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ANNALES DE L I. H. P., SECTION A M. KLAUS B. SIMON Binding of Schrödinger particles through conspiracy of potential wells Annales de l I. H. P., section A, tome 30, n o 2 (1979), p. 8387. <http://www.numdam.org/item?idaihpa_1979 30_2_83_0> GauthierVillars, 1979, tous droits réservés. L accès aux archives de la revue «Annales de l I. H. P., section A», implique l accord avec les conditions générales d utilisation (http://www. numdam.org/legal.php). Toute utilisation commerciale ou impression systématique est constitutive d une infraction pénale. Toute copie ou impression de ce fichier doit contenir la présente mention de copyright. Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques http://www.numdam.org/

We Let Ann. Inst. Henri Poincaré Vol. XXX, n 2, 1979, 83, Physique Section A : théorique. Binding of Schrödinger Particles Through Conspiracy of Potential Wells M. KLAUS (*) and B. SIMON (**) Department of Physics, Princeton University, Princeton, NJ 08540 ABSTRACT. study the ground state energy E(R) for when V and W are négative with compact support. In particular, in dimension 3, when a + V and A + W have no bound states but both have zéro energy résonances, we prove that E(R) ~ 2014 for R large with ~3..321651512... In this note we want to discuss some properties of the ground state energy, E(R), of the Schrödinger operator on where V and W have compact support and lie in ~ for v ~ 3, ~ 2 so that V(x) and W(R x) have disjoint supports. Our first result is (all proofs deferred until later) : THEOREM 1. decreases as R increases, i. e. V, W be négative. In the région R > Ro, 1 E(B) 1 (*) Supported by Swiss National Science Foundation ; on leave from the of Zurich. University (**) Research partially supported by USNSF Grant MCS7801885 also at of Mathematics. Dept. Annales de l Institut Henri Poincaré Section A Vol. XXX, 00202339/1979/83 $4.00 Gauthier Villars 5

1. Let A A 84 M. KLAUS AND B. SIMON Remarks. 2014 1. This is to be compared with the results of LiebSimon [2] who prove (1) when V and W are spherically symmetric and increasing but without the restriction of disjoint supports. 2. It is fairly obvious that this will not be true if V and W are sometime positive. For example, if v 1 and V consists of a négative well and W a positive well, then E(13.) > E( (0). Our remaining results are only of interest 3 dimensions and concern a rather specialized situation. Our interest was stimulated by work of I. Sigal [4] on the Effimov effort who found the results we de scribe below for V W spherical potentials. Our proofs in addition to being more général have some degree of greater simplicity and élégance. DEFINITION. A potential q on R03BD (in as above) is called subcritical if and only if + 03BBq ~ 0 for 0 ~ 03BB ~ 1 + G. It is called critical if and only if + q ~ 0 but 0394 + 03BBq has a négative eigenvalue for any ~. > 1. It is called supercritical if + q has négative eigenvalues. THEOREM 2. 3. If V and W are both subcritical, then E(R) 0 for R sufficiently large. Remark. There is an alternative proof [5] of this fact using hitting probabilities for Brownian paths and one that yields fairly explicit lower bounds on how large R needs to be. This proof dépends on the fact [5] that q is subcritical if and only if where ~ is the norm as a map from LOO to Loo. THEOREM 3. v 3. If V is subcritical and W is critical, then E(R) O(R 4(v 2») at infinity. THEOREM 4. Let v 3. If V and W are both négative and critical, then R~E(R) ~ 2014 ~ as R ~ oo where ~3 a2 and a is the unique solution of Remarks. The fixed point (2) is easily seen to be stable so that a can be computed by itération easily on a calculator. 24 itérations on an SR56 leads to the stable value oc.5671432904 and 03B2.321651512... 2. If v ~ 3, E(B)R 2(v 2) has a limit but unlike the case v 3, the limit is V and W dépendent and not universal. 3. The R 2 falloff and the related fact that thus (2M) 1 ar + E(R) will have an infinity of bound states for suitable Mare critical to Sigal s proof of the Effimov effect [4]. THEOREM 5. 2014 If either V or W is supercritical then E(oo) lim E(R) exists and E(R) E( (0) o(ear) for suitable a > 0. Annales de l Institut Henri Poincaré Section A

1. By BINDING OF SCHRÔDINGER PARTICLES THROUGH 85 Remarks. In fact, E( (0) min 8 + V), inf 6( Ll + W). 2. Using the methods of [3], one easily obtains that E(R) E(oo) o(rn) for all n. We now turn to the method of proof of thèse results. The same method of proof has been used by one of us [7] to analyze the question of defining selfadjoint Dirac Hamiltonians where one has potentials with several singularities. For simplicity, we suppose that V and W are nonpositive, treating the more général case in remarks following the formai proofs. The basic fact that we exploit is that for q 0 in Lp, the ground state energy E( q) is determined by the condition that Kq ~ q ( 1 ~2( ~ E) 1 I q ~ 1 ~2 have norm 1; equivalently since Kq is a positive compact operator, 1 is its (simple) largest eigenvalue ; equivalently since Kq has a positive intégral kernel, it has a pointwise, nonnégative eigenvector with eigenvalue 1. Now if Kq~ " and V(x) + W(R x), then " ij 1 + ~2 with " 1 having support in supp (V) and ~2 in support ofw(r 2014 x). If V and W(R 2014 x) has disjoint supports, then this décomposition is unique. Writing q(x) 111 (!) + 112(R x) we see that Kq~ 11 is équivalent to where 1> is the twocomponent vector 03A6 (111 ~2) and L is the twobytwo matrix operator with intégral kernel: where Go(x y, E) is the kernel of (2014 A 2014 E) 1. To summarize, E(R) is determined in the région E(R) 0 by the condition L(E, R) I~ 1. Since K and hence L is monotone decreasing as E decreases, we see that if L(Eo, R) Il ~ 1 (resp > 1), then E(R) ~ Eo (resp Eo). Proof of 1. Since R > Ro, for each x, y with x ~ supp V, y E supp W, Go(x + y E) Go(x + y R, E) for any E 0 and any ~, > 1. It follows that, for any r~ ~ 0, (r~ 7~ 0), so, since L has a positive intégral kernel, L(E, /LR) ~ ~ ~ L(E, R) proving the result. Remark. the strict inequality in (3) and the compactness of L, we have actually proven that E(AR) > E(R) for R ~ Ro, ~ > 1 and E(R)0. Proof of Theorem 2. 2014 Write L LD + Lo with LD diagonal and Lo off diagonal. Since 0) c x ~ w 2} and V, W E L 1, Since V, W, are subcritical, R) Il 1 R) is R independent). Thus, for we have that E(R)0. Vol. XXX, n 2 1979.

86 M. KLAUS AND B. SIMON Remark. 2014 If ~ L ~ and ~ LD (but not Lo are replaced by max 6(L) and max the proof extends to the case where V and W are not necessarily négative. Proof of Theorem 3. 2014 Make the décomposition L LD + Lo as in the proof of Theorem 2. has 1 as a simple discrète eigenvalue by hypothesis and all other eigenvalues are strictly smaller. Write where bl [LD(E) + Lo(E, R) + As above, for R > Ro, Il Lo(E, R) Il CR (v 2) independently of E. Using E k2 : we see that Il 5L1 Dk2 with A1 the 2 x 2 matrix operator which is zéro offdiagonal and c1v1/2 x y (03BD3)V1/2 and " Cl Wl/21 ;! y B(v 3)W1/2 ondiagonal. We now use perturbation theory. The largest eigenvalue ~o(e, R) of L(E, R) is determined by where 03A6 (11, 0) is the normalized vector with LD(0)03A6 03A6. Expanding (4) becomes : Since (1], c5ll11)1]) ck + 0(k2) with c ~ 0, the condition ~,o 1 becomes k 0(R ~ ~) or E 0(R ~ ~). Remark. 2014 By carrying on the calculations explicitly to second order, one can show that ER4(v2) converges to an explicit V, W dépendent constant as R ~ oo. Proof of Theorem 4. For simplicity, consider first the case V W. Then L leaves the subspace {03A6 (1}, ± 1])} invariant. The largest eigenvalue of L is on the (1], 1]) subspace. On this subspace, 1 is a simple discrète eigenvalue of LD(o). Using first order as above we obtain the équation : Since 1] > 0. ~r~, W l2) ~ 0 and thus so kr ao + E For the general case, V ~ W, LD(O) has 1 as a degenerate eigenvalue. Annales de l Institut Henri Poincaré Section A

If BINDING OF SCHRÖDINGER PARTICLES THROUGH 87 So we need to use degenerate perturbation theory. The first order terms then become : where a 1 V 1 ~2), b (~J W 11/2) with the normalized eigenvalue of The condition that F have a zéro eigenvalue is det F 0 or using a, b ~ 0, k Thus (5) still holds. Remark. order terms are v > 3, and V W (for simplicity only), then the first Since Go(R, k2) dr ~~ 2~, we see that kr 0 and thus Go(R, k2) ~ so that we get E k2 ~ a2r 2~v 2) with a explicitly V dépendent. Proof of Theorem 5. This follows the proof of Theorem 3, except that since one of V, W is supercritical, the off diagonal terms are O(eaR). It is a pleasure to thank I. ACKNOWLEDGMENTS Sigal for informing us of his work before publication and both him and M. Aizenman for valuable discussion. [1] M. KLAUS, in prep. [2] E. LIEB and B. SIMON, J. Phys. B., t. 115,1978, p. L 537L 547. [3] J. MORGAN and B SIMON, in prep. [4] I. SIGAL, in prep. [5] B. SIMON, in prep. ( Manuscrit reçu le 3 janvier 1979) Vol. XXX, n 2 1979.