Downhill Races Acceleration

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Downhill Races Acceleration You may notice that when things move they rarely move at the same speed all the time. Especially when you drive, you can see right away that your speed is constantly changing. When your speed changes, you are accelerating. You can be either speeding up or slowing down. The type of acceleration we deal with, especially in introductory physics, is uniform acceleration. Which means that it is accelerating at a constant rate. We know from earlier work that acceleration due to gravity is a uniform or constant rate of acceleration at 9.8 m/s 2, or 32 ft/s 2. However, if something is rolling down a ramp, it is still pulled by gravity, but at a portion of it, or not the full strength. The force that is acting on an object is equal to it s mass times the amount of acceleration acting on it at any given time. Now the thing to be careful of when trying to calculate this is that this force that is being used to calculate this is the Net Force. Remember from earlier lessons that Net force is all of the forces being added together (in the same axis). When you add up the Net Force of you standing still, you would take the force of gravity ( 490 N) and the normal force (490 N). Add them together and the Net Force is 0 N. IF a = F/m, then a = 0 N/50 kg, and the acceleration = 0 m/s 2. So remember that F=ma works, but only when the F is actually F NET. 2013 Supercharged Science www.sciencelearningspace.com Page 1 of 9

Acceleration Activity Objective: Measure the acceleration of an object as it rolls down a hill Materials: toy car that can freely roll Long wooden board Tape Stopwatch Partner Textbook or small wooden block Procedure: (this is just like we did in the driveway races lab) 1) Raise the wooden ramp up, but not very tall, about 1 2 inches is fine. 2) Place the toy car at the top of the ramp and make a mark with a piece of tape (it doesn t matter if you place the mark at the front or back of the car, just be consistent. If you place the mark at the back, take the mark at the back at each set time interval) 3) Release the car and start the stopwatch. At the 1 second mark, note the location of the car and place a piece of tape or make a mark somehow. 4) Repeat this for 2 more trials to get a total of 3 trials at 1 second. 5) Continue this for up to time intervals up to 6 seconds Data Time Trial 1 distance Trial 2 distance Trial 3 distance Average 1 2 3 4 5 6 Again, like before, graph the results below with time on the x axis and distance in the y axis 2013 Supercharged Science www.sciencelearningspace.com Page 2 of 9

Like before, graph the results with the distance on the y axis and time on the x axis, but square the time and take half of it. Analysis: 1) You should notice a difference between these graphs and the ones from the driveway races. What is it? (Hint: look to second half of the graph) 2) The first graph doesn t continue to curve, but straightens out. What does this mean about the velocity? 3) The second graph, the slope flattens out completely, what does this mean about the acceleration? 4) If the acceleration is zero, what does that mean about the net force? 2013 Supercharged Science www.sciencelearningspace.com Page 3 of 9

5) What are the forces acting on the toy car as it is going down the ramp? When an object is falling or moving as a result of gravity and reaches a maximum speed this is known as its terminal velocity. It is when the frictional forces are equal to the forces causing it to move. Remembering the work we did with net force earlier, we know that it has a net force of zero, and it is no longer accelerating. Because it is not accelerating, it maintains a constant velocity, and in this case it is it s terminal velocity. 6) Name 3 other examples of an object that has reached a terminal velocity. 2013 Supercharged Science www.sciencelearningspace.com Page 4 of 9

Acceleration Problems First find the net force, then solve the F net =ma equation. All problems involve the same sketch and forces labeled F 1 and F 2. Remember the sign of the force depends on the direction of the force!!! F 1 F 2 Example: The object has a mass of 10 kg. F 1 = 20 N and F 2 = 10 N. What is the acceleration? 1. F 1 =27.4 N F 2 = 11.2 N m = 9.5 kg Find a 2. F 1 = 16.1 N F 2 = 21.7 N m = 5 kg Find a 2013 Supercharged Science www.sciencelearningspace.com Page 5 of 9

3. F 1 = 20 N a = 3 m/s 2 m = 1 kg Find F 2 4. F 1 = 32 N F 2 = 12 N a = 5 m/s 2 Find m 5. m = 3.2 kg F 2 = 4 N a = 1.7 m/s 2 Find F 1 2013 Supercharged Science www.sciencelearningspace.com Page 6 of 9

Solutions to Problems: Analysis: 1) You should notice a difference between these graphs and the ones from the driveway races. What is it? (Hint: look to second half of the graph) The graph stopped curving 2) The first graph doesn t continue to curve, but straightens out. What does this mean about the velocity? It was a constant velocity after about 3 seconds 3) The second graph, the slope flattens out completely, what does this mean about the acceleration? The acceleration stopped 4) If the acceleration is zero, what does that mean about the net force? The net force must be zero 5) What are the forces acting on the toy car as it is going down the ramp? Gravity and friction 6) Name 3 other examples of an object that has reached a terminal velocity. Skydiver, racecar driver, bullet fired from a gun 2013 Supercharged Science www.sciencelearningspace.com Page 7 of 9

First find the net force, then solve the F net =ma equation. All problems involve the same sketch and forces labeled F 1 and F 2. Remember the sign of the force depends on the direction of the force!!! F 1 F 2 1. F 1 =27.4 N F 2 = 11.2 N m = 9.5 kg Find a 1.7 m/s 2 2. F 1 = 16.1 N F 2 = 21.7 N m = 5 kg Find a 1.12 m/s 2 3. F 1 = 20 N a = 3 m/s 2 m = 1 kg Find F 2 23 N 2013 Supercharged Science www.sciencelearningspace.com Page 8 of 9

4. F 1 = 32 N F 2 = 12 N a = 5 m/s 2 Find m 4 kg 5. m = 3.2 kg F 2 = 4 N a = 1.7 m/s 2 Find F 1 9.44 N 2013 Supercharged Science www.sciencelearningspace.com Page 9 of 9