Example 1. What are the critical points of f x 1 x x, 0 x? The maximal domain of f is 0 x and we find that

Similar documents
4.3 - How Derivatives Affect the Shape of a Graph

Maximum and Minimum Values

f'(x) = x 4 (2)(x - 6)(1) + (x - 6) 2 (4x 3 ) f'(x) = (x - 2) -1/3 = x 2 ; domain of f: (-, ) f'(x) = (x2 + 1)4x! 2x 2 (2x) 4x f'(x) =

3.1 ANALYSIS OF FUNCTIONS I INCREASE, DECREASE, AND CONCAVITY

Maximum and Minimum Values - 3.3

Overview. Graphing More Accurately First and second derivatives Critical points Extrema

4.3 How derivatives affect the shape of a graph. The first derivative test and the second derivative test.

In order to master the techniques explained here it is vital that you undertake plenty of practice exercises so that they become second nature.

Chiang/Wainwright: Fundamental Methods of Mathematical Economics

(d by dx notation aka Leibniz notation)

PACKET Unit 4 Honors ICM Functions and Limits 1

x π. Determine all open interval(s) on which f is decreasing

To do this which theorem did you use? b) Determine which points are inflections and mark the concavity on a number line for f.

?

Polynomial Functions of Higher Degree

Increasing and Decreasing Functions and the First Derivative Test

18.01 Single Variable Calculus Fall 2006

MAXIMA & MINIMA The single-variable definitions and theorems relating to extermals can be extended to apply to multivariable calculus.

Asymptotes are additional pieces of information essential for curve sketching.

Math 180, Exam 2, Spring 2013 Problem 1 Solution

Section 4.1 Increasing and Decreasing Functions

+ 2 on the interval [-1,3]

CALCULUS APPLICATIONS OF DIFFERENTIATION LESSON PLAN. C3 Topic Overview

Week #6 - Taylor Series, Derivatives and Graphs Section 4.1

Graphing and Optimization

Abe Mirza Graphing f ( x )

4.3 Mean-Value Theorem and Monotonicity

12.10 Lagrange Multipliers

Section 3.3 Limits Involving Infinity - Asymptotes

UNIT 2 SIMPLE APPLICATION OF DIFFERENTIAL CALCULUS

It s Your Turn Problems I. Functions, Graphs, and Limits 1. Here s the graph of the function f on the interval [ 4,4]

DIFFERENTIATION. 3.1 Approximate Value and Error (page 151)

1.2 Functions and Their Properties PreCalculus

TUTORIAL 4: APPLICATIONS - INCREASING / DECREASING FUNCTIONS, OPTIMIZATION PROBLEMS

Section 3.4: Concavity and the second Derivative Test. Find any points of inflection of the graph of a function.

12.1 The Extrema of a Function

Math 180, Final Exam, Spring 2008 Problem 1 Solution. 1. For each of the following limits, determine whether the limit exists and, if so, evaluate it.

Functions. Introduction

HW 5 Date: Name Use Scantron 882E to transfer the answers. Graph. 1) y = 5x

Math Honors Calculus I Final Examination, Fall Semester, 2013

CURVE SKETCHING. Let's take an arbitrary function like the one whose graph is given below:

Find the following limits. For each one, if it does not exist, tell why not. Show all necessary work.

SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question.

Functions. Introduction CHAPTER OUTLINE

236 Chapter 4 Applications of Derivatives

SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question.

MATH 1325 Business Calculus Guided Notes

Review of elements of Calculus (functions in one variable)

Name: NOTES 4: APPLICATIONS OF DIFFERENTIATION. Date: Period: Mrs. Nguyen s Initial: WARM UP:

5.5 Worksheet - Linearization

Math 125 Practice Problems for Test #3

Circle your answer choice on the exam AND fill in the answer sheet below with the letter of the answer that you believe is the correct answer.

Math 2250 Exam #3 Practice Problem Solutions 1. Determine the absolute maximum and minimum values of the function f(x) = lim.

3 Additional Applications of the Derivative

AP Calculus Prep Session Handout. Integral Defined Functions

Math 2414 Activity 1 (Due by end of class Jan. 26) Precalculus Problems: 3,0 and are tangent to the parabola axis. Find the other line.

Daily Lessons and Assessments for AP* Calculus AB, A Complete Course Page 119 Mark Sparks 2012

In #1-5, find the indicated limits. For each one, if it does not exist, tell why not. Show all necessary work.

f on the same coordinate axes.

Mathematics 1161: Midterm Exam 2 Study Guide

MATH section 3.4 Curve Sketching Page 1 of 29

Review Test 2. MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. D) ds dt = 4t3 sec 2 t -

Review for Test 2 Calculus I

Suppose that f is continuous on [a, b] and differentiable on (a, b). Then

Math 2414 Activity 1 (Due by end of class July 23) Precalculus Problems: 3,0 and are tangent to the parabola axis. Find the other line.

Lesson Goals. Unit 2 Functions Analyzing Graphs of Functions (Unit 2.2) Graph of a Function. Lesson Goals

MA Lesson 25 Notes Section 5.3 (2 nd half of textbook)

SAMPLE FINAL EXAM MATH 16A WINTER 2017

Quick Review 4.1 (For help, go to Sections 1.2, 2.1, 3.5, and 3.6.)

Chapter 6 Overview: Applications of Derivatives

Understanding Part 2 of The Fundamental Theorem of Calculus

Calculus 221 worksheet

Calculus 1: Sample Questions, Final Exam

1 x

APPLICATIONS OF DIFFERENTIATION

Directional derivatives and gradient vectors (Sect. 14.5). Directional derivative of functions of two variables.

University of Bergen. Solutions to Exam in MAT111 - Calculus 1

Section 4.1. Math 150 HW 4.1 Solutions C. Panza

November 13, 2018 MAT186 Week 8 Justin Ko

Format. Suggestions for study

Optimization. 1 Some Concepts and Terms

Sections Practice AP Calculus AB Name

UNIT 3. Recall From Unit 2 Rational Functions

12.2. Maxima and Minima. Introduction. Prerequisites. Learning Outcomes

Economics 205 Exercises

Calculus I Practice Problems 8: Answers

Analyzing f, f, and f Solutions

Solutions Exam 4 (Applications of Differentiation) 1. a. Applying the Quotient Rule we compute the derivative function of f as follows:

AP Calculus BC Summer Packet 2017

NOTES 5: APPLICATIONS OF DIFFERENTIATION

17.3. Parametric Curves. Introduction. Prerequisites. Learning Outcomes

Unit #3 Rules of Differentiation Homework Packet

Module 5 Calculus. Module5 CALCULUS 5

Outline. Basic Concepts in Optimization Part I. Illustration of a (Strict) Local Minimum, x. Local Optima. Neighborhood.

Mat 241 Homework Set 7key Due Professor David Schultz

Math 115 Second Midterm November 12, 2018

1998 AP Calculus AB: Section I, Part A

Date Period For each problem, find all points of absolute minima and maxima on the given interval.

Differentiation 9I. 1 a. sin x 0 for 0 x π. So f ( x ) is convex on the interval. [0, π]. f ( x) 6x 6 0 for x 1. So f ( x ) is concave for all x

Chapter Four. Chapter Four

Transcription:

6. Local Etrema of Functions We continue on our quest to etract as much information as possible about a function. The more information we gather, the better we can sketch the graph of the function. This is not the only purpose, such information is essential in applications where there is a need to interpret the behaviour of functions (which usually come from the solutions of comple problems). We now have the necessary tools to study functions it is a matter of organizing the results and relating them to the graphs of the function. We shall begin withsome of the terms used to describe the important features of a function. Several more will be introduced in this chapter. Definition A function f is said to have a stationary point at a if f a. Definition The critical points of a function f areits stationarypoints together with the points whereit is not continuous or not differentiable. The idea is that the critical points compriseall the locations where f has an interesting feature. Eample. What are the critical points of f,? The maimal domain of f is and we find that f so it has a stationary point at & since f 5 and f 5. The point is also a critical point since f is not defined at. Definition A function f is said to have a local minimum at a if its value f a is less than the value of f at all nearby points. By nearby points we mean all points close to a. Definition A function f is said to have a local maimum at a if its value f a is larger than the value of f at all nearby points. Definition A function f is said to have a local etremum at a if it is either a local maimum or a local minimum. The course tet : Calculus by Anton et al., uses the term relative rather than local. A local minumum Eample. Find the local etrema of f. By completing the square, we find f f and, since f we see that f has a local minimum at. Eample. Find the local etrema of f. Again, by completing the square, we find f f and, since f we see that f has a local maimum at. A local maimum

It is quitedifficult, in general, to find local etrema withthesedefinitions (the plurals of maimum / minimum / etremum are maima / minima / etrema, respectively) and weneed more streamlined tools. Theseare provided by using the derivatives of f. Using information from the first derivative We observe from the graphs on the previous page that at a local minimum, f a it is also a stationary point. As increases through the value a, f changes from a decreasing function to an increasing function, i.e., f changes from negative to positive at a local minimum, f a it is also a stationary point. As increases through the value a, f changes from an increasing function function to a decreasing, i.e., f changes from positive to negative This means that we can use the table of signs introduced in the previous chapter to investigate local etrema. Eample. Find the local etrema of f. We first find the stationary points by factorizing f : f and so the stationary points are and.,,, f Direction This table tells us that f is positive to the left of the stationary point at and negative to the right of this point, so the function has a local maimum at. It also tells us that f is negative to the left of the stationary point at and positive to the right of this point, so the function has a local minimum at. The graph of the function shown below confirms these results. 5 5 - - - -5 - -5 Eample 5. Find the local maima and minima of f e /6. We first find the stationary points by factorizing f : f and so the stationary points are and Since e /6 for all values of, we need only consider the algebraic factors and the table of signs is as set out below.,,, f Direction Hence f has a local min. value of f e 6. 5 at,

a local ma. value f e.at.. -8-6 - - 6 8 -. -. -.6 -.8 - -. -. -.6 -.8 - -. -. The net eample is of a slightly different type since the function has a specified domain; in previous eamples the domain was alwaysinterpreted as the maimal domain. Eample 6. Find all local etrema of the function f e sin,,. We first find the stationary points f which factorizes f e Since e for all, the stationary values are given by the equation whose only solution in, is.8.6.. -....6.8...6.8...6.8 -. -.6 -.8 - sin (solid), cos(dashed). Since sin cos for, f on this interval, so f is increasing. On the rest of the interval:, f so the function is decreasing. The picture is completed by noting that both sin and e are positive on the domain. (N.B. sin cos....8.6....8.6.....6.8...6.8...6.8. f e sin,, Functions may not have local etrema It is not unusual for functions not to have local etreme. We show some eamples. Eample 7. Investigate the local etrema of the function f,. Here f f for : f is increasing f for : f is decreasing while there is no point at which f : it has no stationary points. It has a singularity at so it is the only

critical point. Moreover, f for all and there is no point where f : its range is,. We conclude that f has no local minimum and no local maimum: it has no local etrema. We would say that f is bounded below by f. The graph is shown below on the left. 6 6 5 - - Left: f, - - - - Right: f,. Eample 8. Investigate the local etrema of the function f,. Here f f for all : f is decreasing f has a singularity at (which is also a critical point). and it has no stationary points. In this case f as while f as There is no point where f : its range is R\. We conclude that f has no local etrema. We would say that f is unbounded. The graphis shown above on the right. We can now return to some of the eamples in Chapter 5 and deduce the local etrema weleave this as an eercise, the results are tabulated below. Eample Stationary point(s) local ma. local min., y 5,,9, 6,,, 7,,,5, 8 9,,,.7..., 7 7, Using information from the second derivative It the previous eamples we used the fact that the derivative of a function is positive while it is increasing and is negative while the function is decreasing. We now take this a step further. Let us suppose that f has a stationary point at a : f a. Observe that, as increases through a local minimum at a the value of the derivative changes from negative, through zero, to positive values. That is to say, the derivative f increases as passes through a local minimum. This means that its derivative must be positive i.e., f a. Similarly, as increases through a local maimum at a the value of the derivative changes from positive, through zero, to negative values. That is to say, the derivative f decreases as passes through a local maimum. This means that its derivative must be negative i.e., f a. What happens if f a? The answer is, it depends. If f at all points close to a, then we have a local minimum this is an eample of a concave (up) function, f at all points close to a, then we have a local maimum this is an eample of a

concave down (or conve) function f is positive on one side of a and is negative on the other, then f is said to have a point of inflection at a. These rules provide the second derivative test for localmaima & minima and points of inflection. f increasing, f, f is concave up f decreasing, f, f concave down Points of inflection Whether we use this test in preference to the table of signs approach depends on the type of function. If the derivative factorizes into a number of simple factors, the table of signs is generally preferable. Eample 9. Find all the stationary points of f and use the second derivative test to determine their nature.. Here f is differentiable throughout its domain and wehave f 6 Thus the stationary points of f are,. Since f, we find. Stationary points f 6 a local maimum - f 6 a local minimum - f at, which is an inflection point of f. Eample. Use the second derivative test to classify the local etrema of the function f e. What areits inflection points? We first find the stationary points: f e e e so f at and. To classify them, we compute the second derivative so f e e e f this is a ma / min / neither f this is a ma / min / neither The inflection points are where f. These are the roots of, which are. and.. 5

- - - - - Stationary points (dashed) & inflection points (dotted) Eercise. Find the inflection points of the function f e sin,, (see Eample 6). Eercise. Classify the stationarypoints in Eample. Which tests arethe easiestto apply? 6