Lecture 8 Multiple Choice Questions :
|
|
- Melinda Jefferson
- 6 years ago
- Views:
Transcription
1 Lecture 8 Multiple Choice Questions : 1. A point charge -3Q lies at the centre of a conducting shell of radius 2R. The net charge on the outer surface of the shell is -3Q Zero +1.5 Q d. +3Q 2. Two identical spherical conductors A and B of radius R, each carrying a charge Q are kept at some distance from each other. A third spherical conductor C, initially uncharged, is first brought into contact with A and then with B before finally being removed to a far away distance. If the charge on C is (10/9)Q, the radius of C is R/5 R/3 R/2 d. 2R identical spherical drops of mercury are combined to form a large drop. If the potential of each smaller drop is 1 V, the potential of the final drop is 1 V 4 V 16 V d. 64 V 4. Infinite number of charges of equal magnitude Q are placed along the axis at distances a, 2a, 3a,.from the origin. If the charges alternate in sign and the charge closest to the origin is positive, the potential at the origin due to the charge distribution is d. Zero 5. Three charges, Q, q and q are arranged at the vertices of a right angled isosceles triangle of base If the charge Q are fixed, the configuration has minimum electrostatic energy when q is equal to Q QQ2+12 q q
2 d. 6. The electric potential in a region along the x axis varies with distance x (in meters) as (Volts). The force acting on a 1µC charge located at N along the positive x axis N along the negative x axis N along the positive x axis d. N along the negative x axis 7. Four electric charges +q, +q, q and q are placed at the corners of a square of side 2L (see figure). The electric potential at point A, midway between the two charges +q and +q, is d. Zero 8. Two uniformly charged concentric rings of radii R and 2R are placed on a plane. Each ring has a charge density λ. The electric potential at the centre of the rings is d. 9. A hemisphere of radius R is charged with a uniform surface charged density s on its curved surface. The potential the centre is d. 10. A hollow metal sphere of radius R is charged to a potential of 10 V on its surface. What is the potential at the centre of the sphere? is
3 Zero +10 V -10 V d. Same as its value outside at a distance of R from the surface of the sphere. Answers to Multiple choice questions: 1. (a) 2. (d) 3. (c) 4. (c) 5. (c) 6. (d) 7. (b) 8. (c) (9) (b) 10. (b) Problems 1. A uniformly charged sphere of radius R contains a charge Q. Choose the origin of coordinate system at the centre of the sphere and let V(0)=0. Find an expression for the potential both inside and outside the sphere. 2. Two identical metal plates have area 1 m 2 each and are separated by 3 cm. Initially both are uncharged. A charge of 2 nc is transferred from the plate on the left to the plate on the right and equilibrium is allowed to be established. Neglecting edge effects, calculate the electric field (a) in the region II between the plates at a distance of 0.5 cm from the plate to the right and (b) at points to the immediate left of the plate on the left (region I) and at points to the immediate right of the plate to the right in region III. I II III 3. Two identical thin rings, each of radius R, are placed coaxially at a distance R from each other. The rings carry charges Q 1 and Q 2 uniformly spread over the rings. Find the work done in removing a charge q from the centre of the first ring to that of the second ring. 4. A metal sphere of radius R carrying a charge q is surrounded by a thick concentric conducting shell of radii a and The shell has no charge. Calculate the charge densities on the metal sphere as well as on the inside and outside surface of the shell. With the reference of the potential at infinite distances, determine the potential at thecentre of the sphere. If now, the outer surface of the shell is grounded, what will be the potential at the centre of the sphere?
4 5. A metal sphere of radius R has two spherical cavities of radii a and The former has a charge q at the centre of the cavity while the latter has a charge Q at its centre. Find the charge densities in the interior of the two cavities and on the outside surface of the sphere. Also determine the field outside the sphere at a distance r from the centre of the sphere. 6. Potential on the surface of a sphere is 400 V and its value drops to 100 V at a distance of 60 cm from the surface. Calculate the radius of the sphere and the amount of charge contained in the sphere. 7. Two equal charges q are located at a distance 2d apart. Find the expression for the electric potential at a distance of z along the perpendicular bisector of the line joining the two charges. Using this determine the electric field at that point. 8. A metal sphere of radius R carries a charge Q. Surrounding this is a concentric metallic shell of inner radius 2R and outer radius 3R. If the shell carries a total charge 3Q, find the potential for r<r. 9. Can an electric field be given by the expression? 10. How much work is done in moving a 0.5nC charge on the surface of a sphere of radius 2m from an initial position to a final position The electrostatic field in the region is given by (in V/m). Hints for solutions to Problems 1. Electric field is known from Gauss s law to be for r <R and for r>r. For r<r,. For r>r, take the corresponding expression for the field for outside the sphere and integrate from the surface of the sphere to the point where the potential is to be found. We get 2. The charge on the left plate is -2nC and on the right plate is +2nC. Without assuming that the final charges are on the faces of plate facing each other, we can assume that the charge density on the left plate (plate 1) is σ 1L on its left face and σ 1R on its right face. Likewise, the charge density on the right plate (plate 2) are σ 2L and σ 2R respectively. We also have
5 C/m 2. Further, For a point in region II,. σ 1L σ 1R σ 2L σ 2R Substituting values, the field strength is approximately 226 N/C. By similar arguments, the field to the left of the left plate and that to the right of the right plate can be shown to be zero. (Solution becomes simpler if one assumes a- priori that the charges appear only on the faces of the two plates that face each other.) 3. Calculate the potential at P due to the first ring which is Similarly, since P is at a distance from all points on the second ring, the potential at P due to the second ring is. Thus the net potential at P is. Similarly, the potential at P is. The work done is q times the potential difference between P and P, which is. P Q 1 P Q 2
6 4. The charge densities are. Inside the metal sphere (for r<r) the field is zero. Field for R<r<a as well as for r>b, the field is inverse square and is given by. The potential can be calculated as a line integral of the electric field If the outside of the shell is grounded, the charge density on that surface becomes zero while the charge densities on all other surfaces remain unchanged. The only non-zero field is in the region R<r< Further V(b)=0. Thus. 5. The charge densities on the inside surface of the cavities are, while the charge density on the outside surface is. The field outside the sphere is same as due to a charge q+q located at the centre of the sphere. 6. R=0.2 m and C. 7. Take the line joining the charges along the x-axis and the perpendicular bisector along the z axis. Since the point at which the potential is to calculated is at a distance from each of the charges, the potential is given by. The electric field is the gradient of the potential and is given by. 8. The potential in the region r<r is the same as that on the surface of the metal sphere. The charge distribution on the shell will be Q on the inner surface and 4Q on the outer surface. We can use superposition principle to find the potential at r=r. This gives. You can also find it by determining the field distribution using Gauss s law and determining potential 9. No, the curl the given field is not zero (calculate the curl explicitly). 10. Show that the field is conservative and obtain the corresponding potential. The potential is given by (in V). Then convert the given positions to Cartesian. The work done is equal to q times the change in potential. Ans.
13 - ELECTROSTATICS Page 1 ( Answers at the end of all questions )
3 - ELECTROSTATICS Page ) Two point charges 8 and - are located at x = 0 and x = L respectively. The location of a point on the x axis at which the net electric field due to these two point charges is
More informationPHYS102 Previous Exam Problems. Electric Potential
PHYS102 Previous Exam Problems CHAPTER 24 Electric Potential Electric potential energy of a point charge Calculating electric potential from electric field Electric potential of point charges Calculating
More informationRoll Number SET NO. 42/1
Roll Number SET NO. 4/1 INDIAN SCHOOL MUSCAT FIRST TERM EXAMINATION PHYSICS CLASS: XII Sub. Code: 04 Time Allotted: Hrs 0.04.018 Max. Marks: 70 General Instructions: 1. All questions are compulsory. There
More information3. A solid conducting sphere has net charge of +6nC. At electrostatic equilibrium the electric field inside the sphere is:
Conceptual Questions. Circle the best answer. (2 points each) 1. If more electric field lines point into a balloon than come out of it, you can conclude that this balloon must contain more positive charge
More informationConductors in Electrostatic Equilibrium
Lecture 5 Chapter 27 Physics II 09.19.2014 Conductors in Electrostatic Equilibrium 95.144 Course website: http://faculty.uml.edu/andriy_danylov/teaching/physicsii Lecture Capture: http://echo360.uml.edu/danylov201415/physics2fall.html
More informationAP Physics C Electricity & Magnetism Mid Term Review
AP Physics C Electricity & Magnetism Mid Term Review 1984 37. When lighted, a 100-watt light bulb operating on a 110-volt household circuit has a resistance closest to (A) 10-2 Ω (B) 10-1 Ω (C) 1 Ω (D)
More informationAP Physics C. Electric Potential and Capacitance. Free Response Problems
AP Physics C Electric Potential and Capacitance Free Response Problems 1. Two stationary point charges + are located on the y-axis at a distance L from the origin, as shown above. A third charge +q is
More informationweek 3 chapter 28 - Gauss s Law
week 3 chapter 28 - Gauss s Law Here is the central idea: recall field lines... + + q 2q q (a) (b) (c) q + + q q + +q q/2 + q (d) (e) (f) The number of electric field lines emerging from minus the number
More information7. A capacitor has been charged by a D C source. What are the magnitude of conduction and displacement current, when it is fully charged?
1. In which Orientation, a dipole placed in uniform electric field is in (a) stable (b) unstable equilibrium. 2. Two point charges having equal charges separated by 1 m in distance experience a force of
More information2014 F 2014 AI. 1. Why must electrostatic field at the surface of a charged conductor be normal to the surface at every point? Give reason.
2014 F 1. Why must electrostatic field at the surface of a charged conductor be normal to the surface at every point? Give reason. 2. Figure shows the field lines on a positive charge. Is the work done
More informationA) 1, 2, 3, 4 B) 4, 3, 2, 1 C) 2, 3, 1, 4 D) 2, 4, 1, 3 E) 3, 2, 4, 1. Page 2
1. Two parallel-plate capacitors with different plate separation but the same capacitance are connected in series to a battery. Both capacitors are filled with air. The quantity that is NOT the same for
More informationVU Mobile Powered by S NO Group All Rights Reserved S NO Group 2012
PHY101 Physics Final Term Solved MCQs (Latest) 1 1. A total charge of 6.3 10 8 C is distributed uniformly throughout a 2.7-cm radius sphere. The volume charge density is: A. 3.7 10 7 C/m3 B. 6.9 10 6 C/m3
More informationUniversity Physics (Prof. David Flory) Chapt_24 Sunday, February 03, 2008 Page 1
University Physics (Prof. David Flory) Chapt_4 Sunday, February 03, 008 Page 1 Name: Date: 1. A point charged particle is placed at the center of a spherical Gaussian surface. The net electric flux Φ net
More informationINDIAN SCHOOL MUSCAT Department of Physics Class : XII Physics Worksheet - 1 ( ) Electric Charges and Fields
INDIAN SCHOOL MUSCAT Department of Physics Class : XII Physics Worksheet - 1 (2017-2018) Electric Charges and Fields Section A Conceptual and application type Questions 1 What happens to the electric field
More informationConductors in Electrostatic Equilibrium
Lecture 6 Chapter 24 Conductors in Electrostatic Equilibrium 95.144 Conductors full of electrons? Course website: http://faculty.uml.edu/andriy_danylov/teaching/physicsii Today we are going to discuss:
More informationPhys222 S11 Quiz 2: Chapters Name: = 80 nc, and q = 24 nc in the figure, what is the magnitude of the total electric force on q?
Name: 1. Three point charges are positioned on the x axis. If the charges and corresponding positions are +3 µc at x = 0, +0 µc at x = 40 cm, and 60 µc at x = 60 cm, what is the magnitude of the electrostatic
More informationChapter 23 Term083 Term082
Chapter 23 Term083 Q6. Consider two large oppositely charged parallel metal plates, placed close to each other. The plates are square with sides L and carry charges Q and Q. The magnitude of the electric
More informationLecture 13: Electromagnetic Theory Professor D. K. Ghosh, Physics Department, I.I.T., Bombay. Poisson s and Laplace s Equations
Poisson s and Laplace s Equations Lecture 13: Electromagnetic Theory Professor D. K. Ghosh, Physics Department, I.I.T., Bombay We will spend some time in looking at the mathematical foundations of electrostatics.
More informationINDIAN SCHOOL MUSCAT FIRST TERM EXAMINATION PHYSICS
Roll Number SET NO. General Instructions: INDIAN SCHOOL MUSCAT FIRST TERM EXAMINATION PHYSICS CLASS: XII Sub. Code: 04 Time Allotted: Hrs 0.04.08 Max. Marks: 70. All questions are compulsory. There are
More informationF 13. The two forces are shown if Q 2 and Q 3 are connected, their charges are equal. F 12 = F 13 only choice A is possible. Ans: Q2.
Q1. Three fixed point charges are arranged as shown in Figure 1, where initially Q 1 = 10 µc, Q = 15 µc, and Q 3 = 5 µc. If charges Q and Q 3 are connected by a very thin conducting wire and then disconnected,
More informationCH 23. Gauss Law. A. Gauss law relates the electric fields at points on a (closed) Gaussian surface to the net charge enclosed by that surface.
CH 23 Gauss Law [SHIVOK SP212] January 4, 2016 I. Introduction to Gauss Law A. Gauss law relates the electric fields at points on a (closed) Gaussian surface to the net charge enclosed by that surface.
More informationChapter 22 Gauss s Law
Chapter 22 Gauss s Law Lecture by Dr. Hebin Li Goals for Chapter 22 To use the electric field at a surface to determine the charge within the surface To learn the meaning of electric flux and how to calculate
More information2 Which of the following represents the electric field due to an infinite charged sheet with a uniform charge distribution σ.
Slide 1 / 21 1 closed surface, in the shape of a cylinder of radius R and Length L, is placed in a region with a constant electric field of magnitude. The total electric flux through the cylindrical surface
More informationChapter Electrostatic Potential and Capacitance
Chapter Electrostatic Potential and Capacitance C/ 2 C/2 Ans: Q6. MockTime.com Q1. A 4µF conductor is charged to 400 volts and then its plates are joined through a resistance of 1 kω. The heat produced
More informationPHYSICS. Electrostatics
Electrostatics Coulomb s Law: SYNOPSIS SI unit of electric intensity is NC -1 Dimensions The electric intensity due to isolated point charge, Electric dipole moment, P = q (2a), SI unit is C m Torque on
More informationSample Question: A point in empty space is near 3 charges as shown. The distances from the point to each charge are identical.
A point in empty space is near 3 charges as shown. The distances from the point to each charge are identical. A. Draw a vector showing the direction the electric field points. y +2Q x B. What is the angle
More informationQuestions Chapter 23 Gauss' Law
Questions Chapter 23 Gauss' Law 23-1 What is Physics? 23-2 Flux 23-3 Flux of an Electric Field 23-4 Gauss' Law 23-5 Gauss' Law and Coulomb's Law 23-6 A Charged Isolated Conductor 23-7 Applying Gauss' Law:
More informationElectric Flux. If we know the electric field on a Gaussian surface, we can find the net charge enclosed by the surface.
Chapter 23 Gauss' Law Instead of considering the electric fields of charge elements in a given charge distribution, Gauss' law considers a hypothetical closed surface enclosing the charge distribution.
More informationFísica Básica Experimental I Cuestiones Tema VII. Electrostática. Soluciones incluidas. 1.
1. A cubical surface with no charge enclosed and with sides 2.0 m long is oriented with right and left faces perpendicular to a uniform electric field E of (1.6 10 5 N/C) î. The net electric flux E through
More informationPhysics 2212 GH Quiz #2 Solutions Spring 2015
Physics 2212 GH uiz #2 Solutions Spring 2015 Fundamental Charge e = 1.602 10 19 C Mass of an Electron m e = 9.109 10 31 kg Coulomb constant K = 8.988 10 9 N m 2 /C 2 Vacuum Permittivity ϵ 0 = 8.854 10
More informationChapter 22 Gauss s Law. Copyright 2009 Pearson Education, Inc.
Chapter 22 Gauss s Law 22-1 Electric Flux Electric flux: Electric flux through an area is proportional to the total number of field lines crossing the area. 22-1 Electric Flux Example 22-1: Electric flux.
More informationPhysics (
Question 2.12: A charge of 8 mc is located at the origin. Calculate the work done in taking a small charge of 2 10 9 C from a point P (0, 0, 3 cm) to a point Q (0, 4 cm, 0), via a point R (0, 6 cm, 9 cm).
More informationDownloaded from
Question 1.1: What is the force between two small charged spheres having charges of 2 10 7 C and 3 10 7 C placed 30 cm apart in air? Repulsive force of magnitude 6 10 3 N Charge on the first sphere, q
More informationW05D1 Conductors and Insulators Capacitance & Capacitors Energy Stored in Capacitors
W05D1 Conductors and Insulators Capacitance & Capacitors Energy Stored in Capacitors W05D1 Reading Assignment Course Notes: Sections 3.3, 4.5, 5.1-5.4 1 Outline Conductors and Insulators Conductors as
More informationConsider a point P on the line joining the two charges, as shown in the given figure.
Question 2.1: Two charges 5 10 8 C and 3 10 8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
More informationNR/RR. Set No. 2 CODE NO: NR/RR210204
Set No. 2 II B.Tech I Semester Examinations,May 2011 ELECTROMAGNETIC FIELDS Electrical And Electronics Engineering Time: 3 hours Max Marks: 80 Answer any FIVE Questions All Questions carry equal marks
More informationF = Q big = c) The electric potential in a certain region of space can be described by the equation: 16y2 (1 + z 2 ) V (x, y, z) = 10x
1) Short Answer (4 points each)(show YOUR WORK) a) A 3.0 nc (positive) charge and a 1.0 nc (negative) charge are located 0.80 m apart from each other. What is the force on the 3.0 nc (positive) charge
More informationDownloaded from Downloaded from
LEVEL 1 1. How many electrons will have a total charge of 1 coulomb? 2. Find the electric field intensity due to a charge of 5 10-8 C at a point 50 cm from it in vacuum 3. An electric charge of 2 c experience
More informationPhysics 2049 Exam 1 Solutions Fall 2002
Physics 2049 xam 1 Solutions Fall 2002 1. A metal ball is suspended by a string. A positively charged plastic ruler is placed near the ball, which is observed to be attracted to the ruler. What can we
More informationTurn in scantron You keep these question sheets
Exam 1 on FEB. 20. 2018 - Physics 106 R. Schad YOUR NAME ¼À Turn in scantron You keep these question sheets 1) Electric flux through a spherical surface of radius 1m dueto a charge inside [which is the
More informationELECTROSTATICS 3. P.Ravindran, PHY041: Electricity & Magnetism 15 January 2013: Electrostatics 3
ELECTROSTATICS 3 q 0 Electro negativity ti it Rl Relative electro negativity ranking for some common materials from electron donating materials (+, glass) to electron accepting materials (, teflon) + +
More informationConductors in Electrostatic Equilibrium
Lecture 6 Chapter 24 Conductors in Electrostatic Equilibrium 95.144 Conductors full of electrons? Course website: http://faculty.uml.edu/andriy_danylov/teaching/physicsii Today we are going to discuss:
More informationThe Electric Field of a Finite Line of Charge The Electric Field of a Finite Line of
The Electric Field of a Finite Line of Charge The Electric Field of a Finite Line of Charge Example 26.3 in the text uses integration to find the electric field strength at a radial distance r in the plane
More information9/10/2018. An Infinite Line of Charge. The electric field of a thin, uniformly charged rod may be written:
The Electric Field of a Finite Line of Charge The Electric Field of a Finite Line of Charge Example 26.3 in the text uses integration to find the electric field strength at a radial distance r in the plane
More informationChapter 22 Gauss s Law. Copyright 2009 Pearson Education, Inc.
Chapter 22 Gauss s Law Electric Flux Gauss s Law Units of Chapter 22 Applications of Gauss s Law Experimental Basis of Gauss s and Coulomb s Laws 22-1 Electric Flux Electric flux: Electric flux through
More informationPhysics 240 Fall 2003: Exam #1. Please print your name: Please list your discussion section number: Please list your discussion instructor:
Physics 4 Fall 3: Exam #1 Please print your name: Please list your discussion section number: Please list your discussion instructor: Form #1 Instructions 1. Fill in your name above. This will be a 1.5
More informationCoulomb s Law Pearson Education Inc.
Coulomb s Law Coulomb s Law: The magnitude of the electric force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance
More informationE. not enough information given to decide
Q22.1 A spherical Gaussian surface (#1) encloses and is centered on a point charge +q. A second spherical Gaussian surface (#2) of the same size also encloses the charge but is not centered on it. Compared
More informationGauss Law 1. Name Date Partners GAUSS' LAW. Work together as a group on all questions.
Gauss Law 1 Name Date Partners 1. The statement of Gauss' Law: (a) in words: GAUSS' LAW Work together as a group on all questions. The electric flux through a closed surface is equal to the total charge
More informationELECTRO MAGNETIC FIELDS
SET - 1 1. a) State and explain Gauss law in differential form and also list the limitations of Guess law. b) A square sheet defined by -2 x 2m, -2 y 2m lies in the = -2m plane. The charge density on the
More informationName Date Partners. Lab 4 - GAUSS' LAW. On all questions, work together as a group.
65 Name Date Partners 1. The statement of Gauss' Law: Lab 4 - GAUSS' LAW On all questions, work together as a group. (a) in words: The electric flux through a closed surface is equal to the total charge
More informationChapter 21 Chapter 23 Gauss Law. Copyright 2014 John Wiley & Sons, Inc. All rights reserved.
Chapter 21 Chapter 23 Gauss Law Copyright 23-1 What is Physics? Gauss law relates the electric fields at points on a (closed) Gaussian surface to the net charge enclosed by that surface. Gauss law considers
More informationLAST Name (print) ALL WORK MUST BE SHOWN FOR THE FREE RESPONSE QUESTION IN ORDER TO RECEIVE FULL CREDIT.
Physics 107 LAST Name (print) First Mid-Term Exam FIRST Name (print) Summer 2013 Signature: July 5 UIN #: Textbooks, cell phones, or any other forms of wireless communication are strictly prohibited in
More informationCh 16 practice. Multiple Choice Identify the choice that best completes the statement or answers the question.
Ch 16 practice Multiple Choice Identify the choice that best completes the statement or answers the question. 1. What happens when a rubber rod is rubbed with a piece of fur, giving it a negative charge?
More informationHomework 4: Hard-Copy Homework Due Wednesday 2/17
Homework 4: Hard-Copy Homework Due Wednesday 2/17 Special instructions for this homework: Please show all work necessary to solve the problems, including diagrams, algebra, calculus, or whatever else may
More informationAP physics B web review ch 15 electric forces and fields
Name: Class: _ Date: _ AP physics B web review ch 15 electric forces and fields Please do not write on my tests Multiple Choice Identify the choice that best completes the statement or answers the question.
More informationDescription / Instructions: Covers 9th edition chapters and
Description / Instructions: Covers 9th edition chapters 21-1 -- 21-6 and 22-1 -- 22-4. Question 1 Figure 21-14 shows four situations in which charged particles are fixed in place on an axis. In which situations
More informationPhysics Lecture: 09
Physics 2113 Jonathan Dowling Physics 2113 Lecture: 09 Flux Capacitor (Schematic) Gauss Law II Carl Friedrich Gauss 1777 1855 Gauss Law: General Case Consider any ARBITRARY CLOSED surface S -- NOTE: this
More information---------------------------------------------------------------------------------------------------------- PHYS 2326 University Physics II Class number ---------------------------------------------------------------------------------------------------------------------
More informationElectrostatics. 4πε 2) + Q / 2 4) 4 Q
Two spheres A and B of radius a and b respectively are at the same potential The ratio of the surface charge density of A to B is: ) a / b ) b / a a / b b / a Two free protons are separated by a distance
More informationPotential & Potential Energy
Potential & Potential Energy Lecture 10: Electromagnetic Theory Professor D. K. Ghosh, Physics Department, I.I.T., Bombay Electrostatic Boundary Conditions : We had seen that electric field has a discontinuity
More informationQ1. Three point charges are arranged as shown in FIGURE 1. Find the magnitude of the net electrostatic force on the point charge at the origin.
Coordinator: Saleem Rao Monday, May 01, 2017 Page: 1 Q1. Three point charges are arranged as shown in FIGURE 1. Find the magnitude of the net electrostatic force on the point charge at the origin. A) 1.38
More informationPhysics 2220 Fall 2010 George Williams SECOND MIDTERM - REVIEW PROBLEMS
Physics 0 Fall 010 George Williams SECOND MIDTERM - REVIEW PROBLEMS The last four problems are from last years second midterm. Solutions are available on the class web site.. There are no solutions for,
More information4 pt. (in J) 3.A
Mark Reeves - Physics 22, Fall 2011 1 A point charge of mass 0.0699 kg and charge q = +6.87 µc is suspended by a thread between the vertical parallel plates of a parallel-plate capacitor, as shown in the
More information1)Tw o charges g 4q q and q q are placed
Electrostatics 1)Two charges 4q and q are placed a distance r apart. A charge Q is placed exactly mid way between them. What will be the value of Q so that charge 4q experiences no net force? q/4 q/4 q4
More information2. Gauss Law [1] Equipment: This is a theoretical lab so your equipment is pencil, paper, and textbook.
Purpose: Theoretical study of Gauss law. 2. Gauss Law [1] Equipment: This is a theoretical lab so your equipment is pencil, paper, and textbook. When drawing field line pattern around charge distributions
More informationPhysics 102. First Midterm Examination Fall Semester 2015/2016. November 3, 2015 Time: 6.30 p.m p.m. Name. Student No..
Kuwait University Physics Department Physics 102 First Midterm Examination Fall Semester 2015/2016 November 3, 2015 Time: 6.30 p.m. - 8.00 p.m. Name. Student No.. Section No. Instructors: Drs. Abdelkarim,
More informationPhysics 212 Exam I Sample Question Bank 2008 Multiple Choice: choose the best answer "none of the above" may can be a valid answer
Multiple Choice: choose the best answer "none of the above" may can be a valid answer The (attempted) demonstration in class with the pith balls and a variety of materials indicated that () there are two
More informationTALLER DE ELECTROSTÁTICA
TALLER DE ELECTROSTÁTICA MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) If two objects are electrically attracted to each other, 1) A) the objects
More informationElectric Potential Practice Problems
Electric Potential Practice Problems AP Physics Name Multiple Choice 1. A negative charge is placed on a conducting sphere. Which statement is true about the charge distribution (A) Concentrated at the
More information4. Theunitsoftheelectric eldare: A. N C 2 B. C/N C. N D. N/C E. C=m 2 ans: D Section: 22{2; Di±culty: E. Chapter 22: ELECTRIC FIELDS 377
Chapter 22: ELECTRIC FIELDS 1 An electric eld is most directly related to: A the momentum of a test charge B the kinetic energy of a test charge C the potential energy of a test charge D the force acting
More informationOUT OF BOOK QUESTION. Sphere Y is now moved away from X, as in Figure (b).
X and Y are two uncharged metal spheres on insulating stands, and are in contact with each other. A positively charged rod R is brought close to X as shown in Figure (a). Sphere Y is now moved away from
More informationDownloaded from
1. ELECTROSTATICS GIST Electrostatics is the study of charges at rest. The intrinsic property of fundamental particle of matter which give rise to electric force between objects is called charge. Charging
More informationELECTROSTATICS (Important formulae and Concepts) I Electric charges and Coulomb s law
ELECTROSTATICS (Important formulae and Concepts) I Electric charges and Coulomb s law II Electric Field and Electric Dipole www.nrpschool.com www.nrpschool.com III ELECTRIC POTENTIAL www.nrpschool.com
More information+2Q -2Q. (a) 672 N m 2 /C (b) 321 N m 2 /C (c) 105 N m 2 /C (d) 132 N m 2 /C (e) 251 N m 2 /C
1. The figure below shows 4 point charges located on a circle centered about the origin. The exact locations of the charges on the circle are not given. What can you say about the electric potential created
More informationHow to define the direction of A??
Chapter Gauss Law.1 Electric Flu. Gauss Law. A charged Isolated Conductor.4 Applying Gauss Law: Cylindrical Symmetry.5 Applying Gauss Law: Planar Symmetry.6 Applying Gauss Law: Spherical Symmetry You will
More informationClass XII Chapter 1 Electric Charges And Fields Physics
Class XII Chapter 1 Electric Charges And Fields Physics Question 1.1: What is the force between two small charged spheres having charges of 2 10 7 C and 3 10 7 C placed 30 cm apart in air? Answer: Repulsive
More informationPhys 2102 Spring 2002 Exam 1
Phys 2102 Spring 2002 Exam 1 February 19, 2002 1. When a positively charged conductor touches a neutral conductor, the neutral conductor will: (a) Lose protons (b) Gain electrons (c) Stay neutral (d) Lose
More informationAMPERE'S LAW. B dl = 0
AMPERE'S LAW The figure below shows a basic result of an experiment done by Hans Christian Oersted in 1820. It shows the magnetic field produced by a current in a long, straight length of current-carrying
More informationName Date Partners. Lab 2 GAUSS LAW
L02-1 Name Date Partners Lab 2 GAUSS LAW On all questions, work together as a group. 1. The statement of Gauss Law: (a) in words: The electric flux through a closed surface is equal to the total charge
More informationChapter 22 Electric Potential (Voltage)
Chapter 22 Electric Potential (Voltage) Question 29.5 Work and Electric Potential I Which requires the most work, to move a positive charge from P to points 1, 2, 3 or 4? All points are the same distance
More informationPHYS 241 EXAM #1 October 5, 2006
1. ( 5 points) Two point particles, one with charge 8 10 9 C and the other with charge 2 10 9 C, are separated by 4 m. The magnitude of the electric field (in N/C) midway between them is: A. 9 10 9 B.
More informationPhysics (
Exercises Question 2: Two charges 5 0 8 C and 3 0 8 C are located 6 cm apart At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero
More informationPhys102 Second Major-161 Zero Version Coordinator: Dr. Naqvi Monday, December 12, 2016 Page: 1
Coordinator: Dr. Naqvi Monday, December 12, 2016 Page: 1 Q1. Two point charges, with charges q1 and q2, are placed a distance r apart. Which of the following statements is TRUE if the electric field due
More informationAPPLICATIONS OF GAUSS S LAW
APPLICATIONS OF GAUSS S LAW Although Gauss s Law is always correct it is generally only useful in cases with strong symmetries. The basic problem is that it gives the integral of E rather than E itself.
More informationChapter 10. Electrostatics
Chapter 10 Electrostatics 3 4 AP Physics Multiple Choice Practice Electrostatics 1. The electron volt is a measure of (A) charge (B) energy (C) impulse (D) momentum (E) velocity. A solid conducting sphere
More informationPhysics 55 Final Exam Fall 2012 Dr. Alward Page 1
Physics 55 Final Exam Fall 2012 Dr. Alward Page 1 1. The specific heat of lead is 0.030 cal/g C. 300 g of lead shot at 100 C is mixed with 100 g of water at 70 C in an insulated container. The final temperature
More informationQuick Questions. 1. Two charges of +1 µc each are separated by 1 cm. What is the force between them?
92 3.10 Quick Questions 3.10 Quick Questions 1. Two charges of +1 µc each are separated by 1 cm. What is the force between them? 0.89 N 90 N 173 N 15 N 2. The electric field inside an isolated conductor
More informationPhys102 Second Major-181 Zero Version Coordinator: Kunwar, S Monday, November 19, 2018 Page: 1
Coordinator: Kunwar, S Monday, November 19, 2018 Page: 1 Q1. A neutral metal ball is suspended by a vertical string. When a positively charged insulating rod is placed near the ball (without touching),
More informationPhys222 W16 Exam 2: Chapters Key. Name:
Name: Please mark your answer here and in the scantron. A positively charged particle is moving in the +y-direction when it enters a region with a uniform electric field pointing in the +y-direction. Which
More informationElectric Flux. To investigate this, we have to understand electric flux.
Problem 21.72 A charge q 1 = +5. nc is placed at the origin of an xy-coordinate system, and a charge q 2 = -2. nc is placed on the positive x-axis at x = 4. cm. (a) If a third charge q 3 = +6. nc is now
More informationfree space (vacuum) permittivity [ F/m]
Electrostatic Fields Electrostatic fields are static (time-invariant) electric fields produced by static (stationary) charge distributions. The mathematical definition of the electrostatic field is derived
More informationElectric flux. Electric Fields and Gauss s Law. Electric flux. Flux through an arbitrary surface
Electric flux Electric Fields and Gauss s Law Electric flux is a measure of the number of field lines passing through a surface. The flux is the product of the magnitude of the electric field and the surface
More information1. Short Answer (25 points total)
Physics 116b First Practice Examination Due September 19, 2001 Name: Please circle your section: Section 1 Section 2 Section 3 Section 4 I nstructions This is practice for a one hour, closed book examination.
More informationAP Physics Study Guide Chapter 17 Electric Potential and Energy Name. Circle the vector quantities below and underline the scalar quantities below
AP Physics Study Guide Chapter 17 Electric Potential and Energy Name Circle the vector quantities below and underline the scalar quantities below electric potential electric field electric potential energy
More informationLESSON 2 PHYSICS NOTES
LESSON 2 ELECTROSTATIC POTENTIAL AND CAPACITANCE SECTION I ELECTROSTATIC POTENTIAL ELECTRIC FIELD IS CONSERVATIVE In an electric field work done by the electric field in moving a unit positive charge from
More informationA) I B) II C) III D) IV E) V
1. A square loop of wire moves with a constant speed v from a field-free region into a region of uniform B field, as shown. Which of the five graphs correctly shows the induced current i in the loop as
More informationChapter 17. Electric Potential Energy and the Electric Potential
Chapter 17 Electric Potential Energy and the Electric Potential Consider gravity near the surface of the Earth The gravitational field is uniform. This means it always points in the same direction with
More informationElectric Force and Potential Energy
Class 04 (Class 03: whiteboard exercises of Gauss' law.) Electric Force and Potential Energy For a charge q 0 in an electric field: The force picture F=q 0 E Can we similarly look for an energy picture?
More informationProblems. 686 Chapter 24 Gauss s Law
686 Chapter 24 Gauss s Law (b) 2 (c) 4 (d) 6 (ii) Through how many of the cube s faces is the electric flux zero? Choose from the same possibilities. 6. O A cubical gaussian surface is bisected by a large
More information