ENGG 1203 Tutorial. Solution. Op Amps 7 Mar Learning Objectives. Determine V o in the following circuit. Assume that the op-amp is ideal.

Similar documents
ENGG 1203 Tutorial. Op Amps 10 Oct Learning Objectives. News. Ack.: MIT OCW Analyze circuits with ideal operational amplifiers

1 Circuits (20 points)

The equivalent model of a certain op amp is shown in the figure given below, where R 1 = 2.8 MΩ, R 2 = 39 Ω, and A =

Series & Parallel Resistors 3/17/2015 1

Designing Information Devices and Systems I Fall 2018 Lecture Notes Note Introduction: Op-amps in Negative Feedback

DC motor / generator. Jeffrey A. Meunier

Designing Information Devices and Systems II Fall 2016 Murat Arcak and Michel Maharbiz Homework 0. This homework is due August 29th, 2016, at Noon.

Ohm's Law and Resistance

Lecture 5: Using electronics to make measurements

meas (1) calc calc I meas 100% (2) Diff I meas

Simultaneous equations for circuit analysis

Chapter 2. Engr228 Circuit Analysis. Dr Curtis Nelson

ENGG 1203 Tutorial. Quick Checking. Solution. A FSM design for a Vending machine (Revisited) Vending Machine. Vending machine may get three inputs

Lecture 5: Using electronics to make measurements

Homework 3 Solution. Due Friday (5pm), Feb. 14, 2013

ENGG 1203 Tutorial_05. Use of Multimeter. Lab 5 : SYSTEM. Office hours : Chow Yei Ching, CB-LG205 Thu, Fri; 15:30-17:30

Notes on Electricity (Circuits)

Kirchhoff's Laws and Circuit Analysis (EC 2)

resistance in the circuit. When voltage and current values are known, apply Ohm s law to determine circuit resistance. R = E/I ( )

Experiment #6. Thevenin Equivalent Circuits and Power Transfer

Solution: Based on the slope of q(t): 20 A for 0 t 1 s dt = 0 for 3 t 4 s. 20 A for 4 t 5 s 0 for t 5 s 20 C. t (s) 20 C. i (A) Fig. P1.

Operational Amplifiers

Solved Problems. Electric Circuits & Components. 1-1 Write the KVL equation for the circuit shown.

ECE 220 Laboratory 4 Volt Meter, Comparators, and Timer

INTRODUCTION TO ELECTRONICS

20.2 Design Example: Countdown Timer

Active loads in amplifier circuits

DC CIRCUIT ANALYSIS. Loop Equations

Module 1, Add on math lesson Simultaneous Equations. Teacher. 45 minutes

STEAM Clown Production. Series Circuits. STEAM Clown & Productions Copyright 2017 STEAM Clown. Page 2

Outline. Week 5: Circuits. Course Notes: 3.5. Goals: Use linear algebra to determine voltage drops and branch currents.

Prelim Revision. Questions and Answers. Electricity

EE-201 Review Exam I. 1. The voltage Vx in the circuit below is: (1) 3V (2) 2V (3) -2V (4) 1V (5) -1V (6) None of above

P1: Basics - Things you now know that you didn t know you knew (25 pts)

ENGG 1203 Tutorial_9 - Review. Boolean Algebra. Simplifying Logic Circuits. Combinational Logic. 1. Combinational & Sequential Logic

What to Add Next time you update?

Notes on Electricity (Circuits)

Design Engineering MEng EXAMINATIONS 2016

Massachusetts Institute of Technology Department of Electrical Engineering and Computer Science : Circuits & Electronics Problem Set #1 Solution

DEPARTMENT OF COMPUTER ENGINEERING UNIVERSITY OF LAHORE

Designing Information Devices and Systems I Spring 2016 Elad Alon, Babak Ayazifar Midterm 2. Exam location: 145 Dwinelle, last SID# 2

The Approximating Impedance

Simple Resistive Circuits

Electric Power a learn.sparkfun.com tutorial

E1.1 Analysis of Circuits ( ) Revision Lecture 1 1 / 13

R 2, R 3, and R 4 are in parallel, R T = R 1 + (R 2 //R 3 //R 4 ) + R 5. C-C Tsai

Parallel Circuits. Chapter

Fig. 1-1 Current Flow in a Resistive load

mith College Computer Science CSC270 Spring 16 Circuits and Systems Lecture Notes Week 3 Dominique Thiébaut

POLYTECHNIC UNIVERSITY Electrical Engineering Department. EE SOPHOMORE LABORATORY Experiment 2 DC circuits and network theorems

ENGG4420 LECTURE 7. CHAPTER 1 BY RADU MURESAN Page 1. September :29 PM

Figure Circuit for Question 1. Figure Circuit for Question 2

EE292: Fundamentals of ECE

6.01 Final Exam Spring 2011

California University of Pennsylvania. Department of Applied Engineering & Technology. Electrical / Computer Engineering Technology

ES250: Electrical Science. HW1: Electric Circuit Variables, Elements and Kirchhoff s Laws

In this lecture, we will consider how to analyse an electrical circuit by applying KVL and KCL. As a result, we can predict the voltages and currents

ECE Circuit Theory. Final Examination. December 5, 2008

CURRENT SOURCES EXAMPLE 1 Find the source voltage Vs and the current I1 for the circuit shown below SOURCE CONVERSIONS

D is the voltage difference = (V + - V - ).

Series/Parallel Circuit Simplification: Kirchoff, Thevenin & Norton

Designing Information Devices and Systems I Fall 2017 Midterm 2. Exam Location: 150 Wheeler, Last Name: Nguyen - ZZZ

mywbut.com Mesh Analysis

E40M Review - Part 1

Relating Voltage, Current and Resistance

Circuit Theorems Overview Linearity Superposition Source Transformation Thévenin and Norton Equivalents Maximum Power Transfer

RIB. ELECTRICAL ENGINEERING Analog Electronics. 8 Electrical Engineering RIB-R T7. Detailed Explanations. Rank Improvement Batch ANSWERS.

Electric Circuits. June 12, 2013

ENGG 225. David Ng. Winter January 9, Circuits, Currents, and Voltages... 5

PICK UP: Papers & Calc. TURN IN: - (orange sheet if you did not yesterday) DO NOW: On a half-sheet, draw the schematic for the following circuit.

Resistor. l A. Factors affecting the resistance are 1. Cross-sectional area, A 2. Length, l 3. Resistivity, ρ

ECE2210 Final given: Spring 08

Electric Circuits I. Nodal Analysis. Dr. Firas Obeidat

Delta & Y Configurations, Principles of Superposition, Resistor Voltage Divider Designs

Circuits for Analog System Design Prof. Gunashekaran M K Center for Electronics Design and Technology Indian Institute of Science, Bangalore

EE100Su08 Lecture #9 (July 16 th 2008)

Fundamentals of Electric Circuits, Second Edition - Alexander/Sadiku

CIRCUITS AND ELECTRONICS. Dependent Sources and Amplifiers

Homework 1 solutions

IMPERIAL COLLEGE OF SCIENCE, TECHNOLOGY AND MEDICINE UNIVERSITY OF LONDON DEPARTMENT OF ELECTRICAL AND ELECTRONIC ENGINEERING EXAMINATIONS 2010

Engineering Fundamentals and Problem Solving, 6e

Figure 1. (a) An alternating current power supply provides a current that keeps switching direction.

DC STEADY STATE CIRCUIT ANALYSIS

Problem Set 5 Solutions

EE 321 Analog Electronics, Fall 2013 Homework #3 solution

Systematic methods for labeling circuits and finding a solvable set of equations, Operational Amplifiers. Kevin D. Donohue, University of Kentucky 1

Basic Electricity. ME 120 Lecture Notes. Portland State University Mechanical and Materials Engineering

The equation which links current, potential difference and resistance is:

Physics 212 Midterm 2 Form A

Digital logic signals

Digital logic signals

Electricity & Magnetism

Midterm Exam (closed book/notes) Tuesday, February 23, 2010

Module 2. DC Circuit. Version 2 EE IIT, Kharagpur

Experiment 9 Equivalent Circuits

QUIZ 1 SOLUTION. One way of labeling voltages and currents is shown below.

6.01 Midterm 2 Spring 2011

Lecture # 2 Basic Circuit Laws

Designing Information Devices and Systems I Spring 2018 Lecture Notes Note 20

From this analogy you can deduce some rules that you should keep in mind during all your electronics work:

Transcription:

ENGG 03 Tutorial Q Op Amps 7 Mar Learning Objectives Analyze circuits with ideal operational amplifiers News HW Mid term Revision tutorial ( Mar :30-6:0, CBA) Ack.: MIT OCW 6.0 Determine V o in the following circuit. Assume that the op-amp is ideal. Solution Q Since V - = V +, V - = V. So there must be /A flowing left through the two 6 ohm resistors. There must be a corresponding / A flowing to the left through the ohm resistor. V o is then the sum of V - = V and the V across the ohm resistor. Determine the current I x when V = V and V = V. Determine the voltage V A when V = V and V = V. Determine a general expression for V A in terms of V and V. 3

Solution Q3 When V = V and V = V, I x = A When V = V and V = V, V A = V A general expression for V A : 3 - Use a single op-amp and resistors to make a circuit that is equivalent to the following circuit. = V n 6 Q Q Use the ideal op-amp model (V + = V - ) to determine an expression for the output current I o in terms of the input voltage V i and resistors R and R. Determine R so that V o = (V V ). v i +v x v i +v x v x 7 8

Solution Q6 No current in +ve or -ve inputs: Ideal op-amp: A proportional controller that regulates the current through a motor by setting the motor voltage V C to V C = K(I d I o ) K is the gain (ohms) I d is the desired motor current I o is the actual current through the motor. 9 0 Solution Q7 Consider the circuit inside the dotted rectangle. Determine V as a function of I o. V + = / x I o = V - V - = 00/(00+9900) x V V = / x I o x 00 The shaft angle of the output pot tracks that of the input pot If the person turn the left potentiometer (the input pot), then the motor will turn the right potentiometer (the output pot) Determine the gain K and desired motor current I d. KCL at -ve input to right op-amp:. 000. 000 0 0.

Solution Solution Pot resistances depends on shaft angle Lower part of the pot is αr Upper part is ( α)r, where R = 000Ω. α is from 0 (most counterclockwise position) to (most clockwise position) If α i >α o, then the voltage to the motor (V M+ V M ) is positive, and the motor turns clockwise (so as to increase α o ) i.e., positive motor voltage clockwise rotation. Determine an expression for V M+ in terms of α i, R, and V S. The output of the voltage divider is The op-amp provides a gain of, so V M+ = V +. 3 The following circuit produces a voltage V o that depends on the position of the input pot. Determine an expression for the voltage V o in terms of α i, R, R, R, and V S. The following circuit produces a voltage V o that depends on the positions of both pots. Determine an expression for V o in terms of α i, α o, R, and V S. The positive input to the op-amp is connected to pot so that The positive input to the op-amp is connected to a voltage divider with equal resistors so The output pot is on the output of the op-amp, so The input pot is on the output of the op-amp, so In an ideal op-amp, V + = V so In an ideal op-amp, V + = V so 6

Assume that we are provided with a circuit whose output is α i /α o volts. We want to design a motor controller of the following form so that the motor shaft angle (which is proportional to α o ) will track the input pot angle (which is proportional to α i ). Assume that R = R 3 = R = 000Ω and V C = 0. Is it possible to choose R so that α o tracks α i? If yes, enter an acceptable value for R. Assume that R = R 3 = R = 000Ω and V C = 0 If R 3 = R then the right motor input is V. If α i = α o then the gain of the left op-amp circuit must be so that the motor voltage is 0. The gain is R + R /R, so R must be 000Ω. 0 7 8 Assume that R = R 3 = R = 000Ω and V C = V If R 3 = R then the right motor input is V. If α i = α o then V + = V = for the right op-amp. We need the left motor input to be V. But if the left motor input is V and V C = V then V must also be V, which leads to a contradiction. Q8 You have to design a hammer machine (i.e. using a hammer to hit a platform to see how strong the participants are). The design goal is to generate an output voltage (V o ) which is proportional to the force (F) applied on the hammer, i.e. V o = m x F + C, with m > 0 and C > 0. (a) You found a force-sensitive resistor (FSR) from the catalog, which can be modeled by RFSR = 0kΩ F You then design a circuit as a potential divider. Will this circuit correctly implement? No, because V o is not linearly proportional to F. 9 0

(b) Find the gain of the following circuit: At the two op-amp inputs, V - = V + = V i. Since V i is related to V o through the two resistors such that V o R = (R 3 + R ), R Vo = + R 3 Vi (c) Design (by using the non-inverting amplifier circuit) a circuit such that the output voltage (V o ) is directly proportional to the input force (F). Replace R by the FSR. We then have R F R V V V F V 3 3 i o = + i = + i 0000 0000 V o is a linear function of F. R F R V V V F V 3 3 i o = + i = + i 0000 0000 R F R V V V F V 3 3 i o = + i = + i 0000 0000 (d) The system requires that when the force F = 0 N, V o = V; when F = 0 N, V o = V. Construct the circuit designed in (c) using only one FSR, one op-amp, one V power supply, and k ohm resis. When F = 0N, V o = V i = V. We can use R = k ohm and R = k ohm. k ohm resistors can be made by two k ohm resistors in series. When F = 0N, R3 = 0 + R3 = kω 0000 3 (e) Using the above circuit, what is the value of V o when someone hits the hammer too hard, generating a force of 00 N? V (f) Suggest modification(s) such that the max. allowable force to the circuit is 60 N. Change R 3 to /3 k ohm. This can be done by parallel composition of three k ohm resistors.

(Appendix) Q9 Solution Fill in the values of R and R required to satisfy the equations in the left column of the following table. The values must be non-negative (i.e., in the range [0, ]) R R V o = V - V V o = V - V V o = V - V 3 rd : Negative R i.e. Impossible R R V o =V -V 0kΩ 0kΩ V o =V -V 0kΩ 0kΩ V o =V -V Impossible Impossible 6 (Appendix) Q0 (Appendix) Q What is V o? V o = 0 V o = V V V 3 V 3 + V V 3 + V Students Kim, Pat, Jody, Chris, and Leon are trying to design a controller for a display of three robotic mice in the Rube Goldberg Machine, using a 0V power supply and three motors. The first is supposed to spin as fast as possible (in one direction only), the second at half of the speed of the first, and the third at half of the speed of the second. Assume the motors have a resistance of approximately Ω and that rotational speed is proportional to voltage. For each design, indicate the voltage across each of the motors. 7 8

Solution (Jody s Design) Solution (Chris s Design) P.D. of motor = 0V P.D. of motor = 0.0V P.D. of motor 3 = 0V Wrong design 0 0.0 P.D. of motor = 0V P.D. of motor = 0.V P.D. of motor 3 = 0V Wrong design 0 0. Eq. R. (Red): K+~ K Eq. R. (Blue): K//K// ~ 0 Eq. R. (Red): 00K+~ 00K Eq. R. (Blue): K//00K// ~ 0 9 30 Solution (Pat s Design) Solution (Kim s Design) P.D. of motor = 0V P.D. of motor = V P.D. of motor = 0V P.D. of motor = V P.D. of motor 3 = V Wrong design P.D. of motor 3 =.V Correct design 0 0 Eq. R. : K // K = /3K Eq. R. : 00 // 00K = ~00.. 3 3

Solution (Leon s Design) P.D. of motor = 0V P.D. of motor 3 =.V P.D. of motor = V Correct design 0.. 33