Practice Work 53 Stoichiometry-04 Mixed Stoichiometry Problems

Transcription

1 Last Name Do Date First Name Section M T W R Practice Work 53 Stoichiometry-04 Mixed Stoichiometry Problems General Information You will need a periodic table, your stoichiometry notes, and Appendix 2 for this assignment. Sorry about the lack of format. I m in a time crunch g/mol g/mol g/mol Reaction : P4(s) + 6 Cl2(g) 4 PCl3(g) molecules (grams) A) On the Stoichiometry Map below: circle the starting place and the ending place, given the information above. B) Calculate the mass (in grams) of phosphorus trichloride that will be formed from chlorine molecules. ( Cl 2 molec mol Cl 2 ) ( Cl 2 molec ) (4 mol PCl 3 ) ( g PCl 3 ) = xx g PCl 6 mol Cl 2 mol PCl 3 xx 3 Page of 8

2 Reaction 2 Information will be used for Questions 2a, 2b, 3a, and 3b g/mol g/mol g/mol g/mol Reaction 2: 2 NaCl(aq) + Pb(NO3)2(aq) PbCl2(s) + 2 NaNO3(aq) 4.00 M L XS.00 M 0.00 L LR (grams) 2A) On the Stoichiometry Map below: circle the starting place and the ending place, given the information above. Remember: for stoichiometry, you always start with the LR. 2B) Calculate the mass (in grams) of lead(ii) chloride that will be formed from the limiting reagent L NaCl soln 4.00 mol NaCl ( ) ( L NaCl soln ) ( mol PbCl 2 2 mol NaCl ) (278.0 g PbCl 2 ) = xx39 g PbCl mol PbCl 2 xx 2 Page 2 of 8

3 Reaction 2 Information will be used for Questions 2A, 2B, 3A, and 3B g/mol g/mol 278. g/mol g/mol Reaction 2: 2 NaCl(aq) + Pb(NO3)2(aq) PbCl2(s) + 2 NaNO3(aq) 4.00 M L XS.00 M 0.00 L LR (molarity) 3A) On the Stoichiometry Map below: circle the starting place and the ending place, given the information above. Remember: for stoichiometry, you always start with the LR. 3B) Remember that molarity is equal to the moles of solute divided by the total volume of solution. Look carefully at the data. Calculate the total volume of the solution after both reactants are added together. V TOTAL = V NaCl + V PbNO3 = L L = xx0.350 Lxx 3C) Calculate the molarity of sodium nitrate from the limiting reagent L NaCl soln 4.00 mol NaCl ( ) ( L NaCl soln ) (2 mol NaNO 3 ) =.00 mol NaNO 2 mol NaCl 3 M = ( mol NaNO 3 ) = (.00 mol NaNO 3 L soln L soln ) = xx2.86 M NaNO 3xx Page 3 of 8

4 98.09 g/mol 84.0 g/mol 278. g/mol 44.0 g/mol 8.02 g/mol Reaction 4: H2SO4(aq) + 2 NaHCO3(aq) Na2SO4(aq) + 2 CO2(g) + 2 H2O(g) M L LR.50 M L XS (particles) 4A) On the Stoichiometry Map below: circle the starting place and the ending place, given the information above. Remember: for stoichiometry, you always start with the LR. 4B) Calculate the number of molecules of carbon dioxide that will be produced from the limiting reactant. ( L H 2SO 4 soln ) ( mol H 2SO 4 L H 2 SO 4 soln ) ( 2 mol CO 2 ) ( CO 2 molec ) = xx CO mol H 2 SO 4 mol CO 2 molecxx 2 Page 4 of 8

5 6.98 g/mol 8.02 g/mol g/mol Reaction 5: Na2O(s) + H2O(l) 2 NaOH(aq) 00.0 g.250 L LR XS (molarity) 5A) On the Stoichiometry Map below: circle the starting place and the ending place, given the information above. Remember: for stoichiometry, you always start with the LR. 5B) Calculate the molarity of NaOH. Remember the volume of solution comes from the liquid volume of water. (There is no liquid volume for Na2O because it is a solid.) ( 00.0 g Na 2O ) ( mol Na 2O mol NaOH ) (2 ) = mol NaOH 6.98 g Na 2 O mol Na 2 O mol NaOH mol NaOH M NaOH = ( ) = ( ) = xx2.582 M NaOHxx L soln.250 L soln Page 5 of 8

6 74.26 g/mol g/mol 3.80 g/mol 0.0 g/mol Reaction 6: K2SO4(s) + 2 AgNO3(aq) 2 Ag2SO4(aq) + KNO3(aq) L.80 M Volume.25 M 6A) On the Stoichiometry Map below: circle the starting place and the ending place, given the information above. 6B) Calculate the volume (in L) of AgNO3 that is required to react with L of.80 M potassium sulfate. ( L K 2SO 4 soln ) (.80 mol K 2SO 4 L K 2 SO 4 soln ) (2 mol AgNO 3 ) ( L AgNO soln 3 ) = xx0.720 L AgNO mol K 2 SO 4.25 mol AgNO 3 xx 3 Page 6 of 8

7 (Sorry that there is no question 7. It was too difficult, so I omitted it without replacing it.) g/mol g/mol 3.80 g/mol Reaction 8: Cl2O7(g) + H2O(l) 2 HClO4(aq) Did you forget to check the balance? (particles) 4.00 L 0.00 M 8A) On the Stoichiometry Map below: circle the starting place and the ending place, given the information above. 8B) Calculate the number of molecules of dichlorine pentoxide was necessary to produce 4.00 L of 0.00 M HClO4. ( L K 2SO 4 soln ) (.80 mol K 2SO 4 L K 2 SO 4 soln ) (2 mol AgNO 3 ) ( L AgNO soln 3 ) = xx0.720 L AgNO mol K 2 SO 4.25 mol AgNO 3 xx 3 Page 7 of 8

8 74.26 g/mol g/mol 3.80 g/mol Reaction 9: Cl2O3(g) + H2O(l) 2 HClO2(aq) Did you forget to check the balance? g L M 9A) On the Stoichiometry Map below: circle the starting place and the ending place, given the information above. 9B) Calculate the volume (in L) of M HClO2 that is produced from grams of Cl2O3. ( g Cl 2O 3 ) ( mol Cl 2O 3 ) ( 2 mol HClO 2 ) ( L HClO 2 soln ) = xx9.8 L HClO g Cl 2 O 3 mol Cl 2 O mol HClO 2 xx 2 Page 8 of 8