Dynamic Visualization of Complex Integrals with Cabri II Plus

Similar documents
Physics 235 Chapter 5. Chapter 5 Gravitation

RECTIFYING THE CIRCUMFERENCE WITH GEOGEBRA

Stanford University CS259Q: Quantum Computing Handout 8 Luca Trevisan October 18, 2012

The geometric construction of Ewald sphere and Bragg condition:

DonnishJournals

Section 8.2 Polar Coordinates

612 MHR Principles of Mathematics 9 Solutions. Optimizing Measurements. Chapter 9 Get Ready. Chapter 9 Get Ready Question 1 Page 476.

To Feel a Force Chapter 7 Static equilibrium - torque and friction

Physics 2B Chapter 22 Notes - Magnetic Field Spring 2018

working pages for Paul Richards class notes; do not copy or circulate without permission from PGR 2004/11/3 10:50

SMT 2013 Team Test Solutions February 2, 2013

PHYS 110B - HW #7 Spring 2004, Solutions by David Pace Any referenced equations are from Griffiths Problem statements are paraphrased

PDF Created with deskpdf PDF Writer - Trial ::

Duality between Statical and Kinematical Engineering Systems

MAGNETIC FIELD AROUND TWO SEPARATED MAGNETIZING COILS

Analysis of simple branching trees with TI-92

AST 121S: The origin and evolution of the Universe. Introduction to Mathematical Handout 1

Geometry of the homogeneous and isotropic spaces

3.1 Random variables

Physics 2A Chapter 10 - Moment of Inertia Fall 2018

A Bijective Approach to the Permutational Power of a Priority Queue

arxiv: v1 [physics.pop-ph] 3 Jun 2013

Math 2263 Solutions for Spring 2003 Final Exam

Introduction Common Divisors. Discrete Mathematics Andrei Bulatov

Gauss s Law Simulation Activities

arxiv: v1 [math.co] 1 Apr 2011

I. CONSTRUCTION OF THE GREEN S FUNCTION

Surveillance Points in High Dimensional Spaces

On the integration of the equations of hydrodynamics

Analytical time-optimal trajectories for an omni-directional vehicle

1 Similarity Analysis

Magnetic fields (origins) CHAPTER 27 SOURCES OF MAGNETIC FIELD. Permanent magnets. Electric currents. Magnetic field due to a moving charge.

Math 451: Euclidean and Non-Euclidean Geometry MWF 3pm, Gasson 204 Homework 9 Solutions

Hopefully Helpful Hints for Gauss s Law

Using Laplace Transform to Evaluate Improper Integrals Chii-Huei Yu

KEPLER S LAWS OF PLANETARY MOTION

HOW TO TEACH THE FUNDAMENTALS OF INFORMATION SCIENCE, CODING, DECODING AND NUMBER SYSTEMS?

The Archimedean Circles of Schoch and Woo

Prerna Tower, Road No 2, Contractors Area, Bistupur, Jamshedpur , Tel (0657) ,

Physics 111 Lecture 5 (Walker: 3.3-6) Vectors & Vector Math Motion Vectors Sept. 11, 2009

Introduction and Vectors

CALCULUS II Vectors. Paul Dawkins

15 Solving the Laplace equation by Fourier method

1.6. Trigonometric Functions. 48 Chapter 1: Preliminaries. Radian Measure

PHZ 3113 Fall 2017 Homework #5, Due Friday, October 13

What Form of Gravitation Ensures Weakened Kepler s Third Law?

Chapter 3 Optical Systems with Annular Pupils

20th Century Atomic Theory - Hydrogen Atom

Chapter 3: Theory of Modular Arithmetic 38

Lab #9: The Kinematics & Dynamics of. Circular Motion & Rotational Motion

Faraday s Law (continued)

Chapter 7-8 Rotational Motion

B. Spherical Wave Propagation

Tutorial on Strehl ratio, wavefront power series expansion, Zernike polynomials expansion in small aberrated optical systems By Sheng Yuan

( ) Make-up Tests. From Last Time. Electric Field Flux. o The Electric Field Flux through a bit of area is

Physics 2020, Spring 2005 Lab 5 page 1 of 8. Lab 5. Magnetism

MENSURATION-III

Graphs of Sine and Cosine Functions

( ) ( ) Review of Force. Part 1, Topic 1 Force Fields. Dr. Sven Achenbach - based on a script by Dr. Eric Salt - Outline. Review of Force. F r.

Lecture 28: Convergence of Random Variables and Related Theorems

21 MAGNETIC FORCES AND MAGNETIC FIELDS

The Schwartzchild Geometry

Unit 7: Sources of magnetic field

( ) [ ] [ ] [ ] δf φ = F φ+δφ F. xdx.

Welcome to Physics 272

$ i. !((( dv vol. Physics 8.02 Quiz One Equations Fall q 1 q 2 r 2 C = 2 C! V 2 = Q 2 2C F = 4!" or. r ˆ = points from source q to observer

Uniform Circular Motion

Force between two parallel current wires and Newton s. third law

- 5 - TEST 1R. This is the repeat version of TEST 1, which was held during Session.

Kepler s problem gravitational attraction

The Congestion of n-cube Layout on a Rectangular Grid S.L. Bezrukov J.D. Chavez y L.H. Harper z M. Rottger U.-P. Schroeder Abstract We consider the pr

MODULE 5a and 5b (Stewart, Sections 12.2, 12.3) INTRO: In MATH 1114 vectors were written either as rows (a1, a2,..., an) or as columns a 1 a. ...

Kinematics in 2-D (II)

3.2 Centripetal Acceleration

Fresnel Diffraction. monchromatic light source

MATH 415, WEEK 3: Parameter-Dependence and Bifurcations

Semicanonical basis generators of the cluster algebra of type A (1)

ON LACUNARY INVARIANT SEQUENCE SPACES DEFINED BY A SEQUENCE OF MODULUS FUNCTIONS

As is natural, our Aerospace Structures will be described in a Euclidean three-dimensional space R 3.

MATH 417 Homework 3 Instructor: D. Cabrera Due June 30. sin θ v x = v r cos θ v θ r. (b) Then use the Cauchy-Riemann equations in polar coordinates

Complex Eigenvalues. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

Liquid gas interface under hydrostatic pressure

6 PROBABILITY GENERATING FUNCTIONS

Rotational Motion. Lecture 6. Chapter 4. Physics I. Course website:

PHYSICS NOTES GRAVITATION

Polar Coordinates. a) (2; 30 ) b) (5; 120 ) c) (6; 270 ) d) (9; 330 ) e) (4; 45 )

Rigid Body Dynamics 2. CSE169: Computer Animation Instructor: Steve Rotenberg UCSD, Winter 2018

MATH Non-Euclidean Geometry Exercise Set 3: Solutions

The Poisson bracket and magnetic monopoles

A Comment on Increasing Returns and Spatial. Unemployment Disparities

Flux. Area Vector. Flux of Electric Field. Gauss s Law

Electrostatics (Electric Charges and Field) #2 2010

Modeling of High Temperature Superconducting Tapes, Arrays and AC Cables Using COMSOL

A moving charged particle creates a magnetic field vector at every point in space except at its position.

Describing Circular motion

APPLICATION OF MAC IN THE FREQUENCY DOMAIN

Compactly Supported Radial Basis Functions

THE NUMBER OF TWO CONSECUTIVE SUCCESSES IN A HOPPE-PÓLYA URN

ON INDEPENDENT SETS IN PURELY ATOMIC PROBABILITY SPACES WITH GEOMETRIC DISTRIBUTION. 1. Introduction. 1 r r. r k for every set E A, E \ {0},

PHY2061 Enriched Physics 2 Lecture Notes. Gauss Law

Transcription:

Dynamic Visualiation of omplex Integals with abi II Plus Sae MIKI Kawai-juu, IES Japan Email: sand_pictue@hotmailcom Abstact: Dynamic visualiation helps us undestand the concepts of mathematics This pape shows that of complex integals with abi II Plus The geometical intepetation of complex numbes was intoduced by Gauss using the complex plane, but in geneal this geometical idea has not been sufficiently made much of in the scene of education This is only taught in the beginning, and is aely used in teaching complex integation Futhemoe its dynamic visualiation is hadly found out And this is one of the most difficult fields fo students, while it often appeas in studying science This pape highlights not only the visualiation of mathematical concepts but also the effectuality of moving figues Obseving thei movements maes it easie to find out mathematical popeties abi Geomety enables us to mae moving figues without the nowledge of pogamming omplex integals ae visualied with the idea of the quadatue mensuation by pats, using the geometical intepetation of the poduct of complex numbes; otation and dilation This dynamic visualiation helps students undestand complex integation deeply Intoduction This pape gives the dynamic visualiation of complex integals with abi II Plus, which is a dynamic geomety softwae ([] The integal of a eal vaiable function y=f(x on the xy-plane is easily visualied as an aea This idea is often used in the scene of the education, and helps students undestand the meaning of the integation As fo the complex integation, such visualiation is hadly shown, and it may dive students to thin that complex integation is difficult Thee ae only some wos ([], [3], and [4] fo the visualiation of complex integals I d lie to expand thei wos In this pape we can get esults of integals without calculation We only need to daw a cicle (o an ac with a cetain length of a sting Futhemoe, in this way, we can find the symmetic popety of complex integals Thus we easily undestand the special popety of /, and it leads us to open the doo to the concept of esidues, which explains us the necessity of Lauent expansion abi II Plus povides us oppotunities to ceate moving figues only with basic nowledge of geomety

Visualiing Fou Opeations of omplex Numbes We will get the values of integals by epetition of multiplication and addition, which ae geometically visualied on Gauss plane Addition and subtaction of complex numbes ae shown as those of vectos We can use tools of abi II Plus to daw the sum of vectos As fo multiplication and division, they ae shown as otation and dilation; i =,ag = θ, ie, e θ = (,, 3 =, 3 = 3 =, θ3 = θ+ θ The maco in abi II Plus can emembe a flow of constuctions and is useful fo multiplication and quotient of vectos which need epeated constuctions In this pape we egad the aguments of complex numbes to be the positive least 3 Visualiing omplex Integals 3 Quadatue Mensuation by Pats Def f ( d = lim f( ( = + The integal is defined as the quadatue mensuation by pats, which is the sum of poducts Fo simplification, we divide the contou equally by n; all the s have the same length As fo the eal integation, it can be explained as the aea; b n n = 0 ( f ( xdx = lim f( x x = S: aea a n n = 0 { f f f } = lim ( + ( + L + ( n 0 0 n n 3 omplex Integals of α along the icle centeed at the oigin and adius (α : intege The following examples visualie complex integals by multiplication and addition as we have seen in the pevious chapte Th ( α ( α = d 0 α = πi : the cicle centeed at the oigin and adius, : the loop integal Ex ( α d = 0 =

def d = lim ( 0 0 + + L + n n ( = + n With n lage enough, we can egad uuuu uuuuuu OP and PP + to be pependicula and the total sum of s to be the whole cicumfeence of the cicle Now let s thin about the esult of the poduct See Fig (This figue is constucted with the tools of abi II Plus such as icle, Pependicula Line, Measuement Tansfe, etc We can mae a maco to constuct diectly fom and Let n be 0, fo example π π π =, =, ag = = θ, ag ( = θ + 0 0 π π =, ag( = θ + ( = 0,, L, n 0 Fig The Result of the Poduct Then we tae the sum fo = 0,, L,9 See Fig (Macos made in abi II Plus help us epeat the constuctions 4 3 =0,,,,9 0 9 9 Fig Taing the Sum of s fo = 0,, L,9

Imagine a sting winded fom the oigin aound a cicle This sting has the length π 9 =, and goes aound anticlocwise along the cicle twice until the end of the whole = 0 9 π cicle, because the sum of the exteio angles equals to 4π = { ( θ+ θ } = 0 = 0 0 The esult of this calculation appeas as the end point of the sting; 0 Now we get Theefoe, 9 = 0 ( = 0 n= 0 ( α d = 0 = Ex Now let s thin about the esults of the poduct d = πi = ( α See Fig3 =, π =, n π ag = = θ n, ag ( π = θ + π =, n π π ag( = θ + θ + = ( = 0,, L, n Note that evey is independent of, and ag( always equals to π Fig3 The Result of the Poduct

Let n be 0, and we shall obseve the sum of s ( = 0,, L, n See Fig4 9 9 π i =0,,,, 0 0 Fig4 Taing the Sum of s fo = 0,, L,9 This time the sting has the length π, and goes upight The esult of this calculation appeas as the end point of the sting; π i Now we get 9 = π i ( n= 0 = 0 Theefoe, d = πi ( α = Γ In addition, this example has also visualied the following integal; d log = + Ex3 Now let s thin about the esult of the poduct See Fig5 d 0 = = ( α =, π =, ag π θ = = n n, ag ( π = θ + π π =, ag( = θ ( = 0,, L, n n

Fig5 The Result of the Poduct Fig6 Taing the Sum of s fo = 0,, L,9 This time the sting has the length π, and goes aound clocwise along the cicle once until the end of the whole cicle The esult of this calculation appeas as the end point of the sting; 0 See Fig6 Now we get

Theefoe, 9 = 0 ( n = 0 = 0 d = 0 ( α = Summay of 3 Substituting α = β into Th, we obtain the following theoem Th β ( β ( β = d 0 0 = πi 0 : the cicle centeed at the oigin and adius, : the loop integal As well as Ex to 3, def β β 0 β β n d lim 0 n = + + L + n 0 n β β =, π n ag = βθ, ag =, ( β π = β π =, ag( = βθ + n β β π The sting has the length π β, and goes aound anticlocwise along the cicle β times ( if β < 0 then clocwise, and if β = 0 then goes upight until the end of the cicle The esult of this calculation appeas as the end point of the sting; 0( β 0 and i ( 0 π β = See Table

The Length of the Sting = π β Table Popeties of the Sting Appeaing in β d n n n β β β π β π β ; the length of = = = n = π = 0 = 0 = 0 n n How Many Times the Sting Tuns Aound = β times anticlocwise n n β + β π ; the sum of the exteio angles = + = { β ( θ+ θ } = n β = πβ = 0 + = 0 n The End Point of the Sting = 0( β 0 and πi ( β = 0 The esults led by this method ae justified by the following calculations; iθ iθ = e, θ :0 π, d = ie dθ π π β β iβθ iθ β iβθ d = e ie dθ = i e dθ 0 i θ= θ e θ= 0 π β β iβθ πβ i e e e iβ = = = β θ = 0 i θ = 0 i 0 ( 0 ( β 0 π [ θ] = πi ( β = 0 These esults ae symmetic with espect to β Now we get the symmetic popety of integals See Table

β = 0 d = π i length = π Table The Symmetic Popety of Integals otaion = 0times i β = β = d = 0 length = π otaion = time d = 0 length = π otaion = times β = β = d = 0 length = π otaion times = d = 3 0 length = π otaion = times β = 3 β = 3 d= 0 3 length = π otaion = 3times d = 0 4 3 length = π otaion = 3times

33 Lauent seies and Residue The discussion in 3 shows the following theoem Th3 f ( d = πia a a whee f( = L+ + + a0 + a+ a + L (* : the cicle centeed at the oigin and adius (* is called Lauent seies, and this is the theoem of esidue, which shows the impotance of Lauent expansion 4 onclusion Dynamic visualiation is so effective Thans to this idea, we can undestand the complex integals and find the vaious popeties In the pocess of visualiation I found the symmety of integals Integals along the othe contous ae also visualied in this way, and othe theoems, fo example Rouche s theoem, could be visualied with this idea I hope students ae taught the complex integals with this idea and easily undestand the concepts with images Fo dynamic visualiation abi II Plus is vey useful Refeences [] abi Geomety II plus, http://wwwcabicom [] KOBAYASHI Ichio, Gasping the concept of integals of complex-valued functions using abi, IME9 abi poject, 000, http://wwwiescojp/math/ime9/ [3] KOBAYASHI Ichio, Undestanding omplex Analysis concepts with the help of abi, abiwold00 in Monteal, 00, http://wwwiescojp/math/cabi/abiw00_hp/ [4] Tistan Needham, Visual omplex Analysis, laendon pess, Oxfod, 997