ANDHERI / BORIVALI / DADAR / CHEMBUR / THANE / NERUL / KHARGHAR / POWAI ANSWER KEY

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1 Medical Droppers (8 Aspirants) - Part Test - ANDHERI / ORIVALI / DADAR / CHEMUR / THANE / NERUL / KHARGHAR / POWAI FOR 8 ASPIRANTS Medical Droppers - Part Test - DATE: --8 ANSWER KEY PHYSICS CHEMISTRY OTANY ZOOLOGY. (4) 46. () 9. () 6. (). () 47. () 9. () 7. (). () 48. () 9. () 8. () 4. (4) 49. () 94. () 9. (4) 5. () 5. () 95. (4) 4. () 6. () 5. () 96. () 4. () 7. (4) 5. (4) 97. () 4. () 8. () 5. () 98. () 4. (4) 9. () 54. () 99. () 44. (). () 55. (). () 45. (). (4) 56. (4). () 46. (). () 57. (). () 47. (4). (4) 58. (). () 48. () 4. (4) 59. () 4. () 49. () 5. () 6. () 5. () 5. () 6. (4) 6. () 6. (4) 5. () 7. () 6. () 7. () 5. (4) 8. () 6. () 8. () 5. (4) 9. () 64. (4) 9. (4) 54. (). () 65. (). () 55. (). () 66. (). (4) 56. (). () 67. (). () 57. (). () 68. (). () 58. () 4. () 69. () 4. () 59. () 5. () 7. () 5. () 6. () 6. () 7. (4) 6. () 6. () 7. () 7. (4) 7. () 6. () 8. (4) 7. (4) 8. () 6. () 9. () 74. () 9. () 64. (). (4) 75. (). (4) 65. (4). () 76. (). () 66. (4). (4) 77. (). () 67. (). () 78. (). (4) 68 () 4. (4) 79. (4) 4. () 69. () 5. () 8. (4) 5. () 7. () 6. () 8. (4) 6. () 7. () 7. () 8. (4) 7. () 7. () 8. () 8. () 8. (4) 7. (4) 9. () 84. () 9. () 74. () 4. () 85. (). () 75. (4) 4. () 86. (). () 76 () 4. () 87. (). () 77 () 4. () 88. (). () 78. () 44. () 89. () 4. () 79. (4) 45. (4) 9. () 5. (4) 8. () DELHI & NCR / MUMAI / AKOLA / LUCKNOW / KOLKATA / NASHIK / GOA / NAGPUR / PUNE / DURGAPUR / DUAI

2 Medical Droppers (8 Aspirants) - Part Test -. (4) Fro triangular block b, C T N 5a... i N NA T mg or N mag T mg n T... ii SOLUTIONS PHYSICS From free body diagram of block A in frame of block, T 5a 5a... iii rel From free body diagram of block C in the frame of block N 5a... iv and C From Eqs. (i), (iii), (iv) and (v) T 5a 5a T a rel 5 T 5a... v T 5a 5a rel (from Eq. (iii)) 5a 5a rel a a rel 5 T 5a rel (from Eq.(v)) 5 a 5a 5 5al a m/s T N DELHI & NCR / MUMAI / AKOLA / LUCKNOW / KOLKATA / NASHIK / GOA / NAGPUR / PUNE / DURGAPUR / DUAI

3 a rel a 6 m/s N T N. () m g m m m a a 5m / s D C D T m a 5 5N C and D TCD N m g TlCD 5 Medical Droppers (8 Aspirants) - Part Test -. () The linear mass density of the rod at distance x is x m dm dx xdx.5 kg Thus, friction is f mg N k F a 5m / s m 4. (4) Concept If F mg, applied force F is balanced static friction. Thus, tension in string is zero. If F s smg, friction is limiting friction. Thus, F T fmax, T F smg. 5. () F 9 () Common acceleration (a ) m / s m mlb A Free body diagram of block A in the frame of block is shown below, (f s) max sn.5 5 N Also, maa N m a f A S max between A and. f maa N, the blocks will move forward with common acceleration and static friction exists 6 () a 5.m / s 6 ma a 5. N (maal) (f s) max, there will be relative between the blocks and kinetic friction acts between A and. DELHI & NCR / MUMAI / AKOLA / LUCKNOW / KOLKATA / NASHIK / GOA / NAGPUR / PUNE / DURGAPUR / DUAI

4 Free body diagram of block is shown, Ffk ma Or k F N m a... i Also, N m g... ii a From, Eqs. (i) and (ii), we get F kmag a m 6.4 or a 6 m / s free body diagram of A in the frame of ground. f m a or k A A a f k A ma F m g m 4m / s k A (4) a... i Also, f kmag maaa Or A k a g... ii Combining Eqs. (i) and (ii), F kmag Consider, a a A kg mb Hence, a aa for F gm m Or F gm m k A 6. () 7. (4) 8. () 9. (). (). (4). (). () 4. (4) 5. () 6. (4) 7. () 8. () Torque = I o = f = = 4; o 4 4 t 5 4 Nm k A Medical Droppers (8 Aspirants) - Part Test - DELHI & NCR / MUMAI / AKOLA / LUCKNOW / KOLKATA / NASHIK / GOA / NAGPUR / PUNE / DURGAPUR / DUAI 4

5 9. () Medical Droppers (8 Aspirants) - Part Test -. () I CM KRot f K Tot MVCM ICM For a solid sphere, I MR ICM MR MVCM According to given problem mv as v s MVCM f 5 5 MV 7 CM MVCM 5 5 a m v as So a R R mr (i) dv dv ds dv Further more as at v (ii) dt ds dt ds (y chain rule) a Which in light of equation (i) i.e. v s yields m a a as at s m m m So that as as R t a a a mr m as Hence a [ s / R] m F ma as [ s / R] (iii). () When driver applies brakes and the car covers distance x before coming to rest, under the effect of retarding force F then mv Fx mv x F ut when he takes turn then It is clear that x r/ mv r F mv r F i.e. by the same retarding force the car can be stopped in a less distance if the driver apply breaks. This retarding force is actually a friction force.. () g g T m ( g a) g g g T m ( g a) g T T DELHI & NCR / MUMAI / AKOLA / LUCKNOW / KOLKATA / NASHIK / GOA / NAGPUR / PUNE / DURGAPUR / DUAI 5

6 . () We know that in the given condition s s m m m s s m 4. () For exerted by ball on wall 5. () = rate of change in momentum of ball = F 6. () dp dt Ft mv dm v dt v mv F t a F M v M s m mv ( mv) mv t t Medical Droppers (8 Aspirants) - Part Test - y doing so time of change in momentum increases and impulsive force on knees decreases. 7. () 8. (4) T T [ ( v / c )] / y substituting 8 v.6 ms Force acting on plate, T day and T F dp dt dm v dt days we get dm Mass of water reaching the plate per sec = dt V Av A( v v) ( v v) v ( v v v velocity of water coming out of jet w.r.t. plate) ( A Area of cross section of jet V ) v dm V V F v ( v v) ( v v) ( v v) dt v v 9. () When particle moves away from the origin then at position x x force is zero and at x x, force is positive (repulsive in nature) so particle moves further and does not return back to original position. i.e. the equilibrium is not stable. Similarly at position x x force is zero and at x x, force is negative (attractive in nature) So particle return back to original position i.e. the equilibrium is stable.. (4) Work done = change in kinetic energy. () W mv W v dv P P Fv mav m v dt v dv dt m graph will be parabolic in nature DELHI & NCR / MUMAI / AKOLA / LUCKNOW / KOLKATA / NASHIK / GOA / NAGPUR / PUNE / DURGAPUR / DUAI 6

m M) M m 5. () Path of C. M. Will be followed 6. () For an isolated system external force on the body is zero m v M m d F M v cm v cm constant. dt 7.

7 Medical Droppers (8 Aspirants) - Part Test - / P v P t v ( t) / m m P m Now s v dt. (4) / / t / dt / P t / s s t m W. () 4. (4) MgL MgL n () MgL 8 (n = given) Initial momentum = mv Final momentum = ( m M ) V y conservation of momentum Velocity of (bag + bullet) system Kinetic energy = ( M) V mv ( m M ) V mv V M m mv m = ( m M) M m 5. () Path of C. M. Will be followed 6. () For an isolated system external force on the body is zero m v M m d F M v cm v cm constant. dt 7. () If the man starts walking on the trolley in the forward direction then whole system will move in backward direction with same momentum. 8. () Momentum of man in forward direction = Momentum of system (man + trolley) in backward direction 8 (8 ) v v. m / s So the velocity of man w.r.t. ground v gr v r gr r and a g...8 m / s DELHI & NCR / MUMAI / AKOLA / LUCKNOW / KOLKATA / NASHIK / GOA / NAGPUR / PUNE / DURGAPUR / DUAI 7

8 9. () 4. () 4. () Time of descent moment of inertia k.4, R sphere k.5, R disc k R k R ring t sphere t disc t ring. Medical Droppers (8 Aspirants) - Part Test - 4. () Speed of the bottommost point is zero but acceleration is not zero. Friction force may be there if it is an accelerated motion but work done by friction is always zero. 4. () 44. () 45. (4) CHEMISTRY 8RT RT AV rms 8 uav O u N 46. () u O ; u N rms 47. () w = g; V = litre, T = 98 K using w PV RT (for CO ) m P P.atm CO Pin bottle PCO atm.pressure..atm 48. () The mole diffused per unit area in first case The mole diffused per unit area in second case r a t r r t a r Thus, t t r. r, 49. () P' = mole fraction PM The gas having higher mole fraction has high partial pressure.\ 5. () The volume of the balloon = 4 485ml 7 4 r DELHI & NCR / MUMAI / AKOLA / LUCKNOW / KOLKATA / NASHIK / GOA / NAGPUR / PUNE / DURGAPUR / DUAI 8

9 Volume of the cylinder = 8 ml Volume of H at NTP = 8 7 ml = 54 ml After filling the cylinder will have H equal to its volume = 8 ml Volume of H for filling balloons = 54-8 = 4854 ml Hence no. of balloon to be filled = () At P atm, V.4L;T 7K P atm,v?;t 7K V T V T.4 7 V 7 V.6 L Medical Droppers (8 Aspirants) - Part Test - 5. (4) w PV RT; M If other factors are same, V m 5. () For 5 moles of gas at temperature T, PV =5RT For 5 moles of gas at temperature T, PV =5R(T ) P(V V )=5RT(T T); PV R PV R When V is negative, W is +ve. RT 54. () RT c / Pc Vc 8 / 8 / 8 / PV 55. () Gaseous product if formed; more positive is n, more is entropy. H U 56. (4) C P; CV T P T V Also, U / VT for ideal gas = 57. () G H TS; at equilibrium, G, H T S or H J mol 58. () r PV = constant P V dv V dp DELHI & NCR / MUMAI / AKOLA / LUCKNOW / KOLKATA / NASHIK / GOA / NAGPUR / PUNE / DURGAPUR / DUAI 9

10 Medical Droppers (8 Aspirants) - Part Test - r dp V dv dv P V V 59. () Work done by gas = Pext. changein volume litre-atm 6. J 67.9 J o 6. () No doubt () and () both represent heat of formations but standard heat of formation H 6. () CO will be form C O graphite CO as C graphite is most stable form of carbon. o H Zero in most stable form of element. o o H H Cl g r l 6. () Hsolution Hi Hh or = 8 + Hh H 79 kcal mol h, The total 6a 5a H H H a h h h Na Cl where a is total heat of hydration H h 679 Thus, Hh 97.6kcal mol Na 6. () l l 64. (4) H O H aq OH aq ; H 57. kj H / O H O ; H 86. kj H / O H OH ; H 8.88kJ Also / H H ; H / H / O OH ; H 8.88kJ H H 9.5 kj f for H H kJ mol The obs. H H Energy needed to disturb resonance = = 8. kj mol 65. () CH4 O CO HO; H x C H OH O C O H O; H y DELHI & NCR / MUMAI / AKOLA / LUCKNOW / KOLKATA / NASHIK / GOA / NAGPUR / PUNE / DURGAPUR / DUAI

11 CH4 O CHOH; H y x y x ve x y Medical Droppers (8 Aspirants) - Part Test () Volume of ice > volume of water and thus, increase in pressure favours forward reaction showing decrease in volume. 67. () In K H T T K R TT K increase with T or decreases with T it is decided by H. Here, K decrease with T. Thus, H ve At the initial stage if only reactants are taken Q =, but it goes increasing with time to become equal to K. 68. () N H NH x x x c 5% mixture reacts 4 x x x =.5 P Pr m f of NH NH P.5 P 4.5 PCl g PCl g Cl g ; K PCl Cl 69. () 5 P p p p PCl5 CO Cl COCl g CO g Cl g ; K P p p p PCl5 If CO is introduced, the dissociation of COCl will decrease and p Cl will decrease. This will favour dissociation of PCl 5, because both reactions are attained in same vessel. 7. () c NO N O N O NO K 4 K C / / 4 K 5 C 4 Kc 4 7. (4) NH HS(s) NH g H Sg 4 t.5 teq..5p P DELHI & NCR / MUMAI / AKOLA / LUCKNOW / KOLKATA / NASHIK / GOA / NAGPUR / PUNE / DURGAPUR / DUAI

12 PT.5 P P.84 P.7 atm K P P P NH H S =. atm Medical Droppers (8 Aspirants) - Part Test - 7. (4) HCO H HCO HCO H CO 7. (4) Ionic product for M OH Thus, only (weak dissociation) 6.V V. V V 8 Fe OH will be precipitated. Also for AgOH, the product of ionic concentration is. 6 lesser than K sp. 74. () ph pk log a Conjugate base Acid ph pka log ( 5% neutralization) 4 log H log or H () The reaction shows lower K eq. value o=in forward direction, i.e., more direction or HCN decomposes salt of HNO. 76. () meq. of I HCl = meq of II HCl V V litre volume of water added = ( ) = 9 L 77. () Rate K Ester H For strong acid H M For weak acid H K a.c Rate H for strong acid Rate H for weak acid (C = M for weak acid) / K Ka 4 M a K eq. in backward 78. () Carbon has negative oxidation no. in MgC and positive oxidation umber in CO ;O is more electronegative than C. Mg is more electropositive than C. DELHI & NCR / MUMAI / AKOLA / LUCKNOW / KOLKATA / NASHIK / GOA / NAGPUR / PUNE / DURGAPUR / DUAI

13 Medical Droppers (8 Aspirants) - Part Test (4) The same species in each reaction is oxidized and reduced as will to give disproportionation reaction. 8. (4) Addition of KI to CuSO 4 makes it dark brown. 8. (4) 8. (4) S S 8e 6 7 Mn 5e Mn 4 Fe C O4 Fe C O e 5 8. () SO HO SO H; Cl HO HCl O 84. () 4 S S 6e Eq. = mole () N 6e N H H 6e E N 8 ; E 7 NH () oth are correct 87. () Explanation is correct reason for statement. 88. () Q Kc forward reaction Q K c backward reaction 89. () Q K c if G Kw at o 6 C ph 6.5 ; but water is neutral because ph scale contracts to to. 9. () oth statement and explanation are correct but explanation is not reason for statement. 9. () 9. () 9. () 94. () 95. (4) 96. () 97. () 98. () 99. (). (). (). () O\TANY DELHI & NCR / MUMAI / AKOLA / LUCKNOW / KOLKATA / NASHIK / GOA / NAGPUR / PUNE / DURGAPUR / DUAI

14 Medical Droppers (8 Aspirants) - Part Test -. () 4. () 5. () 6. (4) 7. () 8. () 9. (4). (). (4). (). () 4. () 5. () 6. () 7. () 8. () 9. (). (4). (). (). (4) 4. () 5. () 6. () 7. () 8. (4) Sol: Salvinia is an aquaticheterosporouspteridophyte 9. (). (). (). (). () 4. () 5. (4) DELHI & NCR / MUMAI / AKOLA / LUCKNOW / KOLKATA / NASHIK / GOA / NAGPUR / PUNE / DURGAPUR / DUAI 4

NARAYANA I I T / P M T A C A D E M Y. C o m m o n P r a c t i c e T e s t 05 XII-IC SPARK Date:

1. (A). (C). (B). (B) 5. (A) 6. (B) 7. (B) 8. (A) 9. (A) 1. (D) 11. (C) 1. (B) 1. (A) 1. (D) 15. (B) NARAYANA I I T / P M T A C A D E M Y C o m m o n P r a c t i c e T e s t 5 XII-IC SPARK Date: 9.1.17