Fri 6 Nov 09. More IR Mass spectroscopy. Hour exam 3 Fri Covers Chaps 9-12 Wednesday: Review

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Fri 6 Nov 09 our exam 3 Fri 11-13 Covers Chaps 9-12 Wednesday: Review More IR Mass spectroscopy Good web site for IR, Mass, NMR spectra: http://riodb01.ibase.aist.go.jp/sdbs/cgi-bin/cre_index.cgi?lang=eng 11/6/2009 1

IR is good for identifying functional groups, but not good for Mol Wt. 3 C C 3 3 C C 3 3 C C 3 11/6/2009 2 2009 John W. Keller

IR is good for distinguishing some isomeric structures e.g. C 4 8 (NIST webbook) C- C- 3 C C 3 C= - C=C C=C- 2 C 11/6/2009 3 2009 John W. Keller C-

IR frequencies Table 12.1. Do not memorize handed out in exams. 2009 John W. Keller 11/6/2009 4

IR frequencies Table 12.1. Do not memorize handed out in exams. 11/6/2009 5 2009 John W. Keller

The compound from the following list that exhibits the infrared spectrum below is... 1. a 2. b 3. c 4. d 5. e 20 1804 7 1 2 0 a b c d e 11/6/2009 6 2009 John W. Keller

no no no no no no 11/6/2009 7 2009 John W. Keller

1-hexanol 3 C 5-hexen-1-ol C-- C-- C-C C- C=C =C-- 11/6/2009 8

The compound from the following list that best exhibits the infrared spectrum below is... 1. a 2. b 3. c 4. d 5. e 1 1 2120 a 0 0 b c 0 d e 1432 3311 2962 630 11/6/2009 9

The compound from the following list that best exhibits the infrared spectrum below is... The answer is... -C C- bend (alkyne bending: not in table) 2120 1432 3311 2962 630 11/6/2009 10

This compound must be a terminal alkyne, in spite of the fact that the C C stretch falls slightly outside the nominal range given in the WL table. 1) No other bond types absorb in the entire 1810-2400 cm -1 region except C N, which is not among the choices. 2) The terminal C C stretch at 2110 cm -1 does show medium intensity, meaning roughly 50% transmission. 3) Can t be an alcohol, there is no strong C- stretch at 1100 cm -1. 4) Can t be an amine or amide, since none of compounds contain N. 5) Can t be a carboxylic acid, since there is no C=. 6) Can t be aromatic: no medium peaks at either 3100 or 1600 cm -1. 11/6/2009 11

Mass spectrometry C 3 7 + Path of the heavier ion is bent less by mag field. C 4 10 + Vac pump removes neutrals Butane C 4 10 C 4 10+ + e - C 4 10+ C 3 7+ + C 3 11/6/2009 12

C 3 C 2 C 2 C 2 C 4 10 mw=74 Fragment ions Molecular ion M +. "Base peak" = highest x-axis in "m/z" = "mass-to-charge ratio" (usually z = +1, so effectively its m). 11/6/2009 13

3 C C 5 10 70.13 C 3 Molecular ion M +. M+1 ion Natural carbon contains 1% 13 C isotope, so if there are 5 C s in a molecule, then 5% of the molecules will have one 13 C. If there are 20 C s, the M+1 peak will be ~20% and the M+2 peak (two 13 Cs) will be about 2%. (The exact % M+1 and M+2 ions are also influenced by other isotopes such as 2, 18, etc) 11/6/2009 14

Cl and Br are common elements that occur as mixed isotopes with high percentages. 35 Cl 75.5% 37 Cl 24.5% 79 Br 50.5% 81 Br 49.5% C C Br M 12 C 21 5 79 Br M+2 12 C 21 5 81 Br M+3 13 C 12 C 1 5 81 Br M+1 13 C 12 C 1 5 79 Br 11/6/2009 15

See isotopic abundance web applet at http://www.chem.uoa.gr/applets/appletms/appl_ms2.html 11/6/2009 16

Routine mass spectra are resolved to about ±0.1 amu. igh resolution mass spectra may be resolved to ±0.00001 amu N 2 N 2 C 8 14 110.19 110.109550 C 6 10 N 2 110.15 110.084398 C 7 10 110.15 110.073165 C 6 6 2 110.11 110.036779 Molecular weights using most common isotopes ( 1 / 12 C/ 14 N/ 16 ) are significantly different at high resolution. 11/6/2009 17

Which electron is lost? Non-bonding electron if (or other heteroatom) Sigma bond for alkanes The electron hole is actually delocalized by orbital overlap. Therefore different bonds are susceptible to breakage. These electron losses cause fragmentation. We will discuss fragmentation patterns of three types of molecules (and not amines): Alcohols....alpha cleavage and dehydration Alkanes C-C bond breakage Ketones (& aldehydes)..alpha cleavage and McLafferty rearrangment 11/6/2009 18

1. Alcohols A. alpha cleavage 3 C 31 1-butanol C 3 C 2 C 2 C 2 MW 74 43 M - 43 M - 31 M+. 11/6/2009 19

ow does the fragmentation occur? Recall that only cations M +. or others are accelerated by the ms source. So each fragment peak must be due to a cation (+). 3 C 31 3 C 43 This is a homolysis that forms a neutral propyl radical fragment (it is lost), and a protonated formaldehyde. 3 C 3 C 43 This is a heterolysis that forms a neutral hydroxymethyl radical fragment (it is lost), and a propyl carbocation. 11/6/2009 20 31

3 C An alternative, and equivalent, way of looking at alpha cleavage process. This considers the "electron hole" to be in the alpha C-C bond. The fragmentation occurs when that single electron moves to one carbon or the other. 3 C 3 C 3 C 3 C 11/6/2009 21

3 C 3 C The initial alcohol cation-radical 1. Alcohols B. dehydration 3 C 3 C 3 C 56 18 The atom removes a atom from the β-carbon, then splits off as water molecule... 3 C 3 C...leaving behind the dehydrated cation, which can be thought of as an alkene cation-radical. 56 1-butanol C 3 C 2 C 2 C 2 MW 74 M - 18 M+. 11/6/2009 22