Mark Scheme (Results) Summer 2008

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1 Mark (Results) Summer 8 GCE GCE Mathematics (7/) Mark Eecel Limite. Registere in Englan an Wales No. 97 Registere Office: One9 High Holborn, Lonon WCV 7BH

2 7 Further Pure FP Mark Question. cos. (.8 ) Ma be imlicit B. (..8.) M.. (..) Allow awrt A. cos... [or. cos(..cos.) ] Aft.88. (..88. ) Requires use of the ifferential equation to fin M (..) A ()

3 Degree moe in calculator: Gives answers:. (.999 ).7 (.78 ) This can score B M A Aft M A

4 . (a) q q is M A ( eqns imlie) ) ( q q is M A ( eqns, use of arameter imlie) q M: Two equations, one in, one in q M A q q (*) A () (b) or (or with q instea of ) M [ (8 ) ( 8) ( ) ] or q A < q M: Use q to fin value of an of q A: Positive values must be rejecte M A () (c) z, z, z An eqns, with value of M z (or searate equations) M E.vector is k (An non-zero value of k) A () () (a) Assuming a value for, e.g., gives M A A. (a) Assuming result an working backwars : ( ), gives M A A (b) Alternative: z z or z (or q instea of ) M z, z, z z z (i), z (ii), z (iii) From (i) an (iii) z From (ii) (or equiv. in terms of an/or q) A <,, q A: Positive values must be rejecte M A (b) Using the eigenvector scores no marks in this art.

5 . (a) ( ) ) ( M A ( ) ( ) ( ) (*) A () (b) B Follow through: Bft... M A () (c)., (..) [awrt.77] B () (8) (a) M: Use of rouct rule (at least once) an imlicit ifferentiation (at least once). (b) M: Use of series eansion with values for the erivatives (can be allowe without the first term, an can also be allowe if final term uses rather than!)

6 . (a) ( ) i i ( ) M A ( ) M Centre (, ), raius A, A () (b) Circle, centre on -ais B B B C (, ), r Bft O Follow through centre an raius, but eenent on first B. There must be inication of their, or on the -ais an no contraictor evience for their raius. Straight line B Straight line through (, ), or er. bisector of (, ) an (, ). B Straight line through oint of int. of circle & ve -ais, or through (, ) B B B B () (c) Shaing (onl) insie circle Insie correct circle an all of the correct sie of the correct line this mark is eenent on all the revious B marks in arts (b) an (c). (a) st M: Use z i, an attemt square of moulus of each sie. Not squaring the on the RHS woul be M A. n M: Attemting to eress in the form ( a) ( b) k, or attemting centre an raius from the form g f c B B () ()

7 . (a) k t t( k ) M k k t t( k) t( k) t(k ) M k 9 A () (b) et A k ( k) (Must be seen in art (b)) M (k ), which is alwas ositive M A is non-singular Acso () (c) A k k k k k M A () () k, A B A q A q M A () Alt., B M A for solving two sim. eqns. in an to give.,. (o.e.) () (b) n M: Alternative is to use quaratic formula on the quaratic equation, or to use the iscriminant, with a comment about no real roots, or can t equal zero, or a comment about the conition for singularit. ± 8 A Conclusion. (c) M: Nee, k's unchange an attemt to change sign for their et A either (leaving as to right) or k (leaving as bottom left). () M: Requires an attemt to multil the matrices.

8 . (a) ( cosθ isinθ ) cosθ isinθ (b) (c) true for n B Assume true for n k, ( cos θ isinθ ) cos kθ isin kθ k ( cosθ isinθ ) (cos kθ isin kθ )( cosθ isinθ ) k cos k θ cosθ sin kθ sinθ i(sin kθ cosθ cos kθ sinθ ) (Can be achieve either from the line above or the line below) cos( k ) θ isin( k ) θ Requires full justification of ( cosθ isinθ ) cos( k ) θ isin( k ) θ k M M A ( true for n k if true for n k) true for n Z b inuction Acso () cos θ Re[ (cosθ isinθ ) ] cos θ cos θ i sin θ cosθ i sin θ M A cos θ cos θ sin θ cosθ sin θ M cos θ cos θ ( cos θ ) cosθ ( cos θ ) M cos θ cos θ cos θ cosθ (*) Acso () cosθ cosθ cos θ M π π θ θ A cosθ, (a) Alternative: For the n i i i ( ) M mark: ( e )( e ) e π cos is a root (*) A () kθ θ θ k (b) Alternative: z z z z z z M z z z z z z cosθ cosθ cosθ A ( cosθ )... an attemt to ut cos θ in owers of cos θ M Correct metho (or formula) for utting cos θ in owers of cos θ M cosθ cos θ cos θ cosθ Acso (c) Alternatives: (i) Substitute given root into : π π π π cos cos cos cos M π Multil b cos θ an use result from art (b):... cos A an conclusion A π (ii) Use θ in result from art (b) M π π π cos cos cos an ivie b cos θ A an conclusion A ()

9 7. (a) PQ i j k, PR i j k B i j k PQ PR i j k M A () (b) r. (i j k) (i k). (i j k) [ma use OQ uuur uuur or OR ] M r. (i j k) o.e. ft from (a) Aft () (c) z (i), z (ii) (i) (ii) 7 7z, z (M: Eliminate one variable) M In (ii) z z, z (M: Substitute back) M z an z o.e. ( ) z () () () Writing own irection vector of PS from art (c). (Two correct -term equations) A o.e. (M: Form cartesian equations) M A () QR i j k PS PS // QR (or cross-rouct ) A () (e) PT i j (or QT i j k or RT i j k) M Volume uuur PQ PR. PT uuur uuur (i j k). (i j) ft from (a) (Instea of PQ PR, it coul be PQ QR or PR QR ) M Aft ( ) o.e. A () (a) If both vectors are reverse, B M A is ossible () (c) Alternative: Direction of line: 7 M A Through P (,, ) : z M A (e) Alternative: gives M A irectl. Here ft from st line of art (a). Secial case: or instea of, but metho otherwise correct: M A A

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