CHERRY HILL TUITION OCR A CHEMISTRY A2 PAPER 19 MARK SCHEME ANNOTATIONS MUST BE USED CH 3 CH 3 CH 3 H + correct products

Size: px
Start display at page:

Download "CHERRY HILL TUITION OCR A CHEMISTRY A2 PAPER 19 MARK SCHEME ANNOTATIONS MUST BE USED CH 3 CH 3 CH 3 H + correct products"

Transcription

1 ERRY ILL TUITIN R A EMISTRY A2 PAPER 19 MARK SEME ALLW Kekulé structures throughout 1 (a) ANNTATINS MUST BE USED ALLW skeletal ALLW + + N 2 R N 2 ALLW 1st curly arrow from the ring R from within the ring to any part of the N + 2 including the + charge + + D NT ALLW intermediate with broken ring less than halfway down: N 2 N 2 N 2 curly arrow from ring to N 2 + correct intermediate curly arrow from bond back to reform ring 1 mark for intermediate correct products 4 + N 2 orseshoe must have open end towards N 2 ALLW Kekulé mechanism: 1 mark for curly arrow N + 2 N 2 N 2 ALLW double bonds shown in other Kekulé arrangement IF has been omitted completely (ie benzene shown), D NT AWARD intermediate mark R products mark (max 2) IF N 2 is shown in incorrect position in intermediate or product, D NT AWARD intermediate mark but award other marks (max 3) 1

2 ERRY ILL TUITIN R A EMISTRY A2 PAPER 19 MARK SEME 1 (b ) ALLW any correct unambiguous structures N 2 ALLW N 2 Note: connectivity is NT being assessed in this part 2 N N 2 N (c) 1st stage isomer: isomer 3 product: 2 N N 2 reagents: Sn AND (conc) l equation: ANNTATINS MUST BE USED ALLW structure of isomer 3 shown separately R in equation ALLW structure of product shown separately R in equation ALLW correct name (3,5-diaminomethylbenzene) IGNRE incorrect name D NT ALLW 6 3 (N 2 ) 2 ALLW Zn + l/ 2 + metal catalyst/lial 4 /Na in ethanol IGNRE NaB 4 ALLW Sn and l followed by Na D NT ALLW Sn and l and Na 12 [] 4 2 IF isomer 3 R product are given in equation but not shown previously then credit here 2 N N 2 2 N N 2 Also credit reagents here if shown (eg above arrow) ALLW correct structural R displayed R skeletal formula ALLW combination of formulae as long as unambiguous 2

3 ERRY ILL TUITIN R A EMISTRY A2 PAPER 19 MARK SEME (c) (i) 2nd stage organic compound: 2 6 D NT ALLW molecular formula ALLW name of compound: propanedioic acid R propane-1,3-dioic acid ALLW absence of e after propan ALLW acyl dichloride: l 2 l ALLW cyclic acid anhydride of propanedioic acid: 2 type of polymer: polyamide ALLW Nylon or Kevlar D NT ALLW polypeptide D NT ALLW amide Total 12 3

4 ERRY ILL TUITIN R A EMISTRY A2 PAPER 19 MARK SEME 2 (a) propane-1,2,3-triol 1 ALLW absence of e after propan ALLW 1,2,3-propanetriol ALLW absence of hyphens 1, 2 and 3 must be clearly separated: ALLW full stops: R spaces: D NT ALLW (b) (i) methanol R ethanol AND renewable 1 BT points required for the mark ALLW correct structural R displayed R skeletal formula D NT ALLW molecular formulae ALLW easy/cheap to manufacture/produce as alternative for renewable/from plants/from fermentation/burns more easily/efficiently (b) (ii) equilibrium shifts to right 1 ALLW equilibrium shifts in forward direction ALLW more products form ALLW greater yield R fully reacts R goes to completion D NT ALLW improves atom economy 4

5 ERRY ILL TUITIN R A EMISTRY A2 PAPER 19 MARK SEME 2 (c) ALLW correct structural R displayed R skeletal formula ALLW combination of formulae as long as unambiguous D NT ALLW molecular formulae ( 2 ) ALLW further esterification, ie ( 2 ) ALLW linear formula for anhydride, ie 2 2 If incorrect carboxylic acid/anhydride/alcohol is used, ALLW EF for second equation 5

6 ERRY ILL TUITIN R A EMISTRY A2 PAPER 19 MARK SEME 2 (d) A B Mark A, B and independently ie 2 column column R R R R R R R R R R R R Total 8 A can be any of the alternatives in the 1st B can be any of the alternatives in the 2nd can be any of the alternatives in the 3rd column ALLW correct structural R displayed R skeletal formula ALLW combination of formulae as long as unambiguous D NT ALLW molecular formulae ALLW correct names for A, B and For B accept diester For, IGNRE n R brackets (even if wrong); ALLW solid side bonds Minimum is one correct repeat unit. Polymer must be open at both ends 6

7 ERRY ILL TUITIN R A EMISTRY A2 PAPER 19 MARK SEME 3 (a) observation: silver R Ag ALLW black R grey type of reaction: oxidation ALLW redox organic product: 3 3 ALLW correct structural R displayed R skeletal formula ALLW combination of formulae as long as unambiguous D NT ALLW molecular formulae ALLW carboxylate, 3 (b) R R intermediate R products (+ ANNTATINS MUST BE USED ALLW mechanism showing curly arrows from lone pair on and of intermediate 1 mark for curly arrow from to of = 1 mark for correct dipole on = AND curly arrow from double bond to 1 mark for correct intermediate with negative charge on AND curly arrow from to of AND curly arrow from to of 1 mark for correct organic product 4 Dipole not required on D NT ALLW incorrect dipole on ALLW 1 mark for correct intermediate with charge on AND curly arrow from to + IGNRE missing D NT ALLW incorrect second product 7

8 ERRY ILL TUITIN R A EMISTRY A2 PAPER 19 MARK SEME 3 (c) reagent: 2 D NT ALLW EF from incorrect reagent, eg 2,4-DNP observation: decolourised R orange to colourless D NT ALLW goes clear ALLW red/orange/yellow/brown in any combination organic product: 3 3 ALLW organic product from reaction of one of the double bonds only, ie 3 3 R ALLW correct structural R displayed R skeletal formula ALLW combination of formulae as long as unambiguous D NT ALLW molecular formulae ALTERNATIVE reagents For 1st mark, ALLW 2 R l 2 R I 2 R l R R I R 2 For 2nd mark, there must be a statement of no change R no observation or similar that implies there is no visible change EXEPT for I 2 which has an observation of decolourised R brown to colourless Total 10 For 3rd mark, correct organic product must be shown that could be from reaction of both or one of the double bonds. 8

9 ERRY ILL TUITIN R A EMISTRY A2 PAPER 19 MARK SEME 4 (a) (i) l( ) + 3N 3 2 N( ) + N N 4 l 1 ALLW use of two N 3 : l( ) + 2N 3 2 N( ) + N l ALLW products as above R 2 N( ) + N 4 l ALLW use of one N 3 : l( ) + N 3 2 N( ) l ALLW products as above R 2 N( ) + l For alternatives below, for N 4 l, ALLW N 4 + l R N l for l, ALLW + l R + + l for 2 N( ) + N 4 + ALLW 2 N( ) N 4 + R 2 N( )N 4 ALLW R in equation in place of (either or both sides) ALLW correct structural R displayed R skeletal formula ALLW combination of formulae as long as unambiguous D NT ALLW molecular formulae (a) (ii) N ALLW correct structural R displayed R skeletal formula ALLW combination of formulae as long as unambiguous 1 ALLW product from carboxylate ion as nucleophile: 2 N 9

10 ERRY ILL TUITIN R A EMISTRY A2 PAPER 19 MARK SEME 4 (b) (i) R D NT ALLW any structure containing R (except in ) 1 (b) (ii) 2 2 ALL bond linkages must be correct, eg the chiral must be linked to the of the, the of the 2 and the N of the N 2 (connectivity is being tested) 2 N N 2 2 The 2nd mark is for the mirror image of an amino acid. This could be any amino acid EXEPT glycine D NT penalise connectivity more than once ALLW R in equation in place of 2 (either or both sides) Each structure must have four central bonds, with at least two wedges, one in; one out For bond into paper, accept: 4 (c) Disadvantages Any two from: (one stereoisomer might have harmful) side effects reduces the (pharmacological) activity/effectiveness cost R difficulty in separating stereoisomers 2 max ANNTATINS MUST BE USED ALLW optical isomer R enantiomers as alternative for stereoisomers ALLW a response that implies an increased dose Synthesis of a single optical isomer Any two from: using enzymes or bacteria using a chiral catalyst R transition metal complex/transition metal catalyst using chiral synthesis R chiral starting material R natural amino acid 2 max Total 8 ALLW biological catalyst ALLW 'chiral pool' R L-amino acids R D-sugars 10

11 ERRY ILL TUITIN R A EMISTRY A2 PAPER 19 MARK SEME 5 (a) (i) Adsorption (onto the stationary phase) ALLW adsorbtion or adsorb(s) or adsorbed spelled correctly at least once Quality of Written ommunication 1 D NT ALLW anything that begins with ab... Adsorption must be spelled correctly (a) (ii) ALLW any value in the range IGNRE significant figures D NT ALLW fraction/percent as final answer (a) (iii) Spot may contain more than one compound/component 1 ALLW compounds have similar R f values/adsorptions R compounds have not (fully) separated R B is spread over a large region R compounds are similar IGNRE retention times 5 (b) (i) G separates the components/compounds ALLW chromatography for G ALLW they have different retention times (ii) (iii) (iv) AND MS is compared to a database/reference 1 nerol and geraniol AND they are stereoisomers R primary alcohols 1 stereoisomers have the same structural formula AND different 3D arrangements 1 1 ALLW MS analyses compounds/gives structural information/gives different mass spectra ALLW (uses) fragmentation patterns/fragments/peaks/parts of the compound D NT ALLW MS identifies compounds (in question) D NT ALLW molecular ion alone/m r etc. ompounds AND reason required for the mark ALLW they are E/Z isomers R cis-trans isomers ALLW straight-chain alcohols R unsaturated alcohols BT points required for the mark ALLW different arrangements in space ircle must include the correct = double bond AND must not extend further than the adjacent atoms in the main chain, ie limit is: 11

12 ERRY ILL TUITIN R A EMISTRY A2 PAPER 19 MARK SEME 5 (c) (b) (v) * * * orrectly calculates amount of myrcene = 34/136 R 0.25 (mol) orrectly calculates 60% yield of menthol = /100 R 0.15 (mol) 2 orrectly calculates mass of menthol = = 23.4 (g) 3 ALL TREE chiral centres required for 2 marks ANY TW chiral centres required for 1 mark If more than three asterisks are shown, mark incorrect asterisk(s) first ANNTATINS MUST BE USED ALLW amount of myrcene 60/100 ALLW amount of menthol 156 ALLW alternative approach based on reacting masses (using same EF principles as above): correctly calculates mass of myrcene that could be obtained from 34 g myrcene: mass = /136 = 39 (g) 156 ; % of 39 g = 39 60/100 = 23.4 (g) ALLW final answer to 2 or more significant figures correctly rounded orrect answer of 23.4 (g) with no working scores all 3 marks Total 12 12

13 ERRY ILL TUITIN R A EMISTRY A2 PAPER 19 MARK SEME 6 (a) ANNTATINS MUST BE USED a singlet for position 2 R a singlet because it has no adjacent s A triplet for positions 4 and 6 R a triplet because it has 2 adjacent s A quintet for position 5 R a quintet because it has four adjacent s 3 ALLW a response that implies a single peak R no splitting ALLW a response that implies a splitting into three D NT ALLW implications of more than one triplet ALLW pentet R a response that implies a splitting into five R multiplet ALLW 1 mark for singlet and triplet and quintet/pentet/multiplet with no identification of protons Any suggestion that the oxygens cause a splitting scores a maximum of 2 marks. All 3 remaining splitting patterns correct 2 marks. Any 2 correct 1 mark. IF number labels for protons in diagram are not identified, ALLW identification by chemical shifts for 2 marks max: singlet at AND a triplet at quintet/pentet/multiplet at lear and unambiguous identification of the protons other than by position number should be credited, ie 2 between two oxygens Quality of Written ommunication singlet R triplet R quintet R pentet R multiplet (see Guidance) must be spelled correctly at least once 13

14 ERRY ILL TUITIN R A EMISTRY A2 PAPER 19 MARK SEME F324 Mark Scheme January (b) ANY 5 marks plus correct structure (in box) ANNTATINS MUST BE USED Molecular ion/m + peak at (m/z of) 106 Fragment peak at 91 is / ALLW molecular mass R relative molecular mass ALLW 6 4 / ALLW peak at 91 represents loss of Molecular formula is 8 10 (or implied, ie any one of the structures below) 2 5 ALLW correct structural R displayed R skeletal formula ALLW combination of formulae as long as unambiguous ALLW a correct name eg a dimethylbenzene ALL FUR structures needed for 1 mark ALLW correct names 13 NMR spectrum shows 5 environments Peak near 20 is a attached at another carbon, R peaks at ~ for aromatic s ALLW NMR spectrum shows five different types of carbon D NT ALLW NMR spectrum has five peaks the mark is for realising what the peaks show, not for just describing the spectrum 14 14

15 ERRY ILL TUITIN R A EMISTRY A2 PAPER 19 MARK SEME Mark Scheme January (b) Number of peaks for other three isomers matched to structures: Any 2 correct for 2 marks 1 correct for 1 mark peaks 3 peaks 6 peaks ALLW carbon environments for peaks orrect structure shown: 6 Total

1 (a) (CH 3 CO) 2 O + CH 3 CH(OH)CH 3 CH 3 COOCH(CH 3 ) 2 + CH 3 COOH

1 (a) (CH 3 CO) 2 O + CH 3 CH(OH)CH 3 CH 3 COOCH(CH 3 ) 2 + CH 3 COOH Question er Mark Guidance 1 (a) ( 3 ) 2 + 3 () 3 3 ( 3 ) 2 + 3 1st mark orrect structure of ester: 3 ( 3 ) 2 2nd mark Equation contains correct formulae for ( 3 ) 2, 3 () 3 AND 3 2 ALLW correct structural

More information

ALLOW CO 2 and CO 2 H CH 3

ALLOW CO 2 and CO 2 H CH 3 CERRY ILL TUITI CR A CEMISTRY A PAPER 1 MARK SCEME 1 (a) (i) The p R point at which the zwitterion exists 1 ALLW p/point at which there is no overall/net charge IGRE p/point at which there is no charge/

More information

ANNOTATIONS MUST BE USED

ANNOTATIONS MUST BE USED 1 (a) ATATIS MUST BE USED ALLW skeletal ALLW R ALLW 1st curly arrow from the ring R from within the ring to any part of the 2 including the charge H D T ALLW intermediate with broken ring less than halfway

More information

(b) (i) Compound B AND M + /molecular ion peak (at m/z) = 124

(b) (i) Compound B AND M + /molecular ion peak (at m/z) = 124 Answer Mark Guidance 1 (a) (Relative) solubility (in stationary phase) 1 ALLW how well the compound dissolves IGNRE retention time AND partition D NT ALLW adsorption R absorption (b) (i) Compound B AND

More information

Question Answer Marks Guidance 1 (a) M1 EITHER in words: (pyruvic acid forms) hydrogen bonds with water

Question Answer Marks Guidance 1 (a) M1 EITHER in words: (pyruvic acid forms) hydrogen bonds with water 1 (a) M1 EITER in words: (pyruvic acid forms) hydrogen bonds with water 2 R correctly labelled diagram showing hydrogen bond between pyruvic acid and water FR M1 only: if use diagram ALLW a labelled hydrogen

More information

PMT GCE. Chemistry A. Advanced GCE. Unit F324: Rings, Polymers and Analysis. Mark Scheme for January Oxford Cambridge and RSA Examinations

PMT GCE. Chemistry A. Advanced GCE. Unit F324: Rings, Polymers and Analysis. Mark Scheme for January Oxford Cambridge and RSA Examinations GCE Chemistry A Advanced GCE Unit F324: Rings, Polymers and Analysis Mark Scheme for January 2012 xford Cambridge and RSA Examinations CR (xford Cambridge and RSA) is a leading UK awarding body, providing

More information

Question Answer Mark Guidance 1 (a) monomers join/bond/add/react/form polymer/form chain AND another product/small molecule e.g.

Question Answer Mark Guidance 1 (a) monomers join/bond/add/react/form polymer/form chain AND another product/small molecule e.g. Question Answer Mark Guidance (a) monomers join/bond/add/react/form polymer/form chain AND another product/small molecule e.g. 2 /l IGNRE two when referring to monomers, ie (two) monomers... (b) (i) QW

More information

F324 Mark Scheme January 2010 F324 Rings, Polymers and Analysis. Question Expected Answers Marks Additional Guidance 1 (a)

F324 Mark Scheme January 2010 F324 Rings, Polymers and Analysis. Question Expected Answers Marks Additional Guidance 1 (a) F324 Rings, Polymers and Analysis Question Expected Answers Marks Additional Guidance 1 (a) ALLW 6 6 + Br 2 6 5 Br + Br + Br 2 Br + Br (b) (i) White precipitate R white solid R white crystals 1 D T ALLW

More information

Where circles have been placed round charges, this is for clarity only and does not indicate a requirement. ALLOW delocalised carboxylate.

Where circles have been placed round charges, this is for clarity only and does not indicate a requirement. ALLOW delocalised carboxylate. Question (a) Answer Mark Guidance Where circles have been placed round charges, this is for clarity only and does not indicate a requirement (i) ALLOW correct structural OR displayed OR skeletal formulae

More information

2 Answer all the questions.

2 Answer all the questions. ERRY ILL TUITI R A EMISTRY A2 PAPER 17 2 Answer all the questions. 1 A chemist was investigating the reactions of benzene, phenol and cyclohexene with bromine. She found that they all reacted with bromine

More information

Allow CONH- or - COHN - 1(a)(i) Mark two halves separately

Allow CONH- or - COHN - 1(a)(i) Mark two halves separately ERRY ILL TUITIN AQA EMISTRY A2 PAPER 27 MARK SEME Question Marking Guidance (a)(i) 2 2 N N 2 Mark Allow N- or - N - N 6 Mark two halves separately 2 N 6 omments lose each for missing trailing bonds at

More information

Nitrogen Compounds - MS 1. (a) (i) is an amine and a carboxylic acid / contains both NH2 and COOH functional groups (1) AW 1

Nitrogen Compounds - MS 1. (a) (i) is an amine and a carboxylic acid / contains both NH2 and COOH functional groups (1) AW 1 itrogen ompounds - MS. (a) (i) is an amine and a carboxylic acid / contains both and functional groups () AW (c) R( ) () R Does not fit the formula because and are not attached to the same carbon () AW

More information

Question Answer Mark Guidance 1 (a) (i) M1 p-orbitals overlap (to form pi/π-bonds) 4 ANNOTATE ANSWER WITH TICKS AND CROSSES ETC

Question Answer Mark Guidance 1 (a) (i) M1 p-orbitals overlap (to form pi/π-bonds) 4 ANNOTATE ANSWER WITH TICKS AND CROSSES ETC Question Answer Mark Guidance (a) (i) M p-orbitals overlap (to form pi/π-bonds) 4 ANNOTATE ANSWER WIT TICKS AND CROSSES ETC IGNORE p-orbitals overlap to form sigma bonds M2 π-bond(s) are delocalised in

More information

GCE. Chemistry. Mark Scheme for June Advanced GCE 2814/01 Chains, Rings and Spectroscopy. Oxford Cambridge and RSA Examinations

GCE. Chemistry. Mark Scheme for June Advanced GCE 2814/01 Chains, Rings and Spectroscopy. Oxford Cambridge and RSA Examinations GE hemistry Advanced GE 2814/01 hains, Rings and Spectroscopy Mark Scheme for June 2010 xford ambridge and RSA Examinations R (xford ambridge and RSA) is a leading UK awarding body, providing a wide range

More information

PMT GCE. Chemistry A. Advanced GCE Unit F324: Rings, Polymers and Analysis. Mark Scheme for January Oxford Cambridge and RSA Examinations

PMT GCE. Chemistry A. Advanced GCE Unit F324: Rings, Polymers and Analysis. Mark Scheme for January Oxford Cambridge and RSA Examinations GE hemistry A Advanced GE Unit F324: Rings, Polymers and Analysis Mark Scheme for January 2013 xford ambridge and RSA Examinations R (xford ambridge and RSA) is a leading UK awarding body, providing a

More information

PMT GCE. Chemistry A. Advanced GCE Unit F324: Rings, Polymers and Analysis. Mark Scheme for June Oxford Cambridge and RSA Examinations

PMT GCE. Chemistry A. Advanced GCE Unit F324: Rings, Polymers and Analysis. Mark Scheme for June Oxford Cambridge and RSA Examinations GCE Chemistry A Advanced GCE Unit F324: Rings, Polymers and Analysis Mark Scheme for June 2013 xford Cambridge and RSA Examinations CR (xford Cambridge and RSA) is a leading UK awarding body, providing

More information

Practice paper Set 1 MAXIMUM MARK 100. Final. H432/02 Mark Scheme Practice 1. A Level Chemistry A H432/02 Synthesis and analytical techniques

Practice paper Set 1 MAXIMUM MARK 100. Final. H432/02 Mark Scheme Practice 1. A Level Chemistry A H432/02 Synthesis and analytical techniques 432/02 Mark Scheme Practice 1 Practice paper Set 1 A Level hemistry A 432/02 Synthesis and analytical techniques MARK SEME Duration: 2 hours 15 minutes MAXIMUM MARK 100 Final This document consists of

More information

4 ALLOW sugar from equation

4 ALLOW sugar from equation Question Expected Answers Marks Additional Guidance 1 (a) method 1: fermentation of sugars or carbohydrates R reaction with yeast with sugar or carbohydrates 6 12 6 2 2 5 + 2 2 4 ALLW sugar from equation

More information

Acceptable sequence of stages are: chlorination. nitration, reduction, chlorination nitration. nitration, chlorination, reduction, reduction

Acceptable sequence of stages are: chlorination. nitration, reduction, chlorination nitration. nitration, chlorination, reduction, reduction Question er Mark Guidance 1 (a) (i) Response requires three stages Acceptable sequence of stages are: chlorination nitration, reduction, chlorination nitration nitration, chlorination, reduction, reduction

More information

GCE Chemistry A. Mark Scheme for June Unit F324: Rings, Polymers and Analysis. Advanced GCE. Oxford Cambridge and RSA Examinations

GCE Chemistry A. Mark Scheme for June Unit F324: Rings, Polymers and Analysis. Advanced GCE. Oxford Cambridge and RSA Examinations GCE Chemistry A Unit F324: Rings, Polymers and Analysis Advanced GCE Mark Scheme for June 2017 Oxford Cambridge and RSA Examinations OCR (Oxford Cambridge and RSA) is a leading UK awarding body, providing

More information

DO NOT ALLOW any reference to spatial/space

DO NOT ALLOW any reference to spatial/space Question Answer Mark Guidance 1 (a) (i) (compounds or molecules having the) same molecular 1 ALLOW different structure OR different displayed formula but different structural formulae formula OR different

More information

flowers, leaves and roots of roses rose oil heat

flowers, leaves and roots of roses rose oil heat 1 Rose oil can be extracted from the flowers, leaves and roots of roses using the apparatus below. coolant flowers, leaves and roots of roses rose oil heat (a) The rose oil contains a mixture of compounds,

More information

Tuesday 19 June 2012 Afternoon

Tuesday 19 June 2012 Afternoon Tuesday 19 June 2012 Afternoon A2 GCE CEMISTRY A F324 Rings, Polymers and Analysis *F314730612* Candidates answer on the Question Paper. CR supplied materials: Data Sheet for Chemistry A (inserted) ther

More information

CHERRY HILL TUITION OCR (SALTERS) CHEMISTRY A2 PAPER Answer all the questions. O, is formed in the soil by denitrifying bacteria. ...

CHERRY HILL TUITION OCR (SALTERS) CHEMISTRY A2 PAPER Answer all the questions. O, is formed in the soil by denitrifying bacteria. ... 2 Answer all the questions. 1 itrous oxide gas, 2, is formed in the soil by denitrifying bacteria. (a) Give the systematic name for nitrous oxide. ne model of the bonding in nitrous oxide includes a dative

More information

Advanced GCE Chemistry A

Advanced GCE Chemistry A Advanced GE hemistry A Unit F4 Rings, Polymers and Analysis Medium banded andidate Style Answer Introduction R has produced these candidate style answers to support teachers in interpreting the assessment

More information

8 (c) (i) H 2 /Ni or H 2 /Pt or Sn/HCl or Fe/HCl (conc or dil or neither) allow dil H 2 SO 4 ignore mention of NaOH

8 (c) (i) H 2 /Ni or H 2 /Pt or Sn/HCl or Fe/HCl (conc or dil or neither) allow dil H 2 SO 4 ignore mention of NaOH Polymers Answers EM4 - AQA GE hemistry Mark Scheme 200 January series 8 (c) (i) 2 /i or 2 /Pt or Sn/l or e/l (conc or dil or neither) allow dil 2 S 4 ignore mention of a ot ab 4 ot LiAl 4 ot a/ 2 5 not

More information

1 hour 45 minutes plus your additional time allowance

1 hour 45 minutes plus your additional time allowance GE A Level 1094/01 EMISTRY 4 P.M. TUESDAY, 14 June 2016 1 hour 45 minutes plus your additional time allowance Surname Other Names entre Number andidate Number 2 WJE BA Ltd. J*(S16-1094-01)MLP 2 For Examiner

More information

The amide or peptide link is found in synthetic polyamides and also in naturally-occurring proteins.

The amide or peptide link is found in synthetic polyamides and also in naturally-occurring proteins. ERRY ILL TUITIN AQA EMISTRY A2 PAPER 27 10 14 4 (a) (i) The amide or peptide link is found in synthetic polyamides and also in naturally-occurring proteins. Draw the repeating unit of the polyamide formed

More information

THIS IS A NEW SPECIFICATION

THIS IS A NEW SPECIFICATION TIS IS A EW SPEIFIATI ADVAED GE EMISTRY A Rings, Polymers and Analysis F324 * E / 1 5371* andidates answer on the Question Paper R Supplied Materials: Data Sheet for hemistry A (inserted) ther Materials

More information

Final. Mark Scheme. Chemistry CHEM4. (Specification 2420) Unit 4: Kinetics, Equilibria and Organic Chemistry

Final. Mark Scheme. Chemistry CHEM4. (Specification 2420) Unit 4: Kinetics, Equilibria and Organic Chemistry ERRY ILL TUITI AQA EMISTRY A2 PAPER 30 MARK SEME Question : /A Question 2: /A Question 3: /A General ertificate of Education (A-level) June 203 hemistry EM4 (Specification 2420) Unit 4: Kinetics, Equilibria

More information

Question Answer Mark Guidance 1 (a) (i) 4 Please use annotations (rate) molecules/particles in smaller volume OR increases concentration

Question Answer Mark Guidance 1 (a) (i) 4 Please use annotations (rate) molecules/particles in smaller volume OR increases concentration ERRY ILL TUITIN R (SALTERS) EMISTRY A2 PAPER 28 MARK SEME 1 (a) (i) 4 Please use annotations (rate) molecules/particles in smaller volume R increases concentration ALLW molecules/particles closer together

More information

Subject: Chains, Rings and Spectroscopy Code: Session: June Year: Final Mark Scheme

Subject: Chains, Rings and Spectroscopy Code: Session: June Year: Final Mark Scheme Subject: hains, Rings and Spectroscopy ode: : e : Mark Scheme MAXIMUM MARK 90 ADVIE T EXAMINERS N TE ANNTATIN F SRIPTS 1. Please ensure that you use the final version of the Mark Scheme. You are advised

More information

Mark Scheme Page 1 of 8 Unit ode 2814 Session Jan Year 2004 Qu. Expected answers: Marks: 1 (a) (i) (relative) molecular mass / M r (ii) right / highest m /e / highest mass / second highest mass etc AW

More information

PMT GCE. Chemistry A. Advanced GCE F324. Mark Scheme for June Oxford Cambridge and RSA Examinations

PMT GCE. Chemistry A. Advanced GCE F324. Mark Scheme for June Oxford Cambridge and RSA Examinations GE hemistry A Advanced GE F324 Mark Scheme for June 200 xford ambridge and RSA Examinations R (xford ambridge and RSA) is a leading UK awarding body, providing a wide range of qualifications to meet the

More information

A mass spectrometer can be used to distinguish between samples of butane and propanal. The table shows some precise relative atomic mass values.

A mass spectrometer can be used to distinguish between samples of butane and propanal. The table shows some precise relative atomic mass values. Butane and propanal are compounds with M r = 58.0, calculated using data from your Periodic Table. (a) A mass spectrometer can be used to distinguish between samples of butane and propanal. The table shows

More information

UNIT 4 REVISION CHECKLIST CHEM 4 AS Chemistry

UNIT 4 REVISION CHECKLIST CHEM 4 AS Chemistry UNIT 4 REVISION CHECKLIST CHEM 4 AS Chemistry Topic 4.1 Kinetics a) Define the terms: rate of a reaction, rate constant, order of reaction and overall order of reaction b) Deduce the orders of reaction

More information

Candidates answer on the question paper. Time: 1 hour 15 minutes Additional Materials: Data Sheet for Chemistry (Inserted) Scientific calculator

Candidates answer on the question paper. Time: 1 hour 15 minutes Additional Materials: Data Sheet for Chemistry (Inserted) Scientific calculator SPECIMEN Advanced GCE CEMISTRY A F324 QP Unit F324: Rings, Polymers and Analysis Specimen Paper Candidates answer on the question paper. Time: 1 hour 15 minutes Additional Materials: Data Sheet for Chemistry

More information

(07) 3 (e) Calculate the ph of this buffer solution at 298 K. Give your answer to 2 decimal places

(07) 3 (e) Calculate the ph of this buffer solution at 298 K. Give your answer to 2 decimal places 7 3 (e) An acidic buffer solution is formed when 10.0 cm3 of 0.125 mol dm 3 aqueous sodium hydroxide are added to 15.0 cm3 of 0.174 mol dm 3 aqueous HX. The value of Ka for the weak acid HX is 3.01 10

More information

F324: Rings, Polymers and Analysis Carbonyl Compounds

F324: Rings, Polymers and Analysis Carbonyl Compounds F324: Rings, Polymers and Analysis 4.1.2 arbonyl ompounds 1. ydroxyethanal, 2, is sometimes referred to as the first sugar as it is the simplest possible molecule that contains both an aldehyde group and

More information

CHEMISTRY 2814/01 Chains, Rings and Spectroscopy

CHEMISTRY 2814/01 Chains, Rings and Spectroscopy TIS IS A LEGAY SPEIFIATION ADVANED GE EMISTRY 2814/01 hains, Rings and Spectroscopy * OE / 1 9368* andidates answer on the Question Paper A calculator may be used for this paper OR Supplied Materials:

More information

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F324 CHEMISTRY A. Rings, Polymers and Analysis

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F324 CHEMISTRY A. Rings, Polymers and Analysis Candidate Forename Centre Number Candidate Surname Candidate Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F324 CHEMISTRY A Rings, Polymers and Analysis WEDNESDAY 27 JANUARY 2010: Morning DURATION:

More information

Question Answer Mark Guidance 1 (a)

Question Answer Mark Guidance 1 (a) Question Answer Mark Guidance 1 (a) 1 ALLW correct structural R displayed R skeletal 3 3 formula R mixture of the above 3 D NT ALLW molecular formula Br Br ALLW dichloro or diiodo compound instead of the

More information

Thursday 26 January 2012 Afternoon

Thursday 26 January 2012 Afternoon Thursday 26 January 2012 Afternoon A2 GE EMISTRY A F324 Rings, Polymers and Analysis *F314460112* andidates answer on the Question Paper. R supplied materials: Data Sheet for hemistry A (inserted) ther

More information

AS Demonstrate understanding of the properties of selected organic compounds

AS Demonstrate understanding of the properties of selected organic compounds No Brain Too Small EMISTRY AS 91165 Demonstrate understanding of the properties of selected organic compounds ollated Flow hart Type Questions / types of reaction (2017) (a) (i) omplete the following reaction

More information

2 Answer all the questions. CH(NH 2. )COOH, R is CH [1] (ii) Draw the structures of the ions formed by alanine at ph 6.0 and at ph 1.5.

2 Answer all the questions. CH(NH 2. )COOH, R is CH [1] (ii) Draw the structures of the ions formed by alanine at ph 6.0 and at ph 1.5. 2 Answer all the questions. 1 This question looks at the properties and chemistry of some α-amino acids. The general formula of an α-amino acid is R(N 2 ). (a) In the α-amino acid alanine, 3 (N 2 ), R

More information

, by reacting CH 3 with ethanoic anhydride, (CH 3

, by reacting CH 3 with ethanoic anhydride, (CH 3 1 A chemist prepares and analyses some esters. (a) The chemist prepares an ester of propan-2-ol, H 3 H(H)H 3, by reacting H 3 H(H)H 3 with ethanoic anhydride, (H 3 ) 2. Using structural formulae, write

More information

PMT. GCE Chemistry A. Unit F324: Rings, Polymers and Analysis. Advanced GCE. Mark Scheme for June Oxford Cambridge and RSA Examinations

PMT. GCE Chemistry A. Unit F324: Rings, Polymers and Analysis. Advanced GCE. Mark Scheme for June Oxford Cambridge and RSA Examinations GCE Chemistry A Unit F324: Rings, Polymers and Analysis Advanced GCE Mark Scheme for June 2015 Oxford Cambridge and RSA Examinations OCR (Oxford Cambridge and RSA) is a leading UK awarding body, providing

More information

Alcohols. Nomenclature. 57 minutes. 57 marks. Page 1 of 9

Alcohols. Nomenclature. 57 minutes. 57 marks. Page 1 of 9 ..0 Alcohols Nomenclature 57 minutes 57 marks Page of 9 M. (a) % O =.6 % () If % O not calculated only M available C O () = 5. =.5 =.5 Ratio: : 0: ( C 0 O) () If arithmetic error in any result lose M If

More information

3.4 A2 Unit F324: Rings, Polymers and Analysis

3.4 A2 Unit F324: Rings, Polymers and Analysis 3.4 A2 Unit F324: Rings, Polymers and Analysis This unit builds upon the chemical concepts that have been developed during AS Chemistry. This unit consists of three teaching modules: Module 1: Rings, Acids

More information

2 Answer all the questions. 1 Alkenes and benzene both react with bromine but alkenes are much more reactive.

2 Answer all the questions. 1 Alkenes and benzene both react with bromine but alkenes are much more reactive. 2 Answer all the questions. 1 Alkenes and benzene both react with bromine but alkenes are much more reactive. (a) Explain the relative resistance to bromination of benzene compared with alkenes. In your

More information

SPECIMEN MATERIAL v1.0. A-LEVEL Chemistry. Paper 2: Organic and Physical Chemistry Mark scheme. 7405/2 Specimen Paper (set 2) Version 1.

SPECIMEN MATERIAL v1.0. A-LEVEL Chemistry. Paper 2: Organic and Physical Chemistry Mark scheme. 7405/2 Specimen Paper (set 2) Version 1. SPECIMEN MATERIAL v.0 A-LEVEL Chemistry Paper 2: Organic and Physical Chemistry Mark scheme 7405/2 Specimen Paper (set 2) Version.0 Mark schemes are prepared by the Lead Assessment Writer and considered,

More information

Organic Chemistry SL IB CHEMISTRY SL

Organic Chemistry SL IB CHEMISTRY SL Organic Chemistry SL IB CHEMISTRY SL 10.1 Fundamentals of organic chemistry Understandings: A homologous series is a series of compounds of the same family, with the same general formula, which differ

More information

Answer Marks Guidance

Answer Marks Guidance Question number (a) molecular formula: C 4 H 8 Answer Marks Guidance empirical formula: CH 2 This is a revision of earlier chapters. (b) (i) name of mechanism: electrophilic addition Remember that reactions

More information

Name/CG: 2012 Term 2 Organic Chemistry Revision (Session II) Deductive Question

Name/CG: 2012 Term 2 Organic Chemistry Revision (Session II) Deductive Question Name/G: 2012 Term 2 rganic hemistry Revision (Session II) Deductive Question 1(a) A yellow liquid A, 7 7 N 2, reacts with alkaline potassium manganate (VII) and on acidification gives a yellow solid B,

More information

Acceptable Answers Reject Mark. Acceptable Answers Reject Mark. ALLOW Iron/Fe or Zn/Zinc for tin Conc for concentrated. Acceptable Answers Reject Mark

Acceptable Answers Reject Mark. Acceptable Answers Reject Mark. ALLOW Iron/Fe or Zn/Zinc for tin Conc for concentrated. Acceptable Answers Reject Mark (a)(i) (a)(ii) Concentrated nitric acid AND concentrated sulfuric acid concentrated nitric and sulfuric acids Concentrated HNO and concentrated H SO 4 Extra reagents To prevent multiple substitutions/

More information

Page 2. (1)-methylethyl ethanoate OR. Propan-2-yl ethanoate Ignore extra or missing spaces, commas or hyphens 1. (ii) M4 for 3 arrows and lp

Page 2. (1)-methylethyl ethanoate OR. Propan-2-yl ethanoate Ignore extra or missing spaces, commas or hyphens 1. (ii) M4 for 3 arrows and lp M.(a) (i) (CH 3 ) 2 CHOH + (CH 3 CO) 2 O CH 3 COOCH(CH 3 ) 2 + CH 3 COOH Allow CH 3 CO 2 CH(CH 3 ) 2 and CH 3 CO 2 H Ignore (CH 3 ) 2 C in equation ()-methylethyl ethanoate OR Propan-2-yl ethanoate Ignore

More information

GCE A level 1094/01 CHEMISTRY CH4

GCE A level 1094/01 CHEMISTRY CH4 Surname ther Names Centre 2 Candidate GCE A level 1094/01 CHEMISTRY CH4 P.M. MNDAY, 14 January 2013 1¾ hours ADDITINAL MATERIALS In addition to this examination paper, you will need: Data Sheet Periodic

More information

Amides, Amino acids and Chirality

Amides, Amino acids and Chirality R hemistry A 432 Amides, Amino Acids & hirality Amides, Amino acids and hirality aming of Amides The amide functional group consists of a carbonyl group bonded to the nitrogen of an amine. Like amines,

More information

2 Answer all the questions. OH(g) ΔH = 91 kj mol 1 equation 1.1. (a) A pressure of between 50 and 100 atmospheres is used for this reaction.

2 Answer all the questions. OH(g) ΔH = 91 kj mol 1 equation 1.1. (a) A pressure of between 50 and 100 atmospheres is used for this reaction. 2 Answer all the questions. 1 Methanol is added to ethanol to make the ethanol unfit to drink. Methanol can be made by the following reaction. CO(g) + 2H 2 (g) CH 3 OH(g) ΔH = 91 kj mol 1 equation 1.1

More information

COCH 3. + HCl H 5 C 6. Not molecular formulae Not allow C. phenylethanone Ignore number 1 in name but penalise other numbers

COCH 3. + HCl H 5 C 6. Not molecular formulae Not allow C. phenylethanone Ignore number 1 in name but penalise other numbers Not molecular formulae Not allow C 6 H 5 CH CO M. (a) (i) CH COCl + C 6 H 6 C 6 H 5 COCH + HCl OR phenylethanone Ignore number in name but penalise other numbers AlCl can be scored in equation Allow RHS

More information

Section A. 1 at a given temperature. The rate was found to be first order with respect to the ester and first order with respect to hydroxide ions.

Section A. 1 at a given temperature. The rate was found to be first order with respect to the ester and first order with respect to hydroxide ions. 2 Section A Answer all questions in the spaces provided. Question 1:The N/Arate of hydrolysis of an ester X (HCOOCH2CH2CH3) was studied in alkaline 1 at a given temperature. The rate was found to be first

More information

CHERRY HILL TUITION EDEXCEL CHEMISTRY A2 PAPER 32 MARK SCHEME. ±½ a square

CHERRY HILL TUITION EDEXCEL CHEMISTRY A2 PAPER 32 MARK SCHEME. ±½ a square Chemistry Advanced Level Paper 3 (9CH0/03) 1(a)(i) suitable scale and axes labelled including units (1) all points plotted correctly (1) line of best fit (1) Plotted points use at least half the available

More information

Candidate number. Centre number

Candidate number. Centre number Oxford Cambridge and RSA A Level Chemistry A H432/02 Synthesis and analytical techniques Practice paper Set 2 Time allowed: 2 hours 15 minutes *PRACTICE2016* You must have: the Data Sheet for Chemistry

More information

Exam 1 (Monday, July 6, 2015)

Exam 1 (Monday, July 6, 2015) Chem 231 Summer 2015 Assigned Homework Problems Last updated: Friday, July 24, 2015 Problems Assigned from Essential Organic Chemistry, 2 nd Edition, Paula Yurkanis Bruice, Prentice Hall, New York, NY,

More information

Morning. This document consists of 15 printed pages, 1 blank page and a Data Sheet for Chemistry.

Morning. This document consists of 15 printed pages, 1 blank page and a Data Sheet for Chemistry. ADVANED GE 2814/01 EMISTRY hains, Rings and Spectroscopy TUESDAY 23 JANUARY 2007 Morning Additional materials: Scientific calculator Data Sheet for hemistry (Inserted) Time: 1 hour 30 minutes INSTRUTINS

More information

Experiment 8 Optical Isomers. In this experiment you will be given the opportunity to see the 3-dimensional aspects of

Experiment 8 Optical Isomers. In this experiment you will be given the opportunity to see the 3-dimensional aspects of Experiment 8 Optical Isomers In this experiment you will be given the opportunity to see the 3-dimensional aspects of stereochemistry and optical isomers. Previously in class you were exposed to the concept

More information

2 Answer all the questions. 1 Nitrogen monoxide is formed when nitrogen and oxygen from the air combine. (g) + O 2

2 Answer all the questions. 1 Nitrogen monoxide is formed when nitrogen and oxygen from the air combine. (g) + O 2 2 Answer all the questions. 1 Nitrogen monoxide is formed when nitrogen and oxygen from the air combine. N 2 (g) + 2 (g) 2N(g) equation 1.1 Under normal atmospheric conditions, a further reaction occurs

More information

A Level Chemistry A H432/02 Synthesis and analytical techniques. Practice paper Set 1 Time allowed: 2 hours 15 minutes

A Level Chemistry A H432/02 Synthesis and analytical techniques. Practice paper Set 1 Time allowed: 2 hours 15 minutes A Level hemistry A 432/02 Synthesis and analytical techniques Practice paper Set 1 Time allowed: 2 hours 15 minutes You must have: the Data Sheet for hemistry A You may use: a scientific calculator a ruler

More information

Chem 14C Lecture 1 Spring 2017 Final Exam Part B Page 1

Chem 14C Lecture 1 Spring 2017 Final Exam Part B Page 1 Chem 14C Lecture 1 Spring 2017 Final Exam Part B Page 1 1. (2) Write the letter of the structure that best fits the following 13 C-NMR spectrum: 51 ppm (doublet), 44 ppm (triplet), 27 ppm (quartet), 26

More information

2.8 EXTRA QUESTIONS MS. (iii) C 6 H 5 CHCl 2 / C 6 H 5 CCl 3 / C 6 H 5 CHCHC 6 H 5 / other correct possible answer (1) 1

2.8 EXTRA QUESTIONS MS. (iii) C 6 H 5 CHCl 2 / C 6 H 5 CCl 3 / C 6 H 5 CHCHC 6 H 5 / other correct possible answer (1) 1 .8 EXTRA QUESTIONS MS 1. (i) l l / ½ l l 1 (ii) l 6 5 6 5 l 6 5 l l 6 5 l (iii) 6 5 l / 6 5 l / 6 5 6 5 / other correct possible answer 1 [4]. (a) (i) (free)radical substitution 1 (both words required

More information

CHEM1102 Worksheet 4 Answers to Critical Thinking Questions Model 1: Infrared (IR) Spectroscopy

CHEM1102 Worksheet 4 Answers to Critical Thinking Questions Model 1: Infrared (IR) Spectroscopy CEM1102 Worksheet 4 Answers to Critical Thinking Questions Model 1: Infrared (IR) Spectroscopy 1. See below. Model 2: UV-Visible Spectroscopy 1. See below. 2. All of the above. 3. Restricted to the identification

More information

3 Answer all the questions.

3 Answer all the questions. CHERRY HILL TUITIN CR A CHEMISTRY A2 PAPER 18 3 Answer all the questions. 1 Benzene is an important industrial chemical and is used in a wide range of manufacturing processes. ver time our understanding

More information

abc Mark Scheme Chemistry 5421 General Certificate of Education 2005 examination - June series CHM4 Further Physical and Organic Chemistry

abc Mark Scheme Chemistry 5421 General Certificate of Education 2005 examination - June series CHM4 Further Physical and Organic Chemistry Version.0 General Certificate of Education abc Chemistry 542 CM4 Further Physical and Organic Chemistry Mark Scheme 2005 examination - June series Mark schemes are prepared by the Principal Examiner and

More information

(a) Name the alcohol and catalyst which would be used to make X. (2)

(a) Name the alcohol and catalyst which would be used to make X. (2) 1 The chemical X is an ester with formula CH 3 COOC(CH 3 ) 3 which occurs in raspberries and pears. It can be prepared in the laboratory by refluxing ethanoic acid with an alcohol in the presence of a

More information

* * Cambridge International Examinations Cambridge International Advanced Level

* * Cambridge International Examinations Cambridge International Advanced Level *3272601861* Cambridge International Examinations Cambridge International Advanced Level CHEMISTRY 9701/42 Paper 4 Structured Questions ctober/november 2014 2 hours Candidates answer on the Question Paper.

More information

The mechanism of the nitration of methylbenzene is an electrophilic substitution.

The mechanism of the nitration of methylbenzene is an electrophilic substitution. Q1.Many aromatic nitro compounds are used as explosives. One of the most famous is 2-methyl-1,3,5-trinitrobenzene, originally called trinitrotoluene or TNT. This compound, shown below, can be prepared

More information

Monday 19 June 2017 Morning Time allowed: 2 hours 15 minutes

Monday 19 June 2017 Morning Time allowed: 2 hours 15 minutes Oxford ambridge and RSA A Level hemistry A H432/02 Synthesis and analytical techniques Monday 19 June 2017 Morning Time allowed: 2 hours 15 minutes *6826116453* You must have: the Data Sheet for hemistry

More information

4. NMR spectra. Interpreting NMR spectra. Low-resolution NMR spectra. There are two kinds: Low-resolution NMR spectra. High-resolution NMR spectra

4. NMR spectra. Interpreting NMR spectra. Low-resolution NMR spectra. There are two kinds: Low-resolution NMR spectra. High-resolution NMR spectra 1 Interpreting NMR spectra There are two kinds: Low-resolution NMR spectra High-resolution NMR spectra In both cases the horizontal scale is labelled in terms of chemical shift, δ, and increases from right

More information

IGNORE Just benzene has a delocalised ring Benzene does not have C=C double bonds Any references to shape/ bond angles. Acceptable Answers Reject Mark

IGNORE Just benzene has a delocalised ring Benzene does not have C=C double bonds Any references to shape/ bond angles. Acceptable Answers Reject Mark 1(a) All carbon to carbon bonds same length/ longer C-C and shorter C=C not present 1 IGNORE Just benzene has a delocalised ring Benzene does not have C=C double bonds Any references to shape/ bond angles

More information

Afternoon Time: 1 hour 30 minutes

Afternoon Time: 1 hour 30 minutes ADVANED GE 2814/01 EMISTRY hains, Rings and Spectroscopy TURSDAY 12 JUNE 2008 Afternoon Time: 1 hour 30 minutes *UP/T68366* andidates answer on the question paper Additional materials (enclosed): Data

More information

Name this organic reagent and state the conditions for the preparation. Reagent... Conditions (3)

Name this organic reagent and state the conditions for the preparation. Reagent... Conditions (3) 1. (a) Propanoic acid, C 3 C 2 COO, can be prepared from carbon dioxide and an organic reagent. Name this organic reagent and state the conditions for the preparation. Reagent... Conditions...... (3) (b)

More information

Tuesday 19 June 2012 Afternoon

Tuesday 19 June 2012 Afternoon Tuesday 19 June 2012 Afternoon A2 GCE CEMISTRY A F324 Rings, Polymers and Analysis *F314730612* Candidates answer on the Question Paper. CR supplied materials: Data Sheet for Chemistry A (inserted) ther

More information

CHEM J-8 June Complete the following table. Make sure you give the name of the starting material where indicated. REAGENTS/ CONDITIONS

CHEM J-8 June Complete the following table. Make sure you give the name of the starting material where indicated. REAGENTS/ CONDITIONS CEM1102 2014-J-8 June 2014 Complete the following table. Make sure you give the name of the starting material where indicated. STARTIG MATERIAL REAGETS/ CDITIS STRUCTURAL FRMULA(S) F MAJR RGAIC PRDUCT(S)

More information

CHEM 203. Midterm Exam 1 October 31, 2008 ANSWERS. This a closed-notes, closed-book exam. You may use your set of molecular models

CHEM 203. Midterm Exam 1 October 31, 2008 ANSWERS. This a closed-notes, closed-book exam. You may use your set of molecular models CEM 203 Midterm Exam 1 ctober 31, 2008 Your name: ANSWERS This a closed-notes, closed-book exam You may use your set of molecular models This exam contains 8 pages Time: 1h 30 min 1. / 15 2. / 16 3. /

More information

THE UNIVERSITY OF CALGARY FACULTY OF SCIENCE MIDTERM EXAMINATION CHEMISTRY 353

THE UNIVERSITY OF CALGARY FACULTY OF SCIENCE MIDTERM EXAMINATION CHEMISTRY 353 12 TE UNIVERSITY F CALGARY FACULTY F SCIENCE MIDTERM EXAMINATIN CEMISTRY 353 FEBRUARY 28th, 2001 Time: 2 ours PLEASE WRITE YUR NAME, STUDENT I.D. NUMBER AND SECTIN NUMBER (01 for MWF lectures and 02 for

More information

klm Mark Scheme Chemistry 2421 General Certificate of Education Kinetics, Equilibria and Organic Chemistry 2010 examination - January series

klm Mark Scheme Chemistry 2421 General Certificate of Education Kinetics, Equilibria and Organic Chemistry 2010 examination - January series Version.0: 02/200 klm General ertificate of Education hemistry 242 EM4 Kinetics, Equilibria and rganic hemistry Scheme 200 examination - January series schemes are prepared by the Principal Examiner and

More information

Unit 2. Answers to examination-style questions. Answers Marks Examiner s tips. 1 (a) heat energy change at constant pressure

Unit 2. Answers to examination-style questions. Answers Marks Examiner s tips. 1 (a) heat energy change at constant pressure (a) heat energy change at constant pressure This is in the spec but not so well known. Learn it. (b) N 2 (g) + ½O 2 (g) N 2 O(g) (c) (i) D = (bonds broken) (bonds made) = ½(945) + (3/2)(59) 3(278) = 23

More information

Organic and Biochemical Molecules. 1. Compounds composed of carbon and hydrogen are called hydrocarbons.

Organic and Biochemical Molecules. 1. Compounds composed of carbon and hydrogen are called hydrocarbons. Organic and Biochemical Molecules 1. Compounds composed of carbon and hydrogen are called hydrocarbons. 2. A compound is said to be saturated if it contains only singly bonded carbons. Such hydrocarbons

More information

F322: Chains, Energy and Resources Basic Concepts

F322: Chains, Energy and Resources Basic Concepts F322: hains, Energy and Resources Basic oncepts 1. Some of the hydrocarbons in kerosene have the formula 10 22. (i) What is the name of the straight chain hydrocarbon with the formula 10 22? (ii) Draw

More information

This document consists of 16 printed pages and a Data Sheet for Chemistry.

This document consists of 16 printed pages and a Data Sheet for Chemistry. ADVANED GE 2814/01 EMISTRY hains, Rings and Spectroscopy MNDAY 18 JUNE 2007 Afternoon *UP/T24087* Additional materials: Scientific calculator Data Sheet for hemistry (Inserted) Time: 1 hour 30 minutes

More information

GCE Chemistry A. Mark Scheme for June Unit F324: Rings, Polymers and Analysis. Advanced GCE. Oxford Cambridge and RSA Examinations

GCE Chemistry A. Mark Scheme for June Unit F324: Rings, Polymers and Analysis. Advanced GCE. Oxford Cambridge and RSA Examinations GCE Chemistry A Unit F324: Rings, Polymers and Analysis Advanced GCE Mark Scheme for June 2016 Oxford Cambridge and RSA Examinations OCR (Oxford Cambridge and RSA) is a leading UK awarding body, providing

More information

GCE Chemistry A. Mark Scheme for June Unit H432A/02: Synthesis and analytical techniques. Advanced GCE. Oxford Cambridge and RSA Examinations

GCE Chemistry A. Mark Scheme for June Unit H432A/02: Synthesis and analytical techniques. Advanced GCE. Oxford Cambridge and RSA Examinations GE hemistry A Unit 432A/02: Synthesis and analytical techniques Advanced GE Mark Scheme for June 2017 Oxford ambridge and RSA Examinations 432A/02 Mark Scheme OR (Oxford ambridge and RSA) is a leading

More information

CHEMISTRY (SALTERS) Chemistry of Materials. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced GCE

CHEMISTRY (SALTERS) Chemistry of Materials. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced GCE XFRD CAMBRIDGE AND RSA EXAMINATINS Advanced GCE CHEMISTRY (SALTERS) Chemistry of Materials 2849 Monday 19 JUNE 2006 Afternoon 1 hour 30 minutes Candidates answer on the question paper. Additional materials:

More information

AQA A2 CHEMISTRY TOPIC 4.10 ORGANIC SYNTHESIS AND ANALYSIS TOPIC 4.11 STRUCTURE DETERMINATION BOOKLET OF PAST EXAMINATION QUESTIONS

AQA A2 CHEMISTRY TOPIC 4.10 ORGANIC SYNTHESIS AND ANALYSIS TOPIC 4.11 STRUCTURE DETERMINATION BOOKLET OF PAST EXAMINATION QUESTIONS AQA A2 CHEMISTRY TOPIC 4.10 ORGANIC SYNTHESIS AND ANALYSIS TOPIC 4.11 STRUCTURE DETERMINATION BOOKLET OF PAST EXAMINATION QUESTIONS 1 1. Consider the following reaction sequence. CH 3 CH 3 CH 3 Step 1

More information

Calculate a rate given a species concentration change.

Calculate a rate given a species concentration change. Kinetics Define a rate for a given process. Change in concentration of a reagent with time. A rate is always positive, and is usually referred to with only magnitude (i.e. no sign) Reaction rates can be

More information

Tuesday 14 June 2016 Afternoon

Tuesday 14 June 2016 Afternoon xford ambridge and RSA Tuesday 14 June 2016 Afternoon A2 GE HEMISTRY A F324/01 Rings, Polymers and Analysis *5878609421* andidates answer on the Question Paper. R supplied materials: Data Sheet for hemistry

More information

Pearson Edexcel Level 3 GCE Chemistry Advanced Paper 2: Advanced Organic and Physical Chemistry

Pearson Edexcel Level 3 GCE Chemistry Advanced Paper 2: Advanced Organic and Physical Chemistry Write your name here Surname Other names Pearson Edexcel Level 3 GCE Centre Number Candidate Number Chemistry Advanced Paper 2: Advanced Organic and Physical Chemistry Sample Assessment Materials for first

More information

CHEM4 Kinetics, Equilibria and Organic Chemistry Mark scheme

CHEM4 Kinetics, Equilibria and Organic Chemistry Mark scheme AQA Qualifications A-LEVEL EMISTRY EM4 Kinetics, Equilibria and rganic hemistry Mark scheme 2420 June 204 Version:. Final Mark schemes are prepared by the Lead Assessment Writer and considered, together

More information

Question Answer Marks Guidance 1 (a) (+)5 1 ALLOW 5+ OR V OR Cr 5+ 1 (b) For equations, IGNORE any state symbols; ALLOW multiples

Question Answer Marks Guidance 1 (a) (+)5 1 ALLOW 5+ OR V OR Cr 5+ 1 (b) For equations, IGNORE any state symbols; ALLOW multiples Question Answer Marks Guidance 1 (a) (+)5 1 ALLW 5+ R V R Cr 5+ 1 (b) For equations, IGNRE any state symbols; ALLW multiples EXAMPLES ------------------------------------------------------------------------------------

More information

Q1. The following pairs of compounds can be distinguished by simple test tube reactions.

Q1. The following pairs of compounds can be distinguished by simple test tube reactions. Q1. The following pairs of compounds can be distinguished by simple test tube reactions. For each pair of compounds, give a reagent (or combination of reagents) that, when added separately to each compound,

More information