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1 Exact Change (108624) Due: Mon Nov :1 AM MST Question Instructions Read today's Notes and Learning Goals Nearly every problem requires graphing and shading. Expect penalty scored multiple choice questions about your graphs.
2 1. Question Details Exact Change 1 Sp 14 [0870] An object moves along the y axis. Its velocity is dy dt with y in meters and t in seconds. 1. Graph the velocity data on the domain [0,4]. 2. Compute the exact value of Δy on the time interval 0 t 2 seconds. Δy = = 10 5t. Shade an area in your graph that matches your computation of Δy. 4. Answer these questions. (One try only!) The correct shaded region has the shape of a Triangle Rectangle The correct shaded region is located Below the t axis Above the t axis
3 2. Question Details Exact Change 2 Sp 14 [08704] An object moves along the y axis. Its velocity is dy dt = 10 5t with y in meters and t in seconds. 1. Graph the velocity data on the domain [0,4]. 2. Compute the exact value of the integral. Include units. 4 (10 5t) dt = 2. Shade an area in your graph that matches your computation. 4. Answer these questions. (One try only!) The correct shaded region has the shape of a Rectangle Triangle The correct shaded region is located Above the t axis Below the t axis
4 . Question Details Exact Change Sp 14 [08705] An object moves along the y axis. Its velocity is dy dt = 10 5t with y in meters and t in seconds. 1. Graph the velocity data on the domain [0,4]. 2. Compute the exact value of the integral. This time you don't need units. (10 5t) dt = 1. Shade an area in your graph that matches your computation. If your graph is correct, it will look like one of the choices below. Which one? Penalty scored. Lose 1/2 point for each wrong answer.
5
6 4. Question Details Exact Change 4 Sp 14 [08706] The voltage in a circuit is changing at a rate of 240t 120 volts/sec. 1. Graph the rate of change data on the domain [0,1]. 2. Compute the exact value of the integral. Include units (240t 120) dt = 0. Shade an area in your graph that matches your computation. 4. Which sentence most accurately describes your shaded area? Penalty scored. Lose 1/2 point for each wrong answer. There is only negative area. There is more negative area than positive area. There is only positive area. There is more positive area than negative area.
7 5. Question Details Exact Change 5 Sp 14 [08707] The voltage in a circuit is changing at a rate of 240t 120 volts/sec. 1. Graph the rate of change data on the domain [0,1]. 2. Compute the exact change in voltage on the time interval 0.8 t 0.9 seconds. Include units. Total change =. Shade an area in your graph that matches your computation. 4. Which phrase most accurately describes the shape of your shaded area? Penalty scored. Lose 1/2 point for each wrong answer. A square. A tall, thin rectangle. A triangle. A tall, thin trapezoid.
8 6. Question Details Exact Change 8 Sp 14 [08708] The height of a moving object is a function of time, h(t), with h in meters and t in seconds. The velocity of the object is graphed below. Find exact answers for the following. Include units. 9 h'(t) dt = Δh on [9,12] = 12 h'(t) dt = Δh on [0,9] =
9 7. Question Details FA14 Signed Area Sums 2 [16909] Suppose the rate of change of the height of a moving object, v(t) = dh dt graph. The area of each of the shaded regions is given in the graph., measured in feet per second is given by the following 1. What is the total change in height on the interval [a, b]? 2. What is Δh on the interval [a, d]?. Compute g v(t) dt d 4. Compute v(t) dt f c
10 8. Question Details Graph Int Est 1 [1779] Graph the function v(t) = t cos πt on the interval [, ]. 2 a. Shade an area that exactly matches v(t) dt. b. Which statement is true? This is penalty scored. v(t) dt > 0 v(t) dt < 0 v(t) dt = 0
11 9. Question Details Graph Int Est 2 [17794] Graph the function v(t) = t cos πt on the interval [, ]. 2 a. Shade an area that exactly matches 1 v(t) dt. b. Which statement is true? This is penalty scored. 1 v(t) dt > 0 1 v(t) dt < 0 1 v(t) dt = Question Details Graph Int Est [17795] Graph the function v(t) = t cos πt on the interval [, ]. 2 a. Shade an area that exactly matches v(t) dt. 0 b. Which statement is true? This is penalty scored. v(t) dt > 0 0 v(t) dt < 0 0 v(t) dt = 0 0
12 11. Question Details Integral Answer 4 Fall 14 [17799] The pressure in a cylinder is a function of time, P(t), with P in kpa and t in minutes. The rate of change of P is dp 200 = kpa/min dt (t+1) 2 The change in pressure on the time interval 2 t 8 minutes is given by an integral, ΔP = Compute ΔP, accurate to ±0.5 kpa. This is hard to compute exactly. If you use rectangles to approximate the answer you may need more than 100 rectangles to meet the accuracy requirement. You should explore calculator or computer options. ΔP = (t+1) 2 dt Assignment Details Name (AID): Exact Change (108624) Submissions Allowed: 100 Category: Homework Code: Locked: Yes Author: Velasquez, Elena ( elenavelasquez@boisestate.edu ) Last Saved: Aug 15, :09 AM MDT Group: BSU Calculus Randomization: Assignment Which graded: Last Feedback Settings Before due date Question Score Assignment Score Publish Essay Scores Question Part Score Mark Help/Hints Response Save Work After due date Question Score Assignment Score Publish Essay Scores Key Question Part Score Solution Mark
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