EE 355 / GP 265 Homework 5 Solutions

Similar documents
EE 355 / GP 265 Homework 3 Solutions Winter


3-Dimension Deformation Mapping from InSAR & Multiaperture. Hyung-Sup Jung The Univ. of Seoul, Korea Zhong Lu U.S. Geological Survey, U.S.A.

We know that f(x, y) and F (u, v) form a Fourier Transform pair, i.e. f(ax, by)e j2π(ux+vy) dx dy. x x. a 0 J = y y. = 0 b

Notes perso. - cb1 1. Version 3 - November u(t)e i2πft dt u(t) =

The Radar Ambiguity. function Introduction. Chapter 4

Analysis of Doppler signals from nadir altimeters over ocean. F. Boy (CNES)

Homework 5 Solutions

Fast Fourier Transform Discrete-time windowing Discrete Fourier Transform Relationship to DTFT Relationship to DTFS Zero padding

A NEW IMAGING ALGORITHM FOR GEOSYNCHRON- OUS SAR BASED ON THE FIFTH-ORDER DOPPLER PARAMETERS

Fast Fourier Transform Discrete-time windowing Discrete Fourier Transform Relationship to DTFT Relationship to DTFS Zero padding

IMPROVED MOTION COMPENSATION FOR WIDE- BEAM WIDE-SWATH AIRBORNE SAR

Homework 5 Solutions

CHAPTER 7. The Discrete Fourier Transform 436

Homework 6 Solutions

TIME-FREQUENCY ANALYSIS: TUTORIAL. Werner Kozek & Götz Pfander

Homework 1 Solutions

Mandatory Assignment 2013 INF-GEO4310

Estimation of the Cosmic Microwave Background Radiation

NAS Report MTI FROM SAR. Prof. Chris Oliver, CBE NASoftware Ltd. 19th January 2007

Airborne Holographic SAR Tomography at L- and P-band

Lecture 23. Lidar Error and Sensitivity Analysis (2)

The Geometry of Spaceborne Synthetic Aperture Radar

Nonparametric Rotational Motion Compensation Technique for High-Resolution ISAR Imaging via Golden Section Search

Lecture 15: Doppler Dilemma, Range and Velocity Folding, and Interpreting Doppler velocity patterns

Tu: 9/3/13 Math 471, Fall 2013, Section 001 Lecture 1

Lecture 13: Pole/Zero Diagrams and All Pass Systems

A Lecture on Selective RF-pulses in MRI

Solutions. Chapter 5. Problem 5.1. Solution. Consider the driven, two-well Duffing s oscillator. which can be written in state variable form as

Problem Set 9 Solutions

Let us consider a typical Michelson interferometer, where a broadband source is used for illumination (Fig. 1a).

MAE 143B - Homework 7

Massachusetts Institute of Technology Department of Electrical Engineering and Computer Science Electric Machines

Orbit and Transmit Characteristics of the CloudSat Cloud Profiling Radar (CPR) JPL Document No. D-29695

Sentinel-1 Mission Overview

Mobile Radio Communications

Distributed Real-Time Control Systems

MATLAB/SIMULINK Programs for Flutter

Math 56 Homework 5 Michael Downs

A SuperDARN Tutorial. Kile Baker

Assignment 4 Solutions Continuous-Time Fourier Transform

LAB 1: MATLAB - Introduction to Programming. Objective:

2.13 Linearization and Differentials

J. McNames Portland State University ECE 223 DT Fourier Series Ver

Master s Thesis Defense. Illumination Optimized Transmit Signals for Space-Time Multi-Aperture Radar. Committee

Research Article Study on Zero-Doppler Centroid Control for GEO SAR Ground Observation

A REFINED TWO-DIMENSIONAL NONLINEAR CHIRP SCALING ALGORITHM FOR GEOSYNCHRONOUS EARTH ORBIT SAR

J.-M Friedt. FEMTO-ST/time & frequency department. slides and references at jmfriedt.free.fr.

EECS 556, 2002 Exam #1 1. Solutions to Take-Home Exam #1

A Radar Eye on the Moon: Potentials and Limitations for Earth Imaging

High resolution spaceborne SAR focusing by SVD-STOLT

THE COMPARISON OF DIFFERENT METHODS OF CHRIP SIGNAL PROCESSING AND PRESENTATION OF A NEW METHOD FOR PROCESSING IT

BNG/ECE 487 FINAL (W16)

1. Solve each linear system using Gaussian elimination or Gauss-Jordan reduction. The augmented matrix of this linear system is

NAIC NAIC PLANETARY RADAR ASTRONOMY STUDYING SOLAR SYSTEM BODIES WITH RADAR DON CAMPBELL

Progress In Electromagnetics Research M, Vol. 21, 33 45, 2011

Temporal &Spatial Dependency of the MOS RMF

ECE 6390 Homework 2: Look Angles

Rotation. I. Kinematics - Angular analogs

MA 137 Calculus 1 with Life Science Applications The Chain Rule and Higher Derivatives (Section 4.4)

Sentinel-1A SAR Interferometry Verification

PASSIVE MICROWAVE IMAGING. Dr. A. Bhattacharya

E&CE 358, Winter 2016: Solution #2. Prof. X. Shen

Calibration Activities the MOS perspective

Bayesian Analysis - A First Example

A Low-Power Radar Imaging System

Densità spettrale di clutter

ENSC327 Communications Systems 2: Fourier Representations. Jie Liang School of Engineering Science Simon Fraser University

MAT 275 Laboratory 4 MATLAB solvers for First-Order IVP

Laboratory III: Operational Amplifiers

FREQUENCY-DOMAIN RECONSTRUCTION OF THE POINT-SPREAD FUNCTION FOR MOVING SOURCES

Seismic Wave Propagation: HW2 Due 13/5

Diffuser plate spectral structures and their influence on GOME slant columns

Advanced Laser Technologies Homework #2

An Error Analysis of Elliptical Orbit Transfer Between Two Coplanar Circular Orbits

EE368B Image and Video Compression

EE4512 Analog and Digital Communications Chapter 4. Chapter 4 Receiver Design

Homework 5 Solutions. Problem 1

MAE143A Signals & Systems - Homework 5, Winter 2013 due by the end of class Tuesday February 12, 2013.

The Doppler effect for SAR 1

Microelectronic Circuit Design 4th Edition Errata - Updated 4/4/14

Considerations on radar localization in multi-target environments

Evaluation of a new autofocus algorithm within the framework of Fast Factorized Back-Projection

chap5_fourier_series_lr_circuit.doc 1/18 Consider the rectangular pulse train of example 3.2 of the text as the input to the series LR circuit.

ERS-ENVISAT Cross-interferometry for Coastal DEM Construction

Principles of Communications

STAT2201 Assignment 3 Semester 1, 2017 Due 13/4/2017

Solutions - Homework #2

TIME-FREQUENCY ANALYSIS EE3528 REPORT. N.Krishnamurthy. Department of ECE University of Pittsburgh Pittsburgh, PA 15261

Math Theory of Number Homework 1

ECE 501b Homework #6 Due: 11/26

Lecture 14 Dispersion engineering part 1 - Introduction. EECS Winter 2006 Nanophotonics and Nano-scale Fabrication P.C.Ku

Introduction to Signal Analysis Parts I and II

Homework Set #7 - Solutions

High Precision Spin Manipulation at COSY

Optics for Engineers Chapter 11

u(t)u (t + τ) exp(j2πνt)dt 3.1 MAIN PROPERTIES OF THE AMBIGUITY FUNCTION

SWITCHED CAPACITOR AMPLIFIERS

3 Chemical exchange and the McConnell Equations

Supporting Materials

Transcription:

EE / GP Homework Solutions February,. Autofocus: subaperture shift algorithm Compress the signal (with chirp slope s = Hz/s) by correlating it with the reference chirp (with different chirp slope s ) twice: once with the first subaperture of the reference chirp, consisting of positive frequencies (half its bandwidth), and another time with the second subaperture of the reference chirp, which consists of negative frequencies (the other half of its bandwidth). The compressed signals from both subapertures will be slightly offset from each other (see figures), so cross-correlate them to compute the pixel offset p (see second column in table). Convert to time shift t by dividing by the sample rate f s (see third column in table): t = p f s () Then compute the chirp slope correction s (see fourth column in table). This should match the expected slope correction s exp = s s we get from subtraction, since we know the true chirp slope s. s = s t BW = s t = s t () sτ τ s (Hz/s) (a) pixel offset t (s) (b) s (Hz/s).......9..

% EE HW Problem close all; clear; set(, defaultaxesfontsize, ); %%%%%%%%%%%%%%%%%%%%%%%%% Problem %%%%%%%%%%%%%%%%%%%%%%% % pb: autofocus using sub-aperture shift algorithm clear;clc;close all; %% signal chirp s_sig=e; tau=e-; fs=e; Nmin=round(fs*tau); N=^ceil(log(Nmin)/log()); signal=makechirp(s_sig,tau,fs,,,n); spect_sig=fft(signal); %% ref chirp s=e;

s=.e; s=.e; s=.9e; sr=[s,s,s,s]; % reference chirp slopes for k=:numel(sr) sp=sr(k); bw=tau*sp; fullrefchirp=makechirp(sp,tau,fs,,,n); subchirp=makechirp(sp,tau/,fs,-bw/,,n); subchirp=makechirp(sp,tau/,fs,bw/,round(tau/*fs+),n); spect_ref=fft(subchirp); spect_ref=fft(subchirp); compsig=ifft(spect_sig.*conj(spect_ref)); compsig=ifft(spect_sig.*conj(spect_ref)); t=/fs*(-n/:n/-); t=e*t; % figure: Compressed looks, showing their misregistration figure() subplot(,,k) plot(t,fftshift(abs(ifft(spect_sig.*conj(spect_sig)))), linewidth,) hold on plot(t,fftshift(abs(compsig)), linewidth,) hold on plot(t,fftshift(abs(compsig)), linewidth,) hold off xlabel( t,us ) ylabel( amplitude ) xlim([-tau/,tau/]*e) leg( full aperture, sub-negative freq, sub-positive freq ) % saveas(gcf, pb.png, png ) % find the offset delta_t by correlating the two sub-aperture images shift=fftshift(ifft(fft(abs(compsig)).*conj(fft(abs(compsig))))); [maxnum,index]=max(abs(shift)); delta_t(k)=(index-n/-)/fs; delta_s(k)=*delta_t(k)*sp^/bw/e; pixeloffset(k)=(index-n/-); function chirp = makechirp(s,tau,fs,fc,start,n) %s : slope %tau : pulse length %fs : sample rate %fc : center frequency %start: starting location of chirp

%n : number of samples dt=/fs; % sampling time interval npts=floor(tau/dt); % number of points of the chirp signal t=(-npts/:npts/-)*dt; phase=pi*s*t.^+*pi*fc*t; chirp=zeros(n,); chirp(start:start+npts-)=exp(i*phase); return. Range migration with simulated data: cut and paste raw data lines bins.9........ We observe migration in the magnitude of the raw data from simlband.dat: a slant of about - pixels. The signal boundaries are not present within a single bin. (a) Range migration is still evident in the compressed data (left), especially when we zoom in on bins - (right). The signal does not stay in the same bin, but instead curves as the position changes.

compressed data compressed data, zoom lines lines bins bins (b) After transforming the compressed data in the direction (left), we still see migration between the two tail s of the spectra (about - pixels), especially when we zoom in on bins - (right). Notice that f DC is around prf/ (part c), which explains why the s of the spectra come together around - Hz. Also, the frequency can have an ambiguity of n*prf, so we only plot the axis label as [-prf/ prf/]. Azimuth-transformed image Azimuth-transformed image, zoom - - frequency in (Hz) - frequency in (Hz) - bins bins (c) After computing the average Doppler spectrum over all valid bins, we find that it peaks at a frequency of f DC, =.9 Hz, which we estimate as the Doppler centroid. Other possible values of f DC are possible because of ambiguity from sampling the Doppler spectrum. I can also have f DC = f DC, + n P RF, where n is an integer. Letting n =,,,,, I get these possible values of f DC, respectively: -9. Hz, -. Hz,.9 Hz,.9 Hz,.9 Hz.

Average spectrum Average spectrum magnitude (db) - - - frequency (Hz) (d) We use the same focused SAR processing algorithm from Homework, compressing the data in both the and directions, trying all possible f DC values from problem c. We process only patch (with samples). We plot images that are zoomed in both and, to examine the impulse response more closely. The impulse responses for f DC = -. Hz and.9 Hz look the sharpest in both and, but there is still some blurring over a few pixels in both directions. The other f DC values are not at the correct ambiguity because the impulse response is too smeared out in the direction, and we can see some migration. Focused image, f dc = -9.9 Hz Focused image, f dc = -.9 Hz Focused image, f dc =.9 Hz Focused image, f dc =.9 Hz Focused image, f dc =.9 Hz

(e) Range migration with the cut and paste algorithm improved the resolution of the impulse response. It was not very obvious with the original processing results, but the images after migration clearly show that the absolute (unwrapped) Doppler centroid is at f DC = -. Hz (when n = ), where the image is sharpest, and sharper than all images from problem d. Note that the migration process increased the sensitivity to the Doppler centroid ambiguity. Range migration, image, f dc = -9.9 Hz Range migration, image, f dc = -.9 Hz Range migration, image, f dc =.9 Hz Range migration, image, f dc =.9 Hz Range migration, image, f dc =.9 Hz % EE HW Problem close all; clear; set(, defaultaxesfontsize, ); %%%%%%%%%%%%%%%%%%%%%%%%% Problem %%%%%%%%%%%%%%%%%%%%%%% % Read in data nr = ; naz = ; fid=fopen( simlband.dat ); dat = fread(fid, [nr* naz], float, l ); fclose(fid); signal = dat(::,:) + i*dat(::,:);

% Plot raw data imagesc(abs(signal). ); title( raw data ); colormap gray; colorbar; ylabel( lines ); xlabel( bins ); % Part a): Range compression s = e; tau = e-; fs = e; r=makechirp(s,tau,fs,,,nr); R=fft(r); S=fft(signal); Sc=zeros(size(S)); for jj=:naz Sc(:,jj)=S(:,jj).*conj(R. ); rcomp=ifft(sc); nvalid = nr - fs*tau; % valid bins rcomp=rcomp(:nvalid,:). ; imagesc(abs(rcomp)); title( compressed data ); ylabel( lines ); xlabel( bins ); colormap gray; colorbar; imagesc(abs(rcomp)); title( compressed data, zoom ); ylabel( lines ); xlabel( bins ); xlim([ ]); colormap gray; colorbar; % Part b): Transform in Rcomp=fft(rcomp); prf = ; fq=linspace(-prf/,prf/,naz); imagesc(:nvalid, fq, fftshift(abs(rcomp),)); ylabel( frequency in (Hz) ); xlabel( bins ); title( Azimuth-transformed image ) colormap gray; colorbar;

imagesc(:nvalid, fq, fftshift(abs(rcomp),)); ylabel( frequency in (Hz) ); xlabel( bins ); xlim([ ]); title( Azimuth-transformed image, zoom ) colormap gray; colorbar; % Part c): Estimate Doppler centroid with average spectrum Saz=zeros(naz,); for jj=:nvalid Saz=Saz+abs(Rcomp(:,jj)); Saz=Saz/nvalid; ind_max = find(fftshift(saz) == max(fftshift(saz))); fdc_est = fq(ind_max); plot(fq,*log(fftshift(saz)), linewidth,); xlabel( frequency (Hz) ); ylabel( Average spectrum magnitude (db) ); title( Average spectrum ); % Part d): Process image with original (non-migrating) focused SAR lambda=.; r=; % to first bin v=; l=; c =.999e; % speed of light (m/s) dr = c/(*fs); % slant bin spacing (m) nn = [- - ]; % Doppler centroid ambiguity: integer fdc_arr = fdc_est + prf*nn; % Possible Doppler centroid frequencies (Hz) for k=:numel(nn) fdc = fdc_arr(k); % get Doppler centroid rmax = r+(nvalid-)*dr; % to last bin rdcmax = sqrt(rmax^+(fdc*rmax*lambda/(*v))^); % max at antenna boresight (m) tazmax =.*rdcmax*lambda/(l*v); % maximum illumination time (s) validperpatch=floor(naz-tazmax*prf); % number of valid samples per patch % Apply compression for this fdc ( patch, bins) s_focus=zeros(naz,nvalid); for bin=:nvalid =r+(bin-)*dr; rdc=sqrt(^+(fdc**lambda/(*v))^); frate=-*v^/(rdc*lambda); taz=.*rdc*lambda/(v*l); ref=makechirp(frate,taz,prf,fdc,,naz); Ref=fft(ref); 9

s_focus(:,bin)=ifft(rcomp(:,bin).*conj(ref. )); % Plot focused SAR image for this fdc imagesc(abs(s_focus)); colorbar; caxis([ e]); colormap( jet ); xlim([ ]); ylim([ ]); xlabel( ); ylabel( ); title([ Focused image, f_{dc} =, numstr(fdc), Hz ]); % Part e): Range migration with cut-and-paste % Rcomp is -compressed, -transformed data Rcomp=zeros(size(Rcomp)); % Allocate array for -migrated data df = prf/naz; for k=:numel(nn) fdc = fdc_arr(k); % get Doppler centroid fmin = nn(k)*prf; % minimum frequency % Apply migration with cut-and-paste for bin=:nvalid for jj=:naz freq=fmin+(jj-)*df; dist_offset = (freq^-fdc^)*(r/)*(lambda/v)^; % offset distance (m) rshift=floor(dist_offset/dr); % number of offset bins if((bin+rshift <= nvalid) && (bin+rshift > )) % array bounds check Rcomp(jj,bin)=Rcomp(jj,bin+rshift); % Apply compression for this fdc ( patch, bins) s_rm_focus=zeros(naz,nvalid); for bin=:nvalid =r+(bin-)*dr; rdc=sqrt(^+(fdc**lambda/(*v))^); frate=-*v^/(rdc*lambda); taz=.*rdc*lambda/(v*l); ref=makechirp(frate,taz,prf,fdc,,naz); Ref=fft(ref); s_rm_focus(:,bin)=ifft(rcomp(:,bin).*conj(ref. )); % Plot focused, migrated SAR image for this fdc imagesc(abs(s_rm_focus)); colorbar; caxis([ e]); colormap( jet ); xlim([ ]); ylim([ ]); xlabel( ); ylabel( ); title([ Range migration, image, f_{dc} =, numstr(fdc), Hz ]);

. We can consider the radar geometry as two concentric spheres; the outer sphere is the orbital sphere of the satellite, the inner sphere is the Earth. Point A is the point of closest approach of the satellite to point C, and point B is some later position of the satellite. We want to find the r from B to C. We derived the effective velocity for the point P (directly under the satellite) in Handout. The relative height history z(t) between the point P and the satellite can be written as (from Handout ): v t z(t) = z () (z + R e ) From geometry, the height difference between point P (directly under the satellite) and point C (not directly under the satellite) is: cos β = R e z R e z = R e R e cos β () Now write the expression for as a function of time, r (t), but replace z(t) with z(t)+ z: r (t) = v t + y + (z(t) + z) r (t) = v t + y + (z(t)) + z(t) z + ( z) () Plug in Eq. into Eq.. Here we neglect the higher order v t term: ( r (t) = v t + y + z v t ) ( + z (z + R e ) r (t) = v t + y + z z v t z + R e + ( z v t ) z + ( z) (z + R e ) ) () z + ( z) v t (z + R e )

Gather all terms in Eq. with v t, and call everything else constant (not changing with time): r (t) = y + z + z z + ( z) + v t z v t ( z + R e v t (z + R e ) r (t) = const + v t [ z z + R e ) z z ] () z + R e The effective velocity v eff is the term in Eq. in brackets, times v, so simplify: v eff = v [ z z + R e v eff = v [ z + R e z + R e z z + R e z z + R e z ] z + R e [ ] veff = Re z v z + R e Plug in Eq. into Eq., and take the square root: [ ] veff = Re (R e R e cos β) v z + R e [ ] veff = Re cos β v z + R e Re cos β v eff = v z + R e ] () (9)