ID : ww-5-decimal-numbers [1] Grade 5 Decimal Numbers For more such worksheets visit www.edugain.com Answer t he quest ions (1) At a construction site, there are 14.5 loads of bricks, and the total weight of all the loads together is 720.94 kgs. What is the weight of one load? (2) What is the value of 0.3762 0.06? (3) What is the smallest number should be added to 5.05 to give an even number? (4) What is the place value of 2 in 8491.0632? (5) What is the smallest number should be subtracted f rom 7.55 to give a prime number? Choose correct answer(s) f rom given choice (6) The place 1000000 times smaller than the Hundreds place is called : a. The Thousandths Place b. The Ten thousandths Place c. The Thousands Place d. The Tens Place (7) Sarah drove 63.75 kms to visit her grandmother. When she reached her grandmother's house she noticed the car had used up 3.4 litres of petrol. How many kilometers did she travel per litre of petrol? a. 18.73 km b. 18.75 km c. 18.85 km d. 18.92 km (8) What do you get when you subtract 758.11 f rom 819.33? a. 62.72 b. 61.22 c. 6.122 d. 59.12 (9) A slug can move a distance of 33.6 meters in 3.5 hours. What distance can it travel in 4 days? a. 920.2 m b. 925.6 m c. 918.9 m d. 921.6 m (10) Which number is 0.47 larger than the largest 2-digit number? a. 10.47 b. 98.53 c. 99.47 d. 9.53 (11) What do you get when you subtract the sum of 321.55 and 34.98 f rom 454.95? a. 34.98 b. 98.42 c. 741.52 d. 168.38
ID : ww-5-decimal-numbers [2] Fill in the blanks (12) Barbara's f ather gave her $189 to spend. She spent $67.55 to buy some toys and $60.03 to buy some books. She now has $ lef t. (13) Kevin purchased 45 pins to share with his classmates. If it cost him $11.7 to buy them, then the price of each item is $ (14) Solve the f ollowing: A) + 41.41 = 1014.6 B) 756.39 - = 25.78 C) 244.63 - = 7.58 D) - 705.3 = 59.14 (15) 21 Tens + 35 Ten thousandths = 2016 Edugain (www.edugain.com). All Rights Reserved Many more such worksheets can be generated at www.edugain.com
Answers ID : ww-5-decimal-numbers [3] (1) 49.72 kg The number of loads of bricks = 14.5 Total weight of all the loads together = 720.94 kgs In order to f ind the weight of one load, we need to divide the total weight by the number of loads. Theref ore, the weight of one load is 720.94 14.5 = 49.72 kg. (2) 6.27 (3) 0.95 (4) 2 T en thousandths Let s use the place value chart and f ind where 2 is placed: 84910632 Lakhs T housands Ones T enths Hundredths T housandths T en thousandths T L L T T H T H H T O. (1/10) (1/100) (1/1000) (1/10000) 8 4 9 1. 0 6 3 2 Legend: TL - Ten Lakhs, L - Lakhs, TTH - Ten Thousands, TH - Thousands, H - Hundreds, T - Tens, O - Ones. From the above table, we observe that 2 is placed under the Ten thousandths place. Hence, the place value of 2 in 8491.0632 is 2 Ten thousandths. (5) 0.55
(6) b. The Ten thousandths Place ID : ww-5-decimal-numbers [4] In order to f ind the place value which is 1000000 times smaller than the Hundreds place, let us divide 100 by 1000000: 100 = 0.0001 1000000 Let us see what is the place of 1 in the number 0.0001: T housands Ones T enths Hundredths T housandths T en thousandths T T H T H H T O. (1/10) (1/100) (1/1000) (1/10000) 0. 0 0 0 1 Legend: TTH - Ten Thousands, TH - Thousands, H - Hundreds, T - Tens, O - Ones. We see that 1 is placed in the Ten thousandths place. Theref ore, the place 1000000 times smaller than the Hundreds place is called the Ten thousandths place. (7) b. 18.75 km Distance that Sarah drove to reach her grandmother's house = 63.75 kms Number of litres used while driving = 3.4 litres In order to know the number of kilometres per litre of petrol, we will need to divide the number of kilometers traveled Sarah by the number of litres of petrol used. Thus, the number of kilometers Sarah travelled per litre of petrol = 63.75 3.4 = 18.75 km/litre Step 5 Theref ore, the kilometres per litre of petrol (mileage of the car) is 18.75 km/liter.
(8) b. 61.22 ID : ww-5-decimal-numbers [5] Decimals with the same number of decimal places are called Like Decimals. T he numbers given here are theref ore Like Decimals. We need to subtract 758.11 f rom 819.33. Theref ore, 819.33 must be placed on top and 758.11 below. The digits of the two numbers must be placed according to their place values. Let us now do the subtraction of the two numbers digit by digit, starting f rom the hundredths and borrowing if needed: Thousands Hundreds Tens Ones. Tenth Hundredth 8 1 9. 3 3-7 5 8. 1 1 0 6 1. 2 2 Hence, when we subtract 758.11 f rom 819.33, we get 61.22. (9) d. 921.6 m (10) c. 99.47 The largest 2-digit number is 99 (a whole number). The number 0.47 larger than 99 can be f ound by adding the numbers 0.47 and 99. Let us f irst convert the whole number 99 into decimal f orm. In decimal f orm, 99 can be written as 99.00. Decimals with the same number of decimal places are called like decimals. Now, our task is to add the Like Decimals 0.47 and 99.00. Let us add them starting f rom the hundredths and carry over if needed. The decimal point in the answer will be placed as being placed in the addends: Hundred Ten Thousands Hundreds Tens Ones. Tenth Hundredth Thousands Thousands 9 9. 0 0 + 0. 4 7 9 9. 4 7 Step 5 Hence, the number 0.47 larger than the largest 2-digit number is 99.47.
(11) b. 98.42 ID : ww-5-decimal-numbers [6] Let us f irst f ind the sum of the Like Decimal numbers 321.55 and 34.98. Decimals with the same number of decimal places are called Like Decimals. Let us add starting f rom the hundredths and carry over if needed. The decimal point in the answer will be placed as being placed in the addends: Ten Thousands Thousands Hundreds Tens Ones. Tenth Hundredth 3 2 1. 5 5 + 3 4. 9 8 3 5 6. 5 3 Let us now subtract the sum 356.53 f rom 454.95 by placing the digits of these two Like Fractions according to their place values Ten Thousands Thousands Hundreds Tens Ones. Tenth Hundredth 4 5 4. 9 5-3 5 6. 5 3 0 9 8. 4 2 Hence, when we subtract the sum of 321.55 and 34.98 f rom 454.95, we get 98.42.
(12) 61.42 ID : ww-5-decimal-numbers [7] The amount of money that Barbara's f ather gave her = $189 The amount that Barbara spent in buying toys = $67.55 The amount that Barbara spent in buying books = $60.03 Let us add the amount she spent in buying toys and books to f ind her total expense: Toys = $67.55 Books = $60.03 Total expense = $127.58 Step 5 In order to f ind the amount lef t with her, we need to subtract the amount Barbara's f ather gave and the amount Barbara spent. Step 6 Bef ore subtracting the two numbers, let us make sure they are written as Like Decimals. Decimals with the same number of decimal places are called Like Decimals. Thus, let us write $189 as $189.00, and subtract $127.58 f rom it Step 7 Let us subtract the amount Barbara spent ($127.58) f rom the amount her f ather gave ($189) digit by digit. The numbers must be placed according to their place values. The greater number must be placed on top and the lesser one below: Thousands Hundreds Tens Ones. Tenth Hundredth 1 8 9. 0 0-1 2 7. 5 8 0 6 1. 4 2 Step 8 Hence, Barbara is lef t with $61.42.
(13) 0.26 ID : ww-5-decimal-numbers [8] Cost of 45 pins that Kevin purchased = $11.7 Theref ore, the cost of 1 pins = 11.7 45 = $0.26 Hence, the cost of each pins is $0.26. (14) A) B) C) D) 973.19 730.61 237.05 764.44 (15) 210.0035 First, let us convert the number names into numerals as below: 21 Tens = 21 10 = 210 35 Ten thousandths = 35 10000 = 0.0035 Let s now add the two numbers: Lakhs T housands Ones T enths Hundredths T housandths T en thousandths T L L T T H T H H T O. (1/10) (1/100) (1/1000) (1/10000) 2 1 0. 0 0 0 0 0. 0 0 3 5 T otal 2 1 0. 0 0 3 5 Legend: TL - Ten Lakhs, L - Lakhs, TTH - Ten Thousands, TH - Thousands, H - Hundreds, T - Tens, O - Ones. Thus, 21 Tens + 35 Ten thousandths = 210.0035