GÖDEL SPACETIME A THESIS SUBMITTED TO THE GRADUATE SCHOOL OF NATURAL AND APPLIED SCIENCES OF MIDDLE EAST TECHNICAL UNIVERSITY MEHMET KAVUK

Size: px
Start display at page:

Download "GÖDEL SPACETIME A THESIS SUBMITTED TO THE GRADUATE SCHOOL OF NATURAL AND APPLIED SCIENCES OF MIDDLE EAST TECHNICAL UNIVERSITY MEHMET KAVUK"

Transcription

1 GÖDEL SPACETIME A THESIS SUBMITTED TO THE GRADUATE SCHOOL OF NATURAL AND APPLIED SCIENCES OF MIDDLE EAST TECHNICAL UNIVERSITY BY MEHMET KAVUK IN PARTIAL FULFILLMENT OF THE REQUIREMENTS FOR THE DEGREE OF MASTER OF SCIENCE IN PHYSICS AUGUST 5

2 Approval of th Grauat School of Natural an Appli Scincs. Prof. Dr. Canan Özgn Dirctor I crtify that this thsis satisfis all th rquirmnts as a thsis for th gr of Mastr of Scinc. Prof. Dr. Sinan Bilikmn Ha of Dpartmnt This is to crtify that w hav ra this thsis an that in our opinion it is fully aquat in scop an quality as a thsis for th gr of Mastr of Scinc. Assoc. Prof. Dr. Özgür Sarıoğlu Suprvisor Eamining Committ Mmbrs Prof. Dr. Ayş Karasu METU PHYS Assoc. Prof. Dr. Özgür Sarıoğlu METU PHYS Assoc. Prof. Dr. Yusuf İpkoğlu METU PHYS Assist. Prof. Dr. Hakan Öktm METU IAM Assoc. Prof. Dr. Bayram Tkin METU PHYS

3 I hrby clar that all information in this ocumnt has bn obtain an prsnt in accoranc with acamic ruls an thical conuct. I also clar that as rquir by ths ruls an conuct I hav fully cit an rfrnc all matrial an rsults that ar not original to this work. Mhmt Kavuk iii

4 ABSTRACT GÖDEL SPACETIME Kavuk Mhmt MS. Dpartmnt of Physics Suprvisor: Özgür Sarıoğlu August 5 56 pags. In this thsis proprtis of th Göl spactim ar analyz an it is plicitly shown that thr ist clos timlik curvs in this spactim. Gosic motions for massiv particls an light rays ar invstigat. On obsrvs th focusing ffct as a rsult of th solution of th gosic quations. Th tim it taks for a fr particl rlas from a point to com back to its starting point is calculat. A gomtrical intrprtation of th Göl spactim is givn an th qustion of what th Göl spactim looks lik is answr. Kywors: Göl spactim Null gosics Timlik gosics Tim travl Rotation of spactim. iv

5 ÖZ GÖDEL UZAY-ZAMANI Kavuk Mhmt Yüksk Lisans Fizik Bölümü Tz Yönticisi: Özgür Sarıoğlu Ağustos 5 56 sayfa Bu tz Göl uzay-zamanının özlliklri çözümlni v kapalı zamansı ğrilrin varlığı göstrili. Jozik nklmi çözülrk kütlli parçacıkların v ışık mtlrinin jozik harktlri inclni v oaklanma tkisi görülü. Bir noktaan yollanan bir ışık ışınının v srbst bir parçacığın n kaar sür aynı yr öncği hsaplanı. Göl vrninin gomtrik bir yorumu vrili v bu vrnin ny bnziği sorusu cvaplanı. Anahtar klimlr: Göl uzay-zamanı Null joziklr Zamansı joziklr Zamana yolculuk Uzay zamanın önmsi. v

6 To my family an to my girlfrin Görkm Öcalan vi

7 ACKNOWLEDGMENTS Th author wishs to prss his pst gratitu to his suprvisor Özgür Sarıoğlu for his guianc avic criticism ncouragmnts an insight throughout th rsarch. Thank you sincrly. Thr ar no wors to scrib th apprciation an gratitu I fl for my girlfrin Görkm Öcalan. I thank hr for hr ncouragmnt an support. vii

8 TABLE OF CONTENTS PLAGIARISM...iii ABSTRACT...iv ÖZ...v DEDICATION...vi ACKNOWLEDGMENTS...vii TABLE OF CONTENTS...viii CHAPTER. INTRODUCTION.... DERIVATION OF GÖDEL SPACETIME...4. Th Mtric...4. Th Choic of Intgration Constants PROPERTIES OF THE GÖDEL SPACETIME Transformation to Cylinrical Coorinats Killing Vctors Rotation Shar an Epansion GEODESICS Null Gosics Timlik Gosics Th Structur of Light Cons Som Rmarks on Göl Spactim CONCLUSION...39 viii

9 REFERENCES...4 APPENDICES...43 A. Th Componnts of th Einstin Tnsor...43 B. Transformation to Cylinrical Coorinats...44 C. Proof of D. Calculations of th Intgrals..5 i

10 LIST OF FIGURES Figur 3. Th circl C on th t plan which has a tangnt vctor....4 Figur 3. t plan. Lightcons tip ovr an opn out as w proc away from A along concntric circls. Initially such circls ar clos spaclik curvs lik S. Evntually lightcons tip to crat clos null curvs lik N an thn tip furthr to crat clos timlik curvs lik T. Sinc spactim is stationary an rotationally symmtric about ach mattr worllin all obsrvrs s what A ss; all s mattr spinning about thm... Figur 4. Göl s spactim with th irrlvant coorinat z supprss. Th spac is rotationally symmtric about any point; th iagram rprsnts corrctly th rotational symmtry about th r= ais an th tim invarianc. Th light con opns out an tips ovr as r incrass s lin L rsulting in clos timlik curvs. Th iagram os not corrctly rprsnt th fact that all points ar in fact quivalnt...6 Figur 4.: Path of th photon in th r plan for. For vry valu thr is a iffrnt llips passing through th origin. Ths llipss form an nvlop which is a circl with raius r ln aroun th origin...35

11 CHAPTER INTRODUCTION Gnral Rlativity thory hlps us to trmin possibl mols for th larg scal structur of spactim. Each of th mols is a pair M g. Hr M is a four imnsional manifol which rprsnts th totality of all point-vnt locations; an g is a gomtric objct which rprsnts th mtric structur of spactim. W can think of it simply as a function which assigns lngths to vctors at points of M but which assigns ngativ an zro lngths to vctors as wll as positiv ons. It thus partitions th vctors at any point into thr classs an trmins a light con structur. A vctor is sai to b timlik null or spaclik accoring to whthr its lngth is ngativ zro or positiv. Timlik vctors fall insi th con whras null ons fall on th bounary. Of cours ths null cons hav an immiat physical significanc. It is absolutly funamntal to Gnral Rlativity thory that thr is an uppr boun to th sps with which particls can travl as masur by any obsrvr. If w think of vctors at a point as vlocity vctors thn th light con can b intrprt as a marking of that uppr boun []. Massiv particls must hav timlik vlocity vctors; thos with zro mass must hav null ons. Th most important gomtrical notion that turns out to b th tool to travl back in tim is clos timlik curvs. Thy ar simply clos curvs on th spactim manifol whos tangnt vctors at vry point ar timlik an point to th futur. Ths futur irct timlik curvs of cours hav various magnitus u to th spactim mtric in particular lngth an acclration. Th lngth is usually call laps propr tim. Timlik curvs with no accrlation ar call timlik gosics []. In Gnral Rlativity Göl spactim is important bcaus it is th first ampl of a spactim that is a solution of Einstin s fil quations an that has clos timlik curvs which ar classically forbin. In this thsis w will rviw th Göl spactim. In th lat 94s Kurt Göl took an intrst in Einstin's thory of Gnral Rlativity. H was looking for an answr to th qustion of what th natur of tim

12 is. Evntually h succ in fining a nw solution to th fil quations of Einstin s thory of Gnral Rlativity in 949 [] which influnc all th notions about tim known thus far. This nw solution suggsts a spactim with strang proprtis. First of all th spactim is fill with incohrnt prssurlss flui mattr in a stat of uniform rigi rotation. Sconly th particls with no forc on thm follow a path similar to th paths that boomrangs follow. This mans that th particls rlas from a point of th spactim rc from thir starting point until thy rach a critical istanc an thn mov back to thir starting point at a latr tim. Finally an th most important of all thr is a possibility of travling back in tim in th Göl spactim. As a mattr of fact all of us ar travlling in tim uring our aily lif on arth but hr by travlling w man that a particl starting its motion from a spactim point is abl to com back to its starting point again. So thr is no such finit notion as past futur an prsnt in th Göl spactim. In fact Göl s work i not attract much attntion in th bginning. In 956 Kunt [3] in Hamburg Grmany calculat th gosic worl lins in Göl s spactim. H us Killing vctors to fin th first intgrals of th gosic quations as suggst by Fli Pirani. Thn in 96 S. Chanraskhar an J.P. Wright [4] calculat th timlik gosics of th Göl spactim an conclu that thr wasn t any clos timlik gosic so that Göl s rmark on this issu was incorrct. Howvr Göl ha nvr claim that thr wr clos timlik curvs which wr gosics. Noboy notic this misunrstaning until 97 whn Howar Stin [5] show that Chanraskhar an Wright ha bn mistakn. In fact all th calculations on to fin th gosic worl lin of th Göl spactim bgan with ithr th mtric givn in.6 whos solution of th gosic quations has a complicat form an is not vry nlightning to unrstan th gomtrical pictur of th spactim or th mtric conformal to th Göl on. Actually Göl himslf appli a transformation to his mtric.6 to writ it in cylinrical coorinats so as to show th istnc of clos timlik curvs asily. In this thsis w calculat th timlik an null gosics of th Göl spactim by using th Göl mtric writtn in cylinrical coorinats. Thr was no gomtrical figur showing th bhavior of th gosics of th Göl spactim until 973 whn Hawking an Ellis pictur Göl spactim in

13 thir monograph ntitl Th Larg Scal Structur of Spactim [6]. This was th first tim that gomtrical insight was mploy in unrstaning th proprtis of th Göl spactim. In 3 I. Ozsvath an E. Schucking [7] publish a papr whr thy ask th qustion as to how Hawking an Ellis rw this pictur i.. what ar th quations of th null gosics that la to this pictur? Thy bliv that som intrigu ha bn ma whil rawing this pictur. By using a mtric conformal to th Göl mtric thy calculat th null gosics an rconstruct th pictur of Hawking an Ellis. Evn though thy stat a problm rlat with th mattr worl lin which is rawn as spaclik in th pictur of Hawking an Ellis s Figur 4. thy i not giv th quations of th timlik gosics showing that thy rally must b insi th critical raius. In this thsis th problms of th pictur in [6] ar stat again whn ncssary an th ways to corrct it ar shown. In th scon chaptr w bgin with an ansatz an fin th conitions unr which this ansatz satisfis th fil quations of cosmological Einstin s thory of Gnral Rlativity coupl with a prssurlss prfct flui. W first gt th most gnral form of th Göl mtric with thr intgration constants. Howvr A. K. Raychauhuri an S. N. Thakurta [8] show in thir papr that all th solutions obtain for iffrnt valus of th intgration constants can b transformabl to th Göl mtric. Hnc w ci on how to choos th intgration constants so as to gt th original mtric that Göl us in his calculations. In th thir chaptr w invstigat som physical proprtis of th Göl spactim an choos a coorinat systm to transform th mtric into cylinrical coorinats which is usful in monstrating th istnc of clos timlik curvs. W also fin th Killing vctors of th Göl spactim. In th fourth chaptr null an timlik gosics ar calculat an it is shown that ths quations ar th ons from which Figur 4. can b obtain. 3

14 CHAPTER DERIVATION OF THE GÖDEL SPACETIME In this chaptr w bgin with an ansatz an a spcific nrgy-momntum tnsor namly that of a prssurlss prfct flui sourc for th spactim an fin unr what conitions this ansatz satisfis th fil quations of cosmological Einstin s thory of Gnral Rlativity. W n up with th gnral solution of th fil quations with thr intgration constants. As it has bn stat bfor in [8] it is shown that all th solutions obtain for iffrnt valus of th intgration constants can b transformabl to th Göl mtric. By appropriat choic of constants w gt th mtric that Göl foun in his papr.. Th Mtric In 949 Göl foun a nw cosmological solution of Einstin s fil quations of th form [] s g t z u y v t y.. In this mol spactim is full of a prssurlss prfct flui which has an nrgymomntum tnsor of th form T. Hr is th nrgy nsity of th VV flui an V is th flui four-vlocity. To fin unr what conitions. is a solution to th fil quations of cosmological Einstin s thory of Gnral Rlativity with th corrsponing nrgy-momntum tnsor stat i.. to fin th unknown functions u an v w hav to start by calculating th componnts of th Christoffl symbol an th Ricci tnsor corrsponing to this mtric. Th mtric can b writtn in matri form as 4

15 g v v u with an invrs u v v u v u g v. v u v u By using th finition of th Christoffl symbol g g g g. w can calculat th nontrivial componnts of it asily as v v v u vu uv v v u v v u vv u v u u. Hr ot nots rivativ with rspct to. W will us th plicit form of it / whn ncssary. In th sam mannr by using th finition of th Ricci tnsor [9] R.3 w can asily obtain th nontrivial componnts of th Ricci tnsor as R v.4 v u 5

16 R v u v 4 v u vv 4vvu v 4 v u u u u.5 R vu R v 4 v u R u uv vvu u..6 4 v u Ths componnts of th Christoffl symbol an of th Ricci tnsor ar th only ons that o not vanish. Th componnts of th Einstin tnsor ar givn in Appni A. Th Ricci scalar is obtain asily v 3uv 4 v u u u 8vvu 8v v u v R R g..7 4 v u If w put all of ths things togthr in th fil quations of Einstin s Gnral Rlativity with a cosmological constant 8G VV.8 c G g R Rg g an us a co-moving coorinat systm for th nrgy-momntum tnsor i.. tak V.9 so that Hr G is Nwton s gravitational constant c is th sp of light an is th cosmological constant. For simplicity w us units such that G c. 6

17 V g V v g. w gt first of all that G33 R33 Rg33 8 V3V 3 g33 R. whr w us th fact that R 33 an V 3 ar zro. If w us. an put it into.8 w obtain R 8.. VV Thn w can asily obtain th rst of th quations R V V R R V V R.4 8 R v 8VV R 8.5 R 8 V V R R 8v..7 From.5 an.4 w obtain k k k v.7 whr k v u. W also fin from.4 an.3 that 7

18 v k 8..8 Combining.7 togthr with.8 w gt k k 6k..9 k Now lt us solv.9. First not that k / 3/ k k kk / k k k /. Thn.9 bcoms k / kk / k 6k / an multiplying this by k on fins k / / / k k k 6k which can b writtn as k k c k / /. whr c 6. Lt k / p. 8

19 thn. bcoms c p p which is asy to hanl sinc it is a scon orr homognous quation with constant cofficints. Th most gnral solution is givn by p c / c / c c whr c an c ar intgration constants. So by using. w gt k c / c / c c.. From.8 w hav c / c / v c c c whos solution is simply v c / c / c c c3.3 whr c 3 is anothr intgration constant. Lt us fin th paramtr c / 4 4 thn.3 bcoms v c c..4 c 3 9

20 Th maning of will bcom clar in th nt sction. In fact with. an.4 w now hav all w n sinc u can asily b foun by using k v u. Th mtric functions u an v constraints on th intgration constants. satisfy th fil quations with no furthr. Th Choic of th Intgration Constants Now w hav a solution with thr intgration constants. W now limit our consirations to th spcific choic of intgration constants to gt th mtric that Göl prsnt in his papr. In fact Raychauhuri an Thakurta [8] show that all th solutions obtain for iffrnt valus of c c an c 3 can b transformabl to th Göl mtric. Sinc w ar aftr th Göl spactim w will choos appropriat constants so as to gt th Göl mtric. If w tak th ngativ valu of v an choos intgration constants as c c c3 thn. an.4 bcom k v. Rmmbr that k v u so u is asily obtain as u. Now w hav th mtric that Göl us an corrsponing to this mtric i.. all th rlvant quantitis

21 s t z y ty.5 R 4 4 whr th scon quation in th last lin follows immiatly from. an. i.. R g R 8 g V V 8V V 8. This four imnsional spactim can b viw as th sum of a thr imnsional spactim M whos mtric g is givn by s t y ty.6 on th gomtry M fin by th coorinats t y an a on imnsional 3 R spaclik lin with a mtric g givn by s z on th manifol M R fin by th coorinat z. Th mtric on M os not pn on z an th z constant lins ar all orthogonal to M. Sinc clos

22 timlik lins ist for constant z in th M w o not n to consir th full four imnsional spactim insta w can rstrict ourslvs to just M [67]

23 CHAPTER 3 PROPERTIES OF THE GÖDEL SPACETIME In this chaptr w invstigat som physical proprtis of th Göl spactim an choos a coorinat systm to transform th mtric into cylinrical coorinats which is usful in monstrating th istnc of clos timlik curvs. 3. Transformation to Cylinrical Coorinats In his papr Göl ma th transformation to his mtric to monstrat th cylinrical symmtry of th spactim mor plicitly. Th istnc of clos timlik curvs can asily b shown for th mtric writtn in cylinrical coorinats. With th transformation Coshr Cos Sinhr y Sin Sinhr r Tan t t Tan t t th mtric.6 can b transform to th form s Appni B s t r Sinh 4 r Sinh r Sinh r t 3. whr t r an an is intifi with. W in fact hav writtn th mtric in a form which is plicitly cylinrically symmtric sinc it os not pn on. Lt us us th avantag of this symmtry conition an tak a circl r C r const. in th t plan to invstigat th charactristic of such a circl; i.. lt us amin unr what circumstancs it is timlik spaclik or null. 3

24 Figur 3.: Th circl C on th t plan which has a tangnt vctor. W s that th tangnt vctor to th circl C has th lngth squar g g Sinh r Sinh r.. 3. Thn if Sinh r thn C is timlik thn C is null thn C is spaclik s Figur 3.. Th acclration vctor is givn by ; for th timlik unit vctor [7] / g. An plicit calculation yils g / / / g g g 4

25 g g r. r W thn gt th magnitu of th acclration vctor fin as to b Coshr Sinh r. 3.3 Sinhr Sinh r It is asily sn that os not vanish for Sinh r. Thus with th hlp of 3. w s that w hav clos timlik curvs but not gosics sinc its acclration is not zro for r ln. 3. Killing vctors It is asily sn from th mtrics.5 an 3. that th formr amits thr translations along th y t an z as whil th lattr amits rotation aroun th ais. As a mattr of fact by using th Killing quation in Cartsian coorinats 3.4 ; ; w can asily obtain four of th Killing vctors as A t B z C y D y. y 5

26 W also hav a Killing vctor th Cartsian coorinats; in cylinrical coorinats. Transforming back to t y t y w gt th fifth Killing vctor as E t y y y in Cartsian coorinats. Now w hav fiv inpnnt Killing vctors with th following Li algbra. A B A C A D E A B C B D B E C D C C E D D E E. A B an C ar th trivial gnrators corrsponing to th translation invarianc of th mtric.5 in th t z an y irctions rspctivly. W s that A an B commut with vry Killing vctor. Anothr fatur is that th commutator of D with th Killing vctors C an D is proportional to th Killing vctor itslf. Sinc w hav fiv Killing vctors thr is a fiv imnsional group of isomtris in this spactim which is also transitiv. Transitiv mans that no point rmains unchang by a finit transformation. Hnc Göl spactim is homognous an amits th following four paramtr group of transformations: 6

27 i ii iii iv t t y y z z whr an ar th paramtrs of th group. 3.3 Rotation Shar an Epansion If V is th four-vlocity of a flui thn V can b compos as V P 3 a V ; 3.5 whr a is th four-acclration of th flui a V ; V 3.6 is th pansion of th flui worl lins V V ; 3.7 is th rotation -form of th flui an is th shar tnsor V ; P V ; P 3.8 V ; P V ; P P

28 Hr P is th projction tnsor P g VV P V V 3. which projcts a vctor onto th 3-surfac prpnicular to V []. Rotation -form an th shar tnsor ar antisymmtric an symmtric rspctivly. Now sinc w ar co-moving obsrvrs sitting on th flow of th flui our four-vlocity tangnt to th worl lins of th flui has th simplst form givn in.9 an.: V g. V First lt us amin th acclration by using 3.6. Straightforwar calculations show that it is zro: a V V g g. This mans that th flow of th flui movs on th gosics. Th pansion is also asy to calculat with th hlp of 3.7 V. So Göl spactim is not paning which is iffrnt than th obsrvations of our spactim. Our spactim is paning as it is obvious from th r-shift light rays coming towars us from th istant galais. Now a littl bit of work is rquir to fin th rotation -form of th flui: By using th finition of th covariant rivativ V V V ; 3. 8

29 an. w gt V ; g g. From th finition of th Christoffl symbol. w fin g g g g. 3. Multiplication of 3. an 3. givs V P g g g g ; whr th scon trm in th right han si is zro bcaus thr is no tim pnncy in th mtric. Thn w hav V P g g 3.3 ; V P g g 3.4 ; whr in th last lin w hav intrchang th inics an. Now subtract ths two quations an put thm into 3.9 to gt g g g g. 3.5 From 3. w fin g 3.7 9

30 whr w us th fact that g constant. Thn 3.5 bcoms g g. Now w s that th only componnt which survivs is g g an th magnitu of th rotation -form is.

31 Figur 3.: t plan. Light cons tip ovr an opn out as w proc away from A along concntric circls. Initially such circls ar clos spaclik curvs lik S. Evntually light cons tip to crat clos null curvs lik N an thn tip furthr to crat clos timlik curvs lik T. Sinc spactim is stationary an rotationally symmtric about ach mattr worl lin all obsrvrs s what A ss; all s mattr spinning about thm. Now can b intrprt as th rotation of th prssurlss mattr flui in th Göl spactim. In sction 4. w will show that th cntral mattr worl lin is a timlik gosic so if w mov frly on this worl lin w s that th mattr flui aroun us is rotating with th angular vlocity. In fact all th flui mattr contnt is rotating with rspct to vry point in spac bcaus of th homognity of th Göl spactim. Now lt us igrss hr a littl bit an think about th maning of having nonvanishing rotation. Actually this spactim is stationary sinc it amits a timlik Killing vctor fil but it is not static bcaus in orr for this spactim to b static in aition to bing stationary thr shoul ist a hyprsurfac which is

32 orthogonal to th congrunc of timlik Killing vctor fils. Howvr a straightforwar calculation shows that if an only if s Appni C for th proof V [ V ;] = 3.8 which is th conition for hyprsurfac orthogonality. Hnc w can conclu that our worl lins ar not hyprsurfac orthogonal sinc w hav non-vanishing rotation. Lt us now show that th conition 3.8 is ncssary an sufficint for a vctor to b orthogonal to a on-paramtr hyprsurfac. Suppos that thr is a on-paramtr family f of hyprsurfacs givn by f constant. A normal vctor to a hyprsurfac can b writtn as follows; f hf 3.9 whr h is an arbitrary scalar function. Now lt us construct from an arbitrary vctor th compltly antisymmtric tnsor a [ ;] ; ; ; ; ; ;. 3! This tnsor is actually zro for th spcific vctor givn by 3.9 as can b shown as follows: ; h f hf ; ; hf h f h f f ;

33 } { 3! ; ; ; ; ; ; f f h f f h f f h f f h f f h f f h f h hf f h hf f h hf f h hf f h hf f h hf a whr th first trm in th parnthss cancls out with th scon th thir trm with th fourth tc... Thus a ncssary conition for a vctor fil to b vrywhr orthogonal to a on-paramtr family f of thr imnsional hyprsurfacs is a [ ;] =. Hnc our worl lins ar not hyprsurfac orthogonal bcaus 3.8 os not hol for our situation. Thrfor w hav a stationary but non-static spactim. To fin th shar tnsor w just a 3.3 an 3.4 up an fin g g g g. 3. Th last two trms ar obviously zro u to 3.7. By using 3.6 w gt g g g. If w put this quation into 3. w fin. 3. Non of th componnts of th shar tnsor survivs so its magnitu is zro. 3. rprsnts th fact that thr is no istortion in th shap of our collction of tst particls. That is suppos som portion of our tst particls occupy a volum in 3

34 spac in th shap of a sphr thn as tim gos on th sphr will rmain as a sphr as oppos to th cas whr thr is a non-vanishing shar. In th cas of a non-vanishing shar th sphr woul hav bcom an llipsoi as tim pass by. Hnc thr is only a rotation in Göl spactim which actually prvnts us from choosing a cosmic tim coorinat to agr on vnts that ar simultanous. 4

35 CHAPTER 4 GEODESICS In this chaptr gosic motion in Göl spactim is analyz an th gomtrical pictur of th spactim is givn. 4. Null Gosics To stuy th null gosics w us th variational mtho for th mtric givn in 3. an rcapitulat th argumnts that la to Figur 4. blow. This figur is rprouc from [6]. In thir papr [7] Ozsvath an Schucking rw attntion to th fact that th quations us in rawing Figur 4. ar not givn an stat thir blif that an intrigu has bn ma uring th rawing of it. So thy calculat th null gosics of th Göl spactim by using th mtric conformal to th Göl mtric to rconstruct it again. Sinc null gosics ar not affct by such a conformal transformation an sinc th timlik or null natur of a vctor is lft invariant unr such a transformation thr is no loss of gnrality in oing so. Hr w fin th paramtric quations of th null gosics by using th original Göl mtric an try to show that thy ar th ons us in rawing Figur 4.. 5

36 Figur 4.: Göl s spactim with th irrlvant coorinat z supprss. Th spac is rotationally symmtric about any point; th iagram rprsnts corrctly th rotational symmtry about th r= ais an th tim invarianc. Th light con opns out an tips ovr as r incrass s lin L rsulting in clos timlik curvs. Th iagram os not corrctly rprsnt th fact that all points ar in fact quivalnt. 6

37 Consir th following trmization rlat to th thr imnsional mtric 3. which yils th gosics: L L g t 4 r Sinh r Sinh r Sinh r t whr t t r r with th affin paramtr that can b us for null gosics. Sinc th Lagrangian os not pn on t an w hav from th Eulr-Lagrang quations th two intgrals L t t Sinh r a constant 4. L Sinh 4 r Sinh r Sinh r t b constant. 4. Hr a can b intrprt as th total nrgy an b is intrprt as th total angular momntum of th photons. Sinc w ar trying to fin th null gosics w also hav L t r Sinh If w substitut 4. into 4.3 w fin 4 r Sinh r Sinh r t. 4.3 r Cosh r Sinh r a

38 Morovr from 4. an 4. w also gt a b a Sinh r t 4.5 Cosh r b a Sinh r. 4.6 Sinh r Cosh r If w put 4.6 into 4.4 w fin th intgral Coshr Sinhr r /. 4.7 a Cosh r Sinh r b a Sinh r 4.7 givs s Appni D Sinh r Sin a u whr b a 4 4 b a b u an is an intgration constant. a If w put this solution into 4.5 an 4.6 w gt th intgrals t { a Sin a Sin a u a u b} 4.8 Sin a a u { Sin a u b }{ Sin a. u } 8

39 Th first on of ths two intgrals is asir to hanl compar to th scon on so first w fin th solution of th first intgral an thn al with th scon on latr. Aftr som calculations w gt th solution of th first intgral as follows s Appni D: a b u t t a ArcTan Tan a a u u u. 4.9 Now w can invstigat th gosic motion for thr istinct cass: b b an b. Howvr sinc w ar aftr Figur 4. an sinc all th null gosics rawn in it com from r w must choos b. Now it is much simplr to intgrat th scon quation bcaus aftr insrting b th rmaining intgration bcoms trivial. Notic that if w st b thn u an 4. bcoms t t a ArcTan Tan a whras th scon intgral bcoms a. 4. Sin a 4. givs ArcTan Tan a. If w writ thm togthr w now hav th paramtric rprsntation of th null gosics paramtriz by : 9

40 Sinhr Sin a 4. t t a ArcTan Tan a 4. ArcTan Tan a 4.3 whr t an ar intgration constants. Ths quations giv th corrct rprsntation of th null gosics rawn in Figur 4.. For vry valu w hav a iffrnt null gosic. Suppos that on sns out a light signal from point p at som tim of t p in th irction quals zro an lt th constants an t as wll. Thn as th angl incrass th istanc btwn th light signal an th worl lin r incrass until th light signal rachs its maimum istanc r ln from th worl lin r in which cas th angl is qual to /. On can tak th tim th signal rachs th point r ln as t. Continuing on its path th light signal rturns to its starting point at th tim t p. At point p r an 4. givs whras 4. givs t p a. Whn th light signal rachs th point r ln at tim t 4. givs a /. Thn from 4. w fin a. Th tim t p bcoms t p. 3

41 In fact this is th tim for half of th trip. Whn th light signal rturns to its starting point p at a latr tim t p 4. givs a an 4. yils t p a i.. t p. All th rays snt out simultanously in iffrnt irctions of th plan rturn latr at th sam momnt. At th critical istanc r ln from th worl lin r w hav circls for t constant bcaus vry null gosic touchs th t constant plans in on point. In thir paprs Ozsvath an Schucking [7] an Malamnt [] stat that th iagram of th Göl mol in [6] is not corrct about th mattr lins sinc thy ar rawn as spaclik. Howvr thy o not giv th timlik gosics quations which show that all th timlik gosics must b in th circl with raius r ln. In th nt sction w show this proprty of th timlik gosics. Morovr th structur of th light cons i.. what happns to th light cons as w mov away from th worl lin r is givn in sction Timlik Gosics Timlik gosics can b calculat with th sam mtho us in calculating th null gosics but this tim our Lagrangian must b qual to. Obviously 4. an 4. hol also for this situation. Howvr this tim th affin paramtr can b chosn as th propr tim masur by a co-moving obsrvr. Again w st th valu of b to zro bcaus of th sam rason us in th prvious sction. Hnc w hav 3

42 a 4.4 Cosh r a Sinh r t 4.5 Cosh r L t r Sinh 4 r Sinh r Sinh r t. 4.6 If w put 4.4 an 4.5 into 4.6 w obtain Coshr r 4.7 a a Sinh r Cosh r / whos solution is s Appni D Sinhr Sin 4.8 whr a an a with th conition a. If w substitut 4.8 into 4.4 an 4.5 w gt th intgrals { a a Sin Sin } t 4.9 a. 4. Sin Ths ar asily valuat as 3

43 a ArcTan Tan a 4. a a t t a ArcTan Tan a. 4. a For vry valu of a w hav a iffrnt timlik gosic. Whn a an 4. bcom Sinhr r t t rspctivly which corrspons to th cntral mattr worl lin. Suppos that at tim t t p a particl is rlas from point p in Figur 4. in th irction. Thn this particl will mov on th cntral mattr worl lin notic that this particl movs only in tim an will rach th point O at tim t whn. At th n th particl rachs th point pat tim asily obtain t t whn p. Thn on can t p t. p 4 4 For all valus of a r is always smallr than ln. Sinc a is intrprt as th nrgy pr unit mass thn no massiv particl no mattr what its nrgy is can rach this critical raius. All th particls rlas from th point p with iffrnt nrgis will rach som maimum valu of r smallr than ln an 33

44 thn rconvrg to p which shows that all th mattr lins must b insi th cylinr with raius ln. 4.3 Th Structur of th Light Cons To stuy th structur of th light cons w n to fin th clos-form solution of th null gosics quations. Aftr stting b w now com back to an 4.6. Tak 4.6 a Cosh r an substitut this prssion into 4.4 to obtain r Coshr Sinh r givs Sin Sinhr 4.4 Cos with th intgration constant. 34

45 Figur 4.: Path of th photon in th r plan. For vry valu of thr is a iffrnt llips passing through th origin. Ths llipss form an nvlop which is a circl with raius r ln aroun th origin. W hav from 4. that t Sinh r 4.5 or using 4.4 t Tan. 4.6 If w intgrat 4.6 w gt 35

46 t t ArcTan Tan. 4.7 W hav two quations to think about which ar 4.4 an 4.5. From ths two quations w can of cours obtain Figur 4. again. Although all of th commnts ma in sction 4. hol also for ths two quations sinc thr is no istinction btwn thm it will b usful to consir th situation again. For vry valu w hav a iffrnt null gosic. Lt us s what happns to th light rays originating from point p in Figur 4.. Lt us think of th cas whr is zro. W s that th lft han si of 4.4 is maimum whn / th null gosic rachs its largst istanc r ln ; an its istanc is zro whn an. Th light ray starts to mov from point p whn an t t an rachs to its largst istanc from th worl lin r an thn gos to th point p. Th tim takn by th light ray uring th first half of its trip is t / t. All th light rays originat from point p in iffrnt irctions rturn latr at th sam momnt to th point p. Of cours th tim intrval btwn th point p an p is t t. At th istanc r ln from th worl lin r w hav circls for t constant. Ths circls ar null curvs as w s from 3.. Howvr thy ar not gosics. Thy form a cylinr with an ais at r. What happns to th light cons whn w mov away from th ais r? To answr this qustion w n r / t an it is sufficint to consir on raial irction s lin L in Figur 4.. From 4.3 an 4.5 w obtain 36

47 r t r t Coshr Sinh r / Sinh r Coshr Sinh r /. At th origin r th slop of r t is qual to on. This mans that w hav a light con with an angl / 4. That is on th cntral mattr lin th cons ar upright an orint at / 4 to th inicat horizontal plan. Th last prssion bcoms infinit for r ln. It mans as on movs outwar that th cons opn up an tilt ovr in a countr-clockwis irction. At a critical raius r ln thy bcom tangnt to th plan. 4.4 Som Rmarks About th Göl Spactim For a givn point p in th Göl spactim thr is a cylinr associat with p which sparats th spactim into two rgions in a givn coorinat systm in which p rsts on th r lin. All of th points lying insi this cylinr hav raial istancs from p which is lss than ln. In fact this cylinr is construct by th circls with raius r ln which ar also null curvs. Circls with raius r ln ar clos timlik curvs. For any valu of nrgy a th photons originating from p ar confin insi this cylinr. This rsult hols also for massiv particls. Howvr massiv particls ar nvr abl to rach th cylinrical surfac whras th photons ar. Sinc thr ar no clos timlik curvs within this cylinr tim t always incrass along vry futur irct timlik curv. Byon r ln th tim t runs backwar which can b sn from 4.5 a Sinh r t. 4.5 Cosh r 37

48 This prssion is zro for r ln for which th tim t changs its sign. For r ln 4.5 bcoms ngativ which mans t crass. This shows that thr can not b a cosmic tim coorinat t in this spactim which incrass along vry futur irct timlik or null curv. Morovr our obsrvr sitting on th r lin will obsrv only som part of th spactim sinc all of th gosics ar confin insi th cylinr. That is you can not sn a light signal byon th raius r ln. Sinc thr is no way to go byon that cylinr thn thr is no prmission for th light rays coming from istant galais to ntr insi th cylinr ithr. 38

49 CHAPTER 5 CONCLUSION W hav shown that by using th original Göl mtric in calculating th null gosics of Göl spactim Figur 4. can b obtain vry asily. This answrs th qustion that Ozsvath an Schucking hav pos in thir papr [7]. Morovr th problm of Figur 4. that is point out by Ozsvath an Schucking [7] an Malamnt [] is corrct with th hlp of timlik gosics quations. By invstigating th structur of light cons w saw how th clos timlik curvs ar crat in Göl spactim. Göl spactim is intrsting in two faturs: Firstly all th light rays an th fr particls follow th trajctoris which ar clos in spac but not in spactim of cours. This is call th boomrang ffct. As it is asily sn from Figur 4. for th cas whr if w stan at th origin an hol a flashlight pointing to th ast thn all th light rays follow a clos path an com back to th origin from th wst. Evrything woul b quit mssy if w wr to liv in a Göl spactim. Sconly th istnc of clos timlik curvs was first shown in Göl spactim an such curvs allow on to travl back in tim. So far w hav not rfrr to th notion of tim travl vn though th istnc of clos timlik curvs has bn plicitly shown in Göl spactim. Sinc ths clos timlik curvs ar not gosics th acclration is not zro on has to o an acclrat motion to follow ths curvs. Th nrgy rquir for a tim travlr to mov on a clos timlik curv was calculat by Malamnt []. Sinc this nrgy issu is byon th scop of this thsis w hav not stui numrical rsults of his calculations. It is just nough to say that a hug amount of nrgy that is impossibl to prouc with our prsnt tchnology is rquir for such an acclrat motion to travl back in tim. Howvr th consquncs of tim travl woul b important. Thr is no satisfactory answr to th qustion of what happns if on can travl backwars in tim an mt his/hr youngr slf. Th issu rmains obscur vn though thr ar lots of scnarios to liminat th problm that such a mting can caus. Thr woul crtainly b a parao if th prson kill 39

50 his/hr youngr slf. Som popl tn to lav th Göl solution asi u to such a possibility. W can not clu th Göl spactim immiatly just bcaus it allows for tim travl an th fact that th rsults of tim travl ar paraoical to our mins. Th scon rason for th tnncy of laving Göl spactim asi is that it is not paning whil our univrs is. This rsult alon maks it possibl to rul out th Göl spactim as a possibl mol for scribing our univrs. Howvr th issus that aris by th istnc of clos timlik curvs is still staning. 4

51 REFERENCES [] Malamnt D. 984 Tim travl in th Göl Spactim in Procings of th Binnial Mting of th Philosophy of Scinc Association Issu Volum Two: Symposia an Invit Paprs 9-. [] Göl K. 949 An Eampl of a Nw Typ of Cosmological Solutions of Einstin s Fil Equations of Gravitation Rviws of Morn Physics [3] Kunt W. 956 Träghitsbahnn in inm von Göl anggbnn kosmologischn Moll Zitschrift für Physik [4] Chanraskhar S. an Wright J. P. 96 Th Gosics in Göl s Univrs Procings of th National Acamy of Scincs [5] Stin H. 97 On th Paraoical Tim-Structurs of Göl Philosophy of Scinc [6] Hawking S. W. an Ellis G. F. R. 973 Th Larg Scal Structur of Spac-tim Cambrig: Cambrig Univrsity Prss. [7] Ozsvath I. an Schucking E. 3 Göl s Trip Amrican Journal of Physics [8] Raychauhuri A. K. an Thakurta S. N. G. 98 Homognous spactims of th Göl typ Physical Rviw D [9] Wal R. 984 Gnral Rlativity Chicago: Th Univrsity of Chicago Prss. 4

52 [] Lightman A. Prss W. H. Pric R. H. an Tukolsky S. A. 975 Problm Book in Rlativity an Gravitation Princton Nw Jrsy: Princton Univrsity Prss. [] Malamnt D. 985 Minimal Acclration Rquirmnts for Tim Travl in Göl Spactim Journal of Mathmatical Physics

53 APPENDIX A THE COMPONENTS OF THE EINSTEIN TENSOR For th sak of compltnss hr w list th nontrivial componnts of th Einstin tnsor of th Göl spactim corrsponing to th mtric.. G 3v u v u v u u 4vvu 4 v 4 v u 3 uv v G v 4 u v 3v u uv 3uv v 4 v u 3 v v 3 uv u vu G v 4 v u G v 4 uv u v u v 3 uv uv 3uv 4 v u u v 4 uv 3 u v v G 33 3uv u v u u 4vvu 4v v 4 v u 3 uv v v. 43

54 APPENDIX B TRANSFORMATION TO CYLINDRICAL COORDINATES In this appni w show th tails of th calculation that transforms th thr imnsional part of th Göl mtric.6 to its form 3. in cylinrical coorinats. For this purpos lt us start with.6 s t y ty..6 Lt us writ.6 as s t y y B. an thn apply th following transformations to B. Coshr Cos Sinhr B. y Sin Sinhr B.3 r Tan t t Tan t t. B.4 Lt us first fin nw coorinats such that r. Thn B. B.3 an B.4 can simply b writtn as Cos Sin B.5 y Sin Cos B.6 44

55 Tan t t Tan. B.7 Now lt us iffrntiat B.5: Cos Sin Sin Cos i.. Cos Sin Sin Cos. B.8 Manwhil th iffrntiation of B.6 givs:. Cos Sin Sin Cos y y B.9 If w us B.8 in B.6 w gt B. Now subtract B. from B.9 to obtain Sin Cos Sin Cos y. B. Taking th squar of B. givs Cos Sin Cos Sin Sin Cos y 45

56 . 4 4 Sin Cos Sin Cos Sin Cos Sin Cos y B. In th sam mannr taking th squar of B.8 givs Cos Sin Sin Cos Cos Sin Sin Cos r r 4 B.3 Th combination y in th mtric B. can asily b calculat as notic that th trms in B. an B.3 ar qual an opposit y. B.4 Now th iffrntiation of B.7 givs: Sc r Tan t t t t Tan B.5 an by using B.8 B.6 can b writtn as 46

57 Tan Sc Tan Tan t t. Nt lt us multiply an ivi th right han si of th abov quation with Cos : Sin Cos Sin Cos Cos Sin t t i.. t Cos Sin t. B.6 Now a B. an B.6 up Sin Cos t y t i.. Sin Cos t y t an w hav t y t / /. B.7 47

58 Taking th squar of B.7 givs B.8 Now lt us put B.4 an B.8 into B.. / / 4 / / t t s If w writ th abov quation in trms of r an t again w fin It is now straightforwar to obtain 3. 4 t r Sinh r Sinh r Sinh r t s. 3.. / / 4 / / t t y t. 8 4 t t r s r r r r r r 48

59 APPENDIX C PROOF OF 3.8 In this appni w show th proof of th statmnt that if an only if V [ V ;] =. For this purpos lt us first us 3. an thn 3. to obtain V ; P V ; V V i.. V ; P V ; V VV ;. C. Now substituting C. into 3.8 V ; V VV ; V ; V VV ; w can obtain V VV ; VV; VV; VV ; VV ; V V; +V [α;β] = C. whr w hav a an subtract som trms. C. can b writtn as V [α;β] V V V [α;μ] +V V [μ;β] + V V μ;α V μ;β V i.. 49

60 V [α;β] V V V [α;μ] V [μ;β] V V V V μ;α V V V μ;β. Notic that th trms in parnthss can b writtn as follows: V [α;β] V V V [ β;α] 3 V [V μ;β] V V V μ;α V V V μ;β or 3V V [V μ;β] V V V μ;α V V V μ;β. C.3 Rcall that V V i.. w gt thn C.3 bcoms V is timlik thn V V V V. If w tak th covariant rivativ of V V V V V V 3V V [V μ;β]. Thus if an only if V [ V ;] =. 5

61 D. How to Intgrat 4.7 APPENDIX D CALCULATIONS OF THE INTEGRALS Rcall Coshr Sinhr r a Cosh r Sinh r b a Sinh r /. 4.7 If w mak th substitution u Sinh r D. w gt / a u u b b u a a. Now lt us fin th iscriminant of th quaratic quation in th nominator b b b 4 4 a a a 4 b. a Hnc th roots of th nominator ar b u a b u. a 5

62 W now hav u / /. D. a u u u u Now w n anothr substitution u u u u Sin. D.3 Diffrntiation of D.3 givs u u u u Sin u / u u /. D.4 Thn by using D.3 an D.4 D. can b writtn as a. a Aftr using th invrss of th substitutions D.3 an D. rspctivly w gt th sir rsult Sinh r Sin a u. D. How to Intgrat 4.8 Rcall t { a Sin a Sin a u a u b}

63 4.8 can b writtn as a b t a. D.5 Sin a u Aftr th substitution q Tan a D.6 D.4 bcoms t a a b a q q q q u a b q t a. D.7 a u q u Now w n anothr substitution q u Tan D.8 u u q Tan u which taks D.7 to 53

64 a b t a a u u a b t t a. a u u Aftr using th invrss of th substitutions D.8 an D.6 rspctivly w gt a b u t t a ArcTan Tan a a u u u. D.3 How to Intgrat yils Coshr r /. a a Sinh r Cosh r Th substitution n Sinhr D.9 yils 54

65 n / a n a which can b writtn as n / / a a n a. Thn aftr th scon substitution a n Sin D. a w hav / a. a Now using th invrss of th substitutions D. an D.9 rspctivly w gt th sir rsult a Sinhr Sin a. a 55

First order differential equation Linear equation; Method of integrating factors

First order differential equation Linear equation; Method of integrating factors First orr iffrntial quation Linar quation; Mtho of intgrating factors Exampl 1: Rwrit th lft han si as th rivativ of th prouct of y an som function by prouct rul irctly. Solving th first orr iffrntial

More information

Mathematics 1110H Calculus I: Limits, derivatives, and Integrals Trent University, Summer 2018 Solutions to the Actual Final Examination

Mathematics 1110H Calculus I: Limits, derivatives, and Integrals Trent University, Summer 2018 Solutions to the Actual Final Examination Mathmatics H Calculus I: Limits, rivativs, an Intgrals Trnt Univrsity, Summr 8 Solutions to th Actual Final Eamination Tim-spac: 9:-: in FPHL 7. Brought to you by Stfan B lan k. Instructions: Do parts

More information

MSLC Math 151 WI09 Exam 2 Review Solutions

MSLC Math 151 WI09 Exam 2 Review Solutions Eam Rviw Solutions. Comput th following rivativs using th iffrntiation ruls: a.) cot cot cot csc cot cos 5 cos 5 cos 5 cos 5 sin 5 5 b.) c.) sin( ) sin( ) y sin( ) ln( y) ln( ) ln( y) sin( ) ln( ) y y

More information

Thomas Whitham Sixth Form

Thomas Whitham Sixth Form Thomas Whitham Sith Form Pur Mathmatics Unit C Algbra Trigonomtr Gomtr Calculus Vctor gomtr Pag Algbra Molus functions graphs, quations an inqualitis Graph of f () Draw f () an rflct an part of th curv

More information

Thomas Whitham Sixth Form

Thomas Whitham Sixth Form Thomas Whitham Sith Form Pur Mathmatics Cor rvision gui Pag Algbra Moulus functions graphs, quations an inqualitis Graph of f () Draw f () an rflct an part of th curv blow th ais in th ais. f () f () f

More information

SPH4U Electric Charges and Electric Fields Mr. LoRusso

SPH4U Electric Charges and Electric Fields Mr. LoRusso SPH4U lctric Chargs an lctric Fils Mr. LoRusso lctricity is th flow of lctric charg. Th Grks first obsrv lctrical forcs whn arly scintists rubb ambr with fur. Th notic thy coul attract small bits of straw

More information

u x v x dx u x v x v x u x dx d u x v x u x v x dx u x v x dx Integration by Parts Formula

u x v x dx u x v x v x u x dx d u x v x u x v x dx u x v x dx Integration by Parts Formula 7. Intgration by Parts Each drivativ formula givs ris to a corrsponding intgral formula, as w v sn many tims. Th drivativ product rul yilds a vry usful intgration tchniqu calld intgration by parts. Starting

More information

Indeterminate Forms and L Hôpital s Rule. Indeterminate Forms

Indeterminate Forms and L Hôpital s Rule. Indeterminate Forms SECTION 87 Intrminat Forms an L Hôpital s Rul 567 Sction 87 Intrminat Forms an L Hôpital s Rul Rcogniz its that prouc intrminat forms Apply L Hôpital s Rul to valuat a it Intrminat Forms Rcall from Chaptrs

More information

A RELATIVISTIC LAGRANGIAN FOR MULTIPLE CHARGED POINT-MASSES

A RELATIVISTIC LAGRANGIAN FOR MULTIPLE CHARGED POINT-MASSES A RELATIVISTIC LAGRANGIAN FOR MULTIPLE CHARGED POINT-MASSES ADRIAAN DANIËL FOKKER (1887-197) A translation of: Ein invariantr Variationssatz für i Bwgung mhrrr lctrischr Massntilshn Z. Phys. 58, 386-393

More information

Einstein Equations for Tetrad Fields

Einstein Equations for Tetrad Fields Apiron, Vol 13, No, Octobr 006 6 Einstin Equations for Ttrad Filds Ali Rıza ŞAHİN, R T L Istanbul (Turky) Evry mtric tnsor can b xprssd by th innr product of ttrad filds W prov that Einstin quations for

More information

Y 0. Standing Wave Interference between the incident & reflected waves Standing wave. A string with one end fixed on a wall

Y 0. Standing Wave Interference between the incident & reflected waves Standing wave. A string with one end fixed on a wall Staning Wav Intrfrnc btwn th incint & rflct wavs Staning wav A string with on n fix on a wall Incint: y, t) Y cos( t ) 1( Y 1 ( ) Y (St th incint wav s phas to b, i.., Y + ral & positiv.) Rflct: y, t)

More information

Notes on Differential Geometry

Notes on Differential Geometry Nots from phz 6607, Spcial an Gnral Rlativity Univrsity of Floria, Fall 2004, Dtwilr Nots on Diffrntial Gomtry Ths nots ar not a substitut in any mannr for class lcturs. Plas lt m know if you fin rrors.

More information

PHYS ,Fall 05, Term Exam #1, Oct., 12, 2005

PHYS ,Fall 05, Term Exam #1, Oct., 12, 2005 PHYS1444-,Fall 5, Trm Exam #1, Oct., 1, 5 Nam: Kys 1. circular ring of charg of raius an a total charg Q lis in th x-y plan with its cntr at th origin. small positiv tst charg q is plac at th origin. What

More information

Higher order derivatives

Higher order derivatives Robrto s Nots on Diffrntial Calculus Chaptr 4: Basic diffrntiation ruls Sction 7 Highr ordr drivativs What you nd to know alrady: Basic diffrntiation ruls. What you can larn hr: How to rpat th procss of

More information

PROBLEM SET Problem 1.

PROBLEM SET Problem 1. PROLEM SET 1 PROFESSOR PETER JOHNSTONE 1. Problm 1. 1.1. Th catgory Mat L. OK, I m not amiliar with th trminology o partially orr sts, so lt s go ovr that irst. Dinition 1.1. partial orr is a binary rlation

More information

a 1and x is any real number.

a 1and x is any real number. Calcls Nots Eponnts an Logarithms Eponntial Fnction: Has th form y a, whr a 0, a an is any ral nmbr. Graph y, Graph y ln y y Th Natral Bas (Elr s nmbr): An irrational nmbr, symboliz by th lttr, appars

More information

Addition of angular momentum

Addition of angular momentum Addition of angular momntum April, 0 Oftn w nd to combin diffrnt sourcs of angular momntum to charactriz th total angular momntum of a systm, or to divid th total angular momntum into parts to valuat th

More information

The second condition says that a node α of the tree has exactly n children if the arity of its label is n.

The second condition says that a node α of the tree has exactly n children if the arity of its label is n. CS 6110 S14 Hanout 2 Proof of Conflunc 27 January 2014 In this supplmntary lctur w prov that th λ-calculus is conflunt. This is rsult is u to lonzo Church (1903 1995) an J. arkly Rossr (1907 1989) an is

More information

Differentiation of Exponential Functions

Differentiation of Exponential Functions Calculus Modul C Diffrntiation of Eponntial Functions Copyright This publication Th Northrn Albrta Institut of Tchnology 007. All Rights Rsrvd. LAST REVISED March, 009 Introduction to Diffrntiation of

More information

SIGNIFICANCE OF SMITH CHART IN ANTENNA TECHNOLOGY

SIGNIFICANCE OF SMITH CHART IN ANTENNA TECHNOLOGY SIGNIFICANCE OF SMITH CHART IN ANTENNA TECHNOLOGY P. Poornima¹, Santosh Kumar Jha² 1 Associat Profssor, 2 Profssor, ECE Dpt., Sphoorthy Enginring Collg Tlangana, Hyraba (Inia) ABSTRACT This papr prsnts

More information

Additional Math (4047) Paper 2 (100 marks) y x. 2 d. d d

Additional Math (4047) Paper 2 (100 marks) y x. 2 d. d d Aitional Math (07) Prpar b Mr Ang, Nov 07 Fin th valu of th constant k for which is a solution of th quation k. [7] Givn that, Givn that k, Thrfor, k Topic : Papr (00 marks) Tim : hours 0 mins Nam : Aitional

More information

Multiple Short Term Infusion Homework # 5 PHA 5127

Multiple Short Term Infusion Homework # 5 PHA 5127 Multipl Short rm Infusion Homwork # 5 PHA 527 A rug is aministr as a short trm infusion. h avrag pharmacokintic paramtrs for this rug ar: k 0.40 hr - V 28 L his rug follows a on-compartmnt boy mol. A 300

More information

Sundials and Linear Algebra

Sundials and Linear Algebra Sundials and Linar Algbra M. Scot Swan July 2, 25 Most txts on crating sundials ar dirctd towards thos who ar solly intrstd in making and using sundials and usually assums minimal mathmatical background.

More information

MA1506 Tutorial 2 Solutions. Question 1. (1a) 1 ) y x. e x. 1 exp (in general, Integrating factor is. ye dx. So ) (1b) e e. e c.

MA1506 Tutorial 2 Solutions. Question 1. (1a) 1 ) y x. e x. 1 exp (in general, Integrating factor is. ye dx. So ) (1b) e e. e c. MA56 utorial Solutions Qustion a Intgrating fator is ln p p in gnral, multipl b p So b ln p p sin his kin is all a Brnoulli quation -- st Sin w fin Y, Y Y, Y Y p Qustion Dfin v / hn our quation is v μ

More information

Math 34A. Final Review

Math 34A. Final Review Math A Final Rviw 1) Us th graph of y10 to find approimat valus: a) 50 0. b) y (0.65) solution for part a) first writ an quation: 50 0. now tak th logarithm of both sids: log() log(50 0. ) pand th right

More information

Addition of angular momentum

Addition of angular momentum Addition of angular momntum April, 07 Oftn w nd to combin diffrnt sourcs of angular momntum to charactriz th total angular momntum of a systm, or to divid th total angular momntum into parts to valuat

More information

Section 11.6: Directional Derivatives and the Gradient Vector

Section 11.6: Directional Derivatives and the Gradient Vector Sction.6: Dirctional Drivativs and th Gradint Vctor Practic HW rom Stwart Ttbook not to hand in p. 778 # -4 p. 799 # 4-5 7 9 9 35 37 odd Th Dirctional Drivativ Rcall that a b Slop o th tangnt lin to th

More information

The van der Waals interaction 1 D. E. Soper 2 University of Oregon 20 April 2012

The van der Waals interaction 1 D. E. Soper 2 University of Oregon 20 April 2012 Th van dr Waals intraction D. E. Sopr 2 Univrsity of Orgon 20 pril 202 Th van dr Waals intraction is discussd in Chaptr 5 of J. J. Sakurai, Modrn Quantum Mchanics. Hr I tak a look at it in a littl mor

More information

Schematic of a mixed flow reactor (both advection and dispersion must be accounted for)

Schematic of a mixed flow reactor (both advection and dispersion must be accounted for) Cas stuy 6.1, R: Chapra an Canal, p. 769. Th quation scribin th concntration o any tracr in an lonat ractor is known as th avction-isprsion quation an may b writtn as: Schmatic o a mi low ractor (both

More information

First derivative analysis

First derivative analysis Robrto s Nots on Dirntial Calculus Chaptr 8: Graphical analysis Sction First drivativ analysis What you nd to know alrady: How to us drivativs to idntiy th critical valus o a unction and its trm points

More information

Brief Introduction to Statistical Mechanics

Brief Introduction to Statistical Mechanics Brif Introduction to Statistical Mchanics. Purpos: Ths nots ar intndd to provid a vry quick introduction to Statistical Mchanics. Th fild is of cours far mor vast than could b containd in ths fw pags.

More information

Calculus concepts derivatives

Calculus concepts derivatives All rasonabl fforts hav bn mad to mak sur th nots ar accurat. Th author cannot b hld rsponsibl for any damags arising from th us of ths nots in any fashion. Calculus concpts drivativs Concpts involving

More information

That is, we start with a general matrix: And end with a simpler matrix:

That is, we start with a general matrix: And end with a simpler matrix: DIAGON ALIZATION OF THE STR ESS TEN SOR INTRO DUCTIO N By th us of Cauchy s thorm w ar abl to rduc th numbr of strss componnts in th strss tnsor to only nin valus. An additional simplification of th strss

More information

1973 AP Calculus AB: Section I

1973 AP Calculus AB: Section I 97 AP Calculus AB: Sction I 9 Minuts No Calculator Not: In this amination, ln dnots th natural logarithm of (that is, logarithm to th bas ).. ( ) d= + C 6 + C + C + C + C. If f ( ) = + + + and ( ), g=

More information

Lecture 37 (Schrödinger Equation) Physics Spring 2018 Douglas Fields

Lecture 37 (Schrödinger Equation) Physics Spring 2018 Douglas Fields Lctur 37 (Schrödingr Equation) Physics 6-01 Spring 018 Douglas Filds Rducd Mass OK, so th Bohr modl of th atom givs nrgy lvls: E n 1 k m n 4 But, this has on problm it was dvlopd assuming th acclration

More information

Problem Set 6 Solutions

Problem Set 6 Solutions 6.04/18.06J Mathmatics for Computr Scinc March 15, 005 Srini Dvadas and Eric Lhman Problm St 6 Solutions Du: Monday, March 8 at 9 PM in Room 3-044 Problm 1. Sammy th Shark is a financial srvic providr

More information

u r du = ur+1 r + 1 du = ln u + C u sin u du = cos u + C cos u du = sin u + C sec u tan u du = sec u + C e u du = e u + C

u r du = ur+1 r + 1 du = ln u + C u sin u du = cos u + C cos u du = sin u + C sec u tan u du = sec u + C e u du = e u + C Tchniqus of Intgration c Donald Kridr and Dwight Lahr In this sction w ar going to introduc th first approachs to valuating an indfinit intgral whos intgrand dos not hav an immdiat antidrivativ. W bgin

More information

SECTION where P (cos θ, sin θ) and Q(cos θ, sin θ) are polynomials in cos θ and sin θ, provided Q is never equal to zero.

SECTION where P (cos θ, sin θ) and Q(cos θ, sin θ) are polynomials in cos θ and sin θ, provided Q is never equal to zero. SETION 6. 57 6. Evaluation of Dfinit Intgrals Exampl 6.6 W hav usd dfinit intgrals to valuat contour intgrals. It may com as a surpris to larn that contour intgrals and rsidus can b usd to valuat crtain

More information

A Propagating Wave Packet Group Velocity Dispersion

A Propagating Wave Packet Group Velocity Dispersion Lctur 8 Phys 375 A Propagating Wav Packt Group Vlocity Disprsion Ovrviw and Motivation: In th last lctur w lookd at a localizd solution t) to th 1D fr-particl Schrödingr quation (SE) that corrsponds to

More information

2008 AP Calculus BC Multiple Choice Exam

2008 AP Calculus BC Multiple Choice Exam 008 AP Multipl Choic Eam Nam 008 AP Calculus BC Multipl Choic Eam Sction No Calculator Activ AP Calculus 008 BC Multipl Choic. At tim t 0, a particl moving in th -plan is th acclration vctor of th particl

More information

Finite Element Analysis

Finite Element Analysis Finit Elmnt Analysis L4 D Shap Functions, an Gauss Quaratur FEA Formulation Dr. Wiong Wu EGR 54 Finit Elmnt Analysis Roamap for Dvlopmnt of FE Strong form: govrning DE an BCs EGR 54 Finit Elmnt Analysis

More information

Partial Derivatives: Suppose that z = f(x, y) is a function of two variables.

Partial Derivatives: Suppose that z = f(x, y) is a function of two variables. Chaptr Functions o Two Variabls Applid Calculus 61 Sction : Calculus o Functions o Two Variabls Now that ou hav som amiliarit with unctions o two variabls it s tim to start appling calculus to hlp us solv

More information

Grade 12 (MCV4UE) AP Calculus Page 1 of 5 Derivative of a Function & Differentiability

Grade 12 (MCV4UE) AP Calculus Page 1 of 5 Derivative of a Function & Differentiability Gra (MCV4UE) AP Calculus Pag of 5 Drivativ of a Function & Diffrntiabilit Th Drivativ at a Point f ( a h) f ( a) Rcall, lim provis th slop of h0 h th tangnt to th graph f ( at th point a, f ( a), an th

More information

The Matrix Exponential

The Matrix Exponential Th Matrix Exponntial (with xrciss) by D. Klain Vrsion 207.0.05 Corrctions and commnts ar wlcom. Th Matrix Exponntial For ach n n complx matrix A, dfin th xponntial of A to b th matrix A A k I + A + k!

More information

Differential Equations

Differential Equations Prfac Hr ar m onlin nots for m diffrntial quations cours that I tach hr at Lamar Univrsit. Dspit th fact that ths ar m class nots, th should b accssibl to anon wanting to larn how to solv diffrntial quations

More information

INTEGRATION BY PARTS

INTEGRATION BY PARTS Mathmatics Rvision Guids Intgration by Parts Pag of 7 MK HOME TUITION Mathmatics Rvision Guids Lvl: AS / A Lvl AQA : C Edcl: C OCR: C OCR MEI: C INTEGRATION BY PARTS Vrsion : Dat: --5 Eampls - 6 ar copyrightd

More information

The Matrix Exponential

The Matrix Exponential Th Matrix Exponntial (with xrciss) by Dan Klain Vrsion 28928 Corrctions and commnts ar wlcom Th Matrix Exponntial For ach n n complx matrix A, dfin th xponntial of A to b th matrix () A A k I + A + k!

More information

Mor Tutorial at www.dumblittldoctor.com Work th problms without a calculator, but us a calculator to chck rsults. And try diffrntiating your answrs in part III as a usful chck. I. Applications of Intgration

More information

cycle that does not cross any edges (including its own), then it has at least

cycle that does not cross any edges (including its own), then it has at least W prov th following thorm: Thorm If a K n is drawn in th plan in such a way that it has a hamiltonian cycl that dos not cross any dgs (including its own, thn it has at last n ( 4 48 π + O(n crossings Th

More information

Solution: APPM 1360 Final (150 pts) Spring (60 pts total) The following parts are not related, justify your answers:

Solution: APPM 1360 Final (150 pts) Spring (60 pts total) The following parts are not related, justify your answers: APPM 6 Final 5 pts) Spring 4. 6 pts total) Th following parts ar not rlatd, justify your answrs: a) Considr th curv rprsntd by th paramtric quations, t and y t + for t. i) 6 pts) Writ down th corrsponding

More information

Case Study Vancomycin Answers Provided by Jeffrey Stark, Graduate Student

Case Study Vancomycin Answers Provided by Jeffrey Stark, Graduate Student Cas Stuy Vancomycin Answrs Provi by Jffry Stark, Grauat Stunt h antibiotic Vancomycin is liminat almost ntirly by glomrular filtration. For a patint with normal rnal function, th half-lif is about 6 hours.

More information

Ch. 24 Molecular Reaction Dynamics 1. Collision Theory

Ch. 24 Molecular Reaction Dynamics 1. Collision Theory Ch. 4 Molcular Raction Dynamics 1. Collision Thory Lctur 16. Diffusion-Controlld Raction 3. Th Matrial Balanc Equation 4. Transition Stat Thory: Th Eyring Equation 5. Transition Stat Thory: Thrmodynamic

More information

4037 ADDITIONAL MATHEMATICS

4037 ADDITIONAL MATHEMATICS CAMBRIDGE INTERNATIONAL EXAMINATIONS GCE Ordinary Lvl MARK SCHEME for th Octobr/Novmbr 0 sris 40 ADDITIONAL MATHEMATICS 40/ Papr, maimum raw mark 80 This mark schm is publishd as an aid to tachrs and candidats,

More information

Fourier Transforms and the Wave Equation. Key Mathematics: More Fourier transform theory, especially as applied to solving the wave equation.

Fourier Transforms and the Wave Equation. Key Mathematics: More Fourier transform theory, especially as applied to solving the wave equation. Lur 7 Fourir Transforms and th Wav Euation Ovrviw and Motivation: W first discuss a fw faturs of th Fourir transform (FT), and thn w solv th initial-valu problm for th wav uation using th Fourir transform

More information

3 Finite Element Parametric Geometry

3 Finite Element Parametric Geometry 3 Finit Elmnt Paramtric Gomtry 3. Introduction Th intgral of a matrix is th matrix containing th intgral of ach and vry on of its original componnts. Practical finit lmnt analysis rquirs intgrating matrics,

More information

22/ Breakdown of the Born-Oppenheimer approximation. Selection rules for rotational-vibrational transitions. P, R branches.

22/ Breakdown of the Born-Oppenheimer approximation. Selection rules for rotational-vibrational transitions. P, R branches. Subjct Chmistry Papr No and Titl Modul No and Titl Modul Tag 8/ Physical Spctroscopy / Brakdown of th Born-Oppnhimr approximation. Slction ruls for rotational-vibrational transitions. P, R branchs. CHE_P8_M

More information

ph People Grade Level: basic Duration: minutes Setting: classroom or field site

ph People Grade Level: basic Duration: minutes Setting: classroom or field site ph Popl Adaptd from: Whr Ar th Frogs? in Projct WET: Curriculum & Activity Guid. Bozman: Th Watrcours and th Council for Environmntal Education, 1995. ph Grad Lvl: basic Duration: 10 15 minuts Stting:

More information

Einstein Rosen inflationary Universe in general relativity

Einstein Rosen inflationary Universe in general relativity PRAMANA c Indian Acadmy of Scincs Vol. 74, No. 4 journal of April 2010 physics pp. 669 673 Einstin Rosn inflationary Univrs in gnral rlativity S D KATORE 1, R S RANE 2, K S WANKHADE 2, and N K SARKATE

More information

COMPUTER GENERATED HOLOGRAMS Optical Sciences 627 W.J. Dallas (Monday, April 04, 2005, 8:35 AM) PART I: CHAPTER TWO COMB MATH.

COMPUTER GENERATED HOLOGRAMS Optical Sciences 627 W.J. Dallas (Monday, April 04, 2005, 8:35 AM) PART I: CHAPTER TWO COMB MATH. C:\Dallas\0_Courss\03A_OpSci_67\0 Cgh_Book\0_athmaticalPrliminaris\0_0 Combath.doc of 8 COPUTER GENERATED HOLOGRAS Optical Scincs 67 W.J. Dallas (onday, April 04, 005, 8:35 A) PART I: CHAPTER TWO COB ATH

More information

Case Study 4 PHA 5127 Aminoglycosides Answers provided by Jeffrey Stark Graduate Student

Case Study 4 PHA 5127 Aminoglycosides Answers provided by Jeffrey Stark Graduate Student Cas Stuy 4 PHA 527 Aminoglycosis Answrs provi by Jffry Stark Grauat Stunt Backgroun Gntamicin is us to trat a wi varity of infctions. Howvr, u to its toxicity, its us must b rstrict to th thrapy of lif-thratning

More information

CHAPTER 1. Introductory Concepts Elements of Vector Analysis Newton s Laws Units The basis of Newtonian Mechanics D Alembert s Principle

CHAPTER 1. Introductory Concepts Elements of Vector Analysis Newton s Laws Units The basis of Newtonian Mechanics D Alembert s Principle CHPTER 1 Introductory Concpts Elmnts of Vctor nalysis Nwton s Laws Units Th basis of Nwtonian Mchanics D lmbrt s Principl 1 Scinc of Mchanics: It is concrnd with th motion of matrial bodis. odis hav diffrnt

More information

Content Skills Assessments Lessons. Identify, classify, and apply properties of negative and positive angles.

Content Skills Assessments Lessons. Identify, classify, and apply properties of negative and positive angles. Tachr: CORE TRIGONOMETRY Yar: 2012-13 Cours: TRIGONOMETRY Month: All Months S p t m b r Angls Essntial Qustions Can I idntify draw ngativ positiv angls in stard position? Do I hav a working knowldg of

More information

Division of Mechanics Lund University MULTIBODY DYNAMICS. Examination Name (write in block letters):.

Division of Mechanics Lund University MULTIBODY DYNAMICS. Examination Name (write in block letters):. Division of Mchanics Lund Univrsity MULTIBODY DYNMICS Examination 7033 Nam (writ in block lttrs):. Id.-numbr: Writtn xamination with fiv tasks. Plas chck that all tasks ar includd. clan copy of th solutions

More information

are given in the table below. t (hours)

are given in the table below. t (hours) CALCULUS WORKSHEET ON INTEGRATION WITH DATA Work th following on notbook papr. Giv dcimal answrs corrct to thr dcimal placs.. A tank contains gallons of oil at tim t = hours. Oil is bing pumpd into th

More information

The graph of y = x (or y = ) consists of two branches, As x 0, y + ; as x 0, y +. x = 0 is the

The graph of y = x (or y = ) consists of two branches, As x 0, y + ; as x 0, y +. x = 0 is the Copyright itutcom 005 Fr download & print from wwwitutcom Do not rproduc by othr mans Functions and graphs Powr functions Th graph of n y, for n Q (st of rational numbrs) y is a straight lin through th

More information

Note If the candidate believes that e x = 0 solves to x = 0 or gives an extra solution of x = 0, then withhold the final accuracy mark.

Note If the candidate believes that e x = 0 solves to x = 0 or gives an extra solution of x = 0, then withhold the final accuracy mark. . (a) Eithr y = or ( 0, ) (b) Whn =, y = ( 0 + ) = 0 = 0 ( + ) = 0 ( )( ) = 0 Eithr = (for possibly abov) or = A 3. Not If th candidat blivs that = 0 solvs to = 0 or givs an tra solution of = 0, thn withhold

More information

Electromagnetic scattering. Graduate Course Electrical Engineering (Communications) 1 st Semester, Sharif University of Technology

Electromagnetic scattering. Graduate Course Electrical Engineering (Communications) 1 st Semester, Sharif University of Technology Elctromagntic scattring Graduat Cours Elctrical Enginring (Communications) 1 st Smstr, 1388-1389 Sharif Univrsity of Tchnology Contnts of lctur 8 Contnts of lctur 8: Scattring from small dilctric objcts

More information

1997 AP Calculus AB: Section I, Part A

1997 AP Calculus AB: Section I, Part A 997 AP Calculus AB: Sction I, Part A 50 Minuts No Calculator Not: Unlss othrwis spcifid, th domain of a function f is assumd to b th st of all ral numbrs for which f () is a ral numbr.. (4 6 ) d= 4 6 6

More information

COHORT MBA. Exponential function. MATH review (part2) by Lucian Mitroiu. The LOG and EXP functions. Properties: e e. lim.

COHORT MBA. Exponential function. MATH review (part2) by Lucian Mitroiu. The LOG and EXP functions. Properties: e e. lim. MTH rviw part b Lucian Mitroiu Th LOG and EXP functions Th ponntial function p : R, dfind as Proprtis: lim > lim p Eponntial function Y 8 6 - -8-6 - - X Th natural logarithm function ln in US- log: function

More information

DIFFERENTIAL EQUATION

DIFFERENTIAL EQUATION MD DIFFERENTIAL EQUATION Sllabus : Ordinar diffrntial quations, thir ordr and dgr. Formation of diffrntial quations. Solution of diffrntial quations b th mthod of sparation of variabls, solution of homognous

More information

MATH 1080 Test 2-SOLUTIONS Spring

MATH 1080 Test 2-SOLUTIONS Spring MATH Tst -SOLUTIONS Spring 5. Considr th curv dfind by x = ln( 3y + 7) on th intrval y. a. (5 points) St up but do not simplify or valuat an intgral rprsnting th lngth of th curv on th givn intrval. =

More information

NEW APPLICATIONS OF THE ABEL-LIOUVILLE FORMULA

NEW APPLICATIONS OF THE ABEL-LIOUVILLE FORMULA NE APPLICATIONS OF THE ABEL-LIOUVILLE FORMULA Mirca I CÎRNU Ph Dp o Mathmatics III Faculty o Applid Scincs Univrsity Polithnica o Bucharst Cirnumirca @yahoocom Abstract In a rcnt papr [] 5 th indinit intgrals

More information

Quasi-Classical States of the Simple Harmonic Oscillator

Quasi-Classical States of the Simple Harmonic Oscillator Quasi-Classical Stats of th Simpl Harmonic Oscillator (Draft Vrsion) Introduction: Why Look for Eignstats of th Annihilation Oprator? Excpt for th ground stat, th corrspondnc btwn th quantum nrgy ignstats

More information

Derivation of Electron-Electron Interaction Terms in the Multi-Electron Hamiltonian

Derivation of Electron-Electron Interaction Terms in the Multi-Electron Hamiltonian Drivation of Elctron-Elctron Intraction Trms in th Multi-Elctron Hamiltonian Erica Smith Octobr 1, 010 1 Introduction Th Hamiltonian for a multi-lctron atom with n lctrons is drivd by Itoh (1965) by accounting

More information

PROOF OF FIRST STANDARD FORM OF NONELEMENTARY FUNCTIONS

PROOF OF FIRST STANDARD FORM OF NONELEMENTARY FUNCTIONS Intrnational Journal Of Advanc Rsarch In Scinc And Enginring http://www.ijars.com IJARSE, Vol. No., Issu No., Fbruary, 013 ISSN-319-8354(E) PROOF OF FIRST STANDARD FORM OF NONELEMENTARY FUNCTIONS 1 Dharmndra

More information

Coupled Pendulums. Two normal modes.

Coupled Pendulums. Two normal modes. Tim Dpndnt Two Stat Problm Coupld Pndulums Wak spring Two normal mods. No friction. No air rsistanc. Prfct Spring Start Swinging Som tim latr - swings with full amplitud. stationary M +n L M +m Elctron

More information

Deift/Zhou Steepest descent, Part I

Deift/Zhou Steepest descent, Part I Lctur 9 Dift/Zhou Stpst dscnt, Part I W now focus on th cas of orthogonal polynomials for th wight w(x) = NV (x), V (x) = t x2 2 + x4 4. Sinc th wight dpnds on th paramtr N N w will writ π n,n, a n,n,

More information

(Upside-Down o Direct Rotation) β - Numbers

(Upside-Down o Direct Rotation) β - Numbers Amrican Journal of Mathmatics and Statistics 014, 4(): 58-64 DOI: 10593/jajms0140400 (Upsid-Down o Dirct Rotation) β - Numbrs Ammar Sddiq Mahmood 1, Shukriyah Sabir Ali,* 1 Dpartmnt of Mathmatics, Collg

More information

von Neumann-Wigner theorem: level s repulsion and degenerate eigenvalues.

von Neumann-Wigner theorem: level s repulsion and degenerate eigenvalues. von Numann-Wignr thorm: lvl s rpulsion an gnrat ignvalus. Yu.N.Dmkov an P.Kurasov Abstract. Spctral proprtis of Schröingr oprators with point intractions ar invstigat. Attntion is focus on th intrplay

More information

COUNTING TAMELY RAMIFIED EXTENSIONS OF LOCAL FIELDS UP TO ISOMORPHISM

COUNTING TAMELY RAMIFIED EXTENSIONS OF LOCAL FIELDS UP TO ISOMORPHISM COUNTING TAMELY RAMIFIED EXTENSIONS OF LOCAL FIELDS UP TO ISOMORPHISM Jim Brown Dpartmnt of Mathmatical Scincs, Clmson Univrsity, Clmson, SC 9634, USA jimlb@g.clmson.du Robrt Cass Dpartmnt of Mathmatics,

More information

Chapter 1. Chapter 10. Chapter 2. Chapter 11. Chapter 3. Chapter 12. Chapter 4. Chapter 13. Chapter 5. Chapter 14. Chapter 6. Chapter 7.

Chapter 1. Chapter 10. Chapter 2. Chapter 11. Chapter 3. Chapter 12. Chapter 4. Chapter 13. Chapter 5. Chapter 14. Chapter 6. Chapter 7. Chaptr Binomial Epansion Chaptr 0 Furthr Probability Chaptr Limits and Drivativs Chaptr Discrt Random Variabls Chaptr Diffrntiation Chaptr Discrt Probability Distributions Chaptr Applications of Diffrntiation

More information

6.1 Integration by Parts and Present Value. Copyright Cengage Learning. All rights reserved.

6.1 Integration by Parts and Present Value. Copyright Cengage Learning. All rights reserved. 6.1 Intgration by Parts and Prsnt Valu Copyright Cngag Larning. All rights rsrvd. Warm-Up: Find f () 1. F() = ln(+1). F() = 3 3. F() =. F() = ln ( 1) 5. F() = 6. F() = - Objctivs, Day #1 Studnts will b

More information

Things I Should Know Before I Get to Calculus Class

Things I Should Know Before I Get to Calculus Class Things I Should Know Bfor I Gt to Calculus Class Quadratic Formula = b± b 4ac a sin + cos = + tan = sc + cot = csc sin( ± y ) = sin cos y ± cos sin y cos( + y ) = cos cos y sin sin y cos( y ) = cos cos

More information

PHYS-333: Problem set #2 Solutions

PHYS-333: Problem set #2 Solutions PHYS-333: Problm st #2 Solutions Vrsion of March 5, 2016. 1. Visual binary 15 points): Ovr a priod of 10 yars, two stars sparatd by an angl of 1 arcsc ar obsrvd to mov through a full circl about a point

More information

The Transfer Function. The Transfer Function. The Transfer Function. The Transfer Function. The Transfer Function. The Transfer Function

The Transfer Function. The Transfer Function. The Transfer Function. The Transfer Function. The Transfer Function. The Transfer Function A gnraliation of th frquncy rsons function Th convolution sum scrition of an LTI iscrt-tim systm with an imuls rsons h[n] is givn by h y [ n] [ ] x[ n ] Taing th -transforms of both sis w gt n n h n n

More information

TEMASEK JUNIOR COLLEGE, SINGAPORE. JC 2 Preliminary Examination 2017

TEMASEK JUNIOR COLLEGE, SINGAPORE. JC 2 Preliminary Examination 2017 TEMASEK JUNIOR COLLEGE, SINGAPORE JC Prliminary Eamination 7 MATHEMATICS 886/ Highr 9 August 7 Additional Matrials: Answr papr hours List of Formula (MF6) READ THESE INSTRUCTIONS FIRST Writ your Civics

More information

3 2x. 3x 2. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

3 2x. 3x 2.   Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB Math B Intgration Rviw (Solutions) Do ths intgrals. Solutions ar postd at th wbsit blow. If you hav troubl with thm, sk hlp immdiatly! () 8 d () 5 d () d () sin d (5) d (6) cos d (7) d www.clas.ucsb.du/staff/vinc

More information

1 General boundary conditions in diffusion

1 General boundary conditions in diffusion Gnral boundary conditions in diffusion Πρόβλημα 4.8 : Δίνεται μονοδιάτατη πλάκα πάχους, που το ένα άκρο της κρατιέται ε θερμοκραία T t και το άλλο ε θερμοκραία T 2 t. Αν η αρχική θερμοκραία της πλάκας

More information

Introduction to Condensed Matter Physics

Introduction to Condensed Matter Physics Introduction to Condnsd Mattr Physics pcific hat M.P. Vaughan Ovrviw Ovrviw of spcific hat Hat capacity Dulong-Ptit Law Einstin modl Dby modl h Hat Capacity Hat capacity h hat capacity of a systm hld at

More information

General Notes About 2007 AP Physics Scoring Guidelines

General Notes About 2007 AP Physics Scoring Guidelines AP PHYSICS C: ELECTRICITY AND MAGNETISM 2007 SCORING GUIDELINES Gnral Nots About 2007 AP Physics Scoring Guidlins 1. Th solutions contain th most common mthod of solving th fr-rspons qustions and th allocation

More information

Homogeneous Constant Matrix Systems, Part I

Homogeneous Constant Matrix Systems, Part I 39 Homognous Constant Matrix Systms, Part I Finally, w can start discussing mthods for solving a vry important class of diffrntial quation systms of diffrntial quations: homognous constant matrix systms

More information

Exercise 1. Sketch the graph of the following function. (x 2

Exercise 1. Sketch the graph of the following function. (x 2 Writtn tst: Fbruary 9th, 06 Exrcis. Sktch th graph of th following function fx = x + x, spcifying: domain, possibl asymptots, monotonicity, continuity, local and global maxima or minima, and non-drivability

More information

Differential Equations

Differential Equations UNIT I Diffrntial Equations.0 INTRODUCTION W li in a world of intrrlatd changing ntitis. Th locit of a falling bod changs with distanc, th position of th arth changs with tim, th ara of a circl changs

More information

San José State University Aerospace Engineering AE 138 Vector-Based Dynamics for Aerospace Applications, Fall 2016

San José State University Aerospace Engineering AE 138 Vector-Based Dynamics for Aerospace Applications, Fall 2016 San José Stat Univrsity Arospac Enginring AE 138 Vctor-Basd Dynamics for Arospac Applications, Fall 2016 Instructor: Offic Location: Email: Offic Hours: Class Days/Tim: Classroom: Prof. J.M. Huntr E272F

More information

Recall that by Theorems 10.3 and 10.4 together provide us the estimate o(n2 ), S(q) q 9, q=1

Recall that by Theorems 10.3 and 10.4 together provide us the estimate o(n2 ), S(q) q 9, q=1 Chaptr 11 Th singular sris Rcall that by Thorms 10 and 104 togthr provid us th stimat 9 4 n 2 111 Rn = SnΓ 2 + on2, whr th singular sris Sn was dfind in Chaptr 10 as Sn = q=1 Sq q 9, with Sq = 1 a q gcda,q=1

More information

LINEAR DELAY DIFFERENTIAL EQUATION WITH A POSITIVE AND A NEGATIVE TERM

LINEAR DELAY DIFFERENTIAL EQUATION WITH A POSITIVE AND A NEGATIVE TERM Elctronic Journal of Diffrntial Equations, Vol. 2003(2003), No. 92, pp. 1 6. ISSN: 1072-6691. URL: http://jd.math.swt.du or http://jd.math.unt.du ftp jd.math.swt.du (login: ftp) LINEAR DELAY DIFFERENTIAL

More information

ECE602 Exam 1 April 5, You must show ALL of your work for full credit.

ECE602 Exam 1 April 5, You must show ALL of your work for full credit. ECE62 Exam April 5, 27 Nam: Solution Scor: / This xam is closd-book. You must show ALL of your work for full crdit. Plas rad th qustions carfully. Plas chck your answrs carfully. Calculators may NOT b

More information

10. The Discrete-Time Fourier Transform (DTFT)

10. The Discrete-Time Fourier Transform (DTFT) Th Discrt-Tim Fourir Transform (DTFT Dfinition of th discrt-tim Fourir transform Th Fourir rprsntation of signals plays an important rol in both continuous and discrt signal procssing In this sction w

More information