Cluster varieties for tree-shaped quivers and their cohomology

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Cluster varieties for tree-shaped quivers and their cohomology Frédéric Chapoton CNRS & Université de Strasbourg Octobre 2016

Cluster algebras and the associated varieties Cluster algebras are commutative algebras = cluster varieties (their spectrum) are algebraic varieties Question: can we compute their cohomology rings?

Cluster algebras and the associated varieties Cluster algebras are commutative algebras = cluster varieties (their spectrum) are algebraic varieties Question: can we compute their cohomology rings? Why is this interesting? classical way to study algebraic varieties useful (necessary) to understand integration on them answer is not obvious, and sometimes nice there are interesting known differential forms

My choice goes to trees Choice: try to handle first some simple cases = restriction to quivers that are trees (general quivers are more complicated)

My choice goes to trees Choice: try to handle first some simple cases = restriction to quivers that are trees (general quivers are more complicated) This choice is restrictive and rather arbitrary, but turns out to involve a nice combinatorics of perfect matchings and independent sets in trees

My choice goes to trees Choice: try to handle first some simple cases = restriction to quivers that are trees (general quivers are more complicated) This choice is restrictive and rather arbitrary, but turns out to involve a nice combinatorics of perfect matchings and independent sets in trees computing number of points over finite fields F q can be seen as a first approximation towards determination of cohomology and is usually much more easy

First example (for babies) α x Cluster algebra of type A 1 : Presentation by the unique relation with one frozen vertex α. x x = 1 + α

First example (for babies) α x Cluster algebra of type A 1 : Presentation by the unique relation with one frozen vertex α. x x = 1 + α We will consider cluster algebras with invertible coefficients So here α is assumed to be invertible.

First example (for babies) α x Cluster algebra of type A 1 : Presentation by the unique relation with one frozen vertex α. x x = 1 + α We will consider cluster algebras with invertible coefficients So here α is assumed to be invertible. One can then do two different things: (1) either let α be a coordinate, solve for α, and get the open sub-variety xx 1 with coordinates x, x. (2) or fix α to a generic invertible value (here α 1, 0) and get the variety x 0 with coordinate x.

First example (for babies) x x = 1 + α ( ) The first case (1) (α as variable) is a cluster variety spectrum of the cluster algebra R = C[x, x, α, α 1 ]/( )

First example (for babies) x x = 1 + α ( ) The first case (1) (α as variable) is a cluster variety spectrum of the cluster algebra R = C[x, x, α, α 1 ]/( ) The second case (2) (α fixed to a generic value) could be called a cluster fiber variety: the inclusion of algebras C[α, α 1 ] R gives a projection of varieties C Spec(R) and one looks at the (generic) fibers of this coefficient morphism.

First example (for babies) x x = 1 + α ( ) The first case (1) (α as variable) is a cluster variety spectrum of the cluster algebra R = C[x, x, α, α 1 ]/( ) The second case (2) (α fixed to a generic value) could be called a cluster fiber variety: the inclusion of algebras C[α, α 1 ] R gives a projection of varieties C Spec(R) and one looks at the (generic) fibers of this coefficient morphism. Note that the fiber at α = 1 is singular.

General case of trees Let us generalize this simple example. For any tree, there is a well-defined cluster type (because all orientations of a tree are equivalent by mutation) one can therefore work with the alternating orientation, where every vertex is either a source or a sink

General case of trees Let us generalize this simple example. For any tree, there is a well-defined cluster type (because all orientations of a tree are equivalent by mutation) one can therefore work with the alternating orientation, where every vertex is either a source or a sink For any tree T, the aim is to define several varieties that are a kind of compound between cluster varieties and fibers For that, need first to introduce some combinatorics on trees

Independent sets in graphs By definition, an independent set in a graph G is a subset S of the set of vertices of G such that every edge contains at most one element of S 3 3 1 2 4 5 6 1 2 4 5 6 independent and not independent

Independent sets in graphs By definition, an independent set in a graph G is a subset S of the set of vertices of G such that every edge contains at most one element of S 3 3 1 2 4 5 6 1 2 4 5 6 independent and not independent A maximum independent set is an independent set of maximal cardinality among all independent sets. (not the same as being maximal for inclusion)

Independent sets in graphs Independent sets are a very classical notion in graph theory. NP-complete problem for general graphs (Richard Karp, 1972) polynomial algorithm for bipartite graphs (Jack Edmonds, 1961). a very nice description for trees (Jennifer Zito 1991 ; Michel Bauer and Stéphane Coulomb 2004)

Independent sets in graphs Independent sets are a very classical notion in graph theory. NP-complete problem for general graphs (Richard Karp, 1972) polynomial algorithm for bipartite graphs (Jack Edmonds, 1961). a very nice description for trees (Jennifer Zito 1991 ; Michel Bauer and Stéphane Coulomb 2004) One has to distinguish three kinds of vertices: - vertices belonging to all maximal independent sets: RED - vertices belonging to some (not all) max. independent sets: ORANGE - vertices belonging to no maximal independent set: GREEN Chosen colors are traffic light colors

Independent sets in graphs Independent sets are a very classical notion in graph theory. NP-complete problem for general graphs (Richard Karp, 1972) polynomial algorithm for bipartite graphs (Jack Edmonds, 1961). a very nice description for trees (Jennifer Zito 1991 ; Michel Bauer and Stéphane Coulomb 2004) One has to distinguish three kinds of vertices: - vertices belonging to all maximal independent sets: RED - vertices belonging to some (not all) max. independent sets: ORANGE - vertices belonging to no maximal independent set: GREEN Chosen colors are traffic light colors Nota Bene: this green has nothing to do with green sequences

Canonical coloring This gives a canonical coloring of every tree! Here is one example of this coloring: 3 1 2 4 5 6 7 Here, there are 2 maximal indep. sets {1, 3, 5, 7} and {2, 3, 5, 7}.

Canonical coloring This gives a canonical coloring of every tree! Here is one example of this coloring: 3 1 2 4 5 6 7 Here, there are 2 maximal indep. sets {1, 3, 5, 7} and {2, 3, 5, 7}. This coloring can be described by local Feynman rules: - a green vertex has at least two red neighbors - a red vertex has only green neighbors - orange vertices are grouped into neighbourly pairs

Canonical coloring This gives a canonical coloring of every tree! Here is one example of this coloring: 3 1 2 4 5 6 7 Here, there are 2 maximal indep. sets {1, 3, 5, 7} and {2, 3, 5, 7}. This coloring can be described by local Feynman rules: - a green vertex has at least two red neighbors - a red vertex has only green neighbors - orange vertices are grouped into neighbourly pairs It turns out that this coloring is also related to matchings.

Coloring and matchings A matching is a set of edges with no common vertices. A maximum matching is a matching of maximum cardinality among all matchings. 3 1 2 4 5 6 7

Coloring and matchings A matching is a set of edges with no common vertices. A maximum matching is a matching of maximum cardinality among all matchings. 3 1 2 4 5 6 7 Other names: dimer coverings or domino tilings. Here not required to cover all vertices (perfect matchings)

Coloring and matchings A matching is a set of edges with no common vertices. A maximum matching is a matching of maximum cardinality among all matchings. 3 1 2 4 5 6 7 Other names: dimer coverings or domino tilings. Here not required to cover all vertices (perfect matchings) Theorem (Zito ; Bauer-Coulomb) This coloring is the same as: orange: vertices always in the same domino in all max. matchings green: vertices always covered by a domino in any max. matching red: vertices not covered by a domino in some max. matching

Red-green components One can then use this coloring to define red-green components: keep only the edges linking a red vertex to a green vertex; this defines a forest; take its connected components 0 4 2 3 1 5 An example with two red-green components {0, 1, 2} and {3, 4, 5}

Red-green components One can then use this coloring to define red-green components: keep only the edges linking a red vertex to a green vertex; this defines a forest; take its connected components 0 4 2 3 1 5 An example with two red-green components {0, 1, 2} and {3, 4, 5} For a tree T, let us call dimension dim T = # red # green. This is always an integer dim(t ) 0. In the example above, the dimension is 4 2 = 2.

Here is a big random example of tree, with its canonical coloring

So what are the varieties? Take a tree T and consider the alternating (bipartite) orientation on T. This gives a quiver, initial data for cluster theory. Another orientation would give a quiver equivalent by mutation.

So what are the varieties? Take a tree T and consider the alternating (bipartite) orientation on T. This gives a quiver, initial data for cluster theory. Another orientation would give a quiver equivalent by mutation. Pick a maximum matching of T and attach one frozen vertex to every vertex not covered by the matching. β α (Claim: no loss in generality compared to arbitrary coefficients) every coefficient is attached to a red vertex

So what are the varieties? β α the extended graph is still a tree, and has a perfect matching. the number of frozen vertices is dim(t ).

So what are the varieties? β α the extended graph is still a tree, and has a perfect matching. the number of frozen vertices is dim(t ). Then choose independently for every red-green component: - either to let all coefficients vary (but staying invertible) - or to let all coefficients be fixed at generic (invertible) values

So what are the varieties? The equations are the cluster exchange relations for the alternating orientation (of the extended tree): x i x i = 1 + j x j. One uses here a theorem of Berenstein-Fomin-Zelevinsky (in Cluster Algebras III ) which gives a presentation by generators and relations of acyclic cluster algebras.

So what are the varieties? The equations are the cluster exchange relations for the alternating orientation (of the extended tree): x i x i = 1 + j x j. One uses here a theorem of Berenstein-Fomin-Zelevinsky (in Cluster Algebras III ) which gives a presentation by generators and relations of acyclic cluster algebras. β α In this example, one can choose to fix β and let α vary. This is really a mixture between the global cluster variety and the fibers of the coefficient morphism.

The matching does not matter Theorem This variety does not depend on the matching (up to isomorphism). All these varieties are smooth. Proved using monomial isomorphisms ; smoothness by induction

The matching does not matter Theorem This variety does not depend on the matching (up to isomorphism). All these varieties are smooth. Proved using monomial isomorphisms ; smoothness by induction Note that the genericity condition can be made very explicit and is really necessary to ensure smoothness: Counter examples α α A 3 singular when α = 1 and A 1 when α = 1 (A 1 was the baby s example)

Points over finite fields equations have coefficients in Z reduction to finite field F q. Theorem For X any of these varieties, there exists a polynomial P X such that #X (F q ) is given by P x (q). This is a first hint that maybe cohomology may be nice. (not true for all algebraic varieties, see elliptic curves)

Points over finite fields equations have coefficients in Z reduction to finite field F q. Theorem For X any of these varieties, there exists a polynomial P X such that #X (F q ) is given by P x (q). This is a first hint that maybe cohomology may be nice. (not true for all algebraic varieties, see elliptic curves) The proof is by induction on the size of trees. One picks a vertex, corresponding to a variable x. Then either x = 0 or x 0. Both reduces to similar varieties (for well chosen vertices).

Points over finite fields equations have coefficients in Z reduction to finite field F q. Theorem For X any of these varieties, there exists a polynomial P X such that #X (F q ) is given by P x (q). This is a first hint that maybe cohomology may be nice. (not true for all algebraic varieties, see elliptic curves) The proof is by induction on the size of trees. One picks a vertex, corresponding to a variable x. Then either x = 0 or x 0. Both reduces to similar varieties (for well chosen vertices). For A 3 with α generic, one gets q 3 1 points. α

Free action of a torus Recall the dimension dim(t ) = # red # green Clearly the dimension is additive over red-green components.

Free action of a torus Recall the dimension dim(t ) = # red # green Clearly the dimension is additive over red-green components. Consider the variety X T associated with tree T and a choice for every red-green component of T between varying or generic coefficients. Let N be the sum of dim C over all generic -type red-green components C. Theorem There is a free action of (C ) N on X T. Moreover the enumerating polynomial P X can be written as (q 1) N times a reciprocal polynomial.

Free action of a torus Recall the dimension dim(t ) = # red # green Clearly the dimension is additive over red-green components. Consider the variety X T associated with tree T and a choice for every red-green component of T between varying or generic coefficients. Let N be the sum of dim C over all generic -type red-green components C. Theorem There is a free action of (C ) N on X T. Moreover the enumerating polynomial P X can be written as (q 1) N times a reciprocal polynomial. Reciprocal means P(1/q) = q d P(q) (palindromic coefficients)

Free action: an example Let us look at the example of type A 3 (with dim(t ) = 1): α xx = 1 + αy, yy = 1 + xz, zz = 1 + y.

Free action: an example Let us look at the example of type A 3 (with dim(t ) = 1): xx = 1 + αy, α yy = 1 + xz, zz = 1 + y. Here N = 1 and one can pick α = 1 as generic value Free action of C with coordinate λ: x λx, y y, z z/λ.

Free action: an example Let us look at the example of type A 3 (with dim(t ) = 1): xx = 1 + αy, α yy = 1 + xz, zz = 1 + y. Here N = 1 and one can pick α = 1 as generic value Free action of C with coordinate λ: x λx, y y, z z/λ. The enumerating polynomial is q 3 1 = (q 1)(q 2 q + 1) This variety is not a product, but a non-trivial C -principal bundle.

What about cohomology? Tools that can be used to study cohomology : - algebraic de Rham cohomology (algebraic differential forms) - cohomology with compact support - mixed Hodge structure, weights on cohomology

What about cohomology? Tools that can be used to study cohomology : - algebraic de Rham cohomology (algebraic differential forms) - cohomology with compact support - mixed Hodge structure, weights on cohomology Lemma For two adjacent vertices x, y, either x 0 or y 0. Just because of the exchange relation xx = 1 + y! = coverings by two open sets, can apply Mayer-Vietoris long exact sequence

What about cohomology? Tools that can be used to study cohomology : - algebraic de Rham cohomology (algebraic differential forms) - cohomology with compact support - mixed Hodge structure, weights on cohomology Lemma For two adjacent vertices x, y, either x 0 or y 0. Just because of the exchange relation xx = 1 + y! = coverings by two open sets, can apply Mayer-Vietoris long exact sequence can also find coverings by more open sets use spectral sequences. The Hodge structure sometimes help to prove that the spectral sequence degenerates at step 2.

Some simple classes in cohomology With all these tools, only partial results. For every varying coefficient α, there is a class dα α.

Some simple classes in cohomology With all these tools, only partial results. For every varying coefficient α, there is a class dα α. For every tree, there is a natural 2-form usually called the Weil-Petersson form (Gekhtman-Schapiro-Vainshtein, Fock-Goncharov, G. Muller) WP = i j dx i dx j x i x j. sum running over edges in the frozen quiver, excluding the fixed coefficients.

Some simple classes in cohomology With all these tools, only partial results. For every varying coefficient α, there is a class dα α. For every tree, there is a natural 2-form usually called the Weil-Petersson form (Gekhtman-Schapiro-Vainshtein, Fock-Goncharov, G. Muller) WP = i j dx i dx j x i x j. sum running over edges in the frozen quiver, excluding the fixed coefficients. Not enough The sub-algebra generated by those forms is not the full cohomology ring in general!

There are other classes in cohomology Example of type A 3 For α invertible variable, one-form dα α and 2-form WP = dxdα xα + dxdy xy + dzdy zy do generate all the cohomology α H = Q, Q, Q, Q, Q.

There are other classes in cohomology Example of type A 3 For α invertible variable, one-form dα α and 2-form WP = dxdα xα + dxdy xy + dzdy zy do generate all the cohomology α H = Q, Q, Q, Q, Q. For α generic fixed, WP = dxdy xy + dzdy zy, but cohomology has dimensions H = Q, 0, Q, Q 2

Mixed Tate-Hodge structures They form an Abelian category, with a forgetful functor to Q-vector spaces, and with one simple object Q(i) for every i Z no morphisms Q(i) Q(j) if i j. Some extensions Q(i) E Q(j) if j > i. Think of representations of a hereditary quiver with vertices Q 0 Z

Mixed Tate-Hodge structures They form an Abelian category, with a forgetful functor to Q-vector spaces, and with one simple object Q(i) for every i Z no morphisms Q(i) Q(j) if i j. Some extensions Q(i) E Q(j) if j > i. Think of representations of a hereditary quiver with vertices Q 0 Z One can find such structure on the cohomology of all these varieties. Deligne (and many famous names involved) gives us a mixed Hodge structure on the cohomology of all algebraic varieties.

Mixed Tate-Hodge structures They form an Abelian category, with a forgetful functor to Q-vector spaces, and with one simple object Q(i) for every i Z no morphisms Q(i) Q(j) if i j. Some extensions Q(i) E Q(j) if j > i. Think of representations of a hereditary quiver with vertices Q 0 Z One can find such structure on the cohomology of all these varieties. Deligne (and many famous names involved) gives us a mixed Hodge structure on the cohomology of all algebraic varieties. One can prove by induction that it is Hodge-Tate in the varieties under consideration. This means that there are no more complicated factors.

Mixed Tate-Hodge structures: one example Consider the type A 3 for generic α α H = Q(0), 0, Q(2), Q(2) Q(3) the last summand H 3 is not pure (has several weights)

Mixed Tate-Hodge structures: one example Consider the type A 3 for generic α α H = Q(0), 0, Q(2), Q(2) Q(3) the last summand H 3 is not pure (has several weights) Knowing this decomposition allows to recover the number of points over finite fields. Essentially every direct summand Q(i) in the cohomology group H j gives a summand ( 1) j q i. (But beware that one must use cohomology with compact support). The cohomological information above gives back q 3 1.

Some results (Dynkin diagrams are trees) For type A n with n even, every class is a power of the Weil-Petersson 2-form.

Some results (Dynkin diagrams are trees) For type A n with n even, every class is a power of the Weil-Petersson 2-form. For type A n with n odd and one varying coefficient α, every class is in the ring generated by WP and dα α.

Some results (Dynkin diagrams are trees) For type A n with n even, every class is a power of the Weil-Petersson 2-form. For type A n with n odd and one varying coefficient α, every class is in the ring generated by WP and dα α. For type A n with n odd and one generic coefficient α, only a guess: Besides powers of WP, there are (n + 1)/2 more forms in top degree, with distinct weights.

Some results (Dynkin diagrams are trees) For type A n with n even, every class is a power of the Weil-Petersson 2-form. For type A n with n odd and one varying coefficient α, every class is in the ring generated by WP and dα α. For type A n with n odd and one generic coefficient α, only a guess: Besides powers of WP, there are (n + 1)/2 more forms in top degree, with distinct weights. For type D n with n odd and one generic coefficient, one can show that besides powers of WP, there is one more form in degree 3 and one more in degree n.

Some results (Dynkin diagrams are trees) For type A n with n even, every class is a power of the Weil-Petersson 2-form. For type A n with n odd and one varying coefficient α, every class is in the ring generated by WP and dα α. For type A n with n odd and one generic coefficient α, only a guess: Besides powers of WP, there are (n + 1)/2 more forms in top degree, with distinct weights. For type D n with n odd and one generic coefficient, one can show that besides powers of WP, there is one more form in degree 3 and one more in degree n. Something can also be said about some trees of general shape H, in particular for E 6 and E 8 case E 7 with generic coefficient not fully understood.

Some details on type D α One concrete example : D n with n odd and generic coefficient α Theorem The cohomology is given by Q(k) if k = 0 mod (2) Q(k 1) if k = 1 mod (2) and k 1, n Q(n 1) Q(n) if k = n For n = 3, this coincide with the answer for A 3, as it should.

Some things being skipped today Results on counting points over F q (nice formulas) Just one tiny example in type E n for n even: (q 2 q + 1) (qn 1 1) (q 1) cellular decomposition (when coefficients are variables) = formula as a sum for the number of points over F q. Simple algorithm to compute the coloring.

The mysterious Poincaré duality and the curious Lefschetz property of Hausel and Rodriguez-Villegas Recall that the enumerating polynomial P X can be written as (q 1) N times a reciprocal polynomial, because there is a free torus action.

The mysterious Poincaré duality and the curious Lefschetz property of Hausel and Rodriguez-Villegas Recall that the enumerating polynomial P X can be written as (q 1) N times a reciprocal polynomial, because there is a free torus action. It seems that the quotient varieties are very interesting. Their enumerating polynomials are palindromic. Why?

The mysterious Poincaré duality and the curious Lefschetz property of Hausel and Rodriguez-Villegas Recall that the enumerating polynomial P X can be written as (q 1) N times a reciprocal polynomial, because there is a free torus action. It seems that the quotient varieties are very interesting. Their enumerating polynomials are palindromic. Why? Speyer and Lam (in a more general context) have proved that the palindromy comes from a structural property of the cohomology. Namely, cup-product by the Weil-Petersson 2-form gives an isomorphism between some subspaces of the cohomology. This is very similar to the classical statement of algebraic geometry, where the hyperplane class of a projective algebraic variety acts on the cohomology in a way that implies usual Poincaré duality.

Some perspectives (many things to do) - at least complete the case of type A and Dynkin diagrams - go beyond trees to all acyclic quivers and general matrices (see article by David E Speyer and Thomas Lam, arxiv:1604.06843.) - say something about the integrals (ζ(2) and ζ(3) are involved) - try to organize all the cohomology rings of type A into some kind of algebraic structure (Hopf algebra, operad?) - study the topology of the real points (in relation with q = 1) - topology of the set of non-generic parameters (toric arrangement) - what about K-theory instead of cohomology? - understand the mysterious palindromic/poincaré/lefschetz property - some amusing relations between P X and Pisot numbers

Grazie