Double Layer Potentials on Polygons and Pseudodifferential Operators on Lie Groupoids

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Double Layer Potentials on Polygons and Pseudodifferential Operators on Lie Groupoids joint work with Hengguang Li Yu Qiao School of Mathematics and Information Science Shaanxi Normal University Xi an, China International Workshop The Neumann-Poincare Operator, Plasmonics, and Field Concentrations Feb.10 2018 1 / 20

Outline Motivation Example C -algebras Review of Double Layer Potential Method Double Layer Potentials on Plane Sectors Pseudodifferential Operators on Lie Groupoids Double Layer Potentials on Polygons 2 / 20

Motivation Example Let Ω R n be a bounded, open set with boundary Ω := Ω \Ω. Let us consider on Ω the simplest boundary value problems, the Poisson problem { u = f u Ω = g. A well-known, classical result is the following regularity theorem : Theorem If Ω is smooth, then (u) = ( u, u Ω ) defines an isomorphism for m > 3 2. : H m+2 (Ω) H m (Ω) H m+ 3 2 ( Ω), Note: it follows that if f, g, and Ω are smooth, then u is also smooth (including the boundary). 3 / 20

Motivation Example The above theorem is NOT true if Ω is not smooth. Let Ω = (0, 1) 2 and g = 0 on the boundary, and assume that u is smooth. Then we have 2 x u(0, 0) = 0 = 2 y u(0, 0). Therefore, f (0, 0) = u(0, 0) = 0. Remark No solution on (0, 1) 2 is smooth if g = 0 and f (0, 0) 0. Conclusion: The nonsmoothness of the domain causes the problem. 4 / 20

C -algebras Let H be a (separable) Hilbert space, L(H) the collection of all bounded linear operators H H. L(H) is equipped with an involution, where the adjoint T of T L(H) is defined by T x, y = x, Ty. Moreover, L(H) is equipped with a norm which satisfies TT = T 2. Definition T = sup{ T(x) : x 1}, A C -algebra of operators on H is a norm-closed subalgebra A of L(H) such that T A T A. Example Let X be a locally compact space. The algebra C 0 (X) of continuous functions vanishing at infinity is a C -algebra. 5 / 20

Review of Layer Potential Method Let Ω R n be an open bounded domain and consider the Dirichlet problem { u = 0 in Ω u = ϕ, on Ω where denotes Laplace operator. The fundamental solution of Laplace s equation is given by { cn x N(x) = 2 n n 3 c 2 log x n = 2, where c n is a constant depending only on n. 6 / 20

Review of Layer Potential Method Denote N(x, y) = N(x y). Let ψ be a function on Ω. (ψ could be in L 2 ( Ω), C( Ω),.) The double layer potential (with moment ψ) is defined by (Dψ)(x) = k(x, y)ψ(y)dσ(y), Ω (x R n \ Ω) where k(x, y) = νy N(x, y) = c n(x y) ν(y) x y n, and ν(y) is the unit outer normal vector to Ω at y. Fact: the function Dψ is harmonic. 7 / 20

Review of Layer Potential Method Given a function u on R n \ Ω, for x Ω, let u + (x) and u (x) denote the limits of u(y) as y x (nontanentially) from y Ω and y R n \Ω, respectively. The classical results on double layer potentials give Proposition For (a.e.) x Ω, we have (Dψ) + (x) = ψ(x) + Kψ, (Dψ) (x) = ψ(x) + Kψ, where Kψ(x) = k(x, y)ψ(y)dσ(y). Ω The operator K is called the double layer potential operator. 8 / 20

Review of Layer Potential Method We can try to solve the Dirichlet problem in terms of double layer potential u(x) = (Dψ)(x), x Ω, and relate ψ to ϕ. Letting x z Ω yields ϕ(z) = u(z) = (I + K)ψ(z), z Ω. Hence, the (interior) Dirichlet problem is reduced to ϕ = (I + K)ψ. Remark The (exterior) Dirichlet problem is reduced to ϕ = ( I + K)ψ. 9 / 20

Review of Layer Potential Method If Ω has smooth boundary, then K is a pseudodifferential operator of order 1 on Ω, i.e., K Ψ 1 ( Ω). (Taylor s book.) If the boundary of Ω is C 2, then K is compact on L 2 ( Ω). (Folland s book.) If the boundary of Ω is C 1, then K is compact on L p ( Ω). (Fabes, Jodeit, and Riviere. Acta Math. 1978.) If Ω is a SKT domain, then K is compact. (Hofmann, Mitrea, and Taylor. 2010) If Ω is a Lipschitz domain, in general, K is not compact. However, is invertible. (Greg Verchota, 1984) Question: I + K : L 2 ( Ω) L 2 ( Ω), If a domain has singularities (polygon, polyhedra, curvilinear domains,...), can we construct a (natural) pseudodifferential operator algebras containing K in an appropriate sense? (in other words, K Ψ 1 (something)? ) 10 / 20

Double Layer Potentials on Plane Sectors Let Ω R 2 be a plane sector with angle θ. So the boundary ( Ω ) consists of two rays. 0 K12 The double layer potential operator K is of the form, where K K 21 0 12 = K 21 = K, and and ( Kf )(t) = 0 k(t/s)f (s) ds s, k(t) = 1 t sin θ π t 2 + 1 2t cos θ. Clearly, the operator K is a Mellin convolution operator on R +. Let M f denote the multiplication operator by f. It is easy to see that M r a KMr a has convolution kernel k a (r) = 1 π r a+1 sin θ r 2 2r cos θ + 1. We need weighted Sobolev spaces on Ω. For all m Z, where the metric g = (r 1 dr) 2. K m 1 2 ( Ω) := H m ( Ω, g), 11 / 20

Layer Potentials on Plane Sectors Proposition The operators ±I + K a := ±I + M r akm r a are invertible on K m 1 2 ( Ω) if and only if 1 ( Ka (τ)) 2 0 for all τ R, where Ka is the Mellin Transform of K a. We define a θ by a θ := min{ π θ, π { π/(2π θ), 0 < θ < π, 2π θ } = π/θ, π < θ < 2π. Theorem If a ( a θ, a θ ), then ±I + M r akm r a is invertible on K m 1 ( Ω), that is, 2 ±I + K : K m ( Ω) K m ( Ω) 1 2 +a 1 2 +a are invertible. 12 / 20

Pseudodifferental Operators on Lie Groupoids Definition A groupoid is a small category G in which each arrow is invertible. A groupoid G consists of two sets, a set of objects (or units) G 0 and a set of arrows G 1. Usually we shall denote the space of units of G by M and we shall identify G with G 1. Each object of G can be identified with an arrow of G, in that we have an injective map u : M = G 0 G 1, where u(x) is the identity arrow of an object x. To each arrow g G we associate two units: its domain d(g) and its range r(g). The multiplication µ(g, h) = gh of two arrows g, h G is not always defined; it is defined exactly when d(g) = r(h). The multiplication is associative. The inverse of an arrow is denoted by g 1 = ι(g). We can write G 1 G0 G 1 µ ι d G 1 u G 1 G 0 G 1 r (where G 1 G0 G 1 G 1 G 1 is the set of composable arrows). 13 / 20

Pseudodifferental Operators on Lie Groupoids Definition A Lie groupoid is a groupoid G = (G 0, G 1, d, r, µ, u, ι) such that M := G 0 and G 1 are smooth manifolds, possibly with corners, with M Hausdorff, the structural maps d, r, µ, u, and ι are smooth and the domain map d is a submersion (of manifolds with corners). Example (Pair groupoid) Let M be a smooth manifold (with or without corners). Let G = M M and G 0 = M, with structure maps d(m 1, m 2 ) = m 2, r(m 1, m 2 ) = m 1, (m 1, m 2 )(m 2, m 3 ) = (m 1, m 3 ), u(m) = (m, m), and ι(m 1, m 2 ) = (m 2, m 1 ). Example (Action groupoid) Suppose that a Lie group G acts on the smooth manifold M from the right. The transformation groupoid over M {e} M, denoted by M G, is the set M G with structure maps d(m, g) = (m g, e), r(m, g) = (m, e), (m, g)(m g, h) = (m, gh), u(m, e) = (m, e), and ι(m, g) = (m g, g 1 ). 14 / 20

Pseudodifferental Operators on Lie Groupoids Definition The space Ψ m (G) of pseudodifferential operators of order m on a Lie groupoid G with units M consists of smooth families of pseudodifferential operators P = (P x ), x M, with P x Ψ m (G x ), which are uniformly supported and right invariant. For each x M, there is an interesting representation of Ψ (G), the regular representation π x on C c (G x ), defined by π x (P) = P x. The reduced C norm of P is defined by P r = sup x M and the full norm of P is defined by π x (P) = sup P x, x M P = sup ρ(p), ρ where ρ varies over all bounded representations of Ψ 0 (G) satisfying Definition ρ(p) P L 1 for all P Ψ (G). Let G be a Lie groupoid and Ψ (G) be as above. We define C (G) (respectively, C r(g)) to be the completion of Ψ (G) in the norm (respectively, r ). If r =, that is, if C (G) C r(g), we call G amenable. 15 / 20

Pseudodifferental Operators on Lie Groupoids For the case that the domain is a plane sector, let H = [0, ] R +, where R + = (0, ) considered as a commutative group, and the action is just the multiplication. So H is an action groupoid. It is easy to see that C ( H) = C([0, ]) R +. Proposition 1 Let a ( 1, 1). We have M r akm r a C ( H) M 2 (C); 2 For all k, l Z and a ( a θ, a θ ), the following mapping property holds: M r akm r a : K k ( Ω) K l ( Ω). 1 2 +a 1 2 +a 16 / 20

Layer Potentials on Polygons We still use Ω to denote a simply connected polygon. Idea: Using a desingularization procedure, we construct a (natural) Lie groupoid G for Ω (gluing some Lie groupoids), and the double layer potential operator K (associated to Ω and the Laplace operator) can be identified with a pseudodifferential operator on G. We still use K to denote the double layer potential operator associated to Ω and the Laplace operator. Let r Ω be the smoothed distance to vertices of Ω and M f be the multiplication operator by f. Proposition If a ( 1/2, 1/2), then M r a Ω K M r a Ω C (G). 17 / 20

Layer Potentials on Polygons The following theorem is often used to prove certain operators are Fredholm. Recall that π denotes the vector representation of Ψ (G). Theorem (Nistor and Lauter) Suppose that P = (P m ), m M, is a pseudodifferential operator on G or in C (G). Then π(p) is Fredholm P elliptic + P m invertible for all m M. Recall that we have the following identification on Ω. For all m Z, where the metric g = (r 1 Ω dr Ω) 2. K m 1 2 ( Ω) := H m ( Ω, g), 18 / 20

Layer Potentials on Polygons Let θ 0 := min{ π θ 1, π, π 2π θ 1 θ 2, π 2π θ 2,, π θ n, π 2π θ n }. It is clear that 1 < θ 2 0 < 1. Proposition Let Ω be a polygon on R 2, and K be the double layer potential operator associated to Ω and the Laplace operator. Then for a ( θ 0, 1/2), the operators are both Fredholm. ±I + K : K m 1 2 +a ( Ω) K m 1 2 +a ( Ω) Our mail result is as follows: Theorem (YQ and H. Li, 2017) With the same notations as above, the operators ±I + K : K m ( Ω) K m ( Ω) 1 2 +a 1 2 +a are both isomorphisms for all a ( θ 0, 1/2). 19 / 20

Thanks for your attention! 20 / 20