Potential Formulation Lunch with UCR Engr 12:20 1:00

Similar documents
Problem Solving 7: Faraday s Law Solution

Version 001 HW#6 - Electromagnetic Induction arts (00224) 1 3 T

Version 001 HW#6 - Electromagnetism arts (00224) 1

#6A&B Magnetic Field Mapping

Summary of equations chapters 7. To make current flow you have to push on the charges. For most materials:

Physics 202, Lecture 14

EMF Notes 9; Electromagnetic Induction ELECTROMAGNETIC INDUCTION

PHYSICS ASSIGNMENT-9

Unique Solutions R. All about Electromagnetism. C h a p t e r. G l a n c e

Physics 212. Faraday s Law

Chapter 7 Steady Magnetic Field. september 2016 Microwave Laboratory Sogang University

Homework Assignment 9 Solution Set

ECE 3318 Applied Electricity and Magnetism. Spring Prof. David R. Jackson Dept. of ECE. Notes 31 Inductance

200 points 5 Problems on 4 Pages and 20 Multiple Choice/Short Answer Questions on 5 pages 1 hour, 48 minutes

Inductance and Energy of B Maxwell s Equations Mon Potential Formulation HW8

Physics 202, Lecture 10. Basic Circuit Components

Magnetic forces on a moving charge. EE Lecture 26. Lorentz Force Law and forces on currents. Laws of magnetostatics

2. VECTORS AND MATRICES IN 3 DIMENSIONS

Problem Set 4: Mostly Magnetic

Physics 3323, Fall 2016 Problem Set 7 due Oct 14, 2016

DIRECT CURRENT CIRCUITS

Resistors. Consider a uniform cylinder of material with mediocre to poor to pathetic conductivity ( )

( dg. ) 2 dt. + dt. dt j + dh. + dt. r(t) dt. Comparing this equation with the one listed above for the length of see that

THREE-DIMENSIONAL KINEMATICS OF RIGID BODIES

Math 8 Winter 2015 Applications of Integration

Potential Changes Around a Circuit. You must be able to calculate potential changes around a closed loop.

Physics 202, Lecture 13. Today s Topics

IMPORTANT. Read these directions carefully:

WELCOME TO THE LECTURE

Physics 2135 Exam 3 April 21, 2015

This final is a three hour open book, open notes exam. Do all four problems.

F is on a moving charged particle. F = 0, if B v. (sin " = 0)

Cross-section section of DC motor. How does a DC Motor work? 2 Commutator Bars N X. DC Motors 26.1

Week 10: Line Integrals

Fig. 1. Open-Loop and Closed-Loop Systems with Plant Variations

Electromagnetism Answers to Problem Set 10 Spring 2006

Magnetic Fields! Ch 29 - Magnetic Fields & Sources! Magnets...! Earth s Magnetic Field!

Homework Assignment 3 Solution Set

dy ky, dt where proportionality constant k may be positive or negative

The Velocity Factor of an Insulated Two-Wire Transmission Line

Motion of Electrons in Electric and Magnetic Fields & Measurement of the Charge to Mass Ratio of Electrons

in a uniform magnetic flux density B = Boa z. (a) Show that the electron moves in a circular path. (b) Find the radius r o

CAPACITORS AND DIELECTRICS

Problems for HW X. C. Gwinn. November 30, 2009

ES.182A Topic 32 Notes Jeremy Orloff

We partition C into n small arcs by forming a partition of [a, b] by picking s i as follows: a = s 0 < s 1 < < s n = b.

Physics 1402: Lecture 7 Today s Agenda

Homework Assignment 6 Solution Set

Section 4.8. D v(t j 1 ) t. (4.8.1) j=1

Designing Information Devices and Systems I Discussion 8B

10 Vector Integral Calculus

Chapter E - Problems

Conservation Law. Chapter Goal. 5.2 Theory

Reading from Young & Freedman: For this topic, read the introduction to chapter 24 and sections 24.1 to 24.5.

10/25/2005 Section 5_2 Conductors empty.doc 1/ Conductors. We have been studying the electrostatics of freespace (i.e., a vacuum).

Hints for Exercise 1 on: Current and Resistance

SUMMER KNOWHOW STUDY AND LEARNING CENTRE

Consequently, the temperature must be the same at each point in the cross section at x. Let:

Get Solution of These Packages & Learn by Video Tutorials on EXERCISE-1

ELE B7 Power Systems Engineering. Power System Components Modeling

Definition of Continuity: The function f(x) is continuous at x = a if f(a) exists and lim

Reference. Vector Analysis Chapter 2

Conservation Law. Chapter Goal. 6.2 Theory

RFID Technologies HF Part I

Trigonometric Functions

PHYS 1442 Section 004 Lecture #14

R(3, 8) P( 3, 0) Q( 2, 2) S(5, 3) Q(2, 32) P(0, 8) Higher Mathematics Objective Test Practice Book. 1 The diagram shows a sketch of part of

Infinite Geometric Series

Our goal for today. 1. To go over the pictorial approach to Lenz s law.

Exam 1 Solutions (1) C, D, A, B (2) C, A, D, B (3) C, B, D, A (4) A, C, D, B (5) D, C, A, B

Physics Graduate Prelim exam

Line Integrals. Chapter Definition

Review: Velocity: v( t) r '( t) speed = v( t) Initial speed v, initial height h, launching angle : 1 Projectile motion: r( ) j v r

The area under the graph of f and above the x-axis between a and b is denoted by. f(x) dx. π O

Chapter 4 Syafruddin Hasan

Problem 1. Solution: a) The coordinate of a point on the disc is given by r r cos,sin,0. The potential at P is then given by. r z 2 rcos 2 rsin 2

Waveguide Guide: A and V. Ross L. Spencer

Linear Motion. Kinematics Quantities

Faraday's Law ds B B G G ΦB B ds Φ ε = d B dt

63. Representation of functions as power series Consider a power series. ( 1) n x 2n for all 1 < x < 1

du = C dy = 1 dy = dy W is invertible with inverse U, so that y = W(t) is exactly the same thing as t = U(y),

ragsdale (zdr82) HW2 ditmire (58335) 1

Candidates must show on each answer book the type of calculator used.

MORE FUNCTION GRAPHING; OPTIMIZATION. (Last edited October 28, 2013 at 11:09pm.)

7.1 Integral as Net Change and 7.2 Areas in the Plane Calculus

Physics 2135 Exam 1 February 14, 2017

Terminal Velocity and Raindrop Growth

Math Calculus with Analytic Geometry II

PDE Notes. Paul Carnig. January ODE s vs PDE s 1

SYDE 112, LECTURES 3 & 4: The Fundamental Theorem of Calculus

Phys102 General Physics II

Lecture 5 Capacitance Ch. 25

Lecture 7 notes Nodal Analysis

Kinematics equations, some numbers

Practice Problems Solution

- 5 - TEST 2. This test is on the final sections of this session's syllabus and. should be attempted by all students.

Lecture 5. Today: Motion in many dimensions: Circular motion. Uniform Circular Motion

Today in Physics 122: work, energy and potential in electrostatics

Simple Harmonic Motion I Sem

KINEMATICS OF RIGID BODIES

Transcription:

Wed. Fri., Mon., Tues. Wed. 7.1.3-7.2.2 Emf & Induction 7.2.3-7.2.5 Inductnce nd Energy of 7.3.1-.3.3 Mxwell s Equtions 10.1 -.2.1 Potentil Formultion Lunch with UCR Engr 12:20 1:00 HW10

Generliztion of Flux Rule S(t) dl v d S(t+) d v dl Using vector identity (1) A C A C d v dl v dl v dl Thus chnge in mgnetic flux through the loop d v dl rte of chnge in mgnetic flux through the loop F v mg dl dl t q t Emf Wrning: our derivtion used tht the chnging, d/, corresponded to moving chrge, vdl. Not pplicble when tht s not the cse. thr be prdoxes (We will lter extend this resoning to discuss sttionry chrges but chnging fields) mg

q q Electric Genertor cosq Spin loop clockwise t w (perhps stem turbines mke it spin) d Emf d d cosq sin sin wt Genertes voltge between terminls V Emf sinwt w w wt w R Drives current I through resistive lod IR V sinwt Demo! - crnk genertor Electric Motor Sme process run in reverse Demo! - home-mde motor w

Frdy s Lw F mg q dl Emf t d vl v Which drives chrges round the loop, vi mgnetic force From the perspective of someone riding the loop t t From this perspective too we must see chrges move round the loop, there must be force ut mgnetic is defined s chrge force proportionl to chrge s velocity; from this perspective, there is no v, so we cn t cll it mgnetic, hve to cll it electric. F elect q dl Emf t

Frdy s Lw F mg q dl Emf t d vl v Which drives chrges round the loop, vi mgnetic force From the perspective of someone riding the loop t t In most generl cse Emf t From this perspective too we must see chrges move round the loop, there must be force t d d Full time derivtive

Frdy s Lw F elect dl q t qe dl d q t E dl d t E d d t E t circulting electric field is ccompnied by time vrying mgnetic field From the perspective of someone riding the loop oth re produced by time vrying current nd chrge distributions

Oh, Induction, let me count the wys induced emf in the coil 2 on the right I 1 1 Chnge the current in coil 1 v 1 1 Move coil 1 (with current through it) Come up with some more

Copper pipe Not mgnet Induction of the flling mgnet Copper pipe mgnet Why does the mgnet fll so slowly?

Copper pipe Not mgnet Induction of the flling mgnet Copper pipe mgnet Why does the mgnet fll so slowly? E t or d Emf Mens Emf s direction is by left hnd rule round re contining flux 23_Frdy_Mgnet.py To the right s downwrd flux increses To the left s downwrd flux decreses Thus drives chrges round pipe nd so trnsfers energy. These chrges in motion produce field which exerts force on moving chrges in mgnets.

induced emf in the coil 2 on the right Lenz s Lw Copper pipe mgnet nture bhors chnge in flux Chnge I 1 1 the current in coil v 1 1 Move coil 1 (with current through it) v 2 1 Move coil 2 (with current through coil 1) 1 Rotte coil 1 (with current) Induced Emf (or curled Electric field) drives current tht produce mgnetic field which prtly counters the chnge in mgnetic flux. To the left s downwrd flux decreses To the right s downwrd flux increses S N Demo! v 1 1 Thus drives chrges round pipe nd so trnsfers energy. These chrges in motion produce field which exerts force on moving chrges in mgnets.

Using Frdy s Lw d E or Emf or E dl t t re Exmple: very long solenoid of rdius with sinusoidlly vrying current such tht o coswt zˆ. A circulr loop of rdius /2 nd esistnce R is inserted. Wht is the current induced round the loop? ẑ I Demo!

Using Frdy s Lw d E or Emf or E dl t t re Exercise: very long solenoid, with rdius nd n turns per unit length, crries time vrying current, I(t). Wht s n expression for the electric field ẑ distnce s from xis? Recll tht inside solenoid oinzˆ. I

Using Frdy s Lw d E or Emf or E dl t t re Exmple: A slowly vrying lternting current, It I 0 coswt, flows down long, stright, thin wire nd returns long coxil conducting tube of rdius. In wht direction must the electric field point? ẑ I I E E Lenz lw sys in the direction to drive current tht would oppose chnging flux, so down nd up s the current vries up nd down. ẑ Wht s the electric field? E dl t d Clls for n Amperin loop E dl in E dl E d t E dl top E dl where out s z Es z in t s dsz out t s E dl 0 I ˆ s, 2s 0 s. nd It I 0 coswt bottom E dl oi dsz oi 2s ln z t 2 sin

Using Frdy s Lw d E or Emf or E dl t t re Exmple: A slowly vrying lternting current, It I 0 coswt, flows down long, stright, thin wire nd returns long coxil conducting tube of rdius. In wht direction must the electric field point? I I ẑ E E Wht s the electric field? s E in E Lenz lw sys in the direction to drive current tht would oppose chnging flux, so down nd up s the current vries up nd down. ẑ Right-hnd-side is independent of how fr E dl d out of loop s t out is, so E is constnt outside. ut it sout z oi ln z should be 0 quite fr wy, t 2 sin so must be 0 everywhere outside. E E s in s in oi ln t 2 s in t oiow sin wt ln 2 sin I cos wt o o 2 ln s in

Wed. Fri., Mon., Tues. Wed. 7.1.3-7.2.2 Emf & Induction 7.2.3-7.2.5 Inductnce nd Energy of 7.3.1-.3.3 Mxwell s Equtions 10.1 -.2.1 Potentil Formultion Lunch with UCR Engr 12:20 1:00 HW10