Math 155 Prerequisite Review Handout

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Math 155 Prerequisite Review Handout August 23, 2010 Contents 1 Basic Mathematical Operations 2 1.1 Examples...................................... 2 1.2 Exercises....................................... 3 2 Variables, Parameters, and Functions 4 2.1 Examples...................................... 4 2.2 Exercises....................................... 5 3 Manipulating Expressions that Contain Variables 6 3.1 The Distributive Property and Division...................... 6 3.2 A More Complicated Distribution Problem.................... 7 3.3 Factoring...................................... 8 3.4 Exercises....................................... 9 4 Review Problems 11 1

1 Basic Mathematical Operations Recall the basic operations of addition, substraction, multiplication, and division. Consider evaluating the following expression: 2 + 3 5 Do we add 2 and 3 first or do we multiply 3 and 5? Depending on which we do first we get different answers, 25 and 17 respectively. It is for this reason that we have the order of operations, recall that the basic mathematical operations are performed in the following order: 1. Parentheses - first perform operations that are in parentheses 2. Exponents 3. Multiplication and Division 4. Addition and Subtraction If an expression contains two operations of the same rank then the operations are performed from left to right. For example 20 5 3 = 4 3 = 12 Try performing the multiplication operation first, do you get the same answer? The order of operations described above can be easily remembered with the abbreviation PEMDAS, which you can remember by the simple phrase, Please Excuse My Dear Aunt Sally. We finish this section with the following examples: 1.1 Examples Example 1. We simplify the following expression: 4 (2 + 5) 2 10 = 4 (7) 2 10 = 4 49 10 = 196 10 = 186 (1)

Example 2. How do we simplify the following: 4 + 5 + 4 5 3 The fraction bar is treated as if everything in the numerator (top) and denominator (bottom) of the fraction is in parentheses so, 4 + 5 3 + 4 5 = Thus we simplify the expression as follows: 1.2 Exercises 4 + 5 3 (4 + 5) (3) + 4 5 = 9 3 + 4 5 = 3 + 4 5 = 3 + 20 = 23 Directions: Simplify the following expressions. 1. 4 + 6 11 18 + 4 5 (2) 2. (4 + 6) (11 18) 3. (10 9) 3 5 (7 + 4) 4. 10 + 4 7 + 5 10 5. 10 10 + 6 3 + 1 + 2

2 Variables, Parameters, and Functions This section is based on Adler 1.2 Definition 3. 1. A variable is a symbol that represents a value in an algebraic expression, this value can change within the situation or experiment. 2. A parameter is a symbol that represents a value that is fixed for a given situation or experiment. 3. The number (or parameter) that is multiplied by a variable is called the coefficient. 4. A function is a mathematical object that takes an input and associates it to a unique output. 5. The input to a function is called the independent variable and the set of all inputs a function can accept is called the domain. 6. The output of a function is called the dependent variable and the set of all outputs of a function is called the range. Note: Page 9 of the Adler textbook has a nice diagram that describes the relationship between a functions and its domain and range. You can think of a variable as number that will be added later. So when a variable appears in an expression the same PEMDAS order of operations applies, as well as the associative property, commutative property, and the distributive property. All of these properties should be familiar to you form pervious courses, however, we will review the distributive property in one of the following sections. Recall the Vertical Line Test to verify if a relation is a function, states that if the graph of a relation allows a vertical line to cross the graph at more than one point then the relation fails to be a function. See Adler page 12 for a nice picture of this. We conclude this section with some examples: 2.1 Examples Example 4. 3x 2 + x + 4 In this expression the variable is x and the coefficient on x 2 is 3, the coefficient on x is 1, and the constant term is 4.

Example 5. Based on Example 1.2.4 in Adler. Suppose that you measure a fungus population, f, in 3 petri dishes, each dish having been stored at a different temperatures. For each dish the temperature was held constant, throughout the experiment. To determine the size of the population you measure the area of the petri dish the fungus covered. You found the following results: time, t f when T=20 f when T=30 f when T=40 0.0 1.00 1.00 1.00 1.0 1.16 1.56 1.15 2.0 1.34 1.99 1.30 3.0 1.45 2.64 1.45 4.0 1.56 3.25 1.60 5.0 1.69 4.59 1.75 6.0 1.82 6.24 1.90 So in this experiment t is the independent variable, f is the dependent variable, and T is a parameter representing temperature. Now consider just the data in the last column. You might recognize that it all lies on the same line, in fact the line defined by the following function: f(t) = t 0.15 + 1 Question Can you identify the slope and y-intercept of the line? How large do you think that the fungus will be when t = 7? 2.2 Exercises Directions: Identify the dependent variable, independent variable, and the value of the function at 3 and 9. 1. f(x) = 3.24x + 5.7 2. g(t) = 7.56x 2 + 4.5x + 9.7 3. l(n) = 5.67x 3 + 8.5x + 8.45

3 Manipulating Expressions that Contain Variables Recall the Distributive Property of Multiplication states that For example: Similarly, a(x + y) = ax + ay = (x + y)a 3(4 + 5) = 3 4 + 3 5 = 12 + 15 = 27 3(x + 5) = 3 x + 3 5 = 3x + 15 It is when working with variable that we see the true power of the distributive property. 3.1 The Distributive Property and Division Recall that multiplication and division are related, as inverse operations. So a natural question to as is does the Distributive Property work for division and if so how? We aim to answer that question now. Recall that. For example, x a = 1 a x x 3 = 1 3 x. In this way we can view division as multiplication (by inverses). Using this view point we can apply the Distributive Property in the following way: x + y a = 1 a (x + y) = x a y a

Example 6. Let s try to write the following expression with only one x 2 and x term. Example 7. x 2 + x 4 + x 2 + 2x = x2 4 + x 4 + x2 + 2x = 5x2 4 + 6x 4 8x 2 + 4 4x = 8x2 4x + 4 4x = 2x + x 1 (3) (4) 3.2 A More Complicated Distribution Problem You are likely familiar with the term FOIL for multiplying expressions like: (x + 3)(x + 2) FOIL stands for First, Outer, Inner, Last and helps us to remember how to use distribution to expand expressions such as the one above. This is an important technique that will be utilized frequently in this course, so let s do some examples beginning with the one above: (x + 3)(x + 2) = x 2 + 2x + 3x + 6 = x 2 + (2 + 3)x + 6 = x 2 + 5x + 6 (5) Example 8. (4x + 5)(2x + 1) = 8x 2 + 4x + 10x + 5 = 8x 2 + (4 + 10)x + 5 = 8x 2 + 14x + 5 (6)

Example 9. Recall that we can even multiply expression like (x 2 + 3)(x + 2) = x 3 + 2x 2 + 3x + 6 (7) And expressions like (x 2 + 3x + 2)(x + 2) = x 3 + 2x 2 + 3x 2 + 6x + 2x + 4 = x 3 + 6x 2 + 8x + 4 (8) Here we simply multiplied every term in the first set of parentheses by every term in the last set of parentheses, then we combined like terms. 3.3 Factoring At times it is useful to reverse the process of distributing and/or FOILing. Recall that the reversing of these processes is called factoring. This is an important concept for this class so lets consider the following examples: Example 10. x 2 + 5x + 6 = (x + 2)(x + 3) (9) Example 11. 4x 2 + 16x + 16 = 4(x 2 + 4x + 4) = 4(x + 2)(x + 2) = 4(x + 2) 2 (10) Example 12. We can even factor out variables 2x 3 + 10x 2 + 12x = 2x(x 2 + 5x + 6 = 2x(x + 2)(x + 3) (11) Recall that factoring is very useful when we want to solve for x when a function is set equal to 0 (f(x) = 0). This is also something that we will do a lot in this course so let s look at a quick example:

Example 13. x 2 + 5x + 6 = 0 = (x + 2)(x + 3) = 0 this implies x + 2 = 0 or x + 3 = 0 thus x = 2 or x = 3 (12) Note: Some quadratic equations, that is equations of the form ax 2 + bx + c, do not factor easily (or do not factor in the Real Numbers). If you encounter such a quadratic then use the quadratic formula to solve for the roots. (Recall a root, r, of a function is an input to a function such that f(r) = 0.) We state the quadratic formula here for you reference. The quadratic formula: The solutions of ax 2 + bx + c = 0 are 3.4 Exercises x = b ± b 2 4ac 2a Directions: Write the following expressions with only one x 3, x 2, x, x 1 and constant terms. 1. (x + 6)(x 3) 2. (4x + 3)(8x + 1) 3. (x 2 + 3)(4x + 2) 4. (x 2 + 2x + 5)(x + 2) 5. 4x 2 + 2x 2 + x 2 + 2x

6. 12x 2 + 8x 4 + 5x2 + 10x 5 7. 30x 2 + 15x 15 x + 12x2 + 4x 4 8. x 2 + x 4 + x2 + x 2 9. 4x 2 + 8x 4x + 4x2 + 8x 2 10. 4x 2 + 8 4x Directions: + 4x2 + 8x 2 1. x 2 + 9 + 18 = 0 Solve the following equations for the given independent variable. 2. x 2 2x + 1 = 0 3. (x 2 + 3)(4x + 2) = 0 4. 4x 3 20x 2 56x = 0

4 Review Problems Here are some further review problems that correspond to both this handout and Adler Chapter 1. Instructions The following problems should all be review. Please consider the following problems and review any material that you do not remember. A. Find the equation of the line for the information given (i.e. points, slope, intercepts). 1. (0, 0) and (5, 5) 2. (1, 1) and ( 6, 6) 3. (0, 1) and (4, 5) 4. (1, 2) and (4, 8) 5. slope: 4 and (5, 6) 6. slope: 1 and (4, 8) 2 7. y-intercept: 4 and (3, 3) 8. y-intercept: 5 and slope: 2 9. y-intercept: 1 2 and x-intercept: 1 2 10. x-intercept: 1 2 and slope: 5 2 B. Find the Sum, Product, and Composition of the following functions. Then compute the value of each at x = 2 and x = 5. 1. f(x) = x 2 and g(x) = x 2 + 3 2. p(x) = x 3 and t(x) = x 2 + 5x 3. f(x) = x 2 + x and g(x) = x 2 + 3 4. b(x) = x 2 and d(x) = sin(x) 5. f(x) = ln(x) and g(x) = x 2 + 3 C. Graph the following functions and find the inverses if they exists. 1. y = 3x + 4 2. f(x) = 1 4 x + 7 3. g(x) = x 2

4. h(x) = x 2 10 with Domain: x > 0 D. Find a solution to the following systems of linear equations. 1. f(x) = 1 x + 7 and g(x) = 3x + 4 4 2. g(x) = 3x + 4 and h(x) = 3x + 7 3. g(x) = 7x + 6 and j(x) = 3x + 7 4. f(x) = 1 1 x + 7 and h(x) = x + 7 4 4 E. Graph the following functions using the rules of scaling and shifting 1. f(x) = x 2 2. g(x) = x 2 7 3. h(x) = (x + 5) 2 4. j(x) = (x + 5) 2 7 5. k(x) = 3 f(x) (f(x) appears in E.1.) 6. l(x) = f(3x) (f(x) appears in E.1.) F. Does the following data line on a line? Why or why not? 1. 2. time Mites on a lizard, y 0 1 1 5 2 10 3 15 4 20 time Mites on a lizard, y 0 10 2 12 4 14 6 15 8 16 G. Multiply the expressions. 1. (x + 3)(x + 2) 2. (x + 3)(x 3)

H. Solve. 3. (x 2 + 3x)(x 3 + 2x + 5) 1. x 2 4 = 0 2. x 2 + 9x + 9 = 0 3. 3x 2 + 4x 3 = 0 4. 2x 2 + 5x 10 = 0 I. Simplify 1. x 2 4 x 2 2. 4x 2 +6x 2x 4x 3. 2 +8x 4x2 +6x 4 2x J. Graph the following piecewise defined functions. 1. 2. f(n) = f(n) = { n 2 if n 0 n if n 0 { 3n + 4 if n 2 n if n < 2 Other good quiz questions involve the volume, area, perimeter, and surface area equations on page 28 of your textbook. Also review the relations involving mass that appear on page 28 and examples on pages 48-50.

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