Bernhard Holzer, CERN-LHC

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Bernhard Holzer, CERN-LHC * Bernhard Holzer, CERN CAS Prague 2014

Lattice Design... in 10 seconds... the Matrices Transformation of the coordinate vector (x,x ) in a lattice x(s) x = M 0 x'(s) 1 2 x' 0 x ρ Matrix expressed as function of focusing properies M 1 2 = M qf * M ld * M B * M qd * M... s 1 s 2 Transformation of the coordinate vector (x,x ) expressed as a function of the twiss parameters And both descriptions are equivalent!!

Lattice Design... in 10 seconds... the β-function Transformation Matrix for half a FODO 1 l D M halfcell = M QF / 2 * M D * M QD / 2 = l D f f 2 l D 1+ l D f nota bene : f = 2 * f... it is a half quad! Compare to the twiss parameter form of M In the middle of a foc (defoc) quadrupole of the FoDo we allways have α = 0, and the half cell will lead us from β max to β min β cosψ cell β β sin ψ cell β 2 2 M half cell = 1 sinψ cell β β 2 cosψ cell β β 2

Scaling law for a FODO cell: ˆ β = (1+ sin ψ cell 2 )L sinψ cell! β = (1 sin ψ cell 2 )L sinψ cell! ˆ β (ψ) + β (ψ) The maximum and minimum values of the β-function are solely determined by the phase advance and the length of the cell. ψ Longer cells lead to larger β... and there is an optimum phase!! * see advanced CAS lectures, lattice design Bernhard Holzer, CERN CAS Prague (e.g. 2014 CERN-2006-002)

Influence of external fields on the beam: prop. to magn. field & prop. zu 1/p dipole magnet focusing lens particle having... to high energy to low energy ideal energy

in case of a momentum spread: which acts like a quadrupole error in the machine and leads to a tune spread: definition of chromaticity: Q'= 1 4π k(s)β(s)ds

Where is the Problem?

Tunes and Resonances avoid resonance conditions: m Q x +n Q y +l Q s = integer for example: 1 Q x =1

and now again about Chromaticity: Problem: chromaticity is generated by the lattice itself!! Q' is a number indicating the size of the tune spot in the working diagram, Q' is always created if the beam is focussed it is determined by the focusing strength k of all quadrupoles k = quadrupole strength β = betafunction indicates the beam size and even more the sensitivity of the beam to external fields Example: LHC Q' = 250 Δ p/p = +/- 0.2 *10-3 Δ Q = 0.256 0.36 Some particles get very close to resonances and are lost in other words: the tune is not a point it is a pancake

Tune signal for a nearly uncompensated cromaticity ( Q' 20 ) Ideal situation: cromaticity well corrected, ( Q' 1 )

Tune and Resonances m*q x +n*q y +l*q s = integer Qy =1.5 HERA e Tune diagram up to 3rd order and up to 7th order Qy =1.3 Qy =1.0 Qx =1.0 Qx =1.3 Qx =1.5 Homework for the operateurs: find a nice place for the tune where against all probability the beam will survive

Need: additional quadrupole strength for each momentum deviation Δp/p 1.) sort the particles acording to their momentum using the dispersion function 2.) apply a magnetic field that rises quadratically with x (sextupole field) linear rising gradient :

k 1 normalised quadrupole strength k 2 normalised sextupole strength Sextupole Magnets: N S S N Combined effect of natural chromaticity and Sextupole Magnets: Q'= 1 4π { k 1 (s)β(s)ds + k 2 * D(s)β(s)ds} You only should not forget to correct Q in both planes... and take into account the contribution from quadrupoles of both polarities.

corrected chromaticity considering an arc built out of single cells: Q' x = 1 4π k ˆ qf β x l qf k qd β x l qd F quad D quad + 1 4π F sext k 2 F l sext D x F β x F 1 4π D sext k 2 D l sext D x D β x D Q' y = 1 4π k qf β y l qf + F quad k ˆ qd β y l qd D quad 1 4π F sext k 2 F l sext D x F β x F + 1 4π D sext k 2 D l sext D x D β x D

... the most complicated one: the drift space transfer matrix for a drift:

let s assume we are at a symmetry point in the center of a drift. as and we get for the β function in the neighborhood of the symmetry point At the end of a long symmetric drift space the beta function reaches its maximum value in the complete lattice. -> here we get the largest beam dimension. -> keep l as small as possible s β 0 s

21.) Luminosity p2-bunch 10 11 particles Example: Luminosity run at LHC p1-bunch IP 10 11 particles ± σ

8 individually powered quad magnets are needed to match the insertion (... at least)

A mini-β insertion is always a kind of special symmetric drift space. greetings from Liouville x x at a symmetry point β is just the ratio of beam dimension and beam divergence.

The LHC Insertions ATLAS R1 IP1 TAS* Inner Triplet Q1 Q2 Q3 D1 (1.38 T) Separation/ Recombination Tertiary collimator s TAN* D2 Q4 (3.8 T) Matching Quadrupoles Q5 Q6 Q7 1.9 K Warm 188 mm 4.5 K 4.5 K 4.5 K 1.9 K Q3 D1 Q2 mini β optics Q1

and now back to the Chromaticity question: main contribution to Q' in a lattice? mini beta insertions

Clearly there is another problem...... if it were easy everybody could do it Again: the phase space ellipse for each turn write down at a given position s in the ring the single partilce amplitude x and the angle x... and plot it. A beam of 4 particles each having a slightly different emittance:

particle vector: Idea: calculate the particle coordiantes x, x through the linear lattice using the matrix formalism. if you encounter a nonlinear element (e.g. sextupole): stop calculate explicitly the magnetic field at the particles coordinate calculate kick on the particle Δ x 1 = B l z p/e = 1 2 g p/e l(x 2 1 z 2 1 ) = 1 2 m l(x 2 sext 1 z 2 1 ) and continue with the linear matrix transformations

Installation of a weak (!!! ) sextupole magnet The good news: sextupole fields in accelerators cannot be treated with conventional methods. no equatiuons; instead: Computer simulation particle tracking

Effect of a strong (!!! ) Sextupole Catastrophy! dynamic aperture

quadrupole error: tune shift beta beat chromaticity momentum compaction beta function in a symmateric drift

Appendix I: Ansatz: = det M = 1 remember: for Cs) and S(s) to be independent solutions the Wronski determinant has to meet the condition

and as it is independent of the variable s we get for the initital conditions that we had chosen remember: S & C are solutions of the homog. equation of motion: =D(s) or qed

Appendix II: a change of quadrupole strength in a synchrotron leads to tune sift: tune spectrum... tune shift as a function of a gradient change But we should expect an error in the β-function as well shouldn t we???

Quadrupole Errors and Beta Function a quadrupole error will not only influence the oscillation frequency tune but also the amplitude beta function split the ring into 2 parts, described by two matrices A and B s 0 A B ρ s 1 matrix of a quad error between A and B

the beta function is usually obtained via the matrix element m12, which is in Twiss form for the undistorted case and including the error: As M* is still a matrix for one complete turn we still can express the element m 12 in twiss form: Equalising (1) and (2) and assuming a small error 1 2 dq

ignoring second order terms remember: tune shift dq due to quadrupole error: (index 1 refers to location of the error) solve for dβ express the matrix elements a 12, b 12 in Twiss form

after some TLC transformations Nota bene:! the beta beat is proportional to the strength of the error Δk!! and to the β function at the place of the error,!!! and to the β function at the observation point, ( remember orbit distortion!!!)!!!! there is a resonance denominator