_".. psat. Alternatively, Eq. (10.5) may be solved for Xi, in which case summing over all species yields: P=----- (10.

Similar documents
The two major assumptions required to reduce VLE calculations to Raoult's law are:

VaporILiquid Equilibrium: Introduction

CH2351 Chemical Engineering Thermodynamics II Unit I, II Phase Equilibria. Dr. M. Subramanian

Vapor-liquid Separation Process MULTICOMPONENT DISTILLATION

Phase Separation Degree of Freedom Analysis. Binary Vapor-Liquid Systems. Azeotropic Systems. - Gibbs phase rule F C P 2 -General analysis

Ph.D. Qualifying Examination In Thermodynamics

All rights reserved. Armando B. Corripio, PhD, PE Flash Distillation Flash Drum Variables and Specifications... 2

Chemical Process Design / Diseño de Procesos Químicos

Solving Equations and Optimizing Functions

Modified Raoult's Law and Excess Gibbs Free Energy

Chapter 10. Vapor/Liquid Equilibrium: Introduction

ChemSep Case Book: Handling Missing Components

Fuel, Air, and Combustion Thermodynamics

TXY diagram for water-formic acid at 1 atm

All Rights Reserved. Armando B. Corripio, PhD, P.E., Multicomponent Distillation Column Specifications... 2

Chapter 2 Equilibria, Bubble Points, Dewpoints, Flash Calculations, and Activity Coefficients

Distillation Course MSO2015

For an incompressible β and k = 0, Equations (6.28) and (6.29) become:

Vapor-liquid equilibrium

CFD Simulation of Flashing and Boiling Flows Using FLUENT

Agung Ari Wibowo, S.T, M.Sc THERMODYNAMICS MODEL

Introduction: Introduction. material is transferred from one phase (gas, liquid, or solid) into another.

DISTILLATION. Keywords: Phase Equilibrium, Isothermal Flash, Adiabatic Flash, Batch Distillation

(1) The packing group assignment for routes of administration other than inhalation of vapors shall be in accordance with the following table:

PETE 310 Lectures # 36 to 37

Predictive Equation of State

There are five problems on the exam. Do all of the problems. Show your work

Appendix F. Steam Tables

Isobaric Vapour-Liquid Equilibrium of Binary Mixture of 1, 2-Di-chloroethane with 1-Heptanol at Kpa

Vapor Pressure of Liquids Equilibria and Thermodynamics

Isobaric Vapour Liquid Equilibrium for Acetone + Methanol + Calcium bromide at different concentration

An Efficient Design of Multi Component Distillation Column by Approximate & Rigorous Method

DEVELOPMENT OF A ROBUST ALGORITHM TO COMPUTE REACTIVE AZEOTROPES

Evaluating properties of pure substances

Institute of Petroleum Engineering

Chapter 3 PROPERTIES OF PURE SUBSTANCES

Exam 3 Solutions. ClO g. At 200 K and a total pressure of 1.0 bar, the partial pressure ratio for the chlorine-containing compounds is p ClO2

P(N,V,T) = NRT V. = P(N,V,T) dv

Name: First three letters of last name

Note: items marked with * you should be able to perform on a closed book exam. Chapter 10 Learning Objective Checklist

CHEMISTRY 443, Fall, 2014 (14F) Section Number: 10 Examination 2, November 5, 2014

Predictive Equation of State

DETERMINATION OF ACTIVITY COEFFICIENTS AT INFINITE DILUTION FROM DEW POINT AND/OR BUBBLE POINT CURVES"

Step 1. Step 2. g l = g v. dg = 0 We have shown that over a plane surface of water. g v g l = ρ v R v T ln e/e sat. this can be rewritten

Contents. 1 Introduction and guide for this text 1. 2 Equilibrium and entropy 6. 3 Energy and how the microscopic world works 21

Chapter 11 Solution Thermodynamics: Theory

State Polytechnic of Malang Malang Heat Effect. Thermodynamics Course Chapter 4 Agung Ari Wibowo S.T., M.Sc

ECH 4224L Unit Operations Lab I Thin Film Evaporator. Introduction. Objective

Equilibrated Vapor Concentrations for Bicomponent Organic Solvents

Outline of the Course

Business. Business. Multiphase Systems Ch. 6. P vs T Diagram: Water (pure component) P vs T Diagram: CO 2 LYNN ORR

Shortcut Design Method for Columns Separating Azeotropic Mixtures

DETERMINATION OF OPTIMAL ENERGY EFFICIENT SEPARATION SCHEMES BASED ON DRIVING FORCES

G T = G f (product) G f (reactant) = kj/mol Ka (550 O C) = exp(8840/(8.314*( )) = 3.369

Optimization of Batch Distillation Involving Hydrolysis System

CHAPTER SIX THERMODYNAMICS Vapor-Liquid Equilibrium in a Binary System 6.2. Investigation of the Thermodynamic Properties of Pure Water

Distillation. JAMES R. FAIR Department of Chemical Engineering The University of Texas Austin, Texas. 5.1 INTRODUCTION 5.

Lecture 6. NONELECTROLYTE SOLUTONS

FLASH POINT FOR BINARY MIXTURES

Flash point of organic binary mixtures containing alcohols: experiment and prediction

Reflections on the use of the McCabe and Thiele method

Azeotropic distillation Example 1

1. (10) True or False: A material with an ideal thermal equation of state must have a constant c v.

There are five problems on the exam. Do all of the problems. Show your work.

CE 530 Molecular Simulation

ME 201 Thermodynamics

The concept of equilibrium

International Journal of Scientific & Engineering Research, Volume 6, Issue 3, March ISSN

The Advanced Chemical Engineering Thermodynamics. The thermodynamics properties of fluids (II) Ji-Sheng Chang Q&A_-10-11/17/2005(10)

- L. _/cit ...B N - Q. - PAD"t..t... QatJ11.81L. ><"'g. Below is a blank flow diagram of a generalized distillation column: (10 Points)

Chapter 3 PROPERTIES OF PURE SUBSTANCES. Thermodynamics: An Engineering Approach, 6 th Edition Yunus A. Cengel, Michael A. Boles McGraw-Hill, 2008

Chemical Potential. Combining the First and Second Laws for a closed system, Considering (extensive properties)

Vapor Pressure & Raoult s Law. This is the pressure above a solid or liquid due to evaporation.

Department of Chemical Engineering, Slovak Technical Bratislava. Received 8 October 1974

Introduction (1) where ij denotes the interaction energy due to attractive force between i and j molecules and given by; (2)

pv m = RT + Bp The simplest equation for calculating fugacity, given an equation of state, is Z=1 + B RT p

EXPERIMENT 7 - Distillation Separation of a Mixture

(Refer Slide Time: 00:00:43 min) Welcome back in the last few lectures we discussed compression refrigeration systems.

I: Life and Energy. Lecture 2: Solutions and chemical potential; Osmotic pressure (B Lentz).

Solving mass transfer problems on the computer using Mathcad

Business. Final Exam Review. Competencies. Schedule Today. Most missed on Exam 3. Review Exam #3

Problem 2 Distillation of air (20%) Solution

Chapter 6 Thermodynamic Properties of Fluids

DISTILLATION SIMULATION WITH COSMO-RS

B. Correct! Good work. F = C P + 2 = = 2 degrees of freedom. Good try. Hint: Think about the meaning of components and phases.

Chapter Equilibrium Practice AP Chemistry Date: Hour:

DETERMINATION AND PREDICTION OF THE ISOBARIC VAPOR- LIQUID-LIQUID EQUILIBRIUM DATA

Distillation is the most widely used separation

A Short Method To Calculate Residue Curve Maps in Multireactive and Multicomponent Systems

IlE. Simulation of a Distillation Column on an IBM PC, Accounting for Real Behaviour of Electrolyte Solutions * c I

EART 121 PROBLEM SET #5 SOLUTIONS

School of Chemical & Biological Engineering, Konkuk University

Simulation of Ethanol Dehydration Using Cyclohexane as an Entrainer

Nonlinear Parameter Estimation for Solution Diffusion Models of Membrane Pervaporation

Zittau/Goerlitz University of Applied Sciences Department of Technical Thermodynamics Germany. K. Knobloch, H.-J. Kretzschmar, K. Miyagawa, W.

Chapter 11 Spontaneous Change and Equilibrium

Computing Homogeneous Azeotropes æ Why í Identify limitations in separation operations í Construction of residue curve maps for design and synthesis o

Chapter 7 PHASE EQUILIBRIUM IN A ONE-COMPONENT SYSTEM

CinChE Problem-Solving Strategy Chapter 4 Development of a Mathematical Algorithm. partitioning. procedure

Investigating the Phase of High Entropy. Pressure

Transcription:

tion 10.5. VLE by Modified Raoult's Law 359 the,ure )OUt Bubblepoint and dewpoint calculations made with this equation are only a bit more complex than the same calculations made with Raoult's law. Activity coefficients are functions of temperature and liquid-phase composition, and ultimately are based on experiment (Sec. 12.1). For present purposes, the necessary values are assumed known. 6 Because Li Yi = 1, Eq. (10.5) may be summed over all species to yield: P _".. psat - L..,XiYz i (10.6) Alternatively, Eq. (10.5) may be solved for Xi, in which case summing over all species yields: P=----- (10.7) b YifYiP/at i Example 10.3 For the system methanol(1 )/methyl acetate(2), the following equations provide a reasonable correlation for the activity coefficients: lny1 = Ax} ln Y2 = Axf where A= 2.771-0.00523 T In addition, the following Antoine equations provide vapor pressures: In p sat= 16.59158-3,643.31 1 T - 33.424 ln P sat = 14.25326-2,665.54 2 T - 53.424 where T is in kelvins and the vapor pressures are in kpa. Assuming the validity of Eq. (10.5), calculate: (a) P and {Yi}, for T = 318.15 Kand x 1 = 0.25. (b) P and {xd, for T = 318.15 Kand y 1 = 0.60. (c) T and {Yi}, for P = 101.33 kpa and x1 = 0.85. second ;olution -::ient, is (10.5) (d) T and {xi}, for P = 101.33 kpa and YI= 0.40. (e) The azeotropic pressure, and the azeotropic composition, for T = 318.15 K. 6The correlation of activity-coefficient data is treated in Secs. 12.1 and 12.2. h d >!Yv('A v~ N~,u 1 ~Ab~ I/,_~ E ~r~eariv;f- J ~~VD -to vyl {/ 7 -& e J.HI/V'-,.,.1,,. -~

360 CHAPTER 10. Vapor/Liquid Equilibrium: Introduction Solution 10.3 (a) A BUBL P calculation. For T = 318.15 K, the Antoine equations yield: P 2 sat = 65.64 kpa Activity coefficients are calculated from the correlating equations: A= 2.771 - (0.00523)(318.15) = 1.107 YI = exp(axi) = exp [ (l.107)(0.75) 2 ] = 1.864 Y2 = exp(axf) = exp [(1.107)(0.25) 2 ] = 1.072 The pressure is given by Eq. (10.6): P = (0.25)(1.864)(44.51) + (0.75)(1.072)(65.64) = 73.50 kpa By Eq. (10.5) written, Yi = XiYi P/at / P, YI = 0.282 Y2 = 0.718 (b) A DEW P calculation. With T unchanged from part (a), the values of Pi8ai, Prt. and A are unchanged. However, the liquid-phase composition is here unknown, but is required in the calculation of activity coefficients. An iterative procedure is indicated; initial values are provided by Raoult's law, for which YI = Y2 = 1.0. The required steps, with current values of YI and Y2, are: Calculate P by Eq. (10.7), written: Calculate XI by Eq. (10.5): p = 1. YI/YI pisat + Y2/Y2P2sat YIP XI= Yipisat then X2 = 1 - XI Evaluate activity coefficients; return to the first step. Iteration to convergence on a value for P leads to final values: P = 62.89 kpa XI= 0.8169 YI= 1.0378 Y2 = 2.0935 (c) A BUBL T calculation. An initial value for the unknown temperature is found from the saturation temperatures of the pure species at the known pressure. The Antoine equation, solved for T, becomes: T sat - Bi - C, 1 i - Ai -lnp

10.5. VLE by Modified Raoult's Law 361 Application for P = 101.33 kpa leads to: T/at = 337.71 T/at = 330.08 K A mole-fraction-weighted average of these values then provides an initial T: T = (0.85)(337.71) + (0.15)(330.08) = 336.57 K An iterative procedure consists of the steps: For the cmtent value of T calculate values for A, YI, Y2, and a= p 1 sat; P/at from the given equations. Find a new value for PI sat from Eq. (10.6) written: P sat _ I - p XI YI + x2y2/a Find a new value for T from the Antoine equation written for species 1: Return to the initial step. Iteration to convergence on a value for T yields final values: T = 331.20 K P/at = 9524 kpa A= 1.0388 YI= 1.0236 The vapor-phase mole fractions are given by: P 2 sat = 48.73 kpa Y2 = 2.1182 and Y2 = 1 - YI = 0.330 (d) A DEW T calculation. Because P = 101.33 kpa, the saturation temperatures are the same as those of part (c), and an initial value for the unknown temperature is found as a mole-fraction weighted average of these values: T = (0.40)(337.71) + (0.60)(330.08) = 333.13 K Because the liquid-phase composition is not known, the activity coefficients are initialized as YI = Y2 = l. As in part (c) an iterative procedure is indicated: Evaluate A, P 1 sai, P/at, and a = Pt 1 / P 2 sat at the current value of T from the Antoine equations. Calculate XI by Eq. (10.5): YIP XI= YIP1sat then x2 = 1 - XI ' ~ '...,_,

362 CHAPTER 10. Vapor/Liquid Equilibrium: Introduction Calculate values of Yl and y2 from the correlating equations. Find a new value for p 1 sat from Eq. (10.7) written: p 1 sat = p (Yl + Y\x) Y1 Y2 Find a new value for T from the Antoine equation written for species 1: Return to the initial step and iterate with the current values of Yl and Y2 until the process converges on a value of T. The process yields the final values: T :::C 326.70 K A= 1.0624 x1 = 0.4602 P 1 sat = 64.63 kpa Yl = 1.3629 x2 = 0.5398 Pt 1 = 90.89 kpa Y2 = 1.2523 (e) First determine whether or not an azeotrope exists at the given temperature. This calculation is facilitated by the definition of a quantity called the relative volatility: (10.8) At an azeotrope Yl = x1, Y2 = x2, and a12 = 1. In general, by Eq. (10.5), Therefore, Yi Yi pi sat ~=-- Xi p Yl pl sat a12 = p sat Y2 2 (10.9) The correlating equations for the activity coefficients show that when x1 = 0, Y2 = 1, and Y1 = exp(a); when x1 = 1, Yl = 1 and y2 = exp(a). Therefore in these limits, and p sat (a12)x1 =1 = p2sat ~x Values of p 1 sai, p 2 sai, and A are given in part (a) for the temperature of interest. The limiting values of a12 are therefore: _ (44.51) exp(l.107) _ ( 12 ) xi=o - 2 0 65 _ - 52 64 44.51 (a12h1=l = (65.64) exp(l.107) = 0.224

>n 10.6. VLE from K-Value Correlations 363 Because the value at one limit is greater than 1, whereas the value at the other limit is less than 1, an azeotrope does exist, because a12 is a continuous function of xi and must pass through the value of 1.0 at some intermediate composition. For the azeotrope, a12 = 1, and Eq. (10.9) becomes: The difference between the correlating equations for ln YI and ln y2 provides the general relation: Thus the azeotropic occurs at the value of xi for which this equation is satisfied when the activity-coefficient ratio has its azeotrope value of 1.4747; i.e., when: YI ln - = ln 1.4747 = 0.388 Y2 Solution gives xi 2 = 0.325. For this value of xi, Yiz = 1.657. With xiz = Yiz, Eq. (10.5) becomes: paz = yf P/at = (1.657)(44.51) Thus, paz = 73.76 kpa Dewpoint and bubblepoint calculations are readily made with software packages such as Mathcad and Maple, in which iteration is an integral part of an equation-solving routine. Mathcad programs for solution of Ex. 10.3, parts (a) through (d), are given in App. D.2. Calculations for multicomponent systems made without simplifying assumptions are readily carried out in like manner by computer. The procedures are presented in Sec. 14.1. 10.6 VLE FROM K-VALUE CORRELATIONS A convenient measure of the tendency of a given chemical species to partition itself preferentially between liquid and vapor phases is the equilibrium ratio Ki, defined as: (10.10) This quantity is usually called simply a K-value. Although it adds nothing to thermodynamic knowledge of VLE, it does serve as a measure of the "lightness" of a constituent species, i.e., of its tendency to favor the vapor phase. When Ki is greater than unity, sped.es i exhibits a higher concentration in the vapor phase; when less, a higher concentration in the liquid phase, and..