questions from past papers P1 P3

Transcription:

Note : This document might take a little longer time to print.

more exam papers at :

more exam papers at :

more exam papers at :

more exam papers at :

more exam papers at :

more exam papers at :

more exam papers at :

more exam papers at :

more exam papers at :

Note : This document might take a little longer time to print.

more exam papers at :

more exam papers at :

more exam papers at :

more exam papers at :

more exam papers at :

more exam papers at :

more exam papers at :

more exam papers at :

more exam papers at :

SPM Trial Examination 0 Mark Scheme Addition Mathematics Paper No Marking Scheme Total Mark. (a) 7 (b) 8 (c) many to many banyak dengan banyak. (a) 5 (b) h and k B: h or 9h k 5 or g(x) = x - B: h( x) k. (a) 4 ( ) x g x 7 x 4 Accept: 7 (b) p 0 p 4 B: 7 or 7 () 4 p 4. p 6 5. B: ( ) 5( ) p 0 OR ( x )( x ) 0 OR h 5 and h p x B: ( indicated the correct region ) - B: ( x )(x ) 6. (a) x (b) f ( x) ( x ) 6 B: b or c 6

7. 8. n B: n n 4 or equivalent 4 B: n n or equivalent x = 64 B: log x or log 4 x log B: x log x 4 log 4 or log 4 9. x = 40 x x 8 B: x 0 x 0.. (a) (b) 8 4 B: n = 0 B: 56 + ( n ) ( ) < 0. a = 7 and b = 4 () B: a = 7 or b = OR = a () or 5 = a 5 B: 5 a b() or a b() OR b B: log y bx a. (a) h 6 4 0 B: h 0 6 or equivalent (b) : B: n() m(6) n m

4. 6, 6 B: p p B: m or m p 5. ( a) k 6 B: k 8 0 * 6i 8 j 0 i + 4 j 5 5 (b) 6. (a) x y (b) x y 4 B: x ( x y) or y ( x y) 4 4 B : ( x y) or ( x y) 4 4 p 7. (a) sec k (b) B: k k k 8. ( a) 5 (b) 45.56 B: () (.9) (0 ) 5 B : () (.9) or (0 ) 5 9. 4 B: 4 ()( )(x ) () B: (x ) () 0. B : 5 dx dt 5 (4 x ) or equavalent

B: dy dx 4 x dy or 5 dt. y = x 4x 5 B: = () 4() + c B: y = x 4x + c. (a) x = 4 (b) x = 4 x B: 5= 7 6. (a) 76 (b) 008 B : 8 C 4 x 5 C + 8 C 5 x 5 C + 8 C 6 x 5 C 0 B: 8 C 4 x 5 C 4. (a) x = 5 B : x 6 9 (b) B : 8 5 8 5 0 or 0 8 0 8 5. (a) 0.587 0 95 B: P ( Z ) 8 (b) 0.686 B: P( < Z < ) Total 80 4

SPM TRIAL EXAM 0 Marking Scheme Additional Mathematics Paper Section A Question Part Solution Marks x = 5 + y () x + y = () (5 + y) + y = y + 0y 6 = 0 0 0 4()( 6) y () y = 0.87, -.94 x = 5 + (0.87), x = 5 + (-.94) = 5.56 = -.74 or -.74 (a) A(0, -) (b) k k f ( x) ( x kx ) 4 4 k k ( x ) 4 k 0 k 6 p 4 (c) x ( x 6) 0 0 x 6 (a) L r, L r, L r 6 L L ( r ) r L L ( r 6) ( r ) Common difference, d (b)(i) 4 ( n )( ) 7. 8 7.8.4 n.4 n 8 (b)(ii) 0 S0 4.4 0.4 S 549.85 cm or 549.78 cm (using in calculator) 0

4 (a) (b) sin xcos x LHS = y cos x = sin x cos x = sin x 4 y = sin x O y x x 4 (c) 5 (a) (b) Graph y sin x cycle or amlitude 4 All correct y x Straight line y x Number of solution = (9.5) 7(9.5) 6(9.5) (9.5) 6(49.5) 0(59.5) 8(69.5) x 0 = 6.5 (0) 9 Q 4 4.5 0 6 (0) 86 Q 4 44.5 0 6 Q Q = 47 4.88 =.

6 (a)(i) u 0v (ii) EF EC 5 = ( ED DC) 5 = (4u4u5 v) 5 = 5v BF BA AE EF = 0v8u 5v = 8u 5v (b) BF 8u 5v Section B BD u 0v = 4(8u-5v) BF BD 4 BF // BD and B is the common point Thus B, F and D are collinear 7 (a) f ( x) x c c f ( x) x 4 (b) ( + ½ ()() x 4x 4() 4() (c) 9 unit 6 4 ( 4 y) dy = 4 y y 4 4 = 4(4) 4() =

8 (a) y x.98 5.0 8.97.05.0 x 5 6 7 Refer to graph Using the correct, uniform scale and axes All points plotted correctly Line of best fit (b)(i) y x.0.98 h = 7 =.0 (ii) k = - (iii) when x = 4, y x y = 7x = 7(4) p =

Answer for No. 8(a) y x 4 x x 0 x 8 6 x 4 x 0 4 5 6 7 x -

9 (a) 80 0.6 or 4.8 o o or 4.7 4.8 PR = (0) sin or (0)sin(0.r) = 5.90 (b) S 0(0.6) or S 5.90(0.6) (c) PQR RST 4.8 OT = 0 (5.90) sin or 6.507 Perimeter = 0 + 0(0.6) + 5.9(0.6) + 6.507 = 6.05 (5.90) 0.6 (0) 0.6 sin 4.8 o (5.90) 0.6 + (0) 0.6 sin 4.8 o =.4 0 (a)(i) m BD = y 5 = ( x ) y = x + (ii) (x + ) + x = 7 or equivalent M(, ) x 4 y 0 or, =x()+(), + =y()+(5) + D(, ) ( x) ( y) or () () (b) ( x ) + ( y ) = ( + ) + ( + ) x + y x 6y 0 = 0

(a)(i) 6 9 4 C 7 7 0.097 (ii) 0 9 8 7 9 4 9 4 9 C 4 0 or C or C 7 7 7 7 7 7 or equivalent 0 9 8 7 9 4 9 4 9 4 C 0 C C 7 7 7 7 7 7 or equivalent 0.89 (b) 70 76 PX 70 PZ 5 0.6554 p 76 PX p % or PZ 0. 5 p 76 0.44 5 p 8.60 Section C (a) v 8 ms a 0 6t (b) 0 6(0) = 0 cm s 0 6t 0 5 t s (c) 5 5 v 8 0( ) 6 cm s v 0 8 0t t 0 (d) ( 4 t )( t) 0 t 4 0t s 8t t c

s 8t 5t t 48 cm 8(4) 5(4) 4 (a) x 0 y 97.50 z 60 (b) h = 7 044 008 50 7 5 6 60 0.5 (c) 0.5 600 00 RM78 (d) 0 0.5 00 56.6 4 (a)(i) ½(6)(AK)( ) = 4 Using formula of area of triangle 5 AK = 5 cm (ii) 4 cos AKB 5 AB = 5 + 6 4 (5)(6)( ) 5 Using cosine rule AB = 0. cm (b) = x + 6 (x)(6)( 4 ) 5 Using cosine rule (c)(i) 5x 8x + 560 = 0 Simplify to general form Draw obtuse triangle or shows point C on KC and side BC B 6 cm K C B or A K C C

(ii) sin K' CB ' ' 5 6 Using sine rule K C B = 6.87 5 (a) x.5y 0 or 4x 5y 40 40x 80y 640 or x y 6 x y (b) Refer to graph x and y axes with correct scales At least two lines drawn correctly Correct region shaded (c)(i) {4,5,6} or 4 x 6 (ii) Maximum point ( 8, 4 ) 5 (8 ) + 45 ( 4 ) RM 80

y Graph for Question 5 8 7 x = y 6 5 R 4 ( 8, 4 ) 0 4x + 5y = 40 4 6 8 0 4 6 x + y = 6 x