Narayana IIT Academy

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Narayaa IIT Academy INDIA XII_IC_SPARK JEE-MAIN Date: 3-7-7 Time : 3 Hours CPT -5 Ma Marks : 36 KEY SHEET PHYSICS ) B ) C 3) A 4) C 5) B 6) A 7) A 8) C 9) D ) A ) B ) C 3) D 4) B 5) A 6) A 7) C 8) C

1 Narayaa IIT Academy INDIA XII_IC_SPARK JEE-MAIN Date: Time : 3 Hours CPT -5 Ma Marks : 36 KEY SHEET PHYSICS ) B ) C 3) A 4) C 5) B 6) A 7) A 8) C 9) D ) A ) B ) C 3) D 4) B 5) A 6) A 7) C 8) C 9) A ) D ) C ) C 3) A 4) B 5) A 6) D 7) B 8) B 9) C 3) B CHEMISTRY 3) D 3) D 33) D 34) B 35) D 36) D 37) C 38) C 39) A 4) D 4) D 4) B 43) A 44) A 45) A 46) B 47) C 48) C 49) B 5) D 5) D 5) B 53) C 54) B 55) D 56) D 57) A 58) A 59) B 6) C MATHEMATICS 6) B 6) A 63) C 64) A 65) C 66) B 67) B 68) C 69) C 7) C 7) D 7) C 73) B 74) C 75) B 76) B 77) A 78) B 79) D 8) A 8) B 8) C 83) A 84) A 85) B 86) A 87) D 88) D 89) A 9) B

2 Narayaa IIT Academy XII-IC-Spark_CPT-5 [ 3/7/7]. B E 6 PHYSICS V V.. C I is maimum at a certai frequecy. This frequecy is called resoace requecy. 3. A VC ad VL f. f 4. C Sice the capacitor is coected i series to the resistor, the curret I C from the supply ad I R through the resistor is i phase as represeted by choice a. 5. B Iput power = V 5A= W Output power = V 9A=99 W 9 Efficiecy A N Give N E i N Also E i N 4 i A 56. i.a i. 7. A Here, V L =V C. They are i opposite phase. Hece they will cacel each other. Now the resultat potetial differece = applied potetial differece = volt Z=R Z = R ( X L X C ) Vrms Vvrm Lrms Z R 5 = A 8. C The curret draw by iductor ad capacitor will be i opposite phase. Hece, et curret draw by the geerator IL IC.9.4 =.5 A. 9. D The voltage across L & C are i opposite phase so they cacel out each other.. A Sr. IIT-IZ JEE JEE-MAIN Solutios Page

3 Narayaa IIT Academy XII-IC-Spark_CPT-5 [ 3/7/7] Two emfs, each of value Blv, are produced. Both the emfs. Ted to sed curret i the same directio. So, they are added up.. B V V V C R VR 5 V R VR V Also, IV R X Flu XC ad use C=3.3 F.. C C X C, fid C, C V V V 6 rms IV 5, I 4A V Pav IVR 3. D Vrms 6 3V 6IV I V.5A 5 I V, X L 8 6 X L X Now, VL I V.XL 8 4V. 4. B Let I ad I be the currets through B ad B the I R X L R I R X C c I R X R L L C R 4 / R 9.87, I I Bulb B will be brighter. As frequecy icreases X C decreases ad becomes less ad I icreases. brightess of B will icrease ad that of B decreases. X L icreases. I Sr. IIT-IZ JEE JEE-MAIN Solutios Page 3

4 Narayaa IIT Academy XII-IC-Spark_CPT-5 [ 3/7/7] 5. A EL LI d E di L LI dt dt At t=, I=. The del dt di At t,i I therefore, rate = dt 6. A Accordig to Fermat's pricipal of least time, the light takes miimum time to travel from oe poit to aother eve after a umber of reflectios or refractios. 7. C As is clear from the figure the ew distace is v. The distace of image from the object is reduced by a amout v i oe secod. 8. B Clearly, plae mirror ad cove mirror caot produce iverted image. 9. A o Clearly, i r i i 4 or i=7 Clearly, plae mirror makes a agle of with the vertical ad 7 with the horizotal.. D Clearly, the distace of image from observer is 4 cm.. C C 8 o o 8 o radia 3. A Sr. IIT-IZ JEE JEE-MAIN Solutios Page 4

5 Narayaa IIT Academy XII-IC-Spark_CPT-5 [ 3/7/7] I f d u d or I f u or I f 4. B Now, u cm, v=4 cm f 4 or f = 5 cm 5. A Miimum legth of plae mirror height of ma 8cm 9cm 6. D I would act as a object for the plae mirror. Clearly, the image is formed at a distace f i frot of the mirror. 7. B or or f= cm. f f 8. B or u v f v u f Now, compare with y=m+c. 9. C Usig,V f / u v f 3. B 3 or 3 u 4 3 u u 3 cm 9cm or Sr. IIT-IZ JEE JEE-MAIN Solutios Page 5

6 Narayaa IIT Academy XII-IC-Spark_CPT-5 [ 3/7/7] 3. D Cu Cu 4e (cathode) H O O 4H (aode) 4e H SO H SO D O electrolysis of 5% H SO 4 H SO H HSO 4 4 H e H (cathode) HSO H S O e (aode) 4 8 CHEMISTRY 33. D Life spa ca be icreased by icreasig the size of aode electrode. 34. B Icrease i coc. Of cathode i icreases the voltage. 35. D 36. D G e H G FE 37. C M 5.5 = C.59 / ECell Ecell log p H.p O 39. A Fe + /Fe acts as aode; Fe of 4. D Fe Fe e (Aode) / Fe 3 Fe e Fe Cathode Ad Thus if Fe Fe 3Fe 3 acts as cathode. 3 Fe,Fe ad Fe block are kept together 3 Fe decreases. I this equatio.59 E E log H E.59 = =.48 V. 4. D log H E.59 ph 3 Fe get reduced to Fe i.e., cocetratio Sr. IIT-IZ JEE JEE-MAIN Solutios Page 6

7 Narayaa IIT Academy XII-IC-Spark_CPT-5 [ 3/7/7] 4. B Ag Ag le / Cl e Cl G G G Pr oduct Reac ta t G FE G E. F 43. A.59 E log A s ; Ksp 7S 45. A m As the cell is a cocetratio cell, Now, the cell reactio is Left electrode : H P 64mm H P mm 4 Now, from Nerst equatio log.5v B ClO H O 4e ClO 4OH 3 ClO H O e Cl OH Cl e Cl ClO 3H O 6e Cl 6OH 3 3 Ecell G G G G ; G FE 6FE 4F.54 F.45 F E C o G G G 3 H e AgCl H Ag Cl.59 Ecell. log H Cl 48. C Sr. IIT-IZ JEE JEE-MAIN Solutios Page 7

8 Narayaa IIT Academy XII-IC-Spark_CPT-5 [ 3/7/7] If EMF of the battery less tha EMF of electro chemical cell the curret flows from electrochemical cell to battery. 49. B 5. D Apply electrochemical process of corrosio of iro to form hydrated ferric oide (Fe O 3.H O). 5. D 5. B KCl strog electrolyte CH 3 COOH weak electrolyte 53. C 54. B Whe lead accumulator is chargig it acts as electrolytic cell durig dischargig it acts as electrochemical cell. 55. D 56. D 57. A Depeds o hydratio 58. A k / coc.. CH COO H O B M M =3Mole/Litre=6 Moles Per Litres. 6. C 5965 Mole of OH formed B 6. A a a usig formula Give series 63. C g() = - g(a ) f d f a d r Lt r Clearly I vaishes if ga g MATHEMATICS Sr. IIT-IZ JEE JEE-MAIN Solutios Page 8

9 Narayaa IIT Academy XII-IC-Spark_CPT-5 [ 3/7/7] 64. A 65. C 66. B 67. B 68. C 69. C 7. C 7. D 7. C 73. B 74. C d Put t, d dt, e d I e d. Give e log d e a log d Give = Usig formula cos si d cos si d Use d a e f f d e f cos > si, / 4 Give series lim 5 r r 3 I cos d 3 Put t I t t cos t dt / I si d d e d / 3 Sr. IIT-IZ JEE JEE-MAIN Solutios Page 9

10 Narayaa IIT Academy XII-IC-Spark_CPT-5 [ 3/7/7] 75. B 76. B 77. A Apply f(a+b ) formula. I cot d,i cot d I I cot d cot d d /4 I ta ta d /4 g ta sec d si 4t si 4 cos 4tdt 4 4 si 4t g cos 4tdt 4 si 4 si g cos4t dt ; g g g g g g B Let 79. D 3 3 f d d / /!! y lim lim 3 log y lim.log..... lim log log...log r lim log log d r Sr. IIT-IZ JEE JEE-MAIN Solutios Page

11 Narayaa IIT Academy XII-IC-Spark_CPT-5 [ 3/7/7] Usig Leibitz rule. 8. A Put =ta 8. B k log ; /4 8. C /4 log ta d log 8 ta d d d log ta d log 8 ta A Usig reductio formula 84. A si d si d ( The itegral is a eve fuctio of ) Now si si 85. B Whe =, y=, Slope = A y / I I f si si cos d 87. D 88. D /4 f si cos d 4 /4 /4 f cost cos t dt I 4si / 4si / I si / d; / 3 Sr. IIT-IZ JEE JEE-MAIN Solutios Page

12 Narayaa IIT Academy XII-IC-Spark_CPT-5 [ 3/7/7] 89. A Replace by - we get f(4 ) = f() hece f(4+)=f()period f() is I f d f d f d f 48 d 5 5 let b a 9. B t ad use b f d f a b d, the a applyig L' Hospital rule, we get 3 I l 4 Sr. IIT-IZ JEE JEE-MAIN Solutios Page

What is the oxidation number of N in KNO3? Today. Review for our Quiz! K is +1, O is -2 molecule is no charge 1(+1) + 3(-2) = -5 N must be +5

What is the oxidation number of N in KNO3? Today. Review for our Quiz! K is +1, O is -2 molecule is no charge 1(+1) + 3(-2) = -5 N must be +5 Today What is the oxidatio umber of N i KNO3? Review for our Quiz! Thermo ad Electrochemistry What happes whe the coditios are ot stadard Nerst Equatio! A.!! 0! B.!! +1! C.!! -1! D.!! +3! E.!! +5 K is