Chapter 5 Logarithmic, Exponential, and Other Transcendental Functions

Similar documents
L Hôpital s Rule was discovered by Bernoulli but written for the first time in a text by L Hôpital.

Differential and Integral Calculus

Trigonometric substitutions (8.3).

90 Chapter 5 Logarithmic, Exponential, and Other Transcendental Functions. Name Class. (a) (b) ln x (c) (a) (b) (c) 1 x. y e (a) 0 (b) y.

TOTAL NAME DATE PERIOD AP CALCULUS AB UNIT 4 ADVANCED DIFFERENTIATION TECHNIQUES DATE TOPIC ASSIGNMENT /6 10/8 10/9 10/10 X X X X 10/11 10/12

ENGI 3425 Review of Calculus Page then

Chapter 3 Differentiation Rules (continued)

Chapter 2 Derivatives

THEOREM: THE CONSTANT RULE

Test one Review Cal 2

cosh x sinh x So writing t = tan(x/2) we have 6.4 Integration using tan(x/2) = 2 2t 1 + t 2 cos x = 1 t2 We will revisit the double angle identities:

Math 180 Prof. Beydler Homework for Packet #5 Page 1 of 11

Lecture 3. Lecturer: Prof. Sergei Fedotov Calculus and Vectors. Exponential and logarithmic functions

ARAB ACADEMY FOR SCIENCE TECHNOLOGY AND MARITIME TRANSPORT

cosh x sinh x So writing t = tan(x/2) we have 6.4 Integration using tan(x/2) 2t 1 + t 2 cos x = 1 t2 sin x =

Some functions and their derivatives

Hyperbolic Functions. Notice: this material must not be used as a substitute for attending. the lectures

Math 1A Midterm 2 Fall 2015 Riverside City College (Use this as a Review)

( ) = 1 t + t. ( ) = 1 cos x + x ( sin x). Evaluate y. MTH 111 Test 1 Spring Name Calculus I

6.2. The Hyperbolic Functions. Introduction. Prerequisites. Learning Outcomes

Hyperbolic Functions

B 2k. E 2k x 2k-p : collateral. 2k ( 2k-n -1)!

Inverse Relations. 5 are inverses because their input and output are switched. For instance: f x x. x 5. f 4

JUST THE MATHS UNIT NUMBER DIFFERENTIATION 4 (Products and quotients) & (Logarithmic differentiation) A.J.Hobson

Hyperbolics. Scott Morgan. Further Mathematics Support Programme - WJEC A-Level Further Mathematics 31st March scott3142.

Monday, 6 th October 2008

MTH 133 Solutions to Exam 1 October 10, Without fully opening the exam, check that you have pages 1 through 11.

Inverse Trig Functions

NOTES ON INVERSE TRIGONOMETRIC FUNCTIONS

Practice Questions From Calculus II. 0. State the following calculus rules (these are many of the key rules from Test 1 topics).

CALCULUS: Graphical,Numerical,Algebraic by Finney,Demana,Watts and Kennedy Chapter 3: Derivatives 3.3: Derivative of a function pg.

Hyperbolic functions

Lecture Notes for Math 1000

WORKBOOK. MATH 32. CALCULUS AND ANALYTIC GEOMETRY II.

Math Test #2 Info and Review Exercises

CHAPTER 1: FURTHER TRANSCENDENTAL FUNCTIONS

Revision Checklist. Unit FP3: Further Pure Mathematics 3. Assessment information

Throughout this module we use x to denote the positive square root of x; for example, 4 = 2.

MTH 133 Exam 1 February 21, Without fully opening the exam, check that you have pages 1 through 11.

Further Pure Mathematics 3 GCE Further Mathematics GCE Pure Mathematics and Further Mathematics (Additional) A2 optional unit

FUNCTIONS OF ONE VARIABLE FUNCTION DEFINITIONS

Practice Differentiation Math 120 Calculus I Fall 2015

MA 242 Review Exponential and Log Functions Notes for today s class can be found at

10.7. DIFFERENTIATION 7 (Inverse hyperbolic functions) A.J.Hobson

MTH 133 Solutions to Exam 1 October 11, Without fully opening the exam, check that you have pages 1 through 11.

SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question. and θ is in quadrant IV. 1)

2 Recollection of elementary functions. II

MATH 120 Theorem List

Chapter 3 Elementary Functions

Section The Chain Rule and Implicit Differentiation with Application on Derivative of Logarithm Functions

Derivatives and Its Application

FUNCTIONS AND MODELS

Additional Exercises for Chapter 10

Math F15 Rahman

2.1 Limits, Rates of Change and Slopes of Tangent Lines

UNIT NUMBER DIFFERENTIATION 7 (Inverse hyperbolic functions) A.J.Hobson

7.1. Calculus of inverse functions. Text Section 7.1 Exercise:

MTH 133 Solutions to Exam 1 February 21, Without fully opening the exam, check that you have pages 1 through 11.

2. Determine the domain of the function. Verify your result with a graph. f(x) = 25 x 2

Calculus: Early Transcendental Functions Lecture Notes for Calculus 101. Feras Awad Mahmoud

CHAPTER 1. DIFFERENTIATION 18. As x 1, f(x). At last! We are now in a position to sketch the curve; see Figure 1.4.

Find: sinθ. Name: Date:

UNIVERSITI TEKNOLOGI MALAYSIA FACULTY OF SCIENCE... FINAL EXAMINATION SEMESTER I SESSION 2015/2016 COURSE NAME : ENGINEERING MATHEMATICS I

6.7 Hyperbolic Functions

Inverse Trigonometric Functions. September 5, 2018

CHAPTER 3 DERIVATIVES (continued)

Trigonometric Identities Exam Questions

Outline. MS121: IT Mathematics. Differentiation Rules for Differentiation: Part 1. Outline. Dublin City University 4 The Quotient Rule

Math 115 (W1) Solutions to Assignment #4

Ch 5 and 6 Exam Review

CALCULUS II MATH Dr. Hyunju Ban

7.3 Hyperbolic Functions Hyperbolic functions are similar to trigonometric functions, and have the following

SET 1. (1) Solve for x: (a) e 2x = 5 3x

MTH 133 PRACTICE Exam 1 October 10th, Without fully opening the exam, check that you have pages 1 through 11.

7.3 Inverse Trigonometric Functions

Today: 5.6 Hyperbolic functions

Inverse Trig Functions

Implicit Differentiation and Inverse Trigonometric Functions

Chapter 5 Notes. 5.1 Using Fundamental Identities

CHAPTER 5 Logarithmic, Exponential, and Other Transcendental Functions

Differentiation ( , 9.5)

Announcements. Topics: Homework: - sections 4.5 and * Read these sections and study solved examples in your textbook!

THE INVERSE TRIGONOMETRIC FUNCTIONS

7. Differentiation of Trigonometric Function

Differentiability, Computing Derivatives, Trig Review. Goals:

CHAPTER 5 Logarithmic, Exponential, and Other Transcendental Functions

Derivatives of Inverse Functions

Strauss PDEs 2e: Section Exercise 6 Page 1 of 5

Transcendental Functions

m(x) = f(x) + g(x) m (x) = f (x) + g (x) (The Sum Rule) n(x) = f(x) g(x) n (x) = f (x) g (x) (The Difference Rule)

Hyperbolic Functions: Exercises - Sol'ns (9 pages; 13/5/17)

Unit #17: Spring Trig Unit. A. First Quadrant Notice how the x-values decrease by while the y-values increase by that same amount.

Lecture 14 September 26, Today. WH 3 now posted Due Tues. Oct. 2, 2018 Quiz 4 tomorrow. Differentiation summary Related rates

Chapter 2. Exponential and Log functions. Contents

(a) 82 (b) 164 (c) 81 (d) 162 (e) 624 (f) 625 None of these. (c) 12 (d) 15 (e)

Lecture 5: Inverse Trigonometric Functions

MAT137 Calculus! Lecture 17

5.2 Proving Trigonometric Identities

FINAL - PART 1 MATH 150 SPRING 2017 KUNIYUKI PART 1: 135 POINTS, PART 2: 115 POINTS, TOTAL: 250 POINTS No notes, books, or calculators allowed.

Transcription:

Chapter 5 Logarithmic, Exponential, an Other Transcenental Functions 5.1 The Natural Logarithmic Function: Differentiation 5.2 The Natural Logarithmic Function: Integration 5.3 Inverse Functions 5.4 Exponential Functions: Differentiation an Integration 5.5 Bases Other than e an Applications 5.6 Ineterminate Forms an L Hopital s Rule 5.7 Inverse Trigonometric Functions: Differentiation 5.8 Inverse Trigonometric Functions: Integration 5.9 Hyperbolic Functions

5.7. Inverse Trigonometric Functions: Differentiation Definitions of Inverse Trigonometric Functions Review Function Domain Range y = arcsin x = sin 1 x iff sin y = x 1 x 1 π 2 y π 2 y = arccos x = cos 1 x iff cos y = x 1 x 1 0 y π y = arctan x = tan 1 x iff tan y = x < x < π 2 < y < π 2 y = arccot x = cot 1 x iff cot y = x < x < 0 < y < π y = arcsec x = sec 1 x iff sec y = x x 1 0 y π, y π 2 y = arccsc x = csc 1 x iff csc y = x x 1 π 2 y π 2, y 0

5.7. Inverse Trigonometric Functions: Differentiation Example 1. Evaluate each value. (a) arcsin 1 2 (b) arccos 0 (c) arctan 3 () arcsin(0.3) Example 2. Solve the equation. arctan(2x 3) = π 4 Example 3. (a) Given y = arcsin x, where 0 < y < π/2, fin cos y. (b) Given y = arcsec( 5/2), fin tan y.

5.7. Inverse Trigonometric Functions: Differentiation Theorem 5.18 Derivatives of Inverse Trigonometric Functions. Let u be a ifferentiable function of x. x arcsin u = u 1 u 2 x arctan u = u x 1 + u 2 x x arcsec u = u u u 2 1 arccos u = u arccot u = u 1 u 2 1 + u 2 x arccsc u = u u u 2 1

5.7. Inverse Trigonometric Functions: Differentiation Example 4. Fin each erivative (a) [arcsin 2x (b) arctan(3x) (c) arcsin x () x x x x arcsec(e2x ) Example 5. Differentiate the following function an simplify the answer. y = arcsin x + x 1 x 2 Example 6. Analyze the graph of the function. y = arctan x 2.

5.8. Inverse Trigonometric Functions: Integration Theorem 5.18 Let u be a ifferentiable function of x. x arcsin u = u 1 u 2 arctan u = u x 1 + u 2 x arcsec u = u u u 2 1 Theorem 5.19 Let u be a ifferentiable function of x, an let a > 0. 1 a 2 u 2 u = arcsin u a + C 1 a 2 + u 2 u = 1 a arctan u a + C u 2 1 u 2 a 2 u = 1 a arcsec u a + C

5.8. Inverse Trigonometric Functions: Integration Example 1. Integrate each inefinite integral. 1 a 4 x x b 1 2 2 + 9x 2 x c 1 x 4x 2 9 x

5.8. Inverse Trigonometric Functions: Integration Example 2. Fin 1 e 2x 1 x.

5.8. Inverse Trigonometric Functions: Integration Example 3. Fin x + 2 4 x 2 x.

5.8. Inverse Trigonometric Functions: Integration Example 4. Fin 1 x 2 4x + 7 x.

5.8. Inverse Trigonometric Functions: Integration Example 5. Fin 1 3x x x. 2 Then fin the area of the region boune by the graph of 1 f x = 3x x 2 The x-axis, an the lines x = 3 2 an x = 9 4.

Definitions of the Hyperbolic Functions sinh x = ex e x csch x = 1 2 sinh x, x 0 cosh x = ex + e x sech x = 1 2 cosh x sinh x tanh x = coth x = 1 cosh x tanh x, x 0 Remark. The notation sinh x is rea as the hyperbolic sine of x, cosh x as the hyperbolic cosine of x, an so on.

Note that Hyperbolic functions are not perioic

Hyperbolic Ientities cosh 2 x sinh 2 x = 1 tanh 2 x + sech 2 x = 1 cosh 2 x csch 2 x = 1 sinh 2 1 + cosh 2x x = 2 sinh 2x = 2 sinh x cosh x sinh(x + y) = sinh x cosh y + cosh x sinh y sinh(x y) = sinh x cosh y cosh x sinh y cosh(x + y) = cosh x cosh y + sinh x sinh y cosh(x y) = cosh x cosh y sinh x sinh y cosh 2 1 + cosh 2x x = 2 cosh 2x = cosh 2 x + sinh 2 x

Theorem 5.20 Differentiation an Integration of Hyperbolic Functions Let u be a ifferentiable function of x.. sinh u = cosh u u x cosh u = sinh u u x x tanh u = sech2 u u x coth u = csch2 u u sech u = sech u tanh u u x csch u = csch u coth u u x cosh u u = sinh u + C sinh u u = cosh u + C sech 2 u u = tanh u + C csch 2 u u = coth u + C sech u tanh u u = sech u + C csch u coth u u = csch u + C

Example 1. Fin a x sinh x2 3 b c x x ln cosh x x sinh x cosh x [ x 1 cosh x sinh x] x

Example 2. Fin the relative extrema of f x = x 1 cosh x sinh x. Sketch the graph as well.

Example 3. Power cables are suspene between two towers, forming the catenary shown in the Figure. The equation for this catenary is f x = a cosh x a. The istance between the two towers is 2b. Fin the slope of the catenary at the point where the cable meets the right-han tower. y b b b x

Example 4. Fin cosh 2x sinh 2 2x x.

Inverse Hyperbolic Functions Note that four (sinh x, tanh x, csch x, coth x) of the six hyperbolic functions are one-to-one, but cosh x an sech x are not one-to-one. By restricting the omain we can make cosh x an sech x one-to-one.

Theorem 5.21 Inverse Hyperbolic Functions Inverse Function Domain sinh 1 x = ln(x + x 2 + 1) (, ) cosh 1 x = ln(x + x 2 1) [1, ) tanh 1 x = 1 2 coth 1 x = 1 2 1 + x ln 1 x x + 1 ln x 1 sech 1 x = ln 1 + 1 x2 x ( 1,1), 1 (1, ) (0, 1] csch 1 x = ln 1 x + 1 + x2 x, 0 (0, )

Theorem 5.22 Differentiation an Integration Involving Inverse Hyperbolic Functions Let u be a ifferentiable function of x. x sinh 1 u = u 2 + 1 x cosh 1 u = u 2 1 x tanh 1 u = u 1 u 2 x cosh 1 u = u 1 u 2 x sech 1 x = u u u 1 u 2 x csch 1 x = u 1 + u 2 1 u 2 ± a u = ln u + 2 u2 ± a 2 + C 1 a 2 u 2 u = 1 a + u ln 2a a u + C u 1 u a 2 ± u u = 1 2 a ln a + a2 ± u2 + C u u

Example 6. Fin x sinh 1 2x x [tanh 1 x 3 ].

Example 7. Fin 1 x 4 9x x 1 2 5 4x 2 x