What is the Euler characteristic of moduli space? Compactified moduli space? The Gauss-Bonnet theorem for cone manifolds and volumes of moduli spaces
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1 The Gauss-Bonnet theorem for cone manifolds and volumes of moduli spaces Illustration F Curtis McMullen Kappes--Möller (2012) Thurston (199) Allendoerfer--Weil (1943) Schwarz, Picard, Deligne--Mostow, Cohen--Wolfart, Parker, Sauter,... What is the Euler characteristic of moduli space? M 0,n = {(b 1,...,b n ) 2 b C n Fibration ( 0,n 1 )= (n 3) 0,n 1! M 0,n : b i 6= b j }/ Aut b C M 0,n 1 (M 0,n )=( 1) n+1 (n 3)! Theorem M 0,n 6= CH n 3 / for n>4. manifold Γ Γ Figure 6. A holomorphic map from an ideal pentagon to an ideal star. Avg Holomorphic of F 2 in the Galois hyperbolic conjugation metric? Answer: 1/3 Curves on surfaces. Let f : V MF 2 be a Teichmüller /2 curve generated by (X, ω 2 ). Assume that SL(X, ω) hasrealquadratictracefieldk R. Let k k denote the Galois involution1-1 of K/Q, sendinga + b d to a b d, 2 2 and let g g denote the corresponding involution SL 2 (K). orbifold cone manifold We have seen that Jac(X t ), t = f(t), admits real multiplication by K for all t. Let -1+1/2+1/ Σ = H/Γ, = -3/10 Γ SL 2 (K), be the -1+1/2+2/ Hilbert modular = -1/10 surface parameterizing all Abelian varieties with the given action of K, asin 6. Then we obtain a commutative diagram H V f M 2 σ n (M 0,n ) Compactified moduli space? H 2 Σ A (10.1) as in Corollary.3. If we make a change of basepoint for V,byreplacing(X, ω)witha (X, ω), (M 0,n ) A SL 2 (R), then f(v ) M 2 does not change and GL(X, ω) variesonlyby conjugation by A. Themainobservationofthissectionis: Theorem 10.1 After a suitable change of basepoint, we have GL(X, ω) GL 2 (K) and Example: σ(t) =(t, n= F (t)), wheref : H H satisfies F (g t) =g F (t) (P 1 P 1 P P 0 )= = 2 34 (P 1 P 1 +3P 1 3P 0 )=4+6 3=
2 Generating functions Corollary 2 (Getzler) The generating functions f(x) =x n=2 χ(m 0,n+1 ) xn n! are formal inverses of one another. and g(x) =x + Universal; via stable trees (M, L Ens. math.) n=2 χ(m 0,n+1 ) xn n! Moduli spaces of polyhedra... Fix µ 1,...,µ n, 0 <µ i < 1, P µ i = 2. Any (b i ) determines a meromorphic 1-form on b C:! = dx Q n 1 (x b i) µ i (!) = X µ i b i divisor of degree 2 ( b C,! ) = convex polyhedron in R 3 Cone angles 2 (1 µ i ). Example: n=12, μi = 1/6 n=4 n=... are complex hyperbolic after all Example: μ = (,,,,)/1 M 0,n (µ) = moduli space of cone metrics on S 2 with given angles M 0,! M g, g = 2 X : y 1 =(x b 1 ) (x b 4 ) Theorem: M 0,n (µ) is naturally a complex hyperbolic manifold Z/1 acts on H 1 (X) [!] =[dx/y ] 2 H 1 (X) q (locally CH n 3, via periods of!) /1 q = 1 Schwarz, Picard, Deligne-Mostow, Thurston, 196 Math Olympiad (b i )! (positive line in C 1,2 ) = CH 2 Also get rep of braid group B4 U(1,2) (Burau)
3 What is the volume of moduli space? Theorem 1.2 The complex hyperbolic volume of moduli space satisfies vol(m 0,n,g µ )=C n 3 ( 1) P +1 ( P 3)! ( max 0, 1 ) B 1 µ i. B P i B P P { } P: partitions of {1,...,n} into blocks B. special cases (different methods): Parker, Sauter Cone manifolds Example: Glue together spherical polyhedra along faces in pairs. Thurston: The metric completion M 0,n (µ) is a CH n 3 cone manifold. Gauss-Bonnet (M): Acompactcone manifoldofdimensionn satisfies Ψ(x) dv(x) = χ(m σ )Θ σ. M[n] σ = Proof of volume formula GB Volume = 14 ( 1) P +1 ( P 3)! ( max 0, 1 ) B 1 µ i. B P i B P χ(m σ )Θ σ. σ { } (+,,,) contributes a stratum M0,4. no stratum unless P B µ i < 1. Proof of cone GB uses polyhedral GB... Theorem 2.1 (Allendoerfer Weil) The Euler characteristic of a compact Riemannian polyhedron M of dimension n satisfies n 1 ( 1) n χ (M) = Ψ(x) dv(x) + M[n] Riemann curvature tensor by Ψ(x) = 2 ω n bundle to A defined by Ψ(x, ξ) = Ψ r,f (x, ξ) = 1 2 n/2 n! 0 2f r Ψ r,f (x, ξ), 2 ω 2f ω n 2f 1 r=0 ɛ(i)ɛ(j) g i,j S n M[r] where 1 2 f (2f)!(r 2f)! dv(x) Ψ(x, ξ) dξ. N(x) R i1i 2j 1j 2 R in 1i nj n 1j n. intrinsic K ɛ(i)ɛ(j) γ i,j S r R i1i 2j 1j 2 R i2f 1 i 2f j 2f 1 j 2f Λ i2f+1 j 2f+1 (ξ) Λ irj r (ξ). extrinsic K 1943
4 ...which in turns comes from Weyl s tube formula T[r] M[r] Example: μ = (,,,,)/1 16 Galois (continued) M[n] /1 q = 1 /1 q = 1 Figure 1. The tube around a polyhedron in R N+1. Non-arithmetic lattices (DM) (1-14)/36 = 1/9 M 0,n (µ) orbifold = CH 2 / ( discrete) = ( 0 dense) in U(1, 2). (1-10)/36 = 2/9 M 0,n M 0,n (µ 0 ) cone manifold holonomy 0 Invariants Kappes-Möller The volume ratios (µ, µ 0 )= vol(m 0,n(µ 0 )) vol(m 0,n (µ)) are the same for all subgroups of finite index in Γ. The 16 nonarithmetic lattices arising from moduli spaces fall into 9 commensurability classes. Γ is a nonarithmetic lattice
5 Volume ratios: examples q q (p i ) {ρ(µ, ν)} / / / / /16 1 1/ /33, 4/ /33, 4/ / / / / /3, 4/ /3, 4/ /61, 4/ /61, 4/61 (p i) χ(p (µ)) χ(m(µ)) /9-1/ /3 1/ /64-1/ /12 / /16-1/ /4-1/ /16 1/ / 1/ / 1/ / / / / /3-1/ /434-41/ /32 / / / /1296-1/ /6 63/ /64-13/ /216-11/ / / /1296 1/ / / /10-13/ /10 / /64 / /4-1/ /2-1/ /432 / /4-1/ /4 -/ /9-1/ /12 1/ /24 1/ /9-1/ /2 -/ /12 1/ /6 1/ /6 1/ /1 -/ /12 1/ /4 1/ /3 1/ /2 1/ /12-11/ /64 3/ /32 3/ /16 3/12 Table 3. Euler characteristics of the 94 orbifolds M(µ) and their cone manifold covers P (µ), with(µ i)=(p i/q). 94 orbifolds q (p i) χ(p (µ)) χ(m(µ)) /2 13/ /20 1/ / / /12-13/ /100 1/ /10 3/ /0-1/ /2 1/ /100 13/ /4 / / / /432-23/ /216-23/ /4 1/ / 1/ /4 / /6 1/ /24 / /144-31/ /2-23/ /12 1/ /4 13/ /24 / /4 1/ /2 1/ /24 11/ /24 13/ /12 / /49 1/ /49 1/ / 3/ /10 13/ /2 2/ /4 13/ /10 13/ /2 13/ /2 2/ /400 33/ /200 23/ /200 99/ /96 11/ /24 11/ / 2/ /300 3/ / / / 61/ /14 61/2 Table 3. (continued) Coda: nonarithmetic Fuchsian groups μ = (3,3,,)/10 μ = (1,1,9,9)/10 CH 1 CH 1 F Γ Γ Figure 6. A holomorphic map fromb3 an ideal pentagon to an ideal star. /2 T0,4 ρ=1/3 Curves on 2 surfaces. Let f : V M 2 be a Teichmüller 2 curve generated by (X, ω 2 ). Assume that SL(X, ω) hasrealquadratictracefieldk R. Let k k denote the Galois involution of K/Q, sendinga + b d to a b d, and let g g denote the corresponding involution on SL 2 (K).
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