a Lesson from the forthcoming every. ) textbook Mathematics: Building 3. a, b, and c, a + (b + c) = (a + b) + c.
|
|
- Alyson Warner
- 5 years ago
- Views:
Transcription
1 There are eleve basic rules that gover all work i elemetary algebra. Five of these rules relate to additio, five relate to multiplicatio, ad the fial rule coects additio to multiplicatio. These rules ecapsulate all of the basic properties of real umbers. Because the structure of the set of real umbers reflects all of these rules, mathematicias call the real umbers a field. Here they are i symbolic form:. a, b a + b. ( meas implies. ) Note: This essay is extracted from. a, b, a + b = b + a. ( meas for all or for a Lesso from the forthcomig every. ) textbook Mathematics: Buildig. a, b, ad c, a + (b + c) = (a + b) + c. o Foudatios. 4. a, a elemet i called a = a. Remember, meas such that ad meas there exists. 5. For each pair a ad b, there is exactly oe x a + x = b. 6. a, b ab. 7. a, b, ab = ba. 8. a, b, ad c, a(bc) = (ab)c. 9. a, a elemet i called a = a. 0. For each pair a ad b (where a 0), there is exactly oe x ax = b.. a, b, ad c, a(b + c) = ab + ac. The closure property for real umbers uder additio ad multiplicatio coect to their respective iverses. The iverse operatio of additio is subtractio ad the iverse operatio of multiplicatio is divisio. Oe iverse operatio of expoetiatio is extractio of roots. For a review, the followig table illustrates these operatios ad their iverses. Operatio Iverse Additio (7 + = 0) Subtractio (0 = 7) Multiplicatio (6 5 = 0) Divisio (0/5 = 6) Expoetiatio ( = 4) Extractio of roots ( 4= ) The iverse of raisig ay umber x to the secod power, i.e., x = a, is called extractig the square (from ) root, i.e., a x. The iverse of raisig ay umber x to the third power, i.e., x = a, is called extractig the cube (from ) root, i.e., a x. The iverse of raisig ay umber to the fourth power, i.e., x 4 = a, is called extractio the fourth root i.e., 4 a x. I symbols, these operatios look as follows: Raisig to the th power Extractig the th root = 4 4 = = = b b ifiseve There is actually a distictio betwee what mathematicias call a field ad a ordered field, but we will ot embrace such miutiae i this essay.
2 Raisig to the th power Extractig the th root b ifisodd Before we cotiue, ote the odd/eve priciple. Whe you are extractig the th root of a positive umber ad is eve, you will always get two aswers, oe positive ad the other egative. This is because a egative umber times a egative umber equals a positive umber; i.e., (-)(-) = 4. Note also that (-)(-)(-)(-) = 6. If you are multiplyig a eve umber of egative umbers, your aswer will also be positive. If you are multiplyig a odd umber of egative umbers, the aswer will always be egative. For example, (-)(-)(-) = -8 but ()()() = 8. Therefore, 8,but 8. Before the advet of the electroic had held calculator (i the late 960s), all arithmetical operatios had to be worked out by had. By the early 7 th cetury, great advaces had bee made both i astroomy ad i explorig the world through sea voyages. Both these advaces ecessitated performig arithmetical calculatios usig large umbers. A Scottish mathematicia, Joh Napier (550-67) oted these difficulties ad echoed the bae of may studets of arithmetic, Seeig there is othig that is so troublesome to mathematical practice, or that doth more molest ad hider calculators, tha the multiplicatio, divisios, square ad cubical extractios of great umbers. I bega therefore to cosider Joh Napier (Public i my mid by what certai ad ready art I might remove those hidraces. Domai) Napier removed these difficulties by developig a system of arithmetic that replaced multiplicatio by additio ad divisio by subtractio. Cosider the table below (powers of ): Napier first oted that if he multiplied ay umber i row by ay other umber i row, his aswer was a umber i row. Secod, he oted that whe you multiplied ay two umbers i row, the the aswer correlated to a additio problem i row (he made use of the sum law of expoets). Iversely, if you divided ay two umbers i row, the the aswer correlated to a subtractio problem i row (the iverse of the sum law of expoets). Row Row 4 = 8 + = (read 8 i row ) 8 = 6 + = 4 (read 6 i row ) 8 6 = = 7 (read 8 i row ) 6 64 = = 0 (read,04 i row ) = 8 4 = 7 (read 8 i row ) 64 8 = 8 6 = (read 8 i row ) By this method, Napier arrived at aother iverse of expoetiatio. Give x =, recall that we deote as the base ad x as the expoet. I expoetiatio, we are give the base ad the expoet. From this, we Joh Napier, Mirifici logarithmorum caois descriptio (64). Cited i George A. Gibso, Napier ad the Ivetio of Logarithms, i Hadbook of the Napier Terceteary Celebratio, or Moder Istrumets ad Methods of Calculatios, ed. E. M. Horsburgh (Los Ageles: Tomash Publishers, [94] 98), p. 9.
3 determie that result; i.e.,. For example, 4 = 6. I Napier s iverse, we are give the result (i.e., ) ad the base i.e., ). From this, we determie the expoet (i.e., x). He called this process fidig the logarithm. For example, if x = 6, the x (the logarithm of 6) = 4. The logarithmic table looks as follows: Number Logarithm This table has oe serious limitatio. What happes if we wat to multiply by? What is the logarithm of? What is the logarithm of? From the table, we ote that the logarithm of must be betwee ad ad the logarithm of must be betwee 4 ad 5. To fid the logarithm of, we must determie x such that x =. We kow for certai that x will ot be a positive iteger; it will be a fractio or its decimal equivalet. Fractios do cause some icoveiece i calculatios. Our table does ot yet cotai ay fractios (the smallest is 0 = ). We must ow itroduce powers of that are less tha if we wat to express fractios i our table. Hece, we must cosider -, -, -, etc. Whe we raise ay umber to a egative expoet, it meas you take its reciprocal. I symbols, a. Hece, 0.5, 0.5, ad a We ca add these umbers to our table: 8 Number Logarithm Logarithm is derived from two Greek words, logos (reaso or proportio) ad arithmos (umber), ad it literally meas proportio umber. Although, we itroduced expoets (Lesso.5) before logarithms, accordig to mathematics historia Howard Eves (9-004), Oe of the aomalies i the history of mathematics is the fact that logarithms were discovered before expoets were i use. See Howard Eves, A Itroductio to the History of Mathematics (New York: Holt, Rhiehart ad Wisto, [95, 964, 969] 976, p. 50.
4 This helps us somewhat with fidig the logarithm of umbers less tha. But, there are still gaps i the table. How do we fid the logarithm of ; i.e. determie x such that x =? As oted before, < x < (that is, x must be betwee ad ). x, the logarithm of, must be a fractioal expoet. We must be able to determie x where x = a b. Let s cosider how to calculate x whe x = square this umber ad apply the product law of expoets. 6 x 8.. We ca rewrite Sice 8,the as. We ow cosider. Let s Note that 8 is a irratioal umber ad that we rouded it off to the earest teth. Sice.5, the we ca add aother etry to our table: Number Logarithm We have t quite got the logarithm of, but we are gettig close. It ca be show that the solutio to x = is a irratioal umber (x caot be writte as a ratio of two itegers) ad that we ca approximate x to ay desired precisio usig fractioal powers. The process that I have led you through is exactly the pathway that Napier took i costructig his logarithm tables (it took him twety years to do it i the pre-computer ad pre-calculator days). I our example, we are costructig logarithms to the base. This is sigified as follows: log 8 = or, i geeral, log b x = y. The iverse operatio is sigified as = 8 or, i geeral, b y = x. Hece we have this equivalecy: y b x logbx y With this equivalecy, we ca techically ote the two iverses of expoetiatio: Expoetiatio Iverse b x = y Computig logarithms x logby x b = y Extractio of roots x = b y = y b The miraculous powers of moder calculatio are due to three ivetios: the Arabic Notatio, Decimal Fractios, ad Logarithms. Floria Cajori, A History of Mathematics (89). The list below eumerates all the essetial properties of logarithms (for ow, just take ote of the third ad fourth property; we shall prove them as a exercise):. Additio property: log b (xy) = log b x + log b y x. Subtractio property: logb = log b x log b y y
5 . Power property: log b x = log b x 4. Root extractio property: logb x logbx Util the advet of the had held calculator, most high school ad college textbooks cotaied logarithmic tables as appedices. The base commoly used was 0 ad it was sigified without a subscript. It was called the commo logarithm. 4 If you have a scietific calculator, the commo logarithm key is sigified by log. For example, log 00 =. Try it out with your calculator. The iverse operatio is 0 = 00. Here is a table of logarithms to the base 0: Number Logarithm to the base ,000 4 Note the much loger gaps i the table betwee the umbers. log = 0 ad log 0 =. I cotrast, for logarithms to the base, log = 0 ad log =. It will take more effort to fill i the gaps for logarithms to the base 0. Note aother key ext to the log key o your scietific calculator. It is sigified by l. This logarithm is called the atural logarithm. The base of the atural logarithms is a very famous ad sigificat umber that Leohard Euler deoted by the letter e. 5 e is a irratioal umber ad it is approximately equal to Why would this umber be used as a base? Joh Napier came very close to discoverig this umber. As far as historias of mathematics ca ascertai, e first appeared i history i the cotext of fiacial calculatios. Deposit that thought i your metal bak for a momet. We shall withdraw it after we explore the costructio of atural logarithms. We oted that 0 is ot a very good base of logarithms because of the large gaps. is a better base but it still has may gaps. We ca try as the base but that really does o good sice all powers of are. It is ot good to try a base less tha because a fractio less tha raised to a power gets smaller ad smaller. Take ote of successive powers of i the table below: 4 The Eglish mathematicia Hery Briggs (56-60) developed the first base 0 logarithmic tables. Commo logarithms are sometimes called Briggsia logarithms i his hoor. 5 Euler may have chose this letter to stad for expoetial. Sice the letters a, b, c, ad d were already frequetly used i mathematics, Euler may have just choose the ext available letter i the alphabet to represet this uusual umber. It is ulikely that Euler choose this letter because of his ame. As a Christia (his father was a Calviist pastor), Euler uderstood ad practiced the Christia grace of humility. 5
6 So, let s try a umber betwee ad as a base, say.. Note the successive powers of. i the table below. There is a coectio to Pascal s triagle here. Do you see it? Pascal s Triagle Note immediately that these umbers grow slowly ad that there are may umbers betwee ad before we try to calculate those troublesome gaps. It seems that choosig a smaller umber would be a eve better choice. Let s try.00. I this case, we separate the terms i Pascal s triagle by pairs of zeroes (ote how the terms fit eatly ito the decimal expasio):
7 At first we may woder if we will ever reach. Evetually we will, yet very slowly. Mathematicias have prove that the powers of ay umber greater tha (eve slightly greater tha ) will coverge to ifiity. The closer the umber is to, the slower the rate of growth. Although this table cotais a excellet desity of umbers, the drawback is its slow rate of growth. Very large expoets are eeded to produce small umbers. For example, Take ote of this umber (Hit: compare it with the umerical value of e as we defied it earlier i this essay). So, if the expoets were,000 times as big, we could make the table more proportioate. So, let s cosider as a base. Now, we are goig to raise this base to a fractioal power as follows ad make use of the product law of expoets: etc. Note that we are successively raisig to a fractioal power i steps of fractios to decimals, we get: etc Note also that we get the same results as before. Ispect the table below: ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) Covertig these 000 Note the patter that has developed. The expoets ad the correspodig results do ot grow disproportioately. Yet, the desity is uimpaired. Therefore, the base of is a excellet choice. Ca we im-
8 prove o this choice? Yes. Cosider the base of Why stop there? What about the base of ? We could go o ad o ad ifiitum with this type of procedure util we coverge to the atural or best umber. What is this umber? It is e, the base of the atural logarithms. Note the table below: e Let s withdraw our previously deposited fiacial thought from the bak. What does e have to do with moey? Cetral to the cocept of moey is the cocept of iterest. Iterest is what baks charge you for borrowig moey from them. If you do ot have the moey to buy a item ad the bak does, the the bak loas you the purchasig power to buy the item (this is called the pricipal). I retur for this loa, the bak expects a repaymet of this pricipal over time. A extra amout is charged to you for the use of this pricipal. This amout is called iterest. It is a way to pay the bak back for its loss of purchasig power due to its loa to you. The Bible presupposes time ad iterest i its teachig about restitutio (see Exodus :-5; Leviticus 6:- 7; Numbers 5:5-8; Luke 9:-9). Restitutio meas to make ameds or to recompese a ijury. The Bible teaches two forms of restitutio (betwee ma ad God ad betwee ma ad ma). Ma s si agaist God is atoed for by the blood of Jesus Christ (ma is made right with God through faith i the perso ad work of Jesus Christ). Ma s si agaist ma is made right via restitutio. I the case of theft, the Bible requires paymet of iterest for the stole goods (cf. Leviticus 6:4-5; Exodus :). This iterest paymet recogizes that whe a ma steals aother ma s goods, he is stealig aother ma s capital. By robbig ma of his capital, a thief is deprivig ma of ay icrease o that capital durig the time that it is i the thief s possessio. Not oly must the property be restored by a thief, a thief must also restore its value over time. I the same sese (mius the theft cocept), this is what baks do whe they charge iterest for moey borrowed. There are two types of iterest, simple ad compoud. Both are govered by mathematical formulas. The simple iterest formula for derivig how much you must pay a bak back (called the maturity value) for a loa is: S = P( + rt) where S = maturity value, P = the pricipal (amout of the loa), t = iterest rate per time period, ad t = legth of time you take to repay the pricipal. Note that r ad t must be i the same time uits (e.g., iterest per year with a repaymet schedule of x years). Suppose you borrow $000 at % per year iterest for years. What must you pay back? S = 000[ + 0.()] S = 000 (.6) = 60 The maturity value is $60. Normally, with a bak, you pay the loa back o a mothly basis. Your paymets would be $7.78 per moth. I three years you would pay back the $000 plus a iterest charge of $60 for usig the moey. 8
9 Suppose that the iterest rate is % 0.0 per moth ad your paymet schedule is 6 moths 00 ( years). What is S, the maturity value the? S = 000[ + 0.0(6)] S = 000(.6) = 60 The maturity value would be the same. Compoud iterest is govered by this formula: S = P( + r) t where, as before, S = maturity value, P = the pricipal, r = iterest rate per time period, ad t = legth of time you take to repay the pricipal. Let s ow cosider the same situatio: a loa of $000 at % iterest per year with a repaymet schedule of years. What is S? S = 000( + 0.) S = 000 (.) = Note the icrease i the maturity value from $60 calculated at simple iterest to $404.9 calculated at compoud iterest ($9.0 per moth repaymet). What is the icrease? $44.9. Let s ow icrease the loa repaymet to 5 years. What happes the? S, uder simple iterest is: S = 000 [ + 0.(5)] S = 000 (.8) = It pays to pay off a loa early! Although your mothly paymets are oly $5.56 a moth 80, you are payig $800 iterest o a $000 loa. No woder why, i Scripture, a loa for emergecy eeds was limited to 6 years (see Deuteroomy 5:-6). The situatio is much worse with compoud iterest. S = 000( + 0.) 5 S = 000(.) 5 = I this case your mothly paymets are $0.4 a moth. But, you are payig $ iterest 80 o a $000 loa. Ouch! The lesso to be leared about borrowig moey: the higher the iterest rate ad the loger the repaymet schedule, the more you pay i iterest. Some baks compute compouded iterest ot oce but several times a year. If a aual iterest rate of % is compouded semiaually, the bak will use oe-half of the aual iterest rate as the rate per period. Hece, i oe year a pricipal of $000 will be compouded twice, each time at a rate of 6%. This will amout to or $.60, about $.60 cets more tha the same pricipal would yield if compouded aually at %. The bakig idustry uses all kids of compoudig periods from aual to semiaual to quarterly to mothly to weekly to eve daily. Suppose the compoudig is doe times a year. For each period, the bak uses the aual iterest divided by ; i.e., r. Sice i t years there are t periods, the formula for compoud iterest becomes: 9
10 t r SP If = (compouded aually), the formula returs to its origial state, S = P ( + r) t. Let s compare what happes to a $000 loa at % compouded for differet periods. Period t r S Aually 0. $0.00 Semiaually 0.06 $.60 Quarterly $5.5 Mothly 0.0 $6.8 Weekly $7.4 Daily $7.49 $7.49 is the extra that a bak receives from compoudig daily as agaist compoudig aually. It hardly makes a differece how the iterest is compouded. I this case, the differece lies i the pricipal. The larger the pricipal, the larger the iterest charged o a daily basis. Try the formula for the above periods with a pricipal of $,000,000 ad ote what happes. Note that the reverse of borrowig moey is ivestig moey. Ivestig moey at compoud iterest geerates, over the log term, sigificat earigs. What bites you oe way (borrowig) rewards you the other way (ivestig). Let s ow cosider a hypothetical case. Let s assume that the bak loas moey at a iterest rate of 00%. Of course, o oe i his or her right mid would take out a loa at this rate. Ad, if you could fid a ivestmet vehicle that returs 00% you would probably jump o it. Let s cosider what happes i this case. Istead of a pricipal of $000, let P = ad t =. Our equatio ow becomes: Let s see what happes as we vary. S , , , ,000, ,000, SP 0
11 Lo ad behold, the maturity value approaches e, the base of the atural logarithms. Mathematicias have sigified this relatioship as follows: lim e.788 Usig rhetorical algebra, these symbols are read as follows: The limit as approaches ifiity (or icreases without boud) of the sequece of umbers defied by coverges to e. This is almost too icredible to comprehed. Yet, it is aother woder of mathematics. The marvelous coectio betwee the base of the atural logarithms ad the calculatio of compoud iterest at 00% is too amazig to be just a coicidece. Is it ot oe of the astoudig particular details i the Creator s grad desig?
Section 6.4: Series. Section 6.4 Series 413
ectio 64 eries 4 ectio 64: eries A couple decides to start a college fud for their daughter They pla to ivest $50 i the fud each moth The fud pays 6% aual iterest, compouded mothly How much moey will they
More informationARITHMETIC PROGRESSIONS
CHAPTER 5 ARITHMETIC PROGRESSIONS (A) Mai Cocepts ad Results A arithmetic progressio (AP) is a list of umbers i which each term is obtaied by addig a fixed umber d to the precedig term, except the first
More informationUNIT #5. Lesson #2 Arithmetic and Geometric Sequences. Lesson #3 Summation Notation. Lesson #4 Arithmetic Series. Lesson #5 Geometric Series
UNIT #5 SEQUENCES AND SERIES Lesso # Sequeces Lesso # Arithmetic ad Geometric Sequeces Lesso #3 Summatio Notatio Lesso #4 Arithmetic Series Lesso #5 Geometric Series Lesso #6 Mortgage Paymets COMMON CORE
More informationSEQUENCES AND SERIES
Sequeces ad 6 Sequeces Ad SEQUENCES AND SERIES Successio of umbers of which oe umber is desigated as the first, other as the secod, aother as the third ad so o gives rise to what is called a sequece. Sequeces
More informationInfinite Sequences and Series
Chapter 6 Ifiite Sequeces ad Series 6.1 Ifiite Sequeces 6.1.1 Elemetary Cocepts Simply speakig, a sequece is a ordered list of umbers writte: {a 1, a 2, a 3,...a, a +1,...} where the elemets a i represet
More informationCompound Interest. S.Y.Tan. Compound Interest
Compoud Iterest S.Y.Ta Compoud Iterest The yield of simple iterest is costat all throughout the ivestmet or loa term. =2000 r = 0% = 0. t = year =? I =? = 2000 (+ (0.)()) = 3200 I = - = 3200-2000 = 200
More informationWORKING WITH NUMBERS
1 WORKING WITH NUMBERS WHAT YOU NEED TO KNOW The defiitio of the differet umber sets: is the set of atural umbers {0, 1,, 3, }. is the set of itegers {, 3,, 1, 0, 1,, 3, }; + is the set of positive itegers;
More information(A sequence also can be thought of as the list of function values attained for a function f :ℵ X, where f (n) = x n for n 1.) x 1 x N +k x N +4 x 3
MATH 337 Sequeces Dr. Neal, WKU Let X be a metric space with distace fuctio d. We shall defie the geeral cocept of sequece ad limit i a metric space, the apply the results i particular to some special
More information3.1 & 3.2 SEQUENCES. Definition 3.1: A sequence is a function whose domain is the positive integers (=Z ++ )
3. & 3. SEQUENCES Defiitio 3.: A sequece is a fuctio whose domai is the positive itegers (=Z ++ ) Examples:. f() = for Z ++ or, 4, 6, 8, 0,. a = +/ or, ½, / 3, ¼, 3. b = /² or, ¼, / 9, 4. c = ( ) + or
More informationPROPERTIES OF THE POSITIVE INTEGERS
PROPERTIES OF THE POSITIVE ITEGERS The first itroductio to mathematics occurs at the pre-school level ad cosists of essetially coutig out the first te itegers with oe s figers. This allows the idividuals
More informationMath 1030Q Spring Exam #2 Review. (9.2) 8x = log (9.2) 8x = log.32 8x log 9.2 log log log 9.2. x =.06418
Math 1030Q Sprig 2013 Exam #2 Review 1. Solve for x: 2 + 9.2 8x = 2.32 Solutio: 2 + 9.2 8x = 2.32 9.2 8x = 2.32 2 log 9.2 8x = log.32 8x log 9.2 = log.32 8x log 9.2 log.32 = 8 log 9.2 8 log 9.2 x =.06418
More informationn m CHAPTER 3 RATIONAL EXPONENTS AND RADICAL FUNCTIONS 3-1 Evaluate n th Roots and Use Rational Exponents Real nth Roots of a n th Root of a
CHAPTER RATIONAL EXPONENTS AND RADICAL FUNCTIONS Big IDEAS: 1) Usig ratioal expoets ) Performig fuctio operatios ad fidig iverse fuctios ) Graphig radical fuctios ad solvig radical equatios Sectio: Essetial
More informationChapter 7: Numerical Series
Chapter 7: Numerical Series Chapter 7 Overview: Sequeces ad Numerical Series I most texts, the topic of sequeces ad series appears, at first, to be a side topic. There are almost o derivatives or itegrals
More informationExponents. Learning Objectives. Pre-Activity
Sectio. Pre-Activity Preparatio Epoets A Chai Letter Chai letters are geerated every day. If you sed a chai letter to three frieds ad they each sed it o to three frieds, who each sed it o to three frieds,
More informationChapter 6 Overview: Sequences and Numerical Series. For the purposes of AP, this topic is broken into four basic subtopics:
Chapter 6 Overview: Sequeces ad Numerical Series I most texts, the topic of sequeces ad series appears, at first, to be a side topic. There are almost o derivatives or itegrals (which is what most studets
More informationPrecalculus MATH Sections 3.1, 3.2, 3.3. Exponential, Logistic and Logarithmic Functions
Precalculus MATH 2412 Sectios 3.1, 3.2, 3.3 Epoetial, Logistic ad Logarithmic Fuctios Epoetial fuctios are used i umerous applicatios coverig may fields of study. They are probably the most importat group
More informationA sequence of numbers is a function whose domain is the positive integers. We can see that the sequence
Sequeces A sequece of umbers is a fuctio whose domai is the positive itegers. We ca see that the sequece,, 2, 2, 3, 3,... is a fuctio from the positive itegers whe we write the first sequece elemet as
More informationSequences A sequence of numbers is a function whose domain is the positive integers. We can see that the sequence
Sequeces A sequece of umbers is a fuctio whose domai is the positive itegers. We ca see that the sequece 1, 1, 2, 2, 3, 3,... is a fuctio from the positive itegers whe we write the first sequece elemet
More informationThe "Last Riddle" of Pierre de Fermat, II
The "Last Riddle" of Pierre de Fermat, II Alexader Mitkovsky mitkovskiy@gmail.com Some time ago, I published a work etitled, "The Last Riddle" of Pierre de Fermat " i which I had writte a proof of the
More informationRevision Topic 1: Number and algebra
Revisio Topic : Number ad algebra Chapter : Number Differet types of umbers You eed to kow that there are differet types of umbers ad recogise which group a particular umber belogs to: Type of umber Symbol
More informationMIXED REVIEW of Problem Solving
MIXED REVIEW of Problem Solvig STATE TEST PRACTICE classzoe.com Lessos 2.4 2.. MULTI-STEP PROBLEM A ball is dropped from a height of 2 feet. Each time the ball hits the groud, it bouces to 70% of its previous
More informationSail into Summer with Math!
Sail ito Summer with Math! For Studets Eterig Hoors Geometry This summer math booklet was developed to provide studets i kidergarte through the eighth grade a opportuity to review grade level math objectives
More informationSEQUENCES AND SERIES
9 SEQUENCES AND SERIES INTRODUCTION Sequeces have may importat applicatios i several spheres of huma activities Whe a collectio of objects is arraged i a defiite order such that it has a idetified first
More informationLesson 10: Limits and Continuity
www.scimsacademy.com Lesso 10: Limits ad Cotiuity SCIMS Academy 1 Limit of a fuctio The cocept of limit of a fuctio is cetral to all other cocepts i calculus (like cotiuity, derivative, defiite itegrals
More information6.3 Testing Series With Positive Terms
6.3. TESTING SERIES WITH POSITIVE TERMS 307 6.3 Testig Series With Positive Terms 6.3. Review of what is kow up to ow I theory, testig a series a i for covergece amouts to fidig the i= sequece of partial
More informationMath 155 (Lecture 3)
Math 55 (Lecture 3) September 8, I this lecture, we ll cosider the aswer to oe of the most basic coutig problems i combiatorics Questio How may ways are there to choose a -elemet subset of the set {,,,
More information6 Integers Modulo n. integer k can be written as k = qn + r, with q,r, 0 r b. So any integer.
6 Itegers Modulo I Example 2.3(e), we have defied the cogruece of two itegers a,b with respect to a modulus. Let us recall that a b (mod ) meas a b. We have proved that cogruece is a equivalece relatio
More information4.3 Growth Rates of Solutions to Recurrences
4.3. GROWTH RATES OF SOLUTIONS TO RECURRENCES 81 4.3 Growth Rates of Solutios to Recurreces 4.3.1 Divide ad Coquer Algorithms Oe of the most basic ad powerful algorithmic techiques is divide ad coquer.
More informationChapter 6: Numerical Series
Chapter 6: Numerical Series 327 Chapter 6 Overview: Sequeces ad Numerical Series I most texts, the topic of sequeces ad series appears, at first, to be a side topic. There are almost o derivatives or itegrals
More informationRADICAL EXPRESSION. If a and x are real numbers and n is a positive integer, then x is an. n th root theorems: Example 1 Simplify
Example 1 Simplify 1.2A Radical Operatios a) 4 2 b) 16 1 2 c) 16 d) 2 e) 8 1 f) 8 What is the relatioship betwee a, b, c? What is the relatioship betwee d, e, f? If x = a, the x = = th root theorems: RADICAL
More informationOnce we have a sequence of numbers, the next thing to do is to sum them up. Given a sequence (a n ) n=1
. Ifiite Series Oce we have a sequece of umbers, the ext thig to do is to sum them up. Give a sequece a be a sequece: ca we give a sesible meaig to the followig expressio? a = a a a a While summig ifiitely
More informationMA131 - Analysis 1. Workbook 7 Series I
MA3 - Aalysis Workbook 7 Series I Autum 008 Cotets 4 Series 4. Defiitios............................... 4. Geometric Series........................... 4 4.3 The Harmoic Series.........................
More information14.2 Simplifying Expressions with Rational Exponents and Radicals
Name Class Date 14. Simplifyig Expressios with Ratioal Expoets ad Radicals Essetial Questio: How ca you write a radical expressio as a expressio with a ratioal expoet? Resource Locker Explore Explorig
More informationARITHMETIC PROGRESSION
CHAPTER 5 ARITHMETIC PROGRESSION Poits to Remember :. A sequece is a arragemet of umbers or objects i a defiite order.. A sequece a, a, a 3,..., a,... is called a Arithmetic Progressio (A.P) if there exists
More informationThe Binomial Theorem
The Biomial Theorem Robert Marti Itroductio The Biomial Theorem is used to expad biomials, that is, brackets cosistig of two distict terms The formula for the Biomial Theorem is as follows: (a + b ( k
More information= 4 and 4 is the principal cube root of 64.
Chapter Real Numbers ad Radicals Day 1: Roots ad Radicals A2TH SWBAT evaluate radicals of ay idex Do Now: Simplify the followig: a) 2 2 b) (-2) 2 c) -2 2 d) 8 2 e) (-8) 2 f) 5 g)(-5) Based o parts a ad
More informationEnd-of-Year Contest. ERHS Math Club. May 5, 2009
Ed-of-Year Cotest ERHS Math Club May 5, 009 Problem 1: There are 9 cois. Oe is fake ad weighs a little less tha the others. Fid the fake coi by weighigs. Solutio: Separate the 9 cois ito 3 groups (A, B,
More informationSEQUENCE AND SERIES NCERT
9. Overview By a sequece, we mea a arragemet of umbers i a defiite order accordig to some rule. We deote the terms of a sequece by a, a,..., etc., the subscript deotes the positio of the term. I view of
More informationAddition: Property Name Property Description Examples. a+b = b+a. a+(b+c) = (a+b)+c
Notes for March 31 Fields: A field is a set of umbers with two (biary) operatios (usually called additio [+] ad multiplicatio [ ]) such that the followig properties hold: Additio: Name Descriptio Commutativity
More informationIntermediate Math Circles November 4, 2009 Counting II
Uiversity of Waterloo Faculty of Mathematics Cetre for Educatio i Mathematics ad Computig Itermediate Math Circles November 4, 009 Coutig II Last time, after lookig at the product rule ad sum rule, we
More informationAlgebra II Notes Unit Seven: Powers, Roots, and Radicals
Syllabus Objectives: 7. The studets will use properties of ratioal epoets to simplify ad evaluate epressios. 7.8 The studet will solve equatios cotaiig radicals or ratioal epoets. b a, the b is the radical.
More informationSection 5.1 The Basics of Counting
1 Sectio 5.1 The Basics of Coutig Combiatorics, the study of arragemets of objects, is a importat part of discrete mathematics. I this chapter, we will lear basic techiques of coutig which has a lot of
More informationSets. Sets. Operations on Sets Laws of Algebra of Sets Cardinal Number of a Finite and Infinite Set. Representation of Sets Power Set Venn Diagram
Sets MILESTONE Sets Represetatio of Sets Power Set Ve Diagram Operatios o Sets Laws of lgebra of Sets ardial Number of a Fiite ad Ifiite Set I Mathematical laguage all livig ad o-livig thigs i uiverse
More informationLesson 1.1 Recursively Defined Sequences
Lesso 1.1 Recursively Defied Sequeces 1. Tell whether each sequece is arithmetic, geometric, or either. a. 1,, 9, 13,... b. 2, 6, 18, 4,... c. 1, 1, 2, 3,, 8,... d. 16, 4, 1,.2,... e. 1, 1, 1, 1,... f..6,
More informationSOLUTIONS TO PRISM PROBLEMS Junior Level 2014
SOLUTIONS TO PRISM PROBLEMS Juior Level 04. (B) Sice 50% of 50 is 50 5 ad 50% of 40 is the secod by 5 0 5. 40 0, the first exceeds. (A) Oe way of comparig the magitudes of the umbers,,, 5 ad 0.7 is 4 5
More informationOrder doesn t matter. There exists a number (zero) whose sum with any number is the number.
P. Real Numbers ad Their Properties Natural Numbers 1,,3. Whole Numbers 0, 1,,... Itegers..., -1, 0, 1,... Real Numbers Ratioal umbers (p/q) Where p & q are itegers, q 0 Irratioal umbers o-termiatig ad
More informationMA131 - Analysis 1. Workbook 3 Sequences II
MA3 - Aalysis Workbook 3 Sequeces II Autum 2004 Cotets 2.8 Coverget Sequeces........................ 2.9 Algebra of Limits......................... 2 2.0 Further Useful Results........................
More informationMath 113 Exam 3 Practice
Math Exam Practice Exam will cover.-.9. This sheet has three sectios. The first sectio will remid you about techiques ad formulas that you should kow. The secod gives a umber of practice questios for you
More informationFLC Ch 8 & 9. Evaluate. Check work. a) b) c) d) e) f) g) h) i) j) k) l) m) n) o) 3. p) q) r) s) t) 3.
Math 100 Elemetary Algebra Sec 8.1: Radical Expressios List perfect squares ad evaluate their square root. Kow these perfect squares for test. Def The positive (pricipal) square root of x, writte x, is
More informationBertrand s Postulate
Bertrad s Postulate Lola Thompso Ross Program July 3, 2009 Lola Thompso (Ross Program Bertrad s Postulate July 3, 2009 1 / 33 Bertrad s Postulate I ve said it oce ad I ll say it agai: There s always a
More informationSECTION 1.5 : SUMMATION NOTATION + WORK WITH SEQUENCES
SECTION 1.5 : SUMMATION NOTATION + WORK WITH SEQUENCES Read Sectio 1.5 (pages 5 9) Overview I Sectio 1.5 we lear to work with summatio otatio ad formulas. We will also itroduce a brief overview of sequeces,
More informationThe Growth of Functions. Theoretical Supplement
The Growth of Fuctios Theoretical Supplemet The Triagle Iequality The triagle iequality is a algebraic tool that is ofte useful i maipulatig absolute values of fuctios. The triagle iequality says that
More informationSeunghee Ye Ma 8: Week 5 Oct 28
Week 5 Summary I Sectio, we go over the Mea Value Theorem ad its applicatios. I Sectio 2, we will recap what we have covered so far this term. Topics Page Mea Value Theorem. Applicatios of the Mea Value
More informationSection 1.1. Calculus: Areas And Tangents. Difference Equations to Differential Equations
Differece Equatios to Differetial Equatios Sectio. Calculus: Areas Ad Tagets The study of calculus begis with questios about chage. What happes to the velocity of a swigig pedulum as its positio chages?
More informationSection 7 Fundamentals of Sequences and Series
ectio Fudametals of equeces ad eries. Defiitio ad examples of sequeces A sequece ca be thought of as a ifiite list of umbers. 0, -, -0, -, -0...,,,,,,. (iii),,,,... Defiitio: A sequece is a fuctio which
More informationData Analysis and Statistical Methods Statistics 651
Data Aalysis ad Statistical Methods Statistics 651 http://www.stat.tamu.edu/~suhasii/teachig.html Suhasii Subba Rao Review of testig: Example The admistrator of a ursig home wats to do a time ad motio
More information1. n! = n. tion. For example, (n+1)! working with factorials. = (n+1) n (n 1) 2 1
Biomial Coefficiets ad Permutatios Mii-lecture The followig pages discuss a few special iteger coutig fuctios You may have see some of these before i a basic probability class or elsewhere, but perhaps
More informationMath 299 Supplement: Real Analysis Nov 2013
Math 299 Supplemet: Real Aalysis Nov 203 Algebra Axioms. I Real Aalysis, we work withi the axiomatic system of real umbers: the set R alog with the additio ad multiplicatio operatios +,, ad the iequality
More informationZeros of Polynomials
Math 160 www.timetodare.com 4.5 4.6 Zeros of Polyomials I these sectios we will study polyomials algebraically. Most of our work will be cocered with fidig the solutios of polyomial equatios of ay degree
More informationThe picture in figure 1.1 helps us to see that the area represents the distance traveled. Figure 1: Area represents distance travelled
1 Lecture : Area Area ad distace traveled Approximatig area by rectagles Summatio The area uder a parabola 1.1 Area ad distace Suppose we have the followig iformatio about the velocity of a particle, how
More informationMETRO EAST EDUCATION DISTRICT
METRO EAST EDUCATION DISTRICT COMMON PAPER GRADE 1 MATHEMATICS P1 SEPTEMBER 018 MARKS: 150 TIME: 3 hours This questio paper cosists of 10 pages ad 1 iformatio sheet. INSTRUCTIONS AND INFORMATION Read the
More information= = =
Sec 5.8 Sec 6. Mathematical Modelig (Arithmetic & Geometric Series) Name: Carl Friedrich Gauss is probably oe of the most oted complete mathematicias i history. As the story goes, he was potetially recogiized
More informationCHAPTER 10 INFINITE SEQUENCES AND SERIES
CHAPTER 10 INFINITE SEQUENCES AND SERIES 10.1 Sequeces 10.2 Ifiite Series 10.3 The Itegral Tests 10.4 Compariso Tests 10.5 The Ratio ad Root Tests 10.6 Alteratig Series: Absolute ad Coditioal Covergece
More informationP1 Chapter 8 :: Binomial Expansion
P Chapter 8 :: Biomial Expasio jfrost@tiffi.kigsto.sch.uk www.drfrostmaths.com @DrFrostMaths Last modified: 6 th August 7 Use of DrFrostMaths for practice Register for free at: www.drfrostmaths.com/homework
More informationCHAPTER I: Vector Spaces
CHAPTER I: Vector Spaces Sectio 1: Itroductio ad Examples This first chapter is largely a review of topics you probably saw i your liear algebra course. So why cover it? (1) Not everyoe remembers everythig
More informationa 3, a 4, ... are the terms of the sequence. The number a n is the nth term of the sequence, and the entire sequence is denoted by a n
60_090.qxd //0 : PM Page 59 59 CHAPTER 9 Ifiite Series Sectio 9. EXPLORATION Fidig Patters Describe a patter for each of the followig sequeces. The use your descriptio to write a formula for the th term
More informationMA131 - Analysis 1. Workbook 2 Sequences I
MA3 - Aalysis Workbook 2 Sequeces I Autum 203 Cotets 2 Sequeces I 2. Itroductio.............................. 2.2 Icreasig ad Decreasig Sequeces................ 2 2.3 Bouded Sequeces..........................
More informationSequences I. Chapter Introduction
Chapter 2 Sequeces I 2. Itroductio A sequece is a list of umbers i a defiite order so that we kow which umber is i the first place, which umber is i the secod place ad, for ay atural umber, we kow which
More informationStudents will calculate quantities that involve positive and negative rational exponents.
: Ratioal Expoets What are ad? Studet Outcomes Studets will calculate quatities that ivolve positive ad egative ratioal expoets. Lesso Notes Studets exted their uderstadig of iteger expoets to ratioal
More informationThe Random Walk For Dummies
The Radom Walk For Dummies Richard A Mote Abstract We look at the priciples goverig the oe-dimesioal discrete radom walk First we review five basic cocepts of probability theory The we cosider the Beroulli
More informationSimulation. Two Rule For Inverting A Distribution Function
Simulatio Two Rule For Ivertig A Distributio Fuctio Rule 1. If F(x) = u is costat o a iterval [x 1, x 2 ), the the uiform value u is mapped oto x 2 through the iversio process. Rule 2. If there is a jump
More informationActivity 3: Length Measurements with the Four-Sided Meter Stick
Activity 3: Legth Measuremets with the Four-Sided Meter Stick OBJECTIVE: The purpose of this experimet is to study errors ad the propagatio of errors whe experimetal data derived usig a four-sided meter
More informationFUNCTIONS (11 UNIVERSITY)
FINAL EXAM REVIEW FOR MCR U FUNCTIONS ( UNIVERSITY) Overall Remiders: To study for your eam your should redo all your past tests ad quizzes Write out all the formulas i the course to help you remember
More information18.440, March 9, Stirling s formula
Stirlig s formula 8.44, March 9, 9 The factorial fuctio! is importat i evaluatig biomial, hypergeometric, ad other probabilities. If is ot too large,! ca be computed directly, by calculators or computers.
More informationBuilding Sequences and Series with a Spreadsheet (Create)
Overview I this activity, studets will lear how to costruct a.ts file to ivestigate sequeces ad series ad to discover some iterestig patters while avoidig tedious calculatios. They will explore both arithmetic
More informationCSE 191, Class Note 05: Counting Methods Computer Sci & Eng Dept SUNY Buffalo
Coutig Methods CSE 191, Class Note 05: Coutig Methods Computer Sci & Eg Dept SUNY Buffalo c Xi He (Uiversity at Buffalo CSE 191 Discrete Structures 1 / 48 Need for Coutig The problem of coutig the umber
More informationIf we want to add up the area of four rectangles, we could find the area of each rectangle and then write this sum symbolically as:
Sigma Notatio: If we wat to add up the area of four rectagles, we could fid the area of each rectagle ad the write this sum symbolically as: Sum A A A A Liewise, the sum of the areas of te triagles could
More informationINTEGRATION BY PARTS (TABLE METHOD)
INTEGRATION BY PARTS (TABLE METHOD) Suppose you wat to evaluate cos d usig itegratio by parts. Usig the u dv otatio, we get So, u dv d cos du d v si cos d si si d or si si d We see that it is ecessary
More informationMAT 271 Project: Partial Fractions for certain rational functions
MAT 7 Project: Partial Fractios for certai ratioal fuctios Prerequisite kowledge: partial fractios from MAT 7, a very good commad of factorig ad complex umbers from Precalculus. To complete this project,
More informationAP Calculus Chapter 9: Infinite Series
AP Calculus Chapter 9: Ifiite Series 9. Sequeces a, a 2, a 3, a 4, a 5,... Sequece: A fuctio whose domai is the set of positive itegers = 2 3 4 a = a a 2 a 3 a 4 terms of the sequece Begi with the patter
More informationGenerating Functions. 1 Operations on generating functions
Geeratig Fuctios The geeratig fuctio for a sequece a 0, a,..., a,... is defied to be the power series fx a x. 0 We say that a 0, a,... is the sequece geerated by fx ad a is the coefficiet of x. Example
More informationIn number theory we will generally be working with integers, though occasionally fractions and irrationals will come into play.
Number Theory Math 5840 otes. Sectio 1: Axioms. I umber theory we will geerally be workig with itegers, though occasioally fractios ad irratioals will come ito play. Notatio: Z deotes the set of all itegers
More informationEssential Question How can you recognize an arithmetic sequence from its graph?
. Aalyzig Arithmetic Sequeces ad Series COMMON CORE Learig Stadards HSF-IF.A.3 HSF-BF.A. HSF-LE.A. Essetial Questio How ca you recogize a arithmetic sequece from its graph? I a arithmetic sequece, the
More informationMathematics: Paper 1
GRADE 1 EXAMINATION JULY 013 Mathematics: Paper 1 EXAMINER: Combied Paper MODERATORS: JE; RN; SS; AVDB TIME: 3 Hours TOTAL: 150 PLEASE READ THE FOLLOWING INSTRUCTIONS CAREFULLY 1. This questio paper cosists
More informationFind a formula for the exponential function whose graph is given , 1 2,16 1, 6
Math 4 Activity (Due by EOC Apr. ) Graph the followig epoetial fuctios by modifyig the graph of f. Fid the rage of each fuctio.. g. g. g 4. g. g 6. g Fid a formula for the epoetial fuctio whose graph is
More informationPhysics 116A Solutions to Homework Set #1 Winter Boas, problem Use equation 1.8 to find a fraction describing
Physics 6A Solutios to Homework Set # Witer 0. Boas, problem. 8 Use equatio.8 to fid a fractio describig 0.694444444... Start with the formula S = a, ad otice that we ca remove ay umber of r fiite decimals
More information3 Gauss map and continued fractions
ICTP, Trieste, July 08 Gauss map ad cotiued fractios I this lecture we will itroduce the Gauss map, which is very importat for its coectio with cotiued fractios i umber theory. The Gauss map G : [0, ]
More informationAPPENDIX F Complex Numbers
APPENDIX F Complex Numbers Operatios with Complex Numbers Complex Solutios of Quadratic Equatios Polar Form of a Complex Number Powers ad Roots of Complex Numbers Operatios with Complex Numbers Some equatios
More informationLESSON 2: SIMPLIFYING RADICALS
High School: Workig with Epressios LESSON : SIMPLIFYING RADICALS N.RN.. C N.RN.. B 5 5 C t t t t t E a b a a b N.RN.. 4 6 N.RN. 4. N.RN. 5. N.RN. 6. 7 8 N.RN. 7. A 7 N.RN. 8. 6 80 448 4 5 6 48 00 6 6 6
More information4.1 Sigma Notation and Riemann Sums
0 the itegral. Sigma Notatio ad Riema Sums Oe strategy for calculatig the area of a regio is to cut the regio ito simple shapes, calculate the area of each simple shape, ad the add these smaller areas
More informationTopic 1 2: Sequences and Series. A sequence is an ordered list of numbers, e.g. 1, 2, 4, 8, 16, or
Topic : Sequeces ad Series A sequece is a ordered list of umbers, e.g.,,, 8, 6, or,,,.... A series is a sum of the terms of a sequece, e.g. + + + 8 + 6 + or... Sigma Notatio b The otatio f ( k) is shorthad
More informationCORE MATHEMATICS PI Page 1 of 18 HILTON COLLEGE TRIAL EXAMINATION AUGUST 2014 CORE MATHEMATICS PAPER I GENERAL INSTRUCTIONS
CORE MATHEMATICS PI Page of 8 HILTON COLLEGE TRIAL EXAMINATION AUGUST 04 Time: hours CORE MATHEMATICS PAPER I GENERAL INSTRUCTIONS 50 marks PLEASE READ THE FOLLOWING INSTRUCTIONS CAREFULLY.. This questio
More informationSequences, Mathematical Induction, and Recursion. CSE 2353 Discrete Computational Structures Spring 2018
CSE 353 Discrete Computatioal Structures Sprig 08 Sequeces, Mathematical Iductio, ad Recursio (Chapter 5, Epp) Note: some course slides adopted from publisher-provided material Overview May mathematical
More informationInfinite Series. Definition. An infinite series is an expression of the form. Where the numbers u k are called the terms of the series.
Ifiite Series Defiitio. A ifiite series is a expressio of the form uk = u + u + u + + u + () 2 3 k Where the umbers u k are called the terms of the series. Such a expressio is meat to be the result of
More informationZ ß cos x + si x R du We start with the substitutio u = si(x), so du = cos(x). The itegral becomes but +u we should chage the limits to go with the ew
Problem ( poits) Evaluate the itegrals Z p x 9 x We ca draw a right triagle labeled this way x p x 9 From this we ca read off x = sec, so = sec ta, ad p x 9 = R ta. Puttig those pieces ito the itegralrwe
More informationSeptember 2012 C1 Note. C1 Notes (Edexcel) Copyright - For AS, A2 notes and IGCSE / GCSE worksheets 1
September 0 s (Edecel) Copyright www.pgmaths.co.uk - For AS, A otes ad IGCSE / GCSE worksheets September 0 Copyright www.pgmaths.co.uk - For AS, A otes ad IGCSE / GCSE worksheets September 0 Copyright
More informationA REVIEW OF ELEMENTARY MATHEMATICS: FUNCTIONS AND OPERATIONS
QRMC02 9/7/0 4:39 PM Page 7 CHAPTER TWO A REVIEW OF ELEMENTARY MATHEMATICS: FUNCTIONS AND OPERATIONS 2. INTRODUCTION This chapter cotais a review of some of the most basic mathematics fuctios ad operatios
More information3.2 Properties of Division 3.3 Zeros of Polynomials 3.4 Complex and Rational Zeros of Polynomials
Math 60 www.timetodare.com 3. Properties of Divisio 3.3 Zeros of Polyomials 3.4 Complex ad Ratioal Zeros of Polyomials I these sectios we will study polyomials algebraically. Most of our work will be cocered
More informationPROBLEM SET 5 SOLUTIONS 126 = , 37 = , 15 = , 7 = 7 1.
Math 7 Sprig 06 PROBLEM SET 5 SOLUTIONS Notatios. Give a real umber x, we will defie sequeces (a k ), (x k ), (p k ), (q k ) as i lecture.. (a) (5 pts) Fid the simple cotiued fractio represetatios of 6
More information