CHEM1907/ J-7 June 2003 B CHO. Give the products obtained when D-xylose is treated with the following reagents. [Ag(NH 3 ) 2 ] + / OH solution

Size: px
Start display at page:

Download "CHEM1907/ J-7 June 2003 B CHO. Give the products obtained when D-xylose is treated with the following reagents. [Ag(NH 3 ) 2 ] + / OH solution"

Transcription

1 EM1907/ J-7 June 2003 onsider the following two monosaccharides, (A) and (B). 8 2 (A) 2 (B) -D-altropyranose -D-xylofuranose Draw Fischer projections of the open chain forms of A and B. A B 2 2 Give the products obtained when D-xylose is treated with the following reagents. [Ag( 3 ) 2 ] + / solution 2 ab 4 in methanol solvent Draw the aworth structure of a non-reducing disaccharide, which yields D-altrose and D-xylose on acid hydrolysis. 2 2

2 EM1907/ J-7 June 2003

3 EM1907/ J-8 June 2003 The side-chain of the amino acid tryptophan () is a substituted derivative of the heterocycle indole (D). Explain with the aid of diagrams whether you would expect indole to have aromatic stability or not. Would you expect the nitrogen atom of indole to be basic? Give reasons for your answer () (D) Indole is aromatic because: it is a fused ring system with all rings co-planar all atoms in the rings are sp 2 hybridised with p-orbitals perpendicular to the ring it has 10 π electrons, which obeys the (4n + 2) rule required for aromaticity. Indole is not basic as the "lone pair" on the nitrogen is is part of the aromatic π system and thus not free to react. ydrolysis of damp (E), a nucleotide important in DA synthesis, gives the sugar D-2-deoxyribose and the nucleic base adenine. Give the structure of adenine and the structure of one tautomer of adenine. 2 2 P (E) adenine tautomer of adenine 2 2

4 EM1907/ J-9 June 2003 onsider the tripeptide phenylalanylglutamyltyrosine (Phe-Glu-Tyr) (F), whose constitutional formula is shown below. 9 (F) Draw the constitutional formula(s) of the product(s) obtained when the tripeptide is subjected to the following conditions. cold 2 M a M l / heat The pk a values of tyrosine are pk a1 = 2.20 ( -), pk a2 = 9.11 ( - 3 ) and pk a3 = ( ). Draw the structure of the zwitterionic form of tyrosine. 2 3 ASWER TIUES TE EXT PAGE

5 EM1907/ J-9 June 2003 At what p will this be the predominant species in aqueous solution? 5.66 Give the constitutional formulas for the following dipeptides present in water solution at the indicated p values. Tyr-Phe, p 12.0 Glu-Tyr, p

6 EM1907/EM J-11 June 2004 onsider the tripeptide L-lysyl-L-glutamyl-L-tyrosine (Lys-Glu-Tyr), (F), whose constitutional formula is shown below. 8 (F) ( 2 ) Draw the Fischer projections with L-configurations for the amino acids (in their correct ionisation states) obtained from the hydrolysis of (F) using hot concentrated l solution ( 2 ) The pk a values of lysine are pk a1 = 2.18 ( -), pk a2 = 8.95 ( - 3 ) and pk a3 = (-( 2 ) 4 3 ). Draw the structure of the zwitterionic form of lysine. 2 2 ( 2 ) 4 3 At what p will this be the predominant species in aqueous solution? 9.74 ASWER TIUES TE EXT PAGE

7 EM1907/EM J-11 June 2004 Give the constitutional formulas for the following dipeptides present in water solution at the indicated p values. Glu-Tyr, p 12.0 Glu-Lys, p ( 2 )

8 EM1907/EM J-8 June 2004 Lactose, 4--( -D-galactopyranosyl)- -D-glucopyranose is the major sugar in human and cow's milk Lactose Does lactose display mutarotation? Justify you answer. Yes. The right hand ring contains the hemiacetal functional group as the α- anomer. It therefore equilibrates with the open chain (aldehyde + alcohol) form and the β-anomer. Draw the Fischer projection of the open chain form of D-galactose. 2 Give the products obtained when D-galactose is treated with the following reagents. methanol / / heat [Ag( 3 ) 2 ] / solution

9 EM1907/EM J-9 June 2004 Acid hydrolysis of a non-reducing disaccharide yields D-galactose as the only product. Draw the aworth structure of one such disaccharide ow many different disaccharides are possible in the preceding question? What is the relationship between these compounds? 3 disaccharides possible. (The possible linkages are α-α, α-β and β-β. The β-α is identcal to the α-β.) They are all diastereoisomers of each other. TE REMAIDER F TIS PAGE IS FR RUG WRKIG LY

10 EM1907/ J-10 June 2005 Give the products obtained when lysine is treated with the following reagents. excess methanol / l dilute a ( 2 ) 4 3 ( 2 )

11 EM1907/ J-7 June 2005 onsider the structures of the two aldohexoses shown below (A) (B) -D-allopyranose -D-altropyranose (A) Draw the Fischer projection of the open chain forms of sugars (A) and (B). (B) 2 2 Give the products obtained when D-allose is treated with the following reagents. acidified methanol ab 4 in methanol solvent In the case of the product obtained from the reaction with ab 4 in methanol, specify the optical rotation as "(+)", "( )", "zero" or "cannot be predicted". Justify your choice. Zero. It is a meso compound and is therefore achiral and optically inactive. TIS QUESTI IS TIUED TE EXT PAGE.

12 EM1907/ J-8 June 2005 Draw the aworth structure of -D-allopyranosyl- -D-altropyranoside Will this disaccharide be a reducing sugar? Explain your answer. o, not a reducing sugar. o hemiacetal functional group in equilibrium with open chain aldehyde. TE REMAIDER F TIS PAGE IS FR RUG WRKIG LY

13 EM1907/ J-9 June 2005 onsider the three amino acids shown below ( 2 ) threonine (Thr) aspartic acid (Asp) lysine (Lys) Draw the constitutional formulas for the following dipeptides present in water solution at the indicated p values. Thr-Lys, p 1.0 Asp-Thr, p ( 2 ) Draw the stereoformula for L-threonine and indicate its absolute configuration using the (R)- and (S)- convention. b 2 2 a c 2 3 Absolute configuration (S) L-threonine The pk a values of aspartic acid are 1.88 ( -), 9.60 ( - 3 ) and 3.65 (- 2 ). Draw the zwitterionic form of aspartic acid At what p will this be the predominant species in aqueous solution? 2.77

CHEM1907/ J-7 June 2003

CHEM1907/ J-7 June 2003 CEM1907/8 2003-J-7 June 2003 Consider the following two monosaccharides, (A) and (B). 8 C 2 -D-altropyranose (A) C 2 -D-xylofuranose (B) A Draw Fischer projections of the open chain forms of A and B. B

More information

CHEM J-9 June 2014

CHEM J-9 June 2014 CEM1611 2014-J-9 June 2014 Alanine (ala) and lysine (lys) are two amino acids with the structures given below as Fischer projections. The pk a values of the conjugate acid forms of the different functional

More information

CHEM J-2 June Complete the following table, giving either the systematic name or the molecular formula as required.

CHEM J-2 June Complete the following table, giving either the systematic name or the molecular formula as required. verall health EM1108 2008-J-2 June 2008 omplete the following table, giving either the systematic name or the molecular formula as required. 2 Formula S 2 ol 2 6 2 Ag 2 r 4 K 3 Systematic name sulfur dioxide

More information

CHEM J-2 June In the spaces provided, briefly explain the meaning of the following terms.

CHEM J-2 June In the spaces provided, briefly explain the meaning of the following terms. CHEM1611 2013-J-2 June 2013 In the spaces provided, briefly explain the meaning of the following terms. Effective nuclear charge 4 The force of attraction experienced by the outer electrons of an atom.

More information

CHEM J-8 June Complete the following table. Make sure you give the name of the starting material where indicated. REAGENTS/ CONDITIONS

CHEM J-8 June Complete the following table. Make sure you give the name of the starting material where indicated. REAGENTS/ CONDITIONS CEM1102 2014-J-8 June 2014 Complete the following table. Make sure you give the name of the starting material where indicated. STARTIG MATERIAL REAGETS/ CDITIS STRUCTURAL FRMULA(S) F MAJR RGAIC PRDUCT(S)

More information

Chapter 24 Carbohydrates

Chapter 24 Carbohydrates hapter arbohydrates Review of oncepts Fill in the blanks below. To verify that your answers are correct, look in your textbook at the end of hapter. Each of the sentences below appears verbatim in the

More information

Chem 215 F11 Notes Dr. Masato Koreeda - Page 1 of 18. Date: November 9, 2011

Chem 215 F11 Notes Dr. Masato Koreeda - Page 1 of 18. Date: November 9, 2011 Chem F Notes Dr. Masato Koreeda - Page of 8. Date: November 9, 0 Chapters.8; -,,, and 7: Carbohydrates Part I Carbohydrate nomenclature: http://www.chem.qmul.ac.uk/iupac/carb/ Carbohydrates: Polyhydroxylated

More information

The stucture of D-glucose is shown below. Draw the Fischer projection of L-glucose in the space provided. L-glucose

The stucture of D-glucose is shown below. Draw the Fischer projection of L-glucose in the space provided. L-glucose CEM1612 2003--8 ovember 2003 The stucture of D-glucose is shown below. Draw the Fischer projection of L-glucose in the space provided. D-glucose C C 2 L-glucose C 9 C 2 D-glucose is in equilibrium with

More information

Practice Midterm Exam 200 points total 75 minutes Multiple Choice (3 pts each 30 pts total) Mark your answers in the space to the left:

Practice Midterm Exam 200 points total 75 minutes Multiple Choice (3 pts each 30 pts total) Mark your answers in the space to the left: MITES ame Practice Midterm Exam 200 points total 75 minutes Multiple hoice (3 pts each 30 pts total) Mark your answers in the space to the left: 1. Amphipathic molecules have regions that are: a) polar

More information

A. Two of the common amino acids are analyzed. Amino acid X and amino acid Y both have an isoionic point in the range of

A. Two of the common amino acids are analyzed. Amino acid X and amino acid Y both have an isoionic point in the range of Questions with Answers- Amino Acids & Peptides A. Two of the common amino acids are analyzed. Amino acid X and amino acid Y both have an isoionic point in the range of 5.0-6.5 (Questions 1-4) 1. Which

More information

Number of d electrons CO 2 carbon dioxide +IV or +4 0

Number of d electrons CO 2 carbon dioxide +IV or +4 0 CEM1611 2007-J-2 June 2007 Complete the following table. Give, as required, the formula, the systematic name, the oxidation number of the underlined atom and, where indicated, the number of d electrons

More information

CHEM J-2 June 2006 HCO 2. Calculate the osmotic pressure of a solution of 1.0 g of glucose (C 6 H 12 O 6 ) in 1500 ml of water at 37 C.

CHEM J-2 June 2006 HCO 2. Calculate the osmotic pressure of a solution of 1.0 g of glucose (C 6 H 12 O 6 ) in 1500 ml of water at 37 C. CEM1405 2006-J-2 June 2006 Draw Lewis structures of ozone, 3, and the formate anion, C 2, including resonance hybrids where appropriate. 3 C 2 3 C C Calculate the osmotic pressure of a solution of 1.0

More information

CHEM1902/ N-8 November Consider the following reaction sequences beginning with the carboxylic acid, E.

CHEM1902/ N-8 November Consider the following reaction sequences beginning with the carboxylic acid, E. CEM1902/4 2014--8 ovember 2014 Consider the following reaction sequences beginning with the carboxylic acid, E. 6 ame compounds E and G. E: propionic acid G: methyl propionate Propose structures for compounds

More information

25.3 Cyclization of Monosaccharides

25.3 Cyclization of Monosaccharides 090 CAPTER CARBYDRATES PRBLEM. Determine the identity of each of these carbohydrates: C a) b) c) C C C C C (int: This must be rotated first.). Cyclization of Monosaccharides Up to this point, the structure

More information

11/14/2016. NaBH 4. Superimposable on mirror image. (achiral) D-ribose. NaBH 4 NaBH 4. Not superimposable on mirror image.

11/14/2016. NaBH 4. Superimposable on mirror image. (achiral) D-ribose. NaBH 4 NaBH 4. Not superimposable on mirror image. There are multiple ways to relate the structures of ketoses to aldoses. Reduction of a ketose with NaB 4 forms a new stereocenter and thus forms a mixture of two alditols. An aldopentose forms a chiral

More information

CHAPTER 29 HW: AMINO ACIDS + PROTEINS

CHAPTER 29 HW: AMINO ACIDS + PROTEINS CAPTER 29 W: AMI ACIDS + PRTEIS For all problems, consult the table of 20 Amino Acids provided in lecture if an amino acid structure is needed; these will be given on exams. Use natural amino acids (L)

More information

Structures in equilibrium at point A: Structures in equilibrium at point B: (ii) Structure at the isoelectric point: O O

Structures in equilibrium at point A: Structures in equilibrium at point B: (ii) Structure at the isoelectric point: O O ame 21 F10-Final Exam Page 2 I. (42 points) (1) (16 points) The titration curve for L-lysine is shown below. Provide (i) the main structures in equilibrium at each of points and B indicated below and (ii)

More information

Marking Scheme For The Exam QUESTION #

Marking Scheme For The Exam QUESTION # Chemistry 2420 S10 Spring 2005 Term Exam #1 110 Minutes ame: Student umber Marking Scheme For The Exam QUESTI # 1 2 3 4 5 6 7 8 6 12 14 14 13 39 12 9 TTAL 119 % Question 1. (6 Marks) Under mildly acidic

More information

Lecture'18:'April'2,'2013

Lecture'18:'April'2,'2013 CM'224' 'rganic'chemistry'ii Spring'2013,'Des'Plaines' 'Prof.'Chad'Landrie 2 3 N cysteine (Cys) S oxidation S S 3 N cystine N 3 Lecture'18:'April'2,'2013 Disaccharides+&+Polysaccharides Amino+acids++(26.1926.3)

More information

CHAPTER 28 HW: CARBOHYDRATES

CHAPTER 28 HW: CARBOHYDRATES CAPTER 8 W: CARBYDRATES For all problems, consult the table of D-Monosaccharides provided in lecture if a structure or name is necessary. ISMERIC RELATINSIPS. Draw the following and answer the questions.

More information

Amino Acids and Peptides

Amino Acids and Peptides Amino Acids Amino Acids and Peptides Amino acid a compound that contains both an amino group and a carboxyl group α-amino acid an amino acid in which the amino group is on the carbon adjacent to the carboxyl

More information

Loudon Chapter 24 Review: Carbohydrates CHEM 3331, Jacquie Richardson, Fall Page 1

Loudon Chapter 24 Review: Carbohydrates CHEM 3331, Jacquie Richardson, Fall Page 1 CEM 3331, Jacquie Richardson, Fall 2010 - Page 1 This chapter is about carbohydrates molecules with the general formula of C n ( 2 ) n, or in other words C n 2n n. This is a very common formula for sugars

More information

Page 2. The tripeptide shown is formed from the amino acids alanine, threonine and lysine.

Page 2. The tripeptide shown is formed from the amino acids alanine, threonine and lysine. Q1.(a) The tripeptide shown is formed from the amino acids alanine, threonine and lysine. Draw a separate circle around each of the asymmetric carbon atoms in the tripeptide. Draw the zwitterion of alanine.

More information

Page 2. The tripeptide shown is formed from the amino acids alanine, threonine and lysine.

Page 2. The tripeptide shown is formed from the amino acids alanine, threonine and lysine. Q1.(a) The tripeptide shown is formed from the amino acids alanine, threonine and lysine. Draw a separate circle around each of the asymmetric carbon atoms in the tripeptide. Draw the zwitterion of alanine.

More information

CHE 322 Summer 2012 Final Exam Form Choose the lowest unoccupied molecular orbital (LUMO) of the pentadienyl cation.

CHE 322 Summer 2012 Final Exam Form Choose the lowest unoccupied molecular orbital (LUMO) of the pentadienyl cation. Multiple Choice Questions: 100 points 1. Choose the lowest unoccupied molecular orbital (LUMO) of the pentadienyl cation. 2. Select the possible reactants of the following reaction. A i B ii C iii D i

More information

Principles of Biochemistry

Principles of Biochemistry Principles of Biochemistry Fourth Edition Donald Voet Judith G. Voet Charlotte W. Pratt Chapter 4 Amino Acids: The Building Blocks of proteins (Page 76-90) Chapter Contents 1- Amino acids Structure: 2-

More information

Solutions In each case, the chirality center has the R configuration

Solutions In each case, the chirality center has the R configuration CAPTER 25 669 Solutions 25.1. In each case, the chirality center has the R configuration. C C 2 2 C 3 C(C 3 ) 2 D-Alanine D-Valine 25.2. 2 2 S 2 d) 2 25.3. Pro,, Trp, Tyr, and is, Trp, Tyr, and is Arg,

More information

Exam 1 (Monday, July 6, 2015)

Exam 1 (Monday, July 6, 2015) Chem 231 Summer 2015 Assigned Homework Problems Last updated: Friday, July 24, 2015 Problems Assigned from Essential Organic Chemistry, 2 nd Edition, Paula Yurkanis Bruice, Prentice Hall, New York, NY,

More information

ORGANIC - CLUTCH CH CARBOHYDRATES.

ORGANIC - CLUTCH CH CARBOHYDRATES. !! www.clutchprep.com CONCEPT: INTRODUCTION TO CARBOHYDRATE MONOSACCHARIDES Sugars or saccharides are also referred to as carbo-hydrates, implying that carbon has been combined with Monosaccharides are

More information

NAME. EXAM I I. / 36 September 25, 2000 Biochemistry I II. / 26 BICH421/621 III. / 38 TOTAL /100

NAME. EXAM I I. / 36 September 25, 2000 Biochemistry I II. / 26 BICH421/621 III. / 38 TOTAL /100 EXAM I I. / 6 September 25, 2000 Biochemistry I II. / 26 BIH421/621 III. / 8 TOTAL /100 I. MULTIPLE HOIE (6 points) hoose the BEST answer to the question by circling the appropriate letter. 1. An amino

More information

ORGANIC - BRUICE 8E CH THE ORGANIC CHEMISTRY OF CARBOHYDRATES

ORGANIC - BRUICE 8E CH THE ORGANIC CHEMISTRY OF CARBOHYDRATES !! www.clutchprep.com CONCEPT: INTRODUCTION TO CARBOHYDRATE MONOSACCHARIDES Sugars or saccharides are also referred to as carbo-hydrates, implying that carbon has been combined with Monosaccharides are

More information

Carbohydrates - Introduction

Carbohydrates - Introduction arbohydrates - Introduction arbohydrates - General Description A. Polyhydroxy Aldehydes or Ketones ARBN AIN B. Serve a variety of functions ARBN AIN ARBN AIN 1. Energy storage (Glucose, Glycogen, Starch)

More information

Topics in the June 2008 Exam Paper for CHEM1611

Topics in the June 2008 Exam Paper for CHEM1611 June 2008 Topics in the June 2008 Exam Paper for CEM1611 Click on the links for resources on each topic. 2008-J-2: 2008-J-3: 2008-J-4: 2008-J-5: 2008-J-6: 2008-J-7: 2008-J-9: 2008-J-10: 2008-J-11: 2008-J-13:

More information

Structures in equilibrium at point A: Structures in equilibrium at point B: (ii) Structure at the isoelectric point:

Structures in equilibrium at point A: Structures in equilibrium at point B: (ii) Structure at the isoelectric point: ame 21 F10-Final Exam Page 2 I. (42 points) (1) (16 points) The titration curve for L-lysine is shown below. Provide (i) the main structures in equilibrium at each of points A and B indicated below and

More information

ORGANIC - BROWN 8E CH CARBOHYDRATES.

ORGANIC - BROWN 8E CH CARBOHYDRATES. !! www.clutchprep.com CONCEPT: INTRODUCTION TO CARBOHYDRATE MONOSACCHARIDES Sugars or saccharides are also referred to as carbo-hydrates, implying that carbon has been combined with Monosaccharides are

More information

C CH 3 N C COOH. Write the structural formulas of all of the dipeptides that they could form with each other.

C CH 3 N C COOH. Write the structural formulas of all of the dipeptides that they could form with each other. hapter 25 Biochemistry oncept heck 25.1 Two common amino acids are 3 2 N alanine 3 2 N threonine Write the structural formulas of all of the dipeptides that they could form with each other. The carboxyl

More information

PROTEIN STRUCTURE AMINO ACIDS H R. Zwitterion (dipolar ion) CO 2 H. PEPTIDES Formal reactions showing formation of peptide bond by dehydration:

PROTEIN STRUCTURE AMINO ACIDS H R. Zwitterion (dipolar ion) CO 2 H. PEPTIDES Formal reactions showing formation of peptide bond by dehydration: PTEI STUTUE ydrolysis of proteins with aqueous acid or base yields a mixture of free amino acids. Each type of protein yields a characteristic mixture of the ~ 20 amino acids. AMI AIDS Zwitterion (dipolar

More information

I. (42 points) A. Provide the step-wise, curved arrow mechanism for the following (OL 2007, 9, 385). OCH OCH 3

I. (42 points) A. Provide the step-wise, curved arrow mechanism for the following (OL 2007, 9, 385). OCH OCH 3 ame Page 1 F.08.215FEP1 I. (42 points) A. Provide the step-wise, curved arrow mechanism for the following (L 2007, 9, 85). a l B. Provide the step-wise, curved arrow mechanism for the following (JAS 2002,

More information

Describe how an azo dye can be made from phenylamine. Show the structure of the azo dye and the organic intermediate in your answer

Describe how an azo dye can be made from phenylamine. Show the structure of the azo dye and the organic intermediate in your answer 1. oloured organic compounds also include azo dyes. Describe how an azo dye can be made from phenylamine. Show the structure of the azo dye and the organic intermediate in your answer.........................

More information

CHEM J-3 June No. The molecule is linear so the dipoles in the C=O bonds cancel each other out.

CHEM J-3 June No. The molecule is linear so the dipoles in the C=O bonds cancel each other out. HEM1611 201-J-3 June 201 omplete the following table. 12 Molecule 2 S 2 Draw a Lewis structure ame the molecular geometry linear bent (approx 120 ) Does the molecule have a dipole moment? Give a reason

More information

Review of General & Organic Chemistry

Review of General & Organic Chemistry Review of General & Organic Chemistry Diameter of a nucleus is only about 10-15 m. Diameter of an atom is only about 10-10 m. Fig 3.1 The structure of an atom Periodic Table, shown below, is a representation

More information

NH 2. Biochemistry I, Fall Term Sept 9, Lecture 5: Amino Acids & Peptides Assigned reading in Campbell: Chapter

NH 2. Biochemistry I, Fall Term Sept 9, Lecture 5: Amino Acids & Peptides Assigned reading in Campbell: Chapter Biochemistry I, Fall Term Sept 9, 2005 Lecture 5: Amino Acids & Peptides Assigned reading in Campbell: Chapter 3.1-3.4. Key Terms: ptical Activity, Chirality Peptide bond Condensation reaction ydrolysis

More information

Loudon Chapter 24 Review: Carbohydrates Jacquie Richardson, CU Boulder Last updated 4/26/2018

Loudon Chapter 24 Review: Carbohydrates Jacquie Richardson, CU Boulder Last updated 4/26/2018 This chapter is about carbohydrates molecules with the general formula of C n( 2O) n, or in other words C n 2nO n. This is a very common formula for sugars and many other natural products. The structure

More information

Q.1 Draw structures for all amines of molecular formula C 4 H 11 N. Classify them as primary, secondary or tertiary amines.

Q.1 Draw structures for all amines of molecular formula C 4 H 11 N. Classify them as primary, secondary or tertiary amines. 1 AMIES Structure ontain the 2 group. lassification primary (1 ) amines secondary (2 ) amines tertiary (3 ) amines quarternary (4 ) ammonium salts + 1 2 3 4 Aliphatic Aromatic methylamine, ethylamine,

More information

Content : Properties of amino acids.. Separation and Analysis of Amino Acids

Content : Properties of amino acids.. Separation and Analysis of Amino Acids قسم الكيمياء الحيوية.دولت على سالمه د. استاذ الكيمياء الحيوية ٢٠١٥-٢٠١٤ المحاضرة الثانية 1 Content : Properties of amino acids.. Separation and Analysis of Amino Acids 2 3 Physical Properties of Amino

More information

ORGANIC - EGE 5E EXTRA: CARBOHYDRATES.

ORGANIC - EGE 5E EXTRA: CARBOHYDRATES. !! www.clutchprep.com CONCEPT: INTRODUCTION TO CARBOHYDRATE MONOSACCHARIDES Sugars or saccharides are also referred to as carbo-hydrates, implying that carbon has been combined with Monosaccharides are

More information

UCSC, Binder. Section TA. CHEM 108B Organic Chemistry II FINAL EXAM, Version B (400 points)

UCSC, Binder. Section TA. CHEM 108B Organic Chemistry II FINAL EXAM, Version B (400 points) UCSC, Binder Name Section TA SID CEM 108B rganic Chemistry II FINAL EXAM, Version B (400 points) In each of the following problems, use your knowledge of organic chemistry conventions to answer the questions

More information

Q.8. Isomers are the compounds that must have same

Q.8. Isomers are the compounds that must have same Choose the single correct answer for each of the following questions: (1 Mark each). Q. 1. ow many lone pairs are present in C 3 --C 3 i) 3 ii) 2 iii) 1 iv) 4 Q.2. When any hydrocarbon is added to water,

More information

Under strongly acidic conditions at ph = 1 every functional group in phosphoserine that can pick up a proton, does.

Under strongly acidic conditions at ph = 1 every functional group in phosphoserine that can pick up a proton, does. 1. (48 pts) a. L-Phosphoserine is a modified amino acid that is generated in proteins by phosphorylation of serine residues. The amino acid side chain has two acidic protons, which exhibit different pk

More information

CHEM1902/ N-9 November 2014

CHEM1902/ N-9 November 2014 CEM1902/4 2014-N-9 November 2014 The elimination of 2 O from alcohol A can form the isomeric alkenes B and C. Elimination of Br from the alkyl halide D can generate the same two alkenes. 7 Assign the absolute

More information

Partial Periodic Table

Partial Periodic Table EMITY 3331, pring 2005 Professor Walba Final Exam, May 3 U onor ode Pledge: n my honor, as a University of olorado at oulder tudent, I have neither given nor received unauthorized assistance. scores: 1)

More information

Importance of Carbohydrates

Importance of Carbohydrates Chapter 25 Importance of Carbohydrates Distributed widely in nature Key intermediates of metabolism (sugars) Structural components of plants (cellulose) Central to materials of industrial products: paper,

More information

A Plausible Model Correlates Prebiotic Peptide Synthesis with. Primordial Genetic Code

A Plausible Model Correlates Prebiotic Peptide Synthesis with. Primordial Genetic Code Electronic Supplementary Material (ESI) for ChemComm. This journal is The Royal Society of Chemistry 2018 A Plausible Model Correlates Prebiotic Peptide Synthesis with Primordial Genetic Code Jianxi Ying,

More information

Chapter 17 An Introduction to Organic Chemistry, Biochemistry, and Synthetic Polymers

Chapter 17 An Introduction to Organic Chemistry, Biochemistry, and Synthetic Polymers 267 Chapter 17 An Introduction to Organic Chemistry, Biochemistry, and Synthetic Polymers Review Skills 17.1 Organic Compounds Formulas for Organic Compounds Alkanes Alkenes Alkynes Arenes (Aromatics)

More information

B O C 4 H 2 O O. NOTE: The reaction proceeds with a carbonium ion stabilized on the C 1 of sugar A.

B O C 4 H 2 O O. NOTE: The reaction proceeds with a carbonium ion stabilized on the C 1 of sugar A. hbcse 33 rd International Page 101 hemistry lympiad Preparatory 05/02/01 Problems d. In the hydrolysis of the glycosidic bond, the glycosidic bridge oxygen goes with 4 of the sugar B. n cleavage, 18 from

More information

A. B. C. D. 2. Which compound does not give a stable Grignard reagent when reacting with Mg metal?

A. B. C. D. 2. Which compound does not give a stable Grignard reagent when reacting with Mg metal? Practice Test, Chemistry 2220 Final Exam 1. Which structure has the MST signals for its proton NMR? 2. Which compound does not give a stable Grignard reagent when reacting with Mg metal? 3. Which of these

More information

Proteins: Characteristics and Properties of Amino Acids

Proteins: Characteristics and Properties of Amino Acids SBI4U:Biochemistry Macromolecules Eachaminoacidhasatleastoneamineandoneacidfunctionalgroupasthe nameimplies.thedifferentpropertiesresultfromvariationsinthestructuresof differentrgroups.thergroupisoftenreferredtoastheaminoacidsidechain.

More information

===============================================================

=============================================================== Chemistry 3520 Exam 1, Fall 2010 =============================================== This is a closed book exam. The exam lasts 50 minutes. All answers must appear on the answer sheet. Only the answer sheet

More information

LECTURE 5: TYPES OF CARBOHYRATE LECTURE OUTCOMES

LECTURE 5: TYPES OF CARBOHYRATE LECTURE OUTCOMES LECTURE 5: TYPES OF CARBOHYRATE LECTURE OUTCOMES After completing this lecture and mastering the lecture materials, students are expected to be able 1. 2. 3. 4. 5. to explain the origin of plants carbohydrates

More information

Exam III. Please read through each question carefully, and make sure you provide all of the requested information.

Exam III. Please read through each question carefully, and make sure you provide all of the requested information. 09-107 onors Chemistry ame Exam III Please read through each question carefully, and make sure you provide all of the requested information. 1. A series of octahedral metal compounds are made from 1 mol

More information

Chem 332, Exam 4. Spring Provide reagents for the following transformations (2 pts each) NaOH , KOH. 4) H2/Pd NO 2. 1) AlCl 3 O 2) H 2 NNH 2

Chem 332, Exam 4. Spring Provide reagents for the following transformations (2 pts each) NaOH , KOH. 4) H2/Pd NO 2. 1) AlCl 3 O 2) H 2 NNH 2 AME 1. Provide reagents for the following transformations (2 pts each) 2 a 2 1) Al 3 2) 2 2, K h! 1) 3, 2) LDA 3) + 4) 2/Pd C 2 AME 2a Circle the correct product (no mechanisms or partial credit). 3 pts

More information

Regn. No. South Delhi : 28-A/11, Jia Sarai, Near-IIT Metro Station, New Delhi-16, Ph : ,

Regn. No. South Delhi : 28-A/11, Jia Sarai, Near-IIT Metro Station, New Delhi-16, Ph : , 1 2. Section-A contains 30 Multiple Choice Questions (MCQ). Each question has 4 choices,, and, for its answer, out of which LY E is correct. From Q.1 to Q.10 carries 1 Marks and Q.11 to Q.30 carries 2

More information

Chapter 2: Chemistry. What does chemistry have to do with biology? Vocabulary BIO 105

Chapter 2: Chemistry. What does chemistry have to do with biology? Vocabulary BIO 105 Chapter 2: Chemistry What does chemistry have to do with biology? BIO 105 Vocabulary 1. Matter anything that takes up space and has mass Atoms are the smallest units of matter that can participate in chemical

More information

Theme 6 and 7 Carbonyl Compounds & Carbohydrates

Theme 6 and 7 Carbonyl Compounds & Carbohydrates Theme 6 and 7 Carbonyl Compounds & Carbohydrates R C Aldehyde Smith: rganic Chemistry Extracts from Chapters 19, 20, 21, 22 and 27 C 2 Sucrose R C Ketone R' C R R' Ester R C Carboxylic acid C R N Amide

More information

(07) 2 (c) 2 (c) (i) Calculate the ph of this buffer solution at 25 oc (3 marks) (Extra space)

(07) 2 (c) 2 (c) (i) Calculate the ph of this buffer solution at 25 oc (3 marks) (Extra space) 7 The value of Ka for methanoic acid is 1.78 10 4 mol dm 3 at 25 oc. A buffer solution is prepared containing 2.35 10 2 mol of methanoic acid and Question 1: N/A 1.84 10 2 mol of sodium methanoate in 1.00

More information

Department of Chemistry SUNY/Oneonta. Chem Organic Chemistry II Examination #4 - May 5, 2003 ANSWERS

Department of Chemistry SUNY/Oneonta. Chem Organic Chemistry II Examination #4 - May 5, 2003 ANSWERS Department of hemistry SUY/neonta hem 322 - rganic hemistry II Examination #4 - May 5, 2003 ASWERS ISTRUTIS This examination is in multiple choice format and the answers should be placed on the "Test Scoring

More information

PHARMACEUTICAL CHEMISTRY EXAM #1 Februrary 21, 2008

PHARMACEUTICAL CHEMISTRY EXAM #1 Februrary 21, 2008 PHARMACEUTICAL CHEMISTRY EXAM #1 Februrary 21, 2008 1 Name SECTION B. Answer each question in this section by writing the letter corresponding to the best answer on the line provided (2 points each; 60

More information

O H HO H. !-D-galactopyranose

O H HO H. !-D-galactopyranose ame Key W06-Exam o. Page I. ( points) A disaccharide is cleaved by a β-glycosidase, an enzyme that specifically hydrolyzes a β- glycosidic linkage. When the disaccharide is treated with excess dimethyl

More information

CHEM1907/ J-2 June 2003

CHEM1907/ J-2 June 2003 EM1907/8 2003-J-2 June 2003 omplete the following table. Give, as required, the formula, the systematic name and the principal ions present in a solution prepared by adding the substance to water. For

More information

A-level CHEMISTRY (7405/2)

A-level CHEMISTRY (7405/2) SPECIMEN MATERIAL A-level CHEMISTRY (7405/2) Paper 2: Organic and Physical Chemistry Specimen 2015 Session Time allowed: 2 hours Materials For this paper you must have: the Data Booklet, provided as an

More information

Chemistry in Living Systems. By Dr. Carmen Rexach Physiology Mt SAC Biology Department

Chemistry in Living Systems. By Dr. Carmen Rexach Physiology Mt SAC Biology Department Chemistry in Living Systems By Dr. Carmen Rexach Physiology Mt SAC Biology Department Matter and Energy Definitions Types of energy Kinetic vs. potential Forms of energy Chemical Ex: ATP Electrical Ex:

More information

Chemical Properties of Amino Acids

Chemical Properties of Amino Acids hemical Properties of Amino Acids Protein Function Make up about 15% of the cell and have many functions in the cell 1. atalysis: enzymes 2. Structure: muscle proteins 3. Movement: myosin, actin 4. Defense:

More information

1/23/2012. Atoms. Atoms Atoms - Electron Shells. Chapter 2 Outline. Planetary Models of Elements Chemical Bonds

1/23/2012. Atoms. Atoms Atoms - Electron Shells. Chapter 2 Outline. Planetary Models of Elements Chemical Bonds Chapter 2 Outline Atoms Chemical Bonds Acids, Bases and the p Scale Organic Molecules Carbohydrates Lipids Proteins Nucleic Acids Are smallest units of the chemical elements Composed of protons, neutrons

More information

Chapter 2 The Chemistry of Life

Chapter 2 The Chemistry of Life Chapter 2 The Chemistry of Life I. Water Liquid Naturally occurring It expands liquid to solid Covers more than 75% of our surface Most abundant in living organisms most important inorganic compound for

More information

Chapter 25 Organic and Biological Chemistry

Chapter 25 Organic and Biological Chemistry Chapter 25 Organic and Biological Chemistry Organic Chemistry The chemistry of carbon compounds. Carbon has the ability to form long chains. Without this property, large biomolecules such as proteins,

More information

Exam I Answer Key: Summer 2006, Semester C

Exam I Answer Key: Summer 2006, Semester C 1. Which of the following tripeptides would migrate most rapidly towards the negative electrode if electrophoresis is carried out at ph 3.0? a. gly-gly-gly b. glu-glu-asp c. lys-glu-lys d. val-asn-lys

More information

Experiment 8 Optical Isomers. In this experiment you will be given the opportunity to see the 3-dimensional aspects of

Experiment 8 Optical Isomers. In this experiment you will be given the opportunity to see the 3-dimensional aspects of Experiment 8 Optical Isomers In this experiment you will be given the opportunity to see the 3-dimensional aspects of stereochemistry and optical isomers. Previously in class you were exposed to the concept

More information

Chapter 2 Chemical Aspects of Life

Chapter 2 Chemical Aspects of Life Chapter 2 Chemical Aspects of Life Multiple Choice Questions 1. Anything that has weight and occupies space can be described as A. an atom. B. matter. C. a compound. D. a molecule. #1 Learning Outcome:

More information

ORGANIC - BROWN 8E CH AMINO ACIDS AND PROTEINS.

ORGANIC - BROWN 8E CH AMINO ACIDS AND PROTEINS. !! www.clutchprep.com CONCEPT: INTRODUCTION TO PROTEINS Proteins are polypeptides that have some biological function. Peptides are composed of polymers of monomeric units called α-amino acids The 20 most

More information

UCSC, Binder. CHEM 8B Organic Chemistry II FINAL EXAM, Version A (300 points)

UCSC, Binder. CHEM 8B Organic Chemistry II FINAL EXAM, Version A (300 points) UCSC, Binder TA Name SID CEM 8B rganic Chemistry II FINAL EXAM, Version A (300 points) In each of the following problems, use your knowledge of organic chemistry conventions to answer the questions in

More information

CHEMISTRY 1A Fall 2010 Final Exam Key

CHEMISTRY 1A Fall 2010 Final Exam Key CHEMISTRY 1A Fall 2010 Final Exam Key YOU MIGHT FIND THE FOLLOWING USEFUL; 0.008314 kj H E ( n)rt R = K mol 0.00418 kj q C cal m w T g C H rxn = H f (products) H f (reactants) Electronegativities H 2.2

More information

KJM 3200 Required Reading (Pensum), Fall 2016

KJM 3200 Required Reading (Pensum), Fall 2016 KJM 3200 Required Reading (Pensum), Fall 2016 John McMurry: Organic Chemistry 8 nd ed. or Paula Y. Bruice, Organic Chemistry 7 nd ed. as specified below, as specified below. Lise-Lotte Gundersen KJM 3200.

More information

Final Exam. Chem 3B, Fall 2016 Monday, Dec 12, pm. Name Answer Key. Student ID. If you are making up an incomplete, list the semester here:

Final Exam. Chem 3B, Fall 2016 Monday, Dec 12, pm. Name Answer Key. Student ID. If you are making up an incomplete, list the semester here: Final Exam Chem 3B, Fall 2016 Monday, Dec 12, 2016 3-6 pm ame Answer Key Student ID If you are making up an incomplete, list the semester here: You have 180 minutes to complete this exam. Please provide

More information

GOVERNMENT COLLEGE (AUTONOMOUS), RAJAMAHENDRAVARAM DEPARTMENT OF CHEMISTRY CBCS Syllabus for B.Sc. III Year Effective from onwards

GOVERNMENT COLLEGE (AUTONOMOUS), RAJAMAHENDRAVARAM DEPARTMENT OF CHEMISTRY CBCS Syllabus for B.Sc. III Year Effective from onwards GOVERNMENT COLLEGE (AUTONOMOUS), RAJAMAHENDRAVARAM DEPARTMENT OF CHEMISTRY CBCS Syllabus for B.Sc. III Year Effective from 2018 2019 onwards Paper VI Semester V Applied Physical Chemistry and Organic Chemistry

More information

UCSC, Binder. CHEM 8B Organic Chemistry II FINAL EXAM (300 points)

UCSC, Binder. CHEM 8B Organic Chemistry II FINAL EXAM (300 points) UCSC, Binder Name CEM 8B rganic Chemistry II FINAL EXAM (300 points) In each of the following problems, use your knowledge of organic chemistry conventions to answer the questions in the proper manner.

More information

1014NSC Fundamentals of Biochemistry Semester Summary

1014NSC Fundamentals of Biochemistry Semester Summary 1014NSC Fundamentals of Biochemistry Semester Summary Griffith University, Nathan Campus Semester 1, 2014 Topics include: - Water & ph - Protein Diversity - Nucleic Acids - DNA Replication - Transcription

More information

Chapter 4: Amino Acids

Chapter 4: Amino Acids Chapter 4: Amino Acids All peptides and polypeptides are polymers of alpha-amino acids. lipid polysaccharide enzyme 1940s 1980s. Lipids membrane 1960s. Polysaccharide Are energy metabolites and many of

More information

Chemistry of Life 10/1/2010. What makes up the chemistry of life?

Chemistry of Life 10/1/2010. What makes up the chemistry of life? A. Students will be able to identify and define the parts of an atom. Chemistry of Life At the Completion of this Unit, Students will be able to: A. Identify and define the parts of an atom. B. Demonstrate

More information

(R)-(+)-thalidomide. optical rotation = -63 2% H 2 SO 4 /H 2 O room temp. (S)-(-)-thalidomide

(R)-(+)-thalidomide. optical rotation = -63 2% H 2 SO 4 /H 2 O room temp. (S)-(-)-thalidomide I. (22 points) (a) ame Page 1 F.0.21e3p1 In the mid/late 190s, mainly in Europe, a racemic mixture of thalidomide (see below) was prescribed to alleviate "morning sickness" in first trimester pregnant

More information

Theophylline (TH), the structure of which is presented below, is a bronchial-dilator used for the treatment of asthma.

Theophylline (TH), the structure of which is presented below, is a bronchial-dilator used for the treatment of asthma. 1 EXAM SCIETIIC CULTURE CEMISTRY PRBLEM 1: Theophylline (T), the structure of which is presented below, is a bronchial-dilator used for the treatment of asthma. 3 C 7 1 3 9 1.1 Structural study and acid-base

More information

Level 3 Chemistry, 2017

Level 3 Chemistry, 2017 91391 913910 3SUPERVISOR S Level 3 Chemistry, 2017 91391 Demonstrate understanding of the properties of organic compounds 2.00 p.m. Wednesday 15 November 2017 Credits: Five Achievement Achievement with

More information

(4) (5) (6) a. b. H. explanation: explanation:

(4) (5) (6) a. b. H. explanation: explanation: ame Key 15 W11-Exam o. Page I. (15 points) For each of the following pairs of compounds, predict which compound is more acidic. Compare the two underlined s for each pair and circle the compound that is

More information

Full file at https://fratstock.eu

Full file at https://fratstock.eu VanMeter: Microbiology for the Healthcare Professional Chapter 02: Chemistry of Life Test Bank MULTIPLE CHOICE 1. The atomic number equals the number of a. Protons b. Neutrons c. Electrons d. Protons and

More information

Chem 14C Lecture 1 Spring 2017 Final Exam Part B Page 1

Chem 14C Lecture 1 Spring 2017 Final Exam Part B Page 1 Chem 14C Lecture 1 Spring 2017 Final Exam Part B Page 1 1. (2) Write the letter of the structure that best fits the following 13 C-NMR spectrum: 51 ppm (doublet), 44 ppm (triplet), 27 ppm (quartet), 26

More information

CHEMISTRY 1A Spring 2010 Final Exam Key

CHEMISTRY 1A Spring 2010 Final Exam Key CHEMISTRY 1A Spring 2010 Final Exam Key YOU MIGHT FIND THE FOLLOWING USEFUL; 0.008314 kj ΔH = ΔE + (Δn)RT R = K mol 0.00418 kj q = C cal + mw T K mol H rxn = Σ H f (products) Σ H f (reactants) Electronegativities

More information

Human Biology. The Chemistry of Living Things. Concepts and Current Issues. All Matter Consists of Elements Made of Atoms

Human Biology. The Chemistry of Living Things. Concepts and Current Issues. All Matter Consists of Elements Made of Atoms 2 The Chemistry of Living Things PowerPoint Lecture Slide Presentation Robert J. Sullivan, Marist College Michael D. Johnson Human Biology Concepts and Current Issues THIRD EDITION Copyright 2006 Pearson

More information

INTRODUCTION. Amino acids occurring in nature have the general structure shown below:

INTRODUCTION. Amino acids occurring in nature have the general structure shown below: Biochemistry I Laboratory Amino Acid Thin Layer Chromatography INTRODUCTION The primary importance of amino acids in cell structure and metabolism lies in the fact that they serve as building blocks for

More information

Section Week 3. Junaid Malek, M.D.

Section Week 3. Junaid Malek, M.D. Section Week 3 Junaid Malek, M.D. Biological Polymers DA 4 monomers (building blocks), limited structure (double-helix) RA 4 monomers, greater flexibility, multiple structures Proteins 20 Amino Acids,

More information

Chapter 2 The Chemistry of Biology. Dr. Ramos BIO 370

Chapter 2 The Chemistry of Biology. Dr. Ramos BIO 370 Chapter 2 The Chemistry of Biology Dr. Ramos BIO 370 2 Atoms, Bonds, and Molecules Matter - all materials that occupy space and have mass Matter is composed of atoms. Atom simplest form of matter not divisible

More information

Amines Reading Study Problems Key Concepts and Skills Lecture Topics: Amines: structure and nomenclature

Amines Reading Study Problems Key Concepts and Skills Lecture Topics: Amines: structure and nomenclature Amines Reading: Wade chapter 19, sections 19-1-19-19 Study Problems: 19-37, 19-39, 19-40, 19-41, 19-44, 19-46, 19-47, 19-48, 19-51, 19-54 Key Concepts and Skills: Explain how the basicity of amines varies

More information