ANSWERS. mathematical. StUDieS StaNDaRD LeVeL. Peter Blythe Jim Fensom Jane Forrest Paula Waldman de Tokman

Size: px
Start display at page:

Download "ANSWERS. mathematical. StUDieS StaNDaRD LeVeL. Peter Blythe Jim Fensom Jane Forrest Paula Waldman de Tokman"

Transcription

1 O X F O R D I D I p l O m a p R O g R a m m NSWERS mathmatial StDiS StaNDaRD LVL O RS E O M P N I O N Ptr lth Jim Fnsom Jan Forrst Paula Walman Tokman

2 Numr an algra nswrs Skills hk a = ( ) = (. ) (. ) =. = = ( ) (. ). =. = ( )( + ) = ( (. ))(. + ) =. a 7= = + 7 = = 7 ( ) = = = + = ( ) = = = = = or = a % of =..% of = a > > > = =. rmmr that th asolut valu of a numr is alwas gratr than or qual to zro ut nvr ngativ. a = = 7 = = = Eris a i a+ = + = = ii ( a+ ) = ( + ) = iii a = = = iv ( a ) = ( ) = ( ) = i Ys ii Ys iii No iv Ys Eris a + = = = ( or =. ) It is not an intgr. a = = or = oth ar intgrs. a i a = a + + = = ii a = ( ) = = i It is an intgr. ii It is not an intgr. Eris ( or 7. ) Look for th imal pansion of ah of th frations =.... Thrfor th imal pansion of this fration rurs. =.. Thrfor th imal pansion of this fration is finit. Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

3 7 =.... Thrfor th imal pansion of this fration rurs. = Thrfor th imal pansion of this fration rurs. =.. Thrfor th imal pansion of this fration is finit. a a =.. a =..... a =..... a a = a = a = =.. =. =..... = 7 = = a It oul.;.;.;.; t It oul. ;. ;. ;. ; t It oul. 7;. ;. Eris D ithr work out th arithmti man of ths numrs as shown in th ook or look for thir imal pansion. Th numrs ar an Thrfor an. Numrs in twn ma for ampl.;.;. a ( ) whn = an = ( ) = (or.) is a rational numr a Th numrs ar an Thrfor. an.. Numrs in twn ma for ampl.;.;.. i Th numrs ar an ii Thrfor.... an Numrs in twn ma for ampl.;.;. infinit Eris E a It is a right angl triangl. h = +. h =. h =. m h is rational. a r = = m = π = π m is irrational. Eris F a i. <. ii i multipl. <. < mak th sujt of th inqualit + i q =. is solution as <.. t = ii is solution as <. ii q =. is solution as.. t = is not solution as th inqualit is not tru. a i + > > > ii iii > > i iii ii 7 sustitut ah of ths numrs in th inqualitis p Inqualit + > + > π Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

4 Eris G i. = to th narst unit ii iii. = to th narst unit. = to th narst unit iv. = to th narst unit i. = orrt to th narst ii = orrt to th narst iii. = orrt to th narst iv = 7 orrt to th narst i = orrt to th narst. ii = orrt to th narst. iii = orrt to th narst. iv = orrt to th narst. i 7 = orrt to th narst. ii = orrt to th narst. iii = orrt to th narst. iv = orrt to th narst. n whr < n whr < n whr. <. Eris H i.7 =.7 orrt to.p. ii iii. =. orrt to.p.. =. orrt to.p. iv. =. orrt to.p. i.7 =. orrt to.p. ii iii. =. orrt to.p.. =. orrt to.p. iv.7 =. orrt to.p. i. =. orrt to th narst thousanth. ii. =. orrt to th narst thousanth. iii.7 =.7 orrt to th narst thousanth. iv. =. orrt to th narst thousanth.... i ii iii. (.p.) =.7..7 (.p.).7 (.p.) iv orrt to th narst v orrt to th narst ( p + q) p + q =. i. (.p.) ii. (.p.) iii orrt to th narst unit iv orrt to th narst n whr. <. 7 7 n whr. <. Eris I i has signifiant figurs as all non-zro igits ar signifiant an zros twn nonzro igits ar signifiant. ii iii has signifiant figur as trailing zros in a whol numr ar not signifiant.. has signifiant figur as all non-zro igits ar signifiant an zros to th lft of th first non-zro igit ar not signifiant. iv has signifiant figurs as trailing zros in a whol numr ar not signifiant. v has signifiant figurs as all non-zro igits ar signifiant an zros twn non-zro igits ar signifiant. i = ( s.f.) ii iii.7 =.7 ( s.f.). = ( s.f.) iv. =. ( s.f.) i = ( s.f.) ii iii. =. ( s.f.).7 =.( s.f.) iv. = ( s.f.) i 7 = 7 ( s.f.) ii iii. =. ( s.f.) = ( s.f.) iv. =.( s.f.) a =. orrt to signifiant figurs orrt to signifiant figurs. orrt to imal pla. orrt to th narst hunrth π =. a orrt to th narst unit. orrt to.p.. orrt to s.f.. orrt to.p. Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

5 7 a = ( s.f.) a = ( s.f.).7 =.7 ( s.f.) = i.7 ii.7 iii.7 Eris J a = πr a. = πr. p = r r =. p r =. m ( s.f.) = πr. = m ( s.f.) + =. ( s.f.) sustitut th valus of p an q in th formula. ( p+ q) = + ( ) =. ( s.f.) =. m ( s.f.) Eris K a. 7 = = = = = population nsit = = pips. total population lan ara 7 7 population nsit = 77 population nsit population nsit popl pr km Numr of rams = Numr of rams Numr of rams vrag sp = vrag sp =. istan travll tim takn vrag sp vrag sp km h Numr of visitors pr ar = Numr of visitors pr ar Numr of visitors pr ar 7 stimat th ara of th squar using rasonal numrs. ra of squar =.. ra of squar = ra of squar = m Thrfor Ptr s alulation is not orrt. is far iggr than. Eris L a sustitut th valus of a an of in th givn formula. a + =. +.7 =. Prntag rror = v v Prntag rror = E ve %.. % Prntag rror = 7.% ( s.f.) a tual final gra = tual final gra =.7 ( s.f.) Th thr gras roun ar, 7 an. pproimat final gra = pproimat final gra = Prntag rror =. %. Prntag rror =.% ( s.f.) a Eat ara =.. Eat ara =. m Lngth =. m With =. m pproimat ara =. m a r.. Prntag rror =. Prntag rror =.7% ( s.f.) r r = p m r =. m (.p.) = πr = p p =. m ( s.f.) % Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

6 pproimat valu for primtr = m pt valu for primtr =. m Prntag rror =.. Prntag rror = % ( s.f.) Eris M. ; % a numr is writtn in stanar form if it is writtn as a k whr a < an k is an intgr. a =. or. ( s.f.). =. =.. =.. =. First, writ ah numr in stanar form... 7 =. =. Now writ in orr. ;. 7 =. ; =. ;... =.. =... ;. =. ;. =.. Eris N a =.. =.7 7 or.7 7 ( s.f.). =. =.. =. =. a th arithmti man twn a an is simpl a+. rithmti man =. +. rithmti man = rithmti man =. narst million is th narst multipl of = orrt to th narst million or a t =. t =. t q =.. 7 = 7 a = =. ( ) = =. > aus oth hav th sam ponnt for whn writtn in stanar form an. > thrfor th statmnt is tru. i sustitut th valu of in th givn prssion. ii Eris O = = Writ our answr in stanar form =. a km h or km/h kg m or kg/m m s or m/s a i agrams ii ntison iii millimtr iv imtr a km = m = m.7 m =.7 am =.7 am m = m =. m a g = =. kg 7 kg = 7 ag = 7 ag g = hg =. hg a. s =. = ms s = as = as. hs =. s = a 7 mg = 7 = 7. kg = kg orrt to th narst kg. m = km =. km = km orrt to th narst km. g =. mg =. mg Eris P a. m =. m = m. m =. am =. am mm = m = m. m =. mm = mm. km =. hm = hm f m = km =. km a m = m = m. am =. m = m mm = m =. m m = mm =. mm m = am =. am Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

7 f.7 hm =.7 am = 7. am = 7. am ( s.f.) th ara of a squar with si lngth l is l. a ra = l l ra = ra = m m = m =. m th volum of a u with si lngth (or g) l is l. a Volum = l Volum =. Volum =. m or. m ( s.f.). m =. m = m or m ( s.f.) onvrt all th masurmnts to th sam unit.. am =. m ; mm = m ; m =. m 7 m =.7 m. m Thrfor th list from smallst is 7 m ;. m ; m mm ;. am onvrt all th masurmnts to th sam unit.. m ; m =. m. am = m mm =. m m =. m Thrfor th list from smallst is m ;. am ; m ; mm ;. m Eris Q a hang all to sons = h = min = s = s h = min = s = 7 s min = s = s Thrfor h m = s + 7 s + s = s s = (narst ) a hang all to sons = h = min = s = 7 s min = s = s Thrfor min = 7 s + s = 7 s 7 s =.7 s or.7 s ( s.f.) a l = ml = ml. ml =. hl =. hl l = m al = l = l a l = m = m = m. l =. l =. m or. m ( s.f.) hl = l = m = m = m a. m =. l = orrt to th narst unit.. m =. m = m = l =. hl = hl orrt to th narst unit. m = m =. m =. l =. l = l orrt to th narst unit. istan travll vrag sp = tim takn a vrag sp = m min = m tim takn tim takn = istan travll tim takn m m min tim takn = 7 min 7 min = 7 min = s 7 volum of a u = l a Volum =. =.7 m.7 m =.7 m = 7 m a 7 m = 7 l an 7 l < l thrfor l of watr annot pour in this ontainr. Onl 7 l an pour. of m = 7 m 7 m = 7 m = =. ta ups thrfor Mrs an srv up to ta ups. a vrag sp = istan travll km h = tim takn tim takn km tim takn = km km h tim takn =. h or. h ( s.f.) vrag sp = istan travll tim takn vrag sp = km h vrag sp =. km h or 7 km h Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

8 Tim travlling =. h + h +. h =. h rrival tim = +. =. h or : PM Eris R a t = t k 7. t = 7. t = 7. =.. =. orrt to on tnth of gr = + t t = ( ) t = =... =.7 orrt to on tnth of gr a t F = + t F = =.. F = 7 F orrt to th narst gr. t F = + 7 t F = =.. F = F orrt to th narst gr. a t = 7. =. Thrfor K =. or. ( s.f.) hn mans us th pring answr to solv this part qustion. K =. lso t F =. + t F =. + =. Thrfor K =. F or. F ( s.f.) a mak t K th sujt of th formula. t = t K 7. t K = t + 7. mak t th sujt of th formula t t F = t + = ( t ) F Rviw ris Papr stl qustions π. a =.. =.... =. =.. ;. ; ; ;. a kg =. kg i.7 kg = 7 kg ii prntag rror formula Prntag rror = v v E % v Prntag rror = v Prntag rror = E v E ve 7 % % Prntag rror =.7% ( s.f.) a 7 m s = m s m s mans mtrs pr son thrfor th answr from a givs ou th istan travl in son. travls s m m = km = km travls s km travls s km = km km =. km Thrfor th avrag vloit is. km h a Eat wight of on ook = g = kg =. kg. kg =. kg ( s.f.) pt valu =. kg Estimat valu =. kg Prntag rror = v Prntag rror = v E ve... % Prntag rror =.% ( s.f.) % = g a m = m =. m. m =. l of. l = 7. l i. jars 7. Thrfor San pours jars. ii.7 =.7.7 =. Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr 7

9 7 a = = + (. ). + whn =. =.. =. ( s.f.). =. a = i. km =. m = m = = = m ii Primtr = Primtr = m a t = t. 7 F K t F =. 7 t F =. or. ( s.f.) t = t K K. 7 = t K. 7 t K = ( +. 7 ) t F =.7... = orrt to th narst unit a + > + > l = = < p < = >.. =.... > =. >. =. < Thrfor ;. ; a ra = mm 7 mm ra = 7 mm 7 mm = 7 m =.7 m wighs m 7 g on pag wighs. 7 m.7 7 =.777 g =. g ( s.f.). = g g = kg =. kg Rviw ris Papr stl qustions a P rimtr of th fil = + Primtr of th fil = 7 m 7 m = 7 km = 7. km ost of fning th fil = ost of fning th fil =. (.p.) V = =. Prntag rror = v v Prntag rror = E ve % %... Prntag rror =.% ( s.f.) ra of th fil = ra of th fil = m ra of th fil = km =. km a Raius of smiirls = = m Lngth of irumfrn = πr Lngth of irumfrn = π = π Primtr = + π Primtr =.7... m = 7 m orrt to th narst mtr. Numr of laps that Elgr runs total istan run Elgr = primtr of running trak Numr of laps that Elgr runs = Numr of laps that Elgr runs =.7 Thrfor Elgr runs omplt laps aroun th trak. onvrt th istan to km.7... m =.7... km =.7... km avrag sp = istan travll tim takn km h =.7... km tim takn tim takn =.7... km km h tim takn =. h ( s.f.) avrag sp = km h m min m m min = tim takn m m min km m h min tim takn = tim takn =. min ( s.f.) Prntag rror = v v Prntag rror = E ve.. % Prntag rror =.% ( s.f.) % Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

10 a Diamtr =. m Raius =. =. m Volum of on hoolat = πr Volum of on hoolat = π (.) Volum of on hoolat =... m =. m (.p.) first onvrt th masurmnts to m. Raius of linrial o =. mm =. m Volum of linrial o = πr h Volum of linrial o = π (.) Volum of linrial o = m = 7. m (.p.) Numr of hoolats in th o = =. hoolats Volum oupi th hoolats =... =.7... m Volum not oupi th hoolats = volum of o volum oupi hoolats Volum not oupi th hoolats = =. m ( s.f.). m =. mm = mm f. mm Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

11 Dsriptiv statistis nswrs Eris a Disrt ontinuous Disrt Disrt ontinuous f Disrt g ontinuous h ontinuous i ontinuous j Disrt k ontinuous l Disrt a ias Ranom ias Ranom ias Eris Numr of goals Frqun 7 7 Numr of has Frqun 7 7 g Frqun 7 Numr of risps Frqun Numr Frqun 7 7 m =, n = Eris nswrs will pn on with of lass intrvals hosn. Eampl: a Numr Frqun < < 7 < < < < < < < < Numr Frqun < 7 < < 7 < < 7 < 7 7 < < < Numr Frqun < < 7 < 7 7 < < < < < 7 7 < < Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

12 Eris D a lass Lowr ounar ppr ounar Tim (t sons) Lowr ounar ppr ounar. t <.... t <.... t <... Eris E f a Lowr ounaris ar,,,, ppr ounaris ar,,,, 7 f g a Lowr ounar of th thir lass is. an th uppr ounar is. f.... a Lowr ounaris ar.,.,.,., 7.,.,. ppr ounaris ar.,.,., 7.,.,.,. Frqun 7 Lngth (m) a Numr Frqun < < < 7 < < < < 7 7 < < Frqun Numr of tims travl train a Numr of frqun ws < < < < < < 7 < 7 7 < Frqun Numr of ws 7 a Th lowr ounar of th fourth group is. an th uppr ounar is. f Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

13 Numr of visitors Tim (7 + + ) a = ( + ) = So, + = () = 7 = 77 a Zo s total = = Shun s total = 7 = + = () = = 7 + = () = = Eris F a rrang in orr: 7 Mo = Mian = th ntr = 7 7 Man = =.7 ( sf) 7 7 rrang in orr: Mo = Mian =.th ntr = Man = 7 =. ( sf) a rrang in orr: Mian =.th ntr = Mo =. Man = = 7.7( sf) 7 =. rrang in orr: Mian =.th ntr = =. Man = =. a rrang in orr: Mian =.th ntr = =. Man = =. If th mo is thn s = aus w n mor s than othr numrs. If th man is. thn ( t ++) =. + t =. = So, t = Eris G a Moal sor = (it has th highst frqun) Mian = =th ntr = Man = 7 =. 7 a Numr of hilrn = = Highst frqun =, thrfor moal numr of visits = Man = =. a n = ( ) = 7 Man = 7 =.7 7 aus it has th highst frqun. a Man = 7 = =. ( + ) = % aus it has th highst frqun Eris H a t < s GD. S haptr for hlp. a 7 s < s GD. S haptr for hlp. a < Eris I s GD. S haptr for hlp. a N = th total numr of tims = + a = a = = ( ) = = + = Qustions : ll th answrs an ra from th graphs. Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

14 Eris J ll th answrs an ra from th graphs. Eris K ll th answrs an ra from th graphs. Eris L a i rang = = IQR (from GD) = = i rang = = IQR (from GD) = = i rang = = 7 IQR (from GD) =. =. Eris M s GD. S haptr in th ook for hlp. Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

15 Statistial appliations nswrs Skills hk a + h = h = m + = = = = m or 7.7 m ( s.f.) a i sing th mipoint formula. Lt M th mipoint twn an. 7 M =, M = (, ) ii Lt th istan twn an. = ( ) + 7 = ( ) ( ) or. ( s.f.) sing th mipoint formula an st two quations in p an q. q p (.,) = +, + q =. an p Thrfor q = an p = Eris = sing th graint formula. a m = 7 m = m = 7 m = m = 7 ( ) m = m = m = ( 7) a i (, ); (, ) ii m = m = i (, ); (, ) ii m = m = ( ) i (, ); (, ) ii m = m = i (, ); (, ) ii m = ( ) m = i (, ); (, ) ii m = m = ( ) ( ) f i (, ); (, ) m = m = Eris a plot th givn point an thn using that th graint is m = stp fin mor points ling on th lin. stp Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

16 a i m = 7 ii m = graint of = p graint of = graint of = graint of Thrfor p = p = i m = ii m = graint of = t graint of = Thrfor t = t = i m = m = ii graint of = q graint of = Thrfor q q = i m = ( ) ii m = graint of = s graint of = Thrfor s ( ) = s = i m = ( ) m = ii graint of = graint of = r r = = ( ) ( ) r ( ) a ( ) a m = m = a + Thrfor a + quating answr to a to th graint = a + a + = a = a m =. m = t m = t using our answrs to a an. t =. t =. Eris a m = m =. L L L Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

17 if th -oorinats ar th sam thn th lin is paralll to th -ais an if th -oorinats ar th sam th lin is paralll to th -ais. a paralll to th -ais. paralll to th -ais. nithr. a n horizontal lin is paralll to th...-ais. n vrtial lin is paralll to th...-ais. n horizontal lin has graint qual to... zro... If th lin is paralll to th -ais thn -oorinat of an point on that lin will alwas th sam. a =. oth (; ) an(, a) li on th sam lin paralll to th -ais thrfor th hav th sam -oorinat. If th lin is paralll to th -ais thn -oorinat of an point on that lin will alwas th sam. m = oth (m, ) an ( ; ) li on th sam lin paralll to th -ais thrfor th hav th sam -oorinat. Eris D ngativ riproals ar numrs that multipli togthr giv a an ar ngativ riproals. an ar ngativ riproals. an ar ngativ riproals. prpniular lins hav graints that ar ngativ riproals an ar graints of prpniular lins. an ar graints of prpniular lins. a Lt m th graint of a prpniular lin to. m = m = Lt m th graint of a prpniular lin to. m = m = or. Lt m th graint of a prpniular lin to. m = m = Lt m th graint of a prpniular lin to. m = m = Lt m th graint of a prpniular lin to. m = m = ( ) a m = m = 7 Lt m th graint of a prpniular lin to. m 7 = m = 7 m = m = Lt m th graint of a prpniular lin to. m = m = a i ii iii i ii iii Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

18 i ii iii a m = a m = a = m + = + = + = = a i m = ii iii Th point of intrstion with th -ais has th form (, ) = + = Thrfor th point is (, ) Th point of intrstion with th -ais has th form (, ) = + = + m = s answrs to a an to st an quation whr th unknown is a. a = a = 7 a m = m = m = m = = = m t t = t t = t = Eris E a = m + = + = + = = + = m + = + = + = = + = Thrfor th point is i m =, ii = + = Thrfor th point is (, ) iii = + = + = Thrfor th point is, i m = ii = + = Thrfor th point is (, ) iii = + = + = Thrfor th point is (, ) i m = ii = = = Thrfor th point is (, ) iii = = Thrfor th point is, Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

19 a Epan th numrator an writ th whol prssion as a sum. ( ) = = = or =. m =. th -intrpt is, = Th point of intrstion with th -ais has th form (, ) =. =. = Thrfor th point is (, ) a sing th graint formula m = ( ) m = = + = + = = + a m = m = = m+ = + sustitut th graint into th quation = + sustitut P or Q in th quation to fin = = + m = m = or. = m+ =. + =. + = =. + a = m + = + = = + t th -ais th point has =. = + = + 7 a m m m = m m m = thrfor m = = + = m + = m m = = = m + = m m = thrfor m = = WORKED SOLTIONS Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

20 two points from th graph (, ) an (, ) sing th formula m = ( ) m = Or using th graph m = = + = ( ) + = = f two points from th graph (, ) an (, ) m = m = Or using th graph m = = + = = Eris F a Lt (, ) a point on this lin. Sustituting in th graint formula (, ) an (, ). m = = ( ) = + = + = or an multipl of this quation with a,,,. Lt (, ) a point on this lin. Sustituting in th graint formula (, ) an (, ) m = = ( ) = ( ) = + = or an multipl of this quation with a,,,. ( ) m = m = Lt (, ) a point on this lin. Sustituting in th graint formula (, ) an (, ) = ( ) ( ) ( ) = + + = + + 7= or an multipl of this quation with a,,,. (, ) an (,. ) m = m = = ( ) + = + = or an multipl of this quation with a,,,. Mak th sujt of th formula. a Mak th sujt of th formula. + = = + + = = + = = + = = = or =. + = = + = + = + Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

21 a Mak th sujt of th formula. + = + = + = = + or =. + t th -intrpt th -oorinat is. = + = + = Th -intrpt is. = a Point (, ) = = = Whn =, = thrfor th point lis on this lin. Point (, ) = = = Whn = th valu of is not thrfor th point os not li on this lin. Point (, ) = = = Whn =, = thrfor th point lis on this lin. Point D(, ) = = = Whn =, = thrfor th point D lis on this lin. Point E(,) = = = Whn =, th valu of is not thrfor th point E os not li on this lin. Point F(, ) = = = Whn =, = thrfor th point F lis on this lin. = 7= a a = = or a =. t = 7 t = a Point (, ) + = + = = Thrfor point lis on this lin. Point (, ) + = + = = Thrfor point lis on this lin. Point (, ) + = + = = whih is not tru thrfor point os not li on this lin. Point D(, ) + = + = = whih is not tru thrfor point D os not li on this lin. Point E, + = + = = Thrfor point E lis on this lin. + = a + = a = + = + t = t = Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr 7

22 Thr svral was to solv this qustion. On of thm is to hoos on lin an s whih of th onitions sri in th son olumn vrifis. : + = W writ th quation in th form = m+ + = = + = + = + Th graint is an th -intrpt is thrfor it maths with H. : = Th graint is thrfor it is not F an th -intrpt is thrfor it is not E. It is G. : + + = Th -intrpt is. mans that th lin passs through th point (., ). Sustitut (., ) in th givn quation.. thrfor (.,) os not li on this lin. Thrfor it is not E an so it is F. D: = + It is E. Th -intrpt is an whn is. th valu of is. sing th point (, ) = + = = + Points ar ollinar if th li on th sam lin. Putting th oorinats of in th quation of th lin givs = + = Thrfor lis on this lin an, an ar ollinar. Eris G i Vrtial lins hav quations of th form = k = ii Horizontal lins hav quations of th form = k = a us our GD. In th graph mo input oth quations an fi n th intrstion point. mak th sujt of th formula. 7 a + = = + Th graint of L is. Th -intrpt of L is. sustitut into th quation. = + =. t = + t = paralll lins hav qual graints so th graint of L is. if it passs through (, ) thn th -intrpt is. f a m = m = Th intrstion point is (, ). Mtho : writ own oth quations in th form = m+ an thn us th GD as shown in a. + = = an + = Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

23 Th intrstion point is (, ). Mtho : solv th simultanous quations in th quations mo. + = + = + = Th intrstion point is (, ) Th intrstion point is (, ) Mtho : solv th simultanous quations in th GD quations mo. + + = + = + = + = Th intrstion point is ( 7, ). GD. =. + an = Th intrstion point is (, ) Mtho : writ own oth quations in th form = m + an thn us th GD + + = an = + = = + = Th intrstion point is (, ) f Th lins ar = an = Th intrstion point is (, ) Writ th quations in th form = m+ an ompar th graints. L : + + = = an L : + = = + Graint of L = graint of L = Thrfor oth lins ar paralll. a = ( ) = = + an + = = + = + oth graints ar qual an th hav iffrnt -intrpt thrfor ths lins o not mt at an point. Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

24 + = + = ( ) = + an = + Th ar th sam lin (sam graint an sam -intrpt) thrfor th mt at an infinit numr of points. = an = = Th hav iffrnt graints ( an ) an iffrnt -intrpts ( an ) thrfor th mt at onl on point. + = = + an + + = = = + Th ar th sam lin (sam graint an sam -intrpt) thrfor th mt at an infinit numr of points. a Point lis on oth lins. = + (, ) lis on L = + = = Graint of L = = + QR PR PR PQ PQ QR EF ED ED DF DF EF a os ; sin ; tan os ; sin ; tan os ; sin ; tan fin first th missing si. a hp hp i ii iii sin sin os os tan tan opp hp aj hp opp aj opp opp = opp i sin sin opp hp (, ) lis on L = + = = + Eris H ii iii os aj hp os tan tan opp aj Triangl Hpotnus Si opposit Si ajant to X a XZ YZ XY Y Z a R P RQ PR PQ a Q Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

25 a + aj = aj = aj i sin ii iii opp hp sin os os tan tan aj hp opp aj sin tan sin f Eris I tan h h =. ( s.f.) os tan os 7 Sum of th intrior angls of a triangl is. Qˆ Qˆ tan a tan QR PR = QR QR =.7 m ( s.f.) T m Ŝ + + = a Ŝ = os = T T =. m ( s.f.) Z V m S W os. os. =. (.p) tan m m =. (.p) Ẑ + + = a Ẑ = 7 tan VZ VZ =. m ( s.f) L sin. sin. m =. (.p) sin t sin t t =.7 (.p) tan s tan s s =. (.p) Eris J a m R P Q N Mˆ Mˆ 7 os LM LM os M LM =. m ( s.f) a D is right-angl triangl. tan =. m ( s.f.) Primtr of th rtangl D = D + Primtr of th rtangl D = Primtr of th rtangl D = 7. m ( s.f.) Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

26 ra of th rtangl D = D ra of th rtangl D =.... ra of th rtangl D =. m ( s.f.) tan = h 7 a h = 7. m ( s.f.) 7 7 m sin = =. m ( s.f.) 7 os = =. m ( s.f.) Eris K 7 a sin (. ) mans th angl with a sin of. tan os us our GD. a sin (. ) =. tan os a sin. mans th angl with a tangnt of mans th angl with a osin of =. =. sin.. os os. tan tan. a tan = = tan 7. 7 =. =.... =. os R = R = os R =. =.... =. os M =. M = os M =.. =.... =. sin Z = f a Z = sin Z =. Y =.... Y =.. tan J = 7 J = tan J = I = I =.. os F = F = os F =.. E =.... E =. m D tan = m = tan =. Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

27 a E m a 7 a G m os F os F F. J H m m sin H = H = sin H =. I D is a right-angl triangl. tan D D tan D. ( s.f.) m F tan = m = tan m =. m tan = = tan = 7. ( s.f.) a m m sin = = sin =. ( s.f.) Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

28 is th rqust angl. W first fin O whih is half of.. tan O = O =. tan O =.... = O =.... =. tan = a = tan =. 7 m Eris L a 7 m 7 m Th hight of triangl ists (an is prpniular to ). raw th shortr iagonal an rmmr that th two iagonals of th rhomus ist ah othr at right-angls. 7 m. m Lt half of th shortr iagonal.. tan =. = tan = =. m ( s.f.) 7 m 7 m 7 m rop a prpniular to D from. Lt half of. os = 7 =.... m = =.... =. m Primtr of = Primtr of = Primtr of =. 7 Primtr of =. m = m orrt to th narst m. m D 7 m m O. m a DE = DE = m os D = D = os D =7. ( s.f.) a Drop a prpniular from Q to SR. Lt T th point of whr th prpniular an SR mt. ppl Pthagoras in QTR. QT QT QT SP = QT = m ra of PQRS = ( + 7) ra of PQRS = m ossrq = SRQ = os SRQ =. ( s.f.) sin or tangnt an also us. Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

29 a m m m m tan = = tan =. ( s.f.) m m h tan = h m h = m ( s.f.) 7 a sin sin =. D Put all th masurmnts in th sam unit. m. km. km = m tan = = tan =. ( s.f.) i D. m ii (, ) i = ii = D Lt th rquir angl. tan = = tan =. ( s.f.) Eris M m m tan = = tan = 7. 7 a m Lt th hight of th tr. Th = +. tan = = m = +. =. m..7 m km. 7 tan. = =. 7 tan. =. m = s oth an angls ar altrnat intrior angls. Th vrtial istan is th lngth of th si opposit angl (foun in a). Lt th rquir istan. tan = =. km = m (narst mtr) Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

30 Eris N Sustitut into th sin rul formula. a Y X sin 7 = 7 sin = 7sin 7 sin =. 7 km ( s.f.) P m r Q Z m sin = sin = = sin = sin = sin sin =. m ( s.f.) P R r sin = sin Q km Q = Q = r sin r = sin = sin sin r =. 7m ( s.f.) sin = sin 7. sin 7.sin sin. km ( s.f.) sin = sin sin =. m m 7. km Q QR sin QR = R sin = sin sin QR =7. km ( s.f.) Sustitut into th sin rul formula. a m 7 m sin 7 = sin sin = = sin P sin 7 sin 7 =7. ( s.f.) m m sin = sin R sin R = R = sin sin Q R sin R =. ( s.f.) Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

31 Y km using triangl sin sin m ( s.f.) X km Z sin = siny siny = Y = sin sin sin Y = 7. ( s.f.) 7 m Eris O sing osin rul formula a X km Y. 7 km 7 7 os =. km ( s.f.) Z m P m 7 Q m p 7 sin = sin sin = = sin 7 sin 7sin =. ( s.f.) 7 Q m P. m R 7. sin7 = sin R sin7 sin R =. sin7 R = sin. R =. ( s.f.) a X X using triangl X sin = sin X X X sin = sin = sin sin =. m ( s.f.) R p os7 p.7... p.7 m ( s.f.). m.7 m.7..7.os m ( s.f.) In ths ass w ar looking for angls. a m m m os = + os =. 77 P = os (. 77 ) =. ( s.f.) 7. m. m Q. m R os os = = os (. 7...) =. ( s.f.) Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr 7

32 Y km X osa a km km Z osa... a os... a. ( s.f.) m m 7 a osz = + os Z =.... Z = os (....) X. ( s.f.) m J m WORKED SOLTIONS S SJ = + os SJ = = + os = = m ( s.f.) R.7 m. m P SJ =. m ( s.f.) Etn th lin J an raw a prpniular from S to J. m m S 7 m Q PQ = os PQ =.... PQ =7. m ( s.f.) m a Y X m m os X = + os X =. X = os (. ) X =. ( s.f.) km Y X km km Z Z O = O J os7 = = 7. m ( s.f.) os O = + os O =.... O = os.... O = ( s.f.) ( ) a In triangl PQR, PR = os PR =.... PR =. m ( s.f.) ou an appl ithr sin rul or osin rul..... sin =. sin PRQ. sin sin PRQ =.... sin PRQ = PRQ = sin (. 7...) PRQ =. ( s.f.) Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

33 QPR=. QPR=. RPM=. RPM=. sin RPM sin. = 7. h PR 7. + h.... a WORKED SOLTIONS sin... = m (narst m ) = sin =. =. or quivalnt.... = 7. + h Eris P h =. m ( s.f.) s th ara of a triangl formula. a = 7 sin =. km ( s.f.) =. 7. sin = m ( s.f.) a is an isosls triangl = sin =. m a = = = sin =. m Fin first th siz of on angl. a os X = + os X =. X = os (. ) X =.... = sin.... =. km ( s.f.) sin = siny sin siny = sin Y =.... Y = sin (....) Y =.... Z = Z =. ( s.f.) =. = = m 7 a D is a right-angl triangl. D = + D = m or 7. m ( s.f.) in triangl D D m m 7º º = D sin sin7 D = from parts a an. D = =. 7.. sin =. m ( s.f.) sin7 sin D =. 7 m ( s.f.) ra of D = ra of D + ra of D ra of D = ra of D = 7. m ( s.f.) Rviw ris Papr stl qustions a (, ) an (, ) m = m = paralll lins hav th sam graint. = + L passs through (, ) = + or quivalnt forms. a us th graint formula (, ) an (, ) m = m = Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

34 prpniular lins hav graints that ar opposit an riproal. m m = m m = m = m = = + L passs through O (, ) = + = a i lin mts th -ais at th point whr = = + = + = (or.) Point is, ii lin mts th -ais at th point whr = = + = + = Point is (, ) s th two points foun in a an raw th lin. tan. tan α = α = tan α =. ( s.f.) If a point lis on a lin thn its oorinats vrif th quation of th lin. a = + (a, ) lis on L = a + a = = + (., ) lis on L =. + = a us th GD. + = = + an = + Th point is (, ) m tan tan = 7 m ( s.f.) a Sum of th intrior angls of a triangl is. + = = = sin sin sin = sin =. m ( s.f.) = sin =. m ( s.f.) 7 a = = m sing th osin rul, os = os ( ) =. ( s.f.) sin. =. m a O = O = os O = m 7. os O =. O = os (.) O = 7. = sin =. m ( s.f.) Sha ara =.... Sha ara =. m ( s.f.) Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

35 Rviw ris Papr stl qustions a WORKED SOLTIONS.... =. m ( s.f.) Th lngth of th lar is still th sam. P m. m M i D ii D(,) (, ) an (, ) m = m = or D an ar prpniular lins. m m = m = m = us th graint formula = ( ) = ( ) + = f i (, ) an D(, ) ( ) ( ) = + = ii (, ) an (, ) ( ) ( ) = + = g tan D = D = tan D =. ( s.f.) a Lt th lngth of th lar. os = = os = m Lt th hight of th pol. tan = =. m ( s.f.) Nw istan Lt th nw istan +... = =. ( s.f.)... tan... β = tan β =. ( s.f.) a in triangl D, D = + D = m in triangl D, tan D = D = tan D =.7 (.p.) angl D = D =.7 = 7. ( s.f.) In triangl D. = + os 7. = m ( s.f.) i Primtr = Primtr = m ( s.f.) f ii vloit = istan tim. = tim tim =. tim = sons tim = minuts = minuts (narst minut) split th quarilatral in two triangls ra D = ra D + ra D ra D = sin 7. + ra D = m = km =. km. Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

36 Mathmatial mols nswrs Skills hk a =. + whn =, =. h = t whn t =, h = = t t + whn t =, = - a + = =.,. t t = t t = t =.7,. = = =, = a (7, ) (, ) m = = = (, ) (, ) m = = = Eris a Mik Lu Liia Diana a 7 Mrs. rquiza Mr. Gnzr This is a funtion sin ah stunt is in onl on mathmatis lass. Mrs. rquiza Mr. Gnzr Mik Lu Liia Diana This is not a funtion sin ah tahrs tahs two of th stunt. This is a funtion sin ah lmnt of is rlat to on an onl on lmnt of. 7 This is not a funtion sin on lmnt of () is not rlat to an lmnt of. 7 This is a funtion sin ah lmnt of is rlat to on an onl on lmnt of. a i ii iii iv v This is not a funtion sin on lmnt of () is not rlat to an lmnt of. This is not a funtion sin on lmnt of () is not rlat to an lmnt of. This is not a funtion sin on lmnt of () is not rlat to an lmnt of. This is a funtion sin ah lmnt of is rlat to on an onl on lmnt of. This is a not a funtion sin on lmnt of () is not rlat to an lmnt of. a = = = a Funtion Funtion = not a funtion sin ngativ lmnts in th first st ar not rlat to an lmnt in th son st Funtion Eris a i. = 7 ii omain is th st of all ral numrs iii s, sin = is th imag of = Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

37 i ii omain is th st of all ral numrs iii no, sin thr is no solution to th quation = + i ii iii i omain is th st of all ral numrs pt = no, sin thr is no solution to th quation = - ii omain is th st of all non-ngativ ral numrs iii s, = is th imag of = a Fals, thr is no solution to th quation = tru, = for all valus of tru, = + for all valus of tru, = whn = ± tru, = - = f fals, th imag of = is = Eris a = i (, ) = + ii (, ) (, ) no (, ) = = a i {: } ii {: } 7 iii (, ) iv (, ) i {: } ii {: } iii (, ), (, ) iv (, ) i {: } ii {: } iii (, ), (, ) iv (, ) i { : } ii { : } iii no points iv (, ) a i F ii F iii T i F ii T iii F i F ii T iii F i F ii F iii T a = + = Eris D f () = ( ) ( +) a f () = () () = f = 7 = 7 f ( ) = ( )() = = + f ( ) = ( )() = (, ) lis on th graph of f (t) = t t a t (.) = (.). =. () = = () = () = = () = () (n) = n a () = = = () = = 7 (a) = a = a = a i v () = ii v () = m + = m = t = v (t) < for t > Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

38 f () =. ( ) a =.( ) (, ) (,.). ( ) = = = h () = a i h() = ii h( ) = = = = = Eris E a i l = ii w = V = ( )( ) i V () is th volum of th o whn th squars ut from ah ornr hav si lngth m. ii V () = () () () = m iii V (.) = (.) (.). =. m iv No, < 7. sin th with of th ar is onl m a with = = ( ) i () is th ara of th rtangl whn th lngth is m ii () = () = m No, if = th with woul. a = + n () = + () = SD i + n < ii + () =, no iii n <, n <. as. () =. + I() =. + a P() = I() () =. + (. + ) = + P() = + () = 7 D, a loss of 7 D i P() = + () = D ii I() =.() + () = ssuming all ooks hav sam pri, on ook osts I() = D or Eris F a kg = pouns Pouns (l) =. Kilograms (kg) graint =. p () =. p (7) = p () = 7 =. =. f k(7) =. k() =. = S$. a = S$. SGD ($) =. GP ( ) graint =. s () =. s () = s () = 7 p () = = $. a. GP = SD SD ($) =. GP ( ) p () = 7. graint =. u () =. u() = u () =. p () =. f p () = p (77) = k() =. Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

39 Eris G a a Tmpratur ( ) 7 Tim (minuts) º T () = + Lngth of spring (mm) Wight (g) mm g. mm L () =. + T () = +.7º m m g L () =. + Eris H a Flour = s + f Fat = s + f s + f = s + f = s = f = 7 spong aks, 7 fruit aks t + = t + = 7 t = = tals, hairs v + = 7v + = 7 v =. = 7. 7 vans, ars p + t = p + t = p = t = passngr plans, transport plans 7 + = = + = = = = volum, volum Eris I = + (, ) = + (, ) (, ) = + 7 ( 7, ) (, ) Eris J (, ) = ( ), (, ) (, 7) ( ) 7, (, ) = (, ) = (, ) = (, 7) = (, ) = Eris K = ( ) a = (, ) (, ) (, ) = ( + ) a = (, ) (, ) (, ) = = ( ) a = (, ) (, ) (, ) = = ( ) a = (, ) (, ), Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

40 = = ( ) a = (, ) (, ) (, ) = = ( ) a = (, ) (, ), 7 = + = ( + ) a = (, ) (, ) (, ) = + = ( + ) a = (, ) (, ), = ( + ) ( ) a = (, ) (, ) (, ) = ( ) ( + ) a = (, ) (, ) (, ) = ( ) ( ) a = (, ) (, ) (, ) = ( + ) ( ) a = (, ) (, ) (, ) Eris L = + a = no points (, ) = + = ( + ) ( ) a = (, ), (, ) (, ) = + + a = (.7, ), (., ) (, ) = + a = (., ), (., ) (, ) = a = (., ), (., ) (, ) = + 7 a = (., ), (., ) 7 =. + a = no points =. + a = (., ), ( 7., ) Eris M f () = + = ( + ) ( ) a i (, ) ii = iii (, ) iv (, ), (, ) v,,, 7 = + (, ) f () = = ( + ) ( + 7) a i (, 7) ii = iii (, ) iv ( 7, ), (, ) v = (, ) f () = 7 = ( 7) ( + ) a i (, 7) ii = iii (, ) iv (, ), (7, ) v (, ) = 7 f () = = ( ) ( + ) a i (, ) ii = iii, v iv (, ), (, ) = (, ) Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

41 f () = = ( ) ( + ) a i (, ) ii = iii, v iv (, ), (, ) = (, ) f () = + = ( + ) ( ) a i (, ) ii = iii, v iv,, (, ) v Eris N = (, ) (, ) (, ) = (, ) (, ) = + = (, ) 7 f () = + = ( ) ( + ) a i (, ) ii = iii, v = + (, ) iv,, (, ) f () = = ( ) ( + ) = (, ) (, ) (, ) =. (., ) = (, ) (, ) (, ) a i (, ) ii = iii, iv,, (, ) Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

42 (, ) =. (, ) (, ) Eris O f () = + = g () a (, ), (, ) + = + = ( + ) ( ) = = or (Sam as part a) h() = + = + = ( + ) ( ) = = or (, 7), (, ) f () = + a + + = = + = + = ( + ) = = or (, ) (, ) a f () = + g() = + = = ( )( + ) = = or (, ), (, ) f () = + h() = + + = + = ( )( + ) = = or (, 7), (, ) f : rang = { :. } g : rang = { : } = or f () = h() = + = ( )( + ) = = or f (, 7), (, ) a (.,.), (.,.) f () < g(). < <. Eris P f () = a + + = a = = a (, ) = a a = a = a a = a = a = = f () = + g() = a + + = a = = a (, ) = a a = a a = a = = g() = + f () = a + + a = = a (, ) = a + + a + = a + = a a = a =, = f () = + g() = a + + a = = a (, ) = a + + a + = a a = a + = g() = + f () = a + + a = = a (, ) = a + + a + = a = a = = f () = + + g() = a + + a = = a (, ) = a + + a + = a = a = = g() = + + Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr 7

43 f () = a + + a = = a (, ) = a + a = a = a = = f () = + g() = a + a = = a (, ) = a a = a = a = = g() = f () = a + a = = a, a = a = a a = = f () = + g() = a + + a = = (, ) = a + a = g() = + Eris Q a l + w = 7 l + w = l = w = lw = w( w) = w( w) For maimum ara, w =., l =. lngth =. m, with =. m l + w + (w ) = l + w = l =. w = w (. w) For maimum ara, w =., l =. lngth =. m, with =. m H (t) = 7t t a 7 m. m 7 s Eris R For all qustions: intrpt is (, ), horizontal asmptot is = Eris S f () = a (, ) = = f () = a (, ) = f () = = f () = a (, ) = = ( ) a (, ) = p (u) =.u + u a. rials rials units = ( ) Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

44 f () = () + a (, 7) = = () + f () = () a (, ) = = () 7 f () = () + a (, ) = = () + f () = () a (, ) = = () f () =.() + a (,.) = =.() + f () = (.) + a (, ) = = (.) + f () =. + a (, ) = =. + f () = (.) a (, ) = = (.) Eris T f () = () + a (, ) = = () + f () = + a (, ) = = + f () = () + a (, ) = = () + f () = () a (, ) = = () Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

45 f () =.() + a (,.) = =.() + f () =. + a (, ) = f () = () a (, ) = = () Eris f() = +. =. + g() = +. 7 f () = (.) a (, ) = = (.) a (,.) =. v(t) = t a uros = =. v (t) = (.) t v () =. v() =.7 ars M(t) = (.) t f () =. + a (, ) = a M(t) M(t) = (.) t t =. + M = M ()=. g M () = 7.7 M (7) = ars (t) = (.) t f () = (.) + a (, 7) = = (.) + a (t) (t) = (.) t t as for st Jun. ()= m () = 7.7 () =. t = Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

46 k + = an = k +, so = k = T (t) = + () t a T(t) 7 T(t) = + () t t T ()=.7 T (.) =.7 T (.) =.. minuts s t inrass T gts losr to (T = is an asmptot). 7 D (t) = (.) t a SD D () =. SD D () =. D (7) =. 7 ars f () = a (, ) (,.) = a. = a a = =. = + (, a) (, ) a a = + a = = + = = a a =.7 = f() f() = () + rang = { : > } (or f () > ) Eris V a f () = a.77 hours. hours, 7. hours ( ) + = ( ) = = f () Eris W. = + 7 = 7 = = f f () = = = =.7 minuts = 7 =. minuts =, = f () >.7 = + = = =, = = = ±.7 rang is all ral numrs pt { :, } Eris X minimum valu = 7. (whn =.7) 7. ms = + + = =. s,.7 s a v = () = = = = + = + = + For minimum ara, =., =. =. lngth =. m, rath =. m, hight =. m Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

47 a v = h h l l = h + = + l = l = l h h + + = + l = h h = = + f For minimum ara, =.7, h =.7 =. si lngth =.7 m, hight =. m Lt with =, lngth =, hight = h = + h h = viwing ara = h + h + h = h = ( ) maimum viwing ara =.7 = 7 m Eris Y f () = +, a { :, }.. f ()..... f ()... = = = + f () = +, a { :, } f ().. f () 7.. = = Eris Z Skth graphs Rang :.. = + < or. Eris a a, = ( ) = (.,.), (.,.), (.,.7) g() = f() = + =, = Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

48 + = = or. { :, } a (.,.), (.,.) a 7 = g() = f() = =. or. = = solutions = + (., 7.), (.,.), (.,.) = + = (.,.), (.7,.), (.,.) = + = a =. or. = = Eris a tim in hours, watr onsumption in litrs 7 7,, (loal maimum at ) f 7, (loal minimum at ) a tim in minuts, tmpratur in a minut no f approimatl t N s ( ) = = a m. s an. s. s. s 7 s m,. s f all rturns to groun lvl a i. m ii. m iii an < t < a twi f an g no, th tmpratur at th start of th following a is whras it was at th start of this a. 7 a = =. = f ().. = 7 tns to zro Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

49 a m = = = + = + (m) () (m ) (sf ) f =. = + Rviw ris Papr stl qustions a 7 = nr + s a = r + s = r + s r = r = SGD = + s s = SGD a + = ( + ) (, ) (, ) = + (.,.) =. h(t) = t t t a h() = m m from t = to t =, s a f () = m (,.). = f () = (, n) n = f () = = m m =. = a = ( )( + ) i t, = = (, ) 7 a ii ii t, = = (, ) i iii iv a i (.,.) ii (.,.) f () < g (). < <. = a with =. = (. ) a For maimum ara, =. m = = =, = =. Papr stl qustions n = (.) t a, a n n = (.) t t i n = (.). = ii t =. hours = hours mins = Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

50 =, = g() = = ±. { :, } f () = (.) + a a =. = 7. 7 f() = (.) + f () > =. = a (.,.), (., 7.) f =.,. f() = = 7 P = = () + = (.7,.), (.,.), (.,.) + a 7 P f (t) = + 77(.) t a f () = + 77 = = f () =. P = + a f() = g() = (.,.) (, ) a i uros ii iii or 7 iv uros (, 7) (., ) (., ) = 7 (, 7), (., ), (., ) Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

51 a = 7 (., ) (., ) (, 7) = ±. =,,,,, + = ( ) = = or (, ), (, ) = = a = = k = f() = (, ) (, ) g() = + f () < g () < < Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

52 Statistial appliations nswrs Skills hk a man =. stanar viation =. Th small stanar viation implis that th ata ar los to th man man = stanar viation =. Th man is th mil ata valu () sin th frqunis ar smmtrial aout this valu. Th stanar viation is vr small sin most of th ata valus qual th man an th rst ar los to it a = + Eris a a f() = n v n v n σ n n + v n + v n + v 7 Hight (m)... = f() n v n σ n v n n + v n + v n + v 7 Tim (s).%. = a a f() n v n σ n v n n + v n + v n + v Tim (min) %. =. or f() n v n σ n v n n + v n + v n + v Volum (ml). 7. = Eris a f().7 7 Tim (min).7 = 7. or as a i P(IQ < ) =. ii P(IQ > ) =. iii P( < IQ < ) =. P(IQ > ) =.,. = a...7 = 7 a f() Monthl inom (uro).. =.7 or a 7.%.. =. or. 7 a.%. =. or Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

53 man =.7 m stanar viation =. m a. Eris p =. h = k =. w = a.7 to. kg. =. 7.7% w =. a a =, =, =. =.... = (apt to ) 7 a.. t = a f() Sp (km h ).% p =. = 7. = 7 a f() 7 7 Mass (g)... =.7 or 7 p = a.% a wighing. kg (. is narr th man than.).. =. or w =. Eris D a strong positiv linar morat ngativ linar morat positiv linar f g h a wak positiv linar non prft ngativ linar non-linar wak ngativ linar morat positiv linar orrlation morat ngativ linar orrlation Eris E i a, strong positiv orrlation man of =, man of =.7 ii a, strong ngativ orrlation man of =., man of =. a, Wight(kg) Hight (m) morat positiv orrlation man hight =.7 m man wight = kg kg Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

54 a, ITGS(%) 7 7 hmistr (%) wak positiv orrlation hmistr man =. ITGS man =. % a, a ri(hours) a hl (hours) morat ngativ orrlation man numr of hours hl =. man numr of hours spnt ring =.. hours a, ost($) Siz (inhs) morat positiv orrlation man srn siz =. inhs man ost = $ $ Eris F r =., strong positiv orrlation a r =. strong positiv orrlation r =., strong ngativ orrlation r =., strong positiv orrlation r =., strong positiv orrlation r =., vr wak positiv orrlation 7 r =., strong positiv orrlation r =., morat positiv orrlation Eris G a r =., strong positiv orrlation =.7 + =.7 () + =, ( s.f) a r =.7 =. +. =.() +. =.,. m a =. s =. = s =.7 r =. strong ngativ orrlation =.7 + =.7 (7) + = 7., 7 sons a r =.7 =. +. =. () +. =.,. a =.7 +. =.7 (7) +. =.77,. D a =.7 +. =.7 () +. =., situps 7 a =.. =. (). =.7,. a =.7 +. =.7() +. =.,. hours. Eris H a H : Gnr of ook is inpnnt of ag H : Gnr of ook is pnnt on ag 7 =. ( ) ( ) = χ al =.. >., thrfor w rjt th null hpothsis. Thr is nough vin to onlu that gnr of ook is pnnt on ag. ( p-valu =.7 <.) a H : Hair olor an olor ar inpnnt H : Hair olor an olor ar pnnt =.7 ( ) ( ) = χ al =.. > 7.77, thrfor w rjt th null hpothsis. Thr is nough vin to onlu that hair olour an olor ar pnnt. ( p-valu =. <.) Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

55 a H : Favorit flavor is inpnnt of ra. H : Favorit flavor is pnnt on ra. = ( ) ( ) = χ al =.7.7 <., thrfor w o not rjt th null hpothsis. Thr is nough vin to onlu that favourit flavor is inpnnt of ra. ( p-valu =. >.) a H : Film gnr is inpnnt of gnr H : Film gnr is pnnt on gnr =. ( ) ( ) = χ al =.. >., thrfor w rjt th null hpothsis. Thr is nough vin to onlu that film gnr is pnnt on gnr. ( p-valu =.7 <.) a H : Gra is inpnnt of th numr of hours H : Gra is pnnt on th numr of hours =. ( ) ( ) = χ al =.. >., thrfor w rjt th null hpothsis. Thr is nough vin to onlu that gra is pnnt on numr of hours spnts plaing omputr gams. ( p-valu =. <.) a H : Emplomnt gra is inpnnt of gnr H : Emplomnt gra is pnnt on gnr Dirtors Managmnt Tahrs Mal. 7.. Fmal. 7.. ( )( ) = χ al = >., thrfor w rjt th null hpothsis. Thr is nough vin to onlu that mplomnt gra is pnnt on gra. ( p-valu =. <.) 7 a H : mount of sushi sol is inpnnt th a of th wk H : mount of sushi sol is pnnt on th a of th wk =. 7 ( ) ( ) = χ al =.. <., thrfor w o not rjt th null hpothsis. Thr is nough vin to onlu that th amount of sushi sol is inpnnt of th a of th wk. ( p-valu. >.) a H : pupp s wight is inpnnt of its parnt s wight. H : pupp s wight is pnnt on its parnt s wight =. ( )( ) = χ al =..7 >.77, thrfor w rjt th null hpothsis. Thr is nough vin to onlu that a pupp s wight is pnnt on its parnt s wight. a H : Musi prfrn is inpnnt of ag H : Musi prfrn is pnnt on ag 7 =. ( ) ( ) = χ al =.. >., thrfor w rjt th null hpothsis. Thr is nough vin to onlu that musi prfrn is pnnt on ag. ( p-valu =. <.) a H : g at whih a a is pott train is inpnnt of gnr. H : g at whih a a is pott train is pnnt on gnr. =. ( ) ( ) = χ al =.. >., thrfor w rjt th null hpothsis. Thr is nough vin to onlu that th ag at whih a a in pott train is pnnt on gnr. ( p =. <.). Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

56 a H : Gra is inpnnt of gnr H : Gra in pnnt on gnr, or 7 or or Mal... Fmal... ( ) ( ) = χ al =.7.7 <., thrfor w o not rjt th null hpothsis. Thr is nough vin to onlu that gra is inpnnt of gnr. ( p =.7 >.) Rviw ris Papr stl qustions a f() Volum (ml).. =., ans a.%. =., popl a.% p =. a strong positiv orrlation a no orrlation morat ngativ orrlation strong positiv orrlation = = a r =., strong positiv orrlation =. 77. =. (7) 77. =.77,. m 7 a r =., strong positiv orrlation =. +. =. () +. =. sons H : Flavor of i rams is inpnnt of ag H : Flavor of i rams is pnnt on ag Ept valus < < Vanilla... Strawrr... hoolat... grs of from = ( ) ( ) = p-valu =. >., χ al =. W o not rjt th null hpothsis. Thr is nough vin to onlu that flavor of i ram is inpnnt of ag. (ritial valu =., (χ al =. <.) a H : Th numr of pins knok own is inpnnt of whih han is us. ( )( ) = = p-valu =. >. (signifian valu). Thrfor w o not rjt th null hpothsis. Thr is nough vin to onlu that th numr of pins knok own is inpnnt of whih han is us. a H : Th outom is inpnnt of th tim spnt prparing for a tst. ( )( ) = p-valu =. >., thrfor w o not rjt th null hpothsis. Thr is nough vin to onlu that th outom is inpnnt of th tim spnt prparing for a tst. Papr stl qustions a f()..7 7 Hight (m). =., mn k = a f(). 7 Wight (g). = 7., 7 swts Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

57 a, wight( kg) 7 =. = 7. 7 Hight ( m) i =.7. kg a r =. strong positiv orrlation =. +. =.() +. =. = hours (narst hr) a r =. =. (.p.) strong positiv orrlation =.. a r =.7 =. =. (.p.) strong positiv orrlation =. +. =.() +. =.7,. uros 7 a =.. =. (7). =.7, rss siz r =.7 morat positiv orrlation H : hoi of gam is inpnnt of gnr H : hoi of gam pns on gnr Ept valus: aminton Tal tnnis Darts Mal... Fmal... grs of from = ( ) ( ) = χ al =.7 p-valu =.77 >. W o not rjt th null hpothsis. Thr is nough vin to onlu that hoi of gam is inpnnt of gnr. (ritial valu =., χ al =.7 <.) a p =. q =. r =. i H : Th tra-urriular ativit is inpnnt of gnr ii ( )( ) = χ al =.. >., thrfor w rjt th null hpothsis. Thr is nough vin to onlu that tra-urriular ativit is pnnt on gnr. a i = ii = = = H : position in uppr managmnt is inpnnt of gnr H : position in uppr managmnt is pnnt on gnr i χ al =. ii ( )( ) = iii. >., thrfor w rjt th null hpothsis. Thr is nough vin to onlu that position in uppr managmnt is pnnt on gnr. a H : Th hoi of aniat is pnnt on whr th votr livs. 7 = 7 i χ al =. ii ( )( ) = i Th hoi of aniat is pnnt on gnr. ii. >., thrfor w rjt th null hpothsis. a =. i H : Gra is inpnnt of gnr ii ( )( ) = iii χ al =.. <., thrfor w o not rjt th null hpothsis. Thr is nough vin to onlu that gra is inpnnt of gnr Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

58 Introuing iffrntial alulus nswrs Skills hk a f () = 7, f ( ) = f () =, f ( ) = g () =, g g () =, g () = f () =., f ( ) =. a r = r V h =± r V r r f r a = = = = = =± = a a + = ( ) = = ( ) = + Eris a f g h i j k a f g h i 7 j k a + + a Eris a = t t = t t = t + = t = t t = t t t = t + t = t + t = + 7t t = 7 t t f = t t = t t g h = t t + t = t t + t = t t = t t a f (r) = (r ) = f (r) = r f (r) = (r + ) = r + f (r) = (r ) = (r ) = r f (r) = ( r) = ( r) = r f (r) = (r + ) = r + f f (r) = (7 r) = (7 r) = r 7 Eris = f ( ) = = 7 f ( ) = = = 7 f ( ) = g ( ) = g ( ) = + = + g ( ) = + ( ) Eris D = whn =, = () = = whn =, = () = Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

59 = whn =, = ( ) ( ) = = + = + whn =, = ( ) + = = whn =, = () = 7 = whn =, = ( ) = = whn =, = () = = t (, ), = ( ) = 7 s = t t s t t t =, = () = s = t + t s = + t = at t = t t t =, s = + () = 7 t v = 7 t v t W p V r r V r r V r r =.7 h = h. t h =, =.7p. Whn p =, W p r = r r =. Whn r =, V r h =. Whn r =, = r = r +. Whn r =, V r r. Whn r =, = πr + r =. Whn r =, r r = Eris E a = + V r V r. Whn r =, r t P, = + = 7 = = t P, = () + () = + = =.7 = 7 = = = = + = = π at r = = = = = a a 7 = + t Q, t Q, = = t R, = + = = = = = + + = = = = = lso, = + () () = + = So, R = (, ) = t R, = (a) = a = a = lso, = () () = So R is (, ) + = + = whn graint is. = =, = point is (, ) = whn graint is = = = = lso, = ( ) ( ) = = So th point is (, ) = + whn graint is, whn = = + = = = = ± = () + () + = whn = = ( ) + ( ) + = So points ar (, ) an (, ) Ofor nivrsit Prss : this ma rprou for lass us soll for th purhasr s institut Work solutions: haptr

N1.1 Homework Answers

N1.1 Homework Answers Camrig Essntials Mathmatis Cor 8 N. Homwork Answrs N. Homwork Answrs a i 6 ii i 0 ii 3 2 Any pairs of numrs whih satisfy th alulation. For xampl a 4 = 3 3 6 3 = 3 4 6 2 2 8 2 3 3 2 8 5 5 20 30 4 a 5 a

More information

Evans, Lipson, Wallace, Greenwood

Evans, Lipson, Wallace, Greenwood Camrig Snior Mathmatial Mthos AC/VCE Units 1& Chaptr Quaratis: Skillsht C 1 Solv ah o th ollowing or x: a (x )(x + 1) = 0 x(5x 1) = 0 x(1 x) = 0 x = 9x Solv ah o th ollowing or x: a x + x 10 = 0 x 8x +

More information

Numerical methods, Mixed exercise 10

Numerical methods, Mixed exercise 10 Numrial mthos, Mi ris a f ( ) 6 f ( ) 6 6 6 a = 6, b = f ( ) So. 6 b n a n 6 7.67... 6.99....67... 6.68....99... 6.667....68... To.p., th valus ar =.68, =.99, =.68, =.67. f (.6).6 6.6... f (.6).6 6.6.7...

More information

MA1506 Tutorial 2 Solutions. Question 1. (1a) 1 ) y x. e x. 1 exp (in general, Integrating factor is. ye dx. So ) (1b) e e. e c.

MA1506 Tutorial 2 Solutions. Question 1. (1a) 1 ) y x. e x. 1 exp (in general, Integrating factor is. ye dx. So ) (1b) e e. e c. MA56 utorial Solutions Qustion a Intgrating fator is ln p p in gnral, multipl b p So b ln p p sin his kin is all a Brnoulli quation -- st Sin w fin Y, Y Y, Y Y p Qustion Dfin v / hn our quation is v μ

More information

Logarithms. Secondary Mathematics 3 Page 164 Jordan School District

Logarithms. Secondary Mathematics 3 Page 164 Jordan School District Logarithms Sondary Mathmatis Pag 6 Jordan Shool Distrit Unit Clustr 6 (F.LE. and F.BF.): Logarithms Clustr 6: Logarithms.6 For ponntial modls, prss as a arithm th solution to a and d ar numrs and th as

More information

2008 AP Calculus BC Multiple Choice Exam

2008 AP Calculus BC Multiple Choice Exam 008 AP Multipl Choic Eam Nam 008 AP Calculus BC Multipl Choic Eam Sction No Calculator Activ AP Calculus 008 BC Multipl Choic. At tim t 0, a particl moving in th -plan is th acclration vctor of th particl

More information

1997 AP Calculus AB: Section I, Part A

1997 AP Calculus AB: Section I, Part A 997 AP Calculus AB: Sction I, Part A 50 Minuts No Calculator Not: Unlss othrwis spcifid, th domain of a function f is assumd to b th st of all ral numbrs for which f () is a ral numbr.. (4 6 ) d= 4 6 6

More information

Additional Math (4047) Paper 2 (100 marks) y x. 2 d. d d

Additional Math (4047) Paper 2 (100 marks) y x. 2 d. d d Aitional Math (07) Prpar b Mr Ang, Nov 07 Fin th valu of th constant k for which is a solution of th quation k. [7] Givn that, Givn that k, Thrfor, k Topic : Papr (00 marks) Tim : hours 0 mins Nam : Aitional

More information

4. (5a + b) 7 & x 1 = (3x 1)log 10 4 = log (M1) [4] d = 3 [4] T 2 = 5 + = 16 or or 16.

4. (5a + b) 7 & x 1 = (3x 1)log 10 4 = log (M1) [4] d = 3 [4] T 2 = 5 + = 16 or or 16. . 7 7 7... 7 7 (n )0 7 (M) 0(n ) 00 n (A) S ((7) 0(0)) (M) (7 00) 8897 (A). (5a b) 7 7... (5a)... (M) 7 5 5 (a b ) 5 5 a b (M)(A) So th cofficint is 75 (A) (C) [] S (7 7) (M) () 8897 (A) (C) [] 5. x.55

More information

Thomas Whitham Sixth Form

Thomas Whitham Sixth Form Thomas Whitham Sith Form Pur Mathmatics Cor rvision gui Pag Algbra Moulus functions graphs, quations an inqualitis Graph of f () Draw f () an rflct an part of th curv blow th ais in th ais. f () f () f

More information

Partial Derivatives: Suppose that z = f(x, y) is a function of two variables.

Partial Derivatives: Suppose that z = f(x, y) is a function of two variables. Chaptr Functions o Two Variabls Applid Calculus 61 Sction : Calculus o Functions o Two Variabls Now that ou hav som amiliarit with unctions o two variabls it s tim to start appling calculus to hlp us solv

More information

Thomas Whitham Sixth Form

Thomas Whitham Sixth Form Thomas Whitham Sith Form Pur Mathmatics Unit C Algbra Trigonomtr Gomtr Calculus Vctor gomtr Pag Algbra Molus functions graphs, quations an inqualitis Graph of f () Draw f () an rflct an part of th curv

More information

MAXIMA-MINIMA EXERCISE - 01 CHECK YOUR GRASP

MAXIMA-MINIMA EXERCISE - 01 CHECK YOUR GRASP EXERCISE - MAXIMA-MINIMA CHECK YOUR GRASP. f() 5 () 75 f'() 5. () 75 75.() 7. 5 + 5. () 7 {} 5 () 7 ( ) 5. f() 9a + a +, a > f'() 6 8a + a 6( a + a ) 6( a) ( a) p a, q a a a + + a a a (rjctd) or a a 6.

More information

3 a b c km m m 8 a 3.4 m b 2.4 m

3 a b c km m m 8 a 3.4 m b 2.4 m Chaptr Exris A a 9. m. m. m 9. km. mm. m Purpl lag hapr y 8p 8m. km. m Th triangl on th right 8. m 9 a. m. m. m Exris B a m. m mm. km. mm m a. 9 8...8 m. m 8. 9 m Ativity p. 9 Pupil s own answrs Ara =

More information

Objective Mathematics

Objective Mathematics x. Lt 'P' b a point on th curv y and tangnt x drawn at P to th curv has gratst slop in magnitud, thn point 'P' is,, (0, 0),. Th quation of common tangnt to th curvs y = 6 x x and xy = x + is : x y = 8

More information

Math 34A. Final Review

Math 34A. Final Review Math A Final Rviw 1) Us th graph of y10 to find approimat valus: a) 50 0. b) y (0.65) solution for part a) first writ an quation: 50 0. now tak th logarithm of both sids: log() log(50 0. ) pand th right

More information

MATHEMATICS (B) 2 log (D) ( 1) = where z =

MATHEMATICS (B) 2 log (D) ( 1) = where z = MATHEMATICS SECTION- I STRAIGHT OBJECTIVE TYPE This sction contains 9 multipl choic qustions numbrd to 9. Each qustion has choic (A), (B), (C) and (D), out of which ONLY-ONE is corrct. Lt I d + +, J +

More information

First order differential equation Linear equation; Method of integrating factors

First order differential equation Linear equation; Method of integrating factors First orr iffrntial quation Linar quation; Mtho of intgrating factors Exampl 1: Rwrit th lft han si as th rivativ of th prouct of y an som function by prouct rul irctly. Solving th first orr iffrntial

More information

Calculus II (MAC )

Calculus II (MAC ) Calculus II (MAC232-2) Tst 2 (25/6/25) Nam (PRINT): Plas show your work. An answr with no work rcivs no crdit. You may us th back of a pag if you nd mor spac for a problm. You may not us any calculators.

More information

are given in the table below. t (hours)

are given in the table below. t (hours) CALCULUS WORKSHEET ON INTEGRATION WITH DATA Work th following on notbook papr. Giv dcimal answrs corrct to thr dcimal placs.. A tank contains gallons of oil at tim t = hours. Oil is bing pumpd into th

More information

Differentiation of Exponential Functions

Differentiation of Exponential Functions Calculus Modul C Diffrntiation of Eponntial Functions Copyright This publication Th Northrn Albrta Institut of Tchnology 007. All Rights Rsrvd. LAST REVISED March, 009 Introduction to Diffrntiation of

More information

Math 61 : Discrete Structures Final Exam Instructor: Ciprian Manolescu. You have 180 minutes.

Math 61 : Discrete Structures Final Exam Instructor: Ciprian Manolescu. You have 180 minutes. Nm: UCA ID Numr: Stion lttr: th 61 : Disrt Struturs Finl Exm Instrutor: Ciprin nolsu You hv 180 minuts. No ooks, nots or lultors r llow. Do not us your own srth ppr. 1. (2 points h) Tru/Fls: Cirl th right

More information

MSLC Math 151 WI09 Exam 2 Review Solutions

MSLC Math 151 WI09 Exam 2 Review Solutions Eam Rviw Solutions. Comput th following rivativs using th iffrntiation ruls: a.) cot cot cot csc cot cos 5 cos 5 cos 5 cos 5 sin 5 5 b.) c.) sin( ) sin( ) y sin( ) ln( y) ln( ) ln( y) sin( ) ln( ) y y

More information

Solutions to Homework 5

Solutions to Homework 5 Solutions to Homwork 5 Pro. Silvia Frnánz Disrt Mathmatis Math 53A, Fall 2008. [3.4 #] (a) Thr ar x olor hois or vrtx an x or ah o th othr thr vrtis. So th hromati polynomial is P (G, x) =x (x ) 3. ()

More information

Trigonometry. Contents. Syllabus subject matter

Trigonometry. Contents. Syllabus subject matter Trigonomtry 2 ontnts 2.1 ythagoras s Thorm 2.2 Shaow rkoning an triangulation 2.3 Th tangnt ratio 2.4 Th sin ratio 2.5 Th osin ratio 2.6 Using trigonomtri ratios haptr rviw Syllaus sujt mattr asi knowlg

More information

1 1 1 p q p q. 2ln x x. in simplest form. in simplest form in terms of x and h.

1 1 1 p q p q. 2ln x x. in simplest form. in simplest form in terms of x and h. NAME SUMMER ASSIGNMENT DUE SEPTEMBER 5 (FIRST DAY OF SCHOOL) AP CALC AB Dirctions: Answr all of th following qustions on a sparat sht of papr. All work must b shown. You will b tstd on this matrial somtim

More information

CSE 373: AVL trees. Warmup: Warmup. Interlude: Exploring the balance invariant. AVL Trees: Invariants. AVL tree invariants review

CSE 373: AVL trees. Warmup: Warmup. Interlude: Exploring the balance invariant. AVL Trees: Invariants. AVL tree invariants review rmup CSE 7: AVL trs rmup: ht is n invrint? Mihl L Friy, Jn 9, 0 ht r th AVL tr invrints, xtly? Disuss with your nighor. AVL Trs: Invrints Intrlu: Exploring th ln invrint Cor i: xtr invrint to BSTs tht

More information

MATHEMATICS PAPER IB COORDINATE GEOMETRY(2D &3D) AND CALCULUS. Note: This question paper consists of three sections A,B and C.

MATHEMATICS PAPER IB COORDINATE GEOMETRY(2D &3D) AND CALCULUS. Note: This question paper consists of three sections A,B and C. MATHEMATICS PAPER IB COORDINATE GEOMETRY(D &D) AND CALCULUS. TIME : hrs Ma. Marks.75 Not: This qustion papr consists of thr sctions A,B and C. SECTION A VERY SHORT ANSWER TYPE QUESTIONS. 0X =0.If th portion

More information

Math-3. Lesson 5-6 Euler s Number e Logarithmic and Exponential Modeling (Newton s Law of Cooling)

Math-3. Lesson 5-6 Euler s Number e Logarithmic and Exponential Modeling (Newton s Law of Cooling) Math-3 Lsson 5-6 Eulr s Numbr Logarithmic and Eponntial Modling (Nwton s Law of Cooling) f ( ) What is th numbr? is th horizontal asymptot of th function: 1 1 ~ 2.718... On my 3rd submarin (USS Springfild,

More information

(HELD ON 21st MAY SUNDAY 2017) MATHEMATICS CODE - 1 [PAPER-1]

(HELD ON 21st MAY SUNDAY 2017) MATHEMATICS CODE - 1 [PAPER-1] QUESTION PAPER WITH SOLUTION OF JEE ADVANCED - 7 (HELD ON st MAY SUNDAY 7) FEEL THE POWER OF OUR KNOWLEDGE & EXPERIENCE Our Top class IITian facult tam promiss to giv ou an authntic answr k which will

More information

Mathematics 1110H Calculus I: Limits, derivatives, and Integrals Trent University, Summer 2018 Solutions to the Actual Final Examination

Mathematics 1110H Calculus I: Limits, derivatives, and Integrals Trent University, Summer 2018 Solutions to the Actual Final Examination Mathmatics H Calculus I: Limits, rivativs, an Intgrals Trnt Univrsity, Summr 8 Solutions to th Actual Final Eamination Tim-spac: 9:-: in FPHL 7. Brought to you by Stfan B lan k. Instructions: Do parts

More information

1973 AP Calculus AB: Section I

1973 AP Calculus AB: Section I 97 AP Calculus AB: Sction I 9 Minuts No Calculator Not: In this amination, ln dnots th natural logarithm of (that is, logarithm to th bas ).. ( ) d= + C 6 + C + C + C + C. If f ( ) = + + + and ( ), g=

More information

Binomials and Pascal s Triangle

Binomials and Pascal s Triangle Binomils n Psl s Tringl Binomils n Psl s Tringl Curriulum R AC: 0, 0, 08 ACS: 00 www.mthltis.om Binomils n Psl s Tringl Bsis 0. Intif th prts of th polnomil: 8. (i) Th gr. Th gr is. (Sin is th highst

More information

# 1 ' 10 ' 100. Decimal point = 4 hundred. = 6 tens (or sixty) = 5 ones (or five) = 2 tenths. = 7 hundredths.

# 1 ' 10 ' 100. Decimal point = 4 hundred. = 6 tens (or sixty) = 5 ones (or five) = 2 tenths. = 7 hundredths. How os it work? Pl vlu o imls rprsnt prts o whol numr or ojt # 0 000 Tns o thousns # 000 # 00 Thousns Hunrs Tns Ons # 0 Diml point st iml pl: ' 0 # 0 on tnth n iml pl: ' 0 # 00 on hunrth r iml pl: ' 0

More information

1997 AP Calculus AB: Section I, Part A

1997 AP Calculus AB: Section I, Part A 997 AP Calculus AB: Sction I, Part A 50 Minuts No Calculator Not: Unlss othrwis spcifid, th domain of a function f is assumd to b th st of all ral numbrs x for which f (x) is a ral numbr.. (4x 6 x) dx=

More information

AP Calculus BC AP Exam Problems Chapters 1 3

AP Calculus BC AP Exam Problems Chapters 1 3 AP Eam Problms Captrs Prcalculus Rviw. If f is a continuous function dfind for all ral numbrs and if t maimum valu of f() is 5 and t minimum valu of f() is 7, tn wic of t following must b tru? I. T maimum

More information

First derivative analysis

First derivative analysis Robrto s Nots on Dirntial Calculus Chaptr 8: Graphical analysis Sction First drivativ analysis What you nd to know alrady: How to us drivativs to idntiy th critical valus o a unction and its trm points

More information

SAMPLE. Answers. 1ax < 1 b x > 13 c x 3 d x 12 e x 6 f x > 3 g x > 2. h x 8 i x a x < 2

SAMPLE. Answers. 1ax < 1 b x > 13 c x 3 d x 12 e x 6 f x > 3 g x > 2. h x 8 i x a x < 2 Chaptr Eris A a 9 8 g h 7 i 7 j k l aa + a a a a a7 7 g 8 h i j k 7 l a a 8 g h 8 i j k 7 a a a a a a + g h + a a a 7a 8 78..7 8 Eris a + =, =, + =, =, + ) =, 9 + =, 87 A = $8, = $, C = $ an 8 8kg.77 m

More information

1 Introduction to Modulo 7 Arithmetic

1 Introduction to Modulo 7 Arithmetic 1 Introution to Moulo 7 Arithmti Bor w try our hn t solvin som hr Moulr KnKns, lt s tk los look t on moulr rithmti, mo 7 rithmti. You ll s in this sminr tht rithmti moulo prim is quit irnt rom th ons w

More information

Mor Tutorial at www.dumblittldoctor.com Work th problms without a calculator, but us a calculator to chck rsults. And try diffrntiating your answrs in part III as a usful chck. I. Applications of Intgration

More information

DIFFERENTIAL EQUATION

DIFFERENTIAL EQUATION MD DIFFERENTIAL EQUATION Sllabus : Ordinar diffrntial quations, thir ordr and dgr. Formation of diffrntial quations. Solution of diffrntial quations b th mthod of sparation of variabls, solution of homognous

More information

Sundials and Linear Algebra

Sundials and Linear Algebra Sundials and Linar Algbra M. Scot Swan July 2, 25 Most txts on crating sundials ar dirctd towards thos who ar solly intrstd in making and using sundials and usually assums minimal mathmatical background.

More information

Steinberg s Conjecture is false

Steinberg s Conjecture is false Stinrg s Conjtur is als arxiv:1604.05108v2 [math.co] 19 Apr 2016 Vinnt Cohn-Aa Mihal Hig Danil Král Zhntao Li Estan Salgao Astrat Stinrg onjtur in 1976 that vry planar graph with no yls o lngth our or

More information

10. Limits involving infinity

10. Limits involving infinity . Limits involving infinity It is known from th it ruls for fundamntal arithmtic oprations (+,-,, ) that if two functions hav finit its at a (finit or infinit) point, that is, thy ar convrgnt, th it of

More information

Examples and applications on SSSP and MST

Examples and applications on SSSP and MST Exampls an applications on SSSP an MST Dan (Doris) H & Junhao Gan ITEE Univrsity of Qunslan COMP3506/7505, Uni of Qunslan Exampls an applications on SSSP an MST Dijkstra s Algorithm Th algorithm solvs

More information

Answers & Solutions. for MHT CET-2018 Paper-I (Mathematics) Instruction for Candidates

Answers & Solutions. for MHT CET-2018 Paper-I (Mathematics) Instruction for Candidates DATE : /5/8 Qustion Booklt Vrsion Rgd. Offic : Aakash Towr, 8, Pusa Road, Nw Dlhi-5 Ph.: -75 Fa : -77 Tim : Hour Min. Total Marks : Answrs & Solutions for MHT CET-8 Papr-I (Mathmatics) Instruction for

More information

AP Calculus BC Problem Drill 16: Indeterminate Forms, L Hopital s Rule, & Improper Intergals

AP Calculus BC Problem Drill 16: Indeterminate Forms, L Hopital s Rule, & Improper Intergals AP Calulus BC Problm Drill 6: Indtrminat Forms, L Hopital s Rul, & Impropr Intrgals Qustion No. of Instrutions: () Rad th problm and answr hois arfully () Work th problms on papr as ndd () Pik th answr

More information

SUMMER 17 EXAMINATION

SUMMER 17 EXAMINATION (ISO/IEC - 7-5 Crtifid) SUMMER 7 EXAMINATION Modl wr jct Cod: Important Instructions to aminrs: ) Th answrs should b amind by ky words and not as word-to-word as givn in th modl answr schm. ) Th modl answr

More information

( ) Differential Equations. Unit-7. Exact Differential Equations: M d x + N d y = 0. Verify the condition

( ) Differential Equations. Unit-7. Exact Differential Equations: M d x + N d y = 0. Verify the condition Diffrntial Equations Unit-7 Eat Diffrntial Equations: M d N d 0 Vrif th ondition M N Thn intgrat M d with rspt to as if wr onstants, thn intgrat th trms in N d whih do not ontain trms in and quat sum of

More information

Step 1: Units. Step 2: Start Ups. Step 3: Review Tests. Important: turn to page 21 while you are reading this.

Step 1: Units. Step 2: Start Ups. Step 3: Review Tests. Important: turn to page 21 while you are reading this. DiZign Pty Lt Gt th Rsults You Want! START UP MATHS Yar Ags yars ol This book is part o th Exl Avan Skills sris, whih provis stunts with mor hallnging xtnsion work in mathmatis. Th Exl Avan Skills Start

More information

VTU NOTES QUESTION PAPERS NEWS RESULTS FORUMS

VTU NOTES QUESTION PAPERS NEWS RESULTS FORUMS Diffrntial Equations Unit-7 Eat Diffrntial Equations: M d N d 0 Vrif th ondition M N Thn intgrat M d with rspt to as if wr onstants, thn intgrat th trms in N d whih do not ontain trms in and quat sum of

More information

JOHNSON COUNTY COMMUNITY COLLEGE Calculus I (MATH 241) Final Review Fall 2016

JOHNSON COUNTY COMMUNITY COLLEGE Calculus I (MATH 241) Final Review Fall 2016 JOHNSON COUNTY COMMUNITY COLLEGE Calculus I (MATH ) Final Rviw Fall 06 Th Final Rviw is a starting point as you study for th final am. You should also study your ams and homwork. All topics listd in th

More information

CS553 Lecture Register Allocation I 3

CS553 Lecture Register Allocation I 3 Low-Lvl Issus Last ltur Intrproural analysis Toay Start low-lvl issus Rgistr alloation Latr Mor rgistr alloation Instrution shuling CS553 Ltur Rgistr Alloation I 2 Rgistr Alloation Prolm Assign an unoun

More information

(2) If we multiplied a row of B by λ, then the value is also multiplied by λ(here lambda could be 0). namely

(2) If we multiplied a row of B by λ, then the value is also multiplied by λ(here lambda could be 0). namely . DETERMINANT.. Dtrminnt. Introution:I you think row vtor o mtrix s oorint o vtors in sp, thn th gomtri mning o th rnk o th mtrix is th imnsion o th prlllppi spnn y thm. But w r not only r out th imnsion,

More information

a 1and x is any real number.

a 1and x is any real number. Calcls Nots Eponnts an Logarithms Eponntial Fnction: Has th form y a, whr a 0, a an is any ral nmbr. Graph y, Graph y ln y y Th Natral Bas (Elr s nmbr): An irrational nmbr, symboliz by th lttr, appars

More information

b. How many ternary words of length 23 with eight 0 s, nine 1 s and six 2 s?

b. How many ternary words of length 23 with eight 0 s, nine 1 s and six 2 s? MATH 3012 Finl Exm, My 4, 2006, WTT Stunt Nm n ID Numr 1. All our prts o this prolm r onrn with trnry strings o lngth n, i.., wors o lngth n with lttrs rom th lpht {0, 1, 2}.. How mny trnry wors o lngth

More information

AP Calculus Multiple-Choice Question Collection

AP Calculus Multiple-Choice Question Collection AP Calculus Multipl-Coic Qustion Collction 985 998 . f is a continuous function dfind for all ral numbrs and if t maimum valu of f () is 5 and t minimum valu of f () is 7, tn wic of t following must b

More information

COHORT MBA. Exponential function. MATH review (part2) by Lucian Mitroiu. The LOG and EXP functions. Properties: e e. lim.

COHORT MBA. Exponential function. MATH review (part2) by Lucian Mitroiu. The LOG and EXP functions. Properties: e e. lim. MTH rviw part b Lucian Mitroiu Th LOG and EXP functions Th ponntial function p : R, dfind as Proprtis: lim > lim p Eponntial function Y 8 6 - -8-6 - - X Th natural logarithm function ln in US- log: function

More information

4 x 4, and. where x is Town Square

4 x 4, and. where x is Town Square Accumulation and Population Dnsity E. A city locatd along a straight highway has a population whos dnsity can b approimatd by th function p 5 4 th distanc from th town squar, masurd in mils, whr 4 4, and

More information

u x v x dx u x v x v x u x dx d u x v x u x v x dx u x v x dx Integration by Parts Formula

u x v x dx u x v x v x u x dx d u x v x u x v x dx u x v x dx Integration by Parts Formula 7. Intgration by Parts Each drivativ formula givs ris to a corrsponding intgral formula, as w v sn many tims. Th drivativ product rul yilds a vry usful intgration tchniqu calld intgration by parts. Starting

More information

PHYS ,Fall 05, Term Exam #1, Oct., 12, 2005

PHYS ,Fall 05, Term Exam #1, Oct., 12, 2005 PHYS1444-,Fall 5, Trm Exam #1, Oct., 1, 5 Nam: Kys 1. circular ring of charg of raius an a total charg Q lis in th x-y plan with its cntr at th origin. small positiv tst charg q is plac at th origin. What

More information

Higher order derivatives

Higher order derivatives Robrto s Nots on Diffrntial Calculus Chaptr 4: Basic diffrntiation ruls Sction 7 Highr ordr drivativs What you nd to know alrady: Basic diffrntiation ruls. What you can larn hr: How to rpat th procss of

More information

4037 ADDITIONAL MATHEMATICS

4037 ADDITIONAL MATHEMATICS CAMBRIDGE INTERNATIONAL EXAMINATIONS GCE Ordinary Lvl MARK SCHEME for th Octobr/Novmbr 0 sris 40 ADDITIONAL MATHEMATICS 40/ Papr, maimum raw mark 80 This mark schm is publishd as an aid to tachrs and candidats,

More information

Constants and Conversions:

Constants and Conversions: EXAM INFORMATION Radial Distribution Function: P 2 ( r) RDF( r) Br R( r ) 2, B is th normalization constant. Ordr of Orbital Enrgis: Homonuclar Diatomic Molculs * * * * g1s u1s g 2s u 2s u 2 p g 2 p g

More information

Mock Exam 2 Section A

Mock Exam 2 Section A Mock Eam Mock Eam Sction A. Rfrnc: HKDSE Math M Q ( + a) n n n n + C ( a) + C( a) + C ( a) + nn ( ) a nn ( )( n ) a + na + + + 6 na 6... () \ nn ( ) a n( n )( n ) a + 6... () 6 6 From (): a... () n Substituting

More information

Solutions for HW11. Exercise 34. (a) Use the recurrence relation t(g) = t(g e) + t(g/e) to count the number of spanning trees of v 1

Solutions for HW11. Exercise 34. (a) Use the recurrence relation t(g) = t(g e) + t(g/e) to count the number of spanning trees of v 1 Solutions for HW Exris. () Us th rurrn rltion t(g) = t(g ) + t(g/) to ount th numr of spnning trs of v v v u u u Rmmr to kp multipl gs!! First rrw G so tht non of th gs ross: v u v Rursing on = (v, u ):

More information

MATHEMATICS PAPER IIB COORDINATE GEOMETRY AND CALCULUS. Note: This question paper consists of three sections A, B and C.

MATHEMATICS PAPER IIB COORDINATE GEOMETRY AND CALCULUS. Note: This question paper consists of three sections A, B and C. MATHEMATICS PAPER IIB COORDINATE GEOMETRY AND CALCULUS. Tim: 3hrs Ma. Marks.75 Not: This qustion papr consists of thr sctions A, B and C. SECTION -A Vry Short Answr Typ Qustions. 0 X = 0. Find th condition

More information

ENJOY MATHEMATICS WITH SUHAAG SIR

ENJOY MATHEMATICS WITH SUHAAG SIR R-, OPPOSITE RAILWAY TRACK, ZONE-, M. P. NAGAR, BHOPAL :(0755) 00 000, 80 5 888 IIT-JEE, AIEEE (WITH TH, TH 0 TH, TH & DROPPERS ) www.tkoclasss.com Pag: SOLUTION OF IITJEE 0; PAPER ; BHARAT MAIN SABSE

More information

Differential Equations

Differential Equations UNIT I Diffrntial Equations.0 INTRODUCTION W li in a world of intrrlatd changing ntitis. Th locit of a falling bod changs with distanc, th position of th arth changs with tim, th ara of a circl changs

More information

Using the Printable Sticker Function. Using the Edit Screen. Computer. Tablet. ScanNCutCanvas

Using the Printable Sticker Function. Using the Edit Screen. Computer. Tablet. ScanNCutCanvas SnNCutCnvs Using th Printl Stikr Funtion On-o--kin stikrs n sily rt y using your inkjt printr n th Dirt Cut untion o th SnNCut mhin. For inormtion on si oprtions o th SnNCutCnvs, rr to th Hlp. To viw th

More information

Homework #3. 1 x. dx. It therefore follows that a sum of the

Homework #3. 1 x. dx. It therefore follows that a sum of the Danil Cannon CS 62 / Luan March 5, 2009 Homwork # 1. Th natural logarithm is dfind by ln n = n 1 dx. It thrfor follows that a sum of th 1 x sam addnd ovr th sam intrval should b both asymptotically uppr-

More information

Text: WMM, Chapter 5. Sections , ,

Text: WMM, Chapter 5. Sections , , Lcturs 6 - Continuous Probabilit Distributions Tt: WMM, Chaptr 5. Sctions 6.-6.4, 6.6-6.8, 7.-7. In th prvious sction, w introduc som of th common probabilit distribution functions (PDFs) for discrt sampl

More information

Polygons POLYGONS.

Polygons POLYGONS. Polgons PLYGNS www.mthltis.o.uk ow os it work? Solutions Polgons Pg qustions Polgons Polgon Not polgon Polgon Not polgon Polgon Not polgon Polgon Not polgon f g h Polgon Not polgon Polgon Not polgon Polgon

More information

Supplementary Materials

Supplementary Materials 6 Supplmntary Matrials APPENDIX A PHYSICAL INTERPRETATION OF FUEL-RATE-SPEED FUNCTION A truck running on a road with grad/slop θ positiv if moving up and ngativ if moving down facs thr rsistancs: arodynamic

More information

September 23, Honors Chem Atomic structure.notebook. Atomic Structure

September 23, Honors Chem Atomic structure.notebook. Atomic Structure Atomic Structur Topics covrd Atomic structur Subatomic particls Atomic numbr Mass numbr Charg Cations Anions Isotops Avrag atomic mass Practic qustions atomic structur Sp 27 8:16 PM 1 Powr Standards/ Larning

More information

SOLVED EXAMPLES. be the foci of an ellipse with eccentricity e. For any point P on the ellipse, prove that. tan

SOLVED EXAMPLES. be the foci of an ellipse with eccentricity e. For any point P on the ellipse, prove that. tan LOCUS 58 SOLVED EXAMPLES Empl Lt F n F th foci of n llips with ccntricit. For n point P on th llips, prov tht tn PF F tn PF F Assum th llips to, n lt P th point (, sin ). P(, sin ) F F F = (-, 0) F = (,

More information

y = 2xe x + x 2 e x at (0, 3). solution: Since y is implicitly related to x we have to use implicit differentiation: 3 6y = 0 y = 1 2 x ln(b) ln(b)

y = 2xe x + x 2 e x at (0, 3). solution: Since y is implicitly related to x we have to use implicit differentiation: 3 6y = 0 y = 1 2 x ln(b) ln(b) 4. y = y = + 5. Find th quation of th tangnt lin for th function y = ( + ) 3 whn = 0. solution: First not that whn = 0, y = (1 + 1) 3 = 8, so th lin gos through (0, 8) and thrfor its y-intrcpt is 8. y

More information

3) Use the average steady-state equation to determine the dose. Note that only 100 mg tablets of aminophylline are available here.

3) Use the average steady-state equation to determine the dose. Note that only 100 mg tablets of aminophylline are available here. PHA 5127 Dsigning A Dosing Rgimn Answrs provi by Jry Stark Mr. JM is to b start on aminophyllin or th tratmnt o asthma. H is a non-smokr an wighs 60 kg. Dsign an oral osing rgimn or this patint such that

More information

Things I Should Know Before I Get to Calculus Class

Things I Should Know Before I Get to Calculus Class Things I Should Know Bfor I Gt to Calculus Class Quadratic Formula = b± b 4ac a sin + cos = + tan = sc + cot = csc sin( ± y ) = sin cos y ± cos sin y cos( + y ) = cos cos y sin sin y cos( y ) = cos cos

More information

SECTION where P (cos θ, sin θ) and Q(cos θ, sin θ) are polynomials in cos θ and sin θ, provided Q is never equal to zero.

SECTION where P (cos θ, sin θ) and Q(cos θ, sin θ) are polynomials in cos θ and sin θ, provided Q is never equal to zero. SETION 6. 57 6. Evaluation of Dfinit Intgrals Exampl 6.6 W hav usd dfinit intgrals to valuat contour intgrals. It may com as a surpris to larn that contour intgrals and rsidus can b usd to valuat crtain

More information

Solution: APPM 1360 Final (150 pts) Spring (60 pts total) The following parts are not related, justify your answers:

Solution: APPM 1360 Final (150 pts) Spring (60 pts total) The following parts are not related, justify your answers: APPM 6 Final 5 pts) Spring 4. 6 pts total) Th following parts ar not rlatd, justify your answrs: a) Considr th curv rprsntd by th paramtric quations, t and y t + for t. i) 6 pts) Writ down th corrsponding

More information

Digital Signal Processing, Fall 2006

Digital Signal Processing, Fall 2006 Digital Signal Prossing, Fall 006 Ltur 7: Filtr Dsign Zhng-ua an Dpartmnt of Eltroni Systms Aalborg Univrsity, Dnmar t@om.aau. Cours at a glan MM Disrt-tim signals an systms Systm MM Fourir-omain rprsntation

More information

Module graph.py. 1 Introduction. 2 Graph basics. 3 Module graph.py. 3.1 Objects. CS 231 Naomi Nishimura

Module graph.py. 1 Introduction. 2 Graph basics. 3 Module graph.py. 3.1 Objects. CS 231 Naomi Nishimura Moul grph.py CS 231 Nomi Nishimur 1 Introution Just lik th Python list n th Python itionry provi wys of storing, ssing, n moifying t, grph n viw s wy of storing, ssing, n moifying t. Bus Python os not

More information

Grade 12 (MCV4UE) AP Calculus Page 1 of 5 Derivative of a Function & Differentiability

Grade 12 (MCV4UE) AP Calculus Page 1 of 5 Derivative of a Function & Differentiability Gra (MCV4UE) AP Calculus Pag of 5 Drivativ of a Function & Diffrntiabilit Th Drivativ at a Point f ( a h) f ( a) Rcall, lim provis th slop of h0 h th tangnt to th graph f ( at th point a, f ( a), an th

More information

12. Traffic engineering

12. Traffic engineering lt2.ppt S-38. Introution to Tltrffi Thory Spring 200 2 Topology Pths A tlommunition ntwork onsists of nos n links Lt N not th st of nos in with n Lt J not th st of nos in with j N = {,,,,} J = {,2,3,,2}

More information

MATH Non-Euclidean Geometry Exercise Set #8 Solutions

MATH Non-Euclidean Geometry Exercise Set #8 Solutions MATH 68-9 Non-Euliean Geometry Exerise Set #8 Let ( ab, :, ) Show that ( ab, :, ) an ( a b) to fin ( a, : b,, ) ( a, : b,, ) an ( a, : b, ) Sine ( ab, :, ) while Likewise,, we have ( a, : b, ) ( ab, :,

More information

Note If the candidate believes that e x = 0 solves to x = 0 or gives an extra solution of x = 0, then withhold the final accuracy mark.

Note If the candidate believes that e x = 0 solves to x = 0 or gives an extra solution of x = 0, then withhold the final accuracy mark. . (a) Eithr y = or ( 0, ) (b) Whn =, y = ( 0 + ) = 0 = 0 ( + ) = 0 ( )( ) = 0 Eithr = (for possibly abov) or = A 3. Not If th candidat blivs that = 0 solvs to = 0 or givs an tra solution of = 0, thn withhold

More information

Copyright 2012 Pearson Education, Inc. Publishing as Prentice Hall.

Copyright 2012 Pearson Education, Inc. Publishing as Prentice Hall. Chapr Rviw 0 6. ( a a ln a. This will qual a if an onl if ln a, or a. + k an (ln + c. Thrfor, a an valu of, whr h wo curvs inrsc, h wo angn lins will b prpnicular. 6. (a Sinc h lin passs hrough h origin

More information

Assignment 4 Biophys 4322/5322

Assignment 4 Biophys 4322/5322 Assignmnt 4 Biophys 4322/5322 Tylr Shndruk Fbruary 28, 202 Problm Phillips 7.3. Part a R-onsidr dimoglobin utilizing th anonial nsmbl maning rdriv Eq. 3 from Phillips Chaptr 7. For a anonial nsmbl p E

More information

A. Limits and Horizontal Asymptotes ( ) f x f x. f x. x "±# ( ).

A. Limits and Horizontal Asymptotes ( ) f x f x. f x. x ±# ( ). A. Limits and Horizontal Asymptots What you ar finding: You can b askd to find lim x "a H.A.) problm is asking you find lim x "# and lim x "$#. or lim x "±#. Typically, a horizontal asymptot algbraically,

More information

Chapter 1. Chapter 10. Chapter 2. Chapter 11. Chapter 3. Chapter 12. Chapter 4. Chapter 13. Chapter 5. Chapter 14. Chapter 6. Chapter 7.

Chapter 1. Chapter 10. Chapter 2. Chapter 11. Chapter 3. Chapter 12. Chapter 4. Chapter 13. Chapter 5. Chapter 14. Chapter 6. Chapter 7. Chaptr Binomial Epansion Chaptr 0 Furthr Probability Chaptr Limits and Drivativs Chaptr Discrt Random Variabls Chaptr Diffrntiation Chaptr Discrt Probability Distributions Chaptr Applications of Diffrntiation

More information

Multiple Short Term Infusion Homework # 5 PHA 5127

Multiple Short Term Infusion Homework # 5 PHA 5127 Multipl Short rm Infusion Homwork # 5 PHA 527 A rug is aministr as a short trm infusion. h avrag pharmacokintic paramtrs for this rug ar: k 0.40 hr - V 28 L his rug follows a on-compartmnt boy mol. A 300

More information

Problem 22: Journey to the Center of the Earth

Problem 22: Journey to the Center of the Earth Problm : Journy to th Cntr of th Earth Imagin that on drilld a hol with smooth sids straight through th ntr of th arth If th air is rmod from this tub (and it dosn t fill up with watr, liquid rok, or iron

More information

The Matrix Exponential

The Matrix Exponential Th Matrix Exponntial (with xrciss) by D. Klain Vrsion 207.0.05 Corrctions and commnts ar wlcom. Th Matrix Exponntial For ach n n complx matrix A, dfin th xponntial of A to b th matrix A A k I + A + k!

More information

dy 1. If fx ( ) is continuous at x = 3, then 13. If y x ) for x 0, then f (g(x)) = g (f (x)) when x = a. ½ b. ½ c. 1 b. 4x a. 3 b. 3 c.

dy 1. If fx ( ) is continuous at x = 3, then 13. If y x ) for x 0, then f (g(x)) = g (f (x)) when x = a. ½ b. ½ c. 1 b. 4x a. 3 b. 3 c. AP CALCULUS BC SUMMER ASSIGNMENT DO NOT SHOW YOUR WORK ON THIS! Complt ts problms during t last two wks of August. SHOW ALL WORK. Know ow to do ALL of ts problms, so do tm wll. Itms markd wit a * dnot

More information

5. B To determine all the holes and asymptotes of the equation: y = bdc dced f gbd

5. B To determine all the holes and asymptotes of the equation: y = bdc dced f gbd 1. First you chck th domain of g x. For this function, x cannot qual zro. Thn w find th D domain of f g x D 3; D 3 0; x Q x x 1 3, x 0 2. Any cosin graph is going to b symmtric with th y-axis as long as

More information

Chapter 1. Analysis of a M/G/1/K Queue without Vacations

Chapter 1. Analysis of a M/G/1/K Queue without Vacations Chatr nalysis of a M/G// Quu without Vaations W onsir th singl srvr finit aaity quu with Poisson arrivals an gnrally istriut srvi tims. Th M/G// systm may analys using an im Marov Chain aroah vry similar

More information

Modeling with first order equations (Sect. 2.3).

Modeling with first order equations (Sect. 2.3). Moling with first orr quations (Sct. 2.3. Main xampl: Salt in a watr tank. Th xprimntal vic. Th main quations. Analysis of th mathmatical mol. Prictions for particular situations. Salt in a watr tank.

More information