BACHELOR OF SCIENCE (B.Sc.) Term-End Examination June, 2018

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1 No. of Printed Pages : 12 I CHE-04 C C1 BACHELOR OF SCIENCE (B.Sc.) Term-End Examination June, 2018 CHEMISTRY CHE-04 : PHYSICAL CHEMISTRY Time : 2 hours Maximum Marks : 50 Note : Attempt all the parts. Answer five questions from each of the parts A, B, C and D. Use of log tables is permitted. Use of non-programmable calculators is allowed. PART A Answer any five of the following questions : 5x1=5 1. State Trouton's rule Define an adiabatic process What is meant by entropy of a system? 1 4. Define Chemiluminescence. 1 CHE-04 1 P.T.O.

2 5. Give the phase rule equation. 6. Name the methods for finding the transport number. 7. What are the units of second order rate constant? CHE-04 2

3 PART B Answer any five of the following questions : 5x2=10 8. The gas supplied for household use is mostly a mixture of propane and butane. Are the critical temperatures of these gases higher than 298 K? Justify your answer Rice, dal and vegetables are cooked faster inside a pressure cooker than in an open vessel. Explain the reason What are buffer solutions? Give an example Express the equilibrium constant for the reaction CO (g) + 2H 2 (g) CH3OH (g) in terms of extent of reaction, 12. Draw and explain the titration curve for conducto-metric titration for Strong Acid vs Strong Base State Hess's law of constant heat summation. 14. Can azeotropes be separated into pure components by fractional distillation? Justify your answer. 2 CHE-04 3 P.T.Q.

4 PART C Answer any five of the following questions : 5x3= Starting from du = TdS -pdv, derive rar± 117)s = (Z)v Derive Bragg's equation : n2 = 2d sin What is common ion effect? Explain its role in precipitation of cations in qualitative analysis Predict which of the following reactions will be spontaneous, with the help of standard potential values : 3 (a) Fe + 2H+ ---> Fe 2+ + H2 E = 0.44 V Fe2+/Fe (b) Cu + 2H+ ---> Cu + H2 E = V (c) 2Fe > 2Fe E = V I 2/I E = V Fe 3+/Fe` ± CHE-04 4

5 19. Derive Nernst's distribution law thermodynamically. 20. Using the value of p c = x le Pa, Vc = 99.0 x 106 m3 mo1-1, calculate the reduced temperature of a gas if it occupies 5 x 10-2 m3 5 Pa. space at x Arrange the following compounds in the increasing order of boiling points : Ethanol, glycerol and ethylene glycol Justify your answer. 3 CHE-04 5 P.T.O.

6 PART D Answer any five of the following questions : 5x4= Derive the following expression for an ideal gas : 4 1 _ pv = 3 m N u 23. Explain the difference between fluorescence and phosphorescence. 24. Describe the Lindemann and Hinshelwood mechanism to explain the unimolecular decomposition reaction Draw and explain the phase diagram of sulphur Derive the expression for Langmuir adsorption isotherm Calculate the entropy of mixing of 1 mol of 112 with 2 mol of 02. Assume that no chemical reaction occurs. 28. The boiling point of chloroform was raised by K when 5.15 x 10-4 kg of an organic compound was dissolved in 3.5 x 10-2 kg of chloroform. Calculate the molar mass of the organic compound. Molar Elevation constant for chloroform is 3.90 K kg morl. 4 CHE-04 6

7 din ti Inch (41.7r Tft. ) Tr-I-M.76v T-4, 2018 TRIER Ido in 4% : Tfrgi4 04,14 : 2 EITTJ 3#11W6 37 al*w : 50 Tie. : gift 37 3R?" er-47 l w, Zs7, 7T ark RR* 1PT lifw-glw Nr4.77 JR? j1/ IRfIT fll(pled HP/ 41 37Y/Td. */ 31thrArltel 4,e-g)rie(?* Ptirf 1 ari-ga / A..il(Wort # TIN. TR-4T 4- JR?' e-r-4q : 5x feur 1 2. tog mstoi merr ti* 3. cran TEFF 311f? 4. titheipth t.i41 tr-4 CHE-04 7 P.T.O.

8 5. mier-9-tt 14H w-ncniut A-dT-4 I 6. 3TrITT14-44* fetpal TIT fo -FuR 7. t#4.111 itzrd**eff 1114)? CHE-04 8

9 Pi-ifCiRoa # 4 ATef - drit 5x2=10 8. It d kit1) 41 * t 3T111-*7( M A vl-7 T wrr1.11 Wftf 298 K 3TR-T? T *r W-47 I 9. 3cm vaci, 3R 1T Ac-41 t 4.) oeutsen *INR I fiWt f4fzir TM.? dcwul tr4r I TWAT CO (g) (g) CH3OH (g) FT "Fq Trp:Er oem Ar--4R c1 3 TCF 3 74F k-tt1 * KichcArne4 31illTER * 391:17R Witrff Ai* dticn *I-N7 I 'f W2TK daiii-kichcl-i l H -PAR 14. Tf -PaTRzfraft *WI SEITTIt 31T1M TKT d-14 lidct>1 TraTT 6eil? 3 3fft *A7 CHE-04 9 P.T.O.

10 UM TT 14s-i drit 007. : 5x3= du = TdS - pdv 34T4T cht AH WA-R : a), - ( ys)v 16. ATI chtui, na= 2d sin e "09-01W *1177 ( T11: R NITT4 clqc)tiul 4 at44crur *k-41 itrwr *1-044Kgen WA -R i-lcb 1-41-T4 Trr-41 4't ieiril wa-r-4-r PiHroRgo A t al-r : 6 : (a) Fe + 2H+ Fe2+ + H2 E Fe 2+/ = 0.44 V (b) Cu + 2H+ Cu2+ + H2 E 0 c11 4-V al = V (c) 2Fe3+ + 2F 2Fe E 1 2 /1- = V E = V Fe 3+/Fe 2+ CHE-04 10

11 19. 4 ikdtat 3aiiii6bi:9-eciff WA I *fit ti pc = x le Pa at Vc = 99.0 x 106 -m3 mor1 *TR "*1 3RIITT cbt; x 105 Pa tft 3ticbi 1:11:14rd TV' N cict A.N7, zft 5 x 10-2 m3 3iTzrd'9 kt PH ci ctzir10 314) rsit3i4 oticiplo *P4R : 3T:A -R2Wra ', fir kikto Wall q Aziwtai CHE P.T.O. J

12 (-Hort A7-f qfw5r-j drl< 5x4= %7413JT ker PHRIRsid t1i(14)tu1 mj-ezrff AT-4R : pv.- 3 mnu 23. Sfr-dāft:i atit PF-dtRF Atq' 34( *1' 00-11(sAi *Ii-47 I 24. L q I1,3'act.) atcrern atrtftzfr *1 - oii(9,41* R1 rrl ~~li ~l atit fr4wg -Wirr-4RT 0* I 25. TTY 5T 1TaTiliZi A od ill ATTIT alfilatfur (1 1-1(114 co-1 71ch 9c:ff *I* I ztx1 H -k wr( ml twitipieb 34141*-41. Ter 6icn t, 1 4.1)C1 H2 *I. 2 ii)ci 02 f43p4-7-4flft 1-11kct)R1C1 4:11-47 I x 10-2 kg crk-q x 10-4 kg chicipich Art- 'El)--M4 ct.--n14;14 wzi-qk K A-4 TRIT I cblench zrift kirci, *li* ct\-q,4,74 dw.1.1 W2R-k 3.90 K kg morl t I 4 CHE ,500

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