A H$ / Marks. g 3 K Q>o Time 3 Hours. àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. narjm{w m Ho$ {be {ZX}e /INSTRUCTIONS TO CANDIDATE

Size: px
Start display at page:

Download "A H$ / Marks. g 3 K Q>o Time 3 Hours. àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. narjm{w m Ho$ {be {ZX}e /INSTRUCTIONS TO CANDIDATE"

Transcription

1 PAPER- PCB AZwH«$ m H$ / Roll No. CÎma-erQ> H«$ m H$ / MR Answer Sheet No. Kmofm : / Declaration : Zo n îr> g» m 1 na {X o J o {ZX}em H$mo n T>H$a g P {b m h & I have read and understood the instructions given on page No. 1 narjmwu H$m hñvmja /Signature of Candidate (AmdoXZ nì Ho$ AwZgma /as signed in application) narjmwu H$m Zm / Name of Candidate : àíznwpñvh$m H«$ m H$ Question Booklet Sr. No. narjm Ho$ÝÐmÜ j H$s moha Seal of Superintendent of Examination Centre H$j {ZarjH$ Ho$ hñvmja /Signature of the Invigilator àíznwpñvh$m H$moS> BA Q. Booklet Code narjmwu H$mo {X o n amj«m $ H$s ZH$b ñd H$s hñv{b{n ZrMo {X o J o [a³v ñwmz na ZH$b (H$m nr) H$aZr h & ""Amn ghr ì dgm h, h Amn V^r mz Jo ~ : Amn H$m na mzo Ho$ {be qm{vv h, Amn {ZË AnZm H$m g~go AÀN>m H$aZm MmhVo h, Am a Amn AnZo H$m Ho$ hëd H$mo g PVo h &'' AWdm / R To be copied by the candidate in your own handwriting in the space given below for this purpose is compulsory. You will know you are in the right profession when : you wake anxious to go to work, you want to do your best daily, and you know your work is important. * Bg n îr> H$m D$nar AmYm ^mj H$mQ>Zo Ho$ ~mx {ZarjH$ Bgo N>mÌ H$s MR sheet Ho$ gmw gwa{jv aio& * After cutting half upper part of this page, invigilator preserve it along with student s MR sheet. nwpñvh$m win îr> g{hv n îr>m H$s g» m No. of Pages in Booklet including title 6 PAPER- PCB g K Q>o Time Hours àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. A H$ / Marks 600 nwpñvh$m àízm H$s g» m No. of Questions in Booklet 150 AZwH«$ m H$ / Roll No. narjmwu H$m Zm / Name of Candidate : narjm{w m Ho$ {be {ZX}e /INSTRCTINS T CANDIDATE Aä {W m hovw Amdí H$ {ZX}e : Instructions for the Candidate : 1. Amo.E.Ama. CÎma n{ìh$m Jmobm VWm g^r à{dpîq> m H$mo ^azo Ho$ {be Ho$db Zrbo m H$mbo ~mb ßdmB Q> noz H$m hr Cn moj H$a &. SECRITY SEAL ImobZo Ho$ nhbo Aä Wu AnZm Zm, AZwH«$ m H$ (A H$m ) Amo.E.Ama. CÎma-erQ> H$m H«$ m H$ Bg àíz-nwpñvh$m Ho$ D$na {X o J o ñwmz na {bi & {X do Bg {ZX}e H$m nmbz Zht H$a Jo Vmo CZH$s CÎma-erQ> H$m yë m H$Z Zhr hmo gho$jm VWm Eogo Aä Wu A mo½ Kmo{fV hmo m Jo&. àë oh$ àíz Mma A H$m H$m h & {g àíz H$m CÎma Zht {X m J m h, Cg na H$moB A H$ Zht {X m m ojm& JbV CÎma na A H$ Zht H$mQ>m mejm& 4. g^r ~hþ{dh$ënr àízm EH$ hr {dh$ën ghr h, {gna A H$ Xo hmojm& 5. JH$, bm J Q>o{~b, mo~mbb $moz, Bbo³Q >m {ZH$ CnH$a VWm ñbmbs> ê$b Am{X H$m à moj d{ V h & 6. Aä Wu H$mo narjm H$j N>moS>Zo H$s AZw {V narjm Ad{Y H$s g mpßv na hr Xr m ojr& 7. {X {H$gr Aä Wu Ho$ nmg nwñvh $ m AÝ {b{iv m N>nr gm J«r, {ggo do ghm Vm bo gh$vo/gh$vr h, nm r m ojr, Vmo Cgo A mo½ Kmo{fV H$a {X m m gh$vm h & Bgr àh$ma, {X H$moB Aä Wu {H$gr ^r àh$ma H$s ghm Vm {H$gr ^r ómov go XoVm m bovm ( m XoZo H$m m bozo H$m à mg H$aVm) hþam nm m m ojm, Vmo Cgo ^r A mo½ Kmo{fV {H$ m m gh$vm h & 8. {H$gr ^r ^«H$s Xem àíz-nwpñvh$m Ho$ A J«or A e H$mo hr ghr d A {V mzm m ojm& 9. MR sheet Bg Paper Ho$ ^rva h VWm Bgo ~mha {ZH$mbm m gh$vm h naývw Paper H$s grb Ho$db nona ewé hmozo Ho$ g na hr Imobm m ojm& H$j {ZarjH$ Ho$ hñvmja /Signature of the Invigilator àíznwpñvh$m H$moS> BA Q. Booklet Code 1. se BLE or BLACK BALL PINT PEN only for all entries and for filling the bubbles in the MR Answer Sheet.. Before opening the SECRITY SEAL of the question booklet, write your Name, Roll Number ( In figures), MR Answer-sheet Number in the space provided at the top of the Question Booklet. Non-compliance of these instructions would mean that the Answer Sheet can not be evaluated leading the disqualification of the candidate.. Each question carries FR marks. No marks will be awarded for unattempted questions. There is no negative marking on wrong answer. 4. Each multiple choice questions has only one correct answer and marks shall be awarded for correct answer. 5. se of calculator, log table, mobile phones, any electronic gadget and slide rule etc. is strictly prohibited. 6. Candidate will be allowed to leave the examination hall at the end of examination time period only. 7. If a candidate is found in possession of books or any other printed or written material from which he/she might derive assistance, he/she is liable to be treated as disqualified. Similarly, if a candidate is found giving or obtaining (or attempting to give or obtain) assistance from any source, he/she is liable to be disqualified. 8. English version of questions paper is to be considered as authentic and final to resolve any ambiguity. 9. MR sheet is placed within this paper and can be taken out from this paper but seal of paper must be opened only at the start of paper.

2 PAPER- Physics : Q. 1 to Q. 50 Chemistry : Q. 51 to Q. 100 Biology : Q. 101 to Q. 150 PHYSICS / ^m {VH$emó 001. A very long solenoid is made out of a wire with n turns per unit length. The radius of the cylinder is a and is negligible compared to its length l. The interior of the cylinder is filled with materials such that the linear magnetic permeability varies with the distance r from axis according to n ( r) n1 = constant ; for 0 < r < b = ) n = constant ; for b < r < a The self inductance of the solenoid is rn l 6 n1 b + n rn l 6 n1 + n@ a n r l 6 n1 b + n ( a - b )@ rn l 6 n1 b + ( n1 + n) 001. EH$ ~hþv b ~r n[azm{bh$m EH$ Vma go ~Zr h {gho$ BH$mB bå~mb Koamo H$s g»`m n h & Bg ~obz H$s {ÌÁ`m a h mo {H$ BgH$s bå~mb l H$s VwbZm ZJÊ` h & Bg ~obz Ho$ AÝXa Bg àh$ma nxmw ^am hþam h {H$ aoir` Mwå~H$s` nmajå`vm BgHo$ Aj go Xyar r Ho$ gmw {ZåZ Vah go n[ad{v V hmovr h n1 = AMa ; 0 < r < b n( r) = ) n = AMa ; b < r < a n[azm{bh$m H$m ñdàoah$ëd hmojm - rn l 6 n1 b + n rn l 6 n1 + n@ a n r l 6 n1 b + n ( a - b )@ rn l 6 n1 b + ( n1 + n) -BA ] [ ] [ Contd...

3 00. Two children Ramesh (on path ARB) and Sohan (on path ASB), travel down slides of identical height h but different shapes as shown. Assuming they start down the frictionless slides at the same time with zero initial velocity, which of the following statements is true? 00. Xmo ~ƒo a oe (nw ARB na) Ed gmohz (nw ASB na) EH$ g mz D$±MmB h go {MÌmZwgma AbJ AbJ AmH ${V`mo na ZrMo H$s Va $ { $gbvo h & `h m{ze {H$ EH$ hr g mz g ` na do eyý` doj Ho$ gmw Kf a{hv { $gbzm na { $gbzm àma ^ H$aVo h & {ZåZ go H$m Zgm H$WZ gë` h - Ramesh reaches the bottom first with the same average velocity as Sohan. Ramesh reaches the bottom first with a larger average acceleration than Sohan. Ramesh reaches the bottom first with the same average acceleration as Sohan. They reach the bottom at the same time with the same average acceleration. 00. A stream of non viscous liquid emerges from a very short outlet tube at the base of a large open tank, in which the depth of liquid is h. The tube is at a fixed angle θ to the ground as shown. The maximum height of the stream y is a oe Vbr na gmohz go nhbo nhþ±mvm h naývw XmoZm H$m Am gv doj g mz hmojm & a oe Vbr na gmohz go nhbo nhþ±mvm h naývw a oe H$m gmohz go Am gv Ëda A{YH$ hmojm & a oe Vbr na gmohz go nhbo nhþ±mvm h naývw XmoZm H$m Am gv Ëda g mz hmojm & XmoZm Vbr na g mz g ` na nhþ±mvo h Ed XmoZm H$m Am gv Ëda g mz hmojm & 00. EH$ Aí`mZ Ðd H$s Ymam EH$ ~ S>o Iwbo Q> H$ Ho$ AmYma na EH$ ~hþv N>moQ>r {ZJ V Zbr go {ZH$bVr h hm± na Ðd H$s JhamB h h & Q>çy~ H$s rz Ho$ gmw {MÌmZwgma {Z`V H$mo θ h Vmo Ymam H$s A{YH$V D$±MmB y hmojr - h sin i h sin i h sin i h sin i 1 h sin i h tan i 1 h sin i h tan i -BA ] [ ] [ P.T..

4 004. An eagle flies at constant velocity horizontally across the sky, carrying a mouse and releases the mouse while in flight. From the eagle s perspective, the mouse falls vertically with speed v 1. From an observer on the ground s perspective, the mouse falls at an angle with speed v. What is the speed of the eagle with respect to the observer on the ground? v + v v - v 1 1 v1 - v v - v The diffraction pattern of a single slit is shown in figure. The point at which the path difference of the extreme rays is two wavelengths is 004. EH$ ~m EH$ AMa j {V doj go AmH$me EH$ Myho H$mo nh$ S>o hþe C S> ahm h VWm C S>mZ Ho$ Xm amz Cg Myho H$mo wº$ H$aVm h & ~m Ho$ gmnoj Myhm CÜdm Ya ZrMo H$s Va $ v 1 Mmb go {JaVm h & rz na pñwv àojh$ Ho$ gmnoj {H$gr H$mo na Mmb v go Myhm {JaVm h & rz na pñwv àojh$ Ho$ gmnoj ~m H$s Mmb Š`m hmojr? v + v v - v 1 1 v1 - v v - v EH$b {N>Ð H$m {ddv Z à{vê$n {MÌ Xem `m J`m h & dh q~xw H$m Zgm h hm± na Ma (N>moa) {H$am H$m nwm Va Xmo Va JX Y` Ho$ ~am~a h - Point 1 Point Point 4 Point Which frequency produces a sound that can be heard by a person? 100 khz khz 40 khz 0 khz 007. Light from the Sun passes through a prism and a spectrum is produced on a screen. A thermometer placed at point X shows a temperature increase. For the given diagram, which type of radiation causes this temperature increase? Select the most appropriate option. q~xw 1 q~xw q~xw 4 q~xw {ZåZ go H$m Zgr Amd {Îm h {gh$s Üd{Z ì`{º$ Ûmam gwzr m gh$vr h? 100 khz khz 40 khz 0 khz 007. gỳ Ho$ àh$me H$mo EH$ {àá Ûmam Jwmam mvm h Ed naxo (Screen) na ñnoh$q > àmá {H$`m mvm h & q~xw X na aim Vmn mnr Vmn mz ~ T>moVar ~VmVm h & {XE JE {MÌ Ho$ {be {ZåZ go H$m Zgm {d{h$a Bg Vmn d {Õ H$mo ~VmVm h? g~go Cn`wº$ {dh$ën H$m M`Z H$s{E- infra-red Rays ultraviolet Rays X-rays visible light Adaº$ {H$ao nam~ JZr {H$ao EŠg {H$ao Ñí` {H$ao -BA ] [ 4 ] [ Contd...

5 008. Light has wavelength 600 nm in free space. It passes into glass, which has an index of refraction of 1.50, What is the frequency of the light inside the glass? 14. # 10 Hz # 10 Hz 5. # 10 Hz # 10 Hz 009. Two SHM are represented by the equations x1 = 0 sin8 r 5rt + B 4 x = 10^sin 5rt + cos 5rth The ratio of the amplitudes of the two motions is The r m s speed of hydrogen molecule at a certain temperature is v. If the temperature is doubled and hydrogen gas dissociates into atomic hydrogen, the r m s speed will become v v v v 011. The activity of a radioactive element decreases in 10 years to 1/5 of initial activity A 0. After further next 10 years its activity will be A 4 0 A 15 0 A 10 0 A Four very long wires are arranged as shown, so that their cross-section forms a square, with connections at the ends so that current I flows through all four wires as shown. Length of each side of the formed such square is b. The magnetic field at the central point P (centre of the square) is 008. àh$me H$s Va JX Ü` 600 nm wº$ AmH$me h & `h H$m M à{dï> hmovr h {gh$m AndV Zm H$ 1.50 h & àh$me H$s H$m M Ho$ AÝXa Amd {Îm Š`m h? # 10 Hz 5.0 # 10 Hz 5 5. # 10 Hz 5.0 # 10 Hz 009. Xmo gab AmdV J{V`m± {ZåZ g rh$am Ûmam àx{e V H$s mvr h - x1 = 0 sin8 r 5rt + B 4 x = 10^sin 5rt + cos 5rth XmoZm J{V`mo Ho$ Am`m m H$m AZwnmV Š`m hmojm `{X {H$gr {Z{üV Vmn na hmbs moz Aw H$s dj mü` yb Mmb (r m s) v h & `{X Vmn mz H$mo XwJwZm {H$`m mvm h Ed hmbs moz J g hmbs moz na mwam {dk{q>v hmo mvr h V~ dj mü` yb Mmb hmojr- v v v v 011. EH$ ao{s>`mo g{h«$` nxmw H$s àmapå^h$ g{h«$`vm A 0 h VWm `h 10 dfm] KQ>H$a àmapå^h$ g{h«$`vm H$s 1/5 hmo mvr h Vmo Am a AJbo 10 dfm] ~mx BgH$s g{h«$`vm hmojr- A 4 0 A 15 0 A 10 0 A Mma ~hþv b ~o Vma {MÌmZwgma Bg àh$ma ì`dpñwv h BZHo$ Ûmam {MÌmZwgma H$mQ> joì Ûmam dj ~ZVm h d BZ Mmamo Vma Ho$ {gao {MÌmZwgma w S>o h d àë`oh$ Vma àdm{hv Ymam I h & Bg àh$ma ~Zo dj H$s àë`oh$ ^wm b h & H $Ðr` q~xw P (dj H$m H $Ð ) na Mwå~H$s` joì hmojm - n0i rb 0 n0i rb n0 I rb n0i rb 0 n0i rb n0 I rb -BA ] [ 5 ] [ P.T..

6 01. A nonconducting ring carries linear charge density λ. It is rotating with angular speed ω about its axis. The magnetic field at its centre is 0 n m~ r n0 m~ r n0 m~ n0 m~ 014. A stationary source (see figure) emits sound waves of frequency f towards a stationary wall. If an observer moving with speed u in a direction perpendicular to the wall measures a frequency 11 f' = f at the instant shown, then u is related 8 to the speed of sound V S as 01. EH$ AMmbH$ db` aoir` Amdoe KZËd λ aivr h & `h H$mor` doj ω go BgHo$ Aj Ho$ n[av Ky{ V hmovr h Vmo BgHo$ H $Ð na Mwå~H$s` joì hmojm - 0 n m~ r n0 m~ r n m~ 0 n0 m~ 014. EH$ pñwa ómov(source) ({MÌ XoIo ) EH$ pñwa Xrdma H$s Va $ Amd {Îm f H$s Üd{Z Va J CËnÞ H$aVm h & {XE JE j na Xrdma Ho$ bå~dv J{V mz àojh$ (observer) 11 {gh$s Mmb u h dh Amd {Îm f' = f m{nv H$aVm 8 h Vmo u H$m mz Üd{Z Mmb V S go gå~ýy hmojm - V 4 S 8 V S 1 V 4 S V 8 S V 4 S 8 V S 1 V 4 S V 8 S 015. The front solid cylinder has mass M while the M back one solid cylinder has mass. The centers of these cylinders are connected by massless rod as shown. Both the cylinders have same radii R. The system is released from rest on the inclined plane. The cylinders roll down. The speed of the rod after system descending a vertical distance h is 015. AJ«(front) R>mog ~obz H$m Ðì` mz M h ~{H$ M nrn>o dmbo R>mog ~obz H$m Ðì` mz h & BZ ~obzmo Ho$ Ho$ÝÐ Ðì` mz a{hv N> S> go {MÌmZwgma w S>o h & XmoZm ~obzmo H$s {ÌÁ`mE± R g mz h & Bg {ZH$m` H$mo ZV Vb na {dam go wº$ {H$`m mvm h & ~obz bmoq>zr J{V H$aVo h & N> S> H$s Mmb Š`m hmojr ~ {ZH$m` ZrMo CÜdm Ya Xyar h V` H$aVm h gh 4gh gh gh 7 gh 4gh gh gh 7 -BA ] [ 6 ] [ Contd...

7 016. Suppose a particle of mass m moving with kx ax potential energy = + Ae - has velocity v a when its position is x = a. Here k, A and α are constants. The particle will be able to pass the origin if mva A + ka $ - aa ( 1 - e ) mva A + ka # -aa ( 1 - e ) 016. `h m{ze {H$ EH$ H$ {gh$m Ðì` mz m h dh kx ax pñw{v D$m = + Ae - Ho$ gmw J{V H$a ahm h & ~ `h x = a na hmovm h Vmo BgH$m doj v a hmovm h hm± k, A VWm α AMa h & H$ yb q~xw H$mo nma H$aZo g W hmojm `{X - mva A + ka $ - aa ( 1 - e ) mva A + ka # -aa ( 1 - e ) A # mva + ka - aa ( 1 - e ) A # mva + ka - aa ( 1 - e ) A $ mva + ka -aa ( 1 - e ) A $ mva + ka -aa ( 1 - e ) 017. A rectangular wire loop with length a and width b lies in the xy plane as shown. Within the loop there is a time dependent magnetic field given by B = c 6 ( x cos ~ t) i t + ( y sin ~ t) k Here c and ω are constants. The magnitude of emf induced in the loop as a function of time is 017. EH$ Am`VmH$ma Vma H$m byn {gh$s bå~mb a VWm Mm S>mB b h & `h {MÌmZwgma xy Vb h & byn Ho$ ^rva g ` na {Z^ a Mwå~H$s` joì {ZåZ h - B = c 6 ( x cos ~ t) i t + ( y sin ~ t) k hm± c VWm ω AMa h & g ` Ho$ $bz Ho$ ê$n byn ào[av {dúwv dmhh$ ~b H$m n[a m hmojm - ab c ~ cos ~ t ab c ~ cos ~ t ab c~ cos ~ t ab c~ cos ~ t a bc ~ sin ~ t a bc ~ sin ~ t None of the options BZ go H$moB {dh$ën Zht -BA ] [ 7 ] [ P.T..

8 018. A Tennis ball with (small) mass m sits on the top of a basketball with (large) mass m 1. The bottom of the basketball is at a height h above the ground and the bottom of the tennis ball is at a height (h + d) above the ground. The balls are dropped from rest. Here all collisions are elastic and m 1 >> m. To what approximate height from the ground the tennis ball bounce? 018. EH$ N>moQ>r Q>o{Zg J X {gh$m Ðì` mz m h `h EH$ ~ S>r ~mñho$q> J X {gh$m Ðì` mz m 1 h Ho$ D$na pñwv h & ~mñho$q> J X Ho$ {ZMbo Vb H$s rz go D±$MmB h h VWm Q>o{Zg J X Ho$ {ZMbo Vb H$s rz go D±$MmB (h + d) h & J Xm H$mo {dam go wº$ {H$`m mvm h & `hm± g^r Q> $ao àë`mñw h VWm m 1 >> m h & rz go bj^j {H$VZr D$±MmB VH$ Q>o{Zg J X CN>boJr? d + h d + h d + h d + h d + h d + 9h d + h d + 9h 019. An ellipse has uniform linear positive charge density in upper half (total upper half part charge +Q) and uniform linear negative charge density in lower half (total lower half part charge Q) as shown in figure. Here semi minor axis b < a semi major axis. Select the correct statement about the magnitude of electric dipole moment P of the ellipse 019. EH$ XrK d V Ho$ D$nar AY ^mj EH$ g mz aoir` YZmË H$ Amdoe KZËd (D$nar AY ^mj H$m Hw$b Amdoe +Q) h VWm {ZMbo AY ^mj EH$ g mz aoir` F$mË H$ Amdoe KZËd ({ZMbo AY ^mj H$m Hw$b Amdoe Q) {MÌmZwgma h & `hm± AY bkw Aj b < a AY XrK Aj h & XrK d Îm Ho$ {dúwv {ÛY«wd AmKy P Ho$ n[a m Ho$ ~mao ghr H$WZ M`Z H$s{E - Qb P = 0 < P < Qb Qb < P < Qb Qb 00. Consider the circuit shown below. The current in the 4W resistor is Qb P = 0 < P < Qb Qb < P < Qb Qb 00. ZrMo {XE JE {MÌ H$mo br{e & `hm± à{vamoy 4W go àdm{hv Ymam hmojr 0.5 A 0.75 A 0.50 A 1.00 A 0.5 A 0.75 A 0.50 A 1.00 A -BA ] [ 8 ] [ Contd...

9 01. A thin layer of oil (index of refraction 1.5 and thickness 500 nm) floats on the surface of the liquid (index of refraction 1.4). Now white light is normally incident on the thin film of oil. f the following, the most reflected wavelength is 500 nm 550 nm 600 nm 650 nm 0. Point charges 0 C, 0 C and 10 C are located at ( 1, 0, ), (0, 0, 0) and (1, 5, 1) respectively. The total electric flux leaving cube of side 6 m centered at the origin is -0 f 0 f Two infinitely long wires carry linear charge densities + λ and λ respectively as shown. The potential difference between points A (at a distance a from the first wire) and B (at a distance b from the second wire) is 10 f 0 0 f EH$ Vob H$s nvbr nav ({gh$m AndV Zm H$ 1.5 h VWm moq>mb 500 nm) mo {H$ AÝ` Ðd ({gh$m AndV Zm H$ 1.4 h ) H$s gvh na V avr h & A~ gµ $ox àh$me Bg Vob H$s nvbr nav na A{^bå~dV {JaVm h & {ZåZ go H$m Zgr Va JX Y` g~go A{YH$ namd{v V hmojr 500 nm 600 nm 550 nm 650 nm 0. q~xw Amdoe 0 C, 0 C VWm 10 C {~ÝXwAmo ( 1, 0, ), (0, 0, 0) VWm (1, 5, 1) na H«$ e pñwv h & EH$ KZ {gh$s ^wm 6 m h VWm {gh$m Ho$ÝÐ yb q~xw na H ${ÐV h, Cg KZ go nm[av {dúwv âbšg hmojm - -0 f 0 f f 0 0 f 0 0. Xmo AZÝV b ~o Vma na aoir` Amdoe KZËd H«$ e {MÌmZwgma + λ VWm λ h & q~xw A VWm B Ho$ Ü` {d^dmýva Š`m hmojm? (`hm± q~xw A àw Vma go a Xyar na h VWm q~xw B {ÛVr` Vma go b Xyar na h ) m ( d a) ( d b) ln c - - m rf ab 0 m rf 0 d ln c m ab m ( d a)( d b) ln c - - m 4rf ab 0 m c ( d - a) ( d - b) m rf ab 0 m ( d a) ( d b) ln c - - m rf ab 0 m rf 0 d ln c m ab m ( d a)( d b) ln c - - m 4rf ab 0 m c ( d - a) ( d - b) m rf ab A charged particle of mass kg and charge C starts with initial velocity 4it + kt in an electric field 1it + 10t j. Here all units are in SI. At time t = 1 its velocity becomes 16i t + 10 t j + k t 40 i t + 0t j + k t i t + 15 t j + k t i t + 18t j 04. EH$ Amdo{eV H$ {gh$m Ðì` mz kg VWm Amdoe C h `h àmapå^h$ doj 4it + kt go {dywv joì 1it + 10t j J{V H$aZm àma ^ H$aVm h & `hm± g^r BH$mB`m± SI h & g ` t = 1 na BgH$m doj hmojm- 16i t + 10 t j + k t 40 i t + 0t j + k t i t + 15 t j + k t i t + 18t j -BA ] [ 9 ] [ P.T..

10 05. Which of these materials requires the least value of magnetic field strength to magnetize it? Nickel Silver Tungsten Sodium Chloride 06. A chain of length L and of mass m is placed upon a smooth surface. The length of BA is L b. Now the Chain is released and it slides down. Calculate the speed of the chain when its end reaches B 05. {ZåZ go H$m Zgo nxmw Ho$ {be BgH$mo Mwå~{H$V H$aZo Ho$ {be Mwå~H$s` joì H$m Ý`yZV mz Amdí`H$ h - {ZH$b Mm Xr Q> JñQ>Z gmo{s>` ŠbmoamBS> 06. EH$ ra H$s bå~mb L VWm Ðì` mz m h & BgH$mo EH$ {MH$Zr gvh na aim mvm h & ra Ho$ ^mj BA H$s bå~mb L b h & A~ ra H$mo wº$ {H$`m mvm h VWm `h ZrMo gah$vr h & ra H$s Mmb kmv H$amo ~ BgH$m {gam B pñw{v na nhþ±mvm h - g sin i( L - b ) L g sin i( L - b ) L g sin i ( L - b ) L g sin i( L - b) g sin i( L - b) g sin i ( L - b ) L g sin i( L - b) g sin i( L - b) 07. The basic idea of MASER was first given by Max Planck Townes Einstein Fresnel 08. The average value of rotational kinetic energy of one mole of oxygen gas at temperature T will be RT RT 5 1 RT RT 09. If the coefficient of static friction between shoes of a runner and the track is 0.85, the greatest acceleration that can be generated by the runner is (here g gravitational acceleration) 1.85 g g 0.85 g 0.15 g 07. oga (MASER) H$m yb {dmma gd àw {ZåZ Zo {X`m Wm - ošg ßbm H$ AmB ñq>rz Q>mCÝg «o$zb 08. Vmn mz T na EH$ mob Am ŠgrZ J g H$s Am gv Ky Z J{V D$m hmojr - RT RT 5 1 RT RT 09. `{X EH$ YmdH$ Ho$ yvm VWm nw Ho$ Ü` ñw {VH$ Kf Jwm H$ 0.85 h Vmo YmdH$ Ûmam CËnÞ A{YH$V Ëda H$m mz hmojm? (`hm± g JwéËdr` Ëda h ) 1.85 g 0.85 g g 0.15 g -BA ] [ 10 ] [ Contd...

11 00. Two planets (each having mass m) revolve around a stationary star ( of mass M ) in a circle of radius r. The two planets are always on opposite side of the star (i.e. they are diametrically opposite and always having separation r ). The orbital period T of the planets is of the form T = r What is the value of M'? M - m M - m 4 M M + m 4 r GM 01. An infinite number of capacitors.0 μf, 4.0 μf, 8.0 μf, 16.0 μf,... are connected in series. The equivalent capacitance of the system is 0.5 μf 0.5 μf 1.0 μf x 5t 0. A motion is described by y = 4e ^e h where y, x are in metres and t is in second. This represents progressive wave propagating along x direction with 5 m/s This represents progressive wave propagating along + x direction with 5 m/s This does not represent progressive wave. This represents standing wave. 0. A ray of light is incident on the plane mirror at rest. The mirror starts turning at a uniform angular acceleration of π rad.s. The reflected ray at the 1 end of s must have turned through In npn transistor circuit, the collector current is 0 ma. If 90% of the electrons emitted reach the collector then the emitter current will be about 16 ma emitter current will be 19 ma base current will be about ma base current will be about 10 ma - l 00. Xmo J«h (àë`oh$ H$m Ðì` mz m h ) r {ÌÁ`m Ho$ d Îm EH$ pñwa Vmao ({gh$m Ðì` mz M h ) Ho$ Mmamo Amoa n[a^«h$avo h & XmoZm J«h h oem Cg Vmao Ho$ {dnarv Amoa hmovo h AWm V ì`mgv {dnarv Ed h oem CZ J«hm Xyar r hmovr h & CZ J«hm H$m H$jH$ H$mb T {ZåZ ê$n hmojm T = r r GM l Vmo M' H$m mz Š`m hmojm? M - m M - m 4 M M + m AZÝV g»`m g Ym[aÌ.0 μf, 4.0 μf, 8.0 μf, 16.0 μf,... lor H«$ w S>o hþe h & {ZH$m` H$s Vwë` Ym[aVm hmojr μf μf 1.0 μf x 5t 0. EH$ J{V y = 4e ^e h Ûmam Xr mvr h hm± y, x rq>a h VWm t goh$ês> h - `h EH$ x {Xem Ho$ AZw{Xe 5 m/s go J{V mz àjm r Va J H$mo Xem Vm h & `h EH$ + x {Xem Ho$ AZw{Xe 5 m/s go J{V mz àjm r Va J H$mo Xem Vm h & `h EH$ àjm r Va J H$mo Zht Xem Vm h & `h EH$ AàJm r Va J H$mo Xem Vm h & 0. EH$ àh$me {H$a EH$ {dam aio g Vb Xn na Amn{VV hmovr h & `h Xn EH$ g mz H$mor` Ëda π rad.s go Ky Zm àma ^ H$aVm h & namd{v V {H$a g ` 1 s Ho$ nümv Hw$b Ky{ V hþb hmojr EH$ npn Q m {ñq>a n[anw, g J«mhH$ Ymam 0 ma h & `{X 90% CËg{ V BboŠQ moz g J«mhH$ na nhþ MVo h Vmo CËg H$ Ymam bj^j 16 ma hmojr & CËg H$ Ymam 19 ma hmojr & AmYma Ymam bj^j ma hmojr & AmYma Ymam bj^j 10 ma hmojr & -BA ] [ 11 ] [ P.T..

12 05. A wheel of radius m rolls on the ground with uniform velocity 4 m/s.the relative acceleration of the topmost point of the wheel with respect to the bottommost point of the wheel is 8 m/s 16 m/s 4 m/s m/s 06. A stone is released from an aeroplane which is rising with upward acceleration 5 m/s. Here g = 10 m/s. Two seconds after the release, separation between stone and aeroplane will be 10 m 0 m 0 m 5 m 07. A solid body rotates an angle θ about a stationary axis according to the law i = 6t - t.what is the mean value of angular velocity over the time interval between t = 0 and the time when the body comes to rest? 1 rad/s rad/s rad/s 4 rad/s 08. For sodium light, the two yellow lines occur at λ 1 and λ wavelengths. If the mean of these two is 6000 A and m - m1 = 6Ac,then the approximate energy difference between the two levels corresponding to λ 1 and λ is 10 ev ev 000 ev 10 6 ev 09. During the adiabatic expansion of moles of an ideal gas, the increase in internal energy was found to be equal to ( 00 J ). The work done by the gas during the process will be equal to J 00 J 00 J 040. In the given circuit, potential difference between Points A and B is 05. EH$ n{h`m {gh$s {ÌÁ`m m h rz na EH$ g mz doj 4 m/s go bmoq>zr J{V H$a ahm h & n{h`o Ho$ g~go {ZåZV q~xw Ho$ gmnoj n{h`o Ho$ g~go CƒV q~xw H$m Ëda hmojm - 8 m/s 16 m/s 4 m/s m/s 06. EH$ nëwa H$mo EH$ hdmb `mz go wº$ {H$`m mvm h & `hm± hdmb `mz D$nar Ëda 5 m/s go D$na CR> ahm h & `hm± g = 10 m/s h & wº$ H$aZo Ho$ Xmo goh$ês> nümv nëwa VWm hdmb `mz Ho$ Ü` Xyar hmojr - 10 m 0 m 0 m 5 m 07. EH$ R>mog dñvw EH$ pñwa Aj Ho$ n[av H$mo θ go {ZåZ {Z` i = 6t - t go Ky{ V hmovr h & g ` t = 0 VWm ~ dñvw {dam AmVr h Cg g `m Vamb Ho$ {be mü` H$mor` doj H$m mz Š`m hmojm? 1 rad/s rad/s rad/s 4 rad/s 08. gmo{s>` àh$me Ho$ {be Xmo nrbr aoime± Va JX Y` λ 1 VWm λ na hmovr h & `{X BZ XmoZm H$m mü` 6000 A h VWm m - m1 = 6Ac h Vmo BZ λ 1 VWm λ Ho$ g JV BZ XmoZm D$m ñvam Ho$ Ü` bj^j A Va hmojm- 10 ev 000 ev ev 10 6 ev 09. EH$ AmXe J g Ho$ mob Ho$ éymoî àgma Am V[aH$ D$m ( 00 J ) H$s d {Õ hmovr h Vmo Bg àh«$ J g Ûmam {H$`m J`m H$m` hmojm J 400 J 00 J 040. {XE JE n[anw {~ÝXwAmo A VWm B Ho$ Ü` {d^dm Va h V 4 V.7 V 10 V 6.7 V 4 V.7 V 10 V -BA ] [ 1 ] [ Contd...

13 041. The angular momentum of an electron in hydrogen atom is h. The kinetic energy of the r electron is 1.6 ev.4 ev 1.51 ev 0.85 ev 04. Which of the following is not the unit of surface tension? N J m m Kg Watt s m 04. A disk of radius R and mass M is at equilibrium at position D on the smooth inclined plane which makes an angle θ with the vertical as shown. The disk s centre is attracted to a point A located at a vertical distance d above the surface as shown. Assume that the force of attraction is proportional to the distance from the disk s center of mass to point A ; i.e. assume that F = k r where r is the distance from the point A to the disk s centre of mass and k is constant. Then distance BD is 041. BboŠQ moz H$m H$mor` g doj hmbs moz na mw h r h BboŠQ moz H$s J{V D$m hmojr 1.6 ev 1.51 ev.4 ev 0.85 ev 04. {ZåZ go H$m Zgr n ð> VZmd H$s BH$mB Zht h? N m J m Kg s Watt m 04. EH$ MH$Vr {gh$s {ÌÁ`m R d Ðì` mz M h `h pñw{v D na EH$ {MH$Zo ZV Vb na gmå`mdñwm h & `h ZV Vb CÜdm Ya Ho$ gmw {MÌmZwgma H$mo θ ~ZmVm h & {MÌmZwgma gvh go CÜdm Ya d D$±MmB na pñwv q~xw A H$s Amoa MH$Vr H$m H $Ð AmH${f V hmovm h & `h m{ze {H$ AmH$f ~b MH$Vr Ho$ Ðì` mz H $Ð go q~xw A H$s Xyar Ho$ g mzwnmvr hmovm h AWm V F = k r hm± r MH$Vr Ho$ Ðì` mz H $Ð go q~xw A H$s Xyar h VWm k AMa h, V~ Xwar BD hmojr - Mg Mg c - dm cos i c - dm sin i k k Mg Mg c - dm cos i c - dm sin i k k Mg Mg c + dm cos i c - dm tan i k k Mg Mg c + dm cos i c - dm tan i k k 044. ne milligram of matter converted into energy will give 90 J 9 10 J J J 045. An object of mass 10 kg falls from rest through a vertical distance of 10m and acquires a velocity of 10m/s.The work done by the push of air on the object is ^ g = 10 m/ s h 500 J 50 J 500 J 50 J 044. EH$ { brj«m Ðì` H$m D$m ê$nmýva hmojm - 90 J J 9 10 J J 045. EH$ dñvw {gh$m Ðì` mz 10 kg h `h {dam go CÜdm Ya Xyar 10 m go {JaVr h VWm `h 10 m/s H$m doj àmßv H$aVr h & dñvw na hdm Ûmam {H$`m J`m H$m` hmojm- ^ g = 10 m/ s h 500 J 50 J 500 J 50 J -BA ] [ 1 ] [ P.T..

14 046. What type of waves are produced in a sitar wire Transverse progressive Longitudinal progressive Transverse stationary Longitudinal stationary 047. A long rigid wire lies along the x axis and carries a current of 10 A in the positive x direction. Round the wire external magnetic field is B = i t + x t j with x in meters and B in Tesla. The magnetic force (in SI units) on the segment of the wire between x = 1 m and x = 4 m is A train travels east towards Hubli at 80 km/hr. A man on the train runs from the front of the train toward the rear of the train at 10 km/hr with respect to train. As he runs, he carries a plate of fruit with him. He notices a giant spider on the plate and throws the plate away from him (toward the rear of the train) at 0 km/hr with respect to him. Just after that instant, the startled spider jumps towards the man at 5 km/hr with respect to plate. The instant after the spider jumps toward the man, how fast is the spider approaching Hubli? 45km/hr 115 km/hr 55 km/hr 95 km/hr 049. The ratio of magnetic field at the centre of a current carrying circular coil to its magnetic moment is x. If the current and radius each of them are made three times, the new ratio will become x 9 x x / 9 x / If λ 1 and λ denote the de Broglie wavelengths of two particles with same masses but charges in the ratio of 1: after they are accelerated from rest through the same potential difference then λ 1 = λ λ 1 < λ λ 1 > λ none of the options 046. {gvma Vma H$m Zgr Va J CËnÞ hmovr h AZwàñW àjm r AZwX Y` àjm r AZwàñW AàJm r AZwX Y` AàJm r 047. EH$ b ~m ÑT> Vma x Aj Ho$ AZw{Xe h VWm Bg YZmË H$ x Aj Ho$ AZw{Xe Ymam 10 A àdm{hv hmo ahr h & Vma Ho$ Mmamo Amoa ~mø Mwå~H$s` joì B = i t + x t j h hm± x rq>a h VWm B Q>oñbm h & Vma Ho$ x = 1 m VWm x = 4 m Ho$ Ü` ^mj na Mwå~H$s` ~b (SI BH$mB ) hmojm EH$ Q oz nyd H$s Amoa hþ~br H$s Va $ Mmb 80 km/hr go J{V H$aVr h & EH$ ì`{º$ Q oz na AmJo go nrn>o H$s Va $ 10 km/hr go Q oz Ho$ gmnoj Xm S>Vm h & Cg Xm S>Vo hþe ì`{º$ Ho$ nmg EH$ $b H$s ßboQ> h dh `h ào{jv H$aVm h {H$ EH$ ~ S>r H$ S>r ßboQ> na h & dh ñd` Ho$ gmnoj ßboQ> H$mo 0 km/hr go ñd` go Xya Q oz Ho$ nrn>o H$s Va $ o$h$vm h & R>rH$ Bgr j Ho$ nümv Amü` M{H$V H$ S>r ì`{º$ H$s Va $ ßboQ> Ho$ gmnoj 5 km/hr go Hy$XVr h & H$ S>r Ho$ ì`{º$ H$s Va $ Hy$XZo Ho$ R>rH$ nümv Ho$ j H$ S>r hþ~br H$s Va $ {H$VZo doj go J{V mz h? 45km/hr 115 km/hr 55 km/hr 95 km/hr 049. `{X EH$ Ymamdmhr d ÎmmH$ma Hw $S>br Ho$ Ho$ÝÐ na Mwå~H$s` joì VWm CgHo$ Mwå~H$s` AmKy H$m AZwnmV x h & `{X Ymam VWm {ÌÁ`m àë`oh$ VrZ JwZm H$a {X`m mvm h Vmo Z`m AZwnmV hmojm x 9 x x / 9 x / Xmo H$m H$m Ðì` mz g mz h naývw CZH$m Amdoe 1: h & `{X λ 1 VWm λ BZ Xmo H$m H$s S>r ~«mo½br Va JX Ü` H$mo ~VmVo h `{X BÝh {dam go g mz {d^dm Va Ûmam Ëd[aV {H$`m mvm h Vmo λ 1 = λ λ 1 < λ BZ o go H$moB {dh$ën Zht λ 1 > λ -BA ] [ 14 ] [ Contd...

15 051. If a mixture of Fe and Fe 4 contains 75% Fe, what will be the percentage amount of each oxide in the mixture? 64.10% Fe and 5.90% Fe 50% Fe and 50% Fe 75% Fe and 5% Fe % Fe and 64.10% Fe 05. What will be the correct no. of total electrons in 1.6 g methane CHEMISTRY / agm Zemó 051. Fe Ed Fe 4 Ho$ EH$ { l {X 75% Fe h Vmo àë oh$ Am ³gmBS> H$m {H$VZm à{vev { l CnpñWV hmojm? 64.10% Fe Ed 5.90% Fe 50% Fe Ed 50% Fe 75% Fe Ed 5% Fe % Fe Ed 64.10% Fe g rwoz CnpñWV Hw$b Bbo³Q >mozm H$m ghr mz hmojm Which of the following pair of salt produces dourless gas with dil H S 4 HC - and HS - HC - and C - S - - and CHC C - - and CHC 054. ne litre of an acidified solution of KMn 4 containing 15.8 g KMn 4 is decolorised by passing sufficient amount of S. If S is produced by roasting of iron pyrite (FeS ). The amount of pyrite required to produce the necessary amount of S will be 15.8 g FeS 15.0 g FeS 7.5 g FeS 7.9 g FeS 055. If an e is revolving in the first bohr orbit of a H atom with a velocity of cms 1, what will be the velocity of the e in the third orbit of H atom cms cms cms cms Which is the correct formula of Forstrite Mg Si 4 Al (H) 4 (Si 5 ) Zr Si 4 Ca Si {ZåZ {H$g bd w½ VZw H S 4 go {H«$ m hmozo na J YhrZ J g CËg{ V hmovr h & HC - Ed HS - HC - Ed C - S - - Ed CHC - - C Ed CHC 054. EH$ brq>a KMn 4 H$m AåbrH $V {db Z {g 15.8 g KMn 4 CnpñWV h S H$s n m ßV mìm {da {JV {H$ m J m& {X S Am az nmbambq> (FeS ) Ho$ ^ Z go CËnm{XV hmo ahr h Vmo Amdí H$ S CËnm{XV H$aZo Ho$ {b o FeS H$s mìm hmojr? 15.8 g FeS 15.0 g FeS 7.5 g FeS 7.9 g FeS 055. {X EH$ Bbo³Q >mz H na mw Ho$ àw ~moa H$jH$ cms 1, go M³H$a bjm ahm h Vmo H na mw Ho$ V Vr ~moa H$jH$ Bbo³Q >mz H$m doj ³ m hmojm go r go go r go go r go go r go $moañq >mb Q> H$m ghr gyì H$m Z gm h? Mg Si 4 Al (H) 4 (Si 5 ) Zr Si 4 Ca Si 9 -BA ] [ 15 ] [ P.T..

16 057. Which of the following is optically active molecule CMe H H H H CMe CMe H H H H CH CMe D H D H CMe CH H H H H CH 058. Which of the following does not show a resonance effect C 6 H 5 H C 6 H 5 Cl C 6 H 5 NH C 6 H 5 NH 057. {ZåZ go H$m Z gm Aw àh$m{e g{h«$ h CMe H H H H CMe CMe H H H H CH 058. {ZåZ go H$m Z AZwZmX à^md Zht Xem Vm h CMe D H D H CMe CH H H H H CH C 6 H 5 H C 6 H 5 Cl C 6 H 5 NH C 6 H 5 NH 059. Petroleum refining involves Vaccum distillation Fractional distillation Steam distillation Simple distillation 060. D Glucose units in cellulose are joint by a 1, 4 glycosidic bond b 1, 6 glycosidic bond b 1, 4 glycosidic bond Peptide bond 061. Most reactive alcohol towards esterification is Primary alcohol Secondary alcohol Tertiary alcohol All are same reactive 06. The Markonvikov's rule is best applicable to the reaction C H 4 + HCl C H 6 + Br C H 6 + HBr C H 8 + Cl 059. noq >mo{b n[aîh$a hmovm h {Zdm V AmgdZrH$a Am {eh$ AmgdZrH$a dmîn AmgdZrH$a gmyma AmgdZrH$a 060. goë ybmo D ½byH$moµ BH$mB m± {H$gHo$ Ûmam w S>r hmovr h a 1, 4 ½bmBH$mogmB{S>H$ ~ÝY b 1, 6 ½bmBH$mogmB{S>H$ ~ÝY b 1, 4 ½bmBH$mogmB{S>H$ ~ÝY noßq>mbs> ~ÝY 061. dgr H$a A{^{H«$ m Ho$ {be {ZåZ go H$m Zgm EëH$mohmob A{YH$V g{h«$ hmojm àmw{ H$ EëH$mohmob {ÛVr H$ EëH$mohmob V Vr H$ EëH$mohmob g^r g mz ê$n go g{h«$ 06. {H$g A{^{H«$ m Ho$ {be mah$m}zr H$m $ {Z gdm {YH$ Cn w³v h? C H 4 + HCl C H 6 + Br C H 6 + HBr C H 8 + Cl -BA ] [ 16 ] [ Contd...

17 06. The addition of Br to (E) but ene gives (R, R) - - dibromobutane (S, S) dibromobutane (R, S) dibromobutane a mixture of (R, R) and (S, S), dibromobutane 064. Which among the following compounds will have meso form CH H CHH CHH CH CH H CHH CHH CH CH H (CHH) CH H C 6 H CHCl CHH CH 065. Which compound will be most reactive for electrophilic addition reaction CH CH = CH CH CH C / C CH CH CH = CHCCH 06. (E) - ã yq> - B Z H$s Br go mojmë H$ A{^{H«$ m H$m CËnmX hmojm (R, R) - - S>mB ~«mo moã yq>oz (S, S) S>mB ~«mo moã yq>oz (R, S) S>mB ~«mo moã yq>oz (R, R) Ed (S, S), S>mB~«mo moã yq>oz H$m { l 064. {ZåZ go H$m Z gm m {JH$ rgmo ê$n Xem Vm h? CH H CHH CHH CH CH H CHH CHH CH CH H (CHH) CH H C 6 H CHCl CHH CH 065. {ZåZ go H$m Z gm m {JH$ Bbo³Q >mzñzohr mojmë H$ A{^{H«$ m Ho$ {be gdm {YH$ g{h«$ hmojm CH CH = CH CH CH C / C CH CH CH = CHCCH 066. At 98 K what will be the change in standard internal energy change for the given reaction F + H + HF ( g) ( g) ( g) ( g) 1.5 kj 10 kj TH = - 10kJ 15.0 kj 156 kj K na A{^{H«$ m Ho$ {be mzh$ AmÝV[aH$ D$m n[adv Z ³ m hmojm? F + H + HF ( g) ( g) ( g) ( g) 1.5 kj 10 kj TH = - 10kJ 15.0 kj 156 kj 067. How many s bonds and p bonds are present in N C C N C = C N C C N 5 s + 8 p 9 s + 9 p 9 s + 7 p 5 s + 9 p 068. Which of the following reactions is a redox reaction CaC + HCl CaCl + H + C AgN + KI AgI + KN - Cl + Br - Br + Cl BaCl - + S BaS - + Cl N C C N C = C N C C N {H$VZo s d p ~ÝY CnpñWV h & 5 s + 8 p 9 s + 9 p 9 s + 7 p 5 s + 9 p 068. {ZåZ A{^{H«$ mam H$m Z gr A{^{H«$ m Am ³grAnM Z A{^{H«$ m h CaC + HCl CaCl + H + C AgN + KI AgI + KN Cl Br Br Cl BaCl S BaS Cl -BA ] [ 17 ] [ P.T..

18 o 069. The E red of Ag, Cu, Co and Zn are 0.799, 0.7, 0.77 and 0.76 V respectively, which of the following cells will have max cell e.m.f.? + + Zn Zn ( 1M) Cu ( 1M) Cu Zn Zn + (1 M) Ag + (1 M) Ag + + Cu Cu (1 M) Ag (1 M) Ag + + Zn Zn (1 M) Co (1 M) Co 070. What will be the value of G and G for the reaction, A + B C + D at 7 C for which K = 10 - TG = 0 ; TGc = kj mol 1 - TG = 0 ; TGc = kj mol 1-1 TG = kj mol ; T Gc = 0-1 TG = kj mol ; TGc = In which of the following changes entropy decreases. Crystallization of sucrose from solution Dissolving sucrose in water Melting of ice Vaporization of camphor 07. Why is the Heat evolved in neutralization of HF is highest Due to low hydration energy of F ion Due to high hydration energy of F ion HF is a strong acid none of these 07. The reaction between p-methyl benzaldehyde and conc. NaH is an example of Cannizzaro reaction Aldol condensation Hydrolysis Haloform reaction 074. How benzene is converted into n - propyl benzene Friedel - crafts Alkylation Friedel - crafts Acylation Friedel - crafts Alkylation followed by clemmensen reduction Friedal - crafts Acylation followed by clemmensen reduction 069. Ag, Cu, Co Ed Zn Ho$ E AnM Z H«$ e 0.799, 0.7, 0.77 Ed 0.76 V h V~ {ZåZ go H$m Z go gob H$m e.m.f. A{YH$V hmojm& + + Zn Zn ( 1M) Cu ( 1M) Cu Zn Zn + (1 M) Ag + (1 M) Ag + + Cu Cu (1 M) Ag (1 M) Ag + + Zn Zn (1 M) Co (1 M) Co 070. A{^{H«$ m A + B C + D Ho$ {be 7 C na G Am a G H$m mz ³ m hmojm, {gh$m K = 10 h & TG = 0 ; TGc = kj mol 1 - TG = 0 ; TGc = kj mol 1-1 TG = kj mol ; T Gc = 0-1 TG = kj mol ; TGc = {ZåZ o go {H$g n[adv Z EÝQ >m nr H$m mz KQ>oJm {db Z go gwh«$mog H$m {H«$gQ>brH$a b gwh«$mog H$mo KmobZm ~ $ H$m {nkbzm H$ny a H$m dmînrh$a 07. HF H$s {ZpîH«$ Vm {ZH$bZo dmbr Cî m H$m mz A{YH$V hmovm h ³ m {H$ F Am Z H$s hmbs >oez D$m H$ hmozo Ho$ H$ma F Am Z H$s hmbs >oez D$m A{YH$ hmozo Ho$ H$ma HF EH$ à~b Aåb h Cn w ³V go H$moB Zht 07. p- o{wb ~oýopës>hmbs> Am a gmýð NaH Ho$ Ü hmozo dmbr {H«$ m {ZåZ A{^{H«$ m H$m CXmha h & Ho$Zrmamo A{^{H«$ m EëS>m b g KZZ bankq>z hobmo $m A{^{H«$ m 074. ~oýrz, n - àmo{nb ~oýrz {H$g àh$ma n[ad{v V hmojr& «$ss>b-h«$mâq> EbH$mBboeZ «$ss>b-h«$mâq> EgmBboeZ «$ss>b-h«$mâq> EbH$mBboeZ Ho$ nímmv p³b ozgz AnM Z «$ss>b-h«$mâq> EgmBboeZ Ho$ nímmv p³b ozgz AnM Z - -BA ] [ 18 ] [ Contd...

19 075. Which of the following does not depend on the attraction of the bonding pair towards the nucleus. The no. of protons in the nucleus The repulsion by the electrons in the same volence shell The amount of sheieding by inner shell electron The distance from the nucleus Which of the following oxide is of acidic nature. B Al Ga In 077. In activation energy for a simple Chemical reaction A " Bis E a in forward direction. The activation energy for reverse reaction can be less than or more than E a is always double of E a is negative of E a is always less than E a 075. {ZåZ go H$m Zgm w½ ~ {YV Ho$ Zm{^H$ H$s Amoa AmH$f na {Z^ a Zht H$aVm Zm{^H$ àmoq>mozm H$s g» m g mz g moh$ H$j CnpñWV Bbo³Q >mozm Ûmam à{vh$f AmÝV[aH$ H$j Bbo³Q >mozm H$s n[aaj mìm Zm{^H$ go Xÿar 076. {ZåZ go H$m Z-H$m Z go Am³gmBS> H$s àh ${V Aåbr hmovr h? B Al Ga In 077. EH$ gmyma amgm {ZH$ A{^{H«$ m A " B H$mo A{J«A{^{H«$ m H$s g{h«$ D$m E a h, V~ ním A{^{H«$ m H$s g{h«$ D$m E a go H$ AWdm A{YH$ hmo gh$vr h gx d E a go XmoJwZr hmojr E a H$m G$mË H$ hmojr gx d E a go H$ hmojr 078. The rate of first order reaction is mol L 1 min 1 at 0.5 M concentration of the reactant. The half life of the reaction is 0.8 min.1 min 8.7 min 7.5 min 078. àw H$mo{Q> H$s A{^{H«$ m H$m doj mol L 1 min 1 h {X A{^H$maH$ H$s gmýðvm 0.5 M h, A{^{H«$ m Ho$ AY Am wh$mb H$m mz h 0.8 min 8.7 min.1 min 7.5 min molal aqueous solution of a weak acid (HX) is 0% ionised. If K f for water is 1.86 K Kg mol 1, the lowering in freezing point of the solution is 1.1 K 0.56 K 1.1 K 0.56 K 080. Which of the following is not an example of addition polymer Polythene Polystyrene Neoprene Nylon EH$ Xþ~ b Aåb H$m (HX) H$m 0.5 mobb br {db Z 0 à{vev Am {ZV h {X b Ho$ {b o K f H$m mz 1.86 K Kg mol 1, h V~ {db Z Ho$ {h m H$ AdZ Z H$m mz hmojm& 1.1 K 1.1 K 0.56 K 0.56 K 080. {ZåZ go H$m Z gm mojmë H$ ~hþbh$ H$m CXmha Zht h & nm brwrz nm brpñq>arz {Z moàrz Zm bm Z 6.6 -BA ] [ 19 ] [ P.T..

20 081. The reactivity of the transition element usually decreases from Sc to Cu because of Lanthanide contraction Continious increase in ionization enthalpy Continuous decrease in ionization enthalpy Increase in no. of oxidation states 08. S is considered as airpollutant because its concentration increases with temperature increase of atmosphere. It is used as insecticide which is airpollutant It reacts with and H to produce acid rain It is a strong oxidant and oxidizes other components of atmosphere 08. Ferric chloride is used to stop bleeding in cuts because Fe + coagulates blood which is positively charged sol Fe + coagulates blood which is negatively charged sol Cl - coagulates blood which is positively charged sol Cl - coagulates blood which is negatively charged sol 084. A method of removing excess solute from a colloidal solution is distillation crystallization dialysis gas chromatography 085. For a complex, MX Y possessing trigonal prismatic geometry, the number of possible isomer is n doping Ge metal with a little of In or Ga, we get p type semiconductor insulator n - type semi conductor rectifier 081. g H«$ VËdm H$s {H«$ më H$Vm àm Sc go Cu VH$ bjmvma {H$gHo$ H$ma KQ>Vr h boýwozmbs> g Hw$MZ Am ZZ EoÝWobnr {ZaÝVa d {Õ Am ZZ EoÝWobnr {ZaÝVa H$ r Am³grH$a AdñWm H$s g» m d {Õ 08. gë $a S>mBAm ³gmBS> H$mo dm w àxÿfh$ Ho$ ê$n mzm mvm h ³ m {H$ BgH$s gmýðvm dm w ÊS>br Vmn mz d {Õ Ho$ gmw ~ T>Vr h & h EH$ H$sQ>ZmeH$ h mo dm wàxyfh$ h & h d H Ho$ gmw {H«$ m H$a Aåbr dfm CËnÞ H$aVm h & h EH$ à~b Am ³grH$maH$ hmovm h Ed dm w Ho$ AÝ KQ>H$m H$mo Am³grH $V H$a XoVm h & 08. H$Q>Zo na a³vòmd H$mo amoh$zo Ho$ {be Ferric chloride H$m Cn moj {H$ m mvm h ³ mo{h$ Fe + a³v H$mo ñh$pýxv H$aVm h mo {H$ EH$ YZm {ZH$ gm b h & Fe + a³v H$mo ñh$pýxv H$aVm h mo {H$ EH$ G$m {ZH$ gm b h & Cl a³v H$mo ñh$pýxv H$aVm h mo {H$ EH$ YZm {ZH$ gm b h & Cl a³v H$mo ñh$pýxv H$aVm h mo {H$ EH$ G$m {ZH$ gm b h & 084. H$m bmbs> {db Z go {dbo Ho$ Am{Y³ H$mo n WH$ H$aZo H$s {d{y h AmgdZrH$a {H«$ñQ >br H$a AnmohZrH$a J g H«$mo oq>moj«m $s 085. EH$ MH Y g Hw$b {gh$s Á m{ {V {ÌH$mor {àá r h Ho$ g ^m{dv g md dr hm Jo In or Ga H$s Aën mìm go Ge YmVw Ho$ An{ l go àmßv hmovm h p type AY MmbH$ Hw$MmbH$ n - type AY MmbH$ n[aemoyh$ -BA ] [ 0 ] [ Contd...

21 087. Zn converts from its melted state to its solid state, it has hcp structure, then the Number of nearest atoms will be If the pk a of acetic acid and pk b of NH 4 H are 4.76 and 4.75 respectively, what will be the ph of ammonium acetate solution Which of the following has least oxidation state of Fe? K [ Fe (H) 6 ] K [ Fe 4 ] FeS 4. ( NH 4 ) S 4. 6H - Fe ^CNh In electro chemical reaction of which set of reactants, the metal displacement will not take place Mg + Cu + Pb + Ag + Zn + Cu + Cu + Mg The IPAC name of the compound CH CH (CH ) C CH is - methyl - - butanone - methyl - - butanone isopropyl methyl ketone ethyl - methyl pentane 09. CH MgI will give methane with C H 5 H CH CH NH both of these (a and b) None of these 09. n long standing the bleaching powder undergoes auto-oxidation. The products formed are Calcium chloride only Calcium chlorate only Calcium chloride and calcium chlorate Calcium chloride and calcium chlorite 087. Zn AnZr J{bV AdñWm go R>mog AdñWm n[ad{v V hmoh$a hcp g amzm aivm h & V~ g rnñw AwAm H$s g» m hmojr& {X Eogr{Q>H$ Aåb H$s pk a Ed NH 4 H H$s pk b H«$ e 4.76 Am a 4.75 h V~ A mo{z Eo{gQ>oQ> {db Z H$s ph H$m mz hmojm& {ZåZ go {H$g Fe Ý yzv Am³grH$a AdñWm h & K [ Fe (H) 6 ] K [ Fe 4 ] FeS 4. ( NH 4 ) S 4. 6H - Fe ^CNh A{^H$maH$m Ho$ {H$g g yh H$s {dúwv amgm {ZH$ A{^{H«$ m YmVw {dñwmnz Zht hmojm Mg + Cu + Pb + Ag + Zn + Cu + Cu + Mg m {JH$ CH CH (CH ) C CH H$m Zm h - o{wb - - ã yq>ozm Z - o{wb - - ã yq>ozm Z AmBgmoàmo{nb o{wb H$sQ>moZ E{Wb - o{wb noýq>oz 09. CH MgI {H$gHo$ gmw rwoz XoJm C H 5 H CH CH NH (a) Ed (b) XmoZm BZ go H$moB Zht 09. b ~o g VH$ aizo na, ãbrqmj nmcs>a ñdv Am³grH$a go JwaVm h V~ {Z{ V CËnmX h Ho$db H $pëe ³bmoamBS> Ho$db H $pëe ³bmoaoQ> H $pëe ³bmoamBS> Ed H $pëe ³bmoaoQ> H $pëe ³bmoamBS> Ed H $pëe ³bmoamBQ> -BA ] [ 1 ] [ P.T..

22 094. Colour of the bead in borax bead test is mainly due to the formation of metal oxides boron oxides metal metaborates elemental boron 095. Product (P) of the given reaction is CH C CH CC H 5 (two equivalent) (I) NaH / THF (II) I + H / Δ (NH 4 ) C (P) Δ CH - C - CH - CH - C - CH 094. ~moao³g ZH$m narj ZH$m H$m a J w» ê$n go {ZåZ Ho$ ~ZZo Ho$ H$ma hmovm h & YmVw Am³gmBS> ~m am Z Am³gmBS> YmVw oq>m~moaoq²>g m {bh$ ~moamoz 095. A{^{H«$ m H$m CËnmX (P) h CH C CH CC H 5 (two equivalent) (I) NaH / THF (II) I + H / Δ (NH 4 ) C (P) Δ CH - C - CH - CH - C - CH CH - C - CH - CH - C - CH CH - C - CH - CH - C - CH CH CH CH CH CH N CH H CH N CH H CH N CH H CH N CH H 096. Cordite is a mixture of nitroglycerine, guncotton and vaseline borax, glycerine carborundum and charcoal glycerol and KMn H$m as>mbq> {ZåZ H$m { l h ZmBQ >mop½bgarz, JZH$moQ>Z VWm dogbrz ~moa³g VWm p½bgarz H$ma~moaÝS> VWm MmaH$mob p½bgam b VWm KMn 4 -BA ] [ ] [ Contd...

23 097. Which out of the following is the strongest acid? CHCH CHCCH CH CHCH CH CH 097. {ZåZ go H$m Z gm gdm {YH$ à~b Aåb h CHCH CHCCH CH CHCH CH CH CH CH CH CH CH CH 098. Which element is not in first transition series Fe Ag V Cu 099. Which reagent is capable of giving test both of Aldehyde and ketones Tollen reagent Fehling solution, 4 dinitrophenylhydrazine Shift reagent 100. Which reaction will not occur out of the following Fe + HS4 H + FeS4 Cu + AgN Cu(N ) + Ag KBr + I KI + Br Cu + H Cu + H 098. {ZåZ go H$m Z gm VËd àw g H«$ lor Zhr h Fe Ag V Cu 099. EopëS>hmBS> d H$sQ>moZ XmoZm Ho$ narj XoZo gj A{^H$ H$ h & Q>m boz A{^H$ H$ o$hqbj Kmob, 4 S>mB ZmBQ >mo o${zbìhmbs >o{z {e $ A{^H$ H$ 100. {ZåZ go H$m Z gr A{^{H«$ m Zht hmojr Fe + HS4 H + FeS4 Cu + AgN Cu(N ) + Ag KBr + I KI + Br Cu + H Cu + H -BA ] [ ] [ P.T..

24 101. rinary Bladder is absent in all birds, except Duck Gull wl strich 10. Who developed DNA fingerprinting? T.H.Morgan Alec Jeffreys Fedrick Sanger Francois Jacob BILGY / rdemó 101. {ZåZ{bpIV go {H$gr EH$ H$mo N>moS>H$a g^r n{j`m yìme` AZwnpñWV hmovm h? ~VI CbyH$ Kmo am ewvwa wj 10. S>r.EZ.E. A JwbrN>mnZ H$mo {H$gZo {dh${gv {H$`m? Q>r.EM. moajz EobH$ $arg o${ðh$ g Ja «$H$moBg H$m~ 10. Which of the following is formed by mesoderm of Gastrula? Central Nervous System Epidermis Circulatory System Liver and Pancreas 10. {ZåZ{bpIV go H$m Zgm EH$ H$ÝXwH$ Ho$ Ü`ÝñVa go ~ZVm h? Ho$ÝÐr` V {ÌH$m V Ì A{YM n[ag Ma V Ì `H $V VWm A½Ý me` 104. The antibody produced in allergic reaction is: IgG IgA IgE IgM 104. Ebu A{^{H«$`m {Z{ V hmozo dmbr à{vajr h :- IgG IgA IgE IgM 105. When was Montreal Protocol signed? m{zíæb àmoq>moh$mb na hñvmja H$~ hþe? BA ] [ 4 ] [ Contd...

25 106. Consider the following statements: Hardy Weinberg equilibrium is maintained in a population where (i) random mating is there (ii) there is no natural selection (iii) a population may gain or loose alleles Which of the statements given above is/are correct? (i) only (i) and (ii) only (ii) and (iii) only (i),(ii) and (iii) 106. {ZåZ{bpIV H$WZm na {dmma H$s{`o hms>u-dmbz~j g VwbZ Cg Zg»`m AZwajr` hmovm h,hm± (i) `mñpàn>h$ g J hmovm h & (ii) àmh ${VH$ da Zht hmovm h & (iii) EH$ Zg»`m `w½ {dh$pën`m H$s àm{á AdX²X²Vm hmo gh$vr h & Cn`w º$ H$WZm go H$m Z-gm/go ghr h /h? Ho$db (i) Ho$db (i) Am a (ii) Ho$db (ii) Am a (iii) (i), (ii) VWm (iii) 107. Species which are closely related, morphologically similar, reproductively isolated, live in sympatric population are designated as: Clines Ecades Demes Sibling 107. m{v`m, mo {ZH$Q>Vm go gå~ {YV h, AmH$m[a{H$`V g ê$n h, ZZmË H$ {db{jv h VWm g ñwm{zh$ Zg»`m dmg H$aVr h, CÝh H $go Zm mo{xñq> {H$`m mvm h? àd g wx` nm[a g m^mgr 108. Which one of the following group is nutritionally essential amino acids? Tyrosine, Valine, Tryptophan Glycine, Cystine,Valine Histidine, Isoleucine, Threonine Tryptophan, Leusine, Glycine 108. {ZåZ{bpIV go H$m Z-gm g yh nmofv Amdí`H$ E rzmo Aåbmo H$m h? Q>mBamogrZ, dobrz, Q rßq>mo o$z ½bmBgrZ, {gñq>rz, dobrz {hpñvs>rz, AmBgmoë`ygrZ, {W«AmZrZ Q rßq>mo o$z, ë`ygrz, ½bmBgrZ -BA ] [ 5 ] [ P.T..

26 109. Which of the following statements about DNA is not correct? The double helix is right-handed The nitrogenous bases are stacked on the inside of the helix The two strands of the double helix are anti-parallel The bases of the two poly-nucleotides interact by covalent bonding 109. S>r.EZ.E Ho$ {df` {ZåZ{bpIV go H$m Z-gm H$WZ ghr Zht h? {XdHw$ÊS>br X{jmdVu hmovr h ZmBQ moz jma Hw$ÊS>{bZr Ho$ ^rva H$s Amoa g aoir` hmovr h {XdHw$ÊS>br Ho$ Xmo a mwh$ à{vg m Va hmovo h Xmo nmbrý`y{h$bmoq>mbs>mo Ho$ jma ghg `mor Am~ÝYZ Ûmam nmañn[ah$ {H«$`m H$aVo h 110. Match List-I with List-II and select the correct answer using the code given below the list. List I List II A. pbr a. Vector B. EcoRI b. Transgenic monkey C. Andy c. Restriction endonuclease Key: 110. gymr-i H$mo gymr-ii go gw o{bv H$s{E VWm gy{m`m Ho$ ZrMo {XE JE Hy$Q> H$m à`moj H$a ghr CVa Mw{Z`o:- gymr I gymr II A. pbr a. dmhh$ B. EcoRI b. nmarzr ~ Xa C. E S>r c. à{v~ Y E S>moÝ`ypŠbEµ Hy$Q>: A B C A B C A B C A B C a b c b c a a b c b c a A B C A B C A B C A B C a c b c a b a c b c a b 111. Synoptonemal complex helps in Gamete formation Recombination during cell division Production of enzymes during cell division Chromosomal movement towards poles 111. `w½ gyìr g{ l {H$g ghm`vm H$aVm h? `w½ H$ {Z m & H$mo{eH$m {d^mz Ho$ Xm amz nwz`amoz& H$mo{eH$m {d^mz Ho$ Xm amz EÝmB m H$m CËnmXZ& Y«wdm H$s Amoa JwgyÌr g MbZ& -BA ] [ 6 ] [ Contd...

27 11. Methemoglobinemia is caused due to the presence of in excess of which of the following in drinking water? Iron Nitrate Phosphate Copper 11. Maltose is formed by which glycosidic linkage? Glucose α 1-4 glucose Galactose α 1-4 glucose Glucose β 1-4 galactose Glucose β 1-4 glucose 11. no`b {ZåZ{bpIV go {H$gH$s CnpñV{W H$s A{YH$Vm Ho$ H$ma Q>hr m ½bmo{~Zr{ `m hmovm h? bmoh ZmBQ oq> $mñ o$q> Vm «11. mëq>mog {H$g ½bmBH$mo{gS>rH$ ~ Y go ~ZVm h - ½byH$mog α 1-4 ½byH$mog J bošq>mog α 1-4 ½byH$mog ½byH$mog β 1-4 J bošq>mog ½byH$mog β 1-4 ½byH$mog 114. Bombykol is a/an: 114. ~må~rh$mob Š`m h? Hormone Parasite hm m}z nardr Pheromone Enzyme { $amo moz EÝmB 115. The hormone somatostatin is secreted is from: medium eminence zona glomerulosa delta cells in pancreas choroid plexus 115. gmo oq>moñq>o{q>z hm m}z {H$ggo óm{dv hmovm h? r{s>` E rzoýg JwÀN> ñva A½Ý me` H$s So>ëQ>m H$mo{eH$mE± aº$ mbh$ 116. Consider the following (i) Diarrhoea (ii) Demantia (iii) Dermatitis (iv) Delinquency Pellegra is characterized by which of the above? (i), (ii) and (iv) (i), (ii) and (iii) (ii), (iii) and (iv) (i), (iii) and (iv) 116. {ZåZ{bpIV na {dmma H$s{E: (i) àdm{hh$m (ii) Zmo^«e (iii) ËdŠemoW (iv) AnMma nobj«m H$s Cn`w º$ go H$m Z H$m Z gr {deofvme± h? (i), (ii) VWm (iv) (i), (ii) VWm (iii) (ii), (iii) VWm (iv) (i), (iii) VWm (iv) -BA ] [ 7 ] [ P.T..

28 117. Which of the following animal groups belong to same class? Pheretima, Lumbricus, Hirudinaria Spider, Louse, Millepede Cuttlefish, Devilfish, Squids Silverfish, Crayfish, Razorfish 118. Which one of the following is the correct sequence of larval stages in the development of Fasiola? Miracidium, Redia, Sporocyst, Metacercaria, Cercaria Cercaria, Miracidium, Sporocyst, Metacercaria, Redia Miracidium, Sporocyst, Redia, Cercaria, Metacercaria Redia, Cercaria, Metacercaria, Sporocyst, Miracidium 117. {ZåZ{bpIV go H$m Z-gm EH$ rdg yh g mz dj go gå~ýy aivm h? o$ao{q> m, bpå~«h$g, hrê$s>rzo[a`m H$S>r, y, { brnrs> H$Q>b{ $e, g ݽ rz, {gp³ds> amv rzm^, {d{mýjq>, jwa rz 118. ${gamobm Ho$ {dh$mg bmdm AdñWmAm H$m {ZåZ{bpIV go H$m Zgm EH$ AZwH«$ ghr h? ramgr{s>`, ao{s>`m, ñnmoamo{gñq>, oq>mgh $[a`m, gh $[a`m gh $[a`m, ramgr{s>`, ñnmoamo{gñq>, oq>mgh $[a`m, ao{s>`m ramgr{s>`, ñnmoamo{gñq>, ao{s>`m, gh $[a`m, oq>mgh $[a`m ao{s>`m, gh $[a`m, oq>mgh $[a`m, ñnmoamo{gñq>, ramgr{s>` 119. What is the reason of the eye disease Cataract? Destruction of sensory cells in retina. Lens becomes opaque. Loss of flexibility of lens. Increased pressure of vitreous humour in eye ball mo{v`mq~x H$m H$ma Š`m h? ao{q>zm H$s g doxr H$mo{eH$mAm Ho$ {dzme go b g Ho$ AnmaX{e V hmozo go b g bmrbo nz Ho$ Am^md go H$mMm^ Ðd Ho$ ~T>o hþe Xm~ Ho$ H$ma 10. Which of the following is produced by Yeast? Ascorbic Acid Vitamin B 1 Tocopherol Riboflavin 10. `rñq> Ûmam CËnm{XV hmovm h? EñH$mo{~ H$ Aåb {dq>m{ Z B 1 Q>oH$mo{ $amob amb~moâbo{dz -BA ] [ 8 ] [ Contd...

PH-03 December - Examination 2016 B.Sc. Pt. I Examination Electromagnetism. Paper - PH-03. Time : 3 Hours ] [ Max. Marks :- 50

PH-03 December - Examination 2016 B.Sc. Pt. I Examination Electromagnetism. Paper - PH-03. Time : 3 Hours ] [ Max. Marks :- 50 PH-03 December - Examination 2016 B.Sc. Pt. I Examination Electromagnetism {dúwvmwå~h$s Paper - PH-03 Time : 3 Hours ] [ Max. Marks :- 50 Note: The question paper is divided into three sections A, B and

More information

{dúwv Mwpå~H$s {gõm V VWm ñnoñq >moñh$monr

{dúwv Mwpå~H$s {gõm V VWm ñnoñq >moñh$monr MSCPH-07 June - Examination 2017 MSC (Final) Physics Examination Electromagnetic theory and Spectroscopy {dúwv Mwpå~H$s {gõm V VWm ñnoñq >moñh$monr Paper - MSCPH-07 Time : 3 Hours ] [ Max. Marks :- 80

More information

MT-03 June - Examination 2016 B.A. / B.Sc. Pt. I Examination Co-ordinate Geometry and Mathematical Programming Paper - MT-03

MT-03 June - Examination 2016 B.A. / B.Sc. Pt. I Examination Co-ordinate Geometry and Mathematical Programming Paper - MT-03 MT-03 June - Examination 016 B.A. / B.Sc. Pt. I Examination Co-ordinate Geometry and Mathematical Programming Paper - MT-03 Time : 3 Hours ] [ Max. Marks :- 66 Note: The question paper is divided into

More information

{Magå V {dúwvj{vh$s VWm gmno{îmh$vm H$m {d{eîq> {gõmýv

{Magå V {dúwvj{vh$s VWm gmno{îmh$vm H$m {d{eîq> {gõmýv 78 MPH-04 June - Examination 06 M.Sc. (Previous) Physics Examination Classical Electro Dynamics and Special Theory of Relativity {Magå V {dúwvj{vh$s VWm gmno{îmh$vm H$m {d{eîq> {gõmýv Paper - MPH-04 Time

More information

{dúwv Mwpå~H$s {gõm V VWm ñnoñq >moñh$monr

{dúwv Mwpå~H$s {gõm V VWm ñnoñq >moñh$monr MSCPH - 07 December - Examination 2015 MSC (Final) Physics Examination Electromagnetic theory and Spectroscopy {dúwv Mwpå~H$s {gõm V VWm ñnoñq >moñh$monr Paper - MSCPH - 07 Time : 3 Hours ] [ Max. Marks

More information

PH-02 June - Examination 2017 B.Sc. Pt. I Examination Oscillation and Waves. Paper - PH-02. Time : 3 Hours ] [ Max. Marks :- 50

PH-02 June - Examination 2017 B.Sc. Pt. I Examination Oscillation and Waves. Paper - PH-02. Time : 3 Hours ] [ Max. Marks :- 50 PH-02 June - Examination 2017 B.Sc. Pt. I Examination Oscillation and Waves XmobZ Ed Va J Paper - PH-02 Time : 3 Hours ] [ Max. Marks :- 50 Note: The question paper is divided into three sections. A, B

More information

MSCPH-03 June - Examination 2017 MSC (Previous) Physics Examination Solid State Physics. Paper - MSCPH-03. Time : 3 Hours ] [ Max.

MSCPH-03 June - Examination 2017 MSC (Previous) Physics Examination Solid State Physics. Paper - MSCPH-03. Time : 3 Hours ] [ Max. MSCPH-03 June - Examination 017 MSC (Previous) Physics Examination Solid State Physics R>mog AdñWm ^m {VH$s Paper - MSCPH-03 Time : 3 Hours ] [ Max. Marks :- 80 Note: The question paper is divided into

More information

{Magå V {dúwvj{vh$s VWm gmno{îmh$vm H$m {d{eîq> {gõm V

{Magå V {dúwvj{vh$s VWm gmno{îmh$vm H$m {d{eîq> {gõm V MPH-04 December - Examination 016 M.Sc. (Previous) Physics Examination Classical Electro Dynamics and Special Theory of Relativity {Magå V {dúwvj{vh$s VWm gmno{îmh$vm H$m {d{eîq> {gõm V Paper - MPH-04

More information

EMT December - Examination 2017 BAP Examination Elementary Mathematics Paper - EMT

EMT December - Examination 2017 BAP Examination Elementary Mathematics Paper - EMT EMT December - Examination 2017 BAP Examination Elementary Mathematics Paper - EMT Time : 3 Hours ] [ Max. Marks :- 80 The question paper is divided into three sections A, B and C. Write answers as per

More information

MPH-03 June - Examination 2016 M.Sc. (Previous) Physics Examination Quantum Mechanics. Paper - MPH-03. Time : 3 Hours ] [ Max.

MPH-03 June - Examination 2016 M.Sc. (Previous) Physics Examination Quantum Mechanics. Paper - MPH-03. Time : 3 Hours ] [ Max. MPH-03 June - Examination 2016 M.Sc. (Previous) Physics Examination Quantum Mechanics ³dm Q> m {ÌH$s Paper - MPH-03 Time : 3 Hours ] [ Max. Marks :- 80 Note: {ZX}e : The question paper is divided into

More information

PH-06 June - Examination 2016 BSc Pt. II Examination Optics. àh$m{eh$s. Paper - PH-06. Time : 3 Hours ] [ Max. Marks :- 50

PH-06 June - Examination 2016 BSc Pt. II Examination Optics. àh$m{eh$s. Paper - PH-06. Time : 3 Hours ] [ Max. Marks :- 50 PH-06 June - Examination 2016 BSc Pt. II Examination Optics àh$m{eh$s Paper - PH-06 Time : 3 Hours ] [ Max. Marks :- 50 This question paper is divided into three sections A, B and C. Write answer as per

More information

CBSE QUESTION PAPER. MATHEMATICS,(1)1d

CBSE QUESTION PAPER. MATHEMATICS,(1)1d CBSE QUESTION PAPER MATHEMATICS,()d Class-XII Ti me allowed : hours f.:mfftr'fffll: Maximum Marks: 00 'icfi: 00 gm_mý` {ZX}e : (i) (ii) (iii) (iv) (v) g^r àíz A{Zdm` h & Bg àíz nì _ 9 àíz h Omo Mma IÊS>m

More information

J{UV 65/2. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series GBM

J{UV 65/2. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series GBM Series GBM amob Z. Roll No. H$moS> Z. Code No. SET- 65/ narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M H$a

More information

J{UV 65/1/C. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series SSO

J{UV 65/1/C. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series SSO Series SSO amob Z. Roll No. H$moS> Z. Code No. SET- 65//C narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

A H$ / Marks. g 3 K Q>o Time 3 Hours. àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. narjm{w m Ho$ {be {ZX}e /INSTRUCTIONS TO CANDIDATE

A H$ / Marks. g 3 K Q>o Time 3 Hours. àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. narjm{w m Ho$ {be {ZX}e /INSTRUCTIONS TO CANDIDATE PAPER- PC AZwH«$ m H$ / Roll No. CÎma-eQ> H«$ m H$ / R Answe Sheet No. KmofUm : / Declaation : Zo n îr> g» m na {X o J o {ZX}em H$mo n T>H$a g P {b m h & I have ead and undestood the instuctions given

More information

J{UV 65/1/RU. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series SSO

J{UV 65/1/RU. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series SSO Series SSO amob Z. Roll No. H$moS> Z. Code No. SET- 65//RU narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

J{UV. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series OSR/1/C H$moS> Z. 65/1/2 Code No.

J{UV. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series OSR/1/C H$moS> Z. 65/1/2 Code No. Series OSR/1/C H$moS> Z. 65/1/ Code No. amob Z. Roll No. narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M H$a

More information

MT-03 December - Examination 2016 B.A. / B.Sc. Pt. I Examination Co-ordinate Geometry & Linear Programming Paper - MT-03

MT-03 December - Examination 2016 B.A. / B.Sc. Pt. I Examination Co-ordinate Geometry & Linear Programming Paper - MT-03 MT-03 December - Examination 06 B.A. / B.Sc. Pt. I Examination Co-ordinate Geometry & Linear Programming Paper - MT-03 Time : 3 Hours ] [ Max. Marks :- 66 Note: {ZX}e : Note: {ZX}e : The question paper

More information

MSCCH - 09 December - Examination 2015 M.Sc. Chemistry (Final) Examination Drugs and Pharmaceuticals Paper - MSCCH - 09

MSCCH - 09 December - Examination 2015 M.Sc. Chemistry (Final) Examination Drugs and Pharmaceuticals Paper - MSCCH - 09 MSCCH - 09 December - Examination 2015 M.Sc. Chemistry (Final) Examination Drugs and Pharmaceuticals Paper - MSCCH - 09 Time : 3 Hours ] [ Max. Marks :- 80 Note : The question paper is divided into three

More information

CBSE Question Paper. Mathematics Class-XII (set-1)

CBSE Question Paper. Mathematics Class-XII (set-1) CBSE Question Paper Mathematics Class-XII (set-1) {ZYm [av g_` : 3 KÊQ>o Time allowed : 3 hours A{YH$V_ A H$ : 70 MaimumMarks :70 gm_mý` {ZX}e : (i) (ii) (iii) (iv) (v) g^r àíz A{Zdm` h & Bg àíz nì _ 9

More information

CBSE QUESTION PAPER CLASS-X

CBSE QUESTION PAPER CLASS-X CBSE QUESTION PAPER CLASS-X g H${bV narjm - II SUMMATIVE ASSESSMENT - II J{UV MATHEMATICS {ZYm [av g_` 3 KÊQ>o ] [ A{YH$V_ A H$ 90 Time allowed : 3 hours ] [ Maximum marks : 90 gm_mý` {ZX}e (i) g^r àíz

More information

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90 Time allowed : 3 hours Maximum Marks : 90

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90 Time allowed : 3 hours Maximum Marks : 90 Series HRK amob Z. Roll No. H$moS> Z. Code No. SET-2 30/2 narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90 Time allowed : 3 hours Maximum Marks : 90

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90 Time allowed : 3 hours Maximum Marks : 90 Series RLH/2 H$moS> Z. 30/2/1 Code No. amob Z. Roll No. SET-1 narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

M09/4/CHEMI/SPM/ENG/TZ1/XX+ CHEMISTRY. Monday 18 May 2009 (afternoon) 45 minutes INSTRUCTIONS TO CANDIDATES

M09/4/CHEMI/SPM/ENG/TZ1/XX+ CHEMISTRY. Monday 18 May 2009 (afternoon) 45 minutes INSTRUCTIONS TO CANDIDATES M09/4/CHEMI/SPM/ENG/TZ1/XX+ 22096110 CHEMISTRY standard level Paper 1 Monday 18 May 2009 (afternoon) 45 minutes INSTRUCTIONS TO CANDIDATES Do not open this examination paper until instructed to do so.

More information

J{UV 65/3. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series SGN

J{UV 65/3. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series SGN Series SGN amob Z. Roll No. H$moS> Z. Code No. SET- 65/ narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M H$a

More information

J{UV 65/1. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series SGN

J{UV 65/1. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series SGN Series SGN amob Z. Roll No. H$moS> Z. Code No. SET- 65/ narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M H$a

More information

30/1/2 narjmwu H$moS> H$mo CÎma-nwpñVH$m Ho$ _win ð> na Adí` {bi & Candidates must write the Code on the title page of the answer-book.

30/1/2 narjmwu H$moS> H$mo CÎma-nwpñVH$m Ho$ _win ð> na Adí` {bi & Candidates must write the Code on the title page of the answer-book. Series HRK/1 amob> Z. Roll No. H$moS> Z. Code No. SET-2 30/1/2 narjmwu H$moS> H$mo CÎma-nwpñVH$m Ho$ _win ð> na Adí` {bi & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90 Time allowed : 3 hours Maximum Marks : 90

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90 Time allowed : 3 hours Maximum Marks : 90 Series RLH/2 H$moS> Z. 30/2/2 Code No. amob Z. Roll No. SET-2 narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS Series HRK/2 amob Z. Roll No. H$moS> Z. Code No. SET-2 30/2/2 narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

J{UV. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series OSR/C H$moS> Z. 65/1

J{UV. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series OSR/C H$moS> Z. 65/1 Series OSR/C H$moS> Z. 65/1 amob Z. Roll No. Code No. narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M H$a

More information

J{UV. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series OSR/2 H$moS> Z. 65/2/3 Code No.

J{UV. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series OSR/2 H$moS> Z. 65/2/3 Code No. Series OSR/ H$moS> Z. 65//3 Code No. amob Z. Roll No. narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M H$a

More information

30/1/3 narjmwu H$moS> H$mo CÎma-nwpñVH$m Ho$ _win ð> na Adí` {bi & Candidates must write the Code on the title page of the answer-book.

30/1/3 narjmwu H$moS> H$mo CÎma-nwpñVH$m Ho$ _win ð> na Adí` {bi & Candidates must write the Code on the title page of the answer-book. Series HRK/1 amob> Z. Roll No. H$moS> Z. Code No. SET-3 30/1/3 narjmwu H$moS> H$mo CÎma-nwpñVH$m Ho$ _win ð> na Adí` {bi & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90 Time allowed : 3 hours Maximum Marks : 90

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90 Time allowed : 3 hours Maximum Marks : 90 Series HRK amob Z. Roll No. H$moS> Z. Code No. SET-1 30/1 narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

J{UV 65/3. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series GBM

J{UV 65/3. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series GBM Series GBM amob Z. Roll No. H$moS> Z. Code No. SET- 65/ narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M H$a

More information

100% ionic compounds do not exist but predominantly ionic compounds are formed when metals combine with non-metals.

100% ionic compounds do not exist but predominantly ionic compounds are formed when metals combine with non-metals. 2.21 Ionic Bonding 100% ionic compounds do not exist but predominantly ionic compounds are formed when metals combine with non-metals. Forming ions Metal atoms lose electrons to form +ve ions. Non-metal

More information

Chemistry Higher level Paper 1

Chemistry Higher level Paper 1 M15/4/EMI/PM/ENG/TZ1/XX hemistry igher level Paper 1 Thursday 14 May 2015 (afternoon) 1 hour Instructions to candidates Do not open this examination paper until instructed to do so. Answer all the questions.

More information

Chemistry Standard level Paper 1

Chemistry Standard level Paper 1 M15/4/CHEMI/SPM/ENG/TZ1/XX Chemistry Standard level Paper 1 Thursday 14 May 2015 (afternoon) 45 minutes Instructions to candidates Do not open this examination paper until instructed to do so. Answer all

More information

J{UV. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series OSR/1/C H$moS> Z. 65/1/3

J{UV. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series OSR/1/C H$moS> Z. 65/1/3 Series OSR//C H$moS> Z. 65//3 amob Z. Roll No. CSBE Sample papers, Question, papers, Notes For Class 6 to Code No. narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the

More information

J{UV. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series OSR/1/C H$moS> Z. 65/1/1

J{UV. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series OSR/1/C H$moS> Z. 65/1/1 Series OSR/1/C H$moS> Z. 65/1/1 amob Z. Roll No. CSBE Sample papers, Question, papers, Notes For Class 6 to 1 Code No. narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write

More information

J{UV. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series OSR/2 H$moS> Z. 65/2/1 Code No.

J{UV. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 100. Series OSR/2 H$moS> Z. 65/2/1 Code No. Series OSR/ H$moS> Z. 65//1 Code No. amob Z. Roll No. narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M H$a

More information

M11/4/CHEMI/SPM/ENG/TZ2/XX CHEMISTRY STANDARD LEVEL PAPER 1. Monday 9 May 2011 (afternoon) 45 minutes INSTRUCTIONS TO CANDIDATES

M11/4/CHEMI/SPM/ENG/TZ2/XX CHEMISTRY STANDARD LEVEL PAPER 1. Monday 9 May 2011 (afternoon) 45 minutes INSTRUCTIONS TO CANDIDATES M11/4/CHEMI/SPM/ENG/TZ/XX 116116 CHEMISTRY STANDARD LEVEL PAPER 1 Monday 9 May 011 (afternoon) 45 minutes INSTRUCTIONS TO CANDIDATES Do not open this examination paper until instructed to do so. Answer

More information

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS Series HRK amob Z. Roll No. H$moS> Z. Code No. SET-3 30/3 narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

{ZX}e : h àíz-nì "A', "~' VWm "g' VrZ IÊS>m {d^m{ov h & àë oh$ IÊS> Ho$ {ZX}emZwgma àízm H$m CÎma Xr{OE&

{ZX}e : h àíz-nì A', ~' VWm g' VrZ IÊS>m {d^m{ov h & àë oh$ IÊS> Ho$ {ZX}emZwgma àízm H$m CÎma Xr{OE& MSCCH-06 June - Examination 2016 M.Sc. (Final) Chemistry Examination Reaction Mechanisms, Pericyclic Reactions Organic Photochemistry, Sterochemistry Paper - MSCCH-06 Time : 3 Hours ] [ Max. Marks :- 80

More information

MOCK cet paper II 2012 (PHYSICS)

MOCK cet paper II 2012 (PHYSICS) MOCK cet paper II 2012 (PHYSICS) 1. The equations of two sound waves are given by Y 1 = 3 sin 100πt and Y 2 = 4 Sin 150 πt. The ratio of the intensities of sound produced in the medium is 1)1:2 2) 1:4

More information

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS Series RLH/ H$moS> Z. 0// Code No. amob Z. Roll No. SET- narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M H$a

More information

J{UV (Ho$db ZoÌhrZ narjm{w `m Ho$ {be) MATHEMATICS. g H${bV narjm II SUMMATIVE ASSESSMENT II. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90.

J{UV (Ho$db ZoÌhrZ narjm{w `m Ho$ {be) MATHEMATICS. g H${bV narjm II SUMMATIVE ASSESSMENT II. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90. Series RLH amob Z. Roll No. SET-4 H$moS> Z. 30(B) Code No. narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

Chemistry Higher level Paper 1

Chemistry Higher level Paper 1 N17/4/EMI/PM/ENG/TZ0/XX hemistry igher level Paper 1 Wednesday 8 November 2017 (afternoon) 1 hour Instructions to candidates Do not open this examination paper until instructed to do so. Answer all the

More information

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS Series HRK/2 amob Z. Roll No. H$moS> Z. Code No. SET-1 30/2/1 narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

M10/4/CHEMI/SPM/ENG/TZ1/XX+ CHEMISTRY. Wednesday 12 May 2010 (afternoon) 45 minutes INSTRUCTIONS TO CANDIDATES

M10/4/CHEMI/SPM/ENG/TZ1/XX+ CHEMISTRY. Wednesday 12 May 2010 (afternoon) 45 minutes INSTRUCTIONS TO CANDIDATES M10/4/EMI/SPM/ENG/TZ1/XX+ 22106110 EMISTRY standard level Paper 1 Wednesday 12 May 2010 (afternoon) 45 minutes INSTRUTIONS TO ANDIDATES Do not open this examination paper until instructed to do so. Answer

More information

Chapter 3: Stoichiometry

Chapter 3: Stoichiometry Chapter 3: Stoichiometry Chem 6A Michael J. Sailor, UC San Diego 1 Announcements: Thursday (Sep 29) quiz: Bring student ID or we cannot accept your quiz! No notes, no calculators Covers chapters 1 and

More information

8. Relax and do well.

8. Relax and do well. CHEM 15 Exam II John II. Gelder March 4, 1999 Name TA's Name Lab Section INSTRUCTIONS: 1. This examination consists of a total of 7 different pages. The last two pages includes a periodic table, a solubility

More information

II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS

II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS {ZYm [av g_` : 3 KÊQ>o Time allowed : 3 hours A{YH$V_ A H$ : 80 Maximum Marks : 80 gm_mý` {ZX}e : (i) g^r àíz A{Zdm` h & (ii) Bg àíz-nì _ 31 àíz

More information

4.1 Atomic structure and the periodic table. GCSE Chemistry

4.1 Atomic structure and the periodic table. GCSE Chemistry 4.1 Atomic structure and the periodic table GCSE Chemistry All substances are made of atoms this is cannot be chemically broken down it is the smallest part of an element. Elements are made of only one

More information

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS Series RLH H$moS> Z. 30/3 Code No. amob Z. Roll No. narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M H$a b

More information

KCET PHYSICS 2014 Version Code: C-2

KCET PHYSICS 2014 Version Code: C-2 KCET PHYSICS 04 Version Code: C-. A solenoid has length 0.4 cm, radius cm and 400 turns of wire. If a current of 5 A is passed through this solenoid, what is the magnetic field inside the solenoid? ().8

More information

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS Series RLH H$moS> Z. 30/2 Code No. amob Z. Roll No. narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M H$a b

More information

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90 Time allowed : 3 hours Maximum Marks : 90

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90 Time allowed : 3 hours Maximum Marks : 90 Series HRS/2 H$moS> Z. 30/2/3 Code No. amob Z. Roll No. narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M H$a

More information

If anything confuses you or is not clear, raise your hand and ask!

If anything confuses you or is not clear, raise your hand and ask! CHM 1045 Dr. Light s Section December 10, 2002 FINAL EXAM Name (please print) Recitation Section Meeting Time This exam consists of six pages. Make sure you have one of each. Print your name at the top

More information

Essential Chemistry for Biology

Essential Chemistry for Biology 1 Chapter 2 Essential Chemistry for Biology Biology and Society: More Precious than Gold A drought is a period of abnormally dry weather that changes the environment and one of the most devastating disasters.

More information

àoau à^md {H$go H$hVo h?

àoau à^md {H$go H$hVo h? MSCCH-02 December - Examination 2016 M.Sc. (Previous) Chemistry Examination Organic Chemistry Paper - MSCCH-02 Time : 3 Hours ] [ Max. Marks :- 80 Note: The question paper is divided into three sections

More information

Chemistry 2 Exam Roane State Academic Festival. Name (print neatly) School

Chemistry 2 Exam Roane State Academic Festival. Name (print neatly) School Name (print neatly) School There are fifteen question on this exam. Each question is weighted equally. n the answer sheet, write your name in the space provided and your answers in the blanks provided.

More information

Last 4 Digits of USC ID:

Last 4 Digits of USC ID: Chemistry 05 B Practice Exam Dr. Jessica Parr First Letter of last Name PLEASE PRINT YOUR NAME IN BLOCK LETTERS Name: Last 4 Digits of USC ID: Lab TA s Name: Question Points Score Grader 8 2 4 3 9 4 0

More information

Chemistry Standard level Paper 1

Chemistry Standard level Paper 1 Chemistry Standard level Paper 1 Thursday 12 May 2016 (morning) 45 minutes Instructions to candidates Do not open this examination paper until instructed to do so. Answer all the questions. For each question,

More information

Transweb Educational Services Pvt. Ltd Tel:

Transweb Educational Services Pvt. Ltd     Tel: . The equivalent capacitance between and in the circuit given below is : 6F F 5F 5F 4F ns. () () 3.6F ().4F (3) 4.9F (4) 5.4F 6F 5F Simplified circuit 6F F D D E E D E F 5F E F E E 4F F 4F 5F F eq 5F 5

More information

STD : 12 TH GSEB PART A. 1. An electric dipole is placed in a uniform field. The resultant force acting on it...

STD : 12 TH GSEB PART A. 1. An electric dipole is placed in a uniform field. The resultant force acting on it... STD : 1 TH PHYSICS RJ VISION PVT. LTD. (MOST STABLE & INNOVATIVE INSTITUTE) GSEB COURSE NAME: 1 TH Total Marks : 100 Time : 3 hrs PART A Multiple Choice uestions : 1. An electric dipole is placed in a

More information

Scholarship 2006 Chemistry

Scholarship 2006 Chemistry For Supervisor s S 9 3 1 0 2 Scholarship 2006 Chemistry 2.00 pm Saturday 25 November 2006 Time allowed: Three hours Total Marks: 48 Check that the National Student Number (NSN) on your admission slip is

More information

A H$ / Marks. g 3 K Q>o Time 3 Hours. àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. narjm{w m Ho$ {be {ZX}e /INSTRUCTIONS TO CANDIDATE

A H$ / Marks. g 3 K Q>o Time 3 Hours. àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. narjm{w m Ho$ {be {ZX}e /INSTRUCTIONS TO CANDIDATE PAPER- PCB AZwH«$ m H$ / Roll No. CÎma-erQ> H«$ m H$ / OMR Answer Sheet No. àíznwpñvh$m H«$ m H$ Question Booklet Sr. No. àíznwpñvh$m H$moS> BA Q. Booklet Code KmofUm : / Declaration : Zo n îr> g» m 1

More information

CHEMISTRY. Time : 3 Hrs. Max. Marks : 70

CHEMISTRY. Time : 3 Hrs. Max. Marks : 70 CHEMISTRY Time : 3 Hrs. Max. Marks : 70 General instructions 1. All questions are compulsory. 2. Q.no. 1-5 are very short answer questions & carry 1 marks each Section-A. 3. Q.no. 6-12 are short answer

More information

A H$ / Marks. àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. narjm{w m Ho$ {be {ZX}e /INSTRUCTIONS TO CANDIDATE

A H$ / Marks. àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. narjm{w m Ho$ {be {ZX}e /INSTRUCTIONS TO CANDIDATE PAPER-4 AZwH«$ m H$ / Roll No. CÎma-erQ> H«$ m H$ / OMR Answer Sheet No. Aptitude Test for Architecture PART-A : Mathematics & Aesthetic Sensitivity PART-B : Drawing Aptitude àíznwpñvh$m H«$ m H$ Question

More information

Chemistry Standard level Paper 1

Chemistry Standard level Paper 1 M17/4/EMI/SPM/ENG/TZ1/XX hemistry Standard level Paper 1 Thursday 11 May 2017 (afternoon) 45 minutes Instructions to candidates Do not open this examination paper until instructed to do so. Answer all

More information

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90 Time allowed : 3 hours Maximum Marks : 90

g H${bV narjm II SUMMATIVE ASSESSMENT II J{UV MATHEMATICS {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90 Time allowed : 3 hours Maximum Marks : 90 Series RLH H$moS> Z. 30/1 Code No. amob Z. Roll No. Visit www.ncerthelp.com For All NCERT Solutions, SET-1 narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on

More information

A H$ / Marks. g 3 K Q>o Time 3 Hours. àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. narjm{w m Ho$ {be {ZX}e /INSTRUCTIONS TO CANDIDATE

A H$ / Marks. g 3 K Q>o Time 3 Hours. àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. narjm{w m Ho$ {be {ZX}e /INSTRUCTIONS TO CANDIDATE PAPER- PCM AZwH«$ m H$ / Roll No. CÎma-erQ> H«$ m H$ / OMR Answer Sheet No. àíznwpñvh$m H«$ m H$ Question Booklet Sr. No. àíznwpñvh$m H$moS> AD Q. Booklet Code KmofUm : / Declaration : Zo n îr> g» m na

More information

Fall 2011 CHEM Test 4, Form A

Fall 2011 CHEM Test 4, Form A Fall 2011 CHEM 1110.40413 Test 4, Form A Part I. Multiple Choice: Clearly circle the best answer. (60 pts) Name: 1. The common constituent in all acid solutions is A) H 2 SO 4 B) H 2 C) H + D) OH 2. Which

More information

^m {VH$ {dkmz (g ÕmpÝVH$) 55/3/C. PHYSICS (Theory) {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 70. Downloaded From:

^m {VH$ {dkmz (g ÕmpÝVH$) 55/3/C. PHYSICS (Theory) {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 70. Downloaded From: Series SSO amob Z. Roll No. ^m {VH$ {dkmz (g ÕmpÝVH$) PHYSICS (Theory) H$moS> Z. Code No. narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page

More information

M10/4/CHEMI/SPM/ENG/TZ2/XX+ CHEMISTRY. Wednesday 12 May 2010 (afternoon) 45 minutes INSTRUCTIONS TO CANDIDATES

M10/4/CHEMI/SPM/ENG/TZ2/XX+ CHEMISTRY. Wednesday 12 May 2010 (afternoon) 45 minutes INSTRUCTIONS TO CANDIDATES M10/4/CHEMI/SPM/ENG/TZ/XX+ 106116 CHEMISTRY standard level Paper 1 Wednesday 1 May 010 (afternoon) 45 minutes INSTRUCTIONS TO CANDIDATES Do not open this examination paper until instructed to do so. Answer

More information

PHYSICS. [Time 3 hours] [Maximum Marks: 720]

PHYSICS. [Time 3 hours] [Maximum Marks: 720] CBSE MAINS-07 PHYSICS [Time 3 hours] [Maximum Marks: 70] General Instructions:. The Answer Sheet is inside this Test Booklet. When you are directed to open the Test Booklet, take out the Answer Sheet and

More information

^m {VH$ {dkmz (g ÕmpÝVH$) 55/2/1. PHYSICS (Theory) {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 70. Series GBM/2

^m {VH$ {dkmz (g ÕmpÝVH$) 55/2/1. PHYSICS (Theory) {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 70. Series GBM/2 Series GBM/2 amob Z. Roll No. H$moS> Z. Code No. SET-1 55/2/1 narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

CHEM 172 EXAMINATION 1. January 15, 2009

CHEM 172 EXAMINATION 1. January 15, 2009 CHEM 17 EXAMINATION 1 January 15, 009 Dr. Kimberly M. Broekemeier NAME: Circle lecture time: 9:00 11:00 Constants: c = 3.00 X 10 8 m/s h = 6.63 X 10-34 J x s J = kg x m /s Rydberg Constant = 1.096776 x

More information

IIT JEE PAPER The question paper consists of 3 parts (Chemistry, Mathematics and Physics). Each part has 4 sections.

IIT JEE PAPER The question paper consists of 3 parts (Chemistry, Mathematics and Physics). Each part has 4 sections. IIT JEE - 2009 PAPER 2 A. Question paper format: 1. The question paper consists of 3 parts (Chemistry, Mathematics and Physics). Each part has 4 sections. 2. Section I contains 4 multiple choice questions.

More information

SUMMATIVE ASSESSMENT II J{UV MATHEMATICS

SUMMATIVE ASSESSMENT II J{UV MATHEMATICS Series HRS/2 H mos Z. 30/2/1 Code No. amob Z. Roll No. narjmwu H mos H mo CÎma-nwpñVH m Ho _wi-n ð na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H n`m Om±M H a b {H

More information

CHEM 107 (Spring-2005) Exam 3 (100 pts)

CHEM 107 (Spring-2005) Exam 3 (100 pts) CHEM 107 (Spring-2005) Exam 3 (100 pts) Name: ------------------------------------------------------------------------, Clid # ------------------------------ LAST NAME, First (Circle the alphabet segment

More information

A H$ / Marks. àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. narjm{w m Ho$ {be {ZX}e /INSTRUCTIONS TO CANDIDATE

A H$ / Marks. àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. narjm{w m Ho$ {be {ZX}e /INSTRUCTIONS TO CANDIDATE PAPER-4 AZwH«$ m H$ / Roll No. CÎma-erQ«$ m H$ / OMR Answer Sheet No. Aptitude Test for Architecture PART-A : Mathematics & Aesthetic Sensitivity PART-B : Drawing Aptitude àíznwpñvh$m H«$ m H$ Question

More information

^m {VH$ {dkmz (g ÕmpÝVH$) 55/3. PHYSICS (Theory) {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 70. Series GBM

^m {VH$ {dkmz (g ÕmpÝVH$) 55/3. PHYSICS (Theory) {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 70. Series GBM Series GBM amob Z. Roll No. H$moS> Z. Code No. SET-3 55/3 narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

Lab Day and Time: Instructions. 1. Do not open the exam until you are told to start.

Lab Day and Time: Instructions. 1. Do not open the exam until you are told to start. Name: Lab Day and Time: Instructions 1. Do not open the exam until you are told to start. 2. This exam is closed note and closed book. You are not allowed to use any outside material while taking this

More information

Set 1 30/1/1 narjmwu H$moS> H$mo CÎma-nwpñVH$m Ho$ _win ð> na Adí` {bi & Candidates must write the Code on the title page of the answer-book.

Set 1 30/1/1 narjmwu H$moS> H$mo CÎma-nwpñVH$m Ho$ _win ð> na Adí` {bi & Candidates must write the Code on the title page of the answer-book. Series JSR/1 amob> Z. Roll No. H$moS> Z. Code No. Set 1 30/1/1 narjmwu H$moS> H$mo CÎma-nwpñVH$m Ho$ _win ð> na Adí` {bi & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

A H$ / Marks. g 3 K Q>o Time 3 Hours. àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. narjm{w m Ho$ {be {ZX}e /INSTRUCTIONS TO CANDIDATE

A H$ / Marks. g 3 K Q>o Time 3 Hours. àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. narjm{w m Ho$ {be {ZX}e /INSTRUCTIONS TO CANDIDATE PAPER- PCM AZwH«$ m H$ / Roll No. CÎma-erQ> H«$ m H$ / OMR Answer Sheet No. àíznwpñvh$m H«$ m H$ Question Booklet Sr. No. àíznwpñvh$m H$moS> AC Q. Booklet Code KmofUm : / Declaration : Zo n îr> g» m na

More information

àíznwpñvh$m H«$ m H$ Question Booklet Sr. No. Roll No. g 3 K Q>o Time 3 Hours àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No.

àíznwpñvh$m H«$ m H$ Question Booklet Sr. No. Roll No. g 3 K Q>o Time 3 Hours àíznwpñvh$m H«$ m H$/ Question Booklet Sr. No. PAPER- PCB AZwH«$ m H$ / àíznwpñvh$m H$moS> àíznwpñvh$m H«$ m H$ Question Booklet Sr. No. Roll No. BA Q. Booklet Code CÎma-erQ> H«$ m H$ / OMR Answer Sheet No. KmofUm : / Declaration : narjm Ho$ÝÐmÜ j

More information

Atoms and the Periodic Table

Atoms and the Periodic Table Atoms and the Periodic Table Parts of the Atom Proton Found in the nucleus Number of protons defines the element Charge +1, mass 1 Parts of the Atom Neutron Found in the nucleus Stabilizes the nucleus

More information

^m {VH$ {dkmz (g ÕmpÝVH$) 55/3/A. PHYSICS (Theory) {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 70. Series SSO

^m {VH$ {dkmz (g ÕmpÝVH$) 55/3/A. PHYSICS (Theory) {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 70. Series SSO Series SSO amob Z. Roll No. H$moS> Z. Code No. SET-3 55/3/A narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

^m {VH$ {dkmz (g ÕmpÝVH$) 55/1/A. PHYSICS (Theory) {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 70. Series SSO

^m {VH$ {dkmz (g ÕmpÝVH$) 55/1/A. PHYSICS (Theory) {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 70. Series SSO Series SSO amob Z. Roll No. H$moS> Z. Code No. SET-1 55/1/A narjmwu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wi-n ð >na Adí` {bio & Candidates must write the Code on the title page of the answer-book. H $n`m Om±M

More information

BMT June - Examination 2017 BSCP Examination Mathematics J{UV. Paper - BMT. Time : 3 Hours ] [ Max. Marks :- 80

BMT June - Examination 2017 BSCP Examination Mathematics J{UV. Paper - BMT. Time : 3 Hours ] [ Max. Marks :- 80 BMT Jue - Eamiatio 7 BSCP Eamiatio Mathematics J{UV Paper - BMT Time : 3 Hours ] [ Ma. Marks :- 8 Note: The questio paper is divided ito three sectios A, B ad C. Write aswer as per the give istructios.

More information

AP Physics B Summer Assignment

AP Physics B Summer Assignment BERGEN COUNTY TECHNICAL SCHOOL AP Physics B Summer Assignment 2011 Solve all problems on separate paper. This will be due the first week of school. If you need any help you can e-mail Mr. Zavorotniy at

More information

Reporting Category 1: Matter and Energy

Reporting Category 1: Matter and Energy Name: Science Teacher: Reporting Category 1: Matter and Energy Atoms 8.5A Fill in the missing information to summarize what you know about atomic structure. Name of Subatomic Particle Location within the

More information

J{UV (311) Time : 3 Hours ] [ Max i mum Marks : 100. Note : (i) This Question Paper consists of two Sections, viz., A and B.

J{UV (311) Time : 3 Hours ] [ Max i mum Marks : 100. Note : (i) This Question Paper consists of two Sections, viz., A and B. MATH E MAT ICS J{UV (311) 311/OSS/03A Time : 3 Hours ] [ Max i mum Marks : 100 g_` : 3 K Q>o ] [ nyum H$ : 100 Note : (i) This Question Paper consists of two Sections, viz., A and B. (ii) (iii) All questions

More information

JEE MAIN 2018 Sample Question Paper

JEE MAIN 2018 Sample Question Paper SET 1 Roll No. JEE MAIN 2018 Sample Question Paper CHEMISTRY (Theory) General Instructions (i) This test consists of 30 question. (ii) Each question is allotted 4 marks for correct response. (iii) Candidates

More information

DURATION: 2 HOUR 45 MINUTES

DURATION: 2 HOUR 45 MINUTES 1 Exam 9 Our country, our future 525/1 S6 CHEMISTRY PAPER 1 DURATION: 2 HOUR 45 MINUTES For Marking guide contact and consultations: Dr. Bbosa Science 0776 802709. Answer all question in part I and six

More information

Model Paper QUESTION PAPER FOR EXTERNAL EXAMINATIONS. B Sc (Composite) Annual -2012: Subject: Physics

Model Paper QUESTION PAPER FOR EXTERNAL EXAMINATIONS. B Sc (Composite) Annual -2012: Subject: Physics Model Paper Roll No.. GOVERNMENT COLLEGE UNIVERSITY, FAISALABAD QUESTION PAPER FOR EXTERNAL EXAMINATIONS B Sc (Composite) Annual -2012: Subject: Physics Course Title: Mechanics, Waves, Oscilliation & optics

More information

J{UV MATHEMATICS. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90 Time allowed : 3 hours Maximum Marks : 90 IÊS> A SECTION A

J{UV MATHEMATICS. {ZYm [av g_` : 3 KÊQ>o A{YH$V_ A H$ : 90 Time allowed : 3 hours Maximum Marks : 90 IÊS> A SECTION A J{UV MATHEMATICS {ZYm [av g_` : KÊQ>o A{YH$V_ A H$ : 90 Time allowed : hours Maimum Marks : 90 IÊS> A SECTION A. `{X {ÛKmV g_rh$au p 5 p + 5 = 0 Ho$ Xmo g_mz _yb hm, Vmo p H$m _mz kmv H$s{OE & If the quadratic

More information

Physics Higher level Paper 1

Physics Higher level Paper 1 Physics Higher level Paper 1 Tuesday 31 October 17 (afternoon) 1 hour Instructions to candidates Do not open this examination paper until instructed to do so. Answer all the questions. For each question,

More information

B. X : in phase; Y: out of phase C. X : out of phase; Y: in phase D. X : out of phase; Y: out of phase

B. X : in phase; Y: out of phase C. X : out of phase; Y: in phase D. X : out of phase; Y: out of phase 2015 April 24 Exam 3 Physics 106 Circle the letter of the single best answer. Each question is worth 1 point Physical Constants: proton charge = e = 1.60 10 19 C proton mass = m p = 1.67 10 27 kg electron

More information