10.5 Graphs of the Trigonometric Functions

Transcription

1 790 Foundations of Trigonometr 0.5 Graphs of the Trigonometric Functions In this section, we return to our discussion of the circular (trigonometric functions as functions of real numbers and pick up where we left off in Sections 0.. and 0... As usual, we begin our stud with the functions f(t = cos(t and g(t = sin(t Graphs of the Cosine and Sine Functions From Theorem 0.5 in Section 0.., we know that the domain of f(t = cos(t and of g(t = sin(t is all real numbers, (,, and the range of both functions is [, ]. The Even / Odd Identities in Theorem 0. tell us cos( t = cos(t for all real numbers t and sin( t = sin(t for all real numbers t. This means f(t = cos(t is an even function, while g(t = sin(t is an odd function. Another important propert of these functions is that for coterminal angles α and β, cos(α = cos(β and sin(α = sin(β. Said differentl, cos(t+k = cos(t and sin(t+k = sin(t for all real numbers t and an integer k. This last propert is given a special name. Definition 0.. Periodic Functions: A function f is said to be periodic if there is a real number c so that f(t + c = f(t for all real numbers t in the domain of f. The smallest positive number p for which f(t + p = f(t for all real numbers t in the domain of f, if it eists, is called the period of f. We have alread seen a famil of periodic functions in Section.: the constant functions. However, despite being periodic a constant function has no period. (We ll leave that odd gem as an eercise for ou. Returning to the circular functions, we see that b Definition 0., f(t = cos(t is periodic, since cos(t + k = cos(t for an integer k. To determine the period of f, we need to find the smallest real number p so that f(t + p = f(t for all real numbers t or, said differentl, the smallest positive real number p such that cos(t + p = cos(t for all real numbers t. We know that cos(t + = cos(t for all real numbers t but the question remains if an smaller real number will do the trick. Suppose p > 0 and cos(t + p = cos(t for all real numbers t. Then, in particular, cos(0 + p = cos(0 so that cos(p =. From this we know p is a multiple of and, since the smallest positive multiple of is itself, we have the result. Similarl, we can show g(t = sin(t is also periodic with as its period. Having period essentiall means that we can completel understand everthing about the functions f(t = cos(t and g(t = sin(t b studing one interval of length, sa [0, ]. One last propert of the functions f(t = cos(t and g(t = sin(t is worth pointing out: both of these functions are continuous and smooth. Recall from Section. that geometricall this means the graphs of the cosine and sine functions have no jumps, gaps, holes in the graph, asmptotes, See section.6 for a review of these concepts. Alternativel, we can use the Cofunction Identities in Theorem 0. to show that g(t = sin(t is periodic with period since g(t = sin(t = cos ( t = f ( t. Technicall, we should stud the interval [0,, since whatever happens at t = is the same as what happens at t = 0. As we will see shortl, t = gives us an etra check when we go to graph these functions. In some advanced tets, the interval of choice is [,.

2 0.5 Graphs of the Trigonometric Functions 79 corners or cusps. As we shall see, the graphs of both f(t = cos(t and g(t = sin(t meander nicel and don t cause an trouble. We summarize these facts in the following theorem. Theorem 0.. Properties of the Cosine and Sine Functions The function f( = cos( The function g( = sin( has domain (, has domain (, has range [, ] has range [, ] is continuous and smooth is continuous and smooth is even is odd has period has period In the chart above, we followed the convention established in Section.6 and used as the independent variable and as the dependent variable. 5 This allows us to turn our attention to graphing the cosine and sine functions in the Cartesian Plane. To graph = cos(, we make a table as we did in Section.6 using some of the common values of in the interval [0, ]. This generates a portion of the cosine graph, which we call the fundamental ccle of = cos(. cos( (, cos( 0 (0, (, 0 ( (, 0, (, ( 5, ( (, 0 7, (, The fundamental ccle of = cos(. 5 7 A few things about the graph above are worth mentioning. First, this graph represents onl part of the graph of = cos(. To get the entire graph, we imagine coping and pasting this graph end to end infinitel in both directions (left and right on the -ais. Secondl, the vertical scale here has been greatl eaggerated for clarit and aesthetics. Below is an accurate-to-scale graph of = cos( showing several ccles with the fundamental ccle plotted thicker than the others. The 5 The use of and in this contet is not to be confused with the - and -coordinates of points on the Unit Circle which define cosine and sine. Using the term trigonometric function as opposed to circular function can help with that, but one could then ask, He, where s the triangle?

3 79 Foundations of Trigonometr graph of = cos( is usuall described as wavelike indeed, man of the applications involving the cosine and sine functions feature modeling wavelike phenomena. An accuratel scaled graph of = cos(. We can plot the fundamental ccle of the graph of = sin( similarl, with similar results. sin( (, sin( 0 0 (0, 0 (, ( (,, 0 (, 0 ( 5, 5 7 ( (, 7, 0 (, 0 The fundamental ccle of = sin(. 5 7 As with the graph of = cos(, we provide an accuratel scaled graph of = sin( below with the fundamental ccle highlighted. An accuratel scaled graph of = sin(. It is no accident that the graphs of = cos( and = sin( are so similar. Using a cofunction identit along with the even propert of cosine, we have ( ( ( sin( = cos = cos ( = cos Recalling Section.7, we see from this formula that the graph of = sin( is the result of shifting the graph of = cos( to the right units. A visual inspection confirms this. Now that we know the basic shapes of the graphs of = cos( and = sin(, we can use Theorem.7 in Section.7 to graph more complicated curves. To do so, we need to keep track of

4 0.5 Graphs of the Trigonometric Functions 79 the movement of some ke points on the original graphs. We choose to track the values = 0,,, and. These quarter marks correspond to quadrantal angles, and as such, mark the location of the zeros and the local etrema of these functions over eactl one period. Before we begin our net eample, we need to review the concept of the argument of a function as first introduced in Section.. For the function f( = 5 cos(, the argument of f is. We shall have occasion, however, to refer to the argument of the cosine, which in this case is. Loosel stated, the argument of a trigonometric function is the epression inside the function. Eample Graph one ccle of the following functions. State the period of each.. f( = cos ( +. g( = sin( + Solution.. We set the argument of the cosine,, equal to each of the values: 0,,,, and solve for. We summarize the results below. a 0 = a = 0 = = = = 5 Net, we substitute each of these values into f( = cos ( + to determine the corresponding -values and connect the dots in a pleasing wavelike fashion. f( (, f( (, (, (, (, 5 (5, 5 One ccle of = f(. One ccle is graphed on [, 5] so the period is the length of that interval which is.. Proceeding as above, we set the argument of the sine,, equal to each of our quarter marks and solve for.

5 79 Foundations of Trigonometr a = a 0 = 0 = = 0 = = We now find the corresponding -values on the graph b substituting each of these -values into g( = sin( +. Once again, we connect the dots in a wavelike fashion. g( (, g( (, 0 ( (, 0, ( (,, One ccle of = g(. One ccle was graphed on the interval [, ] so the period is ( =. The functions in Eample 0.5. are eamples of sinusoids. Roughl speaking, a sinusoid is the result of taking the basic graph of f( = cos( or g( = sin( and performing an of the transformations 6 mentioned in Section.7. Sinusoids can be characterized b four properties: period, amplitude, phase shift and vertical shift. We have alread discussed period, that is, how long it takes for the sinusoid to complete one ccle. The standard period of both f( = cos( and g( = sin( is, but horizontal scalings will change the period of the resulting sinusoid. The amplitude of the sinusoid is a measure of how tall the wave is, as indicated in the figure below. The amplitude of the standard cosine and sine functions is, but vertical scalings can alter this. 6 We have alread seen how the Even/Odd and Cofunction Identities can be used to rewrite g( = sin( as a transformed version of f( = cos(, so of course, the reverse is true: f( = cos( can be written as a transformed version of g( = sin(. The authors have seen some instances where sinusoids are alwas converted to cosine functions while in other disciplines, the sinusoids are alwas written in terms of sine functions. We will discuss the applications of sinusoids in greater detail in Chapter. Until then, we will keep our options open.

6 0.5 Graphs of the Trigonometric Functions 795 amplitude baseline period The phase shift of the sinusoid is the horizontal shift eperienced b the fundamental ccle. We have seen that a phase (horizontal shift of to the right takes f( = cos( to g( = sin( since cos ( = sin(. As the reader can verif, a phase shift of to the left takes g( = sin( to f( = cos(. The vertical shift of a sinusoid is eactl the same as the vertical shifts in Section.7. In most contets, the vertical shift of a sinusoid is assumed to be 0, but we state the more general case below. The following theorem, which is reminiscent of Theorem.7 in Section.7, shows how to find these four fundamental quantities from the formula of the given sinusoid. Theorem 0.. For ω > 0, the functions C( = A cos(ω + φ + B and S( = A sin(ω + φ + B have period ω have amplitude A have phase shift φ ω have vertical shift B We note that in some scientific and engineering circles, the quantit φ mentioned in Theorem 0. is called the phase of the sinusoid. Since our interest in this book is primaril with graphing sinusoids, we focus our attention on the horizontal shift φ ω induced b φ. The proof of Theorem 0. is a direct application of Theorem.7 in Section.7 and is left to the reader. The parameter ω, which is stipulated to be positive, is called the (angular frequenc of the sinusoid and is the number of ccles the sinusoid completes over a interval. We can alwas ensure ω > 0 using the Even/Odd Identities. 7 We now test out Theorem 0. using the functions f and g featured in Eample First, we write f( in the form prescribed in Theorem 0., ( ( ( f( = cos + = cos + +, 7 Tr using the formulas in Theorem 0. applied to C( = cos( + to see wh we need ω > 0.

7 796 Foundations of Trigonometr so that A =, ω =, φ = and B =. According to Theorem 0., the period of f is ω = / =, the amplitude is A = =, the phase shift is φ ω = / / = (indicating a shift to the right unit and the vertical shift is B = (indicating a shift up unit. All of these match with our graph of = f(. Moreover, if we start with the basic shape of the cosine graph, shift it unit to the right, unit up, stretch the amplitude to and shrink the period to, we will have reconstructed one period of the graph of = f(. In other words, instead of tracking the five quarter marks through the transformations to plot = f(, we can use five other pieces of information: the phase shift, vertical shift, amplitude, period and basic shape of the cosine curve. Turning our attention now to the function g in Eample 0.5., we first need to use the odd propert of the sine function to write it in the form required b Theorem 0. g( = sin( + = sin( ( + = sin( + = sin( + ( + We find A =, ω =, φ = and B =. The period is then =, the amplitude is =, the phase shift is = (indicating a shift right units and the vertical shift is up. Note that, in this case, all of the data match our graph of = g( with the eception of the phase shift. Instead of the graph starting at =, it ends there. Remember, however, that the graph presented in Eample 0.5. is onl one portion of the graph of = g(. Indeed, another complete ccle begins at =, and this is the ccle Theorem 0. is detecting. The reason for the discrepanc is that, in order to appl Theorem 0., we had to rewrite the formula for g( using the odd propert of the sine function. Note that whether we graph = g( using the quarter marks approach or using the Theorem 0., we get one complete ccle of the graph, which means we have completel determined the sinusoid. Eample Below is the graph of one complete ccle of a sinusoid = f(. (, 5 ( 5, 5 (, ( 7, 5 (, One ccle of = f(.. Find a cosine function whose graph matches the graph of = f(.

8 0.5 Graphs of the Trigonometric Functions 797. Find a sine function whose graph matches the graph of = f(. Solution.. We fit the data to a function of the form C( = A cos(ω + φ + B. Since one ccle is graphed over the interval [, 5], its period is 5 ( = 6. According to Theorem 0., 6 = ω, so that ω =. Net, we see that the phase shift is, so we have φ ω =, or φ = ω =. To find the amplitude, note that the range of the sinusoid is [, 5 ]. As a result, the amplitude A = [ 5 ( ] = ( =. Finall, to determine the vertical shift, we average the endpoints of the range to find B = [ 5 + ( ] = ( =. Our final answer is C( = cos ( Most of the work to fit the data to a function of the form S( = A sin(ω + φ + B is done. The period, amplitude and vertical shift are the same as before with ω =, A = and B =. The trickier part is finding the phase shift. To that end, we imagine etending the graph of the given sinusoid as in the figure below so that we can identif a ccle beginning at ( 7,. Taking the phase shift to be 7, we get φ ω = 7, or φ = 7 ω = 7 ( = 7 6. Hence, our answer is S( = sin ( ( 5, 5 ( 7, (, ( 9, 5 ( 8, Etending the graph of = f(. Note that each of the answers given in Eample 0.5. is one choice out of man possible answers. For eample, when fitting a sine function to the data, we could have chosen to start at (, taking A =. In this case, the phase shift is so φ = 6 for an answer of S( = sin ( 6 +. Alternativel, we could have etended the graph of = f( to the left and considered a sine function starting at ( 5,, and so on. Each of these formulas determine the same sinusoid curve and their formulas are all equivalent using identities. Speaking of identities, if we use the sum identit for cosine, we can epand the formula to ield C( = A cos(ω + φ + B = A cos(ω cos(φ A sin(ω sin(φ + B.

9 798 Foundations of Trigonometr Similarl, using the sum identit for sine, we get S( = A sin(ω + φ + B = A sin(ω cos(φ + A cos(ω sin(φ + B. Making these observations allows us to recognize (and graph functions as sinusoids which, at first glance, don t appear to fit the forms of either C( or S(. Eample Consider the function f( = cos( sin(. Find a formula for f(:. in the form C( = A cos(ω + φ + B for ω > 0. in the form S( = A sin(ω + φ + B for ω > 0 Check our answers analticall using identities and graphicall using a calculator. Solution.. The ke to this problem is to use the epanded forms of the sinusoid formulas and match up corresponding coefficients. Equating f( = cos( sin( with the epanded form of C( = A cos(ω + φ + B, we get cos( sin( = A cos(ω cos(φ A sin(ω sin(φ + B It should be clear that we can take ω = and B = 0 to get cos( sin( = A cos( cos(φ A sin( sin(φ To determine A and φ, a bit more work is involved. We get started b equating the coefficients of the trigonometric functions on either side of the equation. On the left hand side, the coefficient of cos( is, while on the right hand side, it is A cos(φ. Since this equation is to hold for all real numbers, we must have 8 that A cos(φ =. Similarl, we find b equating the coefficients of sin( that A sin(φ =. What we have here is a sstem of nonlinear equations! We can temporaril eliminate the dependence on φ b using the Pthagorean Identit. We know cos (φ + sin (φ =, so multipling this b A gives A cos (φ+a sin (φ = A. Since A cos(φ = and A sin(φ =, we get A = +( = or A = ±. Choosing A =, we have cos(φ = and sin(φ = or, after some rearrangement, cos(φ = and sin(φ =. One such angle φ which satisfies this criteria is φ =. Hence, one wa to write f( as a sinusoid is f( = cos ( +. We can easil check our answer using the sum formula for cosine f( = cos ( + = [ cos( cos ( ( sin( sin ] [ = cos( ( ( ] sin( = cos( sin( 8 This should remind ou of equation coefficients of like powers of in Section 8.6.

10 0.5 Graphs of the Trigonometric Functions 799. Proceeding as before, we equate f( = cos( sin( with the epanded form of S( = A sin(ω + φ + B to get cos( sin( = A sin(ω cos(φ + A cos(ω sin(φ + B Once again, we ma take ω = and B = 0 so that cos( sin( = A sin( cos(φ + A cos( sin(φ We equate 9 the coefficients of cos( on either side and get A sin(φ = and A cos(φ =. Using A cos (φ + A sin (φ = A as before, we get A = ±, and again we choose A =. This means sin(φ =, or sin(φ =, and cos(φ =, which means cos(φ =. One such angle which meets these criteria is φ = 5 6. Hence, we have f( = sin ( Checking our work analticall, we have f( = sin ( = [ sin( cos ( ( cos( sin 5 ] [ ( 6 = sin( + cos( ( ] = cos( sin( Graphing the three formulas for f( result in the identical curve, verifing our analtic work. It is important to note that in order for the technique presented in Eample 0.5. to fit a function into one of the forms in Theorem 0., the arguments of the cosine and sine function much match. That is, while f( = cos( sin( is a sinusoid, g( = cos( sin( is not. 0 It is also worth mentioning that, had we chosen A = instead of A = as we worked through Eample 0.5., our final answers would have looked different. The reader is encouraged to rework Eample 0.5. using A = to see what these differences are, and then for a challenging eercise, use identities to show that the formulas are all equivalent. The general equations to fit a function of the form f( = a cos(ω + b sin(ω + B into one of the forms in Theorem 0. are eplored in Eercise 5. 9 Be careful here! 0 This graph does, however, ehibit sinusoid-like characteristics! Check it out!

11 800 Foundations of Trigonometr 0.5. Graphs of the Secant and Cosecant Functions We now turn our attention to graphing = sec(. Since sec( = cos(, we can use our table of values for the graph of = cos( and take reciprocals. We know from Section 0.. that the domain of F ( = sec( ecludes all odd multiples of, and sure enough, we run into trouble at = and = since cos( = 0 at these values. Using the notation introduced in Section., we have that as, cos( 0 +, so sec(. (See Section 0.. for a more detailed analsis. Similarl, we find that as +, sec( ; as, sec( ; and as +, sec(. This means we have a pair of vertical asmptotes to the graph of = sec(, = and =. Since cos( is periodic with period, it follows that sec( is also. Below we graph a fundamental ccle of = sec( along with a more complete graph obtained b the usual coping and pasting. cos( sec( (, sec( 0 (0, (, 0 undefined (, (, 5 ( 5, 0 undefined ( 7, 7 (, The fundamental ccle of = sec(. 5 7 The graph of = sec(. Provided sec(α and sec(β are defined, sec(α = sec(β if and onl if cos(α = cos(β. Hence, sec( inherits its period from cos(. In Section 0.., we argued the range of F ( = sec( is (, ] [,. We can now see this graphicall.

12 0.5 Graphs of the Trigonometric Functions 80 As one would epect, to graph = csc( we begin with = sin( and take reciprocals of the corresponding -values. Here, we encounter issues at = 0, = and =. Proceeding with the usual analsis, we graph the fundamental ccle of = csc( below along with the dotted graph of = sin( for reference. Since = sin( and = cos( are merel phase shifts of each other, so too are = csc( and = sec(. sin( csc( (, csc( 0 0 undefined (, ( (,, 0 undefined ( 5, (, ( 7, undefined 5 7 The fundamental ccle of = csc(. Once again, our domain and range work in Section 0.. is verified geometricall in the graph of = G( = csc(. The graph of = csc(. Note that, on the intervals between the vertical asmptotes, both F ( = sec( and G( = csc( are continuous and smooth. In other words, the are continuous and smooth on their domains. The following theorem summarizes the properties of the secant and cosecant functions. Note that Just like the rational functions in Chapter are continuous and smooth on their domains because polnomials are continuous and smooth everwhere, the secant and cosecant functions are continuous and smooth on their domains since the cosine and sine functions are continuous and smooth everwhere.

13 80 Foundations of Trigonometr all of these properties are direct results of them being reciprocals of the cosine and sine functions, respectivel. Theorem 0.. Properties of the Secant and Cosecant Functions The function F ( = sec( has domain { : + k, k is an integer} = has range { : } = (, ] [, is continuous and smooth on its domain is even has period The function G( = csc( has domain { : k, k is an integer} = has range { : } = (, ] [, is continuous and smooth on its domain is odd has period k= k= ( (k +, (k, (k + In the net eample, we discuss graphing more general secant and cosecant curves. (k + Eample Graph one ccle of the following functions. State the period of each.. f( = sec( Solution.. g( = csc( 5. To graph = sec(, we follow the same procedure as in Eample First, we set the argument of secant,, equal to the quarter marks 0,,, and and solve for. a = a 0 = 0 0 = = = =

14 0.5 Graphs of the Trigonometric Functions 80 Net, we substitute these values into f(. If f( eists, we have a point on the graph; otherwise, we have found a vertical asmptote. In addition to these points and asmptotes, we have graphed the associated cosine curve in this case = cos( dotted in the picture below. Since one ccle is graphed over the interval [0, ], the period is 0 =. f( (, f( 0 (0, undefined (, undefined (, One ccle of = sec(.. Proceeding as before, we set the argument of cosecant in g( = csc( 5 equal to the quarter marks and solve for. a = a 0 = 0 = = 0 = = Substituting these -values into g(, we generate the graph below and find the period to be ( =. The associated sine curve, = sin( 5, is dotted in as a reference. g( (, g( undefined 0 undefined (, (, undefined One ccle of = csc( 5.

15 80 Foundations of Trigonometr Before moving on, we note that it is possible to speak of the period, phase shift and vertical shift of secant and cosecant graphs and use even/odd identities to put them in a form similar to the sinusoid forms mentioned in Theorem 0.. Since these quantities match those of the corresponding cosine and sine curves, we do not spell this out eplicitl. Finall, since the ranges of secant and cosecant are unbounded, there is no amplitude associated with these curves Graphs of the Tangent and Cotangent Functions Finall, we turn our attention to the graphs of the tangent and cotangent functions. When constructing a table of values for the tangent function, we see that J( = tan( is undefined at = and =, in accordance with our findings in Section 0... As, sin( and cos( 0 +, so that tan( = sin( cos( producing a vertical asmptote at =. Using a similar analsis, we get that as +, tan( ; as, tan( ; and as +, tan(. Plotting this information and performing the usual cop and paste produces: tan( (, tan( 0 0 (0, 0 (, undefined (, 0 (, 0 5 ( 5, undefined ( 7 7, 0 (, The graph of = tan( over [0, ]. The graph of = tan(.

16 0.5 Graphs of the Trigonometric Functions 805 From the graph, it appears as if the tangent function is periodic with period. To prove that this is the case, we appeal to the sum formula for tangents. We have: tan( + = tan( + tan( tan( tan( = tan( + 0 (tan((0 = tan(, which tells us the period of tan( is at most. To show that it is eactl, suppose p is a positive real number so that tan( + p = tan( for all real numbers. For = 0, we have tan(p = tan(0 + p = tan(0 = 0, which means p is a multiple of. The smallest positive multiple of is itself, so we have established the result. We take as our fundamental ccle for = tan( the interval (,, and use as our quarter marks =,, 0, and. From the graph, we see confirmation of our domain and range work in Section 0... It should be no surprise that K( = cot( behaves similarl to J( = tan(. Plotting cot( over the interval [0, ] results in the graph below. cot( (, cot( 0 undefined 0 undefined undefined ( (, (, 0, ( 5 (, (, 0 7, 5 7 The graph of = cot( over [0, ]. From these data, it clearl appears as if the period of cot( is, and we leave it to the reader to prove this. We take as one fundamental ccle the interval (0, with quarter marks: = 0,,, and. A more complete graph of = cot( is below, along with the fundamental ccle highlighted as usual. Once again, we see the domain and range of K( = cot( as read from the graph matches with what we found analticall in Section 0... Certainl, mimicking the proof that the period of tan( is an option; for another approach, consider transforming tan( to cot( using identities.

17 806 Foundations of Trigonometr The graph of = cot(. The properties of the tangent and cotangent functions are summarized below. As with Theorem 0., each of the results below can be traced back to properties of the cosine and sine functions and the definition of the tangent and cotangent functions as quotients thereof. Theorem 0.5. Properties of the Tangent and Cotangent Functions The function J( = tan( has domain { : + k, k is an integer} = has range (, is continuous and smooth on its domain is odd has period The function K( = cot( has domain { : k, k is an integer} = has range (, is continuous and smooth on its domain is odd has period k= k= ( (k +, (k, (k + (k +

18 0.5 Graphs of the Trigonometric Functions 807 Eample Graph one ccle of the following functions. Find the period.. f( = tan (.. g( = cot ( + +. Solution.. We proceed as we have in all of the previous graphing eamples b setting the argument of tangent in f( = tan (, namel, equal to each of the quarter marks,, 0, and, and solving for. a = a = = 0 = 0 0 = = Substituting these -values into f(, we find points on the graph and the vertical asmptotes. f( (, f( undefined (, 0 (0, (, 0 0 undefined We see that the period is ( =. One ccle of = tan (.. The quarter marks for the fundamental ccle of the cotangent curve are 0,,, and. To graph g( = cot ( + +, we begin b setting + equal to each quarter mark and solving for.

19 808 Foundations of Trigonometr a 0 + = a + = 0 + = + = + = + = 0 We now use these -values to generate our graph. g( (, g( undefined (, (, (, 0 undefined We find the period to be 0 ( =. One ccle of = cot ( + +. As with the secant and cosecant functions, it is possible to etend the notion of period, phase shift and vertical shift to the tangent and cotangent functions as we did for the cosine and sine functions in Theorem 0.. Since the number of classical applications involving sinusoids far outnumber those involving tangent and cotangent functions, we omit this. The ambitious reader is invited to formulate such a theorem, however.