CHEMISTRY. SECTION 1 (Maximum Marks : 28) at room temperature changes from gas to solid down the group (B) decrease in HOMO-LUMO gap down the group

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1 JEE ADVANCED 07_-05-7 (PAPER-I)_Code-0 [ ] This section contains SEVEN questions. CEMISTRY SECTIN (Maximum Marks : 8) Each question has FUR options (A), (B), (C) and (D). NE R MRE TAN NE of these four options is (are) correct For each question, darken the bubble(s) corresponding to all the correct option(s) in the RS. For each question, marks will be awarded in one of the following categories : Full Marks : +4 If only the bubble(s) corresponding to all the correct option(s) is(are) darkened Partial Marks : + For darkening a bubble corresponding to each correct option, provided N incorrect option is darkened Zero Marks : 0 If none of the bubbles is darkened Negative Marks : In all other cases For example, if (A), (C) and (D) are all the correct options for a question, darkening all these three will get +4 marks; darkening only (A) and (D) will get + marks; and darkening (A) and (B) will get marks, as a wrong option is also darkened. 9. The colour of the X molecules of group 7 elements changes gradually from yellow to voilet down the group. This is due to : (A) the physical state of X at room temperature changes from gas to solid down the group (B) decrease in M-LUM gap down the group (C) decrease in * * gap down the group Ans. (B, C) (D) decrease in ionization energy down the group Colour of halogen is due to charge transfer from M ( * ) -LUM ( * ). 0. Addition of excess aqueous ammonia to a pink coloured aqueous solution of MCl 6 (X) and N 4 Cl gives an octahedral complex Y in the presence of air. In aqueous solution, complex Y behaves as : electrolyte. The reaction of X with excess Cl at room temperature results in the formation of a blue coloured complex Z. The calculated spin only magnetic moment of X and Z is.87 B.M., whereas it is zero for complex Y. Among the following options, which statement(s) is(are) correct? (A) The hybridization of the central metal ion in Y is d²sp³ (B) When X and Z are in equilibrium at 0ºC, the colour of the solution is pink. (C) Z is a tetrahedral complex (D) Addition of silver nitrate to Y gives only two equivalents of silver chloride Ans. (A, B, C)

2 [ ] JEE ADVANCED 07_-05-7 (PAPER-I)_Code-0 [Co( ) ]Cl 6 (X) Pink excess N (aq) N4Cl (air) (d²sp³) [Co(N ) 6]Cl (Y) ( : ) electrolyte M.M. = 0 Excess of Conc. Cl AgN solution [CoCl 4] + (Z) Blue M.M =.87 B.M Pink colour dominates because [Co() 6]Cl is more stable than [CoCl ] 4 AgCl three equivalent. An ideal gas is expanded from (p, V, T ) to (p, V, T ) under different conditions. The correct statement(s) among the following is(are) : (A) (B) If the expansion is carried out freely, it is simultaneously both isothermal as well as adiabatic. The work done by the gas is less when it is expanded reversibly from V to V under adiabatic conditions as compared to that when expanded reversibly from V to V under isothermal conditions. (C) The work done on the gas is maximum when it it compressed irreversibly from (p, V ) to (p, V ) against constant pressure p (D) The change in internal energy of the gas is (i) zero, if it is expanded reversibly with T = T, and (ii) Ans. (A, B, C) positive, if it is expanded reversibly under adiabatic conditions with T T (A) In free expansion W = 0 q U If U 0 then q = 0 or vice-vesa. (B) W adia < W iso : (C) W = P (V V ) : (D) Area under the curve is maximum. U ncvt 0 if T = T U ncvt If adiabatic, expansion is done, temperature decreases and hence T 0 U 0 So, wrong P P Adiabatic (P, V ) II Isothermal V I (P, V ) V

3 JEE ADVANCED 07_-05-7 (PAPER-I)_Code-0 [ ]. For a solution formed by mixing liquids L and M, the vapour pressure of L plotted against the mole fraction of M in solution is shown in the following figure. ere x L and x M represent mole fractions of L and M, respectively, in the solution. The correct statement(s) applicable to the system is(are) : (A) Attractive intermolecular interactions betweeen L-L in pure liquid L and M-M in pure liquid M are stronger than those between L-M when mixed in solution. Ans. (A, D) (B) The point Z represents vapour pressure of pure liquid M and Raoult s law is obeyed when xl 0 (C) The point Z represents vapour pressure of pure liquid M and Raoult s law is obeyed from x L = 0 to x L = (D) The point Z represents vapour pressure of pure liquid L and Raoult s law is obeyed when xl The given graph shows the (+ve) deviation from Raoult s law. So, L-M interaction < L-L and M-M interaction. thats why (A) is Correct. Point Z represent vapour pressure of pure liquid L When x M = 0, x L = (pure L) and in this condition there is no deviation from ideal behaviour and thats why (D) is correct.. The IUPAC name(s) of the following compound is(are) : C Cl (A) -chloro-4-methylbenzene (B) 4-chlorotoluene (C) -methyl-4-chlorobenzene (D) 4-methylchlorobenzene Ans. (A, B) Cl C -chloro-4-methylbenzene and 4-chlorotoluene both are correct IUPAC name of the above compound.

4 [ 4 ] JEE ADVANCED 07_-05-7 (PAPER-I)_Code-0 4. The correct statement(s) for the following addition reactions is(are) : (i) C C Br /CCl M and N (ii) (A) (B) (C) (D) Ans. (B, D) C C and P are identical molecules Br /CCl and P Bromination proceeds through trans-addition in both the reactions (M and ) and (N and P) are two pairs of enantiomers (M and ) and (N and P) are two pairs of diastereomers (i) C C Br /CCl anti addition C Br Br M and N are identical C (Meso) (ii) C C C C Br /CCl Br Br anti addition Br Br C C '' 'P' both are enantiomers M and are diastereomers N & P are diastereomers 5. The correct statement(s) about the oxoacids, Cl 4 and Cl, is (are) : (A) The conjugate base of Cl 4 is weaker base than (B) The central atom in both Cl 4 and Cl is sp³ hybridized (C) Cl 4 is formed in the reaction between Cl and (D) Cl 4 is more acidic than Cl because of the resonance stabilization of its anion Ans. (A, B, D)

5 JEE ADVANCED 07_-05-7 (PAPER-I)_Code-0 [ 5 ] * Cl==, Cl (central atom is sp hybridised) * Cl is weaker base than 4 * Cl Cl Cl * Cl Cl (stability due to resonance) SECTIN (Maximum Marks : 5) This section contains FIVE questions The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive For each question, darken the bubble corresponding to the correct integer in the RS For each question, marks will be awarded in one of the following categories : Full Marks : + If only the bubble corresponding to the correct answer is darkened Zero Marks : 0 In all other cases 6. The conductance of a M aqueous solution of a weak monobasic acid was determined by using a conductivity cell consisting of platinized Pt electrodes. The distance between the electrodes is 0 cm with an area of cross section of cm. The conductance of this solution was found to be S. The 0 p of the solution is 4. The value of limiting molar conductivity m of this weak monobasic acid in Ans. (6) aqueous solution is Z 0 Scm mol. The value of Z is 0 (G) S cm A m M 5 0 m Z 0 0Z Also, [ ] C Z 5 4 Z 6 0 4

6 [ 6 ] JEE ADVANCED 07_-05-7 (PAPER-I)_Code-0 7. The sum of the number of lone pairs of electrons on each central atom in the following species is [TeBr ],[BrF ],SNF,and [XeF ] 6 (Atomic numbers: N = 7, F = 9, S = 6, Br = 5, Te = 5, Xe = 54) Ans. (6) Molecule L.P. [Te Br 6 ] + [Br F ] SN F. [XeF ] F F S F N 0 Total = 6 8. Among the following, the number of aromatic compound(s) is Ans. (5) This is nonplanar (tub shape), so nonaromatic 4 e delocalised, so anti-aromatic electron delocalised so, aromatic Non planar & not fully conjugated so, non aromatic 6 e delocalised so, aromatic (Tropyllium ion)

7 JEE ADVANCED 07_-05-7 (PAPER-I)_Code-0 [ 7 ] 4 e delocalised so, anti-aromatic 6 e delocalised so, aromatic In left side ring 6 e delocalised so, aromatic All three rings are aromatic(4 e delocalised). Total five structures are aromatic. 9. A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm. If the density of the substance in the crystal is 8 g cm, then the number of atoms present in 56 g of the crystal is N 0 4. The value of N is Ans. () In Fcc: a = 400 pm, Z = cm d 8 g / CC no. of atoms in 56 g is N 0 4, N =? Z M d N a A 4 M (4 0 ) M no. of atoms = m N M N = A g Among,e,Li,Be,B,C,N,, and F, the number of diamagnetic species is (Atomic numbers: =, e =, Li =, Be = 4, B = 5, C = 6, N = 7, = 8, F = 9) Ans. (6) If number of unpaired electron = 0, then molecule is considered as DIAMAGNETIC. For Z 4 (s) * (s) (s) * (s) (p p ) x y z x y z, Li, C, N, Be and F are diamagnetic. (p ) * (p p ) * (p )

8 l [ 8 ] JEE ADVANCED 07_-05-7 (PAPER-I)_Code-0 SECTIN (Maximum Marks : 8) This section contains SIX questions of matching type This section contains TW tables (each haivng columns and 4 rows) Based on each table, there are TREE questions Each question has FUR options (A), (B), (C) and (D). NLY NE of these four options is correct For each question, darken the bubble corresponding to the correct option in the RS For each question, marks will be awarded in one of the following categories : Full Marks : + If only the bubble corresponding to the correct option is darkened Zero Marks : 0 If none of the bubbles is darkened Negative Marks : In all other cases Answer Q., Q. and Q. by appropriately matching the information given in the three columns of the following table. The wave function, n, l,m is a mathematical function whose value depends upon spherical polar coordinates l (r,, ) of the electron and characterized by the quantum numbers n, l and m. ere r is distance from nucleus, is colatitude and is azimuth. In the mathematical functions given in the Table, Z is atomic number and a 0 is Bohr radius. l Column Column Column (I) s orbital (i) n, l,m l Z a0 e Zr a 0 (P) n, l,m (r) 0 r/a 0 (II) s orbital (ii) ne radial node (Q) Probability density at nucleus 5 a0 Zr (III) p z orbital (iii) a n, l,m Z 0 l re cos (R) Probability density a0 is maximum at nucleus (IV) dz orbital (iv) xy-plane is a nodal plane (S) Energy needed to excite electron from n = state to n = 4 state is 7 times the energy needed to excite electron from n = state to n = 6 state

9 JEE ADVANCED 07_-05-7 (PAPER-I)_Code-0 [ 9 ]. For e + ion, the only INCRRECT combination is Ans. (D) [A] (I) (i) (R) [B] (II) (ii) (Q) [C] (I) (i) (S) [D] (I) (iii) (R) (i) s-orbital has no angular dependence. so, s-orbital can t have wave function containing (I) does not correspond to (iii) or.. For the given orbital in Column, the only CRRECT combination for any hydrogen-like species is Ans. (D) [A] (I) (ii) (S) [B] (IV) (iv) (R) [C] (III) (iii) (P) [D] (II) (ii) (P) s-orbital has radial node with vs r curves as given in P.. For hydrogen atom, the only CRRECT combination is Ans. (D) [A] (II) (i) (Q) [B] (I) (iv) (R) [C] (I) (i) (P) [D] (I) (i) (S) E.6 Z².6 Z² ev E 6.6 Z².6 Z² ev E4 / E 8 / Answer Q.4, Q.5 and Q.6 by appropriately matching the information given in the three columns of the following table. Columns, and contain starting materials, reaction conditions, and type of reactions, respectively Column Column Column (I) Toluene (i) Na/Br (P) Condensation (II) Acetophenone (ii) Br / h (Q) Carboxylation (III) Benzaldehyde (iii) (C C) /C CK (R) Substitution (IV) Phenol (iv) Na/C (S) aloform 4. The only CRRECT combination in which the reaction proceeds through radical mechanism is : Ans. (D) [A] (II) (iii) (R) [B] (III) (ii) (P) [C] (IV) (i) (Q) [D] (I) (ii) (R) (I) C Br /h (ii) C Br substitution reaction (R) C Br

10 [ 0 ] JEE ADVANCED 07_-05-7 (PAPER-I)_Code-0 5. For the synthesis of benzoic acid, the only CRRECT combination is : [A] (III) (iv) (R) [B] (IV) (ii) (P) [C] (II) (i) (S) [D] (I) (iv) (Q) Ans. (C) C C C (i) Na/Br + CBr (II) this is haloform reaction. (S) 6. The only CRRECT combination that gives two different carboxylic acids is : Ans. (C) [A] (IV) (iii) (Q) [B] (I) (i) (S) [C] (III) (iii) (P) [D] (II) (iv) (R) C (iii) (C C) /C CK C==C C + C C (III) this is Perkin reaction in which condensation occurs between two different molecules. (P)

PART I : PHYSICS. SECTION 1 (Maximum Marks: 28)

PART I : PHYSICS. SECTION 1 (Maximum Marks: 28) This section contains SEVEN questions PART I : PHYSICS SECTION 1 (Maximum Marks: 28) Each question has FOUR options [A], [B], [C] and [D]. ONE OR MORE THAN ONE of these four options is(are) correct For