Review Test 2. MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. D) ds dt = 4t3 sec 2 t -

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1 Review Test MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Find the derivative. ) = sec ) A) = tan B) = csc C) = 7-0 sec tan D) = sec tan ) s = t tan t - t A) ds dt = t sec t tan t + t tan t - C) ds dt = t sec t + t tan t - t t B) ds dt = - t sec t + t tan t + D) ds dt = t sec t - t t ) ) = (csc + cot )(csc - cot ) A) = B) = - csc C) = - csc cot D) = 0 ) ) = sin sin A) d sin - cos 8 cos - 8 sin = d 6 + sin C) d cos - sin 8 sin - 8 cos = d 8 + sin B) d cos + sin 8 sin + 8 cos = d 8 + sin D) d d = cos cos ) 5) p = + sec q - sec q 5) A) dp dq = 6 tan q ( - sec q) B) dp dq = - 6 sin q ( cos q - ) C) dp dq = - sec q tan q ( - sec q) D) dp dq = 6 sin q ( cos q - ) 6) p = sec q + csc q csc q A) dp = sec q tan q dq C) dp dq = sec q + dp B) dq = sec q D) dp = - csc q cot q dq 6)

2 Solve the problem. 7) Find the tangent to = cos at = π. 7) A) = - - π B) = - + π C) = D) = + π 8) Find the tangent to = - sin at = π. A) = - + B) = - + π - C) = - π + D) = - 8) 9) Does the graph of the function = sin have an horizontal tangents in the interval 0 π? If so, where? 9) A) Yes, at = π, = π B) Yes, at = π, = π C) No D) Yes, at = π 0) Find all points on the curve = cos, 0 π, where the tangent line is parallel to the line = -. π A), 0 B) (π, - ) C) (π, ) D) π, 0 0) Find the limit. ) lim 8 cos - 8 ) A) B) 0 C) - D) ) lim π/ + sin(π sec ) ) A) 0 B) C) D) + ) lim π/ sin π + cot cos + sin A) B) - C) D) 0 ) ) lim sec -πt t 0 sin t ) A) - B) - C) 0 D) The equation gives the position s = f(t) of a bod moving on a coordinate line (s in meters, t in seconds). 5) s = + 7 cos t Find the bodʹs speed at time t = π/ sec. A) - 7 m/sec B) 7 m/sec C) - 7 m/sec D) 7 m/sec 5)

3 6) s = + cos t Find the bodʹs jerk at time t = π/ sec. A) m/sec B) - m/sec C) m/sec D) - m/sec 6) Given = f(u) and u = g(), find d/d = f (g())g (). 7) = u, u = - A) - B) - C) D) 6-7) 8) = u(u - ), u = + A) + B) + + C) D) + 6-9) = tan u, u = A) -0 sec (-0 + 6) tan (-0 + 6) B) -0 sec (-0 + 6) C) - sec (-0 + 6) D) sec (-0 + 6) 0) = sin u, u = cos A) - cos(cos ) sin B) cos sin C) - cos sin D) sin(cos ) sin 8) 9) 0) Write the function in the form = f(u) and u = g(). Then find d/d as a function of. ) = ( + 0) 5 A) = 5u + 0; u = 5 ; d d = 0 C) = u 5 ; u = + 0; d = ( + 0)5 D) d B) = u 5 ; u = + 0; d = 0( + 0) d = u 5 ; u = + 0; d = 5( + 0) d ) ) = ) A) = u - u - u; u = 0 ; d d = 80 - B) = u 0 ; u = - C) = u 0 ; u = - D) = u 0 ; u = ; d d = ; d d = ; d d =

4 ) = tan π - 7 ) A) = tan u; u = π - 7 ; d d = 7 sec π - 7 B) = tan u; u = π - 7 ; d d = sec 7 C) = tan u; u = π - 7 ; d d = sec π - 7 D) = tan u; u = π - 7 ; d d = 7 sec π - 7 tan π - 7 ) = cot( - 9) A) = cot u; u = - 9; d = - cot( - 9) csc( - 9) d B) = cot u; u = - 9; d d = - csc ( - 9) C) = cot u; u = - 9; d d = - csc ( - 9) D) = u - 9; u = cot ; d d = - cot csc ) Find the derivative of the function. 5) s = sin 5πt - cos 5πt A) ds 5πt = cos dt C) ds dt = 5π 5πt cos + sin 5πt - 5π sin 5πt B) ds dt = - 5π D) ds dt = 5π 5πt cos 5πt cos - 5π + 5π sin 5πt sin 5πt 5) 6) = 5 (8 + 7) A) = 5 (8 + 7) B) = 8 5 (8 + 7) ) C) = 5 (8 + 7) D) = 5 (8) - - 7) = cos 7 (πt - 0) A) d dt = - 7π cos6 (πt - 0) sin(πt - 0) C) d dt = 7 cos6 (πt - 0) B) d dt = - 7π sin6 (πt - 0) D) d dt = - 7 cos6 (πt - 0) sin(πt - 0) 7)

5 8) q = cos 8t + A) dq dt = - sin 8t + B) dq dt = - sin 8t + 8t + C) dq dt = - dq sin 8t + D) = - sin 8t + 8t + dt 8) 9) h() = cos + sin 9) A) h () = - sin cos cos + sin B) h () = - sin cos C) h () = cos + sin D) h () = - cos ( + sin ) 0) = ( + sin 7t) - A) = - ( + sin 7t) - B) = - (cos 7t) - C) = - ( + sin 7t) - cos 7t D) = - ( + sin 7t) - cos 7t 0) Find. ) = 9 + ) A) B) 9 + C) D) ) = ( - 7) - A) - ( - 7) - B) ( - 7) ) C) - ( - 7)-5 - D) 6 ( - 7)-5 7 ) = cot A) 8 csc C) 0 5 csc 0 cot 0 0 cot 0 B) -8 csc D) - 5 csc 0 0 ) 5

6 ) = tan(0 - ) ) A) sec(0 - ) B) sec (0 - ) tan(0 - ) C) 00 sec (0 - ) tan(0 - ) D) 0 sec (0 - ) 5) = A) B) - 5 (5 + 0) / C) (5 + 0) / D) - 5) Find the value of (f g) at the given value of. 6) f(u) = u -, u = g() =, = 9 u + 6) A) 6 B) 8 C) 9 D) 7) f(u) = u, u = g() = -, = 7) A) B) - C) D) - u 8) f(u) = u -, u = g() = 6 + +, = 0 8) A) 7 5 B) C) 7 5 D) 5 9) f(u) = cos - u, u = g() = π, = u A) π B) - π C) -π D) -π 9) Find an equation for the line tangent to the curve at the point defined b the given value of t. 0) = sin t, = cos t, t = π 0) A) = + B) = - C) = + D) = - + ) = t + cos t, = - sin t, t = π 6 ) A) = - C) = π B) = - - π + 6 π + D) = - + 6

7 ) = csc t, = 6 cot t, t = π ) A) = + B) = - 6 C) = D) = - ) = 6t -, = t 5, t = A) = 5 - B) = 5 + C) = D) = 5 + ) Solve the problem. ) The position of a particle moving along a coordinate line is s = + t, with s in meters and t in seconds. Find the particleʹs velocit at t = sec. A) m/sec B) - m/sec C) m/sec D) m/sec ) 5) The position of a particle moving along a coordinate line is s = 5 + t with s in meters and t in seconds. Find the particleʹs acceleration at t = sec. 5) A) 7 m/sec B) m/sec C) - 7 m/sec D) - 7 m/sec Find the derivative of the function. 6) = 7/5 A) d d = 7 5 6/5 B) d d = 7 5 /5 C) d d = 7 5 -/5 D) d d = /5 6) 7) = 6 A) d d = 6() 5/6 C) d d = - 6() 7/6 B) d d = () 5/6 D) d d = 6() 5/6 7) 8) = 6 + A) d d = + B) d d = + C) d d = - ( + ) / D) d d = - + 8) 9) f() = cos (0 + 6) -/ A) f () = C) f () = - sin - sin (0 + 6)-/ 5 sin (0 + 6)-/ (0 + 6) / B) f () = (0 + 6) / - 5 (0 + 6) / D) f () = - sin (0 + 6) -/ 9) 7

8 50) = (sin ) -/6 cos A) = - 6(sin ) 7/6 B) = 6(cos ) 7/6 cos C) = - 6(sin ) 7/6 D) = (sin ) 7/6 50) 5) = + 6 A) = + 6 B) = + 6 5) C) = + 6 D) = ( + 6) Use implicit differentiation to find d/d. 5) - = A) - B) - C) - D) - 5) 5) + - = + 5) A) ( - ) + - ( - ) B) ( - ) + + ( - ) C) ( - ) - - ( - ) D) ( - ) - + ( - ) 5) + = A) + B) + C) - + D) - + 5) 55) + + = A) B) + - C) - + D) ) 56) cos + 6 = 6 56) A) 65 - sin sin B) 65 - sin 6 5 C) 65 + sin 6 5 D) 65 + sin sin 8

9 57) cos = ) A) 9 - sin 9 sin B) + cos - 9 cos - 9 C) 9 sin D) sin + cos - 9 Use implicit differentiation to find d/d and d /d. 58) - + = A) d d = - + ; d d = - ( + ) B) d d = ; d d = + ( + ) C) d d = ; d d = - ( + ) D) d d = + + ; d d = + ( + ) 58) 59) - + = 6 A) d d = ; d d = + ( + ) B) d d = + + ; d d = + ( + ) C) d d = ; d d = - ( + ) D) d d = - + ; d d = - ( + ) 59) 60) - = 7 A) d d = ; d d = C) d d = ; d d = B) d d = ; d d = D) d d = ; d d = ) 6) - = A) d d = - ; d d = - B) d d = - ; d d = - 6) C) d d = - ; d d = - ( - ) D) d d = - ; d d = ( - ) 6) + =, at the point (, -) A) d d = - ; d d = 0 C) d d = ; d d = - 9 d B) d = ; d d = - D) d d = ; d d = 9 6) 9

10 At the given point, find the slope of the curve, the line that is tangent to the curve, or the line that is normal to the curve, as requested. 6) 5 + = + 0, slope at (0, ) 6) A) - 5 B) C) 0 7 D) 0 6) = 6, slope at (, ) 6) A) B) -8 C) - D) - 65) 5 + = + 0, tangent at (0, ) A) = - - B) = C) = - D) = ) 66) 6 - π cos = 7π, normal at (, π) A) = - π + + π B) = -π + π π 66) C) = π - π + π D) = π - π + π Solve the problem. 67) Find the slope of the curve - 5 = - at (-, ). 67) A) B) - C) - D) ) At the two points where the curve - + = 5 crosses the -ais, the tangents to the curve are parallel. What is the common slope of these tangents? A) - B) C) D) - 68) 69) Find the points on the curve - + = where the tangent is parallel to the -ais. A) (-, -), (, ) B) (-, -), (, ) C) (-, -), (-, ), (, -), (, ) D) (-, -), (-, ), (, -), (, ) 69) 70) Find the normal to the curve + = + that is parallel to the line + = 0. A) = - - B) = - C) = - + D) = + 70) 7) Suppose that the radius r and the circumference C = πr of a circle are differentiable functions of t. Write an equation that relates dc/dt to dr/dt. A) dr dc = π dt dt B) dc dt = π dr dt C) dc dt = dr dt D) dc dt = πr dr dt 7) 7) The area of the base B and the height h of a pramid are related to the pramidʹs volume V b the formula V = Bh. How is dv/dt related to dh/dt if B is constant? 7) A) dv dt = dh dt B) dv dt = B dh dt C) dv dt = B dh dt D) dv dt = dh dt 0

11 7) The kinetic energ K of an object with mass m and velocit v is K = mv. How is dm/dt related 7) to dv/dt if K is constant? A) dm = - mv dv dt dt C) dm dt = - m v dv dt B) dv dt = - m v D) dm dt = m v dv dt dm dt 7) The range R of a projectile is related to the initial velocit v and projection angle θ b the equation R = v sin θ, where g is a constant. How is dr/dt related to dθ/dt if v is constant? g A) dr dt = v sin θ dθ g dt C) dr dt = v cos θ dθ g dt B) dr dt = - v cos θ dθ g dt D) dr dt = v cos θ dθ g dt 7) 75) A compan knows that the unit cost C and the unit revenue R from the production and sale of R units are related b C = Find the rate of change of unit revenue when the unit cost 50,000 is changing b $/unit and the unit revenue is $000. A) $70.00/unit B) $958.80/unit C) $5.0/unit D) $750.00/unit 76) A wheel with radius m rolls at 6 rad/s. How fast is a point on the rim of the wheel rising when the point is π/ radians above the horizontal (and rising)? (Round our answer to one decimal place.) A) 6.0 m/s B) 6.0 m/s C).0 m/s D) 8.0 m/s 75) 76) 77) A piece of land is shaped like a right triangle. Two people start at the right angle of the triangle at the same time, and walk at the same speed along different legs of the triangle. If the area formed b the positions of the two people and their starting point (the right angle) is changing at 5 m/s, then how fast are the people moving when the are m from the right angle? (Round our answer to two decimal places.) A) 5.00 m/s B).50 m/s C) 0.80 m/s D).5 m/s 77) Solve the problem. Round our answer, if appropriate. 78) Water is discharged from a pipeline at a velocit v (in ft/sec) given b v = 778p(/), where p is the pressure (in psi). If the water pressure is changing at a rate of 0.9 psi/sec, find the acceleration (dv/dt) of the water when p =.0 psi. A) 6. ft/sec B) 57 ft/sec C) 50. ft/sec D) 970 ft/sec 79) As the zoom lens in a camera moves in and out, the size of the rectangular image changes. Assume that the current image is 9 cm 6 cm. Find the rate at which the area of the image is changing (da/df) if the length of the image is changing at 0.8 cm/s and the width of the image is changing at 0. cm/s. A) 8. cm /sec B) 6.6 cm /sec C). cm /sec D) 6.8 cm /sec 78) 79)

12 80) Water is being drained from a container which has the shape of an inverted right circular cone. The container has a radius of 6.00 inches at the top and a height of 9.00 inches. At the instant when the water in the container is 7.00 inches deep, the surface level is falling at a rate of 0.6 in./sec. Find the rate at which water is being drained from the container. A) 9. in./s B) 5.7 in./s C).0 in./s D).0 in.s 80) 8) The radius of a right circular clinder is increasing at the rate of 8 in./sec, while the height is decreasing at the rate of 0 in./sec. At what rate is the volume of the clinder changing when the radius is in. and the height is 6 in.? A) -68π in./sec B) -5π in./sec C) -68 in./sec D) in./sec 8) Determine from the graph whether the function has an absolute etreme values on the interval [a, b]. 8) 8) A) Absolute minimum onl. B) Absolute minimum and absolute maimum. C) Absolute maimum onl. D) No absolute etrema. 8) 8) A) Absolute minimum and absolute maimum. B) No absolute etrema. C) Absolute minimum onl. D) Absolute maimum onl.

13 Find the location of the indicated absolute etremum for the function. 8) Minimum 6 5 f() 8) A) = -5 B) = - C) = D) = 5 85) Maimum 5 g() 85) A) = 5 B) = C) = 0 D) No maimum

14 86) Maimum 5 g() 86) A) = B) = - C) = 0 D) No maimum Find the absolute etreme values of each function on the interval. 87) f() = - ; - A) Maimum is 9 at = -; minimum value is - 5 at = B) Maimum is 9 at = ; minimum value is - at = - C) Maimum value is 7 at = ; minimum value is - 5 at = - D) Maimum is 7 at = -; minimum value is - at = 87) 88) f() = + ; - 88) A) Maimum -, 0 and minimum =, 0 B) Maimum =, ; and minimum = -, 0 C) Maimum =, 0 and minimum = -, 0 D) Maimum= -, 0 and minimum =, 0 89) = on [, 8] A) Maimum value is 9 B) Maimum value is 5 C) Maimum value is 5 D) Maimum value is 7 at = ; minimum value is 0 at 8 and 0 at = at = ; minimum value is 0 at 8 and 0 at = at = ; minimum value is 0 at 8 and 0 at = at = ; minimum value is 0 at 8 and 0 at = 89)

15 90) f() = sin + π, 0 7π 90) A) Maimum value of at = π; minimum value of - at = π B) Maimum value of at = π; minimum value of - at = π, C) Maimum value of at = π; minimum value of - at = π, D) Maimum value of at = 0; minimum value of - at = π 9) f() = cos - π, 0 7π 9) A) Maimum value of at = - π ; minimum value of - at = π B) Maimum value of at = - π ; minimum value of - at = - π C) Maimum value of at = π ; minimum value of - at = π D) Maimum value of at = π ; minimum value of - at = π Find the etreme values of the function and where the occur. 9) = + - A) The minimum is at = -. B) The minimum is at =. C) The minimum is - at =. D) The minimum is - at = -. 9) 9) = - + A) Local minimum at (, -). B) None C) Local maimum at (0, ), local minimum at (, -). D) Local maimum at (0, ). 9) 9) = - A) Local maimum at (, 0), local minimum at (-, 0). B) Local maimum at (-, 0), local minimum at (,0). C) None D) Local maimum at (0, -). 9) 8 95) = + A) The maimum value is 0 at = 0. B) The minimum value is 0 at =. The maimum value is 0 at = -. C) The minimum value is 0 at = 0. D) The minimum value is - at = -. The maimum value is at =. 95) 5

16 96) = - 5 A) The maimum is at =. B) The minimum is 0 at =. C) The maimum is at = -. D) The minimum is at = 0. 96) Find the derivative at each critical point and determine the local etreme values. 97) = / ( - ); 0 A) Critical Pt. derivative Etremum Value = 0 = maimum minimum ) B) Critical Pt. derivative Etremum Value = 0 Undefined local ma 0 = minimum C) Critical Pt. derivative Etremum Value = 0 Undefined local ma = minimum D) Critical Pt. derivative Etremum Value = 0 Undefined local ma 0 = minimum Solve the problem. 98) A carpenter is building a rectangular room with a fied perimeter of 60 ft. What are the dimensions of the largest room that can be built? What is its area? A) 5 ft b 5 ft; 9,675 ft B) 0 ft b 0 ft; 5,900 ft C) 5 ft b 5 ft;,5 ft D) 6 ft b ft; 9,0 ft 98) Using the derivative of f() given below, determine the intervals on which f() is increasing or decreasing. 99) f () = (7 - )(8 - ) A) Decreasing on (7, 8); increasing on (-, 7) (8, ) B) Decreasing on (-, 7) (8, ); increasing on (7, 8) C) Decreasing on (-, 7); increasing on (8, ) D) Decreasing on (-, -7) (-8, ); increasing on (-7, -8) 99) Find the largest open interval where the function is changing as requested. 00) Increasing f() = - 00) A) (-, ) B) (-, ) C) (-, -) D) (, ) 0) Increasing = ( - 9) A) (-, 0) B) (, ) C) (-, 0) D) (-, ) 0) 6

17 0) Increasing f() = + A) (-, 0) B) (0, ) C) (, ) D) (-, ) 0) 0) Decreasing f() = - A) (, ) B) (-, ) C) (-, -) D) (-, ) 0) 0) Decreasing = + 7 0) A) (-7, 7) B) (0, ) C) (7, ) D) (-7, 0) 05) Decreasing f() = - + A) (-, ) B) (-, ) C) (-, -) D) (, ) 05) Determine the location of each local etremum of the function. 06) f() = A) Local maimum at ; local minimum at B) Local maimum at -; local minimum at - C) Local maimum at -; local minimum at - D) Local maimum at ; local minimum at 06) 07) f() = A) Local maimum at -; local minima at - and B) Local maima at and -; local minimum at - C) Local maima at - and ; local minimum at - D) Local maimum at -; local minimum at 07) 08) f() = A) Local maimum at - B) Local minimum at - C) No local etrema D) Local maimum at -; local minimum at 08) Identif the functionʹs etreme values in the given domain, and sa where the are assumed. Tell which of the etreme values, if an, are absolute. 09) f() = - 8, - < 8 09) A) Local minimum: (8, 0); Local and absolute maimum: (, -6) B) Local and absolute minimum: (, -6); Local maimum: (8, 0) C) Local and absolute minimum: (, -6); Local and absolute maimum: (8, 0) D) Local minimum: (, -6); Local and absolute maimum: (8, 0) 7

18 0) g(t) = t -.5t + t, 0 t < 0) A) Local minimum:, 6 ; Local maimum:, - 8 ; Absolute maimum:, - 8 B) Local minimum:, 6 ; Local maima: (0, 0) and, - 8 ; Absolute maimum:, - 8 C) Local minima: (0, 0) and, - 8 ; Local maimum:, 6 ; Absolute minimum:, - 8 D) Local minimum:, - 8 ; Local maimum:, 6 ; Absolute minimum:, - 8 Use the graph of the function f() to locate the local etrema and identif the intervals where the function is concave up and concave down. ) ) A) Local minimum at = +; local maimum at = -; concave up on (0, ); concave down on (-, 0) B) Local minimum at = +; local maimum at = -; concave down on (-, ) C) Local minimum at = +; local maimum at = -; concave up on (-, ) D) Local minimum at = +; local maimum at = -; concave down on (0, ); concave up on (-, 0) 8

19 ) ) A) Local minimum at = ; local maimum at = - ; concave up on (0, ); concave down on (-, 0) B) Local minimum at = ; local maimum at = - ; concave down on (-, -) and (, ); concave up on (-, ) C) Local minimum at = ; local maimum at = - ; concave down on (0, ); concave up on (-, 0) D) Local minimum at = ; local maimum at = - ; concave up on (-, -) and (, ); concave down on (-, ) ) 0 ) A) Local minimum at = +.9,; local maimum at = -.9; concave down on (0, ); concave up on (-, 0) B) Local minimum at = +.9,; local maimum at = -.9; concave up on (0, ); concave down on (-, 0) C) Local minimum at = +.9,; local maimum at = -.9; concave up on (-, -.9) and (.9, ); concave down on (-.9,.9) D) Local minimum at = -.9,; local maimum at = +.9; concave up on (-, -.9) and (.9, ); concave down on (-.9,.9) Sketch the graph and show all local etrema and inflection points. 9

20 ) f() = + 9 ) A) Local minimum: (-,- ) Local maimum: (,) Inflection point: (0,0) B) Maimum: (0, 8 ) No inflection point

21 C) Local minimum: (,-) Local maimum: (-,) Inflection point: (0,0) D) Local minimum: (-,-) Local maimum: (,) Inflection point: (0,0), (-, -6 ),(, 6 ) ) f() = + 5)

22 A) Min: (0,0) Inflection points: - 9,, 9, B) Min: 0,- No inflection point C) Min: (0,0) No inflection point D) Min: 0, No inflection point ) f() = + cos, 0 π 6) -

23 A) Local minimum: π, - ; local maimum: π, Inflection point: π, - B) Local minimum: 5π, 5π - 6 ; local maimum: Inflection points: π, π and π, π π, π C) Local minimum: (., -0.6); local maimum: (0.6,.0) Inflection points: (0.785, 0.9) and (.56,.78) -

24 D) No local etrema. Inflection point: π, π - 7) f() = /( - 5) 7) A) Min: (0,0) No inflection points

25 B) Local ma: (0,0), min: ± 08, - 5 Inflection points: ±6, C) No etrema Inflection point: (0,0) D) Local ma: -6, 6 6, min: 6, -6 6 Inflection point: (0,0)

26 Answer Ke Testname: REVIEW CALCULUS TEST ) D ) C ) D ) C 5) D 6) B 7) B 8) C 9) A 0) A ) A ) B ) C ) D 5) B 6) A 7) B 8) C 9) B 0) A ) B ) C ) A ) C 5) D 6) C 7) A 8) C 9) D 0) D ) D ) B ) C ) C 5) B 6) B 7) B 8) B 9) D 0) B ) C ) B ) A ) D 5) C 6) B 7) A 8) A 9) B 50) A 6

27 Answer Ke Testname: REVIEW CALCULUS TEST 5) D 5) C 5) A 5) C 55) D 56) A 57) D 58) A 59) D 60) B 6) D 6) C 6) D 6) C 65) B 66) D 67) C 68) C 69) A 70) C 7) B 7) C 7) C 7) D 75) D 76) B 77) B 78) A 79) B 80) C 8) B 8) D 8) A 8) C 85) C 86) D 87) C 88) B 89) B 90) D 9) C 9) D 9) C 9) D 95) D 96) D 97) D 98) C 99) A 00) D 7

28 Answer Ke Testname: REVIEW CALCULUS TEST 0) B 0) A 0) B 0) B 05) A 06) B 07) A 08) C 09) B 0) C ) A ) A ) B ) D 5) A 6) B 7) D 8

MATH 150/GRACEY EXAM 2 PRACTICE/CHAPTER 2. MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

MATH 150/GRACEY EXAM 2 PRACTICE/CHAPTER 2. MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. MATH 0/GRACEY EXAM PRACTICE/CHAPTER Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Find the indicated derivative. ) Find if = 8 sin. A) = 8