FREQUENCY-RESPONSE DESIGN

Similar documents
ELECTRONICS & COMMUNICATIONS DEP. 3rd YEAR, 2010/2011 CONTROL ENGINEERING SHEET 5 Lead-Lag Compensation Techniques

Today (10/23/01) Today. Reading Assignment: 6.3. Gain/phase margin lead/lag compensator Ref. 6.4, 6.7, 6.10

Stability of CL System

Systems Analysis and Control

DESIGN USING TRANSFORMATION TECHNIQUE CLASSICAL METHOD

INTRODUCTION TO DIGITAL CONTROL

Automatic Control 2. Loop shaping. Prof. Alberto Bemporad. University of Trento. Academic year

EE 4343/ Control System Design Project LECTURE 10

Systems Analysis and Control

Exercise 1 (A Non-minimum Phase System)

Exercise 1 (A Non-minimum Phase System)

Professor Fearing EE C128 / ME C134 Problem Set 7 Solution Fall 2010 Jansen Sheng and Wenjie Chen, UC Berkeley

Control Systems I Lecture 10: System Specifications

CDS 101/110a: Lecture 8-1 Frequency Domain Design

Transient response via gain adjustment. Consider a unity feedback system, where G(s) = 2. The closed loop transfer function is. s 2 + 2ζωs + ω 2 n

Dr Ian R. Manchester Dr Ian R. Manchester AMME 3500 : Review

Homework 7 - Solutions

MAS107 Control Theory Exam Solutions 2008

EE C128 / ME C134 Fall 2014 HW 8 - Solutions. HW 8 - Solutions

DIGITAL CONTROLLER DESIGN

Outline. Classical Control. Lecture 5

Chapter 2. Classical Control System Design. Dutch Institute of Systems and Control

Lecture 6 Classical Control Overview IV. Dr. Radhakant Padhi Asst. Professor Dept. of Aerospace Engineering Indian Institute of Science - Bangalore

AMME3500: System Dynamics & Control

Exercises for lectures 13 Design using frequency methods

Classify a transfer function to see which order or ramp it can follow and with which expected error.

ECE317 : Feedback and Control

ECE 486 Control Systems

CHAPTER 7 : BODE PLOTS AND GAIN ADJUSTMENTS COMPENSATION

Plan of the Lecture. Goal: wrap up lead and lag control; start looking at frequency response as an alternative methodology for control systems design.

Raktim Bhattacharya. . AERO 422: Active Controls for Aerospace Vehicles. Frequency Response-Design Method

Chapter 9: Controller design

(b) A unity feedback system is characterized by the transfer function. Design a suitable compensator to meet the following specifications:

EECS C128/ ME C134 Final Wed. Dec. 15, am. Closed book. Two pages of formula sheets. No calculators.

FEEDBACK CONTROL SYSTEMS

= rad/sec. We can find the last parameter, T, from ωcg new

FREQUENCY-RESPONSE ANALYSIS

Frequency Response Techniques

ECSE 4962 Control Systems Design. A Brief Tutorial on Control Design

MEM 355 Performance Enhancement of Dynamical Systems

The loop shaping paradigm. Lecture 7. Loop analysis of feedback systems (2) Essential specifications (2)

The requirements of a plant may be expressed in terms of (a) settling time (b) damping ratio (c) peak overshoot --- in time domain

MAE143a: Signals & Systems (& Control) Final Exam (2011) solutions

Control System Design

Boise State University Department of Electrical Engineering ECE461 Control Systems. Control System Design in the Frequency Domain

STABILITY ANALYSIS TECHNIQUES

Frequency methods for the analysis of feedback systems. Lecture 6. Loop analysis of feedback systems. Nyquist approach to study stability

16.30/31, Fall 2010 Recitation # 2

Introduction. Performance and Robustness (Chapter 1) Advanced Control Systems Spring / 31

1 (20 pts) Nyquist Exercise

BASIC PROPERTIES OF FEEDBACK

IC6501 CONTROL SYSTEMS

Robust Performance Example #1

EE3CL4: Introduction to Linear Control Systems

ROOT LOCUS. Consider the system. Root locus presents the poles of the closed-loop system when the gain K changes from 0 to. H(s) H ( s) = ( s)

EECS C128/ ME C134 Final Thu. May 14, pm. Closed book. One page, 2 sides of formula sheets. No calculators.

VALLIAMMAI ENGINEERING COLLEGE SRM Nagar, Kattankulathur

Radar Dish. Armature controlled dc motor. Inside. θ r input. Outside. θ D output. θ m. Gearbox. Control Transmitter. Control. θ D.

Loop shaping exercise

Delhi Noida Bhopal Hyderabad Jaipur Lucknow Indore Pune Bhubaneswar Kolkata Patna Web: Ph:

Module 3F2: Systems and Control EXAMPLES PAPER 2 ROOT-LOCUS. Solutions

Robust Control 3 The Closed Loop

KINGS COLLEGE OF ENGINEERING DEPARTMENT OF ELECTRONICS AND COMMUNICATION ENGINEERING

Systems Analysis and Control

Compensator Design to Improve Transient Performance Using Root Locus

100 (s + 10) (s + 100) e 0.5s. s 100 (s + 10) (s + 100). G(s) =

Module 5: Design of Sampled Data Control Systems Lecture Note 8

Active Control? Contact : Website : Teaching

Engraving Machine Example

D(s) G(s) A control system design definition

Dynamic circuits: Frequency domain analysis

STABILITY ANALYSIS. Asystemmaybe stable, neutrallyormarginallystable, or unstable. This can be illustrated using cones: Stable Neutral Unstable

Topic # Feedback Control Systems

6.302 Feedback Systems Recitation 16: Compensation Prof. Joel L. Dawson

Topic # Feedback Control. State-Space Systems Closed-loop control using estimators and regulators. Dynamics output feedback

Performance of Feedback Control Systems

Systems Analysis and Control

Intro to Frequency Domain Design

EE C128 / ME C134 Fall 2014 HW 6.2 Solutions. HW 6.2 Solutions

Systems Analysis and Control

Lecture 5: Frequency domain analysis: Nyquist, Bode Diagrams, second order systems, system types

PID controllers. Laith Batarseh. PID controllers

An Internal Stability Example

ECE382/ME482 Spring 2005 Homework 7 Solution April 17, K(s + 0.2) s 2 (s + 2)(s + 5) G(s) =

Course Summary. The course cannot be summarized in one lecture.

Last week: analysis of pinion-rack w velocity feedback

Lecture 11. Frequency Response in Discrete Time Control Systems

Dynamic Compensation using root locus method

LINEAR CONTROL SYSTEMS. Ali Karimpour Associate Professor Ferdowsi University of Mashhad

Control Systems. Control Systems Design Lead-Lag Compensator.

Positioning Servo Design Example

ECE382/ME482 Spring 2005 Homework 8 Solution December 11,

Chapter 6 - Solved Problems

Analysis of SISO Control Loops

Introduction to Feedback Control

Dr Ian R. Manchester

Systems Analysis and Control

Lecture 1: Feedback Control Loop

Table of Laplacetransform

Automatic Control (TSRT15): Lecture 7

Transcription:

ECE45/55: Feedback Control Systems. 9 FREQUENCY-RESPONSE DESIGN 9.: PD and lead compensation networks The frequency-response methods we have seen so far largely tell us about stability and stability margins of a closed-loop system based on open-loop response. Now, we look at frequency-response based design methods which primarily aim at improving stability margins. Also, given the relationship between PM and performance, we have some idea of transient response as well. Start thinking of Bode-magnitude and Bode-phase plots as LEGO to make the frequency response we want. PD compensation Compensator D(s) = K ( + TD s). We have seen from root-locus that this has a stabilizing effect. Magnitude and phase effect: K 9 K. T D T D. T D T D Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli T D T D

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 2 PD controller increases phase for frequencies over ω./td.so, locate /T D < crossover so that phase margin at crossover is better. Problem: Magnitude response continues to increase as frequency increases. This amplifies high-frequency sensor noise. Lead compensation [ ] Ts + Compensator D(s) = K αts +, α <. Approximate PD control for frequencies up to ω = αt. Magnitude and phase effect: K α φ max K T ω max αt. T The phase contributed at frequency ω is T ω max αt αt φ = tan (T ω) tan (αt ω). To find where the maximum phase contribution is, we take the derivative of φ with respect to ω and set it to zero dφ dω = dtan (T ω) dω = T T 2 ω 2 + dtan (αt ω) dω αt α 2 T 2 ω 2 + = Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 3 α 2 T 3 ω 2 + T = αt 3 ω 2 + αt T 3 ω 2 α(α ) = T (α ) ω max = T α. For this frequency, the amount of phase added is φ max = tan (T ω max ) tan (αt ω max ) ( ) ( ) α = tan α tan α }{{}}{{} θ θ 2 To get a simpler expression, consider the triangles to the right. + α φ max θ θ 2 We can solve for φmax using the law of cosines. This gives: α α + α 2 α α ( α) 2 = ( + α) + (α + α 2 ) 2 + α α + α 2 cos (φ max ) 2α + α 2 = + 2α + α 2 2 + α α + α 2 cos (φ max ) 4α cos (φ max ) = 2 + α α + α = 2 α 2 ( + α). Now, we remember that cos 2 (θ) + sin 2 (θ) =, so sin 2 (φ max ) = 4α ( + α) 2 = ( + α)2 4α ( + α) 2 So, we conclude that = ( α)2 ( + α) 2. Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 4 ( ) α φ max = sin + α We can invert this to find α to add a certain phase φmax α = sin(φ max) + sin(φ max ). We can show that ωmax occurs mid-way between T and on a log αt scale ( ) ( ) ( ) log(ω max ) = log T = log + log αt T αt. = 2 [ ( ) ( )] log + log. T αt 9 8 How much can we improve phase with a lead network? φmax 7 6 5 4 3 2 2 If we need more phase improvement, we can use a double-lead compensator: D(s) = K [ ] Ts + 2. αts + Need to compromise between good phase margin and good sensor noise rejection at high frequency. /α Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 5 9.2: Design method # for lead controllers Design specification include: Desired steady-state error. Desired phase margin. Compute steady-state error of compensated system. Set equal to desired steady-state error by computing K. Evaluate the PM of the uncompensated system using the value of K from above. ω max initially set to crossover frequency. Add a small amount of PM (5 to 2 )totheneededphaselead. (Lead network moves crossover point, so need to design conservatively): Gives φ max. Determine α = sin(φ max ) + sin(φ max ). Determine T = ω max α. Iterate if necessary (choose a slightly different ωmax or φ max ). EXAMPLE: Plant G(s) = s(s + ) Specification : Want steady-state error for ramp input <.. Specification 2: Want overshoot Mp < 25%. Start by computing steady-state error [ ] e ss = lim s R(s) s + D(s)G(s) [ ] = lim = s s + D(s) D(). (s+) Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 6 [ ] Ts + D(s) = K αts + So, D() = K so D() = K. =.... K =. In Bode plot below, red line is original plant. Green line is plant with added gain of K =, butnoleadcompensator. We see that the new crossover is at 3 rad s,soω max = 3rads. Overshoot specification Mp < 25% gives PM > 45. Evaluating (red line) Bode diagram of KG(s) at crossover, we see we have a phase margin of 8.Needabout27 more to meet spec. Note, addition of pole and zero from lead network will shift crossover frequency somewhat. To be safe, design for added phase of 37 instead of 27. α = sin(37 ) + sin(37 ) =.25. T =.25(3) =.667. So, D(s) = [ 2s/3 + 2s/2 + ]. In plots below, the blue line is the Bode plot of the compensated system KD(s)G(s). Also, uncompensated root locus is plotted top-right; compensated root locus is plotted bottom-right. We find that we just missed specifications: PM = 44.Iterateif desired to meet specs. Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 7 Magnitude Phase 6 5 4 3 2 2 3 4 2 2 9 2 3 4 5 6 7 ω (rad/sec) 8 2 2 ω (rad/sec) Imag Axis Imag Axis.5.5.5.5 2.5.5.5 6 4 2 2 4 Real Axis 6 7 6 5 4 3 2 2 Real Axis Amplitude.2.8.6.4.2 Step Response Amplitude 3 2.5 2.5.5 Ramp Response.5.5 2 2.5 Time (sec.) Summary of design example..5.5 2 2.5 3 Time (sec.). Determine dc-gain so that steady-state errors meet spec. 2. Select α and T to achieve an acceptable PM at crossover. Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 8 9.3: Design method #2 for lead controllers Design specifications Desired closed-loop bandwidth requirements (rather than e ss ). Desired PM requirements. Choose open-loop crossover frequency ωc to be half the desired closed-loop bandwidth. Evaluate KG = G( jω c ) and φ G = G( jω c ). Compute phase lead required φmax = PM φ G 8. Compute α = sin(φ max ) + sin(φ max ). Compute T = αωc. Compensation is [ ] Ts + D(s) = K αts + α D( jω c ) =K + α α + = K α + α α + = K. α Open-loop gain at ωc is designed to be : D( jω c ) G( jω c ) = K α G( jω c ) = Our design is now complete. K = α K G. Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 9 EXAMPLE: Desired gain crossover frequency of radians per second. Desired PM of 6. G(s) = s(s + ). KG = j( j + ) =., φ G = 74.3. φmax = 6 + 74.3 8 = 54.3. sin(φ max ) α = + sin(φ max ) =.37. T = α =.35. K D = α K G = 32.36. Matlab code to automate this procedure: % [K,T,alpha]=bod_lead(np,dp,wc,PM) % Computes the lead compensation of the plant np/dp to have % phase margin PM (in degrees) at crossover frequency wc (in radians/sec). % e.g., [K,T,alpha]=bod_lead([],[ ],5,6); function [K,T,alpha]=bod_lead(np,dp,wc,PM) % first compute the plant response at wc. [magc,phc]=bode(np,dp,wc); % now, compute the needed phase lead at wc and convert to radians % for use with "sine" phir=(-8+pm-phc)*pi/8; if abs(phir)pi/2, fprintf('a simple phase lead/lag cannot change the phase by more\n'); fprintf('than +/- 9 degrees.\n'); error('aborting.'); end; % Compute alpha, T, and K for compensator alpha=(-sin(phir))/(+sin(phir)); T=/(wc*sqrt(alpha)); K=sqrt(alpha)/magc; Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 % compute the new open-loop system by convolving the plant polynomials % with the compensator polynomials. nol=conv(np,k*[t ]); dol=conv(dp,[alpha*t ]); % check the solution by plotting the Bode plot for the new open-loop % polynomials. Include the frequency w= % to get the full resonance response to show the gain margin. Also, plot % the uncompensated Bode response. w=logspace(-2,)*wc; w(34)=wc; clf; [mag,ph]=bode(np,dp,w); [mag2,ph2]=bode(nol,dol,w); subplot(2); semilogx(w/wc,2*log(mag),'--'); hold on; semilogx(w/wc,2*log(mag2)); grid; plot(w/wc,*w+,'g-'); ylabel('magnitude (db)'); title('phase-lead design (uncompensated=dashed; compensated=solid)'); subplot(22); semilogx(w/wc,ph,'--'); hold on; semilogx(w/wc,ph2); grid; plot(w/wc,*w-8+pm,'g-'); ylabel('phase'); xlabel('frequency/wc (i.e., ""=wc)'); Matlab results: Magnitude (db) Phase Phase lead design (uncompensated=dashed; compensated=solid) 4 2 2 4 6.. 9 2 5 8.. Frequency/wc (i.e., ""=wc) Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 9.4: PI and lag compensation PI compensation In many problems it is important to keep bandwidth low, and also reduce steady-state error. PI compensation used here. K D(s) = K [ + T I s ]..ωt I ωt I ωt I K 9 ωt I ωt I Infinite gain at zero frequency Reduces steady-state error to step, ramp, etc. But also has integrator anti-windup problems. Adds phase below breakpoint. We want to keep breakpoint frequency very low to keep from destabilizing system. Lag compensation T I ω c. Approximates PI, but without integrator overflow. [ ] Ts + D(s) = α α>. αts + Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 2 Primary objective of lag is to add 2 log α db gain to low frequencies without changing PM. α αt T αt T 9 Steady-state response improves with little effect on transient response. Typical process Assumption is that we need to modify (increase) the dc-gain of the loop transfer function. If we apply only a gain, then ω c typically increases and the phase margin decreases. NOT GOOD. Instead, use lag compensation to lower high-frequency gain. Assume plant has gain K (adjustable), or that we insert a gain K into the system. Adjust the open-loop gain K to meet phase margin requirements (plus about 5 slop factor) at crossover without additional compensation. Draw Bode diagram of system using the gain K from above. Evaluate low-frequency gain. Determine α to meet low-frequency gain requirements. Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 3 Choose one corner frequency ω = (the zero) to be about one T decade below crossover frequency. (This way, the phase added by the lag compensator will minimally affect PM. Thephaseaddedat crossover will be about 5,henceourpreviousslopfactor). The other corner frequency is at ω = αt. Iterate design to meet spec. EXAMPLE: K G(s) = (.5 s + ) (s + ) ( 2 s + ). Bode plot for plant is red line, below. Uncompensated root locus is top-right plot. We want to design compensator for PM 25, K p = 9.. Set K = 4.5 for PM = 3.Thisgivescrossoveratω c.2 rads/sec. (Green line on Bode plot.) 2. Low-frequency gain now about 3 db or (3/2) = 4.5. 3. Should be raised by a factor of 2 to get K p = 9. So,α = 2. 4. Choose corner frequency at ω =.2 rads/sec. =.2, ort = 5. T 5. We then know other corner frequency ω = αt =..4 Step Response From: U() Altogether, we now have the compensator [ ] 5s + D(s) = 2. s + Amplitude To: Y().2.8.6.4.2 5 5 2 25 Time (sec.) Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 4 2 2 Magnitude Phase 2 3 4 2 2 3 6 9 2 5 8 2 24 ω (rad/sec) 27 2 2 ω (rad/sec) Imag Axis Imag Axis 2 3.5 3 2.5 2.5.5.5 2 Real Axis 2 3.5 3 2.5 2.5.5.5 Real Axis Please understand that the recipes in these notes are not meant to be exhaustive! And, we often require both lead and lag to meet specs. Many other approaches to control design using frequency-response methods exist. In fact, once you are comfortable with Bode plots, you can add poles and zeros like LEGOs to build whatever frequency response you might like (within the limitations of Bode s gain-phase theorem). Our next section gives some guidance on this. Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 5 9.5: Design based on sensitivity Goal: Develop conditions on Bode plot of loop transfer function D(s)G(s) that will ensure good performance with respect to sensitivity, steady-state errors and sensor noise. Steady-state performance = lower bound on system low-freq. gain. Sensor noise = upper bound on high-frequency gain. Consider also the risk of an unmodeled system resonance: Magnitude may go over. Can cause instability. Must ensure that high-frequency gain is low so magnitude does not go over. Magnitude 2 4 6 8 2 Frequency Together, these help us design a desired loop frequency response: Magnitude must be high at low frequencies, and Low at high frequencies. Magnitude of D(s)G(s) Steady-state Error Boundary Sensor noise and plant sensitivity boundary Sensitivity functions The presence of noises also enters our design considerations. w(t) r(t) D(s) G(s) y(t) v(t) Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 6 Y (s) = W (s) + G(s)D(s)[R(s) V (s) Y (s)] [ + G(s)D(s)] Y (s) = W (s) + G(s)D(s)[R(s) V (s)] or, Y (s) = G(s)D(s) W (s) + [R(s) V (s)]. + G(s)D(s) + G(s)D(s) Tracking error = R(s) Y (s) G(s)D(s) E(s) = R(s) W (s) [R(s) V (s)] + G(s)D(s) + G(s)D(s) = + G(s)D(s) [R(s) W (s)] + G(s)D(s)V (s) + G(s)D(s) Define the sensitivity function S(s) to be S(s) = + G(s)D(s) which is the transfer function from r(t) to e(t) and from w(t) to e(t). The complementary sensitivity function T (s) = S(s) S(s) = G(s)D(s) + G(s)D(s) = T (s) which is the transfer function from r(t) to y(t). If V =, then and Y (s) = S(s)W (s) + T (s)r(s) E(s) = S(s)[R(s) W (s)]. The sensitivity function here is related to the one we saw several weeks ago SG T = T G G T = = + D(s)G(s) D(s)G(s) [ + D(s)G(s)] 2 + D(s)G(s) = S(s). G(s)[ + D(s)G(s)] G(s) Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 7 So S(s) is the sensitivity of the transfer function to plant perturbations. Recall that T (s) + S(s) =, regardlessofd(s) and G(s). We would like T (s) =. ThenS(s) = ; Disturbanceiscancelled, design is insensitive to plant perturbation, steady-state error. BUT, forphysicalplants,g(s) for high frequencies (which forces S(s) ). Furthermore, the transfer function between V (s) and E(s) is T (s). To reduce high frequency noise effects, T (s) as frequency increases, and S(s). Typical sensitivity and complementary sensitivity (closed-loop transfer) functions are: S( jω) Performance Spec. T ( jω) Stability Spec. Another view of sensitivity: So, + D( jω)g( jω) is the distance between the Nyquist + D( jω)g( jω) curve to the point, and S( jω) =. D( jω)g( jω) + D( jω)g( jω) I(s) R(s) Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 8 Alargevalueof S( jω) indicates a nearly unstable Nyquist plot. The maximum value of S is a more accurate measure of stability than PM or GM. So,wewantmax S( jω) small. How small? Note: E( jω) = S( jω)r( jω) E( jω) = S( jω)r( jω) S( jω) R( jω) put a frequency-based error bound Let W (ω) = R( jω)/e b.then, E( jω) S( jω) R( jω) e b S( jω) W (ω). EXAMPLE: Aunity-feedbacksystemistohaveanerrorlessthan.5 for all unity-amplitude sinusoids below 5 rads/sec. Draw W ( jω) for this design. Spectrum of R( jω) is unity for ω 5. Since eb =.5, W (ω) =.5 = 2 5 for this range. 5 5 2 Magnitude 2 5 Frequency (rads/sec.) We can translate this requirement into a loop-gain requirement. When errors are small, loop gain is high, so S( jω) D( jω)g( jω) and D( jω)g( jω) W (ω) or, D( jω)g( jω) W (ω) Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 9 9.6: Robustness Typically there is some uncertainty in the plant transfer function. We want our design to be robustly stable, and to robustly give good performance (often called H design). Uncertainty often expressed as multiplicative G( jω) = G n ( jω)[ + W 2 ( jω) ( jω)] W2 (ω) is a function of frequency expressing uncertainty, or size of possible error in transfer function as a function of frequency. W2 (ω) is almost always small at low frequencies. W2 (ω) increases at high frequencies as unmodeled structural flexibility is common. Typical W2 Magnitude 7 6 5 4 3 2 5 5 2 Frequency (rads/sec.) ( jω) expresses uncertainty in phase. The only restriction is Design ( jω). Assume design for nominal plant Gn (s) is stable. Thus, + D( jω)g n ( jω) = ω. Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 2 For robust stability, + D( jω)g n ( jω) + D( jω)g n ( jω) }{{} = by assumption + D( jω)g( jω) = ω + D( jω)g n ( jω)[ + W 2 (ω) ( jω)] = + D( jω)g n( jω) + D( jω)g n ( jω) W 2(ω) ( jω) = recall, T ( jω) = D( jω)g n( jω) + D( jω)g n ( jω), [ + T ( jω)w 2 (ω) ( jω)] = so, T ( jω)w 2 (ω) ( jω) < or, T ( jω) W 2 (ω) <. For high freqencies D( jω)gn ( jω) is typically small, so T ( jω) D( jω)g n ( jω). Thus D( jω)g n ( jω) W 2 (ω) < D( jω)g n ( jω) < W 2 (ω). EXAMPLE: The uncertainty in a plant model is described by a function W 2 (ω) which is zero until ω = 3 rads/sec, and increases linearly from there to a value of at ω =, rads/sec. It remains constant at for higher frequencies. Plot constraint on D( jω)g n ( jω). Where W2 (ω) =, thereisnoconstraintonthemagnitudeoftheloop gain. Above ω = 3, /W 2 (ω) is a hyperbola from to. at,. Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli

ECE45/ECE55, FREQUENCY-RESPONSE DESIGN 9 2 Magnitude 8 7 6 5 4 3 2 2 4 6 8 Frequency (rads/sec.) Combining W (ω) and W 2 (ω) requirements, 8 Log Magnitude 6 4 2 2 4 6 8 2 4 6 8 Frequency (rads/sec.) Limitation: Crossover needs to be with slope. So,cannotmake constraints too strict, or design will be unstable. Lecture notes prepared by and copyright 998 23, Gregory L. Plett and M. Scott Trimboli