Three hour lab. Chem : Sept Experiment 2 Session 2. Preparation Pre-lab prep and reading for E2, Parts 3-5

Similar documents
Three hour lab. Chem : Feb Experiment 2 Session 2. Experiment 2 Session 2 Electrons and Solution Color

Three hours of lab Complete E1 (Parts 1, 2, 3, 4, and 5B) Prepare discussion presentation Prepare team report. Course theme

Course theme. Three hours of lab Complete E1 (Parts 1, 2, 3, 4, and 5B) Prepare discussion presentation Prepare team report.

ORBITAL DIAGRAM - A graphical representation of the quantum number "map" of electrons around an atom.

Experiment Three. Lab two: Parts 2B and 3. Halogens used in Parts 2 and 3. Lab one: Parts 1 and 2A. Halogens (Family VIIA) used in Parts 2 and 3

Halogens HALOGENS. Parts 2A and 2B. Chem : Feb. 19, 20 and March 3. Compare the properties and reactivity of the halogens and halides

ORBITAL DIAGRAM - A graphical representation of the quantum number "map" of electrons around an atom.

CHEMICAL COMPOUNDS MOLECULAR COMPOUNDS

CHEMICAL COMPOUNDS MOLECULAR COMPOUNDS

E5 Lewis Acids and Bases: lab 2. Session two lab Parts 2B, 3, and 4. Session one lab Parts 1and 2A. Aquo Complex Ions

E5 Lewis Acids and Bases. Acids. Acids. Session one. Session two Lab: Parts 2B, 3 and 4

-"l" also contributes ENERGY. Higher values for "l" mean the electron has higher energy.

E5 Lewis Acids and Bases: lab 2. Session two lab Parts 2B, 3, and 4. Session one lab Parts 1and 2A. Aquo Complex Ions. Aquo Complex Ion Reactions

VIIIA H PREDICTING CHARGE

- Atomic line spectra are UNIQUE to each element. They're like atomic "fingerprints".

-"l" also contributes ENERGY. Higher values for "l" mean the electron has higher energy.

CHEMICAL COMPOUNDS MOLECULAR COMPOUNDS

Acids. Lewis Acids and Bases. Lewis Acids. Lewis acids: H + Cu 2+ Al 3+ E5 Lewis Acids and Bases (Session 1) March 19-24

WRITING AN IONIC FORMULA

Example: If a simple ionic compound is made of these two ions, what is its formula? In the final formula, don't write the charges on the ions!

Solutions and Ions. Pure Substances

How many grams of sodium metal is required to completely react with 2545 grams of chlorine gas?

Atomic weight: This is a decimal number, but for radioactive elements it is replaced with a number in parenthesis.

VIIIA H PREDICTING CHARGE

How many grams of sodium metal is required to completely react with 2545 grams of chlorine gas?

WRITING AN IONIC FORMULA

EXAMPLES. He VIA VIIA Li Be B C N O F Ne

Bronsted: Acids are proton donors. Session one Pre-lab (p.151) due 1st hour discussion of E4 Lab (Parts 1and 2A)

Periodic Table. - Mendeleev was able to predict the properties of previously unknown elements using his "periodic law" Modern periodic table

Atomic weight: This is a decimal number, but for radioactive elements it is replaced with a number in parenthesis.

CHEM 10113, Quiz 5 October 26, 2011

(please print) (1) (18) H IIA IIIA IVA VA VIA VIIA He (2) (13) (14) (15) (16) (17)

Example: Helium has an atomic number of 2. Every helium atom has two protons in its nucleus.

Periodic Table. Modern periodic table

WRITING AN IONIC FORMULA

- Light has properties of WAVES such as DIFFRACTION (it bends around small obstructions).

CHEMICAL COMPOUNDS. - Dalton's theory does not mention this, but there is more than one way for atoms to come together to make chemical compounds!

Lewis dot structures for molecules

- A CHEMICAL BOND is a strong attractive force between the atoms in a compound. attractive forces between oppositely charged ions

Periodic Table. Modern periodic table

E4 Acids, Bases, and Salts

Atomic terms. Example: Helium has an atomic number of 2. Every helium atom has two protons in its nucleus.

IONIC COMPOUNDS. - USUALLY form from metals combining with nonmetals, or from metals combining with metalloids

CHEMICAL COMPOUNDS MOLECULAR COMPOUNDS

... but using electron configurations to describe how aluminum bromide forms is a bit cumbersome! Can we simplify the picture a bit?

Putting it together... - In the early 20th century, there was a debate on the structure of the atom. Thin gold foil

Circle the letters only. NO ANSWERS in the Columns!

4.06 Periodic Table and Periodic Trends

NUCLEAR MODEL. Electron cloud. Electron cloud. Nucleus. Nucleus

- Why are phase labels required? Because phase changes either absorb or release energy. ... what does this mean?

Circle the letters only. NO ANSWERS in the Columns! (3 points each)

(FIRST) IONIZATION ENERGY

Atomic structure. The subatomic particles. - a small, but relatively massive particle that carres an overall unit POSITIVE CHARGE

ph = - log [H3O+] Example: ph 7 = - log [ 1 x 10-7] [H3O+] = mole/liter units ph values are unitless

E4 Acids, Bases, and Salts

1.02 Elements, Symbols and Periodic Table

Partial Periodic Table of the Elements

- Some properties of elements can be related to their positions on the periodic table.

- A CHEMICAL BOND is a strong attractive force between the atoms in a compound. attractive forces between oppositely charged ions

- Dalton's theory sets LIMITS on what can be done with chemistry. For example:

The exam must be written in ink. No calculators of any sort allowed. You have 2 hours to complete the exam. Periodic table 7 0

7. Relax and do well.

8. Relax and do well.

VIIIA He IIA IIIA IVA VA VIA VIIA. Li Be B C N O F Ne. Na Mg VIB VIIB VIIIB IB IIB S. K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br

- When atoms share electrons, the electrons might not be EVENLY shared. Shared electrons may spend more time around one atomic nucleus than the other.

8. Relax and do well.

4.01 Elements, Symbols and Periodic Table

610B Final Exam Cover Page

E4 Acids, Bases, and Salts

CLEARLY SHOW ALL WORK AND REASONING.

HANDOUT SET GENERAL CHEMISTRY I

Placeholder zeros, even though they aren't SIGNIFICANT, still need to be included, so we know how big the number is!

HANDOUT SET GENERAL CHEMISTRY II

INSTRUCTIONS: Exam III. November 10, 1999 Lab Section

8. Relax and do well.

CHEM 10123/10125, Exam 2

- Some properties of elements can be related to their positions on the periodic table.

K. 27 Co. 28 Ni. 29 Cu Rb. 46 Pd. 45 Rh. 47 Ag Cs Ir. 78 Pt.

8. Relax and do well.

Atomic Emission Spectra. and. Flame Tests. Burlingame High School Chemistry

SHAPES OF EXPANDED VALENCE MOLECULES

INSTRUCTIONS: CHEM Exam I. September 13, 1994 Lab Section

8. Relax and do well.

- Some properties of elements can be related to their positions on the periodic table.

- Some properties of elements can be related to their positions on the periodic table.

8. Relax and do well.

Microsoft Excel Directions

CHM 101 PRACTICE TEST 1 Page 1 of 4

- A polar molecule has an uneven distribution of electron density, making it have ends (poles) that are slightly charged.

Chapter 12 The Atom & Periodic Table- part 2

Chemistry 121 FINAL EXAM

8. Relax and do well.

K. 27 Co. 28 Ni. 29 Cu Rb. 46 Pd. 45 Rh. 47 Ag Cs Ir. 78 Pt.

Formulas and Constants (you may remove this page)

7. Relax and do well.

EXAMPLES. He VIA VIIA Li Be B C N O F Ne

7. Relax and do well.

7. Relax and do well.

The Periodic Table of the Elements

CHEM Come to the PASS workshop with your mock exam complete. During the workshop you can work with other students to review your work.

Transcription:

Chem.25-26: Sept.24-3 Experiment 2 Session 2 Preparation Pre-lab prep and reading for E2, Parts 3-5 Experiment 2 Session 2 Electrons and Solution Color Three hour lab Complete E2 (Parts - 5) Prepare discussion presentation Prepare team report. Give team report to GSI at the end of lab or turn in by grace deadline to GSI s atrium level mailbox. Background Information: Energy and electrons Electrons will move from a lower to an available higher energy level if the provided energy = exactly that needed for a possible energy level transition If electrons move from a higher to a lower energy level, the difference in energy will be released. DEMO

Visible Light and Energy Light is a form of energy λ 4 Violet - Blue - Green - Yellow - Orange - Red λ 8 The shorter the wavelength (λ), the greater is its energy The shorter the wavelength (λ), the higher is its frequency Wavelength and Energy The shorter the wavelength, the greater its energy DEMO. Expose a balloon containing H 2 and Cl 2 to red light ( λ 65). 2. Expose a balloon containing H 2 and Cl 2 to blue light ( λ 45). Balloon containing H 2 and Cl 2 Light source Part 3. Solution Color and Light Interaction Plot an absorption spectrum for each team assigned salt solution Determine if salt solution color is predictable based on the cations interaction with visible light versus: - placement of the cation s element in the periodic table? - the cation s electron configuration? - the cation s ionic radius? 2

A H s IIA IIIA IVA VA VIA VIIA 3 Li 2s Na 3s 9 K 4s Pre-transition. 37 Rb 5s 55 Cs 6s 87 Fr 7s 4 Be 2s 2 2 Mg 3s2 IIIB IVB VB VIB VIIB VIIIB VIIIB IB IIB 2 Ca 4s 2 38 Sr 5s 2 56 Ba 6s 2 88 Ra 7s 2 2 22 23 24 25 26 27 28 Sc Ti V Cr Mn Fe Co Ni 3d 4s 2 3d 2 4s 2 3d 3 4s 2 3d 5 4s 3d 5 4s 2 3d 6 4s 2 3d 7 4s 2 3d 8 4s 2 39 4 4 42 43 44 45 46 Y Zr Nb Mo Tc Ru Rh Pd 4d 5s 2 4d 2 5s 2 4d 3 5s 2 4d 5 5s 4d 5 5s 2 4d 7 5s 4d 8 5s 4d 57 La* 5d 6s 2 Color versus Periodic Table Position Compare the color data of salt solutions containing cations from transition and pre and post transition families Transition Post-transition VIIIA 2 He s 2 5 6 7 8 9 B C N O F Ne 2s 2 2p 2s 2 2p 2 2s 2 2p 3 2s 2 2p 4 2s 2 2p 5 2s 2 2p 6 3 4 5 6 7 8 Al Si P S Cl Ar 3s 2 3p 3s 2 3p 2 3s 2 3p 3 3s 2 3p 4 3s 2 3p 5 3s 2 3p 6 29 Cu 3d 4s 3 Zn 3d 4s 2 3 Ga 32 Ge 33 As 34 Se 35 Br 36 Kr 4s 4p 4s 4p 2 4s 4p 3 4s 4p 4 4s 4p 5 4s 4p 6 47 Ag 4d 5s 48 Cd 4d 5s 2 49 In 5 Sn 5 Sb 52 Te 53 I 54 Xe 5s 5p 5s 5p 2 5s 5p 3 5s 5p 4 5s 2 5p 5 5s 5p 6 72 Hf 73 Ta 74 W 75 Re 76 Os 77 Ir 78 Pt 79 Au 8 Hg 8 Tl 82 Pb 83 Bi 84 Po 85 At 86 Rn 5d 2 6s 2 5d 3 6s 2 5d 4 6s 2 5d 5 6s 2 5d 6 6s 2 5d 7 6s 2 5d 9 6s 6s 2 6p 6s 2 6p 2 6s 2 6p 3 6s 2 6p 4 6s 2 6p 5 6s 2 6p 6 5d 6s 5d 6s 2 89 4 5 6 7 8 9 + Element synthesized, Ac # + + + + + + but no official name assigned 6d 7s 2 6d 2 7s 2 6d 3 7s 2 6d 4 7s 2 6d 5 7s 2 6d 6 7s 2 6d 7 7s 2 Beer-Lambert Law A λ = ε c l at λ = absorptivity factor concentration path length Concentration and path length are held constant while taking the sample s absorption spectrum (Part 3) Recording a spectrum Calibrate ( absorbance and % transmission) the spectrophotomer with the blank every time you change the λ before taking the absorbance of your sample Use the same sample and holder (cuvette) so that sample concentration and path length are constant 3

Absorption Spectrum (Part 3) Record the solution color and the wavelength and color of the wavelengths of absorption and transmission max Absorption λmax Transmission λmax Light vs. Transmission ABSORBANCE = -LOG TRANSMITTANCE Abs = % light transmitted Abs = % light transmitted reading values = to. for minimal error vs. Transmission Spectrum The identity of a solution can be determined from its absorption (or transmission) spectrum. 4

Solution Color and Light Interaction Q. What wavelength colors will a solution of NiSO 4 transmit? DEMO Spectrum of. M differences across wavelengths are due to?. Differences in the absorptivity coefficient ( ε ) 2. Differences in the concentration of the sample. 3. Differences in the path length of the sample holder. 4. All the above. Violet Blue Green Yellow Orange Red.7.6.5.3.2. 4 45 5 55 6 65 7 Wavelength λ (nm) Which statement below is correct?. Color of Abs λ max = blue-purple. 2. The sample is green. 3. ε is greater at λ 5 than at λ 4. 5

Beer-Lambert Law and Path Length Path length and light absorbance are directly proportional at a fixed wavelength and concentration. DEMO Different spectrophotometers have different path lengths! Don t change spectrophotometers in the middle of an analysis (Parts 4 and 5)! Path Length and Absorption Spectra Fig. Absorption spectra at different sample path lengths Path length changes will result in a proportional change in absorbance values if sample concentration is constant. readings will alter proportionately across all wavelengths; the spectrum pattern will not alter. Concentration and Absorption Spectra Fig. Absorption spectra at different sample concentrations Sample concentration changes will result in a proportional change in absorbance values if path length is constant. readings will alter proportionately across all wavelengths; the spectrum pattern will not alter. 6

Part 4. Concentration and Light Plot a calibration curve for your team assigned sample - Write a mathematical expression to express the pattern between the concentrations and the absorbance values of your team assigned sample Successfully use the calibration curve to determine the unknown concentration of your team assigned sample (Part 5) Beer-Lambert Law A λ = ε c l at λ = absorptivity factor concentration path length Wavelength and path length are held constant when producing a calibration curve (Part 4) Beer-Lambert Law and Concentration.2.8.6.2 2 3 4 5 6 7 8 Concentration (mm) is proportional to concentration at a constant wavelength (λ )and constant path length DEMO 7

and Path Length readings for a calibration curve will alter if the path length is altered 2.5 2..5..5....2.3.5 [Plastocyanin], mm = /2path length and Path Length Path length must be fixed for a calibration curve or absorbance readings will be in error. Q. How do you hold the path length constant? Answer: Preparation of Calibration Curve Prepare a set of solutions of known and accurate concentration by diluting the team prepared and assigned. M solution M V = M 2 V 2 8

Preparation of Calibration Curve Refer to the samples absorption spectrum to choose a wavelength for the calibration curve The wavelength of max absorbance is typically chosen. Why?. Calibration Curve Wavelength.2 2.5.8. 25 35 45 55 65 75....2.3.5 Wavelength (nm) [Plastocyanin], mm Spectrum of.6 mm Plastocyanin 2..5..5 Calibration curve at 6nm Q. Will the slope of the linear line of a calibration curve produced at 55 nm be greater or less than the slope of the line of the above calibration curve produced at 6 nm? Wavelength of Calibration Graph?.2 Purple Blue Green Yellow Orange Red.8 Absorption.8.6.2 Absorption.7.6.5.3.2. 4 45 5 55 6 65 7 λ (nm)..2.3.5 [M + ] (Molar) Q. A M solution of M + has the absorption spectrum on the left. Circle the wavelength of its calibration graph: 425 5 55 6 65 9

Preparation of Calibration Curve Calculate the slope of the linear line of your calibration curve.2.8.6.2 2 3 4 5 6 7 8 Concentration (mm) Calibration Curve Slope Q. What does the slope of the calibration curve represent in the Beer-Lambert expression A λ = εlc? Answer:.2.8.6.2 2 3 4 5 6 7 8 Concentration (mm) Unknown concentration determination Q. A sample of unknown concentration of XY(aq) has Abs >.2 at a λ of 6nm, What is its concentration (mm)?.2.8.6.2 2 3 4 5 6 7 8 Concentration (mm) Slope =.5Abs/mM Fig. Calibration Curve of XY(aq) at 6 nm

Beer-Lambert and Calibration Curve Determine the concentration of a diluted sample of the unknown if the unknown s absorbance reads above an Abs = or outside the linear line of the calibration curve Fig. Calibration Curve Deviation The Beer-Lambert law only applies at low concentrations! Do NOT extrapolate the linear line of a calibration curve! Unknown concentration determination Eyeball the graph ONLY for an approximate concentration..2.8.6.2 2 3 4 5 6 7 8 Concentration (mm) Use the slope and Beer-Lambert law to determine an exact concentration What is the unknown concentration? The diluted sample has an absorbance at λ of 6nm =.57..2.8.6.2 2 3 4 5 6 7 8 Concentration (mm) Fig. Calibration Curve of XY(aq) at 6 nm Abs λ6 = elc = c Slope =.5Abs/mM

What is the unknown concentration? Q. A diluted sample of unknown concentration = 3.8 mm. You prepared the diluted sample by adding 6. ml of water to 2. ml of the sample of unknown concentration. What is the unknown concentration (mm)? a) 3.8 mm b) 7.2 mm c).4 mm d) 5.2 mm Questions? Contact nkerner@umich.edu 2