Old Math 120 Exams. David M. McClendon. Department of Mathematics Ferris State University
|
|
- Simon Harrell
- 5 years ago
- Views:
Transcription
1 Old Math 10 Exams David M. McClendon Department of Mathematics Ferris State University 1
2 Contents Contents Contents 1 General comments on these exams 3 Exams from Fall Fall 016 Exam Fall 016 Exam Fall 016 Exam Fall 016 Final Exam Exams from Fall Fall 017 Exam Fall 017 Exam Fall 017 Exam Fall 017 Final Exam
3 Chapter 1 General comments on these exams These are the exams I have given in a Math 10 (trigonometry) course at Ferris State University in Fall 016 and Fall 017. Each exam has two sections: on the first section, calculators are not allowed and exact answers must be given, but on the second section, calculators are permitted and decimal approximations are acceptable. Each exam, other than the Fall 017 final exam, is followed by solutions (there may be minor errors in the solutions). These exams correspond to the material in my lecture notes and the 7 th edition of the McKeague textbook as follows: Exam 1: chapters 1 & of my lecture notes / sections A.1, , 3., of the McKeague text Exam : chapter 3 of my lecture notes / sections ,.1-.4, 3.1, 3.3, of the McKeague text Exam 3: chapters 4 & 5 of my lecture notes / sections , of the McKeague text Final Exam: chapters 1-7 of my lecture notes / chapters 1-5 and 7 of the McKeague text 3
4 Chapter Exams from Fall Fall 016 Exam 1 No calculator allowed on these problems 1. Convert the following angles from radians to degrees, and draw them in standard position: a) 5π 6 b) π c) 8π 3 d) 4π 4. Let cat be the function defined by cat x = x + 1. Compute each quantity: a) cat + 3 b) cat 3 c) cat() + 3 d) cat 3 Calculators allowed on the rest of the exam 3. Parts (a), (b), (c) and (d) of this question are not related to one another. a) Find an angle measuring between 0 and 360 which is coterminal with b) Convert to radians (write your answer as a decimal, rounded to two or more decimal places). c) Find the coordinates of a point on the unit circle which is on the terminal side of a 540 angle, drawn in standard position. d) Draw a picture of a triangle which is isoceles, but not equilateral. 4. Parts (a), (b), and (c) of this question are not related to one another. a) Find the distance between the points (, 8) and (5, 3) (write your answer either as an exact answer or as a decimal, rounded to two or more decimal places). 4
5 .1. Fall 016 Exam 1 b) An angle measures 18 more than its complement. What is the measure of the angle? c) The three angles of a triangle measure x, x + 5 and x 40. Is this triangle an acute triangle, a right triangle, or an obtuse triangle? 5. Parts (a) and (b) of this question are not related to one another. a) A Ferris wheel makes.065 revolutions in a minute. If the radius of the Ferris wheel is 10 feet, what is the linear velocity of someone sitting in a bucket on the edge of the Ferris wheel? b) Find the measure of each angle in this picture: 3x - 3 8x In each picture, find x: 83 5 a) x b) (in this picture, assume the horizontal lines are parallel) 3x - 3 x + 46 x 150 x c) 15 5
6 .1. Fall 016 Exam 1 Exam 1 Solutions 1. a) 5π 6 = 5 π 6 = 5 30 = 150. In standard position, this angle should point just north of the negative x-axis. b) π = 90. In standard position, this angle points due north. c) 8π 3 = 8 π 3 = 8 60 = 480. In standard position, this angle goes all the way around once, then halfway around again to end up on the negative x-axis. d) 4π 4 = π = 180. In standard position, this angle is on the negative x-axis.. a) cat + 3 = cat() + 3 = ( + 1) + 3 = = 8. b) cat 3 = cat 6 = = 37. c) cat() + 3 = ( + 1) + 3 = = 8. d) cat 3 = (3 + 1) = (10) = a) = 1.15 so the angle is = 55. b) π 180 = 3.87 radians. c) 540 = so the terminal side of this angle points on the negative x-axis. The point on the negative x-axis which is on the unit circle is ( 1, 0). d) The triangle should have two sides that are the same length, but not all three sides of the same length. 4. a) D = (x x 1 ) + (y y 1 ) = (5 ) + ( 3 8) = 3 + ( 11) = = b) Let x be the angle; we have x = 18 +(90 x). Solve for x to get x = 54. c) The three angles sum to 180, so x + (x + 5 ) + (x 40 ) = 180. Solve for x to get x = 65. This makes the three angles x = 65, x + 5 = 90 and x 40 = 5. Since one of the angles is 90, the triangle is a right triangle. 5. a) The angular velocity is ω =.065 π =.408 radians per minute. The linear velocity is therefore v = rω = 10(.408) 49 feet per minute. b) The angles are supplementary, so (3x 3 ) + (8x + 38 ) = 180. Solve for x to get x = 15 ; the angles are therefore 3(15 ) 3 = and 8(15 ) + 38 = a) The angles sum to 180 : x = 180. Solve for x to get x = 45. b) The angles are equal, so 3x 3 = x Solve for x to get x = 39. 6
7 .1. Fall 016 Exam 1 c) This shape has five sides, so its angles must add to 180 (5 ) = 540. Therefore x + x = 540. Solve for x to get x =
8 .. Fall 016 Exam. Fall 016 Exam No calculator allowed on these problems 1. Throughout this problem, assume sin θ = 3. a) What is sin( θ)? b) If cos θ > 0, find cos θ. c) If cos θ > 0, what quadrant is θ in? d) What is sin(θ )? e) (Bonus) What is sin(θ )?. Find the exact value of each quantity: a) sin 45 b) cos 10 c) sin 180 d) cos 300 e) sin Find the exact value of each quantity: f) cos( 30 ) a) sin 5π 6 b) sin 8π c) sin 3π 4 d) cos 10π 3 e) sin π f) cos 7π Calculator allowed on the rest of the exam 4. Find cos θ, if θ is as in the following picture: θ Suppose sin θ =.55. Find all possible values of cos θ. 6. a) Find all angles θ between 0 and 360 such that sin θ =.3. b) Find all angles θ between 0 and 360 such that sin θ = 1.3. c) Find all angles θ between 0 and 360 such that cos θ =.75. d) Find all angles θ between 0 and 360 such that cos θ = Find the area of each indicated triangle: 8
9 .. Fall 016 Exam a) b) 7 8. Solve triangle ABC, given the information in the picture below: A B C 9. Solve triangle GHI if g = 17, h = 5 and I = Solve triangle ABC if a = 17, b = 10 and B = A person wants to measure the height of a flagpole. She walks 50 feet away from the base of the flagpole, turns around and notices that her angle of elevation to the top of the pole is 48. If her eyes are 5 feet above the ground, how tall is the flagpole? 9
10 .. Fall 016 Exam Exam Solutions 1. a) sin( θ) = sin θ = 3. b) Start with the Pythagorean identity: cos θ + sin θ = 1 ( ) cos θ + = 1 3 cos θ = 1 cos θ = 5 9 cos θ = ± 5 9. Since we are told cos θ > 0, cos θ = 5 9 = 5 3. c) Since sin θ < 0 and cos θ > 0, θ must be in Quadrant IV. d) sin(θ ) = sin θ = 3. e) θ is in Quadrant II, but has the same reference angle as θ, so sin(θ ) = 3.. a) sin 45 =. b) cos 10 = 1 (Quadrant II; reference angle 60 ) c) sin 180 = 0 (point on unit circle is ( 1, 0)) d) cos 300 = 1 (Quadrant IV; reference angle 60 ) e) sin 570 = sin 10 = 1 (Quadrant II; reference angle 30 ) f) cos( 30 ) = cos 30 = 3 3. a) sin 5π 6 = sin 150 = 1 (Quadrant II; reference angle 30 ) b) sin 8π = sin 0 = 0 c) sin 3π = sin( 135 ) = (Quadrant III; reference angle 45 ) 4 d) cos 10π = cos 4π = cos = 1 (Quadrant III; reference angle 60 ) e) sin π = sin 90 = 1 (point on unit circle is (0, 1)) f) cos 7π = cos 7π = cos 70 = 0 (point on unit circle is (0, 1)) 4. First, use the Pythagorean Theorem to find the adjacent side, which I ll call a: a + 7 = 19 a = 19 7 = Then cos θ = adjacent adjacent =
11 .. Fall 016 Exam 5. Start with the Pythagorean identity: cos θ + sin θ = 1 cos θ + (.55) = 1 cos θ = 1 cos θ =.6975 cos θ = ±.6975 ± a) From a calculator, θ = sin 1 (.3) A second angle which solves the equation is 180 θ b) There are no such angles (because 1.3 > 1). c) From a calculator, θ = cos 1 (.75) A second angle which solves the equation is 360 θ = d) The only such angle is θ = 0 (if you also included θ = 360, that s okay, but 360 is really the same angle as 0 ). 7. a) By the SAS Area Formula, A = 1 ab sin C = 1 (9.)(1.5) sin sq units. b) Use Heron s Formula (so first, find the semiperimeter): s = a + b + c = = 1. Then the area is A = s(s a)(s b)(s c) = 1(1 7)(1 15)(1 0) = 1(14)(6)(1) = First, the third angle is A = 90 5 = 65. = 4 sq units. Second, find the hypotenuse c using a trig function (either sine or cosine): sin 5 = 4.3 c.46 = 4.3 c.46c = 4.3 c = =
12 .. Fall 016 Exam Last, find the remaining side using the Pythagorean Theorem: a + b = c a + (4.3) = (10.175) a = (10.175) (4.3) = The given information is SAS, so start with the Law of Cosines to find side i: i = g + h gh cos I i = (17)(5) cos 6 i = (.4695) i = i = Now use the Law of Sines (or the Law of Cosines) again to find G (you could find H first instead): sin G = sin I g i sin G sin 6 = sin G 17 = sin G = 17(.889) = G = sin 1 (.6615) = Last, find H: H = = The given information is SSA, which is the ambiguous case of the Law of Sines: sin A = sin B a b sin A sin 40 = sin A = 17(.647) sin A = 17(.647) 10 = This equation has no solution (because 1.09 > 1), so there is no such triangle. 1
13 .. Fall 016 Exam 11. Draw a right triangle where the opposite side is the flagpole. We are given that the adjacent side is 50 feet and the angle to the horizontal is 48. That means, labelling the adjacent side as a, that tan 48 = opposite adjacent 1.11 = a (50) = a 55.5 = a. Adding the 5 feet to account for the height of the viewer s eyes, we see that the height of the flagpole is = 60.5 feet. 13
14 .3. Fall 016 Exam 3.3 Fall 016 Exam 3 No calculators allowed on these problems 1. Throughout this problem, assume sec θ = 4. a) What is sec( θ)? b) What is cos θ? c) What is sec(θ 360 )? d) Which two quadrants might θ be in? e) If tan θ < 0, find cot θ.. Find the exact value of each quantity: a) sec 45 b) tan 150 c) cot 180 d) csc( 10 ) e) sec Find the exact value of each quantity: a) tan 5π d) cos π b) csc π 6 c) tan 3π 4 e) sin π 3 4. Find the exact value of each quantity: a) sin 15 + cos 15 b) cot( ) c) tan 5π 6 d) 3 sin π e) sin 3 π Calculators allowed on the rest of this exam 5. In each diagram below, write an equation for x in terms of the other given quantities in the picture. θ x 17 w x a) θ b) 6. Suppose that sin θ =.614 and that tan θ > 0. Find the values of all six trig functions of θ. 7. Use a calculator to compute these quantities: 14
15 .3. Fall 016 Exam 3 a) csc 75 b) cot 40 + cot 70 c) tan 15 d) 3 sec a) Find all angles θ between 0 and 360 such that tan θ =.7. b) Find all angles θ between 0 and 360 such that sec θ =.8. c) Find all angles θ between 0 and 360 such that csc θ = Throughout this question, assume that u = 5, 3, v = 1, 8 and that w is a vector whose magnitude is 7 and whose direction angle is 58. a) Compute u + v. b) Compute u v. c) Compute the angle between u and v. d) Compute the direction angle of v. e) Compute u + v. f) Write w in component form. 10. Let v and w be the vectors indicated in the picture below. a) Sketch the vector v + w on the picture; label that vector v + w. b) Sketch the vector w v on the picture; label that vector w v. w v 11. A bird leaves its nest and flies 0 miles on a heading 37, measured east of north. The bird then flies 9 miles on a bearing 7, measured west of north. a) How far is the bird from its nest? b) If the bird wanted to return to its nest, would it be more accurate to say it should fly southeast, or southwest? Explain your answer. 15
16 .3. Fall 016 Exam 3 Exam 3 Solutions 1. a) sec( θ) = sec θ = 4. b) cos θ = 1 sec θ = 1 4. c) sec(θ 360 ) = sec θ = 4. d) θ must be in Quadrant I or Quadrant IV. e) Since tan θ < 0, we now know θ is in Quadrant IV, so cot θ < 0. Sketch a triangle with hypotenuse 4 and adjacent side of length 1. From the Pythagorean Theorem, the opposite side is 4 1 = 15, so cot θ = adj opp = a) sec 45 =. b) tan 150 = 1 3 (reference angle 30, Quadrant II). c) cot 180 DNE. d) csc( 10 ) = 3 (reference angle 60, Quadrant III). e) sec 60 =. 3. a) tan 5π = 0 b) csc π 6 = c) tan 3π 4 = 1 (reference angle 45, Quadrant II) d) cos π = 0 e) sin π 3 = 3 (reference angle 60, Quadrant II) 4. a) sin 15 + cos 15 = 1 (by a Pythagorean identity) b) cot( ) = cot 90 = 0 c) tan 5π 6 = ( 1 3 ) = 1 3 d) 3 sin π = 3(1) = 3 e) sin 3 π = 1 5. a) x 17 = hyp opp b) x w = adj hyp = csc θ so x = 17 csc θ. = cos θ so x = w cos θ. 6. Since sin θ > 0 and tan θ > 0, θ is in Quadrant I, so all the trig functions are positive. We are given sin θ =.614, so csc θ = 1 = 1 = From the sin θ.614 identity sin θ + cos θ = 1, we can solve for cos θ to get cos θ =.789. Then sec θ = 1 = 1 sin θ = Last, tan θ = =.614 cos θ =.777 and cot θ = = cos θ.789 cos θ.789 sin θ.789 =
17 .3. Fall 016 Exam 3 7. a) csc 75 = b) cot 40 + cot 70 = = c) tan 15 = ( ) = d) 3 sec 40 = 3( ) = a) θ = tan 1.7 = ; a second angle is θ = b) If sec θ =.8, then cos θ = 1 so θ =.8 cos 1 ( 1 ) = A second angle is 360 θ = c) There are no such angles, because csc θ cannot be between 1 and Throughout this question, assume that u = 5, 3, v = 1, 8 and that w is a vector whose magnitude is 7 and whose direction angle is 58. a) u + v = 10, 6 + 1, 8 = 11, 14. b) u v = ( 5)( 1) + 3(8) = = 9. c) First, u = ( 5) + 3 = Second, v = 65 = Therefore, ( 1) + 8 = u v = u v cos θ 9 = (5.83)(8.06) cos θ.6171 = cos θ = θ. d) θ = tan 1 b = a tan 1 8 = 1 tan 1 ( 8) = But this is in the wrong quadrant (v is in Quadrant II), so we need to add 180 to get e) u + v = 6, 11 = ( 6) + 11 = = f) w = w cos θ, w sin θ = 7 cos 58, 7 sin 58 = 3.709, v+w w-v w v 17
18 .3. Fall 016 Exam a) Let v be the first part of the bird s journey; we have v = v cos θ, v sin θ = 0 cos 53, 0 sin 53 = 1.03, Let w be the second part of the bird s journey; we have w = w cos θ, w sin θ = 9 cos 16, 9 sin 16 = 8.559,.781. Therefore the bird s position is v + w = 3.47, The distance from the bird to the nest is v + w = 3.47, = (3.47) + (18.75) = mi. b) The first component of the bird s position is positive, so it has to fly southwest (although just barely west of south) to get back to its nest. 18
19 .4. Fall 016 Final Exam.4 Fall 016 Final Exam No calculators allowed on these questions 1. Find the exact value of each quantity: a) tan 45 b) cos 60 c) sin 90 d) sec 30 e) cos 0. Find the exact value of each quantity: a) cot 40 b) cos( 150 ) c) sin 315 d) csc 70 e) sec Find the exact value of each quantity: a) sin 11π 6 b) sin π 3 c) cot 3π d) tan 5π 6 e) tan 11π 3 4. Find the exact value of each quantity: a) sin 50 + cos 50 c) sin 75 e) 8 sec π 4 b) cos 135 d) tan Suppose cos θ = 3 and tan θ < 0. Find the exact values of all six trig functions 5 of θ. 6. Suppose tan θ = 3. a) Find tan θ. b) Find cot θ. c) Find cot θ. d) What two quadrants might θ be in? e) Find tan(θ + 70 ). f) Find tan( θ). 7. Sketch the graph of y = tan x. 8. a) Which of graphs A-K on the attached page (see page 1 of this pdf file) is the graph of y = sin x? b) Which of graphs A-K is the graph of y = sin x? c) Which of graphs A-K is the graph of y = sin x? d) Which of graphs A-K is the graph of y = sin(x + )? 19
20 .4. Fall 016 Final Exam e) Which of graphs A-K is the graph of y = sin x? f) Which of graphs A-K is the graph of y = sin x? 9. Vectors u, v and w are shown below. Sketch the following vectors on the same picture, being sure to label which vector is which: a) w u b) w c) 1 u d) u + v + w w v u 0
21 .4. Fall 016 Final Exam Graphs for Problem 8 Use these graphs to answer the questions in Problem 8: A B C π π π D E F π -1 π π -1 4 π G H I 4-1 π -1 π π J K π - π
22 .4. Fall 016 Final Exam Calculators allowed on the rest of the exam 10. Evaluate the following expressions using a calculator. Your answers can (and should) be written as decimals. a) csc 5 b) sin 5 + sin 110 c) sec(83 40 ) d) tan 117 e) 4 cot 86 f) sin 100 cos For each equation, find (decimal approximations of) all angles θ between 0 and 360 satisfying the following equations. If there are no such angles, say so. a) sin θ =.8 b) cos θ = 1.35 c) cot θ =.55 d) csc θ = 1 1. Suppose that θ is an angle in a right triangle whose hypotenuse has length 43. and whose side opposite θ has length 5.1. Find the six trig functions of angle θ. 13. a) Compute the norm of the vector 5, 4. b) Compute the direction angle of the vector 5, 7. c) Suppose v = 6, 4 and w =, 11. Compute 5v + w. d) Compute v w, where v and w are as in part (c). e) Find the components of a vector which has norm 17 and direction angle Solve triangle ABC, which is pictured below: C B A
23 .4. Fall 016 Final Exam 15. Solve triangle EF G, which is pictured below at left: F 8 47 Q E 5 77 R G P Solve triangle P QR, which is pictured above at right. 17. Classify the following statements as true or false: a) tan θ 1 = sec θ b) cos( θ) = cos θ c) cos(90 θ) = sin θ d) 1 cos θ = sin θ e) tan θ cos θ = sin θ 18. Answer any two of the following five questions. a) A wedge-shaped piece of pie taken from a pie with a 16 diameter has angle 50. Find the area of the piece of pie. b) A wheel of radius 18 feet rotates at a speed of 4 revolutions per minute. What is the linear velocity of a point on the edge of the wheel? c) Find the area of triangle ABC, if a = 30, b = 18 and C = 48. d) A 16-foot ladder leans up against the side of the building. If the top of the ladder is 13.5 feet above the ground, what angle does the ladder make with the ground? e) A boat leaves a harbor and sails 30 miles on a heading 40, measured east of north, then sails 0 miles due east. How far is it from the harbor? 3
24 .4. Fall 016 Final Exam Final Exam Solutions 1. a) tan 45 = 1 b) cos 60 = 1 c) sin 90 = 1 d) sec 30 = 1 cos 30 = 1 3/ = 3 e) cos 0 = 1. a) cot 40 = 1 3 (quadrant III, reference angle 60 ) b) cos( 150 ) = cos 150 = 3 (quadrant II, reference angle 30 ) c) sin 315 = (quadrant IV, reference angle 45 ) d) csc 70 = 1 = 1 (the point (0, 1) on the unit circle) 1 e) sec 450 = 1 cos 90 = 1 0 DNE. 3. a) sin 11π 6 = 1 (quadrant IV, reference angle 30 ) b) sin π = 3 (quadrant IV, reference angle 60 ) 3 c) cot 3π cos 70 = = 0 = 0 (the point (0, 1) on the unit circle) sin 70 1 d) tan 5π = (quadrant II, reference angle 30 ) e) tan 11π 3 = 3 (quadrant IV, reference angle 60 ) 4. a) sin 50 + cos 50 = 1 b) cos 135 = ( ) = = 1. 4 c) Use the addition identity for sine: sin 75 = sin( ) = sin 30 cos 45 + cos 30 sin 45 = =. 4 d) tan 4 30 = tan(4 30 ) = tan 10 = 3. e) 8 sec π 4 = Since cos θ > 0 and tan θ < 0, θ must be in Quadrant IV. Therefore all the trig functions of θ are negative except for cosine and secant. Next, draw a triangle with adjacent side 3 and hypotenuse 5. Solve for the opposite side using the Pythagorean Theorem to get 5 3 = 5 9 = 16 = 4. Therefore cos θ = 3 5 ; sec θ = 5 3 ; sin θ = 4 5 ; csc θ = 5 4 ; tan θ = 4 3 ; cot θ =
25 .4. Fall 016 Final Exam 6. a) tan θ = tan θ 1 tan θ = (3) 1 3 = 6 8 = 3 4. b) cot θ = 1 tan θ = 1 3. c) cot θ = 1 tan θ = 4 3. d) Since tan θ > 0, θ is in Quadrant I or III. e) tan(θ + 70 ) = tan θ = 3. f) tan( θ) = tan θ = The graph of y = tan x is on page 13 of my lecture notes. 8. a) This graph has period π = 4π, so it is graph F. 1/ b) This graph has been stretched vertically by a factor of, so it is graph A. 9. c) This graph is shifted down units, so it is graph G. d) This graph is shifted left units, so it is graph K. e) This graph has period π = π, so it is graph E. f) This graph has been squashed vertically to be half as tall, so it is graph B. u+v+w w-u u -w 10. a) csc 5 = 1 sin 5 = b) sin 5 + sin 110 = = c) sec(83 40 ) = sec 43 = 1 cos 43 = d) tan 117 = ( ) = e) 4 cot 86 = 4 ( ) 1 tan 86 = 4 1 = 4(.86745) = f) sin 100 cos 44 = ( )(.71934) =
26 .4. Fall 016 Final Exam 11. a) θ = sin 1.8 = 16.6 and = b) cos θ = 1.35 has no solution since 1.35 > 1. c) cot θ =.55 means tan θ = 1.55 = so θ = tan 1 ( ) = and θ = = d) csc θ = 1 means sin θ = 1 1 = 1 so θ = sin 1 1 = First, the adjacent side is = Therefore the six trig functions are sin θ = =.581 csc θ = = tan θ = =.713 cot θ = = cos θ = =.814 sec θ = = a) 5, 4 = 5 + ( 4) = = 41. b) θ = tan = tan.8 = Since θ must be in Quadrant II, add 180 to get θ = c) 5v + w = 30, 0 + 4, = 34,. d) Compute v w = 6() + ( 4)(11) = 1 44 = 3. e) 17 cos 30, 17 sin 30 = 10.97, B = = 55. sin 35 = a 18 so a = 18 sin 35 = cos 35 = b 18 so b = 18 cos 35 = Start with the Law of Cosines to find angle E: e = f + g fg cos E 47 = (5)(8) cos E 09 = cos E 800 = 1400 cos E = cos E cos = E = E 6
27 .4. Fall 016 Final Exam Then use the Law of Cosines (or the Law of Sines) to find angle G: g = e + f ef cos G 8 = (5)(47) cos G 784 = cos G 050 = 350 cos G = cos G 1 05 cos 35 = G 9.7 = G Last, angle F is = First, angle Q is = 77. Second, since angles Q and R are equal, sides q and r are equal so r = Last, use the Law of Sines to find p: sin P = sin R p r sin 6 sin 77 = p = p p = ( )6.43 p = ( ) = a) tan θ 1 = sec θ is FALSE (the tan and sec are backwards from what they are in the Pythagorean identity) b) cos( θ) = cos θ is FALSE (the sign disappears) c) cos(90 θ) = sin θ is TRUE (cofunction identity) d) 1 cos θ = sin θ is TRUE (Pythagorean identity) e) tan θ cos θ = sin θ is TRUE (write tan θ as sin θ and then cancel the cos θ cos θ terms on the left-hand side to see this) 18. a) The radius of the circle is r = 1 (16) = 8 inches; the angle in radians is 50 π = The area of the sector is therefore A = r θ = 1 (8) (.87665) = square inches. b) The angular velocity is ω = 4 pi = 8π = rad/sec, so the linear velocity is v = rω = 18(5.137) = feet per second. 7
28 .4. Fall 016 Final Exam c) By the SAS area formula, A = 1 ab sin C = 1 (30)18 sin 48 = square units. d) The opposite side to the angle is 13.5 and the hypotenuse is 16, so the angle is sin = e) After the first heading, the boat is at position 30 cos 50, 30 sin 50 = 19.8,.98 (the angle is 50 because = 50 ). After moving a further 0 miles east, the boat is at ,.98 = 39.8,.98. The distance from the boat to the harbor is the norm of this vector, which is = miles. 8
29 Chapter 3 Exams from Fall Fall 017 Exam 1 No calculator allowed on these problems 1. Convert the following angles from radians to degrees: a) 4π 3 b) 3π c) π. Draw the angle 50 in standard position. 3. Let sub be the function defined by sub x = x 3. Compute each quantity: a) sub 4 3 b) sub 4 3 c) sub (4) 3 d) 3 sub 4 Calculators allowed on the rest of the exam 4. Parts (a), (b), and (c) of this question are not related to one another. a) Find the measure of two different angles, one of which is less than 64 and one of which is greater than 64, both of which are coterminal with 64. b) Convert 5.6 radians to degrees (write your answer as an exact answer or as a decimal, rounded to two or more decimal places). c) Solve for x: x = x Parts (a), (b) and (c) of this question are not related to one another. 9
30 3.1. Fall 017 Exam 1 a) Find the distance between the points (1, 3) and (, 5) (write your answer either as an exact answer or as a decimal, rounded to two or more decimal places). b) The point (x, y) is on the unit circle. If x =.75, what are all possible values of y? c) Find the area of a sector whose central angle is 53, taken from a circle whose diameter is 6 feet. 6. A dragster has two front tires of radius 16 inches, and two rear tires of radius 6 inches. If the dragster is travelling with all four tires on the ground, with no skidding or friction, and rear tires rotate at 35 revolutions per second, what is the angular velocity of the front tires (in radians per second)? 7. In each problem (a)-(c), find x: a) Two complementary angles have measures x + 34 and 3x 0. b) The three angles of a triangle are x + 14, 3x 35 and 7x + 3. c) x is as in the picture below, where the vertical lines are parallel: 3x 5x -1 30
31 3.1. Fall 017 Exam 1 Solutions 1. a) 4π 3 = 4 π = = 40. b) 3π = 3 π = 3 90 = 70. c) π = Since 50 is a little less than 70, this angle should have its terminal side just west of south (in Quadrant III): 3. a) sub 4 3 = sub(4) 3 = ((4) 3) 3 = 5 3 =. b) sub 4 3 = sub 1 = (1) 3 = 4 3 = 1. c) sub(4) 3 = ((4) 3) 3 = 5 3 = 15. d) 3 sub 4 = 3((4) 3) = 3(5) = 15. (This is the same as (b).) 4. a) For a smaller angle, subtract 360 from 64 to get 64 ; for a larger angle, add 360 to 64 to get 984. b) Multiply by 180 to get π c) Cross-multiply to get 4.8(x 100) = 3.5x. Distribute on the left-hand side to get 4.8x 480 = 3.5x; combine the like terms to get 1.55x = 480; last, divide by 1.55 to get x = a) D = (x x 1 ) + (y y 1 ) = ( 1) + (5 3) = ( 3) + () = = b) From the unit circle formula x + y = 1, we see x + (.75) = 1. Squaring out, this gives x = 1, i.e. x = =.943. Take the square root of both sides to get x = ±.943 = ± c) The radius is half of the given diameter, i.e. r = 3. Convert the angle to radians by multiplying by π to get θ =.95 radians. Then A = r θ = 1 (3) (.95) = sq ft. 6. The rear tires have angular velocity ω rear = 35(π) = rad/sec, so their linear velocity is v rear = r rear ω rear = 6(19.911) = in/sec. The front tires have the same linear velocity as the back tires, so v front = in/sec as well. Finally, ω front = v front r front = = radians per second
32 3.1. Fall 017 Exam 1 7. a) The angles are complementary, so (x + 34 ) + (3x 0 ) = 90. Combine the like terms to get 4x + 14 = 90, i.e. 4x = 76, i.e. x = 19. b) The angles sum to 180 : (x+14 )+(3x 35 )+(7x+3 ) = 180. Combine the like terms to get 11x 18 = 180, i.e. 11x = 198, i.e. x = 18. c) The angles are supplementary, so 3x + 5x 1 = 180. This means 8x = 19, i.e. x = 4. 3
33 3.. Fall 017 Exam 3. Fall 017 Exam No calculator allowed on these problems 1. Throughout this problem, assume cos θ = 3. 4 a) What is cos( θ)? b) What is cos(θ 360 )? c) What are the two quadrants θ could lie in? d) If sin θ < 0, find sin θ.. Find the exact value of each quantity: a) sin 180 c) sin 450 π e) sin 4 b) cos 60 d) cos 135 f) cos 3π g) sin 5π 6 h) cos π Calculators allowed on the rest of the exam 3. Find cos θ and sin θ, if θ is as in the following picture. (Either an exact answer or a decimal is OK, but make sure to tell me which answer is sin θ and which is cos θ.) θ a) Find all angles θ between 0 and 360 such that sin θ =.65. b) Find all angles θ between 0 and 360 such that cos θ =. c) Find all angles θ between 0 and 360 such that cos θ = Find the area of this triangle: A 0-foot long ladder leans up against the side of a building. If the bottom of the ladder makes an angle of 70 with the ground, how high up the side of the building does the ladder go? 33
34 3.. Fall 017 Exam 7. Solve triangle ABC, given the information in the picture below: B 43.5 A 38 C 8. Solve triangle KLM if k = 18, l = 13 and m = Solve triangle ABC if A = 70, B = 58 and a =. 34
35 3.. Fall 017 Exam Solutions 1. a) cos( θ) = cos θ = 3 4. b) cos(θ 360 ) = cos θ = 3 4. c) Since cos θ > 0, θ must be in Quadrants I or IV. d) Start with the Pythagorean identity: cos θ + sin θ = 1 ( ) 3 + sin θ = sin θ = 1 sin θ = 7 16 cos θ = ± Since we are told sin θ < 0, sin θ = 7 16 = a) sin 180 = 0 (point on unit circle is ( 1, 0)). b) cos 60 = 1 c) sin 450 = sin 90 = sin 90 = 1 (point on unit circle is (0, 1)). d) cos 135 = (Quadrant II; reference angle 45 ) e) sin π = sin 4 45 = (Quadrant I) f) cos 3π = cos 540 = cos 180 = 1 (point on unit circle is ( 1, 0)) g) sin 5π 6 = sin( 150 ) = 1 (Quadrant III; reference angle π 6 = 30 ) h) cos π = cos 90 = 0 (point on unit circle is (0, 1)) 3. First, use the Pythagorean Theorem to find the hypotenuse, which I ll call c: Then cos θ = = c c = = adjacent hypotenuse =.5145 and sin θ = opposite hypotenuse = a) From a calculator, θ = sin 1 (.65) Add 360 to this to get ; take 180 the calculator answer to get the second answer which is b) There are no such angles (because > 1). c) From a calculator, θ = cos 1 (.43) A second angle which solves the equation is 360 θ = First, the third angle is = 88. Then, by the SAS Area Formula, A = 1 ab sin C = 1 (1)(15) sin sq units. 35
36 3.. Fall 017 Exam 6. In this problem, we have a right triangle where the hypotenuse is 0 and the angle from the hypotenuse to the ground is 70. We are asked to find the opposite side, which I ll call b. By SOHCAHTOA, we get sin 70 = opposite hypotenuse = b 0. Solve for b by cross-multiplying to get b = 0 sin 70 = ft. 7. First, the third angle is B = = 5. Second, find side a using a trig function (either sine or cosine): sin 38 = a = a = a. Last, find the remaining side using the Pythagorean Theorem: a + b = c (6.78) + b = (43.5) b = (43.5) (6.78) = The given information is SSS, so start with the Law of Cosines to find any angle (say K): k = l + m lm cos K 18 = (13)(10) cos K 34 = cos K 34 = cos K 55 = 60 cos K.115 = cos K 10. = K Now use the Law of Cosines again (or the Law of Sines) to find a second 36
37 3.. Fall 017 Exam angle (say L): l = k + m km cos L 13 = (18)(10) cos L 169 = cos L 169 = cos L 55 = 360 cos L.708 = cos L 44.9 = L Last, find the third angle (for me this is M): M = = The given information is SAA/AAS, which requires the Law of Sines. First, the third angle is C = = 5. Second, find side length b using the Law of Sines: sin A = sin B a b sin 70 sin 58 = b b sin 70 = sin b = b = Last, find side length c using the Law of Sines (you could use the Law of Cosines): sin A = sin C a c sin 70 sin 5 = c c sin 70 = sin 5.939c = c =
38 3.3. Fall 017 Exam Fall 017 Exam 3 No calculator allowed on these problems 1. Throughout this problem, assume cot θ = 5. 3 a) What is cot( θ)? b) What is tan θ? c) Which two quadrants might θ be in? d) If sin θ < 0, find cos θ.. a) csc 135 b) tan 60 c) cot 180 d) sec( 5 ) e) cot 3π f) sec π 6 g) tan 3π 4 3. Find the exact value of each quantity: a) sec 4π 3 b) 8 sin π 6 c) sin 15 + cos 15 d) tan( 90 ) e) cos π In each diagram below, write an equation for x in terms of the other given quantities in the picture. Your formula for x should not contain division in it. x x 10 a) p θ b) α β 5. Let v and w be the vectors indicated in the picture below. a) Sketch the vector 1 w on the picture; label that vector 1 w. b) Sketch the vector v + w on the picture; label that vector v + w. v w 38
39 3.3. Fall 017 Exam 3 Calculators allowed on the rest of the exam 6. Suppose that θ is some angle such that when drawn in standard position, ( 7, 1) is on the terminal side of θ. Find sec θ and tan θ. 7. Use a calculator to compute decimal approximations of these quantities: a) csc 3 b) tan cot 140 c) cos a) Find all angles θ between 0 and 360 such that tan θ = b) Find all angles θ between 0 and 360 such that sec θ = a) Suppose u = 3, 8 and v = 4, 5. Find 3u + v. b) Find u v, where u and v are as in part (a). c) Suppose w is a vector with magnitude 7 and direction angle 85. Find the components of w. d) Find the magnitude of the vector z = 6.3, Nemo the fish swims away from his home on a trajectory 50 north of east for miles, then changes course and swims due east for 1 mile. After that, Nemo changes course again and swims for 3 miles on a trajectory 35 south of east. At this point, what distance would Nemo have to swim if he wanted to swim directly home? 39
40 3.3. Fall 017 Exam 3 Solutions 1. a) cot( θ) = cot θ = 5 3. b) tan θ = 1 cot θ = 3 5. c) cot θ is positive in Quadrants I and III. d) Since cot θ > 0 and sin θ < 0, θ is in Quadrant III, so cos θ will be negative. Now draw a triangle and label the adjacent side as 5 and the opposite side as 3. Solve for the hypotenuse using the Pythagorean Theorem to get = 34. Finally, cos θ =. a) csc 135 =. b) tan 60 = 3. c) cot 180 DNE. d) sec( 5 ) = sec 5 =. e) cot 3π = 0. f) sec π 6 = 3. g) tan 3π 4 = a) sec 4π 3 = ( ) = 4. b) 8 sin π 6 = 8 1 = 4. c) sin 15 + cos 15 = 1. d) tan( 90 ) = tan 180 = 0. e) cos π + 1 = =. 4. a) x p = adjacent hypotenuse = cos θ, so x = p cos θ. adjacent = 5 hypotenuse 34. b) Label the vertical segment common to both triangles as w. Then w = 10 csc β and x = w csc α, so by substitution x = 10 csc β csc α. 5. To get 1 w, sketch a vector in the opposite direction as w, but half as long. To get v + w, first draw v (twice as long as v, in the same direction) and then add by drawing a parallelogram. You end up with the following: v + w 1 w 40
41 6. We have x = 7 and y = 1 so r = x + y = 193. Therefore 3.3. Fall 017 Exam 3 ( 7) + 1 = = sec θ = r x = and tan θ = y x = a) csc 3 = 1 sin 3 = b) tan cot 140 = ( ) = c) cos 13 = (.8386) = a) θ = tan = The other angle is θ = b) cos θ = 1 = 1 =.958. Therefore θ = sec θ 3.38 cos = The other angle is 360 θ = a) 3u + v = 9, 4 + 4, 5 = 5, 9. b) u v = ( 3)4 + 8(5) = 8. c) w = 7 cos 85, 7 sin 85 = 1.811, d) z = = = Nemo s journey can be described by three vectors: the first part of his trip is the second part of his trip is the last part of his trip is a = cos 50, sin 50 = 1.85, 1.53 ; b = 1 cos 0, 1 sin 0 = 1, 0 ; c = 3 cos 35, 3 sin 35 =.457, 1.7. (The angle is = 35 because the trajectory is south of east.) That means Nemo s eventual position is a + b + c = , = 4.74,.188. The magnitude of this vector, which is the distance from Nemo to his home, is (.188) = miles. 41
42 3.4. Fall 017 Final Exam 3.4 Fall 017 Final Exam No calculator allowed on these problems 1. Find the exact value of each quantity: a) cos 30 b) tan 90 c) sin 45 d) csc 90 e) sin 0. Find the exact value of each quantity: a) tan 150 b) cos( 5 ) c) sin 330 d) cot 180 e) sec Find the exact value of each quantity: a) cos 4π 3 b) sin π 3 c) tan 3π 4 d) cot π 6 e) csc 5π 4. Find the exact value of each quantity: a) sin cos 310 b) cos 400 cos 40 c) tan 85 sec 85 d) sin 0 cos 40 + cos 0 sin 40 e) cos Suppose tan θ = 3 of θ. 6. Suppose sin θ = 1 5 and sin θ < 0. Find the exact values of all six trig functions and cos θ > 0. a) Find csc θ. b) What quadrant is θ in? c) Find sin(θ 360 ). d) Find sin( θ). e) Find sin θ. f) Find csc θ. 7. Sketch a crude graph of each function, labelling the graph appropriately: a) y = sin x 4 b) y = 3 cos x c) y = cot x d) y = sin x Simplify the following expression using trig identities: 1 sin θ 1 csc θ 4
43 3.4. Fall 017 Final Exam Calculators allowed on the rest of the exam 9. Evaluate the following expressions using a calculator. Your answers can (and should) be written as decimals. a) sin 103 b) 5 cos( 51 ) c) cos 133 cos 75 d) csc( ) e) sin 31 f) tan 40 cot 108 g) sec For each equation, find (decimal approximations of) all angles θ between 0 and 360 satisfying the following equations. If the equation has no solution, say so. a) sin θ =.683 b) cos θ =.3 c) tan θ = 3.1 d) sec θ = 0 e) cos θ =.735 f) sin θ = Find the six trig functions of the angle θ, if the point (.7, 5.9) is on the terminal side of θ when it is drawn in standard position. 1. Let v = 8, 1 and let w = 3, 7. a) Compute the norm of v. b) Compute v w. c) Find the measure of the angle between v and w. 13. A chipmunk located 4 feet from a flagpole has to look up at an angle of 50 to see the top of the flagpole. How tall is the flagpole? (Assume the chipmunk s eyes are at ground level.) 14. A surveyor is trying to determine the distance between points X and Y as shown below, but can t measure the distance directly because there is an obstacle in the way. So instead, the surveyor measures the distances from X and Y to a third point Z, and measures an angle at point Z as shown in the 43
44 3.4. Fall 017 Final Exam figure below. Find the distance from point X to point Y. Y X obstacle Z 15. Solve triangle P QR, where P = 75, Q = 58 and p = Choose any three of the following five questions. a) The video game Pac-Man features a character that looks like the lefthand figure below. Find the area enclosed by Pac-Man x.85 θ b) Write an expression for x in terms of the other quantities given in the right-hand figure above. Simplify your answer. c) A bicycle wheel of radius 16.5 inches rotates at a speed of 35 revolutions per minute. What is the linear velocity of a point on the edge of the wheel? d) Find the area of triangle ABC, if a = 6, b = 4 and c = 5. e) A bird leaves its nest and flies due west for 9 miles, then flies at an angle 57 north of east for 7 miles. How far from its nest is it? 44
45 3.4. Fall 017 Final Exam Solutions 1. a) cos 30 = 3. b) tan 90 = 1 which DNE. 0 c) sin 45 =. d) csc 90 = 1 1 = 1. e) sin 0 = 0.. a) tan 150 = 3 3 (quadrant II, reference angle 30 ) b) cos( 5 ) = (quadrant II, reference angle 45 ) c) sin 330 = 1 (quadrant IV, reference angle 30 ) d) cot 180 = 1 which DNE. 0 e) sec 780 = (quadrant I, reference angle 60 ) 3. a) cos 4π 3 = 1 (quadrant III, reference angle 60 ) b) sin π 3 = 3 (quadrant III, reference angle 60 ) c) tan 3π 4 = 1 (quadrant II, reference angle 45 ) d) cot π 6 = 3 (quadrant IV, reference angle 30 ) e) csc 5π = csc 90 = 1 1 = a) sin cos 310 = 1 (by the Pythagorean identity) b) cos 400 cos 40 = cos 40 cos 40 (by periodicity) which simplifies to 0. c) tan 85 sec 85 = 1 (by a rewritten version of tan θ + 1 = sec θ) d) Use the addition identity for sine to get sin 0 cos 40 + cos 0 sin 40 = sin( ) = sin 60 = 3 e) Use the addition identity for cosine to get cos 75 = cos( ) = cos 30 cos 45 sin 30 sin 45 = ( 3 ) ( ) ( 1 ) ( ) = Draw a triangle, labelling the opposite side and the adjacent side 3. Solve for the hypotenuse using the Pythagorean Theorem, obtaining 13. Since tan θ > 0 and sin θ < 0, the angle is in Quadrant III, so all trig functions other than tangent and cotangent are negative. Using the right triangle definitions of the trig functions, we get sin θ = 13 cos θ = 3 13 tan θ = 3 13 csc θ = 13 sec θ = 3 cot θ = 3 45
46 π π 3.4. Fall 017 Final Exam 6. a) csc θ = 1 sin θ = 1 1/5 = 5. b) Since sin θ and cos θ are positive, θ is in Quadrant I. c) sin(θ 360 ) sin θ = 1 5. d) sin( θ) = sin θ = 1. 5 e) First, find cos θ: draw a triangle, label the opposite side 1 and the hypotenuse 5, and solve for the adjacent side using the Pythagorean Theorem to get 4. Since the angle is in Quadrant I, cos θ = 4. Next, 5 sin θ = sin θ cos θ = ( 1 5 ) ( 4 5 f) csc θ = 1 sin θ = 1 4/5 = 5 4. ) = a) y = sin x 4 is the graph of y = sin x, shifted down 4 units: π b) y = 3 cos x is the graph of y = cos x, stretched vertically by a factor of 3: 3 π -3 c) y = cot x looks like this: d) y = sin x + 1 has period π B = π = π, and is shifted up 1 unit: 1 π π 46
47 3.4. Fall 017 Final Exam 8. Use Pythagorean identities, then a quotient identity, then divide the fractions: 9. a) sin 103 = sin θ 1 csc θ = cos θ cot θ = cos θ cos θ sin θ b) 5 cos( 51 ) = 5(.693) = = cos θ 1 = sin θ 1 = sin θ. sin θ cos θ c) cos 133 cos 75 = = d) csc( ) = csc 133 = 1 sin 133 = = e) sin 31 = (sin 31 ) = ( ) = f) tan 40 cot 108 = (.8391) ( ) ( 1 tan 108 = (.8391) g) sec 4 83 = (sec(33 )) = ( ) ( 1 cos 33 = ) =.764. ) = a) θ = sin = 43.1 ; the other angle is 180 θ = b) θ = cos 1.3 = 76.7 ; the other angle is 360 θ = c) θ = tan = 7.7. Add 360 to get 87.3 ; the other angle is θ = d) sec θ = 0 has solution because 1 < 0 < 1. e) θ = cos = ; the other angle is 360 θ =.7. f) sin θ = 1.04 has no solution because 1.04 > We are given x =.7, y = 5.9 and need to find r. By the Pythagorean Theorem, r = x + y = (.7) = Then: sin θ = y r = =.909 cos θ = x r = =.416 tan θ = y x = =.185 csc θ = r y = = sec θ = r x = =.40 cot θ = x y = = a) v = = 65. b) v w = 8(3) + 1(7) = =
48 3.4. Fall 017 Final Exam c) Find the measure of the angle between v and w. Start with the formula v w = v w cos θ and solve for θ. From parts (a) and (b), we know v w and v, so we need to find w = = = 58. Now from the formula, we have v w = v w cos θ 31 = cos θ 31 = cos θ = cos θ cos 1 ( ) = θ = θ. 13. Draw a right triangle, labelling the angle to the horizontal with 50. We are given that the adjacent side is 4 and need to find the opposite side, so use tangent: tan 50 = h 4 h = 4 tan 50 = feet. 14. Use the Law of Cosines to find z, the distance between X and Y : z = x + y xy cos Z z = (4)(77) cos 64 z = (4)(77)( ) z = z = z = = First, the third angle is = 47. Next, use the Law of Sines to find q: sin P = sin Q p q sin 75 sin 58 = 53 q = q.96596q = 53(.84808) = q = =
49 3.4. Fall 017 Final Exam Last, use the Law of Sines to find r: sin P = sin R p r sin 75 sin 47 = 53 r = q.96596q = 53( ) = q = = a) The angle enclosed by Pac-Man is = 304 = 304 π 180 = radians. Now by the area formula for sectors, A = 1 r θ = 1 (.85) (5.3058) = square units. b) Let w be the vertical line segment; using the right-hand triangle we have w = tan = 3, so w = Now from the left-hand triangle, we have x = csc θ so x = w csc θ. Substituting in for w, we get x = w 13 3 csc θ. c) ω = 35(π) = radians per minute. Then the linear velocity is v = rω = 16.5(19.911) = inches per minute. d) The semiperimeter is s = 1(a + b + c) = 1 ( ) = 7.5; then by Heron s formula the area is A = s(s a)(s b)(s c) = 7.5(7.5 6)(7.5 4)(7.5 5) = = square units. e) The first part of the bird s journey is the vector v = 9, 0 ; the second part has angle 57 and magnitude 7 so its components are w = 7 cos 57, 7 sin 57 = , Therefore the bird has travelled v + w = , ; the distance from its nest is v + w = ( ) = = miles. 49
Trigonometry Final Exam Review
Name Period Trigonometry Final Exam Review 2014-2015 CHAPTER 2 RIGHT TRIANGLES 8 1. Given sin θ = and θ terminates in quadrant III, find the following: 17 a) cos θ b) tan θ c) sec θ d) csc θ 2. Use a calculator
More informationChapter 4 Trigonometric Functions
Chapter 4 Trigonometric Functions Overview: 4.1 Radian and Degree Measure 4.2 Trigonometric Functions: The Unit Circle 4.3 Right Triangle Trigonometry 4.4 Trigonometric Functions of Any Angle 4.5 Graphs
More informationSection 6.1. Standard position- the vertex of the ray is at the origin and the initial side lies along the positive x-axis.
1 Section 6.1 I. Definitions Angle Formed by rotating a ray about its endpoint. Initial side Starting point of the ray. Terminal side- Position of the ray after rotation. Vertex of the angle- endpoint
More informationTrigonometric Functions. Copyright Cengage Learning. All rights reserved.
4 Trigonometric Functions Copyright Cengage Learning. All rights reserved. 4.3 Right Triangle Trigonometry Copyright Cengage Learning. All rights reserved. What You Should Learn Evaluate trigonometric
More informationChapter 1: Trigonometric Functions 1. Find (a) the complement and (b) the supplement of 61. Show all work and / or support your answer.
Trig Exam Review F07 O Brien Trigonometry Exam Review: Chapters,, To adequately prepare for the exam, try to work these review problems using only the trigonometry knowledge which you have internalized
More information1) SSS 2) SAS 3) ASA 4) AAS Never: SSA and AAA Triangles with no right angles.
NOTES 6 & 7: TRIGONOMETRIC FUNCTIONS OF ANGLES AND OF REAL NUMBERS Name: Date: Mrs. Nguyen s Initial: LESSON 6.4 THE LAW OF SINES Review: Shortcuts to prove triangles congruent Definition of Oblique Triangles
More informationFrom now on angles will be drawn with their vertex at the. The angle s initial ray will be along the positive. Think of the angle s
Fry Texas A&M University!! Math 150!! Chapter 8!! Fall 2014! 1 Chapter 8A Angles and Circles From now on angles will be drawn with their vertex at the The angle s initial ray will be along the positive.
More informationMath 1303 Part II. The opening of one of 360 equal central angles of a circle is what we chose to represent 1 degree
Math 1303 Part II We have discussed two ways of measuring angles; degrees and radians The opening of one of 360 equal central angles of a circle is what we chose to represent 1 degree We defined a radian
More informationSection 6.1 Sinusoidal Graphs
Chapter 6: Periodic Functions In the previous chapter, the trigonometric functions were introduced as ratios of sides of a right triangle, and related to points on a circle We noticed how the x and y values
More informationI IV II III 4.1 RADIAN AND DEGREE MEASURES (DAY ONE) COMPLEMENTARY angles add to90 SUPPLEMENTARY angles add to 180
4.1 RADIAN AND DEGREE MEASURES (DAY ONE) TRIGONOMETRY: the study of the relationship between the angles and sides of a triangle from the Greek word for triangle ( trigonon) (trigonon ) and measure ( metria)
More informationTrigonometric ratios:
0 Trigonometric ratios: The six trigonometric ratios of A are: Sine Cosine Tangent sin A = opposite leg hypotenuse adjacent leg cos A = hypotenuse tan A = opposite adjacent leg leg and their inverses:
More information2. Pythagorean Theorem:
Chapter 4 Applications of Trigonometric Functions 4.1 Right triangle trigonometry; Applications 1. A triangle in which one angle is a right angle (90 0 ) is called a. The side opposite the right angle
More informationMth 133 Trigonometry Review Problems for the Final Examination
Mth 1 Trigonometry Review Problems for the Final Examination Thomas W. Judson Stephen F. Austin State University Fall 017 Final Exam Details The final exam for MTH 1 will is comprehensive and will cover
More informationPractice Test - Chapter 4
Find the value of x. Round to the nearest tenth, if necessary. 1. An acute angle measure and the length of the hypotenuse are given, so the sine function can be used to find the length of the side opposite.
More informationName Date Period. Calculater Permitted MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
PreAP Precalculus Spring Final Exam Review Name Date Period Calculater Permitted MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Simplify the expression.
More informationMath Section 4.3 Unit Circle Trigonometry
Math 10 - Section 4. Unit Circle Trigonometry An angle is in standard position if its vertex is at the origin and its initial side is along the positive x axis. Positive angles are measured counterclockwise
More informationTrigonometry Trigonometry comes from the Greek word meaning measurement of triangles Angles are typically labeled with Greek letters
Trigonometry Trigonometry comes from the Greek word meaning measurement of triangles Angles are typically labeled with Greek letters α( alpha), β ( beta), θ ( theta) as well as upper case letters A,B,
More informationA List of Definitions and Theorems
Metropolitan Community College Definition 1. Two angles are called complements if the sum of their measures is 90. Two angles are called supplements if the sum of their measures is 180. Definition 2. One
More informationSince 1 revolution = 1 = = Since 1 revolution = 1 = =
Fry Texas A&M University Math 150 Chapter 8A Fall 2015! 207 Since 1 revolution = 1 = = Since 1 revolution = 1 = = Convert to revolutions (or back to degrees and/or radians) a) 45! = b) 120! = c) 450! =
More informationUnit Circle. Return to. Contents
Unit Circle Return to Table of Contents 32 The Unit Circle The circle x 2 + y 2 = 1, with center (0,0) and radius 1, is called the unit circle. Quadrant II: x is negative and y is positive (0,1) 1 Quadrant
More informationPractice Test - Chapter 4
Find the value of x. Round to the nearest tenth, if necessary. Find the measure of angle θ. Round to the nearest degree, if necessary. 1. An acute angle measure and the length of the hypotenuse are given,
More informationSection 6.2 Notes Page Trigonometric Functions; Unit Circle Approach
Section Notes Page Trigonometric Functions; Unit Circle Approach A unit circle is a circle centered at the origin with a radius of Its equation is x y = as shown in the drawing below Here the letter t
More informationChapter 6: Periodic Functions
Chapter 6: Periodic Functions In the previous chapter, the trigonometric functions were introduced as ratios of sides of a triangle, and related to points on a circle. We noticed how the x and y values
More information5.1: Angles and Radian Measure Date: Pre-Calculus
5.1: Angles and Radian Measure Date: Pre-Calculus *Use Section 5.1 (beginning on pg. 482) to complete the following Trigonometry: measurement of triangles An angle is formed by two rays that have a common
More information( 3 ) = (r) cos (390 ) =
MATH 7A Test 4 SAMPLE This test is in two parts. On part one, you may not use a calculator; on part two, a (non-graphing) calculator is necessary. When you complete part one, you turn it in and get part
More informationCK- 12 Algebra II with Trigonometry Concepts 1
1.1 Pythagorean Theorem and its Converse 1. 194. 6. 5 4. c = 10 5. 4 10 6. 6 5 7. Yes 8. No 9. No 10. Yes 11. No 1. No 1 1 1. ( b+ a)( a+ b) ( a + ab+ b ) 1 1 1 14. ab + c ( ab + c ) 15. Students must
More informationChapter 3. Radian Measure and Circular Functions. Section 3.1: Radian Measure. π 1.57, 1 is the only integer value in the
Chapter Radian Measure and Circular Functions Section.: Radian Measure. Since θ is in quadrant I, 0 < θ
More informationFind the length of an arc that subtends a central angle of 45 in a circle of radius 8 m. Round your answer to 3 decimal places.
Chapter 6 Practice Test Find the radian measure of the angle with the given degree measure. (Round your answer to three decimal places.) 80 Find the degree measure of the angle with the given radian measure:
More informationSection 6.2 Trigonometric Functions: Unit Circle Approach
Section. Trigonometric Functions: Unit Circle Approach The unit circle is a circle of radius centered at the origin. If we have an angle in standard position superimposed on the unit circle, the terminal
More informationn power Name: NOTES 2.5, Date: Period: Mrs. Nguyen s Initial: LESSON 2.5 MODELING VARIATION
NOTES 2.5, 6.1 6.3 Name: Date: Period: Mrs. Nguyen s Initial: LESSON 2.5 MODELING VARIATION Direct Variation y mx b when b 0 or y mx or y kx y kx and k 0 - y varies directly as x - y is directly proportional
More informationAlgebra II Standard Term 4 Review packet Test will be 60 Minutes 50 Questions
Algebra II Standard Term Review packet 2017 NAME Test will be 0 Minutes 0 Questions DIRECTIONS: Solve each problem, choose the correct answer, and then fill in the corresponding oval on your answer document.
More informationMAC 1114: Trigonometry Notes
MAC 1114: Trigonometry Notes Instructor: Brooke Quinlan Hillsborough Community College Section 7.1 Angles and Their Measure Greek Letters Commonly Used in Trigonometry Quadrant II Quadrant III Quadrant
More informationMATH 130 FINAL REVIEW
MATH 130 FINAL REVIEW Problems 1 5 refer to triangle ABC, with C=90º. Solve for the missing information. 1. A = 40, c = 36m. B = 53 30', b = 75mm 3. a = 91 ft, b = 85 ft 4. B = 1, c = 4. ft 5. A = 66 54',
More informationCHAPTER 1. ANGLES AND BASIC TRIG
DR. YOU: 017 FALL 1 CHAPTER 1. ANGLES AND BASIC TRIG LECTURE 1-0 REVIEW EXAMPLE 1 YOUR TURN 1 Simplify the radical expression. Simplify the radical expression. (A) 108 (A) 50 First, find the biggest perfect
More informationPrecalculus Midterm Review
Precalculus Midterm Review Date: Time: Length of exam: 2 hours Type of questions: Multiple choice (4 choices) Number of questions: 50 Format of exam: 30 questions no calculator allowed, then 20 questions
More informationCollege Trigonometry
College Trigonometry George Voutsadakis 1 1 Mathematics and Computer Science Lake Superior State University LSSU Math 11 George Voutsadakis (LSSU) Trigonometry January 015 1 / 8 Outline 1 Trigonometric
More informationMATH 1316 REVIEW FOR FINAL EXAM
MATH 116 REVIEW FOR FINAL EXAM Problem Answer 1. Find the complete solution (to the nearest tenth) if 4.5, 4.9 sinθ-.9854497 and 0 θ < π.. Solve sin θ 0, if 0 θ < π. π π,. How many solutions does cos θ
More informationPrecalculus: An Investigation of Functions. Student Solutions Manual for Chapter Solutions to Exercises
Precalculus: An Investigation of Functions Student Solutions Manual for Chapter 5 5. Solutions to Exercises. D (5 ( )) + (3 ( 5)) (5 + ) + (3 + 5) 6 + 8 00 0 3. Use the general equation for a circle: (x
More informationCHAPTER 6. Section Two angles are supplementary. 2. Two angles are complementary if the sum of their measures is 90 radians
SECTION 6-5 CHAPTER 6 Section 6. Two angles are complementary if the sum of their measures is 90 radians. Two angles are supplementary if the sum of their measures is 80 ( radians).. A central angle of
More informationFind: sinθ. Name: Date:
Name: Date: 1. Find the exact value of the given trigonometric function of the angle θ shown in the figure. (Use the Pythagorean Theorem to find the third side of the triangle.) Find: sinθ c a θ a a =
More information1. (10pts) If θ is an acute angle, find the values of all the trigonometric functions of θ given that tan θ = 1. Draw a picture.
Trigonometry Exam 1 MAT 145, Spring 017 D. Ivanšić Name: Show all your work! 1. (10pts) If θ is an acute angle, find the values of all the trigonometric functions of θ given that tan θ = 1. Draw a picture.
More informationMath Section 4.3 Unit Circle Trigonometry
Math 10 - Section 4. Unit Circle Trigonometry An angle is in standard position if its vertex is at the origin and its initial side is along the positive x axis. Positive angles are measured counterclockwise
More informationHonors Algebra 2 Chapter 14 Page 1
Section. (Introduction) Graphs of Trig Functions Objectives:. To graph basic trig functions using t-bar method. A. Sine and Cosecant. y = sinθ y y y y 0 --- --- 80 --- --- 30 0 0 300 5 35 5 35 60 50 0
More information1.1 Angles, Degrees, and Arcs
MA140 Trig 2015 Homework p. 1 Name: 1.1 Angles, Degrees, and Arcs Find the fraction of a counterclockwise revolution that will form an angle with the indicated number of degrees. 3(a). 45 3(b). 150 3(c).
More information(A) (12, 5) (B) ( 8, 15) (C) (3,6) (D) (4,4)
DR. YOU: 018 FALL 1 CHAPTER 1. ANGLES AND BASIC TRIG LECTURE 1-0 REVIEW EXAMPLE 1 YOUR TURN 1 Simplify the radical expression. Simplify the radical expression. (A) 108 (A) 50 First, find the biggest perfect
More informationA Short Course in Basic Trigonometry. Marcel B. Finan Arkansas Tech University c All Rights Reserved
A Short Course in Basic Trigonometry Marcel B. Finan Arkansas Tech University c All Rights Reserved PREFACE Trigonometry in modern time is an indispensable tool in Physics, engineering, computer science,
More informationUnited Arab Emirates University
United Arab Emirates University University Foundation Program - Math Program ALGEBRA - COLLEGE ALGEBRA - TRIGONOMETRY Practice Questions 1. What is 2x 1 if 4x + 8 = 6 + x? A. 2 B. C. D. 4 E. 2. What is
More informationUnit 2 - The Trigonometric Functions - Classwork
Unit 2 - The Trigonometric Functions - Classwork Given a right triangle with one of the angles named ", and the sides of the triangle relative to " named opposite, adjacent, and hypotenuse (picture on
More informationSHORT ANSWER. Write the word or phrase that best completes each statement or answers the question.
MATH 116 Test Review sheet SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question. Provide an appropriate response. 1) Find the complement of an angle whose measure
More informationChapter 13: Trigonometry Unit 1
Chapter 13: Trigonometry Unit 1 Lesson 1: Radian Measure Lesson 2: Coterminal Angles Lesson 3: Reference Angles Lesson 4: The Unit Circle Lesson 5: Trig Exact Values Lesson 6: Trig Exact Values, Radian
More informationMPE Review Section II: Trigonometry
MPE Review Section II: Trigonometry Review similar triangles, right triangles, and the definition of the sine, cosine and tangent functions of angles of a right triangle In particular, recall that the
More informationand sinθ = cosb =, and we know a and b are acute angles, find cos( a+ b) Trigonometry Topics Accuplacer Review revised July 2016 sin.
Trigonometry Topics Accuplacer Revie revised July 0 You ill not be alloed to use a calculator on the Accuplacer Trigonometry test For more information, see the JCCC Testing Services ebsite at http://jcccedu/testing/
More informationAlgebra II Final Exam Semester II Practice Test
Name: Class: Date: Algebra II Final Exam Semester II Practice Test 1. (10 points) A bacteria population starts at,03 and decreases at about 15% per day. Write a function representing the number of bacteria
More informationChapter 3. Radian Measure and Circular Functions. Copyright 2005 Pearson Education, Inc.
Chapter 3 Radian Measure and Circular Functions Copyright 2005 Pearson Education, Inc. 3.1 Radian Measure Copyright 2005 Pearson Education, Inc. Measuring Angles Thus far we have measured angles in degrees
More information2018 Midterm Review Trigonometry: Midterm Review A Missive from the Math Department Trigonometry Work Problems Study For Understanding Read Actively
Summer . Fill in the blank to correctl complete the sentence..4 written in degrees and minutes is..4 written in degrees and minutes is.. Find the complement and the supplement of the given angle. The complement
More informationFunctions and their Graphs
Chapter One Due Monday, December 12 Functions and their Graphs Functions Domain and Range Composition and Inverses Calculator Input and Output Transformations Quadratics Functions A function yields a specific
More informationCh6prac 1.Find the degree measure of the angle with the given radian measure. (Round your answer to the nearest whole number.) -2
Ch6prac 1.Find the degree measure of the angle with the given radian measure. (Round your answer to the nearest whole number.) -2 2. Find the degree measure of the angle with the given radian measure.
More informationChapter 6. Trigonometric Functions of Angles. 6.1 Angle Measure. 1 radians = 180º. π 1. To convert degrees to radians, multiply by.
Chapter 6. Trigonometric Functions of Angles 6.1 Angle Measure Radian Measure 1 radians 180º Therefore, o 180 π 1 rad, or π 1º 180 rad Angle Measure Conversions π 1. To convert degrees to radians, multiply
More informationChapter 5: Trigonometric Functions of Angles Homework Solutions
Chapter : Trigonometric Functions of Angles Homework Solutions Section.1 1. D = ( ( 1)) + ( ( )) = + 8 = 100 = 10. D + ( ( )) + ( ( )) = + = 1. (x + ) + (y ) =. (x ) + (y + 7) = r To find the radius, we
More informationSection 5.1 Exercises
Section 5.1 Circles 79 Section 5.1 Exercises 1. Find the distance between the points (5,) and (-1,-5). Find the distance between the points (,) and (-,-). Write the equation of the circle centered at (8,
More information15 x. Substitute. Multiply. Add. Find the positive square root.
hapter Review.1 The Pythagorean Theorem (pp. 3 70) Dynamic Solutions available at igideasmath.com Find the value of. Then tell whether the side lengths form a Pythagorean triple. c 2 = a 2 + b 2 Pythagorean
More information1.1 Find the measures of two angles, one positive and one negative, that are coterminal with the given angle. 1) 162
Math 00 Midterm Review Dugopolski Trigonometr Edition, Chapter and. Find the measures of two angles, one positive and one negative, that are coterminal with the given angle. ) ) - ) For the given angle,
More informationChapter 2: Trigonometry
Chapter 2: Trigonometry Section 2.1 Chapter 2: Trigonometry Section 2.1: The Tangent Ratio Sides of a Right Triangle with Respect to a Reference Angle Given a right triangle, we generally label its sides
More information(c) cos Arctan ( 3) ( ) PRECALCULUS ADVANCED REVIEW FOR FINAL FIRST SEMESTER
PRECALCULUS ADVANCED REVIEW FOR FINAL FIRST SEMESTER Work the following on notebook paper ecept for the graphs. Do not use our calculator unless the problem tells ou to use it. Give three decimal places
More informationMath 175: Chapter 6 Review: Trigonometric Functions
Math 175: Chapter 6 Review: Trigonometric Functions In order to prepare for a test on Chapter 6, you need to understand and be able to work problems involving the following topics. A. Can you sketch an
More informationS O H C A H T O A i p y o d y a p d n p p s j p n p j
The Unit Circle Right Triangle Trigonometry Hypotenuse Opposite Side Adjacent Side S O H C A H T O A i p y o d y a p d n p p s j p n p j sin opposite side hypotenuse csc hypotenuse opposite side cos adjacent
More informationThe No Calculators Pages
Trigonometry Summer 2005 Name: The No Calculators Pages Instructions: See front page for general instructions. Finish this page before going to the rest. You may not return to this page once you turn on
More informationI. Degrees and Radians minutes equal 1 degree seconds equal 1 minute. 3. Also, 3600 seconds equal 1 degree. 3.
0//0 I. Degrees and Radians A. A degree is a unit of angular measure equal to /80 th of a straight angle. B. A degree is broken up into minutes and seconds (in the DMS degree minute second sstem) as follows:.
More informationGiven an arc of length s on a circle of radius r, the radian measure of the central angle subtended by the arc is given by θ = s r :
Given an arc of length s on a circle of radius r, the radian measure of the central angle subtended by the arc is given by θ = s r : To convert from radians (rad) to degrees ( ) and vice versa, use the
More informationGiven an arc of length s on a circle of radius r, the radian measure of the central angle subtended by the arc is given by θ = s r :
Given an arc of length s on a circle of radius r, the radian measure of the central angle subtended by the arc is given by θ = s r : To convert from radians (rad) to degrees ( ) and vice versa, use the
More informationUnit 3 Right Triangle Trigonometry - Classwork
Unit 3 Right Triangle Trigonometry - Classwork We have spent time learning the definitions of trig functions and finding the trig functions of both quadrant and special angles. But what about other angles?
More informationCore Mathematics 2 Trigonometry
Core Mathematics 2 Trigonometry Edited by: K V Kumaran Email: kvkumaran@gmail.com Core Mathematics 2 Trigonometry 2 1 Trigonometry Sine, cosine and tangent functions. Their graphs, symmetries and periodicity.
More informationTriangles and Vectors
Chapter 3 Triangles and Vectors As was stated at the start of Chapter 1, trigonometry had its origins in the study of triangles. In fact, the word trigonometry comes from the Greek words for triangle measurement.
More informationSection 6.5 Modeling with Trigonometric Functions
Section 6.5 Modeling with Trigonometric Functions 441 Section 6.5 Modeling with Trigonometric Functions Solving right triangles for angles In Section 5.5, we used trigonometry on a right triangle to solve
More information1.1 Angles and Degree Measure
J. Jenkins - Math 060 Notes. Angles and Degree Measure An angle is often thought of as being formed b rotating one ra awa from a fied ra indicated b an arrow. The fied ra is the initial side and the rotated
More informationMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Exam Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Use the appropriate identity to find the indicated function value. Rationalize the denominator,
More informationChapter 1: Analytic Trigonometry
Chapter 1: Analytic Trigonometry Chapter 1 Overview Trigonometry is, literally, the study of triangle measures. Geometry investigated the special significance of the relationships between the angles and
More informationAs we know, the three basic trigonometric functions are as follows: Figure 1
Trigonometry Basic Functions As we know, the three basic trigonometric functions are as follows: sin θ = cos θ = opposite hypotenuse adjacent hypotenuse tan θ = opposite adjacent Where θ represents an
More informationCrash Course in Trigonometry
Crash Course in Trigonometry Dr. Don Spickler September 5, 003 Contents 1 Trigonometric Functions 1 1.1 Introduction.................................... 1 1. Right Triangle Trigonometry...........................
More informationSect 7.4 Trigonometric Functions of Any Angles
Sect 7.4 Trigonometric Functions of Any Angles Objective #: Extending the definition to find the trigonometric function of any angle. Before we can extend the definition our trigonometric functions, we
More informationRecall from Geometry the following facts about trigonometry: SOHCAHTOA: adjacent hypotenuse. cosa =
Chapter 1 Overview Trigonometry is, literally, the study of triangle measures. Geometry investigated the special significance of the relationships between the angles and sides of a triangle, especially
More information1. For Cosine Rule of any triangle ABC, b² is equal to A. a² - c² 4bc cos A B. a² + c² - 2ac cos B C. a² - c² + 2ab cos A D. a³ + c³ - 3ab cos A
1. For Cosine Rule of any triangle ABC, b² is equal to A. a² - c² 4bc cos A B. a² + c² - 2ac cos B C. a² - c² + 2ab cos A D. a³ + c³ - 3ab cos A 2. For Cosine Rule of any triangle ABC, c² is equal to A.
More information8.1 Solutions to Exercises
Last edited 9/6/17 8.1 Solutions to Exercises 1. Since the sum of all angles in a triangle is 180, 180 = 70 + 50 + α. Thus α = 60. 10 α B The easiest way to find A and B is to use Law of Sines. sin( )
More informationUnit #17: Spring Trig Unit. A. First Quadrant Notice how the x-values decrease by while the y-values increase by that same amount.
Name Unit #17: Spring Trig Unit Notes #1: Basic Trig Review I. Unit Circle A circle with center point and radius. A. First Quadrant Notice how the x-values decrease by while the y-values increase by that
More informationTrigonometric Functions. Concept Category 3
Trigonometric Functions Concept Category 3 Goals 6 basic trig functions (geometry) Special triangles Inverse trig functions (to find the angles) Unit Circle: Trig identities a b c The Six Basic Trig functions
More informationUnit 3 Trigonometry Note Package. Name:
MAT40S Unit 3 Trigonometry Mr. Morris Lesson Unit 3 Trigonometry Note Package Homework 1: Converting and Arc Extra Practice Sheet 1 Length 2: Unit Circle and Angles Extra Practice Sheet 2 3: Determining
More informationPractice Questions for Midterm 2 - Math 1060Q - Fall 2013
Eam Review Practice Questions for Midterm - Math 060Q - Fall 0 The following is a selection of problems to help prepare ou for the second midterm eam. Please note the following: anthing from Module/Chapter
More informationPre Calc. Trigonometry.
1 Pre Calc Trigonometry 2015 03 24 www.njctl.org 2 Table of Contents Unit Circle Graphing Law of Sines Law of Cosines Pythagorean Identities Angle Sum/Difference Double Angle Half Angle Power Reducing
More informationWe can use the Pythagorean Theorem to find the distance between two points on a graph.
Chapter 5: Trigonometric Functions of Angles In the previous chapters, we have explored a variety of functions which could be combined to form a variety of shapes. In this discussion, one common shape
More informationPre-AP Geometry 8-2 Study Guide: Trigonometric Ratios (pp ) Page! 1 of! 14
Pre-AP Geometry 8-2 Study Guide: Trigonometric Ratios (pp 541-544) Page! 1 of! 14 Attendance Problems. Write each fraction as a decimal rounded to the nearest hundredths. 2 7 1.! 2.! 3 24 Solve each equation.
More informationOctober 15 MATH 1113 sec. 51 Fall 2018
October 15 MATH 1113 sec. 51 Fall 2018 Section 5.5: Solving Exponential and Logarithmic Equations Base-Exponent Equality For any a > 0 with a 1, and for any real numbers x and y a x = a y if and only if
More informationMATH 2412 Sections Fundamental Identities. Reciprocal. Quotient. Pythagorean
MATH 41 Sections 5.1-5.4 Fundamental Identities Reciprocal Quotient Pythagorean 5 Example: If tanθ = and θ is in quadrant II, find the exact values of the other 1 trigonometric functions using only fundamental
More informationFundamentals of Mathematics (MATH 1510)
Fundamentals of Mathematics () Instructor: Email: shenlili@yorku.ca Department of Mathematics and Statistics York University March 14-18, 2016 Outline 1 2 s An angle AOB consists of two rays R 1 and R
More informationJUST THE MATHS SLIDES NUMBER 3.1. TRIGONOMETRY 1 (Angles & trigonometric functions) A.J.Hobson
JUST THE MATHS SLIDES NUMBER 3.1 TRIGONOMETRY 1 (Angles & trigonometric functions) by A.J.Hobson 3.1.1 Introduction 3.1.2 Angular measure 3.1.3 Trigonometric functions UNIT 3.1 - TRIGONOMETRY 1 - ANGLES
More information25 More Trigonometric Identities Worksheet
5 More Trigonometric Identities Worksheet Concepts: Trigonometric Identities Addition and Subtraction Identities Cofunction Identities Double-Angle Identities Half-Angle Identities (Sections 7. & 7.3)
More informationSpecial Angles 1 Worksheet MCR3U Jensen
Special Angles 1 Worksheet 1) a) Draw a right triangle that has one angle measuring 30. Label the sides using lengths 3, 2, and 1. b) Identify the adjacent and opposite sides relative to the 30 angle.
More informationPrecalculus Lesson 6.1: Angles and Their Measure Lesson 6.2: A Unit Circle Approach Part 2
Precalculus Lesson 6.1: Angles and Their Measure Lesson 6.2: A Unit Circle Approach Part 2 Lesson 6.2 Before we look at the unit circle with respect to the trigonometric functions, we need to get some
More informationUNIT 5 SIMILARITY, RIGHT TRIANGLE TRIGONOMETRY, AND PROOF Unit Assessment
Unit 5 ircle the letter of the best answer. 1. line segment has endpoints at (, 5) and (, 11). point on the segment has a distance that is 1 of the length of the segment from endpoint (, 5). What are the
More informationPre-Calc Trigonometry
Slide 1 / 207 Slide 2 / 207 Pre-Calc Trigonometry 2015-03-24 www.njctl.org Slide 3 / 207 Table of Contents Unit Circle Graphing Law of Sines Law of Cosines Pythagorean Identities Angle Sum/Difference Double
More informationTrigonometric Functions and Triangles
Trigonometric Functions and Triangles Dr. Philippe B. Laval Kennesaw STate University Abstract This handout defines the trigonometric function of angles and discusses the relationship between trigonometric
More information