Asymptote. 2 Problems 2 Methods

Similar documents
Chapter 8: Converter Transfer Functions

( x) f = where P and Q are polynomials.

Curve Sketching. The process of curve sketching can be performed in the following steps:

RATIONAL FUNCTIONS. Finding Asymptotes..347 The Domain Finding Intercepts Graphing Rational Functions

CHAPTER 7 : BODE PLOTS AND GAIN ADJUSTMENTS COMPENSATION

8.1.6 Quadratic pole response: resonance

Math-3 Lesson 8-5. Unit 4 review: a) Compositions of functions. b) Linear combinations of functions. c) Inverse Functions. d) Quadratic Inequalities

Math-3 Lesson 1-4. Review: Cube, Cube Root, and Exponential Functions

Polynomials, Linear Factors, and Zeros. Factor theorem, multiple zero, multiplicity, relative maximum, relative minimum

8.4 Inverse Functions

Math Review and Lessons in Calculus

Example: When describing where a function is increasing, decreasing or constant we use the x- axis values.

Lab on Taylor Polynomials. This Lab is accompanied by an Answer Sheet that you are to complete and turn in to your instructor.

MHF 4U Unit 7: Combining Functions May 29, Review Solutions

9.3 Graphing Functions by Plotting Points, The Domain and Range of Functions

Objectives. By the time the student is finished with this section of the workbook, he/she should be able

Differentiation. The main problem of differential calculus deals with finding the slope of the tangent line at a point on a curve.

0,0 B 5,0 C 0, 4 3,5. y x. Recitation Worksheet 1A. 1. Plot these points in the xy plane: A

Analog Computing Technique

Extreme Values of Functions

MEAN VALUE THEOREM. Section 3.2 Calculus AP/Dual, Revised /30/2018 1:16 AM 3.2: Mean Value Theorem 1

Solution: K m = R 1 = 10. From the original circuit, Z L1 = jωl 1 = j10 Ω. For the scaled circuit, L 1 = jk m ωl 1 = j10 10 = j100 Ω, Z L

Review of Prerequisite Skills for Unit # 2 (Derivatives) U2L2: Sec.2.1 The Derivative Function

Solutions for Homework #8. Landing gear

3. Several Random Variables

Fs (30.0 N)(50.0 m) The magnitude of the force that the shopper exerts is f 48.0 N cos 29.0 cos 29.0 b. The work done by the pushing force F is

Decibels, Filters, and Bode Plots

10. Joint Moments and Joint Characteristic Functions

Differential Equaitons Equations

Exponential and Logarithmic. Functions CHAPTER The Algebra of Functions; Composite

Physics 5153 Classical Mechanics. Solution by Quadrature-1

Class 8 Multiplication of Polynomials

Philadelphia University Faculty of Engineering Communication and Electronics Engineering

Decibels, Filters, and Bode Plots

Additional exercises in Stationary Stochastic Processes

AH 2700A. Attenuator Pair Ratio for C vs Frequency. Option-E 50 Hz-20 khz Ultra-precision Capacitance/Loss Bridge

Answer Key-Math 11- Optional Review Homework For Exam 2

Asymptotic Bode Plot & Lead-Lag Compensator

UNIVERSITY OF CALIFORNIA AT BERKELEY College of Engineering Department of Electrical Engineering and Computer Sciences. EE105 Lab Experiments

SIO 211B, Rudnick. We start with a definition of the Fourier transform! ĝ f of a time series! ( )

The achievable limits of operational modal analysis. * Siu-Kui Au 1)

8. THEOREM If the partial derivatives f x. and f y exist near (a, b) and are continuous at (a, b), then f is differentiable at (a, b).

Math 2412 Activity 1(Due by EOC Sep. 17)

Sec 3.1. lim and lim e 0. Exponential Functions. f x 9, write the equation of the graph that results from: A. Limit Rules

R. W. Erickson. Department of Electrical, Computer, and Energy Engineering University of Colorado, Boulder

Basic mathematics of economic models. 3. Maximization

Topic 4b. Open Methods for Root Finding

A Fourier Transform Model in Excel #1

AP Calculus Notes: Unit 1 Limits & Continuity. Syllabus Objective: 1.1 The student will calculate limits using the basic limit theorems.

Class 8 Introduction to Graphs

Flip-Flop Functions KEY

The 2nd Texas A&M at Galveston Mathematics Olympiad. September 24, Problems & Solutions

Calculators are NOT permitted.

Feedback Linearization

Functions Operations. To add, subtract, multiply, and divide functions. To find the composite of two functions.

ELEG 3143 Probability & Stochastic Process Ch. 4 Multiple Random Variables

Probability, Statistics, and Reliability for Engineers and Scientists MULTIPLE RANDOM VARIABLES

Universidad Carlos III de Madrid

GIMC-based Fault Detection and Its Application to Magnetic Suspension System

1/100 Range: 1/10 1/ 2. 1) Constant: choose a value for the constant that can be graphed on the coordinate grid below.

Definitions. Decade: A ten-to-one range of frequency. On a log scale, each 10X change in frequency requires the same distance on the scale.

Roberto s Notes on Differential Calculus Chapter 8: Graphical analysis Section 1. Extreme points

Lecture : Feedback Linearization

y2 = 0. Show that u = e2xsin(2y) satisfies Laplace's equation.

«Develop a better understanding on Partial fractions»

APPENDIX 1 ERROR ESTIMATION

UNIT #6 EXPONENTS, EXPONENTS, AND MORE EXPONENTS REVIEW QUESTIONS

Aggregate Growth: R =αn 1/ d f

Christoffel symbols and Gauss Theorema Egregium

Saturday X-tra X-Sheet: 8. Inverses and Functions

EEO 401 Digital Signal Processing Prof. Mark Fowler

Homework 7 - Solutions

Syllabus Objective: 2.9 The student will sketch the graph of a polynomial, radical, or rational function.

Function Operations. I. Ever since basic math, you have been combining numbers by using addition, subtraction, multiplication, and division.

1. Design a 3rd order Butterworth low-pass filters having a dc gain of unity and a cutoff frequency, fc, of khz.

Poles and Zeros and Transfer Functions

UNIVERSITY OF CALIFORNIA - SANTA CRUZ DEPARTMENT OF PHYSICS PHYS 112. Homework #4. Benjamin Stahl. February 2, 2015

1 Relative degree and local normal forms

A Systematic Approach to Frequency Compensation of the Voltage Loop in Boost PFC Pre- regulators.

CONVECTIVE HEAT TRANSFER CHARACTERISTICS OF NANOFLUIDS. Convective heat transfer analysis of nanofluid flowing inside a

ENGI 3424 Engineering Mathematics Five Tutorial Examples of Partial Fractions

! " k x 2k$1 # $ k x 2k. " # p $ 1! px! p " p 1 # !"#$%&'"()'*"+$",&-('./&-/. !"#$%&'()"*#%+!'",' -./#")'.,&'+.0#.1)2,'!%)2%! !"#$%&'"%(")*$+&#,*$,#

Lecture 8 Optimization

18-660: Numerical Methods for Engineering Design and Optimization

Response to a pure sinusoid

EECE 301 Signals & Systems Prof. Mark Fowler

Numerical Solution of Ordinary Differential Equations in Fluctuationlessness Theorem Perspective

ESE319 Introduction to Microelectronics Bode Plot Review High Frequency BJT Model

Solving Continuous Linear Least-Squares Problems by Iterated Projection

Acoustic forcing of flexural waves and acoustic fields for a thin plate in a fluid

New Functions from Old Functions

r + - FINAL June 12, 2012 MAE 143B Linear Control Prof. M. Krstic

Least-Squares Spectral Analysis Theory Summary

One-Dimensional Motion Review IMPORTANT QUANTITIES Name Symbol Units Basic Equation Name Symbol Units Basic Equation Time t Seconds Velocity v m/s

Definition: Let f(x) be a function of one variable with continuous derivatives of all orders at a the point x 0, then the series.

A NOVEL METHOD OF INTERPOLATION AND EXTRAPOLATION OF FUNCTIONS BY A LINEAR INITIAL VALUE PROBLEM

Mesa College Math SAMPLES

MODULE 6 LECTURE NOTES 1 REVIEW OF PROBABILITY THEORY. Most water resources decision problems face the risk of uncertainty mainly because of the

Heat Transfer: A Practical Approach - Yunus A Cengel Assignment 11 Fall 2003 Tuesday, November 18, 2003 Chapter 11, Problem 49

Canonical Forms of Multi-Port Dynamic Thermal Networks

Transcription:

Asymptote Problems Methods

Problems Assume we have the ollowing transer unction which has a zero at =, a pole at = and a pole at =. We are going to look at two problems: problem is where >> and problem is where >>. We will look at two methods to solve these two problems: one where the coeicient o the zero is / and the other where it is /. The goal is to determine the best way to calculate the Bode magnitude plot o the transer unction using asymptotes. A = j ( + j )( + j ) The process we will use is irst to determine the asymptotes associated with this transer unction. Then divide the requency spectrum into segments where these asymptotes deined. Then determine the composite asymptote by adding the asymptotes deined within each segment.

Problem : >> Method : Coeicient o the Zero = / A db = = + + + ( ) + ( ) log[ ] log( ) log ( ) log ( ) = + + log( ) log( ( ) ) log( ( ) ) where >> 3 Asymptotes can be determined rom the logarithmic orm Asymptote=log( ) Zero at = Asymptote= log( ) Pole at = Asymptote3= log( ) Pole at =

Problem : >> Method : Coeicient o the Zero = / To determine the composite, let's look are three regions (see the ollowing drawing): For > Composite = Asymptote = log( ) Zero slope=+db/decade For > > Composite = Asymptote + Asymptote = log( ) log( ) Zero + Pole at slope= For > Composite = Asymptote + Asymptote + Asymptote3 = log( ) log( ) log( )Zero + Pole at + Pole at slope=-db/decade

Problem : >> Method : Coeicient o the Zero = / 6 4 Zero Pole - Pole -4-6 -8 - - -4 6 4 Zero - Pole -4 Pole -6 Composite -8 - - -4 - -4-6 Magnitude Composite -8 - - -4

Problem : >> Method : Coeicient o the Zero = / To make the coeicient o the zero = /, we multiply the transer unction by / and we get. j j A ( + j )( + j ) ( + j )( + j ) + ( ) + ( ) = π = = tan ( ) tan ( ) Adb = log[ ] = log( ) + log( ) log + ( ) log + ( ) + ( ) + ( ) = log( ) + log( ) log( + ( ) ) log( + ( ) ) where >>

Problem : >> Method : Coeicient o the Zero = / A db = + + + log( ) log( ) log( ( ) ) log( ( ) ) We now ind there are 4 Asymptotes Asymptote= log( ) Constant Asymptote=log( ) Zero at = Asymptote3= log( ) Pole at = Asymptote4= log( ) Pole at =

Problem : >> Method : Coeicient o the Zero = / For > Composite = Asymptote+ Asymptote = log( ) + log( ) Constant + Zero slope=-db/decade For > > Composite = Asymptote + Asymptote + Asymptote3 = log( ) + log( ) log( ) For > Constant + Zero + Pole at slope= Composite = Asymptote + Asymptote + Asymptote3 + Aysmptote4 = log( ) log( ) log( ) log( ) Constant + Zero + Pole at + Pole at slope=-db/decade +

Problem : >> Method : Coeicient o the Zero = / 5 5 5-5 Constant Zero Pole Pole Constant 5 Zero Pole Pole -5 Composite - - -5-5 - -4-6 Magnitude Composite -8 - - -4

Problem : >> Method : Coeicient o the Zero = / A db = = + + + ( ) + ( ) log[ ] log( ) log ( ) log ( ) = + + log( ) log( ( ) ) log( ( ) ) where >> 3 Asymptotes Asymptote=log( ) Zero at = Asymptote= log( ) Pole at = Asymptote3= log( ) Pole at =

Problem : >> Method : Coeicient o the Zero = / For > Composite = Asymptote = log( ) Zero slope=+db/decade For > > Composite = Asymptote + Asymptote = log( ) log( ) Zero + Pole at slope= For > Composite = Asymptote + Asymptote + Asymptote3 = log( ) log( ) log( )Zero + Pole at + Pole at slope=-db/decade

5 Problem : >> Method : Coeicient o the Zero = / 5 5-5 Zero Pole Pole 5 Zero Pole Pole Composite -5 - - -5-5 - - Magnitude Composite -3-4 -5-6

Problem : >> Method : Coeicient o the Zero = / j j A ( + j )( + j ) ( + j )( + j ) + ( ) + ( ) Adb = = + + + + ( ) + ( ) = + ) log( + ( ) ) log( + ( ) ) = π = = tan ( ) tan ( ) log[ ] log( ) log( ) log ( ) log ( ) log( ) log( where >> 4 Asymptotes Asymptote=log( ) constant Asymptote=log( ) Zero at = Asymptote3= log( ) Pole at = Asymptote4= log( ) Pole at =

Problem : >> Method : Coeicient o the Zero = / For > Composite = Asymptote+ Asymptote = log( ) log( ) Constant + Zero slope=-db/decade For > > Composite = Asymptote + Asymptote + Asymptote3 = log( ) log( ) log( ) For > Constant + Zero + Pole at slope= + + Composite = Asymptote + Asymptote + Asymptote3 + Aysmptote4 = log( ) log( ) log( ) log( ) Constant + Zero + Pole at + Pole at slope=-db/decade +

Problem : >> Method : Coeicient o the Zero = / 5-5 Constant Zero Pole Pole 5 Constant Zero Pole Pole -5 Composite - - -5-5 Magnitude - Composite - -3-4 -5-6

Which one is easier? Whichever approach you chose you must be consistent and calculate the composite using all o the asymptotes in the region where they exist.