BRANE COSMOLOGY and Randall-Sundrum model
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1 BRANE COSMOLOGY and Randall-Sundrum model M. J. Guzmán June 16, 2009
2 Standard Model of Cosmology CMB and large-scale structure observations provide us a high-precision estimation of the cosmological parameters: Ω tot 1, Ω m 0.27
3 Standard Model of Cosmology CMB and large-scale structure observations provide us a high-precision estimation of the cosmological parameters: Ω tot 1, Ω m 0.27 we need Ω Λ 0.73
4 Standard Model of Cosmology CMB and large-scale structure observations provide us a high-precision estimation of the cosmological parameters: Ω tot 1, Ω m 0.27 we need Ω Λ 0.73 But, we have Flatness problem
5 Standard Model of Cosmology CMB and large-scale structure observations provide us a high-precision estimation of the cosmological parameters: Ω tot 1, Ω m 0.27 we need Ω Λ 0.73 But, we have Flatness problem Small-scale inhomogeneity
6 Standard Model of Cosmology CMB and large-scale structure observations provide us a high-precision estimation of the cosmological parameters: Ω tot 1, Ω m 0.27 we need Ω Λ 0.73 But, we have Flatness problem Small-scale inhomogeneity Large-scale smoothness
7 Standard Model of Cosmology CMB and large-scale structure observations provide us a high-precision estimation of the cosmological parameters: Ω tot 1, Ω m 0.27 we need Ω Λ 0.73 But, we have Flatness problem Small-scale inhomogeneity Large-scale smoothness Cosmological constant
8 Standard Model of Cosmology CMB and large-scale structure observations provide us a high-precision estimation of the cosmological parameters: Ω tot 1, Ω m 0.27 we need Ω Λ 0.73 But, we have Flatness problem Small-scale inhomogeneity Large-scale smoothness Cosmological constant Magnetic monopoles
9 Standard Model of Cosmology One of the solutions
10 Standard Model of Cosmology One of the solutions INFLATION
11 Standard Model of Cosmology One of the solutions INFLATION When vaccum energy was the dominant component of the energy density of the universe, a(t) grew exponentially. In a time interval t [s] a(t) grows by a factor of e !
12 Brane Cosmology One alternative cosmological model is Brane Cosmology. Embedding our typical 4D space-time in a higher 5D space, and proposing that matter is confined to the brane, yields a model of universe consistent with requirements of General Relativity. Furthermore, it is required a fine-tunning relation between parameters in the brane and the bulk.
13 Randall-Sundrum model Properties of the BULK: Λ 5 : bulk cosmological constant κ 5 : 5D gravitational coupling constant (κ 5 = 8πG (5) )
14 Randall-Sundrum model Properties of the BULK: Λ 5 : bulk cosmological constant κ 5 : 5D gravitational coupling constant (κ 5 = 8πG (5) ) BRANE: σ : brane tension (a constant) The brane is located at y = 0.
15 Randall-Sundrum model Properties of the BULK: Λ 5 : bulk cosmological constant κ 5 : 5D gravitational coupling constant (κ 5 = 8πG (5) ) BRANE: σ : brane tension (a constant) The brane is located at y = 0. 5D spacetime x 0 : time coordinate x i : space coordinates, i = 1, 2, 3 y : additional dimension such that y = y (Z 2 symmetry)
16 Action From an Action, we can derive equations of motion. Einstein-Hilbert Action S H = grd 4 x S = 1 16πG S H + S M Using principle of least action, it is obtained the Einstein Field Equations, R µν 1 2 Rg µν = 8πGT µν
17 Randall-Sundrum model In the Randall-Sundrum model, total action is a sum of the contribution of the bulk (5D space-time) and the brane (4D space-time). S EH = S brane = S = S EH + S brane ( R d 5 x g (5) 2κ 2 5 d 4 x g (4) ( σ) + Λ 5 )
18 Solution of RS model But here things are more complicated, it is not enough to calculate δs = 0... The brane induces a discontinuity in the bulk, which is solved by imposing junction conditions. with G µν the Einstein tensor, G µν K µν K η µν G µν = R µν 1 2 Rg µν K µν is the extrinsic curvature 4-tensor of the brane.
19 Solution of RS model Using these, and proposing the previous ansatz for the metric, ds 2 = e 2K(y) η µν dx µ dx ν + dy 2 yields two equations for the parameters of the bulk and the brane, 6K 2 = κ 2 5Λ 5 3K = κ 2 5σδ(y) ( ) κ 2 5 solving both, we obtain K(y) = 6 Λ 5 y, and 6K (y) y=0 = κ 2 5 σ
20 Solution of RS model Together, the two equations imply Λ 5 = κ2 5 6 σ2 For static solutions to exist, a fine-tunning must exist between the brane tension and the bulk cosmological constant. Setting κ 5 1, and writing the bulk metric of the form ds 2 = a 2 b 2 (dt 2 dy 2 ) a 2 δ ij dx i dx j Leads us to ρ + 3ȧ (ρ + p) = 0 a
21 Solution of RS model It is defined dτ = abdt, ah = da/dτ, a = e α(t), ah = da/dτ Playing with the equations, we obtain: H 2 = ρ Λ µ a 4 with µ an integration constant. Splitting energy-density and pressure: ρ = ρ M + σ, p = p M + σ we obtain Friedmann s equation H 2 = 8πG ( 3 ρ M 1 + ρ M 2σ ) + Λ µ a 4
22 Physical considerations Identifying 8πG 3 = σ 18 Λ 4 3 = σ Λ 5 6 and comparing with the fine-tunning relation Λ 5 = κ2 5 6 σ2, we see that Λ 4 = 0. If this is not satisfied, Λ 4 0. From Friedmann s equation, if ρ M σ, H ρ M, instead of H ρ M. It is obtained an expansion rate larger than in the standard model.
23 Physical considerations Another models, more complicated, include a scalar field φ confined to the brane, obtaining inflation in the brane. An interesting possibility, given by more sophisticated models, is a variation in the traditional potencial energy between two masses (confined on the brane): V (r) = G (5) m 1 m 2 r (1 + l 2 ) r 2 + O(r 3 ) with l related to the parameters of the bulk: l = 6 κ 2 5 Λ 5
24 REFERENCES D. Langlois, Prog.Theor.Phys.Suppl.148: ,2003 Bruck et al 2003, arxiv:hep-th/ v1 Papantonopoulos, Lect.Notes Phys. 592 (2002) 458 Randall L, Sundrum R Phys.Rev.Lett Randall L, Sundrum R Phys.Rev.Lett Israel W 1966 Nuovo Cim B44S10 1; Erratum: ibid Nuovo Cim B Battye, Carter, Phys.Lett. B, Volume 509, Issue 3-4, p Kolb and Turner, The Early Universe Sean Carroll, Spacetime and Geometry. Weinberg, Gravitation and Cosmology. Peacock, Cosmological Physics. Misner, Thorne and Wheeler, Gravitation.
25 Thanks :)
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