Chemistry 132 NT. Acids and Bases

Similar documents
Contents and Concepts

Contents and Concepts

Section 32 Acids and Bases. Copyright (c) 2011 by Michael A. Janusa, PhD. All rights reserved.

Molecular Definitions of Acids and Bases: H 2 O (l)

Introduction to Acids & Bases. Packet #26

Introduction to Acids & Bases II. Packet #26

CHEMISTRY Matter and Change

Chapter 15. Preview. Lesson Starter Objectives Hydronium Ions and Hydroxide Ions The ph Scale Calculations Involving ph

Chemistry 132 NT. Acid-Base Equilibria. The face of a child can say it all. Especially the mouth part of the face.

Chapter 16 Acid-Base Equilibria

In the Brønsted-Lowry system, a Brønsted-Lowry acid is a species that donates H + and a Brønsted-Lowry base is a species that accepts H +.

Acids & Bases Strong & weak. Thursday, October 20, 2011

Definitions. Acids give off Hydrogen ions (protons) Bases give off hydroxide ions

Chem 321 Lecture 10 - Acid-Base Equilibria (Review) 10/1/13

Mixtures of Acids and Bases

Chemistry Monday, May 22 Tuesday, May 23, 2017

Stuff. Make-up Exam tomorrow night, Date: Tuesday Feb 17. Room: C-109 Time: 6-8 (1.5 hr) Problems for Acid-Bases posted. Hour Exam Solutions posted

Acids and Bases. A strong base is a substance that completely ionizes in aqueous solutions to give a cation and a hydroxide ion.

Objectives. Base Chemistry

Chapter 18. Acid-Base Equilibria. Acid Base Theories. There are three acid/base theories used to define acids and bases: Arrhenius Theory

Equilibrium constant

Common Ion Effect. Segue to Acid-Base Chemistry

12. Acid Base Equilibria

Chapter 14. Acids and Bases

Chemistry 12 UNIT 4 ACIDS AND BASES

Acids and Bases Notes (Ch. 15) A. Acids Vs. Bases

Unit 9. Acids, Bases, & Salts Acid/Base Equilibrium

C4S: ACID BASE EQUILIBRIUM Lesson 3

STOICHIOMETRY OF ACID-BASE NEUTRALIZATION REACTIONS. Ms. Grobsky

19.2 Hydrogen Ions and Acidity > Chapter 19 Acids, Bases, and Salts Hydrogen Ions and Acidity Acid-Base Theories

CHEMFILE MINI-GUIDE TO PROBLEM SOLVING CHAPTER 17. Name Date Class. 1 of 12

Chapter 16. Acid-Base Equilibria

Acids, Bases and ph Preliminary Course. Steffi Thomas 14/09/2017

THE BIG IDEA: REACTIONS. 1. Review nomenclature rules for acids and bases and the formation of acids and bases from anhydrides. (19.

1.12 Acid Base Equilibria

*In every acid-base reaction, equilibrium favors transfer of a proton from the stronger acid to the stronger base.

Problem Solving. ] Substitute this value into the equation for poh.

What is an acid? What is a base?

4. Acid Base Equilibria

[H + ] OH - Base contains more OH - than H + [OH - ] Neutral solutions contain equal amounts of OH - and H + Self-ionization of Water

What is an acid? What is a base?

Dr. Diala Abu-Hassan, DDS, PhD Lecture 3 MD summer 2014

Chemistry 132 NT. Acid-Base Equilibria

Acids, Bases, and ph. ACIDS, BASES, & ph

The Chemistry of Acids and Bases Separately Chapter 14 Part I

School of Chemistry, University of KwaZulu-Natal, Howard College Campus, Durban. CHEM191 Tutorial 1: Buffers

HA(s) + H 2 O(l) = H 3 O + (aq) + A (aq) b) NH 3 (g) + H 2 O(l) = NH 4 + (aq) + OH (aq) Acid no. H + type base no. OH type

ACIDS & BASES PROPERTIES OF ACIDS ACIDS PROPERTIES OF ACIDS PROPERTIES OF ACIDS 11/1/2016

Grace King High School Chemistry Test Review

Chapter 16: Acids and Bases I. Chem 102 Dr. Eloranta

Chap 16 Chemical Equilibrium HSU FUYIN

Stoichiometry of Acid-Base Neutralization Reactions. Ms. Grobsky

What are the properties of acids and bases?

Chem 116 POGIL Worksheet - Week 9 Equilibrium Continued Introduction to Acid-Base Concepts

capable of neutralizing both acids and bases

What is an acid? What is a base?

Titration region & buffer calculations. An acid base region is a circumstance

Lesson Five: Acids, Bases, ph, and Buffers

Acids, Bases and Salts. Chapters 19

Brønsted-Lowry Acid-Base Model. Chapter 13 Acids and Bases. The Nature of H + Outline. Review from Chapter 4. Conjugate Pairs

IB Chemistry ABS Introduction An acid was initially considered a substance that would produce H + ions in water.

Chpt 16: Acids and Bases

Chapter 10. Acids, Bases, and Salts

11/15/11. Chapter 16. HA(aq) + H 2 O(l) H 3 O + (aq) + A (aq) acid base conjugate conjugate

CHAPTER Acid & Base

Chapter 13 Acids and Bases

5.1.3 Acids, Bases and Buffers

Chemistry 210, March 2012 ANSWERS Extra acid/base/salt equilibrium problems. See solutions beginning on the next page.

Hydrogen Ions and Acidity Annotated Reading

Unit 4a Acids, Bases, and Salts Theory

Chapter 16. Acids and Bases. Copyright Cengage Learning. All rights reserved 1

Acid Base Equilibria

Chapter 16: Acid Base Equilibria Chapter 16 Acid-Base Equilibria Learning Standards & Objectives;

AP Chemistry CHAPTER 16 STUDY GUIDE Acid-Base Equilibrium

Acids and Bases. Click a hyperlink or folder tab to view the corresponding slides. Exit

Do Now May 1, Obj: Observe and describe neutralization reactions. Copy: Balance the neutralization reaction. KCl(aq) + H 2 O(l)

8.2. The Equilibrium of Weak Acids and Bases. The Ion Product Constant for Water. 388 MHR Unit 4 Chemical Systems and Equilibrium

Chem 5 PAL Worksheet Acids and Bases Smith text Chapter 8

Acid Base Equilibrium Review

Acid-Base Equilibria. 1.NH 4 Cl 2.NaCl 3.KC 2 H 3 O 2 4.NaNO 2. Acid-Ionization Equilibria. Acid-Ionization Equilibria

CHAPTER 8: ACID/BASE EQUILIBRIUM

Unit 10: Acids and Bases

Chapter 14 Properties of Acids and Bases

Chapter 8 Acid-Base Equilibria

Chem 40S Notes: Indicators What makes an acid/base strong?

Chem 40S Notes: Indicators What makes an acid/base strong?

Properties of Acids. Base Chemistry. Properties of Bases. Three Acid and Base Theories. 1) Arrhenius Theory. May 09, Naming Acids Review

1 Chapter 19 Acids, Bases, and Salts

Chapter Menu Chapter Menu

( 1 ) Concept of acid / base

CHEMISTRY - BROWN 13E CH.16 - ACID-BASE EQUILIBRIA - PART 2.

H 2 O (l) H + (aq) + OH (aq)

Chem12 Acids : Exam Questions M.C.-100

Chemical Equilibrium. Many reactions are, i.e. they can occur in either direction. A + B AB or AB A + B

CHEMISTRY. Chapter 16 Acid-Base Equilibria

Chemistry: The Central Science. Chapter 16: Acid-Base Equilibria. 16.1: Acids and Bases: A Brief Review

EXPERIMENT 11 Acids, Bases, and ph

Experiment 5 Titration of Acids and Bases

Chapter 15. Properties of Acids. Structure of Acids 7/3/08. Acid and Bases

Acid-Base Equilibria. 1.NH 4 Cl 2.NaCl 3.KC 2 H 3 O 2 4.NaNO 2. Solutions of a Weak Acid or Base

Transcription:

Chemistry 132 NT It is the mark of an instructed mind to rest satisfied with the degree of precision that the nature of a subject permits, and not to seek exactness where only an approximation of the truth is possible. Aristotle 1 Chem 132 NT Acids and Bases Module 3 SelfIonization of Water and ph SelfIonization of Water The ph of a Solution Acidbase indicator dye. 2 3 1

Review Conjugate acidbase pairs Acidic strength related to molecular structure 4 Selfionization of Water Selfionization is a reaction in which two like molecules react to give ions. In the case of water, the following equilibrium is established. O(l) H O(l) H O (aq) OH (aq) H2 2 3 The equilibriumconstant expression for this system is: [H3O [OH Kc = 2 [H2O 5 Selfionization of Water Selfionization is a reaction in which two like molecules react to give ions. The concentration of ions is extremely small, consequently the concentration of H 2 O remains essentially constant. This gives: 2 [ H2O Kc = [H3O [OH constant 6 2

Selfionization of Water Selfionization is a reaction in which two like molecules react to give ions. We call the equilibrium value for the ion product [H 3 O [OH the ionproduct constant for water which is written K w. Kw 3 = [H O [OH At 25 o C, the value of K w is 1.0 x 14. Like any equilibrium constant, K w varies with temperature. 7 Selfionization of Water Selfionization is a reaction in which two like molecules react to give ions. Because we often write H 3 O as H, the ionproduct constant expression for water can be written: K w = [H [OH Using K w you can calculate the concentrations of H and OH ions in pure water. 8 Selfionization of Water These ions are produced in equal numbers in pure water, so if we let x = [H = [OH 1.0 14 = (x)(x) at 25 o C x = 1.0 14 = 1.0 7 Thus, the concentrations of H and OH in pure water are both 1.0 x 7 M. If you add acid or base to water they are no longer equal but the K w expression still holds. 9 3

In a solution of a strong acid you can normally ignore the selfionization of water as a source of H (aq). The H (aq) concentration is usually determined by the strong acid concentration. However, the selfionization still exists and is responsible for a small concentration of OH ion. As an example, calculate the concentration of OH ion in 0. M HCl. Because you started with 0. M HCl (a strong acid) the reaction will produce 0. M H (aq) HCl (aq ) fi H (aq ) Cl (aq ) Substituting [H =0. into the ionproduct expression, we get: 1.0 = (0.)[OH 14 11 As an example, calculate the concentration of OH ion in 0. M HCl. Because you started with 0. M HCl (a strong acid) the reaction will produce 0. M H (aq) HCl (aq ) fi H (aq ) Cl (aq ) Substituting [H =0. into the ionproduct expression, we get: 14 1 13 [OH = 0. = 1 M Very very small 12 4

Similarly, in a solution of a strong base you can normally ignore the selfionization of water as a source of OH (aq). The OH (aq) concentration is usually determined by the strong base concentration. However, the selfionization still exists and is responsible for a small concentration of H ion. 13 As an example, calculate the concentration of H ion in 0.0 M NaOH. Because you started with 0.0 M NaOH (a strong base) the reaction will produce 0.0 M OH (aq) NaOH (s) H 2 O fi Na (aq ) OH (aq ) Substituting [OH =0.0 into the ionproduct expression, we get: 1.0 = [H 14 (0.0) 14 As an example, calculate the concentration of H ion in 0.0 M NaOH. Because you started with 0.0 M NaOH (a strong base) the reaction will produce 0.0 M OH (aq) NaOH (s) H 2 O fi Na (aq ) OH (aq ) Substituting [OH =0.0 into the ionproduct expression, we get: 14 1 12 [H = = 1 0.0 M Very very small 15 5

By dissolving substances in water, you can alter the concentrations of H (aq) and OH (aq). In a neutral solution, the concentrations of H (aq) and OH (aq) are equal, as they are in pure water. In an acidic solution, the concentration of H (aq) is far greater than that of OH (aq). In a basic solution, the concentration of OH (aq) is far greater than that of H (aq). 16 At 25 o C, you observe the following conditions. In an acidic solution, [H > 1.0 x 7 M. In a neutral solution, [H = 1.0 x 7 M. In a basic solution, [H < 1.0 x 7 M. 17 The ph of a Solution Although you can quantitatively describe the acidity of a solution by its [H, it is often more convenient to give acidity in terms of ph. The ph of a solution is defined as the negative logarithm of the molar hydrogenion concentration. ph = log[h 18 6

The ph of a Solution For a solution in which the hydrogenion concentration is 1.0 x 3, the ph is: ph = log(1.0 3 ) = 3.00 Note that the number of decimal places in the ph equals the number of significant figures in the hydrogenion concentration. 19 The ph of a Solution In a neutral solution, whose hydrogenion concentration is 1.0 x 7, the ph = 7.00. For acidic solutions, the hydrogenion concentration is greater than 1.0 x 7, so the ph is less than 7.00. Similarly, a basic solution has a ph greater than 7.00. The next slide shows a diagram of the ph scale and the ph values of some common solutions. 20 The ph Scale 7

A Problem To Consider A sample of orange juice has a hydrogenion concentration of 2.9 x 4 M. What is the ph? ph = log[h ph = log(2.9 ph = 3.54 4 ) 22 A Problem To Consider The ph of human arterial blood is 7.40. What is the hydrogenion concentration? [ H = anti log( ph ) [ H = anti log( 7.40) [H = 7.40 8 = 4.0 M 23 The ph of a Solution A measurement of the hydroxide ion concentration, similar to ph, is the poh. The poh of a solution is defined as the negative logarithm of the molar hydroxideion concentration. poh = log[oh 24 8

The ph of a Solution A measurement of the hydroxide ion concentration, similar to ph, is the poh. Then because K w = [H [OH = 1.0 x 14 at 25 o C, you can show that ph poh = 14.00 25 A Problem To Consider An ammonia solution of has a hydroxideion concentration of 1.9 x 3 M. What is the ph of the solution? You first calculate the poh poh = log(1.9 Then the ph is: 3 ) = 2.72 ph = 14.00 2.72 = 11.28 26 The ph of a Solution The ph of a solution can accurately be measured using a ph meter 27 9

The ph of a Solution Although less precise, acid base indicators are often used to measure ph because they usually change color with in a narrow ph range. The next slide shows the color changes of various acidbase indicators. 28 29 Operational Skills Identifying acid and base species Identifying Lewis acid and base species Deciding whether reactants or products are favored in an acidbase reaction Calculating the concentration of H and OH in solutions of strong acid or base Calculating the ph from the hydrogenion concentration, or vice versa. 30

Key Equations K w = [H 3 O [OH = 1 x 14 at 25 o C ph = log[h 3 O ph poh = 14.00 Time for a few review questions. 31 32 11