The Simplest Proof of Fermat Last Theorem(1)
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1 The Smplest roof of Fermat Last Theorem( Chun-Xuan Jang. O. Bo 39, Beng 0085,. R. Chna Abstract In 637 Fermat wrote: It s mpossble to separate a cube nto two cubes, or a bquadrate nto two bquadrates, or n general any power hgher than the second nto powers of lke degree: I have dscovered a truly marvelous proof, whch ths margn s too small to contan. n n n Ths means: y z ( n has no nteger solutons, all dfferent from 0(.e., t has only the trval soluton, where one of the ntegers s equal to 0. It has been called Fermat s last theorem (FLT. It suffces to prove FLT for eponent and every prme eponent. Fermat proved FLT for eponent. Euler proved FLT for eponent 3. In ths paper usng automorphc functons we prove FLT for eponents and, where s an odd prme. We redscover the Fermat proof. The proof of FLT must be drect. But ndrect proof of FLT s dsbelevng. Theorem:The smplest proof of Fermat last theorem.we have Fermat equaton y z, where s odd prme. We prove that f y and z are nteger numbers then, and are rratonal numbers. In 97 Jang found out Euler formula of the cyclotomc real numbers n the cyclotomc felds ep where J denotes a m th root of unty, S m m tj SJ, ( m J, m=,,3,, t are the real numbers. s called the automorphc functons(comple hyperbolc functons of order m wth m varables [,5,7]. ( ( cos cos m m A H B S e e e m
2 ( m ( A D ( e e cos m m ( where,...,m; m m A t, A t(, H t (, t ( m m B t cos, t sn, m m D t ( cos, t( sn, m m m m m m, m A A H ( B D 0. (3 From ( we have ts nverse transformaton[5,7] m m A A, ( e S e S m m H H e cos S (, e sn S (, B e cos S S cos, e sn S sn m m m B m, D e cos S S ( cos, e sn S ( sn m m m D m. ( (3 and ( have the same form. From (3 we have m ep A A H ( B D From ( we have S S S m m S S S3 ep A A H ( B D S S S m m (5
3 where S ( S [7] t S ( S ( S m S ( S ( S m S ( S ( S m m m m (6 From (5 and (6 we have crculant determnant S S S m S S S m 3 ep A A H ( B D S S S m m (7 Assume S 0, S 0, S 0, where 3,..., m. S 0 are (m ndetermnate equatons wth (m varables. From ( we have A A H e SS, e SS, e S S B D e S S SScos, e S S SScos (8 m m Eample []. Let m. From (3 we have A ( tt ( t t0 ( t3t9 ( t t8 ( t5 t7 t 6, A ( t t ( t t ( t t ( t t ( t t t 6, H ( t t ( t t t, B ( ttcos ( t t0cos ( t3 t9cos ( t t8cos ( t5 t7cos t6, B ( tt cos ( t t0 cos ( t3t9 cos ( t t8 cos ( t5 t7 cos t6, 3 5 D ( tt cos ( t t0 cos ( t3t9 cos ( t t8cos ( t5 t7 cos t6, D ( ttcos ( t t0cos ( t3t9cos ( t t8cos ( t5 t7cos t6, A A ( H BB DD 0, A B 3( t3 t6 t9. (9 From (8 and (9 we have 3 3 ep[ A A ( H B B D D ] S S ( S ( S. (0 From (9 we have 3
4 3 ep( A B [ep( t t t ]. ( From (8 we have ep( A B ( S S ( S S S S S S. ( 3 From ( and ( we have Fermat s equaton ep( A B S S [ep( t t t ] 3. ( Fermat proved that (0 has no ratonal solutons for eponent [8]. Therefore we prove we prove that (3 has no ratonal solutons for eponent 3. [] Theorem. Let m, where s an odd prme, ( / s an even number. From (3 and (8 we have From (3 we have From (8 we have ep[ A A H ( B D ] S S ( S ( S. ( ep[ A ( B D ] [ep( t t t3 ]. (5 S ep[ A ( B D ] S From (5 and (6 we have Fermat s equaton 3. (6 3 ep[ A ( B D ] S S [ep( t t t ]. (7 Fermat proved that ( has no ratonal solutons for eponent [8]. Therefor we prove that (7 has no ratonal solutons for prme eponent. Theorem.The smplest proof of Fermat last theorem. We have the Fermat equaton y z (8 where s the odd prme. We rewrte (8 ( ( y ( z. (9 Fermat proved that (9 has no nteger solutons for eponent. We assume that y and z are nteger numbers, y and z also are nteger numbers. We have and are rratonal
5 numbers. Therefore we prove (8 has no nteger solutons We rewrte (8 ( ( y ( z (0 We assume that y and z are nteger numbers, y and z also are nteger numbers. From theorem we prove s rratonal number, also s rratonal number. Therefore we prove (0 has no nteger solutons for prme eponent. Concluson.In(8 we prove that f y and then, and are rratonal numbers.. z are nteger numbers References [] Jang, C-X, Fermat last theorem had been proved, otental Scence (n Chnese,.7-0 (99, reprnts (n Englsh December (99. [] Jang, C-X, Fermat last theorem had been proved by Fermat more than 300 years ago, otental Scence (n Chnese, 6.8-0(99. [3] Jang, C-X, On the factorzaton theorem of crculant determnant, Algebras, Groups and Geometres, (99, MR. 96a: 03, [] Jang, C-X, Fermat last theorem was proved n 99, reprnts (993. In: Fundamental open problems n scence at the end of the mllennum, T.Gll, K. Lu and E. Trell (eds. Hadronc ress, 999, [5] Jang, C-X, On the Fermat-Santll theorem, Algebras, Groups and Geometres, (998 [6] Jang, C-X, Comple hyperbolc functons and Fermat s last theorem, Hadronc Journal Supplement, (000. [7] Jang, C-X, Foundatons of Santll Isonumber Theory wth applcatons to new cryptograms, Fermat s theorem and Goldbach s Conecture. Inter. Acad. ress. 00. MR00c:00, [8] Rbenbom,. Fermat last theorem for amateur,sprnger-verlag(999. 5
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