(2) fv*-t)2v(»-«)=(*-a>:+(*-*)2

Size: px
Start display at page:

Download "(2) fv*-t)2v(»-«)=(*-a>:+(*-*)2"

Transcription

1 proceedings of the american mathematical society Volume 23, Number 2, December 995 OSTROWSKI TYPE INEQUALITIES GEORGE A. ANASTASSIOU (Communicated by Andrew M. Bruckner) Abstract. Optimal upper bounds are given to the deviation of a function / 6 CN([a, b]), N 6 N, from its averages. These bounds are of the form A ' H/^'lIco i where A is the smallest universal constant, i.e., the produced inequalities are sharp sometimes are attained. This work has been greatly motivated by the works of Ostrowski (938) Fink (992). 0. Introduction Here we establish optimal upper bounds on the deviation of a function from its averages. These lead to sharp inequalities. Namely, let / Cn+l([a, b]), n Z+, such that ßk)(x) = 0, k = I,..., n, where x is a fixed point in [a, b]. Then we establish that (*) rjj>>*-/w <9n(x)-\\f(n+l)\\ "+)'-oc where <pn(x) is a continuous function that depends only on n, a, b, it has a simple form it is the smallest possible, i.e., (*) is sharp in some cases it is even attained. The special case of x = =^ is encountered.. On Ostrowski's inequality Ostrowski's inequality (see Ostrowski [2]) is as follows: () / f(y)dy-f(x, (*-*?) 4+ ()2 where / e C ([a, b]), x [a, b]. Inequality () is sharp since the function in ( ) cannot be replaced by a smaller one. One can easily notice that (2) fv*-t)2v(»-«)=(*-a>:+(*-*)2 ()2 / v "' 2-() Received by the editors October 3, 993, in revised form, June 7, Mathematics Subject Classification. Primary 26D07, 26D0, 26D5, 4A44; Secondary 26A24, 26D20. Key words phrases. Function average, deviation of a function, best constant, sharp/attained inequality. 995 American Mathematical Society 3775

2 3776 G. A. ANASTASSIOU Next, we give a different proof to () from that of Ostrowski's initial proof of 938 in [2]. Theorem. Let f C ([a, b]), x [a, b]. Then (3) fb f, w ft n ^ f(x-a)2 + (b-x)2\.... I f{y)dy- f(x) < ( 2.{b_a) ) /II Inequality (3) is sharp, namely the optimal function is (4) f*(y):=\y-x\a-(), a >. Proof. Observe that X- [f(y)dy- /(x) = ^ - IjfVöO - f(x))dy So, we have established inequality (3). Note that thus r'(y) = a-\y- *\*hr)'l!^-fw'dy ^w^ym--sy-^dy n/'i ((x-û)2 + (è-x)2). 2 (b - a) x\a~l sign(y -x)-(), \r'(y)\=a.\y-x\a-l-() /*' oc = a. (b - a) (max(è - x, x - a)). Also we notice that /*(x) = 0. Therefore we have for /* that (5) Also, we observe that L.H.S.(3)= / \y-x\a-dy = la lim L.H.S.(3) = a» a+ (x - a)2 + (b - x)2 R.H.S.(3) i.e., proving (3) sharp. (x - a)2 + (b- x)2 ) a (max(z> - x, x - a))a ' lim R.H.S.(3) = a > D (x-a)2 + (6-x)2 lim L.H.S.(3) = lim R.H.S.(3), a» a»

3 OSTROWSKI TYPE INEQUALITIES 3777 Note that when x = a or x = b, inequality (3) can be attained by fa(y) := (y - a)'(b - a), fb(y) := (y - b) (b - a), respectively (then both sides of (3) are equal to (b - a)2/2). 2. More general Ostrowski type inequalities The following material has been greatly motivated by the important work of Fink []. Let / Cn+l([a, b]), n N, x [a, b], be fixed. Then by Taylor's theorem we get (6) f(y) - f(x) = ^ ^ (y -x)k +X (x,y), where (7) %n(x,y) := j\fw(t) - f{n)(x)). iy{~^ dt; here y can be > x or < x. Let y > x ; then i.e., \3ln(x, y)\ < jf \fn)(t) - f-n\x)\ {y~^ <II/^IU7>* -^^ = ll/^iu-^f, dt (8) \^n(x,y)\<^^-(y-x)"+l, y>x. Now let x > v ; then \&n(x, y)\ = \f(f(n)(t) - /«(*)). {y{~^ ~ dt < f\ß"\t)-f("kx)\-ly{-f~y.dt i.e., = M_ü~. (x - V)"+I (n+)! [ y) ' II f(n+l)\\ (9) \&n(x,y)\<u{n + ll~-(x-yy+i, x > y. From (8) (9) we get (0) \Xn{x,y)\<^+^~.\y-x\n+l, for all x, y [a, b].

4 3778 G. A. ANASTASSIOU Next we treat ~f Ay)dy-f(x) " \l y/w(x) ^ k\ k=\ J2^.(y-x)k+^n(x,y) f(f(y)-f(x))-dy dy f (y-x)k-dy+ f Mn(x,y).dy ffm.. \(b- x)*+> _{a_ x)k+i] k=i (k + iy. + f âên(x,y) dy (by (0)) ^b^a k=\ ^ '" \\fin+ + (»+!)! ly ' dy i.e., we have proved that (H) < I ñy)dy-f(x) J2l- ^-\(b-x)k+]-(a-x)k+i> 7c=l (*+l)! + \\f'(n+l) (n + 2)! ((x-a)"+2 + (è-x)n+2) where / e C"+l ([a, b]), n N, x [a, b], is fixed. If we choose x = =^, then (2) bh-samdy-f{ b-x = x-a = a + b 2 ' < /(^(^+) (,-fl)*+i U/t"*')»,,, ( -a)"*2 ^ Ofc + )! 2fc (w + 2)! 2"+!< even<«where /e C"+([a, 6]), " N. The above considerations the established inequalities () (2) lead to the following results.

5 OSTROWSKI TYPE INEQUALITIES 3779 Theorem 2. Let f C"+]([a, b]), n N x [a, b] be fixed, such that fik)(x) = 0, k=l,...,n. Then (3) jf/w-a^iph^-^)- Inequality (3) is sharp. Namely, when n is odd it is attained by f*(y) := (y - x)"+[ '(), while when n is even the optimal function is f(y):=\y-x\"+a-(), «>. Proof. Inequality (3) comes immediately from (). Next we prove the sharpness of inequality (3). When n is odd: Notice that f*(k)(x) = 0, k = 0,,..., n, f*{n+i)(y) = (n + )! -(). Hence Plugging f* into (3) we get ILT("+) oo = («+ l)!-( -a). (4) L.H.S.(3)=( >-^+2 + ^-fl)"+2. K ' K ' n+2 Also, (5, R.H.s.q^'*-'""2-^ -*> ", v ' v ' n+2 From (4) (5), when«is odd, inequality (3) was proved to be sharp, in particular attained by /*. When n is even: Notice that f(k)(x) = 0, k = 0, I,..., n, fin+i\y) = (n + a)(n + a - I) (a + ) a \y - x Q-' sign(y -x) (b - a). Hence \f{n+l](y)\= lfl(n + a-j)y\y-x\a-l-() \\f{n+])\\oo = ( f[(n + a - j) j - (max(è - x, x - a))a~l (b - a). Consequently we have,,., (n;=o(«+ «-7))-(max( -x,x-a))"-' R.H.S.(3) =-^^- ((x - a)n+2 + (b - x)"+2), (6) UmR.H.S.(3)=<^l^±^^ v ' a-\ v ' n + 2 L.H.S.(3)=^-^+Q+'+^-^+Q+. v ; n+a+l a>l.

6 3780 G. A. ANASTASSIOU Therefore (7) liml.h.s.(3) = a» (x - g)"+2 + (b - x)n+2 n + 2 From (6) (7) we get that (3) is sharp also when n is even. D Note that when x = a or x = b n is even, inequality (3) can be attained by fa(y) := (y - a)n+l (b - a), fb(y) := (y-b)n+i-(), respectively (then both sides of (3) are equal to (b - a)n+2/n + 2). When x = (a + b)/2, we have a case of special interest which is described next. Theorem 3. Let f Cn+l([a, b]), nen such that fik>((a + b)/2) = 0,all k even {I,..., n}. Then <\\f{n+l)\\oo ()"+l (n + 2)! ' 2"+' Inequality (8) is sharp. Namely, when n is odd it is attained by f*(y) := (y - =^)"+ '(), while when n is even the optimal function is (8) h-o^-'m f(y) a + b (), a>l. Corollary. Let f C2([a, b]) such that f"((a + b)/2) = 0. Then (9) b i_.rw/(^) < unie ()2 24 which is sharp as in Theorem 3. Proof. Apply Theorem 3 with n =. Proof of Theorem 3. Inequality (8) comes immediately from (2) the assumption f{k)((a + b)/2) = 0, all k even in {,...,«}. Next we prove the sharpness of inequality (8). When n is odd: We notice that r{k) (^y^) =. for A: = 0 all k even e {,. n}, furthermore (20) Also we find (2) /»(i+dq,) = («+ )!. (ft - a), R.H.S.(8) = L.H.S.(8) = (b - a)n+2 («+ 2)-2"+! (b - a)n+2 (n + 2). 2«+'' all y [a, b]. From (20) (2) we get that (8) is attained by /*, therefore (8) has been proved as sharp when n is odd.

7 OSTROWSKI TYPE INEQUALITIES 378 When n is even: We notice that furthermore f(k)((a + b)/2) = 0, for k = 0 all k even in {,...,«}, f {n+l\y) = fl(n +a-j).\y-^\a~l-sign (y-^y () 7=0 ll/("+)lloc = (flin + a - j)) (^f' ' (b- a). {\Tj=o{n + <*-J))'{{b-ä)/2T-i.() * ' A ' (n + 2)! ()n+l HpRT Q>- Hence ()n+2 (22) limr.h.s.(8)= / "\ ^,. v ' Q-i v ' (n + 2)-2"+' Also we find (23) L.H.S.(8)=2'<"'-'"/2r"' v ' n+a+ ()n+2 liml.h.s.(8 =.K", "'... Q-i v ' 2n+i-(n + 2) From (22) (23) we have established that inequality (8) is sharp again when n is even. D References. A. M. Fink, Bounds on the deviation of a function from its averages, Czechoslovak Math. J. 42(7) (992), A. Ostrowski, Über die Absolutabweichung einer differentiebaren Funktion von ihrem Integralmittelwert, Comment. Math. Helv. 0 (938), Department of Mathematical Sciences, The University of Memphis, Memphis, Tennessee 3852

a x a y = a x+y a x a = y ax y (a x ) r = a rx and log a (xy) = log a (x) + log a (y) log a ( x y ) = log a(x) log a (y) log a (x r ) = r log a (x).

a x a y = a x+y a x a = y ax y (a x ) r = a rx and log a (xy) = log a (x) + log a (y) log a ( x y ) = log a(x) log a (y) log a (x r ) = r log a (x). You should prepare the following topics for our final exam. () Pre-calculus. (2) Inverses. (3) Algebra of Limits. (4) Derivative Formulas and Rules. (5) Graphing Techniques. (6) Optimization (Maxima and

More information

Math 141: Section 4.1 Extreme Values of Functions - Notes

Math 141: Section 4.1 Extreme Values of Functions - Notes Math 141: Section 4.1 Extreme Values of Functions - Notes Definition: Let f be a function with domain D. Thenf has an absolute (global) maximum value on D at a point c if f(x) apple f(c) for all x in D

More information

8.7 Taylor s Inequality Math 2300 Section 005 Calculus II. f(x) = ln(1 + x) f(0) = 0

8.7 Taylor s Inequality Math 2300 Section 005 Calculus II. f(x) = ln(1 + x) f(0) = 0 8.7 Taylor s Inequality Math 00 Section 005 Calculus II Name: ANSWER KEY Taylor s Inequality: If f (n+) is continuous and f (n+) < M between the center a and some point x, then f(x) T n (x) M x a n+ (n

More information

A Generalized Ostrowski Type Inequality For A Random Variable Whose Probability Density Function Belongs To L p [a, b]

A Generalized Ostrowski Type Inequality For A Random Variable Whose Probability Density Function Belongs To L p [a, b] Applied Mathematics E-Notes, 8008), 46-53 c ISSN 607-50 Available free at mirror sites of http://www.math.nthu.edu.tw/ amen/ A Generalized Ostrowski Type Ineuality For A Random Variable Whose Probability

More information

THE PRIME NUMBER THEOREM FROM log»! N. LEVINSON1. During the nineteenth century attempts were made to prove the

THE PRIME NUMBER THEOREM FROM log»! N. LEVINSON1. During the nineteenth century attempts were made to prove the THE PRIME NUMBER THEOREM FROM log»! N. LEVINSON1 During the nineteenth century attempts were made to prove the prime number theorem from the formula [l, pp. 87-95] (D log pin \ + n + n LP3J + ) log p.

More information

MATH 409 Advanced Calculus I Lecture 16: Mean value theorem. Taylor s formula.

MATH 409 Advanced Calculus I Lecture 16: Mean value theorem. Taylor s formula. MATH 409 Advanced Calculus I Lecture 16: Mean value theorem. Taylor s formula. Points of local extremum Let f : E R be a function defined on a set E R. Definition. We say that f attains a local maximum

More information

Engg. Math. I. Unit-I. Differential Calculus

Engg. Math. I. Unit-I. Differential Calculus Dr. Satish Shukla 1 of 50 Engg. Math. I Unit-I Differential Calculus Syllabus: Limits of functions, continuous functions, uniform continuity, monotone and inverse functions. Differentiable functions, Rolle

More information

A Fixed Point Theorem in a Generalized Metric Space for Mappings Satisfying a Contractive Condition of Integral Type

A Fixed Point Theorem in a Generalized Metric Space for Mappings Satisfying a Contractive Condition of Integral Type Int. Journal of Math. Analysis, Vol. 3, 29, no. 26, 1265-1271 A Fixed Point Theorem in a Generalized Metric Space for Mappings Satisfying a Contractive Condition of Integral Type Bessem Samet Ecole Supérieure

More information

d(x n, x) d(x n, x nk ) + d(x nk, x) where we chose any fixed k > N

d(x n, x) d(x n, x nk ) + d(x nk, x) where we chose any fixed k > N Problem 1. Let f : A R R have the property that for every x A, there exists ɛ > 0 such that f(t) > ɛ if t (x ɛ, x + ɛ) A. If the set A is compact, prove there exists c > 0 such that f(x) > c for all x

More information

MATH 1372, SECTION 33, MIDTERM 3 REVIEW ANSWERS

MATH 1372, SECTION 33, MIDTERM 3 REVIEW ANSWERS MATH 1372, SECTION 33, MIDTERM 3 REVIEW ANSWERS 1. We have one theorem whose conclusion says an alternating series converges. We have another theorem whose conclusion says an alternating series diverges.

More information

nail-.,*.. > (f+!+ 4^Tf) jn^i-.^.i

nail-.,*.. > (f+!+ 4^Tf) jn^i-.^.i proceedings of the american mathematical society Volume 75, Number 2, July 1979 SOME INEQUALITIES OF ALGEBRAIC POLYNOMIALS HAVING REAL ZEROS A. K. VARMA Dedicated to Professor A. Zygmund Abstract. Let

More information

A NEW PROOF OF THE EXISTENCE THEOREM FOR IMPLICIT FUNCTIONS.

A NEW PROOF OF THE EXISTENCE THEOREM FOR IMPLICIT FUNCTIONS. 1912.] EXISTENCE THEOREM FOR IMPLICIT FUNCTIONS. 175 A NEW PROOF OF THE EXISTENCE THEOREM FOR IMPLICIT FUNCTIONS. BY PROFESSOR GILBERT AMES BLISS. (Read before the American Mathematical Society October

More information

Linearization and Extreme Values of Functions

Linearization and Extreme Values of Functions Linearization and Extreme Values of Functions 3.10 Linearization and Differentials Linear or Tangent Line Approximations of function values Equation of tangent to y = f(x) at (a, f(a)): Tangent line approximation

More information

Functional Equations

Functional Equations Functional Equations Henry Liu, 22 December 2004 henryliu@memphis.edu Introduction This is a brief set of notes on functional equations. It is one of the harder and less popular areas among Olympiad problems,

More information

Analysis/Calculus Review Day 3

Analysis/Calculus Review Day 3 Analysis/Calculus Review Day 3 Arvind Saibaba arvindks@stanford.edu Institute of Computational and Mathematical Engineering Stanford University September 15, 2010 Big- Oh and Little- Oh Notation We write

More information

A Common Fixed Point Theorem for a Sequence of Multivalued Mappings

A Common Fixed Point Theorem for a Sequence of Multivalued Mappings Publ. RIMS, Kyoto Univ. 15 (1979), 47-52 A Common Fixed Point Theorem for a Sequence of Multivalued Mappings By Kenjiro YANAGI* 1. introduction Recently, fixed point theorems for multivalued contraction

More information

e x = 1 + x + x2 2! + x3 If the function f(x) can be written as a power series on an interval I, then the power series is of the form

e x = 1 + x + x2 2! + x3 If the function f(x) can be written as a power series on an interval I, then the power series is of the form Taylor Series Given a function f(x), we would like to be able to find a power series that represents the function. For example, in the last section we noted that we can represent e x by the power series

More information

MATH 31B: MIDTERM 2 REVIEW. sin 2 x = 1 cos(2x) dx = x 2 sin(2x) 4. + C = x 2. dx = x sin(2x) + C = x sin x cos x

MATH 31B: MIDTERM 2 REVIEW. sin 2 x = 1 cos(2x) dx = x 2 sin(2x) 4. + C = x 2. dx = x sin(2x) + C = x sin x cos x MATH 3B: MIDTERM REVIEW JOE HUGHES. Evaluate sin x and cos x. Solution: Recall the identities cos x = + cos(x) Using these formulas gives cos(x) sin x =. Trigonometric Integrals = x sin(x) sin x = cos(x)

More information

Math 0230 Calculus 2 Lectures

Math 0230 Calculus 2 Lectures Math 00 Calculus Lectures Chapter 8 Series Numeration of sections corresponds to the text James Stewart, Essential Calculus, Early Transcendentals, Second edition. Section 8. Sequences A sequence is a

More information

1 + lim. n n+1. f(x) = x + 1, x 1. and we check that f is increasing, instead. Using the quotient rule, we easily find that. 1 (x + 1) 1 x (x + 1) 2 =

1 + lim. n n+1. f(x) = x + 1, x 1. and we check that f is increasing, instead. Using the quotient rule, we easily find that. 1 (x + 1) 1 x (x + 1) 2 = Chapter 5 Sequences and series 5. Sequences Definition 5. (Sequence). A sequence is a function which is defined on the set N of natural numbers. Since such a function is uniquely determined by its values

More information

ON THE MEDIANS OF GAMMA DISTRIBUTIONS AND AN EQUATION OF RAMANUJAN

ON THE MEDIANS OF GAMMA DISTRIBUTIONS AND AN EQUATION OF RAMANUJAN PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 121, Number I, May 1994 ON THE MEDIANS OF GAMMA DISTRIBUTIONS AND AN EQUATION OF RAMANUJAN K. P. CHOI (Communicated by Wei Y. Loh) Abstract. For

More information

ISE I Brief Lecture Notes

ISE I Brief Lecture Notes ISE I Brief Lecture Notes 1 Partial Differentiation 1.1 Definitions Let f(x, y) be a function of two variables. The partial derivative f/ x is the function obtained by differentiating f with respect to

More information

ASYMPTOTIC DISTRIBUTION OF THE MAXIMUM CUMULATIVE SUM OF INDEPENDENT RANDOM VARIABLES

ASYMPTOTIC DISTRIBUTION OF THE MAXIMUM CUMULATIVE SUM OF INDEPENDENT RANDOM VARIABLES ASYMPTOTIC DISTRIBUTION OF THE MAXIMUM CUMULATIVE SUM OF INDEPENDENT RANDOM VARIABLES KAI LAI CHUNG The limiting distribution of the maximum cumulative sum 1 of a sequence of independent random variables

More information

f (x) = k=0 f (0) = k=0 k=0 a k k(0) k 1 = a 1 a 1 = f (0). a k k(k 1)x k 2, k=2 a k k(k 1)(0) k 2 = 2a 2 a 2 = f (0) 2 a k k(k 1)(k 2)x k 3, k=3

f (x) = k=0 f (0) = k=0 k=0 a k k(0) k 1 = a 1 a 1 = f (0). a k k(k 1)x k 2, k=2 a k k(k 1)(0) k 2 = 2a 2 a 2 = f (0) 2 a k k(k 1)(k 2)x k 3, k=3 1 M 13-Lecture Contents: 1) Taylor Polynomials 2) Taylor Series Centered at x a 3) Applications of Taylor Polynomials Taylor Series The previous section served as motivation and gave some useful expansion.

More information

WORKSHEET FOR THE PUTNAM COMPETITION -REAL ANALYSIS- lim

WORKSHEET FOR THE PUTNAM COMPETITION -REAL ANALYSIS- lim WORKSHEET FOR THE PUTNAM COMPETITION -REAL ANALYSIS- INSTRUCTOR: CEZAR LUPU Problem Let < x < and x n+ = x n ( x n ), n =,, 3, Show that nx n = Putnam B3, 966 Question? Problem E 334 from the American

More information

Solutions of Math 53 Midterm Exam I

Solutions of Math 53 Midterm Exam I Solutions of Math 53 Midterm Exam I Problem 1: (1) [8 points] Draw a direction field for the given differential equation y 0 = t + y. (2) [8 points] Based on the direction field, determine the behavior

More information

Solutions for November. f(x + f(y)) = f(x) + y

Solutions for November. f(x + f(y)) = f(x) + y Solutions for November 647. Find all continuous functions f : R R such that for every x, y R. f(x + f(y)) = f(x) + y Solution 1. Setting (x, y) = (t, 0) yields f(t + f(0)) = f(t) for all real t. Setting

More information

Recitation 7: Existence Proofs and Mathematical Induction

Recitation 7: Existence Proofs and Mathematical Induction Math 299 Recitation 7: Existence Proofs and Mathematical Induction Existence proofs: To prove a statement of the form x S, P (x), we give either a constructive or a non-contructive proof. In a constructive

More information

A Note on Extended Gaussian Quadrature

A Note on Extended Gaussian Quadrature MATHEMATICS OF COMPUTATION, VOLUME 30, NUMBER 136 OCTOBER 1976, PAGES 812-817 A Note on Extended Gaussian Quadrature Rules By Giovanni Monegato* Abstract. Extended Gaussian quadrature rules of the type

More information

THE INVERSE FUNCTION THEOREM FOR LIPSCHITZ MAPS

THE INVERSE FUNCTION THEOREM FOR LIPSCHITZ MAPS THE INVERSE FUNCTION THEOREM FOR LIPSCHITZ MAPS RALPH HOWARD DEPARTMENT OF MATHEMATICS UNIVERSITY OF SOUTH CAROLINA COLUMBIA, S.C. 29208, USA HOWARD@MATH.SC.EDU Abstract. This is an edited version of a

More information

Solution: f( 1) = 3 1)

Solution: f( 1) = 3 1) Gateway Questions How to Evaluate Functions at a Value Using the Rules Identify the independent variable in the rule of function. Replace the independent variable with big parenthesis. Plug in the input

More information

THE MAXIMUM OF SUMS OF STABLE RANDOM VARIABLES

THE MAXIMUM OF SUMS OF STABLE RANDOM VARIABLES THE MAXIMUM OF SUMS OF STABLE RANDOM VARIABLES BY D. A. DARLING(') 1. Introduction. Let Xu X2, be identically distributed independent random variables and set Sn=Xi+ +X. In this paper we obtain the limiting

More information

MATH 118, LECTURES 27 & 28: TAYLOR SERIES

MATH 118, LECTURES 27 & 28: TAYLOR SERIES MATH 8, LECTURES 7 & 8: TAYLOR SERIES Taylor Series Suppose we know that the power series a n (x c) n converges on some interval c R < x < c + R to the function f(x). That is to say, we have f(x) = a 0

More information

Math 112 Rahman. Week Taylor Series Suppose the function f has the following power series:

Math 112 Rahman. Week Taylor Series Suppose the function f has the following power series: Math Rahman Week 0.8-0.0 Taylor Series Suppose the function f has the following power series: fx) c 0 + c x a) + c x a) + c 3 x a) 3 + c n x a) n. ) Can we figure out what the coefficients are? Yes, yes

More information

Study of some equivalence classes of primes

Study of some equivalence classes of primes Notes on Number Theory and Discrete Mathematics Print ISSN 3-532, Online ISSN 2367-8275 Vol 23, 27, No 2, 2 29 Study of some equivalence classes of primes Sadani Idir Department of Mathematics University

More information

AP Calculus Testbank (Chapter 9) (Mr. Surowski)

AP Calculus Testbank (Chapter 9) (Mr. Surowski) AP Calculus Testbank (Chapter 9) (Mr. Surowski) Part I. Multiple-Choice Questions n 1 1. The series will converge, provided that n 1+p + n + 1 (A) p > 1 (B) p > 2 (C) p >.5 (D) p 0 2. The series

More information

MATH 1301, Solutions to practice problems

MATH 1301, Solutions to practice problems MATH 1301, Solutions to practice problems 1. (a) (C) and (D); x = 7. In 3 years, Ann is x + 3 years old and years ago, when was x years old. We get the equation x + 3 = (x ) which is (D); (C) is obtained

More information

Math 118B Solutions. Charles Martin. March 6, d i (x i, y i ) + d i (y i, z i ) = d(x, y) + d(y, z). i=1

Math 118B Solutions. Charles Martin. March 6, d i (x i, y i ) + d i (y i, z i ) = d(x, y) + d(y, z). i=1 Math 8B Solutions Charles Martin March 6, Homework Problems. Let (X i, d i ), i n, be finitely many metric spaces. Construct a metric on the product space X = X X n. Proof. Denote points in X as x = (x,

More information

Section Taylor and Maclaurin Series

Section Taylor and Maclaurin Series Section.0 Taylor and Maclaurin Series Ruipeng Shen Feb 5 Taylor and Maclaurin Series Main Goal: How to find a power series representation for a smooth function us assume that a smooth function has a power

More information

Constructing Approximations to Functions

Constructing Approximations to Functions Constructing Approximations to Functions Given a function, f, if is often useful to it is often useful to approximate it by nicer functions. For example give a continuous function, f, it can be useful

More information

ADVANCED PROBLEMS AND SOLUTIONS

ADVANCED PROBLEMS AND SOLUTIONS Edited by Florian Luca Please send all communications concerning ADVANCED PROBLEMS AND SOLU- TIONS to FLORIAN LUCA, IMATE, UNAM, AP. POSTAL 61-3 (XANGARI),CP 58 089, MORELIA, MICHOACAN, MEXICO, or by e-mail

More information

SOLUTIONS FOR 2011 APMO PROBLEMS

SOLUTIONS FOR 2011 APMO PROBLEMS SOLUTIONS FOR 2011 APMO PROBLEMS Problem 1. Solution: Suppose all of the 3 numbers a 2 + b + c, b 2 + c + a and c 2 + a + b are perfect squares. Then from the fact that a 2 + b + c is a perfect square

More information

CALCULUS AB. SECTION I, Part A. Time minutes. Number of questions - 28 A CALCULATOR MAY NOT BE USED ON THIS PART OF THE EXAMINATION.

CALCULUS AB. SECTION I, Part A. Time minutes. Number of questions - 28 A CALCULATOR MAY NOT BE USED ON THIS PART OF THE EXAMINATION. E E S f CALCULUS AB SECTION I, Part A Time -- 55 minutes Number of questions - 28 Calculus AS ~.l Part A -J A CALCULATOR MAY NOT BE USED ON THIS PART OF THE EXAMINATION. Directions: Solve each of the following

More information

SOUTH AFRICAN TERTIARY MATHEMATICS OLYMPIAD

SOUTH AFRICAN TERTIARY MATHEMATICS OLYMPIAD SOUTH AFRICAN TERTIARY MATHEMATICS OLYMPIAD. Determine the following value: 7 August 6 Solutions π + π. Solution: Since π

More information

WORKSHEET FOR THE PUTNAM COMPETITION -REAL ANALYSIS- lim

WORKSHEET FOR THE PUTNAM COMPETITION -REAL ANALYSIS- lim WORKSHEET FOR THE PUTNAM COMPETITION -REAL ANALYSIS- INSTRUCTOR: CEZAR LUPU Problem Let < x < and x n+ = x n ( x n ), n =,, 3, Show that nx n = Putnam B3, 966 Question? Problem E 334 from the American

More information

STATISTICAL LIMIT POINTS

STATISTICAL LIMIT POINTS proceedings of the american mathematical society Volume 118, Number 4, August 1993 STATISTICAL LIMIT POINTS J. A. FRIDY (Communicated by Andrew M. Bruckner) Abstract. Following the concept of a statistically

More information

AN INEQUALITY OF TURAN TYPE FOR JACOBI POLYNOMIALS

AN INEQUALITY OF TURAN TYPE FOR JACOBI POLYNOMIALS PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 32, Number 2, April 1972 AN INEQUALITY OF TURAN TYPE FOR JACOBI POLYNOMIALS GEORGE GASPER Abstract. For Jacobi polynomials P^^Hx), a, ß> 1, let RAX)

More information

n=0 ( 1)n /(n + 1) converges, but not

n=0 ( 1)n /(n + 1) converges, but not Math 07H Topics for the third exam (and beyond) (Technically, everything covered on the first two exams plus...) Absolute convergence and alternating series A series a n converges absolutely if a n converges.

More information

ME3.6 Sheet 2 Answers

ME3.6 Sheet 2 Answers ME36 Sheet 2 Answers (i) We have dx/dt Ý6x 2xy Ý 8 fx,y,dy/dt y 2 Ý x 2 gx,y The critical points satisfy g y x and f Ý6x 2xy Ý 8 Substitute y x to get Ý6x 2x 2 Ý 8 x Ý 4x x 4 or Ý If instead we substitute

More information

Analysis II: Basic knowledge of real analysis: Part V, Power Series, Differentiation, and Taylor Series

Analysis II: Basic knowledge of real analysis: Part V, Power Series, Differentiation, and Taylor Series .... Analysis II: Basic knowledge of real analysis: Part V, Power Series, Differentiation, and Taylor Series Kenichi Maruno Department of Mathematics, The University of Texas - Pan American March 4, 20

More information

THE FIXED POINT PROPERTY FOR CONTINUA APPROXIMATED FROM WITHIN BY PEANO CONTINUA WITH THIS PROPERTY

THE FIXED POINT PROPERTY FOR CONTINUA APPROXIMATED FROM WITHIN BY PEANO CONTINUA WITH THIS PROPERTY PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 91, Number 3, July 1984 THE FIXED POINT PROPERTY FOR CONTINUA APPROXIMATED FROM WITHIN BY PEANO CONTINUA WITH THIS PROPERTY AKIRA TOMINAGA ABSTRACT.

More information

Definitions & Theorems

Definitions & Theorems Definitions & Theorems Math 147, Fall 2009 December 19, 2010 Contents 1 Logic 2 1.1 Sets.................................................. 2 1.2 The Peano axioms..........................................

More information

Math 2233 Homework Set 7

Math 2233 Homework Set 7 Math 33 Homework Set 7 1. Find the general solution to the following differential equations. If initial conditions are specified, also determine the solution satisfying those initial conditions. a y 4

More information

ON THE HURWITZ ZETA-FUNCTION

ON THE HURWITZ ZETA-FUNCTION ROCKY MOUNTAIN JOURNAL OF MATHEMATICS Volume 2, Number 1, Winter 1972 ON THE HURWITZ ZETA-FUNCTION BRUCE C. BERNDT 1. Introduction. Briggs and Chowla [2] and Hardy [3] calculated the coefficients of the

More information

ON A SINE POLYNOMIAL OF TURÁN

ON A SINE POLYNOMIAL OF TURÁN ROCKY MOUNTAIN JOURNAL OF MATHEMATICS Volume 48, Number 1, 18 ON A SINE POLYNOMIAL OF TURÁN HORST ALZER AND MAN KAM KWONG ABSTRACT. In 1935, Turán proved that ( n + a j ) S n,a() = sin(j) >, n j n, a N,

More information

LESSON 25: LAGRANGE MULTIPLIERS OCTOBER 30, 2017

LESSON 25: LAGRANGE MULTIPLIERS OCTOBER 30, 2017 LESSON 5: LAGRANGE MULTIPLIERS OCTOBER 30, 017 Lagrange multipliers is another method of finding minima and maxima of functions of more than one variable. In fact, many of the problems from the last homework

More information

EASY PUTNAM PROBLEMS

EASY PUTNAM PROBLEMS EASY PUTNAM PROBLEMS (Last updated: December 11, 2017) Remark. The problems in the Putnam Competition are usually very hard, but practically every session contains at least one problem very easy to solve

More information

International Mathematical Forum, Vol. 9, 2014, no. 36, HIKARI Ltd,

International Mathematical Forum, Vol. 9, 2014, no. 36, HIKARI Ltd, International Mathematical Forum, Vol. 9, 2014, no. 36, 1751-1756 HIKARI Ltd, www.m-hikari.com http://dx.doi.org/10.12988/imf.2014.411187 Generalized Filters S. Palaniammal Department of Mathematics Thiruvalluvar

More information

THE SOLUTION OF 3y2 ± 2" = x3

THE SOLUTION OF 3y2 ± 2 = x3 PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 69, Number, May 978 Abstract. THE SOLUTION OF y ± " = x The diophantine equation STANLEY RABINO WITZ (») y + "y = x, with y = ± is solved. Let 9

More information

Complex Variables. Chapter 1. Complex Numbers Section 1.2. Basic Algebraic Properties Proofs of Theorems. December 16, 2016

Complex Variables. Chapter 1. Complex Numbers Section 1.2. Basic Algebraic Properties Proofs of Theorems. December 16, 2016 Complex Variables Chapter 1. Complex Numbers Section 1.2. Basic Algebraic Properties Proofs of Theorems December 16, 2016 () Complex Variables December 16, 2016 1 / 12 Table of contents 1 Theorem 1.2.1

More information

EXISTENCE AND UNIQUENESS OF SOLUTIONS FOR THIRD ORDER NONLINEAR BOUNDARY VALUE PROBLEMS

EXISTENCE AND UNIQUENESS OF SOLUTIONS FOR THIRD ORDER NONLINEAR BOUNDARY VALUE PROBLEMS Tόhoku Math. J. 44 (1992), 545-555 EXISTENCE AND UNIQUENESS OF SOLUTIONS FOR THIRD ORDER NONLINEAR BOUNDARY VALUE PROBLEMS ZHAO WEILI (Received October 31, 1991, revised March 25, 1992) Abstract. In this

More information

Previous Year Questions & Detailed Solutions

Previous Year Questions & Detailed Solutions Previous Year Questions & Detailed Solutions. The rate of convergence in the Gauss-Seidal method is as fast as in Gauss Jacobi smethod ) thrice ) half-times ) twice 4) three by two times. In application

More information

Math 240 Calculus III

Math 240 Calculus III Line Math 114 Calculus III Summer 2013, Session II Monday, July 1, 2013 Agenda Line 1.,, and 2. Line vector Line Definition Let f : X R 3 R be a differentiable scalar function on a region of 3-dimensional

More information

1.1 Limits and Continuity. Precise definition of a limit and limit laws. Squeeze Theorem. Intermediate Value Theorem. Extreme Value Theorem.

1.1 Limits and Continuity. Precise definition of a limit and limit laws. Squeeze Theorem. Intermediate Value Theorem. Extreme Value Theorem. STATE EXAM MATHEMATICS Variant A ANSWERS AND SOLUTIONS 1 1.1 Limits and Continuity. Precise definition of a limit and limit laws. Squeeze Theorem. Intermediate Value Theorem. Extreme Value Theorem. Definition

More information

Taylor and Maclaurin Series. Approximating functions using Polynomials.

Taylor and Maclaurin Series. Approximating functions using Polynomials. Taylor and Maclaurin Series Approximating functions using Polynomials. Approximating f x = e x near x = 0 In order to approximate the function f x = e x near x = 0, we can use the tangent line (The Linear

More information

2 2 + x =

2 2 + x = Lecture 30: Power series A Power Series is a series of the form c n = c 0 + c 1 x + c x + c 3 x 3 +... where x is a variable, the c n s are constants called the coefficients of the series. n = 1 + x +

More information

w = X ^ = ^ ^, (i*i < ix

w = X ^ = ^ ^, (i*i < ix A SUMMATION FORMULA FOR POWER SERIES USING EULERIAN FRACTIONS* Xinghua Wang Math. Department, Zhejiang University, Hangzhou 310028, China Leetsch C. Hsu Math. Institute, Dalian University of Technology,

More information

Continuity. To handle complicated functions, particularly those for which we have a reasonable formula or formulas, we need a more precise definition.

Continuity. To handle complicated functions, particularly those for which we have a reasonable formula or formulas, we need a more precise definition. Continuity Intuitively, a function is continuous if its graph can be traced on paper in one motion without lifting the pencil from the paper. Thus the graph has no tears or holes. To handle complicated

More information

Later Faber2 established necessary and His theorem is the following: The latter condition is more restrictive than the former.

Later Faber2 established necessary and His theorem is the following: The latter condition is more restrictive than the former. VI11 FUNCTIONS HAVING ONLY ONE SINGULARITY 40. An important problem in the theory of Taylor's series is that of determining the conditions to be satisfied by the coefficients in order that the function

More information

SEPARATION AXIOMS FOR INTERVAL TOPOLOGIES

SEPARATION AXIOMS FOR INTERVAL TOPOLOGIES PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 79, Number 2, June 1980 SEPARATION AXIOMS FOR INTERVAL TOPOLOGIES MARCEL ERNE Abstract. In Theorem 1 of this note, results of Kogan [2], Kolibiar

More information

Calculus. Mathematics FRDIS. Mendel university in Brno

Calculus. Mathematics FRDIS. Mendel university in Brno Calculus Mathematics FRDIS Mendel university in Brno Podpořeno projektem Průřezová inovace studijních programů Lesnické a dřevařské fakulty MENDELU v Brně (LDF) s ohledem na discipĺıny společného základu

More information

MATH 131A: REAL ANALYSIS (BIG IDEAS)

MATH 131A: REAL ANALYSIS (BIG IDEAS) MATH 131A: REAL ANALYSIS (BIG IDEAS) Theorem 1 (The Triangle Inequality). For all x, y R we have x + y x + y. Proposition 2 (The Archimedean property). For each x R there exists an n N such that n > x.

More information

Math 0320 Final Exam Review

Math 0320 Final Exam Review Math 0320 Final Exam Review SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question. Factor out the GCF using the Distributive Property. 1) 6x 3 + 9x 1) Objective:

More information

Worksheet 9. Topics: Taylor series; using Taylor polynomials for approximate computations. Polar coordinates.

Worksheet 9. Topics: Taylor series; using Taylor polynomials for approximate computations. Polar coordinates. ATH 57H Spring 0 Worksheet 9 Topics: Taylor series; using Taylor polynomials for approximate computations. Polar coordinates.. Let f(x) = +x. Find f (00) (0) - the 00th derivative of f at point x = 0.

More information

Partial Derivatives Formulas. KristaKingMath.com

Partial Derivatives Formulas. KristaKingMath.com Partial Derivatives Formulas KristaKingMath.com Domain and range of a multivariable function A function f of two variables is a rule that assigns to each ordered pair of real numbers (x, y) in a set D

More information

WHAT STRONG MONOTONICITY CONDITION ON FOURIER COEFFICIENTS CAN MAKE THE RATIO \\f-sn(f)\\/en(f) BOUNDED? S. P. ZHOU. (Communicated by J.

WHAT STRONG MONOTONICITY CONDITION ON FOURIER COEFFICIENTS CAN MAKE THE RATIO \\f-sn(f)\\/en(f) BOUNDED? S. P. ZHOU. (Communicated by J. proceedings of the american mathematical society Volume 121, Number 3, July 1994 WHAT STRONG MONOTONICITY CONDITION ON FOURIER COEFFICIENTS CAN MAKE THE RATIO \\f-sn(f)\\/en(f) BOUNDED? S. P. ZHOU (Communicated

More information

n=1 ( 2 3 )n (a n ) converges by direct comparison to

n=1 ( 2 3 )n (a n ) converges by direct comparison to . (a) n = a n converges, so we know that a n =. Therefore, for n large enough we know that a n

More information

Quiz 1. Directions: Show all of your work and justify all of your answers.

Quiz 1. Directions: Show all of your work and justify all of your answers. Quiz 1 1. Let p and q be the following statements. p : Maxwell is a mathematics major. q : Maxwell is a chemistry major. (1) a. Write each of the following in symbolic form using logical connectives. i.

More information

(iii) E, / at < Eygj a-j tfand only if E,e; h < Ejey bj for any I, J c N.

(iii) E, / at < Eygj a-j tfand only if E,e; h < Ejey bj for any I, J c N. PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 118, Number 1, May 1993 A STRENGTHENING OF LETH AND MALITZ'S UNIQUENESS CONDITION FOR SEQUENCES M. A. KHAMSI AND J. E. NYMANN (Communicated by Andrew

More information

MAT 570 REAL ANALYSIS LECTURE NOTES. Contents. 1. Sets Functions Countability Axiom of choice Equivalence relations 9

MAT 570 REAL ANALYSIS LECTURE NOTES. Contents. 1. Sets Functions Countability Axiom of choice Equivalence relations 9 MAT 570 REAL ANALYSIS LECTURE NOTES PROFESSOR: JOHN QUIGG SEMESTER: FALL 204 Contents. Sets 2 2. Functions 5 3. Countability 7 4. Axiom of choice 8 5. Equivalence relations 9 6. Real numbers 9 7. Extended

More information

CRITERIA FOR ABSOLUTE CONVERGENCE OF FOURIER SERIES

CRITERIA FOR ABSOLUTE CONVERGENCE OF FOURIER SERIES PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 50, July 1975 CRITERIA FOR ABSOLUTE CONVERGENCE OF FOURIER SERIES NICOLAS ARTÉMIADIS ABSTRACT. Let / L!(T). Define fa by fa(x) = f(x + a). Then the

More information

Analysis Finite and Infinite Sets The Real Numbers The Cantor Set

Analysis Finite and Infinite Sets The Real Numbers The Cantor Set Analysis Finite and Infinite Sets Definition. An initial segment is {n N n n 0 }. Definition. A finite set can be put into one-to-one correspondence with an initial segment. The empty set is also considered

More information

MATH 217A HOMEWORK. P (A i A j ). First, the basis case. We make a union disjoint as follows: P (A B) = P (A) + P (A c B)

MATH 217A HOMEWORK. P (A i A j ). First, the basis case. We make a union disjoint as follows: P (A B) = P (A) + P (A c B) MATH 217A HOMEWOK EIN PEASE 1. (Chap. 1, Problem 2. (a Let (, Σ, P be a probability space and {A i, 1 i n} Σ, n 2. Prove that P A i n P (A i P (A i A j + P (A i A j A k... + ( 1 n 1 P A i n P (A i P (A

More information

On some shift invariant integral operators, univariate case

On some shift invariant integral operators, univariate case ANNALES POLONICI MATHEMATICI LXI.3 1995) On some shift invariant integral operators, univariate case by George A. Anastassiou Memphis, Tenn.) and Heinz H. Gonska Duisburg) Abstract. In recent papers the

More information

Levels of Ultrafilters with Extension Divisibilities

Levels of Ultrafilters with Extension Divisibilities arxiv:180704805v1 [mathgn] 12 Jul 2018 Levels of Ultrafilters with Extension Divisibilities Salahddeen Khalifa Department of Mathematics and Computer Sience University of Missouri- St Louis StLouis, MO

More information

Solutions to Problem Sheet for Week 8

Solutions to Problem Sheet for Week 8 THE UNIVERSITY OF SYDNEY SCHOOL OF MATHEMATICS AND STATISTICS Solutions to Problem Sheet for Wee 8 MATH1901: Differential Calculus (Advanced) Semester 1, 017 Web Page: sydney.edu.au/science/maths/u/ug/jm/math1901/

More information

Problem 1 HW3. Question 2. i) We first show that for a random variable X bounded in [0, 1], since x 2 apple x, wehave

Problem 1 HW3. Question 2. i) We first show that for a random variable X bounded in [0, 1], since x 2 apple x, wehave Next, we show that, for any x Ø, (x) Æ 3 x x HW3 Problem i) We first show that for a random variable X bounded in [, ], since x apple x, wehave Var[X] EX [EX] apple EX [EX] EX( EX) Since EX [, ], therefore,

More information

SMOOTHNESS OF FUNCTIONS GENERATED BY RIESZ PRODUCTS

SMOOTHNESS OF FUNCTIONS GENERATED BY RIESZ PRODUCTS SMOOTHNESS OF FUNCTIONS GENERATED BY RIESZ PRODUCTS PETER L. DUREN Riesz products are a useful apparatus for constructing singular functions with special properties. They have been an important source

More information

Sets. 1.2 Find the set of all x R satisfying > = > = > = - > 0 = [x- 3 (x -2)] > 0. = - (x 1) (x 2) (x 3) > 0. Test x = 0, 5

Sets. 1.2 Find the set of all x R satisfying > = > = > = - > 0 = [x- 3 (x -2)] > 0. = - (x 1) (x 2) (x 3) > 0. Test x = 0, 5 Sets 1.2 Find the set of all x R satisfying > > Test x 0, 5 > - > 0 [x- 3 (x -2)] > 0 - (x 1) (x 2) (x 3) > 0 At x0: y - (-1)(-2)(-3) 6 > 0 x < 1 At x5: y - (4)(3)(2) -24 < 0 2 < x < 3 Hence, {x R: x

More information

ON THE MAZUR-ULAM THEOREM AND THE ALEKSANDROV PROBLEM FOR UNIT DISTANCE PRESERVING MAPPINGS

ON THE MAZUR-ULAM THEOREM AND THE ALEKSANDROV PROBLEM FOR UNIT DISTANCE PRESERVING MAPPINGS PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 118, Number 3, July 1993 ON THE MAZUR-ULAM THEOREM AND THE ALEKSANDROV PROBLEM FOR UNIT DISTANCE PRESERVING MAPPINGS THEMISTOCLES M. RASSIAS AND

More information

GENERATING FUNCTIONS OF CENTRAL VALUES IN GENERALIZED PASCAL TRIANGLES. CLAUDIA SMITH and VERNER E. HOGGATT, JR.

GENERATING FUNCTIONS OF CENTRAL VALUES IN GENERALIZED PASCAL TRIANGLES. CLAUDIA SMITH and VERNER E. HOGGATT, JR. GENERATING FUNCTIONS OF CENTRAL VALUES CLAUDIA SMITH and VERNER E. HOGGATT, JR. San Jose State University, San Jose, CA 95. INTRODUCTION In this paper we shall examine the generating functions of the central

More information

AUTOMORPHISMS ON A C -ALGEBRA AND ISOMORPHISMS BETWEEN LIE JC -ALGEBRAS ASSOCIATED WITH A GENERALIZED ADDITIVE MAPPING

AUTOMORPHISMS ON A C -ALGEBRA AND ISOMORPHISMS BETWEEN LIE JC -ALGEBRAS ASSOCIATED WITH A GENERALIZED ADDITIVE MAPPING Houston Journal of Mathematics c 2007 University of Houston Volume, No., 2007 AUTOMORPHISMS ON A C -ALGEBRA AND ISOMORPHISMS BETWEEN LIE JC -ALGEBRAS ASSOCIATED WITH A GENERALIZED ADDITIVE MAPPING CHOONKIL

More information

CALCULUS JIA-MING (FRANK) LIOU

CALCULUS JIA-MING (FRANK) LIOU CALCULUS JIA-MING (FRANK) LIOU Abstract. Contents. Power Series.. Polynomials and Formal Power Series.2. Radius of Convergence 2.3. Derivative and Antiderivative of Power Series 4.4. Power Series Expansion

More information

DEPARTMENT OF MATHEMATICS AND STATISTICS UNIVERSITY OF MASSACHUSETTS. MATH 233 SOME SOLUTIONS TO EXAM 2 Fall 2018

DEPARTMENT OF MATHEMATICS AND STATISTICS UNIVERSITY OF MASSACHUSETTS. MATH 233 SOME SOLUTIONS TO EXAM 2 Fall 2018 DEPARTMENT OF MATHEMATICS AND STATISTICS UNIVERSITY OF MASSACHUSETTS MATH 233 SOME SOLUTIONS TO EXAM 2 Fall 208 Version A refers to the regular exam and Version B to the make-up. Version A. A particle

More information

Ternary Modified Collatz Sequences And Jacobsthal Numbers

Ternary Modified Collatz Sequences And Jacobsthal Numbers 1 47 6 11 Journal of Integer Sequences, Vol. 19 (016), Article 16.7.5 Ternary Modified Collatz Sequences And Jacobsthal Numbers Ji Young Choi Department of Mathematics Shippensburg University of Pennsylvania

More information

x.+ x. +,p,(n)x._,,<. O,n O, (1.1) x.+ x. + -,p,(n)x._,n 0,n 0, (1.2)

x.+ x. +,p,(n)x._,,<. O,n O, (1.1) x.+ x. + -,p,(n)x._,n 0,n 0, (1.2) Internat. J. Math. & Math. Sci. VOL. 19 NO. (1996) 171-176 171 COMPARISON AND OSCILLATION RESULTS FOR DELAY DIFFERENCE EQUATIONS WITH OSCILLATING COEFFICIENTS WEIPING YAN and JURANG YAN Department of Mathematics

More information

Preliminary Exam 2018 Solutions to Morning Exam

Preliminary Exam 2018 Solutions to Morning Exam Preliminary Exam 28 Solutions to Morning Exam Part I. Solve four of the following five problems. Problem. Consider the series n 2 (n log n) and n 2 (n(log n)2 ). Show that one converges and one diverges

More information

Convergence of sequences and series

Convergence of sequences and series Convergence of sequences and series A sequence f is a map from N the positive integers to a set. We often write the map outputs as f n rather than f(n). Often we just list the outputs in order and leave

More information

On Some Estimates of the Remainder in Taylor s Formula

On Some Estimates of the Remainder in Taylor s Formula Journal of Mathematical Analysis and Applications 263, 246 263 (2) doi:.6/jmaa.2.7622, available online at http://www.idealibrary.com on On Some Estimates of the Remainder in Taylor s Formula G. A. Anastassiou

More information