Name: Class: Date: ID: A Physics Q--Fall 0, 60 points possible out of 50 points maximum. Multiple Choice Make no marks on these sheets. Identify the choice that best completes the statement or answers the question and record them on the bubble sheet.. ( point) According to the graph above, during which interval is the cat at rest? a. 0.0 5.0 s b. 5.0 0.0 s c. 0.0 5.0 s d. 5.0 0.0 s. ( point) According to the graph above, during which interval does the cat have the greatest positive velocity? a. 5.0 0.0 s b. 0.0 5.0 s c. 0.0 5.0 s d. 5.0 0.0 s 3. ( point) According to the graph above, the cat has the fastest speed during which interval? a. 5.0 0.0 s b. 0.0 5.0 s c. 0.0 5.0 s d. 5.0 0.0 s 4. ( point) If the change in position x is related to velocity v (with units of m/s) in the equation x = Av, the constant A has which dimension? a. m b. m c. s d. m/s 5. ( point) Three values were obtained for the mass of a metal bar: 8.83 g; 8.84 g; 8.8 g. The known mass is 0.68 g. The values are a. accurate. b. precise. c. both accurate and precise. d. neither accurate nor precise. 6. ( point) The SI base unit for time is a. minute. b. hour. c. day. d. second. 7. ( point) The symbol mm represents a a. micrometer. b. megameter. c. manometer. d. millimeter. 8. ( point) The SI base unit used to measure mass is the a. liter. b. second. c. meter. d. kilogram.
Name: ID: A 9. ( point) A lack of precision in scientific measurements typically arises from a. limitations of the measuring instrument. b. too many significant figures. c. lack of calibration. d. human error. 0. ( point) If a is acceleration (m/s ), v is change in velocity (m/s), x is change in position (m), and t is the time interval (s), which equation is not dimensionally correct? a. t = x v b. a = v x c. v = a t d. t = x a. ( point) The most appropriate SI unit for measuring the length of an automobile is the a. kilometer. b. nanometer. c. meter. d. micron.. ( point) The Greek letter (delta) indicates a(n) a. sum or total. b. difference or change. c. direct proportion. d. inverse proportion. 3. ( point) Which of the following is the equation for average velocity? v i v f a. v avg = x t b. v avg = c. v avg = t d. v x avg = x t 4. ( point) What two dimensions, in addition to mass, are commonly used by physicists to derive additional measurements? a. length and time b. area and mass c. length and width d. velocity and time 5. ( point) The sun is composed mostly of hydrogen. The mass of the sun is.0 0 30 kg, and the mass of a hydrogen atom is.67 0 7 kg. Estimate the number of atoms in the sun. a. 0 30 b. 0 3 c. 0 57 d. 0 75 6. ( point) What is the speed of an object at rest? a..0 m/s b. 9.8 m/s c. 0.0 m/s d. 9.8 m/s Short Answer. In the space below the box, write your answers to Short Answer and show your work for the Problems. 7. ( points) For the seven SI base units, list the unit s names, the of measure, and symbol. 8. ( points) In increasing order, list the four metric prefixes, symbol and their respective multiplier that you are expected to memorize for Physics. Problems, Show all conversion factors and how they cancel. 9. (0 points) There are 0 tumtum trees in the tulgey wood. In each tulgey wood is one frumious Bandersnatch. There are 5 slithy toves in borogoves. There are mome raths per Jabberwock. There are Jubjub birds in 00 tumtum trees. There are 00 mome raths in each borogove. There are 5 Jubjub birds per slithy tove. If there are 5 frumious Bandersnatches, how many Jabberwocks should there be? 0. ( point) µm = km
Physics Q--Fall 0, 60 points possible out of 50 points maximum. Answer Section MULTIPLE CHOICE. ANS: B PTS: DIF: II OBJ: -.3. ANS: C PTS: DIF: II OBJ: -.3 3. ANS: B PTS: DIF: II OBJ: -.3 4. ANS: C x = Av Rearrange the equation to solve for A and substitute units. A = x v = m m/s = s PTS: DIF: IIIA OBJ: -3.3 5. ANS: B PTS: DIF: II OBJ: -.3 6. ANS: D PTS: DIF: I OBJ: -. 7. ANS: D PTS: DIF: I OBJ: -. 8. ANS: D PTS: DIF: I OBJ: -. 9. ANS: A PTS: DIF: I OBJ: -.3 0. ANS: C Does v = a t? Substitute units into the right side of the equation. Ê ˆ m Ê ˆ a = m/s Ë Á s Ë Á s = = m t s Ê ( s) ˆ s 3 Ë Á s Substituting units into both sides of the equation yields the following result: m s m s 3 PTS: DIF: IIIA OBJ: -3.3. ANS: C PTS: DIF: II OBJ: -.. ANS: B PTS: DIF: I OBJ: -3. 3. ANS: D PTS: DIF: I OBJ: -. 4. ANS: A PTS: DIF: I OBJ: -.
5. ANS: C Given m sun =.0 0 30 kg m H atom =.67 0 7 kg Estimate the answer using an order-of-magnitude calculation. 0 30 = 057 7 0 PTS: DIF: IIIB OBJ: -3.4 6. ANS: C PTS: DIF: I OBJ: -. SHORT ANSWER 7. ANS: time seconds s length meter m mass (kilo)gram kg or g temperature Kelvin K luminosity candela cd elec current amp, ampere A amount of substance mole mol PTS: 8. ANS: micro- µ 0 6 milli- m 0 3 centi- c 0 kilo- k 0 3 PTS:
PROBLEM 9. ANS: 5 Bandersnatch * tulgey wood * 0 tumtum tree * Jubjub birds * slithy tove * borogove * 00 mome rath * Jaberwock Bandersnatch tugley wood 00 tumtum tree 5 Jubjub bird 5 slithy tove borogove mome rath PTS: 0 0. ANS: 5**0****00* = 8 Jaberwocks **00*5*5** µm Ê Ë Á m / 0^6µm ˆ ( km / 0^3m) = 0^ 9km PTS: 3