THE MOLE CONCEPT CHAPTER 10. (Part 3) Empirical Formulas Molecular Formulas The Ideal Gas Law ACTIVE LEARNING IN CHEMISTRY EDUCATION ALICE
|
|
- Aubrie Watts
- 5 years ago
- Views:
Transcription
1 NAME PER DATE DUE ACTIVE LEARNING IN CHEMISTRY EDUCATION ALICE CHAPTER 10 THE MOLE CONCEPT (Part 3) Empirical Formulas Molecular Formulas The Ideal Gas Law , A.J. Girondi
2 NOTICE OF RIGHTS All rights reserved. No part of this document may be reproduced or transmitted in any form by any means, electronic, mechanical, photocopying, or otherwise, without the prior written permission of the author. Copies of this document may be made free of charge for use in public or nonprofit private educational institutions provided that permission is obtained from the author. Please indicate the name and address of the institution where use is anticipated A.J. Girondi, Ph.D. 505 Latshmere Drive Harrisburg, PA Website: , A.J. Girondi
3 SECTION 10.1 Laboratory Determination of Empirical Formulas An empirical formula is one which identifies which elements are present in a compound, and it gives the simplest ratio of atoms of those elements in the compound. Examples of empirical formulas include NaCl, CaCl2, and Al 2O3 in which the simplest ratios are 1:1, 1:2, and 2:3, respectively. You can write empirical formulas using oxidation numbers, but they can also be determined using experimental data from experiments. The following example will illustrate how this is done. Sample Problem: A laboratory analysis found that a compound contained 36.5 g Na, 25.4 g S, and 38.1 g of O. What is the empirical formula of the compound? Note: In these kinds of problems, you should attempt to calculate the mole quantities to at least 2 decimal places; otherwise, some problems may be solved incorrectly. Solution: Step 1: Change the mass data to moles: 36.5 g Na X 25.4 g S X 38.1 g O X 1 mole Na g Na 1 mole S g O 1 mole O g O = 1.59 mole Na = 0.79 mole S = 2.38 mole O Step 2: Change the numbers of moles to a simple whole number ratio. You do this by dividing each of the mole quantities by the smallest of them. In our example, the smallest is Thus, the calculations are: 1.59 mol Na = 2.01 mol Na; mol S = 1.00 mol S; 2.38 mol O = 3.01 mol O These results are very close to 2:1:3, so the answer is Na2SO3. In some problems of this kind, a third step is necessary. This is illustrated in the next sample problem. Sample Problem: What is the empirical formula of a compound that contains 53.73% iron, Fe, and 46.27% sulfur, S? (When the data are given in percentages, they can be changed to grams simply by assuming that you have 100 grams of the sample.) Step 1: Change the mass data to moles: g Fe X g S X 1 mole Fe g Fe 1 mole S g S = mol Fe = mol S , A.J. Girondi
4 Step 2: Change the numbers of moles to a simple whole number ratio. You do this by dividing each of the mole quantities by the smallest of them mol Fe = mol Fe and mol S = 1.50 mol S After completing step 2, the mole ratio is 1:1.5. The 1.5 is not close enough to a whole number to be rounded. Therefore, we go to step three. Step 3: Multiply the mole ratio by the smallest integer which will give a whole number ratio. In this case, that integer is 2:2 X = 2.000; and 2 X 1.50 = 3.00 Thus, the answer is: Fe2S3 Note: In order to be rounded to a whole number in step 2, a mole quantity should be within one-tenth of that number. For example, 2.1 can be rounded to 2, or 3.9 can be rounded to 4 and step 3 is not needed. However, 2.2 and 3.8 should not be rounded to 2 and 4. In such a case, step three is necessary. Problem 1. It is found that a sample of magnesium oxide consists of 4.04 g of magnesium (Mg) and 2.66 g of oxygen (O). Calculate the empirical formula of the magnesium oxide using this information. Problem 2. Experimental evidence reveals that a compound between iron (Fe) and oxygen (O) consists of 2.24 g Fe and 0.96 g O. Find the empirical formula. Problem 3. An investigation reveals that the percentage composition of a compound is 75.0% carbon (C) and 25.0% hydrogen (H) by mass. Find its empirical formula , A.J. Girondi
5 Problem 45.0% O. 4. Calculate the empirical formula of a compound which contains 32.4% Na, 22.6% S, and Problem 5. A laboratory analysis of an unknown compound revealed that 100 g of it consisted of g K, g Cr, and g O. What is the empirical formula of the compound? ACTIVITY 10.2 Determination of the Formula of an Oxide of Tin In an earlier chapter you learned how to write chemical formulas for compounds by using what are known as oxidation numbers. Now that you know something about the mole concept, you are ready to try to determine the chemical formula of a compound experimentally in the lab. In this activity you are going to make a compound of tin and oxygen, and you are going to gather data which will allow you to, hopefully, determine its formula. 1. Clean and dry an evaporating dish and a watch glass cover (see figure 10.1). Determine the mass of the dish with watch glass cover to the nearest 0.01 g. 2. Place about 2 g of 30-mesh granulated tin in the dish, cover with the watch glass, and measure the mass. If the balance in your lab displays masses to three decimal places, then read the mass of the tin to the nearest g or to the nearest 0.01 g if your balance is accurate to only two decimal places. Enter all this data in Table While your instructor is watching, under a fume hood, carefully add 5 ml of 8 M nitric acid (HNO3), and replace the watch glass. (The 8 M indicates the concentration of the acid.) Handle the acid with great care, and be sure to wear safety glasses! Do not allow the acid to drip on anything. ring stand watch glass evaporating dish wire screen iron ring Figure 10.1 Heating an Evaporating Dish , A.J. Girondi
6 4. A reaction should begin which will result in the production of a reddish toxic gas, NO2. When this reaction has subsided, you can take the dish back to your lab station for the rest of this activity. Briefly, here is what is happening in the dish. Some of the oxygen from the nitric acid, HNO3, combines with the tin to form a compound of tin and oxygen. At the same time, the acid decomposes to form H2O and NO2. The unfinished equation is:? HNO3 +? Sn ---->? Sn?O? +? H2O +? NO2 So as the reaction goes on, you should see the formation of water, NO2 gas, and the white compound of tin and oxygen. In order to complete and balance the equation, you need to determine the correct formula for the tin oxygen compound. 5. Position the dish, watch glass and the contents on a wire gauze supported by a ring stand as shown in Figure Begin heating the dish with a low flame. Hold the burner in your hand and rotate it slowly under the gauze. Excessive heating at this point will result in spitting and popping in the dish. Continue to heat slowly and carefully until the contents are dry. 6. When popping and spattering no longer occur, remove the watch glass with tongs and place it upside down on your lab table. Break up the solid with a stirring rod, and heat with a hot flame until the solid becomes a pale yellow. Be careful not to unnecessarily lose any material when you remove the watch glass or use the stirring rod. 7. After the dish has cooled, replace the watch glass cover and determine the mass of the dish, cover, and contents. Reheat the dish without the cover for a few minutes, allow to cool again, and determine the mass again as before. If the two masses are not very close, reheat again until there is no further loss of mass. 8. Discard the product in the waste container. Clean and return all equipment. Table Mass of dish and watch glass g 2. Mass of dish, watch glass, and tin g 3. Mass of tin (subtract 1 from 2 above) g 4. Mass of dish, watch glass, and product g (after heating to a constant mass) 5. Mass of oxygen in product g (subtract 2 from 4 above) Calculations: 1. Since all of the tin you used ends up in the product, you should be able to calculate the number of moles of tin in the product. Express your answer to three decimal places , A.J. Girondi
7 2. From the mass of oxygen gained, calculate the number of moles of oxygen, O, in the product. (This oxygen is not in the gaseous diatomic form.) Express your answer to three decimal places. 3. Enter your results from calculations 1 and 2 above in the blanks below. Sn O This is the formula of the compound you made. However, we want to change these results to a whole number ratio. Do this by dividing each of the subscripts by the smallest of the two. For example, if you got a ratio such as 0.33 to 0.97, you would divide each value by The result would be a ratio of 1 to 2.9. This is close enough (within ±0.1) to be rounded to 1 to 3. What if this process does not result in values which are close (within ±0.1) to whole numbers? For example, what if the division process described above gives you a ratio such as 1 to 2.5? The 2.5 cannot be rounded to a whole number. You should then multiply the values by the smallest integer which will give you a whole number ratio. In the case of 1 to 2.5, that integer would be 2. The resulting ratio would be 2 to 5. Enter the whole number ratio resulting from your lab data into the blanks below. The correct formula for the compound which you made is SnO2. The unbalanced equation representing the reaction which you used to make the SnO2 is shown below. Balance it by adding the correct coefficients. HNO 3 + Sn ----> SnO 2 + H 2 O + NO 2 In this compound the oxidation number of tin is +4 and of oxygen is -2. What are the two possible names for the tin oxygen product? {1} and {2}. SECTION 10.3 Molecular Formulas The empirical formula of a compound gives the simplest ratio of the atoms in the molecule. A molecular formula reveals the exact number of atoms of each element in the molecule. For example, the empirical formula of a certain gas is NO2, while its molecular formula is N2O4. Its empirical formula mass is 46, while its molecular formula mass is 92. Note that the molecular formula's mass is a multiple of the empirical formula's mass. That's because the molecular formula is always a multiple of the empirical formula. If you know the empirical formula mass and the molecular formula's mass, you can calculate the molecular formula as shown below: (empirical formula mass) X (M) = (molecular formula's mass) The letter M represents the multiple that relates the two formulas. For our example above: (46) X M = (92), so M = 2 Therefore, 2 X (NO2) = N2O4 With this information, you should now be able to do problem , A.J. Girondi
8 Problem 6. Your answer to problem 3 (earlier in this chapter) represents the empirical formula of the compound. If the molecular mass of that compound is 48, find its molecular formula. (Begin by calculating the formula mass of your answer to problem 3.) Problem 7. Butane is a compound of 82.7% carbon (C) and 17.3% hydrogen (H). Its molecular mass is 58 amu. What are the empirical formula and molecular formulas of butane? Problem 8. An organic (carbon) compound if found to contain g of carbon and 7.75 g of hydrogen. If the molecular mass is 78, what is the molecular formula? SECTION 10.4 The Ideal Gas Law: PV = nrt You may remember that when you were studying the gas laws, it was mentioned that there was one other law that you would learn about later. Now's the time! It's called the ideal gas law, because it describes the behavior of an ideal gas, which is defined as a gas that always obeys the gas laws under all conditions. Of course, there is no such gas. Real gases, like H2 or O2 do not strictly obey the gas laws under extreme conditions like very high pressures or very low temperatures. Nonetheless, we don't have to be concerned about that, because our work is not usually done under such conditions. The ideal gas law is different from the others you have learned in that it deals with only one set of conditions. The problems you solved using the other gas laws included an "old" and "new" temperature, and "old" and "new" pressure, etc. Maybe you were given an "original" volume and asked to find a "new" volume. However, you will use the ideal gas law to solve problems involving only one pressure, temperature, volume, etc. The formula for the ideal gas law is: PV = nrt , A.J. Girondi
9 where P = pressure, V = volume, n = moles, T = temperature, and R is called the ideal gas constant. R has a value of and its units are really crazy. They are shown below. R = L. atm. mole K These units are "liter-atmospheres per mole-kelvin." Scientific constants usually have strange units, but don't worry. They cancel when you use R in problems. R, like all constants, was experimentally determined, and is used to make the equation "work." We often use such constants. For example, consider the equation: P = C x A. P = number of people, and A = number of arms. What's the value of the constant C? Well, if you got O.5, that's right. In other words, if you have 16 arms and multiply by 0.5, you get 8 people. C is used to make the equation work. Its units would be people/arms, right? Anyway, PV=nRT is the only gas law that you have studied that uses such a constant. When a constant is used in an equation, the units of the other variables in the equation must be the same as those used in the constant. For that reason, when using the value in the ideal law you MUST express volume in liters, pressure in atmospheres, temperature in K (as always), and mass (n) in moles. Learn the relationships below which will allow you to make any needed conversions. 1 atmosphere = 760 mm Hg; 1 L = 1000 ml; oc = K To solve a variety of problems, you will have to rearrange the ideal gas equation. How s your algebra? For example, of we solve the equation for n, V, and T, respectively, we get: n = PV RT V = nrt P T = PV nr Sample Problem: What volume would 34 g of CO2 gas have at 23 o C and 800. mm pressure? (Notice that only one set of conditions is given? This is a hint that the use of the ideal gas law is appropriate.) Solution: We must change 34 g of CO2 to moles, o C to K, and mm to atm. These are the results of those conversions: 34 g CO2 = 0.77 mole; 23 o C = 296 K; 800 mm = 1.05 atm. When we do the substitutions we get: (1.05 atm)(v) = (0.77 mole)( L.atm./mol.K.)(296 K) Solving for V we get: V = (0.77 mole)( L.atm./Mole K)(296 K) 1.05 atm. And the answer is: 17.8, or 18 Liters Solve the problems below. Show your work, and include units with all measurements. Problem 10.0 o C? 9. What is the volume of 2.77 moles of H2 gas at a pressure of 700. mm and a temperature of , A.J. Girondi
10 Problem 10. What is the temperature in o C of 1.06 moles of O2 gas at a volume of 670. ml and a pressure of 900. mm? Problem 11. What is the pressure (in mm of Hg) exerted by 0.80 moles of methane (CH4) gas at 67 o C and if it has a volume of 2.3 liters? In the ideal gas law, the letter "n" represents moles of gas. Moles of a substance can be calculated by dividing the number of grams (g) of the substance that you have by its molecular mass (MM). For example, 4.04 g of H2 (molecular mass = 2.02) is 2.00 moles: 4.04 g H 2 X 1 mole H g H 2 = 2.00 moles H 2 In other words, moles = grams molecular mass or n = g MM Now if n = g MM, then the ideal gas law can also be written as PV = g MM RT An alternate form of the ideal gas law is: PV = g MM RT This form of the ideal gas equation can be rearranged to solve for any of the variable it contains. For example: MM = grt PV or g = (MM)PV RT Remember this form of the ideal gas law because it is particularly useful in problems which involve the mass in grams of a gas or the molecular mass of a gas. Problems which have you solved before using dimensional analysis can also be solved using the ideal gas law. Problems 11 through 14 below are identical to problems 21, 22, and 23 in chapter 9. Solve them again, but use the ideal gas law this time, and check Chapter 9 to see if you get the same answers you got before. Problem 12. A gas sample with a mass of 50.0 grams has a volume of 40.0 L at STP. What is the molecular mass of the gas? (You want to end with units of g/moles.) , A.J. Girondi
11 Problem 13. What is the volume in liters occupied by 10.0 grams of CO2 gas at STP? (Hint: you must first find the molecular mass of CO2.) Problem 14. If 1.00 mole of a gas has a mass of 18 grams, and you have 15.0 grams of the gas, what would its volume be at STP? At this point, go back and compare the three problems above to problems 21, 22, and 23 in Chapter 9. Compare the methods of solving the problems as well as the answers. Now let's try a problem in which the gas is not at STP: Problem 15. At 600. mm Hg pressure and 35.0 o C, 2.70 L of a gas has a mass of 3.80 grams. What is its molecular mass? (Since you are using for the constant R, remember that you must express pressure in atm and temperature in K.) ACTIVITY 10.5 Determination of the Molar Volume of a Gas In this activity you will learn one method for determining the molar volume of a gas, and you will learn how to collect a gas in the lab by a procedure known as water displacement. You will be making measurements at room temperature and pressure, but conversion to standard conditions (STP) will be necessary to complete the calculations. Fill a large beaker (600 ml or larger) about 3 /4 full of tap water. Next, ask your instructor or others in your class whether you should follow procedure A or B below (do not follow both). You will use procedure B if you have a balance in your lab which can measure mass to three decimal places , A.J. Girondi
12 Procedure A: Obtain a piece of magnesium ribbon about 3.5 cm long. On an analytical balance which is accurate to three decimal places, determine the mass of your piece of Mg. It must have a mass between and Trim with scissors as needed. Record the mass in Table Mg Procedure B: (Follow this only if you cannot use procedure A.) Cut a piece of magnesium ribbon about 3.5 cm long. Carefully measure the length of the piece of ribbon to the nearest millimeter, mm. Record the length in Table Obtain a piece of fine copper wire about 15 cm long and tie it to the Mg ribbon which has been rolled into a coil that will fit inside the gas-measuring tube (see Figure 10.2). Obtain a ring stand with a utility clamp to support the gas-measuring tube. 1 or 2 holed stopper Cu wire 2. Slowly pour about 10 to 15 ml of 6 M HCl (hydrochloric acid) into the gas tube. Use caution. Incline the tube slightly so air may escape and slowly fill it to the brim with tap water from a beaker. Try not to mix the acid and water any more than necessary. 3. With the tube completely full of water, insert the magnesium ribbon about 3 or 4 cm into the tube. With the wire against the side of the tube, insert a 1- hole or 2-hole stopper. The stopper should force a little water out of the tube and should hold the wire in place. 4. With your finger over the hole in the stopper, invert the tube and place the stoppered end into the beaker 3 /4 full of water. Clamp the gas-measuring tube in place so that the bottom of the rubber stopper in slightly above the bottom of the beaker. The reaction will not start immediately, since the acid has to make its way down to the metal. The acid will react with the magnesium to produce hydrogen gas: acid + water Mg(s) + 2 HCl(aq) ----> MgCl2(aq) + H2(g) 5. When the Mg has reacted completely, tap the tube with your finger to remove any bubbles you may see on the side of the tube. Adjust the height of the gas- collecting tube so that the level of the water inside the tube is equal to that in the beaker. This will make the pressure on the gas inside the tube equal to the pressure in the room. If you have trouble doing this, ask your teacher for advice. Now read the level of the water inside the tube as carefully as possible. This will be the volume of gas in the tube. Record the volume in Table Record the temperature of the water in the beaker ( o C) which we will assume to Table 10.2 Vapor Pressures of Water T ( o C) P (mm) T ( o C) P (mm) Figure 10.2 be the temperature of the gas in the tube. In addition, measure the barometric pressure (mm Hg). Your teacher will help you to read the barometer in the lab. The temperature and pressure must be measured immediately after the gas has been collected. Record these values in the table , A.J. Girondi
13 7. Empty the contents of the tube and beaker and rinse both. Return all equipment to the proper place.(if you followed procedure B earlier in this experiment, ask your teacher for the precise mass of meter of magnesium ribbon. Record this value in Table10.3. If you followed procedure A, you can disregard this value.) Table 10.3 Molar Volume of a Gas *(Skip entries 1, 2, and 3 below if you followed procedure A. Skip entry 4 if you followed procedure B.) *1. Length of Mg ribbon used mm *2. Mass of meter of Mg ribbon g/m *3. Calculated mass of Mg ribbon used g (should be between and g) *4. Mass of Mg ribbon used g (from analytical balance) 5. Volume of gas in tube ml 6. Temperature o C 7. Atmospheric pressure mm Hg (Do calculation 3 before completing entries 8 and 9 below.) 8. Water vapor pressure mm Hg 9. Pressure of dry H2 mm Hg Calculations: 1. Calculate the mass of Mg ribbon used to the nearest g by using the mass of meter of the ribbon, which you got from the teacher. Use unit analysis. (Skip this calculation if you followed procedure A.) 2. Based on the mass of Mg used, calculate the number of moles of Mg used. Express your answer to three decimal places. That amount of precision is needed! 3. The pressure of the gases in the tube is equal to the atmospheric pressure in the room. The H2 gas in the tube was mixed with water vapor. This is a problem which results from collecting a gas in this way. Therefore, the pressure in the tube is the sum of the pressures exerted by H2 gas and H2O vapor. Dalton's law of partial pressures reveals that the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures exerted by each gas , A.J. Girondi
14 We need to know the pressure exerted by the H2 only. We call this the pressure of the "dry" H2. To get this, we will subtract the partial pressure of water vapor from the total pressure. The formula is: Ptotal = Pwater + Phydrogen. Ptotal is the atmospheric pressure. The vapor pressure of water, Pwater, is dependent on temperature and can be found in Table (Your ALICE reference notebook also contains a table of water vapor pressures which covers a broader temperature range.) Use the atmospheric pressure and the partial pressure of water vapor to calculate the pressure of the "dry" hydrogen: Phydrogen = Ptotal - Pwater Pressure of "dry" hydrogen = mm Hg 4. The pressure you just calculated above is the pressure to be used in your calculations. You now have the pressure, the temperature, and the volume of the H2 under these conditions. Now, you must calculate what the volume of the H2 which you collected in the tube would be (in liters) at STP. Use the combined gas law (from Chapter 4 as given below). P 1 V 1 T 1 = P 2 V 2 T 2 L H2 at STP 5. In calculation 2, you determined the number of moles of Mg used in this reaction. Enter this value in the blank below. According to the equation for the reaction, the number of moles of Mg used is the same as the number of moles of H2 produced. Fill in the blanks in the mole-to-mole ratio below, and solve for moles of H2 produced. Mg + 2 HCl ----> MgCl2 + H2 mole Mg X mole H 2 mole Mg = mole H 2 How many moles of H2 were produced in your experiment? moles H2 produced 6. With your results from steps 4 and 5 above, you have established a relationship between moles of H2 and liters of H2 at STP. Now you must use this relationship to determine what volume the hydrogen gas would have occupied if you had collected 1.00 mole of it (instead of the very small number of moles of H2 which you actually did collect). You can do this by unit analysis. The "fencepost" is set up for you below. Copy the data from calculations 4 and 5 above into the ratio below and solve the problem mole H 2 X L H 2 moles H 2 = L H 2 Because of the very small volume of gas collected in this activity, there is usually a fair amount of error. How does your answer for the volume of one mole of a gas at STP, compare to the generally accepted value of 22.4 L? , A.J. Girondi
15 Problem 16. Assume that mole of a gas is collected in the lab by water displacement. If the temperature of the gas is 26.0 o C and the total pressure in the gas tube is 745 mm Hg (including water vapor), what is the volume in liters of the dry gas? (Use the ideal gas law.) Caution: you can t use the total pressure in your calculations. You must first find the pressure of the dry gas by subtracting the water vapor pressure at 26.0 o C from the total pressure. It is the pressure of the dry gas that is used in the calculations. Water vapor pressures can be found in Table 12 in your reference notebook. SECTION 10.6 Optional Review Problems Problem 17. Using the ideal gas law, determine the number of moles of gas which will have a volume of 2.5 liters at 1.3 atm and 303 K. Problem 18. Using the ideal gas law, determine the temperature (in o C) of 1.8 moles of a gas if it has a volume of 50.9 L at 705 mm Hg. Problem 19. Using a form of the ideal gas law, calculate the number of grams of helium gas, He, which are present in an 8.00 liter container at 345 o C and 1.33 atm. Problem 20. A 14 liter container holds 50.0 grams of a gas at 2.3 atm and 345 K. The gas is known to be one of the following: O2, Cl2, Br2, or CO2. What is the molecular mass and the identity of the gas? Problem 21. How many moles of KClO3 are required to form 37.3 g of KCl? 2 KClO3(s) ----> 2 KCl(s) + 3 O2(g) Problem 22. Analysis of a sample of propane gas (also known as LP gas) from a backyard grill is shown to contain 36.7 grams of C and grams of H. Calculate the empirical formula of propane gas. Problem 23. Calculate the empirical formula of vitamin C if it is composed of 40.9% Carbon, 4.58% hydrogen, and 54.5% oxygen. Problem 24. A sample of a hypothetical compound contains 2.44 g of element X and 1.02 g of element Z. The atomic mass of hypothetical element X is 12.2 grams/mole, while that of hypothetical element Z is 2.04 grams/mole. The molecular mass of this hypothetical compound is Calculate both the empirical formula and the molecular formula of this compound. Problem ml of a wet gas is collected by water displacement at 27.0 o C and a total pressure of 805 mm Hg. How many moles of the dry gas does this represent?. (Answer using 3 sig figs.) , A.J. Girondi
16 SECTION 10.7 Learning Outcomes This is the end of Chapter 10. Check the learning outcomes below to be sure that you have mastered them. Take the Chapter 10 exam, and move on to Chapter Calculate the empirical formula of a compound from experimental data. 2. Calculate the molecular formula of a compound from experimental data. 3. Solve problems using both forms of the ideal gas law, PV = nrt and PV = grt/mm 4. Solve problems related to the collection of a gas by water displacement. SECTION 10.8 Answers to Questions and Problems Questions: {1} tin (IV) oxide; {2} stannic oxide Problems: 1. MgO 2. Fe2O3 3. CH4 4. Na2SO4 5. K2Cr2O7 6. C3H12 7. C2H5 and C4H10 8. C6H L o C mm Hg (rounds to 7400 mm Hg) g/mole L L g/mole L mole o C g g/mole, CO mole 22. C3H8 23. C3H4O3 24. X2Z5, X4Z mole , A.J. Girondi
EXPERIMENT 6 Empirical Formula of a Compound
EXPERIMENT 6 Empirical Formula of a Compound INTRODUCTION Chemical formulas indicate the composition of compounds. A formula that gives only the simplest ratio of the relative number of atoms in a compound
More informationUpon completion of this lab, the student will be able to:
1 Learning Outcomes EXPERIMENT 30A5: MOLAR VOLUME OF A GAS Upon completion of this lab, the student will be able to: 1) Demonstrate a single replacement reaction. 2) Calculate the molar volume of a gas
More informationCHEM 30A EXPERIMENT 5: MOLAR VOLUME OF A GAS (MG + HCL) Learning Outcomes. Introduction. Upon completion of this lab, the student will be able to:
1 CHEM 30A EXPERIMENT 5: MOLAR VOLUME OF A GAS (MG + HCL) Learning Outcomes Upon completion of this lab, the student will be able to: 1) Demonstrate a single replacement reaction. 2) Calculate the molar
More informationChemistry 11 Unit 1:Stoichiometry 10/30/2016 /20
Lab #6 Reaction of a Metal with Hydrochloric Acid THE AIM OF THIS EXPERIMENT: Name: Partners: In this experiment, you will react hydrochloric acid with magnesium to produce H 2 gas, and to determine the
More informationReaction of Magnesium with Hydrochloric Acid
Reaction of Magnesium with Hydrochloric Acid Your Name: Date: Partner(s): Objectives: React magnesium metal with hydrochloric acid, collecting the hydrogen over water. Calculate the grams of hydrogen produced
More informationRead the lab thoroughly. Answer the pre-lab questions that appear at the end of this lab exercise.
Experiment 10 Stoichiometry- Gravimetric Analysis Pre-lab Assignment Read the lab thoroughly. Answer the pre-lab questions that appear at the end of this lab exercise. Purpose The purpose this experiment
More informationChemistry 212 MOLAR MASS OF A VOLATILE LIQUID USING THE IDEAL GAS LAW
Chemistry 212 MOLAR MASS OF A VOLATILE LIQUID USING THE IDEAL GAS LAW To study the Ideal Gas Law. LEARNING OBJECTIVES To determine the molar mass of a volatile liquid. BACKGROUND The most common instrument
More informationChapter 10 Chemical Quantities
Chapter 10 Chemical Quantities 10.1 The Mole: A Measurement of Matter OBJECTIVES: Describe methods of measuring the amount of something. Define Avogadro s number as it relates to a mole of a substance.
More informationChesapeake Campus Chemistry 111 Laboratory
Chesapeake Campus Chemistry 111 Laboratory Objectives Calculate molar mass using the ideal gas law and laboratory data. Determine the identity of an unknown from a list of choices. Determine how sources
More informationExperiment #5. Empirical Formula
Experiment #5. Empirical Formula Goal To experimentally determine the empirical formula of magnesium oxide based on reaction stoichiometry. Introduction The molecular formula (usually shortened to simply
More informationApply the ideal gas law (PV = nrt) to experimentally determine the number of moles of carbon dioxide gas generated
Teacher Information Ideal Gas Law Objectives Determine the number of moles of carbon dioxide gas generated during a reaction between hydrochloric acid and sodium bicarbonate. Through this investigation,
More informationLaboratory Experiment No. 3 The Empirical Formula of a Compound
Introduction An initial look at mass relationships in chemistry reveals little order or sense. Mass ratios of elements in a compound, while constant, do not immediately tell anything about a compound s
More informationEXPERIMENT #6 Calculation of the Atomic Mass of Magnesium
OBJECTIVES: EXPERIMENT #6 Calculation of the Atomic Mass of Magnesium Observe the reaction between oxygen and magnesium Accurately weigh reaction mixtures before and after reaction Calculate the atomic
More informationPart II. Cu(OH)2(s) CuO(s)
The Copper Cycle Introduction In this experiment, you will carry out a series of reactions starting with copper metal. This will give you practice handling chemical reagents and making observations. It
More informationClassifying Chemical Reactions
1 Classifying Chemical Reactions Analyzing and Predicting Products Introduction The power of chemical reactions to transform our lives is visible all around us-in our cars, even in our bodies. Chemists
More informationGas Volumes and the Ideal Gas Law
Section 3, 9B s Gases react in whole-number ratios. Equal volumes of gases under the same conditions contain equal numbers of molecules. All gases have a volume of 22.4 L under standard conditions. In
More informationAP Chemistry Laboratory #1
Catalog No. AP8813 Publication No. 10528A Determination of the Empirical Formula of Silver Oxide AP Chemistry Laboratory #1 Introduction There is an official database that keeps track of the known chemical
More informationA Gas Uniformly fills any container. Easily compressed. Mixes completely with any other gas. Exerts pressure on its surroundings.
Chapter 5 Gases Chapter 5 A Gas Uniformly fills any container. Easily compressed. Mixes completely with any other gas. Exerts pressure on its surroundings. Copyright Cengage Learning. All rights reserved
More informationSolutions to the Extra Problems for Chapter 8
Solutions to the Extra Problems for Chapter 8. The answer is 83.4%. To figure out percent yield, you first have to determine what stoichiometry says should be made: Mass of MgCl 4.3 amu + 35.45 amu 95.
More informationGeneral Stoichiometry Notes STOICHIOMETRY: tells relative amts of reactants & products in a chemical reaction
General Stoichiometry Notes STOICHIOMETRY: tells relative amts of reactants & products in a chemical reaction Given an amount of a substance involved in a chemical reaction, we can figure out the amount
More informationMoles and Chemical Formulas 11
Moles and Chemical Formulas 11 LABORATORY GOALS Determine the simplest formula of a compound. Calculate the percent water in a hydrate. Determine the formula of a hydrate. LAB INFORMATION Time: Comments:
More informationLab #5 - Limiting Reagent
Objective Chesapeake Campus Chemistry 111 Laboratory Lab #5 - Limiting Reagent Use stoichiometry to determine the limiting reactant. Calculate the theoretical yield. Calculate the percent yield of a reaction.
More informationClassifying Chemical Reactions
Classifying Chemical Reactions Prepared by M.L. Holland and A.L. Norick, Foothill College Purpose of the Experiment To make observations when reactants are combined and become familiar with indications
More informationGeneral Stoichiometry Notes STOICHIOMETRY: tells relative amts of reactants & products in a chemical reaction
General Stoichiometry Notes STOICHIOMETRY: tells relative amts of reactants & products in a chemical reaction Given an amount of a substance involved in a chemical reaction, we can figure out the amount
More informationIdeal Gas & Gas Stoichiometry
Ideal Gas & Gas Stoichiometry Avogadro s Law V a number of moles (n) V = constant x n Constant temperature Constant pressure V 1 /n 1 = V 2 /n 2 Ammonia burns in oxygen to form nitric oxide (NO) and water
More informationGas Volumes and the Ideal Gas Law
SECTION 11.3 Gas Volumes and the Ideal Gas Law Section 2 presented laws that describe the relationship between the pressure, temperature, and volume of a gas. The volume of a gas is also related to the
More informationTypes of Chemical Reactions and Predicting Products
Types of Chemical Reactions and Predicting Products Pre-Lab Discussion There are many kinds of chemical reactions and several ways to classify them. One useful method classifies reactions into four major
More information12.2. The Ideal Gas Law. Density and Molar Mass of Gases SECTION. Key Terms
SECTION 12.2 The Ideal Gas Law You have related the combined gas law to Avogadro s volume-mole gas relationship using two sets of conditions. This enabled you to make calculations of pressure, temperature,
More information5. What pressure (in atm) would be exerted by 76 g of fluorine gas in a 1.50 liter vessel at -37 o C? a) 26 atm b) 4.1 atm c) 19,600 atm d) 84 atm
Test bank chapter (5) Choose the most correct answer 1. A sample of oxygen occupies 47.2 liters under a pressure of 1240 torr at 25 o C. What volume would it occupy at 25 o C if the pressure were decreased
More informationIGCSE (9-1) Edexcel - Chemistry
IGCSE (9-1) Edexcel - Chemistry Principles of Chemistry Chemical Formulae, Equations and Calculations NOTES 1.25: Write word equations and balanced chemical equations (including state symbols): For reactions
More informationLab: Types of Chemical Reactions
Name: Date: Period: Lab: Types of Chemical Reactions ESSENTIAL QUESTION: How do we represent chemical reactions as a chemical equation? BACKGROUND- See class handout. PRELAB: 1. What is a chemical reaction
More informationWhat is a Mole? An Animal or What?
Unit 7: (Chapter 9) Chemical Quantities What is a Mole? An Animal or What? Section 9.1 The Mole: A Measurement of Matter Describe how Avogadro s number is related to a mole of any substance. Calculate
More informationCHEMICAL REACTIONS OF COPPER AND PERCENT YIELD
CHEMICAL REACTIONS OF COPPER AND PERCENT YIELD Objective To gain familiarity with basic laboratory procedures, some chemistry of a typical transition element, and the concept of percent yield. Apparatus
More informationUnit Outline. I. Introduction II. Gas Pressure III. Gas Laws IV. Gas Law Problems V. Kinetic-Molecular Theory of Gases VI.
Unit 10: Gases Unit Outline I. Introduction II. Gas Pressure III. Gas Laws IV. Gas Law Problems V. Kinetic-Molecular Theory of Gases VI. Real Gases I. Opening thoughts Have you ever: Seen a hot air balloon?
More informationChemical Reactions: Introduction to Reaction Types
Chemical Reactions: Introduction to Reaction Types **Lab Notebook** Record observations for all of the chemical reactions carried out during the lab in your lab book. These observations should include:
More informationCounting by mass: The Mole. Unit 8: Quantification of Chemical Reactions. Calculating molar mass. Particles. moles and mass. moles and particles
Unit 8: Quantification of Chemical Reactions Chapter 10: The mole Chapter 12: Stoichiometry Counting by mass: The Mole Chemists can t count individual atoms Use moles to determine amounts instead mole
More informationCHAPTER 14: The Behavior of Gases
Name: CHAPTER 14: The Behavior of Gases Period: RELATIONSHIPS BETWEEN PRESSURE, VOLUME & TEMPERATURE OF A GAS Boyle s Law-Pressure and Volume Volume (ml) Pressure ( ) 60 50 40 30 20 10 Practice problem:
More informationEXPERIMENT 7 Reaction Stoichiometry and Percent Yield
EXPERIMENT 7 Reaction Stoichiometry and Percent Yield INTRODUCTION Stoichiometry calculations are about calculating the amounts of substances that react and form in a chemical reaction. The word stoichiometry
More informationMultiple Choices: Choose the best (one) answer. Show in bold. Questions break-down: Chapter 8: Q1-8; Chapter 9: Q9-16: Chapter 10:
HCCS CHEM 1405 textbook PRACTICE EXAM III (Ch. 8-10) 5 th and 6 th edition of Corwin s The contents of these chapters are more calculation-oriented and are the beginning of learning of the chemical language.
More informationUnit 4 ~ Learning Guide Name:
Unit 4 ~ Learning Guide Name: Instructions: Using a pencil, complete the following notes as you work through the related lessons. Show ALL work as is eplained in the lessons. You are required to have this
More informationL = 6.02 x mol Determine the number of particles and the amount of substance (in moles)
1.1 The Mole 1.1.1 - Apply the mole concept to substances A mole is the name given to a certain quantity. It represents 6.02 x 10 23 particles. This number is also known as Avogadro's constant, symbolised
More informationHomework 12 (Key) First, separate into oxidation and reduction half reactions
Homework 12 (Key) 1. Balance the following oxidation/reduction reactions under acidic conditions. a. MnO 4 - + I - I 2 + Mn 2+ First, separate into oxidation and reduction half reactions Oxidation half
More informationEvaluation copy. The Molar Mass of a Volatile Liquid. computer OBJECTIVES MATERIALS
The Molar Mass of a Volatile Liquid Computer 3 One of the properties that helps characterize a substance is its molar mass. If the substance in question is a volatile liquid, a common method to determine
More information2. Relative molecular mass, M r - The relative molecular mass of a molecule is the average mass of the one molecule when compared with
Chapter 3: Chemical Formulae and Equations 1. Relative atomic mass, A r - The relative atomic mass of an element is the average mass of one atom of an element when compared with mass of an atom of carbon-12
More informationPhysical Changes and Chemical Reactions
Physical Changes and Chemical Reactions Gezahegn Chaka, Ph.D., and Sudha Madhugiri, Ph.D., Collin College Department of Chemistry Objectives Introduction To observe physical and chemical changes. To identify
More information1. Mole Definition & Background
Unit 5: THE MOLE 1. Mole Definition & Background 2. Molar Mass 3. Mole Calculations 4. Percent Composition 5. Empirical Formulas 6. Molecular Formulas 1 1. Mole Definition & Background The mole was developed
More informationComposion Stoichiometry
Composition Stoichiometry blank 3.3.13.notebook Due: Ch 10 RG Hummmm... How do you "measure" bananas? > How many? Count 1 dozen naners or 12 naners Composion Stoichiometry 3 new conversion factors > Avogadro's
More informationClassifying Chemical Reactions Analyzing and Predicting Products
Classifying Chemical Reactions Analyzing and Predicting Products Background A chemical reaction is defined as any process in which one or more substances are converted into new substances with different
More informationWhat is a Representative Particle
Chapter 7 Moles What is a Representative Particle The smallest unit into which a substance can be broken down without changing the composition of the substance. Atoms, molecules, and formula units What
More informationRevision Checklist :4.3 Quantitative Chemistry
Revision Checklist :4.3 Quantitative Chemistry Conservation of Mass The law of conservation of mass states that no atoms are lost or made during a chemical reaction so the mass of the products equals the
More informationExperiment 14 - Qualitative Analysis
Introduction Qualitative analysis involves the identification of the substances in a mixture. When chemical methods are used in the identification of mixtures of metal cations, these ions are usually separated
More informationClassifying Chemical Reactions: Lab Directions
Classifying Chemical Reactions: Lab Directions Please Return Background: The power of chemical reactions to transform our lives is visible all around us in our homes, in our cars, even in our bodies. Chemists
More informationElectrolysis: Splitting Water Student Advanced Version
Electrolysis: Splitting Water Student Advanced Version In this lab you will use a battery to perform electrolysis, or chemical decomposition, of different aqueous solutions (like water) to produce gases
More informationLaboratory 3. Development of an Equation. Objectives. Introduction
Laboratory 3 Development of an Equation Objectives Apply laboratory procedures and make observations to investigate a chemical reaction. Based on these observations, identify the pattern of reactivity
More informationThe Molecular Weight of Carbon Dioxide
The Molecular Weight of Carbon Dioxide Objectives The objectives of this laboratory are as follows: To generate and collect a sample of carbon dioxide gas, then measure its pressure, volume, temperature
More information4 CO O 2. , how many moles of KCl will be produced? Use the unbalanced equation below: PbCl 2. PbSO 4
Honors Chemistry Practice Final 2017 KEY 1. Acetylene gas, C 2, is used in welding because it generates an extremely hot flame when combusted with oxygen. How many moles of oxygen are required to react
More informationSection Using Gas Laws to Solve Problems
Gases and Gas Laws Section 13.2 Using Gas Laws to Solve Problems Kinetic Molecular Theory Particles of matter are ALWAYS in motion Volume of individual particles is zero. Consists of large number of particles
More information9/18/2013. Scientists represent atoms by using different colored circles, called a model.
Pre-Lab Notes Lab Title: Behavior of Gases: Molar Mass of a Vapor Purpose: To determine the molar mass of a gas from a knowledge of its mass, temperature, pressure, and volume. Each element is unique.
More information4) Tetrasulfur trioxide. 5) barium fluoride. 6) nitric acid. 7) ammonia
Unit 9: The Mole- Funsheets Part A: Molar Mass Write the formula AND determine the molar mass for each of the following. Be sure to include units and round you answer to 2 decimal places. 1) calcium carbonate
More informationSTOICHIOMETRIC RELATIONSHIPS
STOICHIOMETRIC RELATIONSHIPS Most chemical reactions involve two or more substances reacting with each other. Substances react with each other in certain ratios, and stoichiometry is the study of the ratios
More informationCHM 130LL: Chemical and Physical Changes
CHM 130LL: Chemical and Physical Changes In this experiment you will observe and record observations of properties of substances and you will cause changes to occur and classify these changes as physical
More informationUnit 6: Chemical Quantities. Understanding The Mole
Unit 6: Chemical Quantities Understanding The Mole 1 How do We Typically Measure Matter? You can measure mass, or volume, or you can count pieces. We measure mass in grams. We measure volume in liters.
More information6.02 x 1023 CHAPTER 10. Mole. Avogadro s Number. Chemical Quantities The Mole: A Measurement of Matter Matter is measured in one of three ways:
Chapter 10 Notes CHAPTER 10 10.1 The Mole: A Measurement of Matter Matter is measured in one of three ways: Chemical Quantities Mole SI unit that measures the amount of a substance A mole of a substance
More informationChapter 11. Preview. Lesson Starter Objectives Pressure and Force Dalton s Law of Partial Pressures
Preview Lesson Starter Objectives Pressure and Force Dalton s Law of Partial Pressures Section 1 Gases and Pressure Lesson Starter Make a list of gases you already know about. Separate your list into elements,
More informationChapter 3 Stoichiometry. Ratios of combination
Chapter 3 Stoichiometry Ratios of combination Topics Molecular and formula masses Percent composition of compounds Chemical equations Mole and molar mass Combustion analysis (Determining the formula of
More informationLesson Plan Book-stacking Activity
T o g o d i r e c t l y t o a l e s s o n, c l i c k o n e o f t h e f o l l o w i n g l i n k s : B o o k - s t a c k i n g A c t i v i t y B a l l o o n A c t i v i t y H y d r o g e n G a s L a b F
More informationGases. A gas. Difference between gas and vapor: Why Study Gases?
Gases Chapter 5 Gases A gas Uniformly fills any container. Is easily compressed. Mixes completely with any other gas. Exerts pressure on its surroundings. Difference between gas and vapor: A gas is a substance
More informationAlthough different gasses may differ widely in their chemical properties, they share many physical properties
IV. Gases (text Chapter 9) A. Overview of Chapter 9 B. Properties of gases 1. Ideal gas law 2. Dalton s law of partial pressures, etc. C. Kinetic Theory 1. Particulate model of gases. 2. Temperature and
More informationNotes: Stoichiometry (text Ch. 9)
Name Per. Notes: Stoichiometry (text Ch. 9) NOTE: This set of class notes is not complete. We will be filling in information in class. If you are absent, it is your responsibility to get missing information
More informationCHEMISTRY 202 Hour Exam I. Dr. D. DeCoste T.A.
CHEMISTRY 202 Hour Exam I September 22, 2016 Dr. D. DeCoste Name Signature T.A. This exam contains 23 questions on 11 numbered pages. Check now to make sure you have a complete exam. You have two hours
More informationName Date Class THE ARITHMETIC OF EQUATIONS
12.1 THE ARITHMETIC OF EQUATIONS Section Review Objectives Calculate the amount of reactants required or product formed in a nonchemical process Interpret balanced chemical equations in terms of interacting
More informationChemistry Section Review 7.3
Chemistry Section Review 7.3 Multiple Choice Identify the choice that best completes the statement or answers the question. Put the LETTER of the correct answer in the blank. 1. The molar mass of an element
More information2.1.3 Amount of substance
2.1.3 Amount of substance The mole is the key concept for chemical calculations DEFINITION: The mole is the amount of substance in grams that has the same number of particles as there are atoms in 12 grams
More informationExperiment 8 - Double Displacement Reactions
Experiment 8 - Double Displacement Reactions A double displacement reaction involves two ionic compounds that are dissolved in water. In a double displacement reaction, it appears as though the ions are
More informationName: Unit 4 Study Guide Part 1
Name: Unit 4 Study Guide Part 1 Review of last unit: 1. What follows an element s symbol in a chemical formula to indicate the number of atoms of that element in one molecule of the compound? 2. What is
More information7-A. Inquiry INVESTIGATION. 322 MHR Unit 3 Quantities in Chemical Reactions. Skill Check. Safety Precautions
Inquiry INVESTIGATION 7-A Skill Check Initiating and Planning Performing and Recording Analyzing and Interpreting Communicating Safety Precautions Wear safety eyewear throughout this investigation. Wear
More informationStoichiometry ( ) ( )
Stoichiometry Outline 1. Molar Calculations 2. Limiting Reactants 3. Empirical and Molecular Formula Calculations Review 1. Molar Calculations ( ) ( ) ( ) 6.02 x 10 23 particles (atoms or molecules) /
More informationPlease understand that you will NOT receive another copy of this packet! Name:
Mole Unit Packet Please understand that you will NOT receive another copy of this packet! Name: Period: Introduction to The unit of the Mole is the HEART of all chemistry and most of its calculations.
More informationB 2, C 2, N 2. O 2, F 2, Ne 2. Energy order of the p 2p and s 2p orbitals changes across the period.
Chapter 11 Gases Energy order of the p p and s p orbitals changes across the period. Due to lower nuclear charge of B, C & N there is no s-p orbitals interaction Due to high nuclear charge of O, F& Ne
More informationLesson (1) Mole and chemical equation
Lesson (1) Mole and chemical equation 1 When oxygen gas reacts with magnesium, magnesium oxide is formed. Such Reactions are described by balanced equations known as "chemical equations" Δ 2Mg(s) + O2(g)
More informationPhysical and Chemical Changes
Objectives Introduction Physical and Chemical Changes Gezahegn Chaka, Ph.D. Collin College Department of Chemistry To observe physical and chemical changes. To identify and characterize physical and chemical
More informationChemical Reactions of Copper and Percent Recovery
and Percent Recovery EXPERIMENT 9 Prepared by Edward L. Brown, Lee University To take copper metal through series of chemical reactions that regenerates elemental copper. Students will classify the various
More informationUNIT 1 Chemical Reactions Part II Workbook. Name:
UNIT 1 Chemical Reactions Part II Workbook Name: 1 Molar Volume 1. How many moles of a gas will occupy 2.50 L at STP? 2. Calculate the volume that 0.881 mol of gas at STP will occupy. 3. Determine the
More informationChapter 3. Stoichiometry
Chapter 3 Stoichiometry Chapter 3 Chemical Stoichiometry Stoichiometry The study of quantities of materials consumed and produced in chemical reactions. Since atoms are so small, we must use the average
More informationMinneapolis Community and Technical College. Separation of Components of a Mixture
Minneapolis Community and Technical College Chemistry Department Chem1020 Separation of Components of a Mixture Objectives: To separate a mixture into its component pure substances. To calculate the composition
More informationElemental Mass Percent and Empirical Formula from Decomposition
EXPERIMENT Elemental Mass Percent and Empirical Formula from Decomposition 10 Prepared by Edward L. Brown, Lee University The student will heat copper oxide in a methane atmosphere forming elemental copper.
More informationPractice Test Unit A Stoichiometry Name Per
Practice Test Unit A Stoichiometry Name Per This is practice - Do NOT cheat yourself of finding out what you are capable of doing. Be sure you follow the testing conditions outlined below. DO NOT USE A
More informationAP Chemistry Lab #5- Synthesis and Analysis of Alum (Big Idea 1 & 2)
www.pedersenscience.com AP Chemistry Lab #5- Synthesis and Analysis of Alum (Big Idea 1 & 2) 1.A.1: Molecules are composed of specific combinations of atoms; different molecules are composed of combinations
More informationFormulas and Models 1
Formulas and Models 1 A molecular formula shows the exact number of atoms of each element in the smallest unit of a substance An empirical formula shows the simplest whole-number ratio of the atoms in
More informationMolar Mass. The total of the atomic masses of all the atoms in a molecule:
Molar Mass The total of the atomic masses of all the atoms in a molecule: Ex: H 2 O H (1.0079) x 2 atoms = 2.0158 grams O (15.999) x 1 atom = 15.999 grams 18.0148 grams (18.0 grams) Ex: Cu(NO 3 ) 2 Cu
More informationChemical Background Information: Magnesium reacts with oxygen in air to for magnesium oxide, according to equation 1.
HESS S LAW LAB Pre lab assignment: You will need to complete the following parts prior to doing the lab: Title, Purpose, and Storyboard of the procedures for each part, Blank Data tables, and the Prelab
More informationName: Unit 9- Stoichiometry Day Page # Description IC/HW
Name: Unit 9- Stoichiometry Day Page # Description IC/HW Due Date Completed ALL 2 Warm-up IC 1 3 Stoichiometry Notes IC 1 4 Mole Map IC X 1 5 Mole to Mole Practice IC 1 6 Mass to Mole Practice IC 1/2 X
More informationCHEMISTRY 202 Hour Exam I. Dr. D. DeCoste T.A.
CHEMISTRY 0 Hour Exam I September, 016 Dr. D. DeCoste Name Signature T.A. This exam contains 3 questions on 11 numbered pages. Check now to make sure you have a complete exam. You have two hours to complete
More informationStoichiometric relationships 1
Stoichiometric relationships 1 Chapter outline Describe the three states of matter. Recall that atoms of diff erent elements combine in fi xed ratios to form compounds which have diff erent properties
More informationo Test tube In this experiment, you ll be observing the signs of chemical reactions. These include the following:
Experiment: Chemical Reactions & Chemical s Objective In this experiment, students perform a variety of chemical reactions. For each reaction, student identify the signs that a reaction has occurred, write
More informationHYSICAL AND CHEMICAL PROPERTIES AND PHYSIC AND CHEMICAL CHANGES
Experiment 4 Name: 15 P HYSICAL AND CHEMICAL PROPERTIES AND PHYSIC AND CHEMICAL CHANGES 13 Al e In this experiment, you will also observe physical and chemical properties and physical and chemical changes.
More informationUnit 6 Chemical Analysis. Chapter 8
Unit 6 Chemical Analysis Chapter 8 Objectives 39 Perform calculations using the mole to calculate the molar mass 40 Perform calculations using the mole to convert between grams, number of particles, volume,
More informationChemistry Entrance Material for Grade 10 to
Chemistry Entrance Material for Grade 10 to 11 2018-2019 Chapter 1: Laboratory Skills and Techniques In all multiple choice questions, more than answer could be correct Section : 1 Safety Rules Concept
More informationChapter 5. The Gas Laws
Chapter 5 The Gas Laws 1 Pressure Force per unit area. Gas molecules fill container. Molecules move around and hit sides. Collisions are the force. Container has the area. Measured with a barometer. 2
More informationPractice Test. Moles & Stoich. Page What is the total number of nitrogen atoms in 0.25 mole of NO2 gas? (1)
1. What is the total number of nitrogen atoms in 0.25 mole of NO2 gas? (1) 1.5 10 23 (3) 3.0 10 23 (2) 6.0 10 23 (4) 1.2 10 24 2. Which quantity of O2 contains exactly 3.01 10 23 molecules? (1) 0.250 mole
More information