OR Angle QCD = 54 Angle ACP = = 50 x =
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1 MA Practice Tests Set : Paper H (Regular) mark scheme Version.0 Angle BAC = 76 Angle BAP = = 6 x = 76 6 Angle QCD = Angle ACP = = 0 x = o B f Angle BAC = 76 (could be just on the diagram) 76 ( ) A f x = 0 (explicitly stated) C (dep on M) f the sum of the angles of a triangle is 80 and alternate angles on parallel lines are equal B f Angle QCD = (could be just on the diagram) ( ) A f x = 0 o (explicitly stated) C (dep on M) f cresponding angles on parallel lines are equal and sum of the angles on a straight line is 80 o and the sum of the angles of a triangle is 80 o cresponding angles on parallel lines are equal and exteri angle of a triangle is equal to the sum of the two interi opposite angles angle QCB = 80 (=6) A f x = 0 o (explicitly stated) C (dep on M) f sum of allied angles = 80 and the sum of the angles of a triangle is 80 MA Practice Tests: Set Regular (H) mark scheme Version.0 This publication may only be reproduced in accdance with Pearson Education Limited copyright policy. 6 Pearson Education Limited.
2 MA Practice Tests Set : Paper H (Regular) mark scheme Version attempt to find the LCM of and eg at least crect multiples of and at least crect multiples of fact trees with at least one crect A f 7 at least one of "7" "7" either unassociated associated with the crect pack p. M f attempt to find the number of packs of cups and plates eg sight of ( ) 7 ( ) A f ( ) and 7 ( ) p MA practice test paper H (Set ) mark scheme: Version.0
3 MA Practice Tests Set : Paper H (Regular) mark scheme Version.0 (a) (b) B f oe fraction 8 ( + 9) (= 6) (a) (= ) 8 ( + 9) 9 oe (c) e.g. 6 green crect method to find twice as many green beads as red beads, e.g. 0 (= 60) (8 ) + 6 (= 60) Katie spends me A f 6 (green) if n reds are added then n + 6 (greens), where n and n could be numbers 0 (red) and 60 (green) C (dep on M) f showing crect relevant wking and clear conclusion stating number of green beads stating total numbers of red beads and green beads A f. C (dep on M)f conclusion ft from comparison of two percentages.(0) +. f 0% =.(0), % =., 00 A f 6.7 C (dep on M)f crect ft from comparison of 6.7 and 8. MA practice test paper H (Set ) mark scheme: Version.0
4 MA Practice Tests Set : Paper H (Regular) mark scheme Version.0 Jan x Feb x Mar x + 0 Apr (x + 0) x x x 0 x 0 6x+ 8 a method to express all months amounts algebraically (at least crect, ft) Mf an expression f total with at least crect terms added a crect inequality stated algebraically an inequality reduced to ax > b - c NB: accept inequalities written as equations SC T&I is marks f 8, otherwise 0 marks MA practice test paper H (Set ) mark scheme: Version.0
5 MA Practice Tests Set : Paper H (Regular) mark scheme Version π = 9. π (= 78.(9 )) π 0 (= (.9 )) 00π π 0 (= 7(.07 )) 0π M (dep on at least one of the previous Ms) f 0 M (dep on previous M) f ( 0 ) ' ' '78...' π/ A f answer in range π (= 78.(9 )) π 0 (= (.9 )) 00π π 0 (= 78.(98 )) π (= 9.(69 )).π M(dep on previous Ms) f A f answer in range MA practice test paper H (Set ) mark scheme: Version.0
6 MA Practice Tests Set : Paper H (Regular) mark scheme Version.0 7 explanation C f he has not expanded the brackets crectly oe 8 (a) M oe (b) (i) (ii) M oe a complete method f compound interest year on year M oe a complete method not using a multiplier M.088 M ( ) 00 M seen M ( -)x00 MA practice test paper H (Set ) mark scheme: Version.0 6
7 MA Practice Tests Set : Paper H (Regular) mark scheme Version.0 9 (a) (x + )(x + ) = 00 6x + x + x + = 00 (b) (x + )(x 7) (= 0) x =. (Area =) 6. (.) (. ) 6x + 7x 98 = 0 M (x + )(x + ) = 00 (x x) + (x + ) + x = 00 oe (x x) + ( x ( )) + ) + x + + = 00 oe 7. Other partitions are acceptable but partitioning must go on to fm a crect equation. A Accept 6x + 7x + = 00 if M awarded M f (x + )(x 7) (= 0) x x 7 0 If not M then (x ±)(x ± 7) x condone + in place of ± and sign err. 7 9 A Dependent on at least M Igne negative root. Mft Dependent on at least M and x > 0 Dependent on first M MA practice test paper H (Set ) mark scheme: Version.0 7
8 MA Practice Tests Set : Paper H (Regular) mark scheme Version.0 0 (a), 6, B cao f all (B f any crect) (b) Quadratic graph B f a fully crect graph B f all 7 points ft on (a) plotted crectly ± sq B f a smooth curve through all 7 of their plotted points depending on at least B in (a) (c) Draw y = 0.,.7 B f ft from graph ± square B f.6.8 ft from graph ± square (SC: If no marks earned then B f line y = drawn) recognising that 88% is equivalent to oe MA practice test paper H (Set ) mark scheme: Version.0 8
9 MA Practice Tests Set : Paper H (Regular) mark scheme Version.0 DC 8 ; DC 89 DB 0 ; DB BC 8 0 ; BC cos CDB 89 = M DC ) 8 89 ( DC = 9.() M ( DB ) 0 DB =.(8) M M BC ) ( '89' ' ' ' 6' cos CDB ' 89' ' ' A BC =.8() M crect sub into cosine rule on fmula sheet ' 6' '89' ' ' M crect rearrangement to A '89' ' ' cos x '89' ' ' ' 6' cos CDB ' 89' ' ' MA practice test paper H (Set ) mark scheme: Version.0 9
10 MA Practice Tests Set : Paper H (Regular) mark scheme Version.0 (x + ) = x + 6 (x + ) = x + 6 x + 6 = (x + 6) x + 8 = x + x = 6 ⅓ a crect expression f at least one perimeter. x + 6 = (x + 6) oe x + 8 = x + x + 6 = 8x + oe A f B ft f + M f x + = (x + ) x + = 6x + 8 x + = x + 8 oe A f B ft f + T&I B f. better MA practice test paper H (Set ) mark scheme: Version.0 0
11 MA Practice Tests Set : Paper H (Regular) mark scheme Version.0 80 B f (could be seen in wking on a tree diagram) A f oe 0.8(...) B f 8 8 A f oe 0.8(...) (continued overleaf ) MA practice test paper H (Set ) mark scheme: Version.0
12 MA Practice Tests Set : Paper H (Regular) mark scheme Version.0 (co nt) B f A f oe 0.8(...) 80 NB if decimals used they must be crect to at least decimal places SC : with replacement B f oe 0 e.g. B0 A MA practice test paper H (Set ) mark scheme: Version.0
13 MA Practice Tests Set : Paper H (Regular) mark scheme Version.0 x x sin sin M x sin 60( 6) ab sin 60( 6) Or M x x x (= 6) 7 x sin 60 A ab sin 60 6 x 0.7 *6 (n + )(m + ) = nm + n + m + = (nm + n + m) + Proof n + oe used to describe an odd number A f product = nm + n + m + where n is not the same as m C (dep on M) f stating that (nm + n + m) is even since it is a multiple of so adding gives an odd number MA practice test paper H (Set ) mark scheme: Version.0
14 MA Practice Tests Set : Paper H (Regular) mark scheme Version splitting curve appropriately to find area complete area calculation e.g. + ( + 0) + (0 + ) + ( + ) + (b) 8 70 = n.66( ) = 70 n. 00 overestimate with reason 60 A f answer in range 6 8 C f overestimate and appropriate reason linked to method, e.g. area between trapeziums and curve is also included M = oe 70 n ( oe.% seen (= 8) (= ) ( ) seen ) A 60 cao C f a crect mathematical assumption eg population hasn t changed overnight sample is random, etc. MA practice test paper H (Set ) mark scheme: Version.0
15 National perfmance data from Results Plus Source of questions Mean sce of students achieving grade: Qu Spec Paper Session Qu Topic Max sce Mean % all ALL A* A B C D E MM F 06 Q Angles AM H Q6 Money calculations MM H Q Probability AM H Q07 Percentages AM H Q Solve inequalities MM H Q Area of a circle NEW Solving linear equations No data available 8a AM H 6 Q6a Compound interest b AM H 6 Q6bi Compound interest No data available 9 MA0 H 0 Q8 Solve quadratic equations F 8 Q8 Graphs of quadratic equations H 9 Q Reverse percentages H 7 Q Pythagas in D AM H Q Solve linear equations MA0 H 6 Q Ratio H 7 Q Trigonometry MM H 06 Q Algebraic proof AM H 06 Q Area under a graph MB0 H Q Estimating populations 0.8 No other data available 80 MA practice test paper H (Set ) mark scheme: Version.0
4 M1 for a correct method to find of 40; eg (= 16) A1 39. M1 for 1
1 4 M1 f a crect method to find of 40; eg. 40 (= 16) 39 80 f a crect method to find 8 of 40; eg. 40 8 (= ) M1 f a crect method to find of 40 and 8 of 40 M1 (dep on M1) f 80 "16" "" (= 39) = A1 OR 39 80
More information(b) M1 for a line of best fit drawn between (9,130) and (9, 140) and between (13,100) and (13,110) inclusive
1 4 3 M1.1 (= 4) or.1. (=.13 ) 1 4 3 4. 1 4 3 4 4 4 3 + 9 = 11 11 = 1MA1 Practice Tests: Set 1 Regular (H) mark scheme Version 1. This publication may only be reproduced in accordance with Pearson Education
More informationM A1. 4 M1 for listing at least three multiples for any two of 25, 12, (i) 24
MA Practice papers Set : Paper H (Regular) mark scheme Version.0. 3 M 500 (00 00) (=0.5) 87 A M 8 0.5. (i) 4 50 75 4 M for listing at least three multiples for any two of 5,, 8 M for listing at least three
More information1 B1 cao. (c) reason 1 B1 for a valid reason that demonstrates the understanding that the number of triangles is twice the pattern number
1. 13 0 1 B1 cao 2. 64 1 B1 cao 3. 8 1 B1 cao 4. 2401 1 B1 cao 5. (a) 8, 10 1 B1 cao (b) 24 1 B1 cao (c) reason 1 B1 for a valid reason that demonstrates the understanding that the number of triangles
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1MA1 Practice papers Set : Paper H (Regular) mark scheme Version 1.0 1. 9.1 M1 use of cos. 000 1.05 = 000 1.105 000 1.05 = 100 100 1.05 = 05 M1 cos ("x") = (= 0.87 ) or ("x" =) cos 1 ( ) or M for sin and
More information1MA1 Practice papers Set 3: Paper 2H (Regular) mark scheme Version 1.0 Question Working Answer Mark Notes M1 use of cos
1. 9.1 M1 use of cos. 000 1.05 = 000 1.105 000 1.05 = 100 100 1.05 = 05 M1 cos ("x") = (= 0.87 ) or ("x" =) cos 1 ( ) 05 M 000 1.05 or M for sin and following correct Pythagoras or M for tan and following
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1. 1.85 5 9 = 3.33 2 M1 for 1.85 5 or 1.85 9 or 0.37 or 16.65 or 333 seen 2. (a) 37 1 B1 cao 3. (a) (i) (b) a 1 B1 cao NB Working can be in or p (1, 2) 2 B1 (allow (x = 1,y = 2) (ii) ( 4, 3) B1 (allow
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1. (i) 9 1 B1 (ii) 19 1 B1 (iii) 7 1 B1. 17 5 = 1 1 = x + 5 = 17 x = 17 5 6 3 M1 17 (= 8.5) or 17 5 (= 1) M1 for correct order of operations 5 then Alternative M1 for forming the equation x + 5 = 17 M1
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