SCHOLASTIC APTITUDE TEST (SAT) HINTS & SOLUTIONS

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1 NATIONAL TALENT SEARCH EXAMINATION-08-9, UTTAR PRADESH NATIONAL TALENT SEARCH EXAMINATION-08-9, UP SCHOLASTIC APTITUDE TEST (SAT) HINTS & SOLUTIONS Solution PHYSICS 0. [] When object at C image at C Q 5 0. []= = = A T 5 0. [ ] Image is formed at retina 0. [ ] kwh = J 05. [ ] Generator converts mechanical energy to Electrical energy. 06. [] = V C = C = 0 8 m/sec V rated 07. [ ] R rated = P rated = 8 Now V = 0 V ; R = 8 P = R V = 5 Watt [ ] P = = = 5D f [ ] 5 = + = V f u 50 V = 6 cm 0. [] minimum distance to hear echo = 7 m. [] Solar cells are used in satellite.. [] At ºC density is maimum hence volume for same mass is minimum V > V SOL. SAT NTSE STAGE-I-09 PAGE-

2 . [] each resistance after cutting 5 R R When connected in parallel 5 R = 5 R' CHEMISTRY. Ans.() MO formula of amide M M Valency of element M is + So the phosphate of element is + M PO M (PO ) 5. Ans.() Solid CO is also called dry Ice. 6. Ans.() F-have maimum electro negativity 7. Ans.() HgO Hg + O 8. Ans. () HgS is called cinnabar NTSE STAGE-I-07-8 PAGE-

3 9. Ans. () CHO is functional group of ethanal 0. Ans. () ph of water is = 7. Ans. () C H 5 OH ethanol. Ans. () Oalic acid present in tomato. Ans. () 5 ml NaOH neutralize to = 0 ml HCl them 0 ml NaOH neutralize to 0 ml HCl. Ans. () Baking soda = NaHCO 5. Ans. () Displacement reaction 6. Ans. () If aluminium carbide react with water them aluminium hydroide and methane will produce. Al C + H O Al (OH) + CH NTSE STAGE-I-07-8 PAGE-

4 Mathematics 8. P() = =...() = ( 8) = 9 = 9 = + + = 5 + = 5 = =... () Using () & () = + + = = 0 = 8 = 7 Which not in option, so it is bonus 8. y = + y = = 6 = y = a =, b = Which not in option, so it is bonus NTSE STAGE-I-07-8 PAGE-

5 8. A (, ), B (5, ) and C (, y) 5 0 y + = y = 9 = y = 5 (, 5) 8. (i) tan + sin = m tan sin = n (tan sin ) = m. n...() m + n = tan m n = sin (m + n) (m n) = tansin from equ. () sin cos sin = m. n sin cos cosec = n. n tan sin = mn tansin = mn tansin = n.m put tansin = m n m n = n.m = 75 ( ) = 75 5= () ( ) = () ( ) = () equation () + () ( ) + ( ) = 8 ( ) ( ) + 8 = = = = 75. NTSE STAGE-I-07-8 PAGE-5

6 86. = = y = y = = y = + y = = Option (a) 88. Let number of sides = n n 8 = 60 n = 60 8 = 0 n = ( )( )( )( 8) = 6 = P( 6, 8), O(0, 6) OP = ( 6 0)(s 0) = = A B Income 9 Epenses y y Save = Income Epenses 000 = 9 y...() 000 = y... () () () 000 = 9 y 000 = y = NTSE STAGE-I-07-8 PAGE-6

7 = 000 Income of B = = 000 = 8000 Answer not in option. So it is Bonus. 9. Let side of st square = a Let side of nd square = a Area of first square = a Area of second square = a a + a = 68 perimeter p = a p = a (a + a ) = 0 a + a = 0 (a + a ) = 900 a + a + a a = (0 a ) (a ) = 900 a (0 a ) = = a + 0a = 6 a 0a + 6 = 0 a 8a a + 6 = 0 a (a 8) (a 8) = 0 (a ) (a 8) = 0 a = a = 8 Difference 8 = (A ) area of ABC = 8 (A ) area of AEF = NTSE STAGE-I-07-8 PAGE-7

8 A A = BC EF Given EF = 8 = BC = BC BC = = D 6 C 8 A 6 B Area ABC s = 6 8 = 9 = 9 5 = 5 Area of parallelogram = area triangle = Cone radius = height = y Volume = ( ) (y) Cylinder radius = height = y V = () (y) (6)(y) V V 9 y = 8 NTSE STAGE-I-07-8 PAGE-8

9 96. 5 sin = 5 cos = 5 sin = sin cos = 5 5 = Let = y = = y = = y = = 6 9y = 7 = 6 9 y = y = 6 7 = =.. are + + = = Let 5 = y 5 5 = 6 5y + 5 y = 6 5y 6y + 5 = 0 5y 5y y + 5 = 0 5y(y 5) (y 5) = 0 (5y ) (y 5) = 0 y = 5, 5 =, = NTSE STAGE-I-07-8 PAGE-9

HINTS & SOLUTIONS NATIONAL STANDARD EXAMINATION IN JUNIOR SCIENCE (NSEJS)

HINTS & SOLUTIONS NATIONAL STANDARD EXAMINATION IN JUNIOR SCIENCE (NSEJS) NATIONAL STANDARD EXAMINATION IN JUNIOR SCIENCE (NSEJS) DATE : 9--07. (a) 008, 09,.., 9997 a 008 d 0 a n 9997 a n a + (n )d 9997 008 + (n ) 0 8989 (n ) 0 89 n n 90. HINTS & SOLUTIONS CODE : JS-5. (c)...